The human body obtains 955 kJ of energy from a candy bar.? If this energy were used to vaporize water at 100.0 ∘C, how much water (in liters) could be vaporized? (Assume the density of water is 1.00 g/mL.)

Answers

Answer 1

Final answer:

Using the enthalpy of vaporization for water, the energy from a candy bar could vaporize approximately 0.421 liters of water at 100°C.

Explanation:

To determine how much water could be vaporized from the energy obtained from a candy bar, we need to use the enthalpy of vaporization of water at 100°C, which is given as 40.7 kJ/mol. This value tells us the amount of energy needed to convert one mole of water from liquid to gas at these conditions.

First, we convert the energy in kJ from the candy bar to moles of water using the enthalpy of vaporization:

955 kJ × (1 mol / 40.7 kJ) = 23.46 moles of water

Next, we'll convert the moles of water to grams since we know the molar mass of water is approximately 18 g/mol:

23.46 moles × 18 g/mol = 421.28 grams of water

Finally, given that the density of water is 1.00 g/mL and that 1 liter equals 1000 mL, we convert grams to liters:

421.28 g × (1 mL / 1 g) × (1 L / 1000 mL) = 0.421 L of water

Therefore, the energy from the candy bar could vaporize approximately 0.421 liters of water.


Related Questions

Nonmetals tend to form what kind of ions?

Answers

Nonmetals form High ionization properties.

How many bonding electrons are in the lewis structure of carbon monoxide, co?

Answers

There are six (6) bonding electrons are in the lewis structure of carbon monoxide (CO).
In Lewis structure, there are ten (10) valence electrons of Carbon monoxide (CO). For lewis structure we need a triple bond between carbon and oxygen, so when electrons made a triple bond it means there is six bonding electrons in lewis structure of carbon monoxide.

Answer:

6

Explanation:

The Lewis structure represents the valence electrons at the atoms, which ones are shared and the lone pairs. Carbon is at group 4 at the periodic table, and so has 4 electrons in the valence shell; oxygen is at group 6, and so has 6 electrons at the valence shell.

That compound is an exception of the octet rule. A triple bond is done between the atoms, and so, 3 electrons of carbon are shared and 3 electrons of oxygen are shared. Thus, there are 6 bonding electrons, as shown below in red.

How many molecules of water are needed to completely hydrolyze a polymer that is 11 monomers long?

Answers

10 molecules of water are needed.

Ten molecules of water are required to completely hydrolyze a polymer of 11 monomers.

What is a polymer?

A polymer can be described as a macromolecule which essentially is a combination of many subunits. From Polypropylene which is used widely around the world as plastic to the strand of our DNA, which is a naturally occurring biopolymer.

Polymers can be naturally found in plants and animals called natural polymers or can be man-made called synthetic polymers. Different types of polymers posses different physical and chemical properties.

Semisynthetic polymers are those which can be derived from naturally occurring polymers and can undergo further modification such as cellulose nitrate, and cellulose acetate.

Polymers can be broken down into monomers is called hydrolysis of polymer, which is a reaction in which a water molecule is utilized during the breakdown.

Given polymer has 11 monomers which are connected with each other through 10 bond links that can be broken by ten water molecules.

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What substance is needed to reverse a condensation reaction?

Answers

Like we can use steam,300C temperature,60-70 atm and phosphoric acid which convert the ethene to alcohol which hydration reaction reverse of condensation reaction

Sally is measuring the weight of a sodium chloride crystal. the scale indicates the crystal weighs 10.0010 g. how many significant figures are in this measurement?

Answers

Actually there are three established rules on counting how many significant figures are in a number:

Rule 1: Positive integers are always significant.

Rule 2: Any zeros between two significant digits are always significant.

Rule 3: A final zero or trailing zeros after the decimal point are always significant.

 

Since the given number is 10.0010 g, the two 1’s is under Rule 1, the three 0’s between the two 1’s is under Rule 2, and the zero after the last 1 is under Rule 3. Therefore all the digits are significant.


Answer: So the number of significant figures in the measurement is 6.

What is one of the products produced when al(no3)3 and cao react together? alo2 cano3 al2o3 ca(no3)3?

