The length of one base of a trapezoid is 19 less than five times the length of the other base. If the trapezoid has a height of 18 feet and an area of 477 ft squared, find the length of the longer base.

Answers

Answer 1
Area of a trapezoid: [(top +bottom)*height]/2
suppose the length of one base is x, then the other base is 5x-19
[(x+5x-19)*18]/2=477
[6x-19]*18=954
6x-19=53
6x=72
x=12
The longer base is 5*12-19=41


Answer 2
Final answer:

The length of the shorter base of the trapezoid is found by solving the equation generated by using the formula for the area of a trapezoid. After finding this length, it is substituted into the equation representing the length of the longer base to find its value, which is 76 feet.

Explanation:

To solve this problem, let's denote the length of the shorter base of the trapezoid as 'a'. According to the problem, the length of the longer base is then 5a - 19. We also know that the area of a trapezoid is given by the formula: (1/2) * (sum of lengths of bases) * height. So, by substituting the given trapezoid area (477 ft squared) and height (18 ft) into the this formula, we get: 477 = 1/2 * (a + (5a - 19)) * 18. Solving this equation will give us the value of 'a'. As calculating 'a' we find it to be 19. After that, we insert 'a' into the longer base equation: 5a - 19, we find the length of the longer base to be 76 ft.

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Related Questions

Find the length of the diagonal of this rectangle.

Answers

cos 32  = 10 / AC 
AC = 10 / cos 32

   =  11.79  m  ( to nearest hundredth)

Answer:

The length of the diagonal of the given Rectangle is, 11.80 m (Approx.)

Step-by-step explanation:

In Rectangle:

* It is a four sided shape where every angle is a right angle.

* The alternative sides are equal.

*Two axes of symmetry bisect each other.

* Diagonals are equal in length.

The figure of rectangle has given the length [tex]l[/tex] = 10m

In right angle triangle ADC.  

DC = 10 m ( as alternative sides are equal )

Note that we are given here the adjacent and we have to find the  length of hypotenuse, then we use trigonometric ratio that contains both sides adjacent and hypotenuse.

Use:  [tex]Cosine = \frac{Adjacent}{hypotenuse}[/tex]

then,

[tex]\cos 32^{\circ} = \frac{10}{AC}[/tex]  or

[tex]Ac = \frac{10}{\cos 32^{\circ}} =\frac{10}{0.8480481}[/tex]

On simplify we get;

AC = 11.791784 m

therefore, the length of the diagonal of this rectangle (AC) is, 11.80 m (Approx)

   





Can you find a shortcut in doing two translations in geometry

Answers

You can. I am pretty sure

“all integers are rational numbers” true or false? why?

Answers

true
Every rational number can be written as a fraction a/b , where a and b are integers. ... If a number is a whole number, for instance, it must also be an integer and a rational.
true
Every rational number can be written as a fraction a/b , where a and b are integers. ... If a number is a whole number, for instance, it must also be an integer and a rational


The functions graphed show the snowfall, in inches, in two cities after x hours.

Select each correct answer.



Middletown had a faster rate of snowfall.

Smithville had a faster rate of snowfall.

Snow fell in Smithville at a rate of 4 inches per hour.

Middletown already had snow on the ground at the beginning of the storm.

Answers

The answer Fam is............. Smithville had a faster rate of snowfall., And..Snow fell in Smithville at a rate of 4 inches per hour.

we know that

the formula to calculate the slope between two points is equal to

[tex]m=\frac{y2-y1}{x2-x1}[/tex]

in this problem

the rate of snowfall is equal to the slope of the linear equation

so

Let

x-------> the time in hours

y---------> the snowfall in inches

Step 1

Find the slope of the line of the Smithville city

Let

[tex]A(0,0)\\B(5,20)[/tex]

substitute the values in the formula above

[tex]m=\frac{20-0}{5-0}[/tex]

[tex]m=4\frac{inches}{hour}[/tex]

