The gas in a cylinder has a volume of 8 liters at a pressure of 101 kPa. The pressure of the gas is increased to 213 kPa. Assuming the temperature remains constant, what would the new volume be?



Please show your work, thanks!

Answers

Answer 1
We'll use the Ideal Gas Law.

Before:
[tex]p_1V_1=n_1RT_1\\\\ (101\times10^{3})\cdot8=n_1RT_1\\\\ n_1RT_1=808\times10^3~~~(i)[/tex]

After:
[tex]p_2V_2=n_2RT_2\\\\ (213\times10^3)\cdot V_2=n_2RT_2~~~(ii)[/tex]

Since the quantity of gas wasn't changed, [tex]n_1=n_2=n[/tex]. Furthermore, the temperature remains constant, so [tex]T_1=T_2=T[/tex]. Then, the expressions that were find are:

[tex]nRT=808\times10^3~~~(i)\\\\ nRT=(213\times10^3)\cdot V_2~~~(ii)[/tex]

Dividing them:

[tex]\dfrac{nRT}{nRT}=\dfrac{808\times10^3}{(213\times10^3)\cdot V_2}\\\\ 1=\dfrac{808}{213\cdot V_2}\\\\ 213V_2=808\\\\ V_2=\dfrac{808}{213}\\\\ \boxed{V_2\approx 3.79~L}[/tex]
Answer 2
Hello! 

Data:

Vo (initial volume) = 8 L
V (final volume) = ?
Po (initial pressure) = 101 kPa
P (final pressure) = 213 kPa 

We have an isothermal transformation, that is, its temperature remains constant, if the volume of the gas in the container decreases, so its pressure increases. Applying the data to the formula, we have:

[tex]P_0*V_0 = P*V[/tex]

[tex]101*8 = 213*V[/tex]

[tex]808 = 213V[/tex]

[tex]213V = 808[/tex]

[tex]V = \dfrac{808}{213} [/tex]

[tex]\boxed{\boxed{V \approx 3,79\:L}}\end{array}}\qquad\checkmark[/tex]

I Hope this helps, greetings ... DexteR!

Related Questions

In the important industrial process for producing ammonia (the Haber Process), the overall reaction is: N2(g) + 3H2(g) → 2NH3(g) + 100.4 kJ A yield of NH3 of approximately 98% can be obtained at 200°C and 1,000 atmospheres of pressure. This reaction is:

exothermic
endothermic

Answers

Endothermic i think? Using Le Chât's principle

Answer:

Exothermic

Explanation:

From the perspective of thermodynamics, chemical reactions can be broadly

classified as endothermic and exothermic reactions.

Endothermic reactions are accompanied by the absorption of heat and have a negative value for the reaction enthalpy i.e. ΔH is negative. In contrast, exothermic reactions are accompanied by the release of heat and have a positive value for the reaction enthalpy i.e. ΔH is positive.

The given reaction is:

[tex]N2(g) + 3H2(g)---- 2NH3(g) + 100.4 kJ[/tex]

Based on the above reaction, production of NH3 is accompanied by the release of 100.4 kJ of heat, hence this is an exothermic reaction.

Which of these redox reactions is spontaneous as written?


Pb + Fe3+ → Pb2+ + Fe



Fe + Mg2+ → Fe3+ + Mg



H2 + Al3+ → H+ + Al



Zn + Ag+ → Zn2+ + Ag

Answers

Answer:

Zn + Ag+ → Zn2+ + Ag

Explanation:

Plato

The statement of the redox reactions is spontaneous as "[tex]Zn + Ag^{+}[/tex]→ [tex]Zn^{2+} + Ag[/tex] ".

What is redox reaction?

A redox reaction is the process in which electrons are exchanged between two reactants that are involved. The oxidation number of a molecule, atom, or ion varies as a result of gaining or losing an electron.

If the standard electrode potential for the redox reaction, [tex]E^{0}[/tex], is positive, the redox reaction is spontaneous. That means, the reaction will move forward if [tex]E^{0}[/tex] is positive. In this reaction, silver ion is the oxidizing agent that readily accepts the electron to attain (stable configuration) the metal state, while Zn is a reducing agent which loses electrons (i.e., oxidized) by causing a reduction. It proceeds with[tex]E^{0}[/tex] redox reaction as given, the reaction moves forward and is considered to be spontaneous.

