Answer:
B.) x = –4 or x = 1/6 .
Step-by-step explanation:
Given : g(x) = 6x² + 23x – 4.
To find : Solve.
Solution : We have given that
g(x) = 6x² + 23x – 4.
If g(x) = 0
6x² + 23x – 4 = 0 .
On factoring
6x² + 24x - 1x – 4 = 0
Taking common 6x from first two terms and -1 from last two terms.
6x ( x + 4 ) -1 (x + 4) = 0.
On grouping
(6x -1) ( x +4) = 0
For 6x -1 = 0
6x = 1
on dividing by 6
x = 1/6.
For x +4 = 0
On subtracting 4 from both sides
x = -4.
Therefore, B.) x = –4 or x = 1/6 .
the equation of line AB is y = 1/5x -1 write an equation of a line perpendicular to line AB in slope intercept form that contains point (1, -2)
A cylindrical tree trunk is 14 yards high from the ground up to the lowest branch, and it measures 4 yards around. What is the volume of wood in this section of the trunk?
write the following inequality in slope intercept form. -6+2y less than or equal to 42
Answer: The required slpe-intercept form of the given inequality is
[tex]y\leq 0\times x+24.[/tex]
Step-by-step explanation: We are given to write the following inequality in the slope-intercept form :
[tex]-6+2y\leq 42~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)[/tex]
We know that
the slope intercept form of a straight line with slope m and y-intercept c is given by
[tex]y=mx+c.[/tex]
Writing equation (i) in slope-intercept form, we have
[tex]-6+2y\leq 42\\\\\Rightarrow 2y\leq 42+6\\\\\Rightarrow 2y\leq 48\\\\\Rightarrow y\leq 24\\\\\Rightarrow y\leq 0\times x+24,[/tex]
where slope, m = 0 and y-intercept, c = 24.
Thus, the required slpe-intercept form of the given inequality is
[tex]y\leq 0\times x+24.[/tex]
Which statements about the graph of the function f(x) = 2x2 – x – 6 are true? Check all that apply.
The domain of the function is .
The range of the function is all real numbers.
The vertex of the function is .
The function has two x-intercepts.
The function is increasing over the interval (, ∞).
we have
[tex] f(x) = 2x^{2}- x -6 [/tex]
using a graph tool
see the attached figure
we know that
1) the domain of the function is all real numbers-------> interval (-∞,∞)
2) The range of the function is the interval [-6.125,∞)
3) The vertex of the function is the point (0.25,-6.125)
4) The function has two x-intercepts-----> ( -1.5,0) and (2,0)
5) The function is increasing over the interval (0.25,∞) and decreasing over the interval (-∞,0.25)
A test consists of 20 problems and students are told to answer any 15 of these questions. In how many different ways can they choose the 15 questions?
a. 15,504
b. 20,145
c. 23,670
d. 25,890
A man travelled 3/8 of his journey by a rail 1/4 by a taxi 1/8 by and the remaining 2km on foot what is the length of his total journey?
A contractor records all of the bedroom areas, in square feet, of a five-bedroom house as: 100, 100, 120, 120, 180 What is the variance?
The variance of the five bedroom house is 864.
The formula varianceσ²
[tex]=\frac{X^2}{N} -u^2[/tex]
To get the value of X²
= 100²+100²+120²+120²+180²
= 81200
The number is N = 5
u = mean
[tex]u = \frac{100+100+120+120+180}{5}[/tex]
u = 124
The values in the variance formula
[tex]\frac{81200}{5} -124^2[/tex]
16240-15376
= 864
The variance is 864
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find the area of a regular hexagon if a side is 20cm
Area = 1039.23 square units
Round answer as needed. See picture for equation
The number of baseball cards in Neil's collection is 80 percent of the number in Larry's collection. If Neil has 80 fewer baseball cards than Larry, how many do they have altogether
The problem involves setting up an equation based on the given situation to solve for the number of baseball cards Neil and Larry have. By solving the equation, you find that Larry has 400 cards and Neil has 320 cards. So, they have 720 baseball cards together.