Answers

The chemical balanced equation for the given question is this:
2AL[NO3]3 + 3CaO = AL2O3 + 3Ca[NO3]2.
So, one of the product formed is AI2O3. The other product is Ca[NO3]2.
The reaction is a double replacement reaction.

Answer: Option (c) is the correct answer.

Explanation:

When [tex]Al(NO_{3})_{3}[/tex] reacts with CaO then it results in the formation of aluminium oxide and calcium nitrate.

The chemical reaction equation will be as follows.

[tex]2Al(NO_{3})_{3} + 3CaO \rightarrow Al_{2}O_{3} + 3Ca(NO_{3})_{2}[/tex]

Thus, we can conclude that out of the given options [tex]Al_{2}O_{3}[/tex] is one of the products produced when [tex]Al(NO_{3})_{3}[/tex] and CaO react together.


Does the entropy (△S) increase or decrease in each of the following processes? The wind blows a pile of leaves all over the yard. As you are pumping gas into your car, gas fumes escape into the air. a. decreasing decreasing b. increasing decreasing c. decreasing increasing d. increasing increasing

Answers

B, increasing decreasing is my opinion

A blood sample is diluted by placing 0.2ml of the blood in a tube and filling the tube to the 5ml mark with a solution. what percent of the solution represents whole blood?

Answers

v₀=0.2 ml
v=5 mL

a=100v₀/v

a=100×0.2/5=4%

4%

If Uranium-234 decays via alpha emission, what is the likely product of radioactive decay? (U, atomic no. = 92)

Answers

An alpha emission is one in which an atomic nucleus emits an alpha particle (helium nucleus). Therefore in this reaction, the products of the decay are Helium and another element X. Helium has an atomic mass and atomic number of 4 and 2 respectively, therefore the complete reaction is:

U-234 (92) ---> He-4 (2) + X

Since atomic mass and number must be conserved therefore X = X-230 (90)

U-234 (92) ---> He-4 (2) + X-230 (90)

The element with atomic number of 90 is Thorium. Therefore the other product is Thorium-230 (90).

U-234 (92) ---> He-4 (2) + Th-230 (90)

What group of elements generally have the lowest second ionization energy?

Answers

Answer: Group 2: alkaline earth metals.
Explanation: The second ionization energy is the energy required so that the molecule in the gaseous state would lose its second valence electron. Since all atoms tend to stabilize by having complete number of electrons in the valence shell (octet rule), thus, the elements having the lowest second ionozation energy will be those having 2 electrons in the outermost shell (the first ionozation energy removes the first outermost electron while the second ionozation energy removes the second one , thus, turning the atom into the stable state)

A solution is made by dissolving 25.5 grams of glucose (C6H12O6) in 398 grams of water. What is the freezing point depression of the solvent if the freezing point constant is -1.86 °C/m? Show all of the work needed to solve this problem. 

Please help!

Answers

The freezing point depression is a coligative property.

The formula for the freezing point depression is:

ΔTf = Kf * m

Where m is the molality and Kf is the cryoscopic constant.

Kf of water is 1.86 °C / m

m = moles of solute / kg of solvent

moles of solute = mass in grams / molar mass

molar mass of C6H12O6 = 6*12g/mol + 12*1g/mol + 6*16g/mol = 180 g/mol

moles of C6H12O6 = 25.5 g / 180 g/mol = 0.14167 mol

m = 0.14167 mol / 0.398 kg = 0.3559 m

=> ΔT = 1.86°C/m * 0.3559m = 0.66°C

Answer: 0.66°C


How many chlorine atoms are in 5.0 g chloral hydrate?

Answers

To determine the number of chlorine atoms from the given amount of chloral hydrate, first, we need to know the formula and the molar mass of this compound. Chloral hydrate has a chemical formula C2H3Cl3O2 and a molar mass of 165.4 g/mol. Then, we convert the mass of the compound to moles by the molar mass. Next, we calculate for the amount in moles of Cl in the compound. Lastly, we use Avogadro's number to determine the number of chlorine atoms in the compound. We calculate as follows:

5.0 g C2H3Cl3O2 ( 1 mol C2H3Cl3O2 / 165.4 g C2H3Cl3O2) ( 35.46x10^2 mol Cl / 1 mol C2H3Cl3O2 ) ( 6.022 x10^23 Cl atoms / 1 mol Cl ) = 5.46 x 10^22 atoms of Cl
Final answer:

To find the number of chlorine atoms in 5.0 g of chloral hydrate, calculate the moles of chloral hydrate and then use Avogadro's number to find the atoms. There are approximately 5.46 x 10²² chlorine atoms in 5.0 g of chloral hydrate.