Hence the correct answer is [tex]Zn + Ag^{+}[/tex] → [tex]Zn^{2+} + Ag[/tex].

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How much energy is required to melt a 500. gram block of iron? The heat of vaporization is 6090 J/g and the heat of fusion is 247 J/g.

Answers

Since we have to MELT the iron, heat of fusion will be used.
So, energy required = 247 * 500 J
= 123500 J.

Intrusive igneous rocks _____. form from confining pressure cool quickly on Earth's surface cool slowly beneath Earth's surface form layers called foliations

Answers

Answer:cool slowly beneath Earths surface

Explanation:

Answer:

cool slowly beneath Earth's surface

Explanation:

exhaled air contains 16% oxygen by volume. Assuming you exhale like the average person does during strenuous exercise (that is, you exhale 1L of air per breath and you exhale 40 breaths per minute) ad assuming the dive will take 90 minutes, what volume of oxygen will you end up exhaling?

Answers

Exhaled air for 90 minutes would be 40 breaths per minute (at 1 litre per breath) x 90 minutes =3600 litres x 0.16= 576 litres of oxygen, In other words, first work out the amount of air breathed out in litres/minute and then multipy by the number of minutes to get the total litres of air breathed out and then multiply that figure by 0.16 (16 % oxygen per volume of air) to get total litres of oxygen breathed out.

What percent of the energy used produced radioactive waste

Answers

Your Question isn't clear to me. Please rephrase that.
 

The higher the percentage of the active ingredient in a drug

Answers

Basically, the higher the percentage of the active ingredient in a drug, the more quickly it will reach the blood stream.

For example, when making a tablets, the active and the inactive ingredients are mixed together to form small grains and compressed into tablets. How quickly the drug reach the bloodstream depends on the type and amount of addictive in the drug, and the degree of compression.  

Further Explanation

The drug is the active ingredients while the addictive is the inactive ingredients. The chemical substances consumed in order to produce a desired effect is the active ingredients and the addictive such as stabilizers, diluents, lubricants are mixed together with the drug so that the drugs can be swallowed easily. The inactive ingredients also help in the breaking down of the drug in the gastrointestinal tract.

Drug absorption refers to the movement of drug into the bloodstream and how quickly it will reach its intended site depends on several factors.

Some of the factors include:

the ingredients it contains (active and inactive), the drug physical and chemical properties, how the drug is stored and how it is manufactured.

However, Drug dosage can be in a form of capsules, a tablet, solution or transdermal patch. It is made up of the drug and addictive.  

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active ingredient in a drug https://brainly.com/question/7197859

KEYWORDS:

active ingredientsinactive ingredientsdrugtabletscapsulesbloodstream

Basically, a drug will enter the blood stream more quickly the larger the amount of the active ingredient is.

What are drugs?

Drugs are defined as any chemical that, when taken, alters the physiology or psychology of an organism. They might affect how your brain works, as well as your emotions, conduct, comprehension, and senses.They are therefore erratic and harmful, particularly for children. Drug effects vary depending on the user and the substance.

The active components of the drug are different from the inactive components that make it addictive. The addictive substances such as stabilizers, diluents, and lubricants are combined with the medicine to make it easier to swallow, while the active ingredients are ingested to create the intended effect. The drug's breakdown in the digestive system is also aided by the inactive components.

Thus, basically, a drug will enter the blood stream more quickly the larger the amount of the active ingredient is.

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If two cars get a 4 way stop intersection at the same time, which car should be yeiled the right of way

Answers

At a four-way stop if 4 vehicles reach the intersection simultaneously, the vehicle on the left must yield the right-of-way to the vehicle on the right. So right side goes first.

If two cars get a 4 way stop intersection at the same time, the car on the right should be yielded the right of way. This is known as the "right-of-way rule."

The right-of-way rule is a traffic law that determines which vehicle has the right to proceed first at an intersection.

-When two vehicles arrive at a 4-way stop intersection at the same time, the vehicle on the right has the right of way and should proceed first.

-If the two vehicles arrive at the same time and are facing each other, the vehicle going straight has the right of way over the vehicle turning left.

