The length of a rectangle is increasing at a rate of 8 cm/s and its width is increasing at a rate of 3 cm/s. when the length is 20 cm and the width is 10cm, how fast is the area of the rectangle increasing

Answers

Answer 1
Let l = length of the rectangle,
b = breadth of the rectangle,
a = area of the rectangle,
t = time,

So, [tex] \frac{dl}{dt} [/tex] = 8 cm/s &
[tex] \frac{dw}{dt} [/tex] = 3 cm/s

Area of the rectangle, a = l × w

Differentiate the equation with respect to t,

[tex] \frac{da}{dt} [/tex] = l × [tex] \frac{dw}{dt} [/tex] +  w × [tex] \frac{dl}{dt} [/tex]

[tex] \frac{da}{dt} [/tex] = 20 × 3 +  10 × 8

[tex] \frac{da}{dt} [/tex] = 60 +  80

[tex] \frac{da}{dt} [/tex] = 140 [tex] cm^{2} [/tex]/s

Therefore, the correct answer is 140 [tex] cm^{2} [/tex]/s.
Answer 2
The information that is given:
dl/dt = 8  (rate of length increasing)
dw/dt = 3 (rate of width increasing)
l = 20 (when the length is 20)
w = 10 (when the width is 10)

The unknown is dA/dt (the rate the area is increasing)

Start with the formula for the area of a rectangle
A = w*l
Find the derivative of it
d/dt(A) = d/dt(w*l)  Use the multiplication rule
dA/dt = w(dl/dt) + l(dw/dt) 
Substitute in what is known from above
dA/dt = 10(8) + 20(3) = 80+60 = 140
The area is increasing 140 square centimeters per second


Related Questions

clothing store sells t-shirts and jeans. The store charges customers $15 per t-shirt and $35 per pair of jeans. The store pays $4.50 per t-shirt and $5.00 per pair of jeans, plus a flat fee of $150 per order. Complete the work to determine the expression that represents the store's profit if they sell t t-shirts and j pairs of jeans

Answers

What are the answer choices??


What is the value of the 7 digit in 91,764,350?

Answers

700,000 is the value of the digit

700,000 is the value

For f(x)=3x+1 and g(x)=x squared - 6 find (f- g)(x)

Answers

It helps to first clarify that the notation (f - g)(x) simply means f(x) - g(x). Given that, let's look at our f(x) and our g(x) here, and use their definitions to find their difference.

[tex]f(x)=3x+1\\g(x)=x^2-6[/tex]

When we're taking (f - g)(x), we simply substitute the expression 3x + 1 for f(x) and the expression x² - 6 for g(x) to obtain:

[tex](3x+1)-(x^2-6)=3x+1-x^2+6[/tex]

Or, ordering the polynomial from highest power to lowest and combining the constants:

[tex]-x^2+3x+7[/tex]

Edit: By request, here's what would happen if you had something instead like:

[tex](f\times g)(x)[/tex]

In this case, you'd have to *multiply* the two function expressions together. Here's what that would look like:

[tex](3x+1)(x^2-6)[/tex]

Using the distributive property, we can distribute the expression [tex]3x+1[/tex] to the terms [tex] x^{2} [/tex] and [tex]-6[/tex]:

[tex](3x+1)x^2-(3x+1)6[/tex]

Distributing again, we get:

[tex]3x(x^2)+x^2-3x(6)+6=3x^3+x^2-18x+6[/tex]

And we're done.


Evaluate u + xy, for u = 20, x = 9, and y = 8.

Answers

92 is your answer
20 + 9(8)

(50 POINTS) Hi, I really need help on this first part of my portfolio it was due last week but I don't really get this part so if someone could explain it to me I could get the other four parts done on my own.
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Use the City Populations table found on the message board and select a city that is experiencing population growth. Determine the percentage growth and use that to write an exponential function to represent the city’s population, y, based on the number of years that pass, x from 2010 (i.e. 2011 means that x = 1)

City: Portland, Oregon 585,256 593,939 603,026 609,456 619,334 630621 639863

This was deleted once and idk why there is plenty of information :(

Ik this is a lot to ask of someone but I haven't had any luck with any function sites.

Answers

hello im sorry ur question got answered so late but i beleive the answer is 585,256(1+.015)^x

Multiplying by a conjugate gives a rational number because (a + b)(a -
b.= _____.