Step 2

Find the slope of the line of the Middletown city

Let

[tex]A(0,0)\\B(5,15)[/tex]

substitute the values in the formula above

[tex]m=\frac{15-0}{5-0}[/tex]

[tex]m=3\frac{inches}{hour}[/tex]

Step 3

Verify the statements

case A) Middletown had a faster rate of snowfall

The statement is False

Because Smithville had a faster rate of snowfall with [tex]4\frac{inches}{hour}[/tex]

case B) Smithville had a faster rate of snowfall

The statement is True

case C) Snow fell in Smithville at a rate of 4 inches per hour

The statement is True

case D) Middletown already had snow on the ground at the beginning of the storm

The statement is False

Because at the beginning of the storm the value of the snow is equal to zero

therefore

the answer is

Smithville had a faster rate of snowfall

Snow fell in Smithville at a rate of 4 inches per hour

What? I don’t know what I’m doing???

Answers

looks like your doing it right

Which expression is equivalent to -3.5(4x – 3)?
A. -3.9x – 3.2
B. -3.9x + 3.2
C. -14x + 10.5
D. -14x – 10.5

Answers

First, you need to solve the equation.

-3.5 * 4x = -14x
-3.5 * -3 = 10.5

C) -14x + 10.5

Hope this helps!



Answer:

The answer is c

Step-by-step explanation:

Angle a has the property that twenty eight times times its complement is equal to thirteen times its supplement. find the measure of angle
a.

Answers

< a....its complement is (90 - a) and its supplement is (180 - a)

28(90 - a) = 13(180 - a)
2520 - 28a = 2340 - 13a
-28a + 13a = 2340 - 2520
- 15a = - 180
a = -180/-15
a = 12 <=== so < a = 12

Simplify (s)(-3st)(-1/3).
A.) -3 1/3 t
B.) s^2t
C.) 3s^2t 
(If this format is too weird I have added a screenshot)

Thanks in advance!

Answers

the answer is b!!!!!!
The 3 will cut off each other and the s will be squared so the answer is B..s^2.t

How to solve for a side of a right triangle when you only know one side?

Answers

Well if you know the area of the triangle you can use that to find the other lengths or else just use the Pythagorean Theroem.

Hope I helped :)
If you only know one side, then that's not enough information to solve for any other part of a triangle. You also need to know the measures of the angles at each end of it. In a right triangle, that means you need to know one of the acute angles (since you already know the right angle).

Customers of a phone company can choose between two service plans for long distance calls. The first plan has a $27 monthly fee and charges an additional $0.12 for each minute of calls. The second plan has no monthly fee but charges $0.16 for each minute of calls. For how many minutes of calls will the costs of the two plans be equal?

Answers

The first plan : y = 27 + 0.12x
Second plan : y = 0.16x

27 + 0.12x= 0.16x
27 = 0.04x

x = 67.5 minutes

what did the candle say to the match

Answers

YOU LIGHT UP MY LIFE

I really need help with these problems please come it will mean a lot if u help.

Answers

1. 59 degrees

2. 59 degrees

3. would be 4

I'm not for sure about the other ones...


What is the ratio 35 to 15 expressed as a fraction in simplest form?

Answers

35/15 = 7/3

Dividing by a factor of 5 should help.
The ratio of 35 to 15 is represented as 35:15
That is the same as 35/15
Let's use 5 to divide to its simplest form. That will be;
35 divided by 5 is 7. And 15 divided by 5 is 3. So you have;
7/3
Hope that helped. Have a nice day

Consider the function
{8x-x^2 for x is less than or equal to 8
x^2+3 for x>8}

what is f(8)?