Explanation:This is a problem of percentages and of algebra. First, you know that the number of cards Neil has is 80% of what Larry has. This can be set up as an algebraic equation, where N represents Neil’s cards and L represents Larry’s cards: N = 0.8L. You also know that Neil has 80 fewer cards than Larry, which provides a second equation: N = L - 80.
Because both expressions equal N, you can set them equal to each other to solve for L. This leads to 0.8L = L - 80. Solve this equation for L, and you get L = 400. Substituting this into the equation N = 0.8L, you find that N = 320. Therefore, Neil and Larry have 720 baseball cards altogether.
Learn more about Solving Equation here:https://brainly.com/question/18322830
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Among the contestants in a competition are 3636 women and 2525 men. if 5 winners are randomly? selected, find the probability that they are all? men? round to five decimal places.
What is #3 step by step?
:) Answers? Thanks,❤
A rectangle has a length of ∛81 and a width of 3 2/3 inches. Find the area of the rectangle.
A.3 2/3 power inches squared
B.3 8/3 power inches squared
C.9 inches squared
D. 9 2/3 power inches squared
PLEASE HELP! A square piece of paper 144 mm on a side is folded in half along a diagonal. The result is a 45 -45-90 triangle. What is the length of the hypotenuse
A:140 mm
B:12 square root 2
C:280mm
D: 140 square root 2
Which graph shows the solution set for -1.1x+ 6.4> -1.3
PLEASE help me!!!!! and can you show me how you did it please!?!
Standard automobile license plates in a country display 1 numbers, followed by 2 letters, followed by 4 numbers. how many different standard plates are possible in this system? (assume repetitions of letters and numbers are allowed.)
there are 10 numbers ( 0-9)
there are 26 letters ( A-Z)
10 x 26 x 26 x 10 x 10 x 10 x 10 =67,600,000 possible combinations
A die is rolled 12 times find the probability of rolling exactly 12 ones
Answer:
[tex]P(X=12)=(12C12)(\frac{1}{6})^12 (1-\frac{1}{6})^{12-12}=4.59x10^{-10}[/tex]
Step-by-step explanation:
Previous concepts
The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".
Solution to the problem
We assume that the die is fair and the probability of obatin a one is 1/6.
Let X the random variable of interest, on this case we now that:
[tex]X \sim Binom(n=12, p=1/6)[/tex]
And we want to find this probability:
[tex] P(X=12)[/tex]
And if we replace we got:
[tex]P(X=12)=(12C12)(\frac{1}{6})^12 (1-\frac{1}{6})^{12-12}=4.59x10^{-10}[/tex]
A quadrilateral has two consecutive angles that measure 90° each. Which of the following quadrilaterals could have this property?
i. square
ii. rectangle
iii. parallelogram
iv. kite
v. rhombus
vi. trapezoid
A.
i, ii
B.
i, ii, iii
C.
i, ii, iii, iv
D.
i, ii, iii, v, vi
Final answer:
A square, rectangle, and certain cases of rhombuses and trapezoids can have two consecutive right angles, while typically a parallelogram and kite do not unless they are special cases of the rectangle or square respectively.
Explanation:
In the context of quadrilaterals with two consecutive right angles, it's important to recognize that certain quadrilaterals have this property by definition. A square and a rectangle both have four right angles, which means they certainly have at least two consecutive right angles.
A parallelogram typically does not have right angles, but a rectangle is a special type of parallelogram with right angles, so it fits this description. A kite generally does not have right angles unless specifically constructed to do so, which is not typical.
A rhombus can have right angles, making it a square, so it fits the criteria too. A trapezoid can also have a pair of consecutive right angles when it is a right trapezoid.
Therefore, the list of quadrilaterals that might have two consecutive right angles is not only the square and the rectangle but extends to include the rhombus and trapezoid as well.
Given these definitions, the correct answer to the question would be:
D. i, ii, iii, v, vi
Final answer:
The quadrilaterals that can have two consecutive angles measuring 90° each are squares, rectangles, and certain parallelograms (when they are squares or rectangles). Therefore, the correct answer to the question is B. This includes a square (i), a rectangle (ii), and some parallelograms (iii).