Answers

Use foil.

(a+b)(a–b)
a^2 -ab +ab -b^2
a^2 – b^2

Hope I helped :)

You want to put a 5 inch thick layer of topsoil for a new 23 ft by 18 ft garden. the dirt store sells by the cubic yards. how many cubic yards will you need to order? the store only sells in increments of 1/4 cubic yards.

Answers

Answer:

You need to buy 6.5 cubic yards.

Step-by-step explanation:

You want to put a 5 inch thick layer of topsoil for a new 23 ft by 18 ft garden.

We know 1 yard = 3 feet or 1 yard = 36 inches

Then 1 inch = [tex]1/36[/tex] yard.

1 feet = 1/3 yard

The volume of the layer of the topsoil is given by:

= [tex]5(1/36)(23)(1/3)(18)(1/3)[/tex] cubic yards

[tex]2070/324=6.39[/tex] cubic yards

Now, the store only sells increments of 1/4 = 0.25 cubic yards.

So, we need to buy [tex]6.39/0.25=25.56[/tex] increments

Rounded to 26 increments.

Therefore, we need to buy 26 increments of 1/4 cubic yards.

That becomes 6.5 cubic yards.

how to graph the first derivative of this function

Answers

from -co to 0, the derivative is y=-2x and its domain is (-co,4]. Then y=-(x-2)/2 + 6 from (4,co)

Solve for t.

q=r+rst

Answers

t=(q-r)/rs

q=r+rst
subtract r from both sides
q-r=rst
divide rs from both sides
(q-r)/rs=t

Final answer:

The equation q=r+rst can be rearranged to isolate t, with the final solution being t=(q-r)/rs.

Explanation:

To solve for t in the equation q=r+rst, first, you need to isolate t on one side of the equation. You can do this by subtracting r from both sides so that you have q-r=rst. Next, divide both sides by rs, which gives you the final solution: t=(q-r)/rs.

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Consider this equation (csc x+1)/cot x = cot x/(csc x +1) is it an identity?

Answers

cross multiplying:-
cot^2 x = (csc x+ 1)(csc x + 1)

also  cot^2 x =  csc^2 x - 1  = (csc x + 1)(csc x - 1)  (Known Identitiy)

so the equation is not an identity

Describe how to draw a line that passes through the origin and has a slope of 3/5

Answers

The "origin" of a line is simply the points (0, 0)

To draw a line that passes through the origin (0, 0) & has a slope of 3/5, we simply start by drawing a point at (0, 0).

Then, from there, you use the slope to find your next points.

Slope = rise/run

So, 3 is the rise, and 5 is the run.

So, starting from (0, 0), you go up 3 times, and go to the right 5 times. So, (3, 5) is your next point. Just continue doing that and you'll get a line.

~Hope I helped!~

calculate the rate of change for the quadratic function over the given interval:
f(x)=x^2 + 4x +5 ; -4 =< x =< -2

Answers

The rate of change of the quadratic function over the interval −4≤x≤−2 is 2.

To find the rate of change of the quadratic function [tex]$f(x)=x^2+4 x+5$[/tex] , over the interval −4≤x≤−2, we need to find the average rate of change over that interval.

The average rate of change of a function f(x) over an interval [a,b] is given by:

[tex]Average Rate of Change =\frac{f(b)-f(a)}{b-a}$[/tex]

So, in this case:

a=−4

b=−2

We calculate f(−4) and f(−2):

[tex]$\begin{aligned} & f(-4)=(-4)^2+4(-4)+5=16-16+5=5 \\ & f(-2)=(-2)^2+4(-2)+5=4-8+5=1\end{aligned}$[/tex]

Now we can find the rate of change:

Rate of Change = [tex]$\frac{1-5}{-2-(-4)}=\frac{-4}{-2}=2$[/tex]

The average rate of change of the function f(x)=x² + 4x + 5 over the interval from x = -4 to x = -2 is -2.

The rate of change for the quadratic function f(x)=x² + 4x + 5 over the interval from x = -4 to x = -2 can be calculated using the average rate of change formula. This formula is given by:

Rate of Change = [f(x2) - f(x1)] / (x2 - x1)

Where x1 = -4 and x2 = -2. We first calculate f(-4) and f(-2) by plugging these values into the function:

f(-4) = (-4)² + 4(-4) + 5 = 16 - 16 + 5 = 5

f(-2) = (-2)² + 4(-2) + 5 = 4 - 8 + 5 = 1

Now we use these results in our rate of change formula:

Rate of Change = (1 - 5) / (-2 + 4) = -4 / 2 = -2

The average rate of change of the function f(x) over the interval from x = -4 to x = -2 is -2.

