THE FUNCTION ARCSINE CAN ALSO BE DEFINED AS?

Answers

Answer 1
The arcsine, [tex]\sin^{-1}[/tex], is the inverse of the [tex]\sin[/tex] function. This means that it takes as inputs what would usually be outputs for the [tex]\sin[/tex] function and produces as outputs what would usually be inputs for the [tex]\sin[/tex] function.

This can be particularly useful when you're trying to find an angle on a right triangle, but you've only been given the lengths of the sides. To find any angle [tex]\theta[/tex] in a right triangle, just take [tex]\sin^{-1} \frac{o}{h} [/tex], where o is the side opposite [tex]\theta[/tex] and h is the hypotenuse of the right triangle.
THE FUNCTION ARCSINE CAN ALSO BE DEFINED AS?

Related Questions

One car rental company charges $30 per day plus $0.25 per mile driven. a car company charges $40 per day plus $0.10 per mile driven. how many miles must you drive for a one-day rental at the second company to be less expensive than the same rental at the first company? write an inequality to solve.

Answers

Rewrite the question into equations:
let's say x is the miles you drive for a day
the first company's rental charge= $30+$0.25x
the second company's rental charge= $40+$0.10x

Calculate what the x is when two equations are equal to each other:
$30+$0.25x=$40+$0.10x
$0.25x-$0.10x=$40-$30
$0.15x=$10
x=$10/$0.15
x=66.667 miles

at least 66.667 miles. I am not sure though. I'm a little bit tired today, so you might want to check it yourself.

Answer:

66.667 miles

Step-by-step explanation:

Given: One car rental company charges $30 per day plus $0.25 per mile driven.

Second car company charges $40 per day plus $0.10 per mile driven.

To find:  how many miles must you drive for a one-day rental at the second company to be less expensive than the same rental at the first company?

Solution: Let the distance driven on a day be x miles.

As per question,

The first rental company will charge [tex]=30+0.25x[/tex]

The second rental company will charge [tex]=40+0.10x[/tex]

Now, we want the rental charges of second company to be less expensive then the first.

So we get the inequality,

[tex]30+0.25x>40+0.10x[/tex]

[tex]0.25x-0.10x>40-30[/tex]

[tex]0.15x>10[/tex]

[tex]x>\frac{1000}{15}[/tex]

[tex]x>66.667[/tex] miles

Hence, at least 66.667 miles should be driven on a day.

It takes 33 pounds of seeds to completly plant a 6 acre field. how many acres can be planted per pound of seed

Answers

If it takes 33 pounds of seeds to plant a 6 acre field; 

6/33=2/11 or 0.1818 

One pound of seeds would be able to plant 2/11 of an acre. 

Hope I helped :) 


The median of the values of the data set is h. If 625 were subtracted from each of the values in the data set what would be the median of the resulting data ?

A. H - 625
B.625 - h
C.h + 625
D.625 • h

Answers

b
it always turns to a negative

The correct answer is A. H - 625.

Sure, let's go step by step to find the correct answer.

Given:

- Median of the original data set = h

- Subtracted 625 from each value in the data set

Let's represent the original data set as {x1, x2, x3, ..., xn} where n is the number of values in the data set.

1. Median of the original data set:

The median of a data set is the middle value when the values are arranged in ascending or descending order. Since the data set has been modified by subtracting 625 from each value, the new data set would be {x1 - 625, x2 - 625, ..., xn - 625}.

2. Median of the modified data set:

If we subtract 625 from each value, it doesn't affect the relative order of the values. Therefore, the median of the modified data set would also be h.

So, the correct answer is A. H - 625.

The median represents the middle value in a sorted data set. When we subtract a constant (625 in this case) from each value in the data set, it shifts the entire set downwards without changing the order of values relative to each other. Therefore, the position of the middle value, which determines the median, remains the same. This means the median of the modified data set will still be h.

complete question

The median of the values of the data set is h. If 625 were subtracted from each of the values in the data set what would be the median of the resulting data ?

A. H - 625

B.625 - h

C.h + 625

D.625 • h

The first three numbers in sequence are 1, 4, and 9. Marie determined that the fourth number in the sequence is 16. Marie’s rule involved multiplication. What rule did she use to determine the fourth number in the sequence? Specific please

Answers

We notice that:

1² = 1
2² = 4
3² = 9,
then 4² = 16 and son and so forth

3.Cornelia spends 2 2/3 hours studying for her big science test. She spent 2/3 of an hour finishing her writing assignment and 1/4 of an hour playing outside. How much time did she spend overall on the three activities?