Explanation:
If a quadrilateral has two consecutive angles measuring 90° each, it could be any of the shapes that inherently contain right angles by definition. These shapes are a square, a rectangle, and certain types of parallelograms, specifically rectangles and squares. Both a square and a rectangle always have four right angles, which makes them valid answers. A rhombus or a general parallelogram may also have right angles, but only in specific cases, such as when a rhombus is also a square. Thus, kites and trapezoids do not necessarily fit this criterion as they do not always have consecutive right angles. Therefore, the correct answer is B, which includes a square, a rectangle, and some parallelograms.
find a positive angle less than one rotation that is coterminal with 750 degrees
To solve this problem, all you have to do is to subtract 360 degrees (equivalent to 1 rotation) from the given angle until the answer is less than 360 degrees.
1st subtraction: 750 – 360 = 390 degrees
2nd subtraction: 390 – 360 = 30 degrees
Therefore the positive angle less than one rotation that is coterminal with 750 degrees is 30 degrees.
What is the quality a design has if it maintains all characteristics when it is rotated about a point lying in its plane?
Answer:
The answer is rotational symmetry.
Step-by-step explanation:
The Rotational symmetry is the quality a design has if it maintains all characteristics when it is rotated about a point lying in its plane. A shape is said to possess rotational symmetry when it still looks the same after we rotate it.
George's page contains twice as many typed words as bills page and bills page contains 50 fewer words than Charlie's page. If each person can type 60 words per minute, after one minute, the difference between twice the number of words on bills page and the number of words on Charlie's page is 210. How many words did bills page contain initially? Use a table to organize the information.
Calculate the hypotenuse
Write two ratios that are equivalent to 3:11
Find the sale price when the original price is $37.00 and the discount rate is 44%.
a.
$20.72
c.
$35.37
b.
$16.28
d.
$1.63
Please select the best answer from the choices provided
P = 3^7 x 11^2 and Q = 3^4 x 7^3 x 11. Write as the product of prime factors the LCM of P and Q
The LCM of P and Q is found by taking the highest powers of the common prime factors from both numbers, which results in LCM(P, Q) = 37 x 73 x 112.
Explanation:To find the Least Common Multiple (LCM) of P and Q when given as products of prime factors, we look for the highest powers of the prime factors that appear in either P or Q. In this case:
P = 37 x 112Q = 34 x 73 x 11For prime factor 3, the highest power in P and Q is 37. For prime factor 11, the highest power is 112 (from P). Since prime factor 7 only appears in Q, we include it in its highest power, which is 73. Combining these, the LCM of P and Q as the product of prime factors is:
LCM(P, Q) = 37 x 73 x 112
If 5x + x2>100 then x is not
What is the awnser to -10x+3(4x-2)=6
A school typically sells 500 yearbooks each year for $50 each.
The economics class does a project and discovers that they can sell 100 more yearbooks for every $5 decrease in price.The revenue for yearbook sales is equal to the number of yearbooks sold times the price of the yearbook.
Let X represent the number of $5 decreases in price. If the expression that represents the revenue is written in the form R(X)=(500+ax)(50-bx). Find the values of a and b.
Answer: a=100 and b=5
Step-by-step explanation:
Given: A school typically sells 500 yearbooks each year for $50 each.
The economics class discovers that they can sell 100 more yearbooks for every $5 decrease in price.
Let x represents the number of $5 decreases in price.
Then the new price (in dollars)=50-5x
Total yearbook sold=500+100x
If the revenue for yearbook sales is equal to the number of yearbooks sold times the price of the yearbook.
Then the revenue function will be [tex]R(X)=(500+100x)(50-5x)[/tex]
On comparing this with the given revenue expression we get
a=100 and b=5.
In this exercise we have to calculate the values of A and B, so we have to:
[tex]A=100\\B=5[/tex]
Since the equation is:
[tex]R(X)=(500+ax)(50-bx)[/tex]
And the following information was given:
A school typically sells 500 yearbooks each year for $50 each.The economics class discovers that they can sell 100 more yearbooks for every $5 decrease in price.So knowing that by increasing 100 more books sold this is equal to A and the decrease in value is going to be equal to b.
[tex]R(X)=(500+100x)(50-5x)[/tex]
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For what values of x and y are the triangles congruent?
a. x=-4. y=-4
b. x=-4, y=4
c. x=4, y=7
d. x=7, y=4