Find the equation of a line perpendicular to another line

Answers

You'll need to present the "other line" so that you have a reference.

If you start with y = mx + b, the slope of a line perpendicular to this line is -1/m.

Then the equation of the new line is    y = (-1/m)x + c, where c is the y-intercept of the new line.


Final answer:

To find the equation of a line perpendicular to another, determine the slope of the original line and use the negative reciprocal of that slope for the perpendicular line. Choose a point on the perpendicular line, and apply the point-slope form to get the equation.

Explanation:

The process of finding a perpendicular line involves first understanding the slope of the given line. To find the equation of a line that is perpendicular to another, you need to identify the slope (m) of the original line and use the fact that the slopes of perpendicular lines are negative reciprocals of each other (meaning if the slope of the first line is m, the slope of the line perpendicular to it will be -1/m). In the context of vectors and analytical methods in physics, components can help describe forces or directions. If we consider the example of a skier on a slope, breaking down the weight force into components parallel and perpendicular to the slope helps analyze the motion. However, for strictly finding a perpendicular line in mathematics, we focus on the slopes of the lines. Suppose you have the equation of the original line. If it is in the format y = mx + b, where m is the slope and b is the y-intercept, you can find the slope of the perpendicular line by taking the negative reciprocal of m. If the slope is not readily apparent, you might need to rearrange the equation into this format. Once you have the slope of the perpendicular line, choose a point through which the line passes (this could be the original point or any particular point you're given). Then, use the point-slope form (y - y1) = m(x - x1) to write the equation of the line.

The point p(x, y) on the unit circle that corresponds to a real number t is given. find the values of the indicated trigonometric function at t.

Answers

Unit circle : a circle with radius of one. Unit circle is centered at the origin.

Use the formula cot x = base / perpendicular, where x is the angle. Substituting x,y and t to the formula, we get cot (t) = x / y.

To find the trigonometric function values for a point on the unit circle corresponding to a real number t involves using the x and y coordinates, which are derived from the cosine and sine functions at that angle t.

The student's question involves finding the values of trigonometric functions for a point p(x, y) on the unit circle that corresponds to a real number t. This typically involves understanding the relationship between the coordinates of a point on the unit circle and the trigonometric functions sin, cos, and tan. In this context, x(t) and y(t) are understood as the x and y coordinates of a point on the unit circle at a certain angle t. The point p(x, y) would be given by the cosine and sine functions: x(t) = cos(t) and y(t) = sin(t). In more advanced contexts, these functions can take different forms like x(t) = A cos(wt + p) where A, w, and p are constants. The solution to trigonometric equations may involve differential equations or complex numbers in such cases.

Julia saw 5 times as many cars as trucks in a parking lot.if she saw 30 cars and trucks altogether in the parking lot,how many were trucks?

Answers

There were 6 trucks.

if you multiply 6 * 5 = 30.

Hopes this helps mark me as the Brainliest please.!!!!   

:) 

A probability experiment consists of rolling a fair 16​-sided die. Find the probability of the event below of rolling a 5.

Answers

Lets first consider how many different possibilities there are: 16 sided die means it has 16 different numbers.

Only one of the numbers is 5, so the probability is 1 out of 16 also written as: 1/16. 

So the probabilty of rolling a 5 is 1/16.

Muchas luck on your math!

Answer:

The probability of the event below of rolling a 5 is 0.0625.

Step-by-step explanation:

Given is : A probability experiment consists of rolling a fair 16​-sided die. Find the probability of the event below of rolling a 5.

Total number of faces = 16

So, there is only one way for rolling a 5 on a die

And the probability of rolling a 5 on a die = [tex]\frac{1}{16}[/tex]

= 0.0625

Both Pythagorean Theorem and trigonometric ratios are used with right triangles. Explain what information you need to apply to these different methods and include examples to show how to use each.

Answers

If given the value of an angle of the right triangle (aside from the 90° angle), then the trigonometric ratios will be more useful for solving for the sides of the triangle. One could use sin, cosin, and tangeant, the main trigonmetric ratios to solve for all sides and angles of the triangle, if given at least one angle and one side length. 