The right-of-way rule is important for safety reasons. It helps to prevent accidents and reduce traffic congestion by providing a clear and consistent way to determine which vehicle has the right to proceed first.

Therefore, the car on the right should be yielded the right of way.

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Drag each label to the correct category. Systems are classified as human-made or natural. Match each example to the correct type of system. solar systemtelephone systemplant root systemhuman digestive systemcity transit systemwater purification system

Answers

Natural
- solar system
- plant root system
- human digestive system

Human made
- telephone system
- city transit system
- water purification system

Explanation:

Systems which occur in the nature on their own are known as natural system. On the other hand, systems which are made by human beings are known as human-made systems.

Therefore, classifying given systems as follows.

Natural systems are:

Solar systemPlant root systemHuman digestive system

Human-made system are:

TelephoneCity transit systemWater purification system

A structure containing at least 2 different types of tissue that work together for a common purpose is

Answers

Answer:

it is an organ it is a structure containing at least 3 different types of tissue that works together for a common purpose

Liquid nitrogen has different properties from gaseous nitrogen. Is it a chemical change when liquid nitrogen warms to gaseous nitrogen?

Answers

No, it is a physical change. Changing states is physical.A chemical change is to change the nature of something by changing it's chemical makeup.
No, it is a physical change

how to calculate the formula mass of H2S2, HFO2 an keep at least one decimal place in atomic masses from the periodic table

Answers

H = 1.008
S = 32.066
F = 18.998
O = 15.999

(1.008 x 2) + (32.066 x 2) = 66.148 g/mol

(1.008) + (18.998) + (15.999 x 2) = 52.004

Let me know if you need any further help!

Final answer:

The formula mass of a compound is calculated by adding the atomic masses of each atom in its formula according to their quantities. For instance, for H2S2 it's (2*1.0) + (2*32.1) equals 66.2 amu, and for HFO2 it's (1*1.0) + (1*19.0) + (2*16.0) equals 52.0 amu.

Explanation:

To calculate the formula mass of H2S2 and HFO2, one must first understand the atomic masses of each element involved from the periodic table. Indeed, the formula mass is the sum of the atomic masses of each atom in the compound formula. Therefore,

For H2S2, you find the atomic masses for Hydrogen (H) and Sulfur (S). The atomic mass of hydrogen is approximately 1.0 and sulfur is around 32.1. Given the compound has 2 atoms of hydrogen and 2 atoms of sulfur, we obtain:  (2*1.0) + (2*32.1) = 66.2 amu.

For HFO2, you find the atomic masses for Hydrogen (H), Fluorine (F), and Oxygen (O). Atomic mass of Hydrogen is 1.0, Fluorine is 19.0, and Oxygen is 16.0. Thus, we calculate: (1*1.0) + (1*19.0) + (2*16.0) = 52.0 amu.

Remember to keep at least one decimal place in the atomic masses during your calculations. This will improve the accuracy of your result.

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Help please! I'd appreciate it 
A sample of marble has a volume of 6 cm3 and a density of 2.76 g/cm3. What is its mass?
A - 16.56 g
B - 8.76 g
C - 2.17 g
D - 0.46 g

Answers

Answer:

16.56 g

Explanation:

Mass is the production of Volume and Density.

m = V. d = 6 × 2.76 = 16.56 g

What is the [H3O+]in a solution of pOH 0.253

Answers

carbonated water would be what you are looking for :v)

Answer:

1.79*10^-14

Explanation:

A quick easy way I do is find the pH which is .253-14 = -13.747

and put it as the exponent for 10.

10^-13.747=1.79*10^-14

Propane gas (C3H8) burns completely in the presence of oxygen gas (O2) to yield carbon dioxide gas (CO2) and water vapor (H2O).

Answers

Final answer:

Propane's complete combustion reaction with oxygen producing carbon dioxide and water is a chemical process, representing a typical exothermic combustion reaction used for heat generation.

Explanation:

The combustion of propane (C3H8) in the presence of oxygen (O2) to produce carbon dioxide (CO2) and water vapor (H2O) is a chemical reaction that involves the breaking and forming of chemical bonds.