Explanation:

The question asks us to determine the number of chlorine atoms in 5.0 g of chloral hydrate. To find this, we need the molar mass of chloral hydrate (C₂H₃Cl₃O₂) and the molar mass of chlorine. The atomic mass of chlorine is 35.45 u. Chloral hydrate contains three chlorine atoms per molecule.

First, calculate the molar mass of chloral hydrate:

C (12.01 u) x 2 = 24.02 uH (1.008 u) x 3 = 3.024 uCl (35.45 u) x 3 = 106.35 uO (16.00 u) x 2 = 32.00 u

Total molar mass = 165.394 u.

Next, we calculate the amount (in moles) of chloral hydrate:

5.0 g / 165.394 g/mol = 0.0302 mol. Since each molecule of chloral hydrate contains three chlorine atoms, we multiply the number of moles by Avogadro's number (6.022 x 10²³ atoms/mol) and then by three:

0.0302 mol x 3 x 6.022 x 10²³ atoms/mol = 5.46 x 10²²  chlorine atoms.

Therefore, there are approximately 5.46 x 10²² chlorine atoms in 5.0 g of chloral hydrate.

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If the theoretical yield of the reaction below corresponds to 25.3 g and the percent yield of the reaction is known to be reproducibly 81.1%, calculate the actual yield. given: li2o + h2o → 2 lioh 81.1 g 48.9 g 20.5 g 45.8 g none of the above

Answers

The actual yield is computed by multiplying the theoretical yield by the decimal equivalent of the given yield of reaction.
That is,
Actual yield = (Theoretical Yield) x (Percent Yield of reaction)
Actual yield = (25.3 g) x (0.811)
Actual yield = 20.51 g

Hence, the actual yield is approximately 20.5g and the answer is the third choice. 

A volume of 90.0 ml of aqueous potassium hydroxide (koh) was titrated against a standard solution of sulfuric acid (h2so4). what was the molarity of the koh solution if 13.7 ml of 1.50 m h2so4 was needed? the equation is

Answers

2KOH + H₂SO₄ → K₂SO₄ + 2H₂O

v₁=90.0 mL
c₁-?
v₂=13.7 mL
c₂=1.50 mol/L=1.50 mmol/mL

n(KOH)=v₁c₁
n(H₂SO₄)=v₂c₂
n(KOH)=2n(H₂SO₄)

v₁c₁=2v₂c₂

c₁=2v₂c₂/v₁

c₁=2*13.7*1.50/90.0=0.457 mol/L

0.457 M KOH

How many liters of water must be added to 5.40 g of sodium nitrate to create a solution that has a concentration of 3.81 g/L?

Answers

Hey there !

Mass of solute = 5.40 g

Concentration = 3.81 g/L

Volume =  ?

therefore :

C = m / V

3.81 = 5.40 / V

V = 5.40 / 3.81

V = 1.417 L

Answer: The volume of water that must be added will be 1.417 L.

Explanation:

Concentration of a substance is defined as mass of solute (in grams) present in the given volume of a solution (in L).

The equation representing concentration is given as:

[tex]\text{Concentration of solute}=\frac{\text{Mass of solute}}{\text{Volume of solvent}}[/tex]

We are given:

Concentration = 3.81 g/L

Mass of sodium nitrate = 5.40 g

Putting values in above equation, we get:

[tex]3.81g/L=\frac{5.40g}{\text{Volume of water}}\\\\\text{Volume of water}=1.417L[/tex]

Hence, the volume of water that must be added will be 1.417 L.

How many moles of hydrogen gas would be needed to react with excess carbon dioxide to produce 30.6 moles of water vapor?