The Pythagorean Theorem as it is generally applied, helps solve for the third side of a triangle, given that you know the other 2 sides. This is less applicable, and trigonometric ratios can also be used in this case to solve for the rest of the triangle's angles and the third side. 
Final answer:

To apply the Pythagorean Theorem, you need the lengths of the two legs of a right triangle. Trigonometric ratios involve the angles and ratios of sides in a right triangle. Examples are provided for both methods.

Explanation:

In order to apply the Pythagorean Theorem, you need the lengths of the two legs of a right triangle. The theorem states that the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides. For example, if we have a triangle with legs of lengths 3 and 4, we can use the theorem to find the length of the hypotenuse. The square of the hypotenuse is 3^2 + 4^2 = 9 + 16 = 25, so the hypotenuse has a length of 5.

Trigonometric ratios, on the other hand, involve the angles of the right triangle and ratios of its sides. The three main trigonometric ratios are sine, cosine, and tangent. For example, if we have a right triangle with an angle of 30 degrees and one leg of length 5, we can use trigonometry to find the length of the other leg. The sine of the angle is given by the ratio of the opposite side (the leg we want to find) to the hypotenuse. So, sin(30 degrees) = opposite / hypotenuse = x / 5. Solving for x, we get x = 5 * sin(30 degrees) = 5 * 0.5 = 2.5.

This is a number that can be divided out of each term in an expression.

Answers

Answer:

Hello!

Great question!

The correct answer would be "Common Factor."

Step-by-step explanation:

It is a common factor when it is a factor of two (or more) numbers.

The number which can be divided out of each term in an expression is called the GCF or greatest common factor of that number.

What is GCF (greatest common factor)?

GCF or greatest common factor is the common number which all the term has in a group of terms. It is the number which can divide each number of the group.

For example, let a group of number as,

[tex]\{1,2,4,8,16\}[/tex]

The number which can be divided out of each term in this data is 16 which is the greater common factor of this data set.

Thus, the number which can be divided out of each term in an expression is called the GCF or greatest common factor of that number.

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What is the answer to this?

Answers

Greetings!

Simplify.
[tex]5mn(2m^3+n^2m)[/tex]
Distribute the Parenthesis.
[tex]5mn*2m^3+5mn*n^2m[/tex]
Simplify (Using Power Laws)
[tex]10m^4n+5mn*n^2m[/tex]
[tex]10m^4n+5m^2n^3[/tex]

Hope this helps.
-Benjamin

What is the simplified value of the expression below?

A.4.8
B.19.2
C.22.1
D.57.6

Answers

Remember your order of operation, and go from left to right

12/2 = 6
6 x 3.2 =  19.2
24 - 19.2 = 4.8

A. 4.8 is your answer

hope this helps

Answer: Option C i.e. 22.1 is correct


Step-by-step explanation:

The given expression follows pemdas rule

PEMDAS:

P for Paranthesis

E for Exponents

M for Multiplication

D for division

A for Addition

S for Subtraction

Given :24 -12 /2 *3.2

=  24-12/2*3.2     [Multiplication]

= 24- 12/6.4      [Division]

=24-1.875         [Subtraction]

=22.125

So the answer is C. 22.1

The distance d in feet that dropped object falls in t seconds is givin by the equation d divided 16 = tsquared how long does it take a dropped object to fall 64 feet

Answers

d / 16 = t^2

when d = 64

64 /16 = t^2

t^2 = 4 

t = 2     

answer is 2 seconds

Order numbers least to greatest, -1.6, 5/2, -7/8, 0.9, -6/5

Answers

-1.6 , -6/5 , -0.875, 0.9, 2.5

The negative number many seem high but since the greatest negative number is closer to zero it is higher than the other negative numbers.