The balanced chemical equation for this reaction is:

C3H8 + 5O2 -> 3CO2 + 4H2O

The balanced chemical equation for the complete combustion of propane is C3H8 + 5O2 → 3CO2 + 4H2O. This reaction is exothermic, releasing heat energy which is why propane is commonly used as a fuel source.

All energy waves other than the visible light spectrum cannot be seen. true or false

Answers

true (hence the name visible light)

The specific heat of gasoline is 2.22 J/g•°C. How much heat would it take to raise 35.0 G of gasoline to 3.00°C?

Answers

To find the amount of heat energy required to raise a substance by a certain number of degrees, we simply multiply: (specific heat * change in temperature * mass) Heat = 2.22 * 35 * 3 = 233.1 joules Therefore, we would need 233.1 joules of heat to raise the temperature by 3 degrees Celsius.

If scientists knew the latitude of a location on earth's surface but not the longitude what could they determine about the location?

Answers

The scientist can know about the temperature or climate in the area.

the distance north of south of the equator .thats the answer

In a laboratory experiment, pure lead metal reacted with excess sulfur to produce a lead sulfide compound. The following data was collected: Mass of empty evaporating dish: 25.000 g Mass of evaporating dish and lead metal: 26.927 g Mass of evaporating dish and lead sulfide: 27.485 g Solve for the empirical formula of the lead sulfide compound. Be sure to show, or explain, all of your calculations.

Answers

To get the empirical formula, we need to know the ratio of the moles of both lead and sulfur.

First, lets get the mass of each:
mass of lead = mass of evaporating dish and lead - mass of empty dish
                     = 26.927  - 25.000  = 1.927 gm of lead (Pb)
mass of sulfur = mass of dish and lead sulfide - mass of dish and lead
                       = 27.485  - 26.927  = 0.558 gm of sulfur (S)

The next step is to get the number of moles in 1.927 gm of Pb and in 0.558 gm of S:
From the periodic table:
molar mass of lead = 207.2 gm
molar mass of sulfur = 32 gm

number of moles = mass / molar mass
number of moles of Pb = 1.927 / 207.2 = 0.0093 moles
number of moles of S = 0.558 / 32 = 0.0174 moles

The third step is to get the ratio between the moles by dividing the number of moles of each by the smaller of the two:
1 mole of Pb (0.0093 / 0.0093) reacts with 0.0174 / 0.0093 = 1.99 (approximately 2 moles) of sulfur.

Final step is to write the empirical formula based on the ratio:
Lead sulfide compound is written as : PbS2

A gas with a volume of 4.0 L at 90.0 kPa expands until the pressure drops to 20.0 kPa. What is its new volume if the temperature doesn't change?

Answers

You are trying to find V2, the formula is V2= P1 / P2 ⋅ V1
input your numbers, V2= 90.0kPa / 20.0kPa ⋅ 4.0 L to get 18 L

The new volume of the gas can be calculated using Boyle's law of gases. The volume of the gas when pressure drops from 90 kpa to 20 kpa, increases from 4 L to 18 L.

What is Boyle's law?

Boyle's law states that, at constant temperature, the volume of a gas is inversely proportional to the pressure of the gas.

hence, PV = a constant.

Let P1 and V1 be the initial pressure and volume and P2 and V2 be the final pressure and volume, then

P1 V1 = P2V2.

Given that,

P1 = 90 kPa

P2 = 20 kPa

V1 = 4 L

V2 = P1 V1/P2

     = (90kPa  × 4 L)/20 kPa

     = 18 L.

Therefore, the final volume of the gas will be 18 L.

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How many grams of CuSO4 would be needed to make 150 mL of 0.300 M CuSO4 solution?

Answers

Hey there!

Molar mass CuSO4 = 159.609 g/mol

Note that the molarity is in the enunciation of the issue, then the problem asks the mass of the solute :

Volume in liters of solution:

150 mL / 1000 => 0.15 L

Calculation of quantity in Moles of the solute :

1 L ----------------- 0.300 M
0.15 L ------------  ( moles )

Moles CuSO4 = 0.15 * 0.300 / 1

Moles CuSO4 = 0.045 moles

Therefore :

1 mole CuSO4 --------------------- 159.609 g
0.045 moles CuSO4-------------- mass

mass = 0.045 * 159.609 / 1

mass = 7.182405 g of CuSO4 


[tex]\boxed{{\text{7}}{\text{.182 g}}}[/tex] of [tex]{\text{CuS}}{{\text{O}}_{\text{4}}}[/tex] would be needed to make 150 mL of 0.300 M [tex]{\text{CuS}}{{\text{O}}_4}[/tex] solution.