Answers

Final answer:

To produce 30.6 moles of water vapor from the reaction of hydrogen gas with excess carbon dioxide, 30.6 moles of hydrogen gas are required according to the balanced chemical equation with a 1:1 molar ratio of hydrogen to water.

Explanation:

To determine how many moles of hydrogen gas would be needed to react with excess carbon dioxide to produce 30.6 moles of water vapor, we need the balanced chemical equation for the reaction between hydrogen gas (H2) and carbon dioxide (CO2) to produce water (H2O) and carbon monoxide (CO).

To determine the number of moles of hydrogen gas needed to react with excess carbon dioxide to produce 30.6 moles of water vapor, we need to use the balanced chemical equation for the reaction.

The balanced equation is:

2H2(g) + CO2(g) -> 2H2O(g)

From the equation, we can see that 2 moles of hydrogen gas react with 1 mole of carbon dioxide to produce 2 moles of water vapor. Therefore, the ratio of hydrogen gas to water vapor is 2:2.

Since we are given that 30.6 moles of water vapor are produced, we can calculate the moles of hydrogen gas as:

(30.6 moles of water vapor) x (2 moles of hydrogen gas / 2 moles of water vapor) = 30.6 moles

Therefore, 30.6 moles of hydrogen gas would be needed to react with excess carbon dioxide to produce 30.6 moles of water vapor.

H2(g) + CO2(g) → H2O(g) + CO(g)

From the balanced equation, we see that the molar ratio of hydrogen gas to water vapor is 1:1. Therefore, to produce 30.6 moles of water vapor, 30.6 moles of hydrogen gas are needed:

30.6 moles H2O × 1 mole H2/1 mole H2O = 30.6 moles H2

Thus, 30.6 moles of hydrogen gas are required to react with excess carbon dioxide to produce 30.6 moles of water vapour.

a commercial refrigeration unit accidentally releases (6.05x10^1) ml of ammonia gas at satp determine the mass and number of molecules of ammonia released

Answers

The volume given likely has an error, but I will work with it to show you how to solve this problem, so you will be able to find the right answer using the same procedure.

V = 6.05 * 10 ml = 0.00605 l

SATP => T = 373.15 K, P = 1 atm

pV = nRT => n = pV / RT

R = 0.0821 atm*l / (K*mol)

n = 1 atm * 0.00605 l / [ (0.0821 atm * l / K*mol) * 273.15 K] = 0.00026978 mol

So, the number of molecules is the number of moles times Avogadro's number:

0.0026978mol = 0.0026978 * 6.022*10^23 molecules = 1.6225 * 10^ 21 molecules

The mass is found using mass = molar mass * number of moles

Ammonia gas = NH3 => molar mass = 14 g/mol + 3 * 1g/mol = 17 g/mol

Mass = 17 g/mol * 0.0026978 mol = 0.4586 g.

With that procedure, you just have to replace the right volume of ammonia.

Can someone please help me:)
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A radon atom has 86 protons, 136 neutrons, and 86 electrons. What will it change to during alpha decay?

An astatine atom with 85 protons, 137 neutrons, and 86 electrons
A francium atom with 87 protons, 135 neutrons, and 86 electrons
A polonium atom with 84 protons, 134 neutrons, and 86 electrons
A radon atom with 86 protons, 136 neutrons, and 85 electrons

Answers

We have here Radon Rn with mass number = 86 protons + 136 neutrons = 222. Therefore, we have Rn222. The alpha radiation emits particles in the same size of the He atom whose mass number equals 4. By subtracting 4 from 222 we get 218 which is the mass number of Polonium Po218 with 84 protons and 134 neutrons.
Therefore, the right answer is C.