Answers

2 2/3 + 2/3 + 1/4 =
8/3 + 2/3 + 1/4 =
10/3 + 1/4 =
40/12 + 3/12 =
43/12 =
3 7/12 hrs <===

By the end of the school year, Terry had passed 80% of his science tests. If Terry failed 4 science tests, how many science tests did Terry pass?

Answers

We can say that 4 tests failed was 20%, and x tests passed was 80%: 4/20 = x/80
In this case, x = 16 tests passed.

Answer:  Terry passed 16 science tests.

Step-by-step explanation:  Given that by the end of the school year, Terry had passed 80% of his science tests and Terry failed 4 science tests.

We are to find the number of science tests that Terry passed.

Let x represents the total number of science tests that Terry appeared in.

Since he failed 4 science tests, so the number of science tests that Terry passes is given by

[tex](x-4).[/tex]

Since he passed 80% of his tests, so we get

[tex]80\%\times x=x-4\\\\\\\Rightarrow \dfrac{80}{100}\times x=x-4\\\\\\\Rightarrow \dfrac{4}{5}\times x=x-4\\\\\Rightarrow 4x=5x-20\\\\\Rightarrow 5x-4x=20\\\\\Rightarrow x=20.[/tex]

So, total number of science tests = 20.

Therefore, the number of science tests that Terry passed is given by

[tex]n=20-4=16.[/tex]

Thus, Terry passed 16 science tests.

What is the point slope form of a line with slope 4/5 that contains the points -2,1

Answers

y - y1 = m(x - x1)
slope(m) = 4/5
(-2,1)....x1 = -2 and y1 = 1
now we sub
y - 1 = 4/5(x - (-2) =
y - 1 = 4/5(x + 2) <===

Answer:

[tex]y-1= \frac{4}{5} (x+2)[/tex]  

Step-by-step explanation:

Using point-slope intercept form:

The equation of line is given by:

[tex]y-y_1 = m(x-x_1)[/tex]              .....[1]

where,

m is the slope of the line and [tex](x_1, y_1)[/tex] is the point on the line.

As per the statement:

A line with slope 4/5 that contains the points (-2,1)

⇒m = [tex]\frac{4}{5}[/tex] and [tex](x_1, y_1)=(-2, 1)[/tex]

Substitute these values in [1] we have;

[tex]y-1= \frac{4}{5} (x+2)[/tex]  

Therefore, [tex]y-1= \frac{4}{5} (x+2)[/tex]  is the point slope form of a line with slope 4/5 that contains the points (-2,1).

if an angle is acute then its measure is 30 degrees true or false

Answers

False. An acute angle's measure is anywhere from 0 to 90 degrees. So it doesn't have to be 30 degrees, it can be anywhere in that range.
Final answer:

An acute angle is any angle less than 90 degrees, and while 30 degrees is an example of an acute angle, it is not accurate to say that all acute angles must be 30 degrees.

Explanation:

The statement 'If an angle is acute then its measure is 30 degrees' is false. An acute angle is defined as any angle that is less than 90 degrees. While 30 degrees is indeed an example of an acute angle, an acute angle can be any value less than 90 degrees. For example, 45 degrees, 20 degrees, or 1 degree are also acute angles. Therefore, it is not accurate to say that an acute angle must be 30 degrees.

Learn more about Acute Angles here:

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What is the area of a rectangle with vertices at (−3, −1) , (1, 3) , (3, 1) , and (−1, −3) ?

Enter your answer in the box. Do not round any side lengths.


___units²

Answers

Hiya,

So I did this quiz just now and I have the answers. c:


1.) What is the area of a rectangle with vertices at 

(−3, −1)(−3, −1) , (1, 3)(1, 3) , (3, 1)(3, 1) , and (−1, −3)(−1, −3) ?

Enter your answer in the box. Do not round any side lengths.

Answer: 16 Units


2.) What is the perimeter of the rectangle shown on the coordinate plane, to the nearest tenth of a unit?

Answer: 26.8 Units


3.) What is the area of a triangle with vertices at 

(0, −2) ,  ​ (8, −2) ​ , and ​ (9, 1) ​ ?

Enter your answer in the box.