Answers

f(x) = 8x-x^2 only if x is equal to 8 or less than 8
OR
f(x) = x^2+3 only if x > 8

We can only pick one of the two paths. The function f(x) can't be both at the same time. In the case of computing f(8) we have the input x = 8. It won't fit the bottom piece as x > 8 is false when x = 8. The inequality 8 > 8 is false

So instead we pick the top piece

x = 8 ----> so "x is less than or equal to 8" is true
f(x) = 8x - x^2
f(8) = 8*8 - 8^2
f(8) = 64 - 64
f(8) = 0

The final answer is 0

Justin is constructing a line through point Q that is perpendicular to line n. He has already constructed the arcs shown. He places his compass on point B to construct an arc. What must be true about the width of the compass opening when Justin draws the arc?
A .It must be wider than when he constructed the arc centered at point A.

B It must be the same as when he constructed the arc centered at point A.

C. It must be equal to BQ .

D.It must be equal to AB .


Answers

B. It must be the same as when he constructed the arc centered at point A. This problem would be a lot easier if you had actually supplied the diagram with the "arcs shown". But thankfully, with a few assumptions, the solution can be determined. Usually when constructing a perpendicular to a line through a specified point, you first use a compass centered on the point to strike a couple of arcs on the line on both sides of the point, so that you define two points that are equal distance from the desired intersection point for the perpendicular. Then you increase the radius of the compass and using that setting, construct an arc above the line passing through the area that the perpendicular will go. And you repeat that using the same compass settings on the second arc constructed. This will define a point such that you'll create two right triangles that are reflections of each other. With that in mind, let's look closely at your problem to deduce the information that's missing. "... places his compass on point B ..." Since he's not placing the compass on point Q, that would imply that the two points on the line have already been constructed and that point B is one of those 2 points. So let's look at the available choices and see what makes sense. A .It must be wider than when he constructed the arc centered at point A. Not good. Since this implies that the arc centered on point A has been constructed, then it's a safe assumption that points A and B are the two points defined by the initial pair of arcs constructed that intersect the line and are centered around point Q. If that's the case, then the arc centered around point B must match exactly the setting used for the arc centered on point A. So this is the wrong answer. B It must be the same as when he constructed the arc centered at point A. Perfect! Look at the description of creating a perpendicular at the top of this answer. This is the correct answer. C. It must be equal to BQ. Nope. If this were the case, the newly created arc would simply pass through point Q and never intersect the arc centered on point A. So it's wrong. D.It must be equal to AB. Sorta. The setting here would work IF that's also the setting used for the arc centered on A. But that's not guaranteed in the description above and as such, this is wrong.

Answer:

just to confuse yall less it is indeed b!

Step-by-step explanation:

took the test on k12

What is the angle of elevation from jim to the top of the waterfall

Answers

Answer: <7

Step-by-step explanation:

When two straight lines or rays intersect at a shared endpoint, an angle is generated. The angle of elevation from Jim to the top of the waterfall is ∠5. The correct option is B.

What is an angle?

When two straight lines or rays intersect at a shared endpoint, an angle is generated. An angle's vertex is the common point of contact. Angle is derived from the Latin word angulus, which means "corner."

The angle of elevation is an imaginary angle that is assumed between the horizontal line and the line through which an object at a height is been seen.

In the given image the angle of elevation from Jim to the top of the waterfall is the angle formed by the line parallel to the horizontal plane and the line that connects Jim's eyesight to the top of the waterfall.

Hence, the angle of elevation from Jim to the top of the waterfall is ∠5.

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1. Create a circle. Show and explain the difference between the following:
a. secant line and tangent line
b. inscribed angle and central angle

2. Describe the steps necessary to construct an inscribed circle in a triangle and contrast this with the steps you take to construct a circumscribed circle.

3. Demonstrate on the whiteboard how to find the center and radius of a circle using an equation. Be sure to provide a unique example of your own that shows how to find both of these.

4. A classmate is having difficulty finding the measures of
5. The world’s largest round pizza, which also happened to be gluten-free, was set in December 2012 by five Italian chefs. The diameter of this pizza was 131 feet. If this pizza was cut into 50 slices, what would be the area of each slice and the length of the crust for the slice? Explain what concepts of a circle these calculations related to.

Answers

1. 
a.
A secant line is a line which intersects the circle at 2 different points. 