Determine the molar solubility of baf2 in pure water. ksp for baf2 = 2.45 x 10-5. 1.83 x 10-2 m 1.23 x 10-5 m 2.90 x 10-2 m 4.95 x 10-3 m 6.13 x 10-6 m

Answers

The Molar solubility of baf2 in pure water is 1.83 x 10⁽₋₂⁾ if ksp for baf2 = 2.45 x 10⁻⁵.
solubility product equilibrium reaction from the balance equation of reaction is:
k₍sp₎ = [Ba⁺²] [F⁻]²
using mole ratios from one to another, [Ba⁺²] = x and  [F⁻]² = 2x
k₍sp₎ = [Ba⁺²] [F⁻]²
k₍sp₎ = [x][2x]²
ksp = 2.45 x 10⁻⁵ then,
2.45 x 10⁻⁵  =  [x][2x]²
4x³ = 2.45 x 10⁻⁵
x = ∛(2.45 x 10⁻⁵)/4 = 1.83 x 10⁻²m
so, x is molar solubility which is 1.83 x 10⁻²m

Final answer:

The molar solubility of BaF2 in pure water is approximately 6.13 x 10⁻⁶ M.

Explanation:

The molar solubility of BaF2 in pure water can be calculated using the solubility product constant (Ksp) of BaF2. The equation for the dissolution of BaF2 is BaF2 → Ba²+ + 2F¯. The Ksp expression for BaF2 is Ksp = [Ba²+][F¯]². Since there is a 1:2 stoichiometric relationship between BaF2 and fluoride ions in solution, the molar solubility of BaF2 can be represented as x, which gives the concentrations of Ba²+ and F¯ as x and 2x, respectively. Substituting these values into the Ksp expression, we get:

Ksp = (x)(2x)² = 4x³ = 2.45 x 10⁻⁵

Solving for x, we find that the molar solubility of BaF2 in pure water is approximately 6.13 x 10⁻⁶ M.

When sodium chloride reacts with silver nitrate, silver chloride precipitates. what mass of agcl is produced from 75.00 g of agno3?

Answers

We first need to know that At. wt. of Silver(Ag) = 108amu
Then 1 mol AgNO³ replaces 1 mol AgCl
i.e. 170gm AgNO³ gives 143.5gm AgCl
So using unitary method, 75gm AgNO³ gives 63.31gm AgCl

To calculate the atoms of an element in a given molecule, we need to multiply stoichiometry by the number that is written on the foot of that element. Therefore, the mass of  AgCl produced from 75.00 g of AgNO[tex]_3[/tex]. is 63.0g.

What is stoichiometry?

Stoichiometry is a part of chemistry that help us in making relationship between reactant and product from quantitative aspects.

The balanced reaction is  

NaCl + AgNO[tex]_3[/tex] → NaNO[tex]_3[/tex] + AgCl

Mass of AgNO[tex]_3[/tex]=75.00 g

Molar mass of AgNO[tex]_3[/tex]=169.87 g/mol

Moles of AgNO[tex]_3[/tex]=0.44mol

From 1 mole of  AgNO[tex]_3[/tex], 1 mole of  AgCl is produced.

So, from 0.44 of AgNO[tex]_3[/tex], 0.44 mole of AgCl  is produced.

Mass of AgCl =Molar mass of AgCl ×moles of AgCl

Mass of AgCl =143.32 g/mol  ×0.44 mole

Mass of AgCl =143.32 g/mol  ×0.44 mole

Mass of AgCl =63.0g

Therefore, the mass of  AgCl produced from 75.00 g of AgNO[tex]_3[/tex]. is 63.0g.

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What is the correct formula for calcium cyanide?

A. Ca2CN
B. CN(Ca)2
C. Ca(CN)2
D. CaCN

Answers

C.  Ca(CN)₂
____________________________________________

What is the density of sulfur dioxide (so2) at 1.2 atmospheres and 271 kelvin? show all of the work used to solve this problem?

Answers

density = mass/V = MW P / RT
density = 64.1 g/mol X 1.2 atm / 0.0821 Latm/molK (271K) = 3.46 g/L
Final answer:

To find the density of sulfur dioxide (SO2) at 1.2 atmospheres and 271 Kelvin, we can use the ideal gas law equation. We need to know the molar mass of sulfur dioxide, which is 64.06 g/mol. Using the ideal gas law equation, we can calculate the volume of SO2 and find the density.

Explanation:

To find the density of sulfur dioxide (SO2) at 1.2 atmospheres and 271 Kelvin, we can use the ideal gas law equation:

density = (mass of SO2) / (volume of SO2)

We need to know the molar mass of sulfur dioxide, which is 64.06 g/mol. We also need to convert the given pressure to Pascals (Pa) and temperature to Kelvin (K).