Auto insurance options offered by AA Auto Insurance are outlined in the table below.  What monthly payment would you expect for an insurance policy through AA Auto Insurance with the following options? Bodily Injury:  $25/50,000 Property Damage:  $25,000 Collision:  $250 deductible Comprehensive:  $100 deductible
a.
$43.23
b.
$46.10
c.
$54.85
d.
$64.44


 

Answers

Option C. 54.85
22.5 + 120.5 + 415.25 + 100 = 658.25
658.25/12 = 54.854
round down and get answer c

In this exercise we have to use the knowledge of finance to calculate the monthly amount of insurance, so the best alternative that represents this amount is:

Option C

In this exercise we want to calculate the monthly insurance payment amount, so from the given values ​​we find:

[tex]Payment= (Bodily Injury)+ (Property Damage)+ (Collision)+(Comprehensive)[/tex]

Substituting the values ​​in the formula given above we find that:

[tex]Payment= 22.5 + 120.5 + 415.25 + 100 \\= 658.25\\658.25/12 = 54.854[/tex]

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A store sells an item for $180. This is 12/7 of their wholesale cost for the item. How much does the store mark the item up?

Answers

Make an algebraic formula:

12/7x = 180

Solving:

12/7x (7/12) = 180 * 7/12
x = 105

Hope this helps!

10(2y+2)−y=2(8y−8). please help me

Answers

10(2y+2)−y=2(8y−8)
                =
               12-

Factor the expression using the GCF. The expression 3y−24 factored using the GCF is

Answers

The GCF is three so it would be y-8.
take out a 3, you'll get
3(y-8)

What is the value of x in the figure below? In this diagram, ΔABD ~ ΔCAD.

Answers

The Answer would be [tex] \sqrt{45} [/tex] aka A i hope this helps

The value of x in the figure given is E. √70.

The answer is E. √70.

The two triangles are similar by the AAA Similarity Theorem, since they have two pairs of congruent angles, namely ∠ABD and ∠CAD, and ∠BAD and ∠CDA.

Since the triangles are similar, the ratio of corresponding sides is constant. In particular, the ratio of AD to CD is the same as the ratio of BD to AD.

We are given that AD = 14 and CD = 20, so the ratio of AD to CD is 14/20. We are also given that BD = x, so the ratio of BD to AD is x/14.

Setting these two ratios equal to each other, we get x/14 = 14/20, which simplifies to x = √70.

Here is a proof that shows why the two triangles are similar:

AAA Similarity: Triangles ABD and CAD have two pairs of congruent angles, namely <ADB> and <CAD>, because they are both right angles.

SSS Similarity: Triangles ABD and CAD have three pairs of corresponding sides that are proportional, namely AD/CD = 14/20, BD/AD = x/14, and AB/CD = √70/20. Therefore, the two triangles are similar by the SSS Similarity Theorem.

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Which number line represents the solutions to |x + 4| = 2?

Answers

The number line for [tex]\fbox{\begin\\\ \bf \text{option 1}\\\end{minispace}}[/tex] represents the solution for the equation [tex]|x+4|=2[/tex].

Further explanation:

The equation is given as follows:

[tex]|x+4|=2[/tex]

In the above equation [tex]||[/tex] represents the modulus function.

Modulus function is defined as a function which gives positive value of the function for any real value of [tex]x[/tex].

For example: The function [tex]y=|x|[/tex] is a modulus function in which [tex]y>0[/tex] and [tex]x<0[/tex] or [tex]x>0[/tex].

In the given equation [tex]|x+4|[/tex]  is a modulus expression.  

There are two cases formed for [tex]|x+4|[/tex].

First case:  [tex]x>-4[/tex]

If [tex]x>-4[/tex] then [tex]|x+4|\rightarrow (x+4)[/tex].

Substitute [tex]|x+4|=(x+4)[/tex] in [tex]|x+4|=2[/tex].

[tex]\begin{aligned}x+4&=2\\x&=2-4\\&=-2\end{aligned}[/tex]

Therefore, for [tex]x>-4[/tex] the value of [tex]x[/tex] which satisfies the equation [tex]|x+4|=2[/tex] is [tex]x=-2[/tex].

Second case:  [tex]x<-4[/tex]

If [tex]x<-4[/tex] then [tex]|x+4|\rightarrow -(x+4)[/tex].

Substitute [tex]|x+4|=-(x+4)[/tex] in [tex]|x+4|=2[/tex].

[tex]\begin{aligned}-(x+4)&=2\\-x-4&=2\\-x&=2+4\\-x&=6\\x&=-6\end{aligned}[/tex]

Therefore, for [tex]x<-4[/tex] the value of [tex]x[/tex] which satisfies the equation [tex]|x+4|=2[/tex] is [tex]x=-6[/tex].