Further Explanation:

The proportion of substance in the mixture is called concentration. The most commonly used concentration terms are as follows:

1. Molarity (M)

2. Molality (m)

3. Mole fraction (X)

4. Parts per million (ppm)

5. Mass percent ((w/w) %)

6. Volume percent ((v/v) %)

Molarity is a concentration term that is defined as the number of moles of solute dissolved in one litre of the solution. It is denoted by M and its unit is mol/L.

The formula to calculate the molarity of [tex]{\text{CuS}}{{\text{O}}_4}[/tex] solution is as follows:

[tex]{\text{Molarity of CuS}}{{\text{O}}_4}\;{\text{solution}}=\dfrac{{{\text{Moles}}\;{\text{of}}\;{\text{CuS}}{{\text{O}}_4}}}{{{\text{Volume }}\left( {\text{L}}\right){\text{ of}}\;{\text{CuS}}{{\text{O}}_4}\;{\text{solution}}}}[/tex]   ......(1)

Rearrange equation (1) to calculate the moles of [tex]{\text{CuS}}{{\text{O}}_4}[/tex].

[tex]{\text{Moles}}\;{\text{of}}\;{\text{CuS}}{{\text{O}}_4}= \left( {{\text{Molarity of HN}}{{\text{O}}_3}\;{\text{solution}}} \right)\left( {{\text{Volume of}}\;{\text{CuS}}{{\text{O}}_4}\;{\text{solution}}} \right)[/tex]   ......(2)

The volume of [tex]{\text{CuS}}{{\text{O}}_4}[/tex] solution is to be converted into L. The conversion factor for this is,

[tex]{\text{1 mL}} = {10^{ - 3}}\;{\text{L}}[/tex]

So the volume of [tex]{\text{CuS}}{{\text{O}}_4}[/tex] solution is calculated as follows:

[tex]\begin{aligned}{\text{Volume of CuS}}{{\text{O}}_4}\;{\text{solution}}&= \left( {{\text{150 mL}}}\right)\left({\frac{{{{10}^{ - 3}}\;{\text{L}}}}{{{\text{1 mL}}}}} \right)\\&= 0.15{\text{ L}}\\\end{aligned}[/tex]

The molarity of [tex]{\text{CuS}}{{\text{O}}_4}[/tex] solution is 0.300 M.

The volume of [tex]{\text{CuS}}{{\text{O}}_4}[/tex] solution is 0.15 L.

Substitute these values in equation (2).

[tex]\begin{aligned}{\text{Moles}}\;{\text{of}}\;{\text{CuS}}{{\text{O}}_4}&=\left( {{\text{0}}{\text{.300 M}}} \right)\left( {0.15{\text{ L}}}\right)\\&= 0.04{\text{5 mol}}\\\end{aligned}[/tex]

The formula to calculate the mass of [tex]{\text{CuS}}{{\text{O}}_4}[/tex] is as follows:

[tex]{\text{Mass of CuS}}{{\text{O}}_{\text{4}}}=\left( {{\text{Moles of CuS}}{{\text{O}}_{\text{4}}}} \right)\left( {{\text{Molar mass of CuS}}{{\text{O}}_{\text{4}}}} \right)[/tex]       ......(3)

Substitute 0.045 mol for the moles of [tex]{\text{CuS}}{{\text{O}}_4}[/tex] and 159.609 g/mol for the molar mass of [tex]{\text{CuS}}{{\text{O}}_4}[/tex] in equation (3).

[tex]\begin{aligned}{\text{Mass of CuS}}{{\text{O}}_{\text{4}}}&= \left({{\text{0}}{\text{.045 mol}}} \right)\left( {\frac{{{\text{159}}{\text{.609 g}}}}{{{\text{1 mol}}}}}\right)\\&= 7.1824{\text{05 g}}\\&\approx {\text{7}}{\text{.182 g}}\\\end{aligned}[/tex]

Therefore the mass of [tex]{\mathbf{CuS}}{{\mathbf{O}}_{\mathbf{4}}}[/tex]  is 7.182 g.