Answer: 12 Units

4.) What is the perimeter of the triangle shown on the coordinate plane, to the nearest tenth of a unit?
Answer: 21.6 Units

5.) 
What is the perimeter of a polygon with vertices at 

(−2, 1) , ​ (−2, 4) ​,  (2, 7) , ​ (6, 4) ​, and (6, 1) ​?

Enter your answer in the box. Do not round any side lengths.​

Answer: 24 Units


I really hope this helps! Let me know if it did... or anyone else that used this info!

The length of the side joining points (-3, -1) and (1, 3) is given by

[tex]l= \sqrt{(1+3)^2+(3+1)^2} \\ \\ = \sqrt{4^2+4^2} = \sqrt{16+16} \\ \\ = \sqrt{32} [/tex]

The length of the side joining points (1, 3) and (3, 1) is given by

[tex]w= \sqrt{(3-1)^2+(1-3)^2} \\ \\ = \sqrt{2^2+(-2)^2} = \sqrt{4+4} \\ \\ = \sqrt{8}[/tex]

The area of a rectangle is given by length times width.

Thus, the area of the given rectangle is given by

[tex]Area=l\times w \\ \\ = \sqrt{32} \times \sqrt{8} \\ \\ = \sqrt{32\times8} = \sqrt{256} \\ \\ =\bold{16} \ units^2[/tex]

Evaluate ab for a = 2 3/4 and b = 4/5

A. 1 1/15
B. 8/15
C. 2 1/5
D. 2/3

Answers

the answer is C) 2 1/5

The width of a poster is 4/5 of its length, It takes 36 ft. of metal framing to frame the poster. Find the dimensions of the poster.

Answers

The length is 10 and width is 8

What is the perimeter of the triangle shown on the coordinate plane, to the nearest tenth of a unit?

14.6 units
15.5 units
21.0 units
21.6 units

Answers

To calculate the perimeter, consider each side separately.

Right side: This is easiest since it's a vertical line - it's 7 units long.

Top side: If you look carefully, this side is really the hypotenuse of a triangle that is 1 unit tall and 6 units long. Using the Pythagorean Theorem, you can calculate the length of the hypotenuse to be 1^2 + 6^2 = c^2 --> c = 6.1

Left side: just like the top side, this side is the hypotenuse of a triangle that is 6 units tall and 6 units long. Pythagoras again: 6^2 + 6^2 = c^2 --> c = 8.5

Add these three numbers to get the perimeter: 7 + 6.1 + 8.5 = 21.6

Solve the inequality for x

20x > 8(4x - 5) - 20

Answers

Hi there! I can help you with this! First, let's combine like terms and do everything for the right side of the problem. When you do the distributive property, you get 32x - 40. Combine like terms and you'll get 32x - 60. Now, the inequality is 20x = 32x - 60. First, let's subtract 32x from both sides to get the integer by itself. When you do that, you get -12x = -60. Now, divide each side by -12 to isolate the "x". -60/-12 is 5. Let's plug it in. 20 * 5 is 100. 32 * 5 is 160. 160 - 60 is 100. 100 = 100. There. x = 5.

Answer:

its -5 not five

Step-by-step explanation:

1. The equation of a circle is x ^2 + y ^2 – 4 x + 2 y = 11 .
What are the coordinates of the center of the circle?
Question 1 options
(2, –1)
(4, –2)
(–4, 2)
(–2, 1)

2. What is the equation of the circle with center (4, -3) and radius 2?
Question 2 options:
(x + 4)^2 + (y – 3)^2 = 4
(x + 4)^2 – (y – 3)^4 = 4
(x – 4)^2 + (y + 3)^2 = 2
(x – 4)^2 + (y + 3)^2 = 4

3. What is the equation of this circle? (has picture)
(x – 2)^2 + (y – 7)^2 = ½
(x + 2)^2 + (y + 7)^2 = ¼
(x + 7)^2 + (y + 2)^2 = ¼
(x + 2)^2 + (y + 7)^2 = ½

4. What are the center and radius of the circle described by the equation x2 + y2 – 18x + 12y + 68 = 0?
Question 4 options:
Center (-9, 6); radius 7
Center (9, -6); radius 7
Center (-6, 9); radius 7
Center (6, -9); radius 7

5. Select the equation of a circle with center (-3, 7) and radius 5.
Question 5 options:
(x - 3)^2 + (y + 7)^2 = 25
(x + 3)^2 + (y - 7)^2 = 25
(x + 3) + (y - 7) = 25
(x - 3) + (y + 7) = 25