This implies that the solution for the equation [tex]|x+4|=2[/tex] or the value of [tex]x[/tex] which satisfies the given equation are [tex]\fbox{\begin\\\ \math x=-2\ \text{and}\ x=-6\\\end{minispace}}[/tex].

Option 1:

The number line in option 1 shows that the solutions of the equation [tex]|x+4|=2[/tex] are [tex]x=-2[/tex] and [tex]x=-6[/tex].

As per our calculation made above the solutions for the equation [tex]|x+4|=2[/tex] are [tex]x=-2[/tex] and [tex]x=-6[/tex].

This implies that option 1 is correct.

Option 2:

The number line in option 2 shows that the solutions of the equation [tex]|x+4|=2[/tex] are [tex]x=2[/tex] and [tex]x=4[/tex].

As per our calculation made above the solutions for the equation [tex]|x+4|=2[/tex] are [tex]x=-2[/tex] and [tex]x=-6[/tex].

This implies that option 2 is incorrect.

Option 3:

The number line in option 3 shows that the solutions of the equation [tex]|x+4|=2[/tex] are [tex]x=2[/tex] and [tex]x=6[/tex].

As per our calculation made above the solutions for the equation [tex]|x+4|=2[/tex] are [tex]x=-2[/tex] and [tex]x=-6[/tex].

This implies that option 3 is incorrect.

Option 4:

The number line in option 4 shows that the solutions of the equation [tex]|x+4|=2[/tex] are [tex]x=-2[/tex] and [tex]x=-4[/tex].

As per our calculation made above the solutions for the equation [tex]|x+4|=2[/tex] are [tex]x=-2[/tex] and [tex]x=-6[/tex].

This implies that option 4 is incorrect.

Therefore, the number line for [tex]\fbox{\begin\\\ \bf \text{option 1}\\\end{minispace}}[/tex] represents the solution for the equation [tex]|x+4|=2[/tex].

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Answer details:

Grade: High school

Subject: Mathematics

Chapter: Functions

Keywords: Functions, modulus, modulus function, number line, real line, |x+4|=2, equation, root, zeroes, solutions,  absolute function, x=-6 and x=-2.

Option A is correct, the values of [tex]x[/tex] staisfying the given equation [tex]|x+4|=2[/tex] are [tex]-2[/tex] and [tex]-6[/tex].

Modulus function always returns a positive value to the equation.

Here, [tex]|x+4|[/tex] will give positive result if [tex]x>-4[/tex] and negative value if, [tex]x<-4[/tex].

Case 1: When [tex]x>-4[/tex]

According to the given equation,

[tex]|x+4|=2\\x=2-4\\x=-2[/tex]

So, the value of [tex]x[/tex] which satisfies the given equation [tex]|x+4|=2[/tex] for [tex]x>-4[/tex] is [tex]x=-2[/tex].

Case 2: When [tex]x<-4[/tex]

According to the given equation,

[tex]|x+4|=2\\-x-4=2\\x=-6[/tex]

So, the value of [tex]x[/tex] which satisfies the given equation [tex]|x+4|=2[/tex] for [tex]x<-4[/tex] is [tex]x=-6[/tex].

Hence, the values of [tex]x[/tex] staisfying the given equation [tex]|x+4|=2[/tex] are [tex]-2[/tex] and [tex]-6[/tex].

Now, according to the options, Option A is correct.

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A line goes through the points (8,9) and (2,4).

What is the slope of the line?

Write the equation of the line in point-slope form?

Write the equation of the line in slope-intercept form?

Answers

9-4/8-2
5/6
The slope is 5/6
y-4=5/6(x-2)
y-4=5/6x-5/3
y=5/6x+7/3
The equation of line in point-slope is y - 4 = 5/6(x - 2)
The equation of the line in slope-intercept is y = 5/6x + 7/3

If f(x) = 3x2 - x, find f(-2).

10
14
38

Answers

f(x) = 3x^2-x

F(-2)

 replace x with -2

3(-2)^2 - -2 =

3*4 +2 = 14

 Answer is 14


'Ello. 

Just plug in the values.
 
f(-2) = 3(-2)^2 - (-2) {Equation}
f(-2) = 3(4) - (-2) {Multiply}
f(-2) = 12 - (-2) {The signs become a positive; add}
f(-2) = 14 {Answer}

You're welcome. 
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