A tangent line is a line which has only one point in common with the circle.

Check picture 1: The orange line s is a secant line, the blue line t is a tangent line.


b.
An inscribed angle is an angle formed by using 3 points of a circle. 

The main property of an inscribed angle is that its measure is half of the measure of the arc it intercepts.

Check picture 2: If  [tex]m(\angle KML)=\beta[/tex], then the measure of arc KL is [tex]2 \beta [/tex].

A central angle is an angle whose vertex is the center of the circle, and the 2 endpoints of the rays are points of the circle.

The main property is: the measure of the central angle is equal to the measure of the arc it intercepts. 

Check picture 2

2.
To construct the inscribed circle of a triangle, we first draw the 3 interior angle bisectors of the triangle.
They meet at a common point called the incenter, which is the center of the inscribed circle.
We open the compass, from the incenter, so that it touches one of the sides at only one point. We then draw the circle. (picture 3)

To draw the circumscribed circle, we first find the midpoints of each side. We then draw perpendicular segments through these (the midpoints.) They meet  at one common point, which is the circumcenter: the center of the circumscribed circle.
We open the compass from the circumcenter to one of the vertices of the triangle. We draw the circle, and see that it circumscribes the triangle.

(picture 4)

3.

Given an equation of a circle: [tex]x^2-2x+y^2+6y+6=0[/tex].

To determine the center and the radius of the equation we must write the above equation in the form :

                              [tex](x-a)^2+(y-b)^2=r^2[/tex].

Then, (a, b) is the center, and r is the radius of this circle. We do this process by completing the square.

Note that [tex]x^2-2x[/tex] becomes a perfect square by adding 1, and 
[tex]y^2+6y[/tex] becomes a perfect square by adding 9. 

Thus we have:

[tex]x^2-2x+y^2+6y+6=0\\\\(x^2-2x+1)+(y^2+6y+9)-4=0\\\\(x-1)^2+(y+3)^2=2^2[/tex]

Thus, the center is (1, -3), and the radius is 2.

4. Not complete


5.

The radius of the pizza is [tex]\displaystyle{ \frac{131}{2}ft=65.5ft [/tex].

The surface of a circle with radius r is given by the formula [tex]\displaystyle{  A=\pi r^2[/tex],
and the circumference is given by the formula C=2πr.

Thus, the area of the whole pizza is given by [tex]\displaystyle{ A=\pi r^2= \pi\cdot65.5^2=4290.25 \pi [/tex] (square ft).

Each of the 50 slices, has an area of [tex]\displaystyle{ \frac{4290.25 \pi}{50} =85.805 \pi [/tex] (square ft)

Notice that the perimeter (the crust) of a slice is made of 2 radii, and the arc-like part.
The arc is 1/50 of the circumference, so it is [tex] \displaystyle{\frac{2 \pi r}{50} = \frac{2\cdot65.5\cdot \pi }{50}= 2.62 \pi [/tex].

So the perimeter of one slice is 65.5+65.5+2.62π=131+2.62π

Final answer:

The differences between secant and tangent lines, and between inscribed and central angles, involve the number of intersection points with the circle and the position of the vertex, respectively. Constructing an inscribed circle involves finding the incenter, while a circumscribed circle requires finding the circumcenter. To find the center and radius of a circle using its equation, we use the standard form (x - h)² + (y - k)² = r².

Explanation:

Differences Between Secant Lines, Tangent Lines, Inscribed Angles, and Central Angles

A secant line is a line that intersects a circle at two points, while a tangent line touches the circle at exactly one point. An inscribed angle is an angle formed by two chords in a circle that meet at one point in the circle, whereas a central angle is an angle whose apex (vertex) is the center of the circle.

Constructing Inscribed and Circumscribed Circles in a Triangle

To construct an inscribed circle (incircle) of a triangle, draw the angle bisectors of the triangle's angles to find the incenter, and then use this point to draw the circle that touches all three sides of the triangle. For a circumscribed circle (circumcircle), draw the perpendicular bisectors of the triangle's sides and the point where they intersect will be the circumcenter; use this as the center to draw the circle that passes through all three vertices of the triangle.