Learn more:

1. Calculation of volume of gas: https://brainly.com/question/3636135

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Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Concentration terms

Keywords: molarity, CuSO4, dilution, moles of CuSO4, volume, solution, 0.045 mol, 150 mL, 0.300 M, 7.182 g, 159.609 g/mol, 0.15 L.

How much heat is absorbed when 2.8 mol NH4NO3 is dissolved in water? The molar heat of solution of NH4NO3 is 25.7 kJ/mol.

Answers

Final answer:

To find the heat absorbed by the dissolution of 2.8 moles of NH4NO3, multiply the amount of substance by its molar heat of solution, yielding 71.96 kJ.

Explanation:

To calculate the amount of heat absorbed when 2.8 moles of NH4NO3 are dissolved in water, you multiply the number of moles by the molar heat of solution. The molar heat of solution for NH4NO3 is 25.7 kJ/mol.

The calculation is as follows:

Heat absorbed = Number of moles × Molar heat of solutionHeat absorbed = 2.8 mol × 25.7 kJ/molHeat absorbed = 71.96 kJ

Therefore, the dissolution of 2.8 moles of NH4NO3 in water absorbs 71.96 kJ of heat.

When 2.8 mol NH₄NH₃ is dissolved in water, 71.96 kJ of heat is absorbed.

To determine how much heat is absorbed when 2.8 mol NH₄NH₃ is dissolved in water, use the given molar heat of solution.

Dissolution Process:

NH₄NH₃ (s) → NH4⁺ (aq) + NO₃⁻ (aq)

The molar heat of solution for NH₄NH₃ is 25.7 kJ/mol.

Multiply the amount of NH₄NH₃ (in moles) by its molar heat of solution:Heat absorbed = 2.8 mol NH₄NH₃ × 25.7 kJ/mol = 71.96 kJ

Hence, 71.96 kJ of heat is absorbed when 2.8 mol of NH₄NH₃ is dissolved in water.

difference between core science and double science ( ENGLAND GCSE OCR EXAM BOARD)

Answers

With the core science you don't go into as much detail in the topics and you only get one GCSE out of it. Double science goes into more detail so you learn mor science and you get 2 GCSEs out of it. With double science you will have more science lessons which means you will have more science work and I think you have an extra exam if you take that because it is one of the options.
Final answer:

Core science provides a basic understanding of key scientific concepts, while double science goes further in depth and grants two GCSE qualifications upon completion. The choice between the two often depends on a student's academic and career aspirations in the field of science.

Explanation:

The main difference between core science and double science as part of the England GCSE OCR exam board involves the extent of the curriculum covered and the number of GCSE qualifications granted upon completion.

Core Science is a single award course which delivers one GCSE qualification. This course provides a broad and basic understanding of key scientific concepts, covering aspects of Biology, Chemistry, and Physics.

On the other hand, Double Science, also known as Combined Science, awards two GCSE qualifications. It covers a more extensive curriculum, diving deeper into the subjects of Biology, Chemistry, and Physics. This might be the preferred choice for students wishing to pursue sciences at A-level or beyond, as it provides a more comprehensive foundation in these subject areas.

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when organism convert forms of energy what usually results

Answers

An example of conversion of a form of energy is energy from the sunlight which both wild and cultivated plants use to promote leaf growth and the growth of the vegetable plants like say radishes, lettuce etc. Where there is more sunlight and more intense like in the tropics the plant growth is much more prolific as a consequence whereas where there is less sunlight and colder temperatures like in the Canadian north, trees where they exist tend to be stunted and small in size.

In an experiment, a student gently heated a hydrated copper compound to remove the water of hydration. the following data was recorded:

1. mass of the crucible, cover and contents before heating 23.4g.

2. mass of empty crucible and cover.