Answers

Problem 1

x^2 + y^2 - 4x + 2y = 11
x^2 - 4x + y^2 + 2y = 11
(x^2 - 4x) + (y^2 + 2y) = 11
(x^2 - 4x + 4) + (y^2 + 2y) = 11 + 4
(x - 2)^2 + (y^2 + 2y) = 15
(x - 2)^2 + (y^2 + 2y + 1) = 15+1
(x - 2)^2 + (y + 1)^2 = 16

The equation
(x - 2)^2 + (y + 1)^2 = 16
can be written as
(x - 2)^2 + (y - (-1))^2 = 4^2
which is in the form
(x-h)^2 + (y-k)^2 = r^2
where,
center = (h,k) = (2,-1)
radius = r = 4

Answer: Choice A) (2,-1)

====================================================
Problem 2

Given Center = (h,k) = (4,-3)
h = 4, k = -3
Given Radius = r = 2

(x-h)^2 + (y-k)^2 = r^2
(x-4)^2 + (y-(-3))^2 = 2^2
(x-4)^2 + (y+3)^2 = 4

Answer is choice D

====================================================
Problem 3

Based on the picture, the center is (-2,-7)
(h,k) = (-2,-7)
h = -2
k = -7

Each tick mark is 1/2 a unit. The distance from the red center to the outer edge of the circle is 1 tick or 1/2 a unit. The radius is 1/2 a unit. So r = 1/2 and r^2 = (1/2)^2 = 1/4

(x-h)^2 + (y-k)^2 = r^2
(x-(-2))^2 + (y-(-7))^2 = (1/2)^2
(x+2)^2 + (y+7)^2 = 1/4

Answer is choice B

====================================================
Problem 4

x^2 + y^2 - 18x + 12y + 68 = 0
(x^2 - 18x) + (y^2 + 12y) + 68 = 0
(x^2 - 18x + 0) + (y^2 + 12y + 0) + 68 = 0
(x^2 - 18x + 81 - 81) + (y^2 + 12y + 36 - 36) + 68 = 0
(x^2 - 18x + 81) - 81 + (y^2 + 12y + 36) - 36 + 68 = 0
(x - 9)^2 + (y + 6)^2 - 81 - 36 + 68 = 0
(x - 9)^2 + (y + 6)^2 - 49  = 0
(x - 9)^2 + (y + 6)^2 = 49
(x - 9)^2 + (y - (-6))^2 = 7^2

The center is (9,-6) and the radius is 7

====================================================
Problem 5

Center = (h,k) = (-3,7)
Radius = r = 5

(x-h)^2 + (y-k)^2 = r^2
(x-(-3))^2 + (y-7)^2 = 5^2
(x+3)^2 + (y-7)^2 = 25

Answer is choice B

HELP MATH!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answers

it can be the line of best fit because it shows a negative linear association .

line B

A negative nonlinear association

last pg d













If EG=40 and point F is 2/5 of the way between E and G, find the value FG.
The drawing is not to scale.

a. 32
b. 20
c. 16
d. 24

Answers

EG = 40
Point F (EF) = 2/5

EF = 2/5 × 40
EF = 16

EF + FG = EG
16 + FG = 40
FG = 24

d. 24

Which of the following is the linear parent function

Answers

The linear parent function is f(x) = x or y = x. We can scale it to get y = mx and then shift it around to get y = x+b. Combine the scaling and shifts and we have y = mx+b as the slope intercept form template.

Answer: Choice C) f(x) = x
Answer:

Option: C is the correct answer.

              C.)  F(x)= x

Step-by-step explanation:

We know that a linear parent function is a function whose graph is a straight line passing through the origin and the equation of such a function is given by:

                                y=F(x)=x

Since, it is the simplest form of the equation of all the linear functions that are known to us and hence known as the parent linear function.

Is 50 degrees celsius hotter than 50 degrees fahrenheit?

Answers

50 degrees Celsius is half way between freezing and boiling so 50 degrees celsius is hotter then 50 degrees fahrenheit 
Final answer:

50 degrees Celsius is hotter than 50 degrees Fahrenheit because the Celsius scale rises at a faster rate of 1.8 times the Fahrenheit scale per degree, which measurably shows the greater warmth of 50°C compared to 50

Explanation:

Yes, 50 degrees Celsius is hotter than 50 degrees Fahrenheit. To understand why, let's look at how temperature is measured on both scales. On the Celsius scale, the freezing point of water is 0°C and the boiling point is 100°C, whereas on the Fahrenheit scale, the freezing point is 32°F and the boiling point is 212°F. This means that 100 Celsius degrees cover the same range as 180 Fahrenheit degrees.