Using the ideal gas law equation, we can calculate the volume of SO2:

volume of SO2 = (mass of SO2) / (density)

Finally, we substitute the given values into the equation to find the density:

density = mass of SO2 / volume of SO2

How did the discoveries of scandium (sc) and germanium (ge) affect mendeleevâs work?

Answers

they showed mandeleeves predictions were correct

The pharmacy receives a prescription for 50 grams of 5% salicylic acid ointment. the pharmacy has a 30% salicylic acid ointment and petrolatum available. using only these products, how much petrolatum should be used to compound the prescription? express the answer in grams. (answer must be numeric; no units or commas; include leading zero when answer is less than 1; round the final answer to the nearest one decimal place.)

Answers

In this problem, we can formulate two equations.

First, the overall mass balance of the ointment. The mass of 30% salicylic acid ointment plus the mass of petrolatum must be 50 grams.

x + p = 50

Where x is the mass of 30% salicylic acid ointment and p is the mass of petrolatum

Second, the component mass balance of salicylic acid:

0.3 * x = 50 * 0.05

x = 8.33 g

Therefore the mass of petrolatum to be used is:

x + p = 50

p = 50 – x

p = 50 – 8.33

p = 41.67 g

 

Answer:

41.7

The mass defect is the result of what action occurring?

A. energy being converted into moles of atoms when neutrons break apart protons

B. mass being converted to energy when protons and neutrons bind together in a nucleus

C. mass being converted to energy when protons and neutrons break apart in a nucleus

D. protons and electrons being attracted to each other

E. strong forces overcoming weak forces

Answers

B. mass being converted to energy when protons and neutrons bind together in a nucleus
Answer;

B. mass being converted to energy when protons and neutrons bind together in a nucleus

Explanation;The mass defect of a nucleus refers to the mass of the energy binding the nucleus. This energy is given by the difference between the mass of a nucleus and the sum of the masses of the nucleons of which it is composed.Mass defect is energy mass that is removed from the total mass of the original particles when a nucleus is formed. This mass is missing in the resulting nucleus and represent the energy lost when the nucleus is formed.

Which would be most likely be the pH of a highly-corrosive acid?

a) 1
b) 5
c) 8
D) 11

Answers

1
the lower the number the higher the ph and the more acidic it is
I believe that it will be 1?

A Term that describes a group of diseases caused by mutations and different genes

Answers

Genetic & Pediatric Diseases

or maybe you're looking for a word like 

Haplotype

The boiling point of a solution will ______ and the vapor pressure will _______ with a(n)_____ in the amount of dissolved solute.

Answers

This is about the colligative property of a solution. The boiling point, vapor pressure and freezing point are affected when solute is added to the solution. These colligative properties are called boiling point elevation, vapor pressure lowering and freezing point depression. These properties are affected by the amount of the solute, not by its identity. Thus, the complete answer to the statement is

The boiling point of a solution will increase and the vapor pressure will decrease with a(n)increase in the amount of dissolved solute.

3. The bonds between hydrogen and oxygen in water differ from the bonds between hydrogen and carbon in carbohydrates. How and why do these bonds differ?

Answers

Because they are different elements have different number of protons and neutrons........ I guessed do not trust me...

In a strong acid–strong base titration (both monoprotic), if 25.0 milliliters of the base is required to completely neutralize 25.0 milliliters of the acid, which of the following conclusions can you make?
A)The concentartion of the acid is higher than that of the base.
B)The concentration of the acid is the same as that of the base.
C)The concentration of the base is higher than that of the acid.
D)The equivalence point will occur arround a pH of 2.5.

Answers

B)The concentration of the acid (C₁) is the same as that of the base (C₂).

V₁=V₂

n(acid)=C₁V₁
n(base)=C₂V₂

HX + YOH = YX + H₂O

n(acid)=n(base)

C₁V₁=C₂V₂

C₁=C₂

The concentration of the acid is the same as that of the base.

If equal volumes of acid and base are required, you can conclude that the concentrations must be the same.

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