3. mass of crucible, cover, and contents after heating to constant mass 20.94g

Answers

The unknown of this problem is the experimental percent of water in the compound in order to remove the water of hydrogen, given the following:

Mass of crucible, cover and contents before heating                               23.54 g
Mass of empty crucible and cover                                                            18.82 g
Mass of crucible, cover, and contents after heating to constant mass     20.94 g

In order to get the answer, determine the following:

Mass of hydrated salt used                          = 23.54 g – 18.82 g = 4.72 g
Mass of dehydrated salt after heating          = 20.94 g – 18.82 g = 2.12 g
Mass of water liberated from salt                 = 4.72 g – 2.12 g = 2.60 g

Then solve the percent of water in the hydrated salt by:

% water = (mass of water / mass of hydrated salt) x 100
% water = 2.60 g / 4.72 g x 100
% water = 55.08 % in the compound 

An unknown quantity of gas is held at a temperature of 295 K in a container with a volume of 25 L and a pressure of 742 kPa. How many moles of gas are in the container?

Answers

Using PV = nRT you can rearrange to find n = PV/RT
P = 742000 Pa
V = 0.025 m^3
R = 8.31
T = 295 K

n = (742000 • 0.025)/(8.31 • 295)
n = 7.56 mol

Answer:

7.56 moles

Explanation:

For a 742 kPa, we can consider the gas as an ideal gas because it will be close to 7 atm (1 kPa = 0.01 atm), which is low pressure. So, the ideal gas equation is:

PV = nRT

Where P is the pressure, V is the volume, n the number of moles, R the gas constant and T the temperature (always in Kelvin). For pressure in kPa and volume in liters, R = 8.314 kPa.L/mol.K, then:

742x25 = nx8.314x295

2452.63n = 18550

n = 18550/2452.63

n = 7.56 moles

Which of the following metals is most reactive?

A. aluminum

B. sodium

C. copper

D. calcium

Answers

the answer is, D. Calcium
Sodium seems to be the most reactive out of the options

If a 30-ft3 volume of air at 10 psig is compressed to 25 ft3 at a constant temperature, what would be the new pressure in psig?

Answers

Final answer:

To find the new pressure in psig, we can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional at constant temperature. The new pressure would be 12 psig.

Explanation:

To determine the new pressure in psig, we can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional at constant temperature.

Boyle's Law can be represented by the equation: P1V1 = P2V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume.

Using this equation, we can rewrite it as:

P1/P2 = V2/V1

Substituting the given values into the equation, we have:

10 psig/P2 = 25 ft3/30 ft3

Solving for P2, we find:

P2 = (10 psig)(30 ft3)/25 ft3 = 12 psig

Which explains the change in ionized energy that occurs between removing the first and second electrons from an Atom?

Answers

Ionization energy is the energy needed to remove an electron from an atom or ion to form a positive ion.

The first ionization energy is the energy needed to remove one electron from an atom (atom are neutral species) to form a positive ion. This electron is the electron with the higher energy level (it is from the valence shell, of course). It is the electron easiest to release.

The second ionization energy is the energy needed to remove a second electron from the atom. It implies to remove an electron from the positive ion that was formed after removing the first electron from the neutral atom. It is harder to release  an electron from a positive ion than from a neutral atom.

So, it is the higher ratio of the protons to electrons which make succesive ionization energies to increase.

In conclusion: The ionization energy increases because the ratio of the protons to electrons increases.





Answer:

B. The ionization energy increases because the ratio of the protons to electrons increases.

Explanation:

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A chemist finds that when platinum is added to a reaction, the reaction speeds up. He thinks the platinum may be acting as a catalyst. What measurement should the chemist make to determine whether it is a catalyst?

Measure the mass of the platinum before and after the reaction.
Measure the temperature of the solution before and after the reaction.
Measure the change in volume of the solution.
Measure the amount of gas released by the reaction.

Answers

Measure the mass of the platinum before and after the reaction 
as if it is acting as a catalyst the mass of platinum will remain unchanged as catalyst do not consume themselves in reaction  

Answer: Option (a) is the correct answer.

Explanation:

A substance that does not get consumed in a chemical reaction and helps in increasing rate of the reaction by lowering the activation energy is known as a catalyst.

Hence, when the chemist finds that reaction speeds up when platinum is added into the reaction then the chemist must calculate or measure the mass of platinum before and after the completion of reaction.

This is because if there occurs change in the mass of platinum then it means that platinum is not acting as a catalyst in the reaction.

Thus, we can conclude that chemist must measure the mass of the platinum to determine whether it is a catalyst.

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