Finding the Center and Radius of a Circle Using an Equation

Given a circle's equation in the standard form (x - h)² + (y - k)² = r², the center is at point (h, k), and the radius is the square root of r². For example, if we have the equation (x - 3)² + (y + 2)² = 16, the center is (3, -2) and the radius is 4 units.

Area and Length of the Crust of a Circular Pizza Slice

For the world's largest round pizza with a diameter of 131 feet, the radius would be 65.5 feet. The area of each slice is a fraction of the whole pizza's area, which can be found using the formula A = πR², and the length of the crust for the slice corresponds to the arc length of that slice.

Area of whole pizza = 3.14 * 65.5² ≈ 13478.2 ft²

Area of each slice = total area /50 = 13478.2/50 ≈ 269.5 ft²

Length of crust =  2πR * (slice area/total area)

= 2 * 3.14 * (1/50)

≈ 0.125 ft

What is the area of a triangle with vertices at (−4, 1) , ​ (−7, 5) ​ , and ​ (0, 1) ​ ?

Enter your answer in the box.

Answers

we know that

A method for calculating the area of a triangle when you know the lengths of all three sides is the Heron's Formula.

The Heron's Formula states that

[tex]A=\sqrt{p(p-a)(p-b)(p-c)}[/tex]  

where

a,b.c are the length sides of the triangle

p is half the perimeter of the triangle

Let

[tex]A(-4,1)\\B(-7,5)\\C(0,1)[/tex]

Step 1

Find the distance AB

we know that

the formula to calculate the distance between two points is equal to

[tex]d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}[/tex]

we have

[tex]A(-4,1)\\B(-7,5)[/tex]

substitute the values in the formula

[tex]d=\sqrt{(5-1)^{2}+(-7+4)^{2}}[/tex]

[tex]d=\sqrt{(4)^{2}+(-3)^{2}}[/tex]

[tex]d=\sqrt{25}[/tex]

[tex]dAB=5\ units[/tex]

Step 2

Find the distance BC

we know that

the formula to calculate the distance between two points is equal to

[tex]d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}[/tex]

we have

[tex]B(-7,5)\\C(0,1)[/tex]

substitute the values in the formula

[tex]d=\sqrt{(1-5)^{2}+(0+7)^{2}}[/tex]

[tex]d=\sqrt{(-4)^{2}+(7)^{2}}[/tex]

[tex]d=\sqrt{65}[/tex]

[tex]dBC=8.06\ units[/tex]

Step 3

Find the distance AC

we know that

the formula to calculate the distance between two points is equal to

[tex]d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}[/tex]

we have

[tex]A(-4,1)\\C(0,1)[/tex]

substitute the values in the formula

[tex]d=\sqrt{(1-1)^{2}+(0+4)^{2}}[/tex]

[tex]d=\sqrt{(0)^{2}+(4)^{2}}[/tex]

[tex]d=\sqrt{16}[/tex]

[tex]dAC=4\ units[/tex]

Step 4

Find half the perimeter

[tex]p=\frac{1}{2}(AB+BC+AC)[/tex]

substitute the values

[tex]p=\frac{1}{2}(5+8.06+4)[/tex]

[tex]p=8.53\ units[/tex]

Step 5

Find the area

Applying the Heron's Formula

[tex]A=\sqrt{8.53(8.53-5)(8.53-8.06)(8.53-4)}[/tex]  

[tex]A=\sqrt{8.53(3.53)(0.47)(4.53)}[/tex]    

[tex]A=\sqrt{64.11}[/tex]  

[tex]A=8\ units^{2}[/tex]  

therefore

the answer is

the area of the triangle is [tex]8\ units^{2}[/tex]  

The area of a shape is the amount of space it occupies.

The area of the triangle is 8 unit square.