The rate at which temperature increases per degree is faster on the Celsius scale compared to the Fahrenheit scale. Specifically, each degree on the Celsius scale corresponds to a 1.8 times larger temperature change than one degree on the Fahrenheit scale. Therefore, a temperature of 50°C is significantly warmer than 50°F. so, 50°C is equivalent to 122°F, a fact made evident by the conversion formula: °F = (°C × 9/5) + 32.

Classify the function as linear or quadratic and identify the quadratic, linear, and constant terms. f(x) = (3x + 2)(−6x − 3)

A) quadratic function; quadratic term: 6x^2; linear term: 24x; constant term: −6

B) linear function; linear term: −21x; constant term: −6

C) quadratic function; quadratic term: −18x^2; linear term: −21x; constant term: −6

D) linear function; linear term: −18x^2; constant term: −6

Answers

believe the answer is d, though I’m not completely sure. hope this helps

Answer:

The correct Option is C).  quadratic function; quadratic term: −18x²; linear term: −21x ; constant term: −6

Step-by-step explanation:

Given : f(x) = (3x + 2)(-6x - 3)

Now, f(x) = -18x² -9x -12x - 6

⇒ f(x) = -18x² - 21x - 6

Now, since the highest degree of the given function f(x) is 2 so the function f(x) is quadratic.

Now, quadratic term is one which has highest power x = 2 So, quadratic term = -18x²

Linear term is one which has  power x = 1 So, linear term = -21x

Constant term is one which has power of x = 0. So, constant term = -6

Hence, The correct Option is C).  quadratic function; quadratic term: −18x²; linear term: −21x ; constant term: −6

A prism is named for the shape of its bases.

True

False

Answers

True
Wikipedia says "Prisms are named for their bases, so a prism with a pentagonal base is called a pentagonal prism."
https://en.wikipedia.org/wiki/Prism_(geometry)


true

Step-by-step explanation:

Hope is helps and good luck

he formula for a trapezoid relates the area A, the two bases, a and b, and the height, h.

A=1/2 h(a+b)

Solve for h.

Answers

If you want to isolate h, move all terms to the other side, leaving h behind. 

A=1/2h(a+b) 
2A=1h(a+b) 
2A/a+b=h 

Hope I helped :)

Find two positive numbers such that the sum of one and the square of the other is 200 and whose product is a maximum.

Answers

the maximum of f(y) must be occur at the middle point of two y-intercepts y = 0, and y =100 . So, (0+100)/2 = 50.

What is the class rank if someone has the 40th best GPA in his class of 600?

Answers

The rank would be 40 out of 600, or 40th
The rank would be 40 out of 600, or 40thhope this helps:D

What is the difference between 3/7 and 1/14

Answers

The difference between 3/7 and 1/14 is that 3/7 is 5/14 bigger than 1/14

3/7 = 6/14

6/14 - 1/14 = 5/14

hope this helps

what is the mass of an object that has a force of 100 Newtons and acceleration of 25 m/s2

Answers

F=ma
m=F/a
m=100/25=4 kg
Mass of an object is 4 kg

True or false? If four points are collinear, they are also coplanar

Answers

If we are given four points, it can be the case that the points are found in the same line or called collinear lying on the same axis. However,  it is not  a guarantee that those points are also coplanar. Yes, four points can create a plane but not at all time they are also collinear.

We have that the statement  If four points are collinear, they are also coplanar is

True

From the Question we are told that

four points are collinear

Collinear

This occurs when three or more lines lines on the same plane or line

While

Coplanar is when simply means on the same plane

Therefore

If four points are collinear, they are also coplanar

For more information on this visit

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A general contractor is constructing a building that requires a concrete foundation that is to be 20 feet by 12 feet and 4 inches thick. if the local home supply store sells concrete for $125 per cubic yard, what will be the cost of the concrete for the foundation?

Answers

First we calculate the volume of the foundation:

Volume (V) = 20 ft * 12 ft * 4 in (1 ft / 12 in)

V = 80 ft^3

 

Since the cost is in cubic yard (yard^3) so convert:

V = 80 ft^3 * (1 yard^3 / 27 ft^3) = 2.963 yard^3

 

So the total cost is:

cost = ($125 / yard^3) * 2.963 yard^3

cost = $370.37

Answer:

$370.37.