The vertices are given as:

[tex]\mathbf{A = (-4,1)}[/tex]

[tex]\mathbf{B = (-7,5)}[/tex]

[tex]\mathbf{C = (0,1)}[/tex]

The area of the triangle is:

[tex]\mathbf{A= \frac{1}{2} \times |A_x(B_y - C_y) + B_x(C_y - A_y) + C_x(A_y - B_y)|}[/tex]

So, we have:

[tex]\mathbf{A= \frac{1}{2} \times |-4(5 - 1) -7(1 - 1) + 0(1 - 5)|}[/tex]

[tex]\mathbf{A= \frac{1}{2} \times |-4(4) -7(0) + 0|}[/tex]

[tex]\mathbf{A= \frac{1}{2} \times |-4(4) -0 + 0|}[/tex]

[tex]\mathbf{A= \frac{1}{2} \times |-16|}[/tex]

Remove absolute brackets

[tex]\mathbf{A= \frac{1}{2} \times 16}[/tex]

[tex]\mathbf{A= 8}[/tex]

Hence, the area of the triangle is 8 unit square.

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write a word phrase for each algebraic expression

1. 25 - 6

2. 2/3y + 4

factor each expression

3. 45c + 10d

4. 27 - 9x + 15y

Simplify the expression.

5. 3(t - 4) - 8 (2 - 3t )

6. 12x + 24

Answers

1.) Twenty five minus six

Answer:


Step-by-step explanation:

1)Twenty five minus sixty percent times a number.



Your Turn: Find the equation of a line that is parallel to y=2x+7, and passes through the point (-4, 7). SHOW YOUR WORK

Answers

Parallel lines have the same slope. Let's fill that into the slope-intercept equation.
y=2x+b

Now, we can use the point we are given to find the y-intercept.
7=2(-4)+b
7=-8+b
b=7+8
b=15

Finally, we can substitute all the information we have discovered to complete the slope-intercept equation.
y=2x+15

if i have 64,32,16,8 what two numbers comes next

Answers

4 and 2.
(Because the pattern is that it is dividing the previous number by 2)

Sample text because sample text is sample text, which is sample text according to sample text.
4 then 2


i hope this helps and have a wonderful day!!

If a share of stock costs $32.63, what would it cost to buy 1,000 shares of the stock?

Answers

Here is your answer:                                                                                                                                                                                                                                                                      If a share of the stock cost 32.63 and you wanted to buy 1,000 shares of the stock you just need to multiply 1,000 and 32.63                                                                                                                                                                         32.63*1,000=32,630                                                                                                                                                                                                                            Your answer is: 32,630$
answer is: $32,630

you just multiply the 2 intergers

brainliest plz:)

The legs of a right triangle measure 30cm and 40cm.what is the length of the hypotenuse

Answers

The equation to find a hypotenuse is
A^2 + b^2=c^2

Plug in the numbers

30^2 + 40^2 = c^2

900 + 1600 =c^2

2500 = c^2

The square-root of 2500 = c

50=c

The hypotenuse of the triangle is 50

Hope this helps!
a²+b²=c²
30²+40²=c²
900+1600=c²
2500=c²
√2500=√c²
c=50
The hypotenuse is 50cm long.

Hope this helps!

nick bought a pet lizard and enjoys the responsibility of taking care of it . every week , the lizard will eat 60 grasshoppers. nick pays $1 for 20 grasshoppers . how many dollars will a year’s worth of food cost for the lizard

Answers

60*52 = 3120 per year

3120/20 = 156

 it will cost $156 a year

Help please !!!!!!!!!!!!!!

Answers

To start, we're given the range that x lies in: from -1 to 4. We know from the fact that [tex]-1 \leq x[/tex] that -1 will be included in that range, so we mark -1 on the number line with a solid circle. We also know from [tex]x\ \textless \ 4[/tex] that, while x can be any value up to 4, it does not include 4. We indicate this by drawing a hollow circle around 4 on the number line. Since x can be any value within this range, we make that fact clear by drawing a bold line between the points -1 and 4 on the number line. I've attached an image of what our final graph would look like.

A company plans to enclose three parallel rectangular areas for sorting returned goods. the three areas are within one large rectangular area and 10641064 yd of fencing is available. what is the largest total area that can be​ enclosed?

Answers

First get the perimeter

Perimeter: 2l + 2w = 1064 yd

 

The region inside the fence is the area

Area: A = lw

 

We need to solve the perimeter formula for either length or width.

2l + 2w = 1064 yd

2w = 1064 yd – 2l

W = 1064– 2l / 2

W = 532 – l

 

Now substitute than to the area formula

A = lw

A = l (532 – l)

A = 532 – l^2

 

Since the equation A represents a quadratic expression, rewritte the expression with the exponents in descending order

A(l) = -l^2 + 532l

 

Then look for the value of the x coordinate

 

l = -b/2a

l = -532/2(-1)

l = -532/-2

l = 266 yards

 

Plugging in the value into our calculation for area:

A(l) = -l^2 + 532

A(266) = -(266)^2 + 532 (266)

A(266) =  70756+ 141512

= 70756 square yards.

 

Thus the largest area that could encompass would be a square where each side has a length of 266 yards and a width of:


W = 532 – l

= 532 – 266

= 266

It should be noted that the largest total area that can be enclosed will be 70756 yards².

How to calculate the area.

Firstly, we have to calculate the perimeter. This will be:

2l + 2w = 1064 yd

Area: A = length × width

2l + 2w = 1064 yd

2w = 1064 yd – 2l

W = 1064– 2l / 2

W = 532 – l

Since Area = lw

A = l(532 – l)

A = 532 – l²

A(l) = -l² + 532l

l = -b/2a

l = -532/2(-1)

l = -532/-2

l = 266 yards

The length is 266 yards.

Area = -l² + 532

A( = -(266)² + 532 (266)

Area = 70756+ 141512

Area = 70756 yards²

Learn more about areas on:

https://brainly.com/question/25292087

Can someone help me with this? 18(−8c+16)−13(6+3c) =

Answers

Hi. I am attaching a step by step image for you. Hope this helps.

Take care,
Diana

how would you graph the solution set of the system of inequalities {3y≤2x+6} { 2x+y>0}

Answers

1) Solve the first inequality

3y ≤ 2x + 6

=> y ≤ 2x/3 + 2

2) Draw the line y = 2x/3 + 2

3) Shade the region below the line y = 2x/3 + 2

4) Solve the inequality 2x + y > 0

=> y > - 2x

5) draw the line y = -2x

6) Shade the region above the line y = -2x

7) The solution is the region between the two lines shaded including the portion of the line y = 2x/3 + 2

I need help with #17

Answers

The van's consumption is 200/10  = 20 miles per gallon

so for 480 miles we need  480 / 20  = 24 gallons

Two cars leave town going in opposite directions. one car is traveling 55 miles per hour (mph), and the other car is traveling 40 mph. how long will it take before the cars are 285 miles apart?

Answers

The distance, d, traveled by a car going at speed, s, in time, t, is
d = st

Car 1 travels distance 1, d1, at s1 = 55 mph, for t1 time.
Car 2 travels distance 2, d2, at s2 = 40 mph, for t2 time.

The two distances add to 285 miles, so
d1 + d2 = 285
The two times are equal, so t1 = t2 = t

d1 = 55t1
d2 = 40t2

d1 = 55t
d2 = 40t

d1 + d2 = 55t + 40t

d = 95t

285 = 95t

95t = 285

t = 3

Answer: It will take 3 hours.

Note:
This problem shows you that if two cars are traveling along the same line in opposite directions, the speed at which they are distancing themselves is the sum of the two speeds. We can solve the problem in a simpler way:

55 mph + 40 mph = 95 mph

d = st

285 = 95t

t = 3

Answer: 3 hours.
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