Step-by-step explanation:

We have been given that a general contractor is constructing a building that requires a concrete foundation that is to be 20 feet by 12 feet and 4 inches thick.

First of all, we will convert the given dimensions of foundation in yards.

[tex]\text{3 feet}=\text{1 yard}[/tex]

[tex]20\text{ feet}=\frac{20}{3}\text{ yards}[/tex]

[tex]12\text{ feet}=\frac{12}{3}\text{ yards}[/tex]

[tex]\text{36 inches}=\text{1 yard}[/tex]

[tex]\text{4 inches}=\frac{4}{36}\text{ yards}=\frac{1}{9}\text{ yards}[/tex]

Since the foundation of building is in form of cuboid, so volume of foundation will be the product of 3 sides.

[tex]\text{Volume of foundation}=\frac{20}{3}\text{ yards}\times \frac{12}{3}\text{ yards}\times \frac{1}{9}\text{ yards}[/tex]

[tex]\text{Volume of foundation}=\frac{20\times 12\times 1}{3\times 3 \times 9}\text{ yards}^3[/tex]

[tex]\text{Volume of foundation}=\frac{240}{81}\text{ yards}^3[/tex]

[tex]\text{Volume of foundation}=2.962962962962963\text{ yards}^3[/tex]

Since the local home supply store sells concrete for $125 per cubic yard, so the cost of the concrete for the foundation will be the volume of foundation times $125.

[tex]\text{The cost of the concrete for the foundation}=2.962962962962963\text{ yards}^3\times \frac{\$125}{\text{ yards}^3}[/tex]

[tex]\text{The cost of the concrete for the foundation}=\$370.37037\approx \$370.37[/tex]

Therefore, the cost of the concrete for the foundation is $370.37.

the ordered pair (2 36) is a solution to which equation(s)

A. y=2x^2
B. y=(3x)^2
C. y=7x^2+2
D. y=(x+4)^2

Answers

(2, 36) → x = 2, y = 36

Substitute the value of x and y to the equations of the functions:

A. y = 2x^2

36 = 2(2)^2 → 36 = 8 FALSE

B. y = (3x)^2

36 = (3 · 2)^2 → 36 = 6^2 → 36 = 36 CORRECT

C. y = 7x^2 + 2

36 = 7(2)^2 + 2 → 36 = 7 · 4 + 2 → 36 = 30 FALSE

D. y = (x + 4)^2

36 = (2 + 4)^2 → 36 = 6^2 → 36 = 36 CORRECT

Answer: B. y = (3x)^2 and D. (x + 4)^2

Twenty-five members of the eighth grade class at Park Center Middle School are going to a museum and then to lunch. Each student must pay an entrance fee to the museum and $7.25 for lunch. The total cost for the trip is $443.75. What is the entrance fee for one student?

Answers

There are two costs involved:

1) the cost for lunch, which is given as a rate per student: $7.25/student

2) the cost for the trip which is $443.75 to be divided by the 25 students, so it is $443.75 / 25 = $17.75/student

Now, you can add up those two costs per student to have the total cost per student:

$7.25 + $17.75 = $25.00/student

Answer: $25.00

Answer: $17.75

Step-by-step explanation: $443.75 / 25 = $17.75

1. Factor the expression 3x^3 + 4x^2 - 15x - 20 Please show work!

Answers

Do the split method, by splitting it in the middle

Factor 3x^3 + 4x^2 and -15x - 20 seperately

x^2 (3x + 4) - 5(3x + 4)

(x^2 - 5)(3x + 4) is your answer

hope this helps
Final answer:

The expression 3x^3 + 4x^2 - 15x - 20 can be factored into the form (3x + 4)(x^2 - 5) by grouping terms, factoring out common components, and simplifying.

Explanation:

The provided expression to be factored is [tex]3x^3 + 4x^2 - 15x - 20.[/tex]Factoring this involves finding common factors and breaking the terms down until we cannot do so any further.

Group terms that look like they might have common factors: [tex](3x^3 + 4x^2) - (15x + 20).[/tex]Factor out the common factors: [tex]x^2(3x + 4) - 5(3x + 4).[/tex]Notice that we have the binomial of (3x + 4) common between both terms. We can now factor that out: [tex](3x + 4)(x^2 - 5).[/tex]

So, the factored form of the expression is [tex](3x + 4)(x^2 - 5).[/tex]

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