the following is an example of what property?
5=x+5
A. Multiplicative Property of Zero
B. Multiplicative Inverse Property
C. Additive Inverse Property
D. Additive Identity Property
E. Multiplicative Inverse Property
F. Commutative Property of Zero
G. Associative Property of Zero

Final answer:

The ratios 10/20 and 30/60 both simplify to 1/2, showing they form a proportion as they equal the same value when reduced to simplest form.

Explanation:

Proportion is a mathematical concept where two ratios are equivalent.

For example, the ratios 10/20 and 30/60 form a proportion.

We can show this by finding a common multiplier and simplifying the ratios.

10/20 can be simplified by dividing both the numerator and denominator by their greatest common divisor, which is 10.

This yields:

10 ÷ 10 = 1 and 20 ÷ 10 = 2. So, 10/20 simplifies to 1/2.

Similarly, 30/60 can be simplified by dividing both the numerator and denominator by 30, resulting in:

30 ÷ 30 = 1 and 60 ÷ 30 = 2. This simplifies to 1/2, the same as the first ratio.

Since both ratios simplify to 1/2, we can say that 10/20 and 30/60 form a proportion because they both equal the same value when reduced to simplest form.

Answer: 3.055 feet

Step-by-step explanation:

Given : The statue of liberty is 305.5 feet tall from the foundation of its pedestal to the top of its torch.

Its model will be one hundredth times as tall as the actual statue.

Now , One hundredth = [tex]\dfrac{1}{100}=0.01[/tex]

According to the statement,

The height of the model will be = [tex]\dfrac{1}{100}\times\text{Height of original statue}[/tex]

[tex]=\dfrac{1}{100}\times305.5=3.055\text{ feet}[/tex]

Hence, the height of the model will be 3.055 feet.

To find the starting amounts of cranberry and orange punch, we equate 2/3 of the cranberry punch to 5/6 of the orange punch. After setting up the equation 2/3 * C = 5/6 * O, we can solve for either C or O given a specific amount for one.

Understanding Proportional Quantities in Punch

To determine how many ounces of cranberry and orange punch might have been at the start of the party, given that guests drank 2/3 of the cranberry punch and 5/6 of the orange punch, and that they drank the same amount of each, we can set up an equation. Let's label the amount of cranberry punch initially as C ounces and the amount of orange punch initially as O ounces. According to the problem, 2/3 of C is equal to 5/6 of O; therefore:

2/3 * C = 5/6 * O

We can find a common multiple of the denominators 3 and 6 to solve the equation. For simplicity, let's assume that the common multiple is 6. If we multiply both sides of the equation by 6 to get rid of the fractions, we have:

4 * C = 5 * O

This means that the amount of cranberry punch is always 5/4 times the amount of orange punch. For example, if there were 20 ounces of orange punch at the start (O = 20), then there would have been 5/4 * 20 = 25 ounces of cranberry punch (C).

Final answer:

The party guests drank equal amounts of 2/3 of cranberry punch and 5/6 of orange punch. By setting up an equation and choosing a common multiple of the denominators (6), we conclude that one possible starting amount for each type of punch is 18 ounces, demonstrating that whenever x is chosen, y will be equal to x.

Explanation:

The student's question involves solving a problem where two quantities are compared to find out how much of each was present initially. Since the guests drank the same amount of cranberry punch and orange punch, with the proportions being 2/3 and 5/6 respectively, we can set up an equation to solve for the initial amounts.

Let x represent the original amount of cranberry punch and y represent the original amount of orange punch. According to the question:

2/3 of cranberry punch = 5/6 of orange punch

To find multiple answers, we could assume a common multiple of both denominators 3 and 6, which is 6. Then, if we let x = 6 and y = 6, we have:

However, these amounts are not equal. We need to find a value for x and y that, when substituted into the proportion, yields an equal amount for both types of punch. Multiply both sides of the equation by 3/2 to isolate y:

Now, we can select any multiple of 6 for x to represent the initial amount. If we choose multiple of 6 such as 18 ounces for x, then y would also be 18 ounces. Thus, the starting amount of both cranberry punch and orange punch could have been 18 ounces each as one of the possible answers.

Final answer:

Joan completed 13 free throws. This was determined by solving the equation derived from the information that Tabitha's 6 completed shots were a third of 5 more than Joan's completed shots.

Explanation:

Tabitha completed 6 free throws, which is stated to be a third of 5 more than Joan completed. This means that if J represents the number of shots Joan completed, then 6 is one-third of J plus 5. Therefore, we can express this relationship in an equation: 6 = (J + 5) / 3.

To find out how many shots Joan completed, we solve for J as follows:

Multiply both sides of the equation by 3 to eliminate the fraction: 18 = J + 5.

Subtract 5 from both sides to solve for J: J = 18 - 5.

Calculate the result: J = 13.

Hence, Joan completed 13 free throws.

Victoria would have paid $4.25 for 8.5 pounds of carrots if they were $0.50 less per pound.

To find out how much Victoria would have paid for 8.5 pounds of carrots if they were $0.50 less per pound, we need to subtract $0.50 from the original price per pound and then multiply it by 8.5.

Let's say the original price per pound of carrots is $1.00. Subtracting $0.50 from it gives us $0.50. Multiplying $0.50 by 8.5 gives us $4.25.

Therefore, Victoria would have paid $4.25 for 8.5 pounds of carrots if they were $0.50 less per pound.

Answer:

80 total candy bars

Step-by-step explanation;

set up proportion

24

30/100

24 x 100=2400 divided by 30

=80

The total number of candy bars that he has sold is 80 candy bars.

Using this formula

Total sold candy bars=Number of candy bars sold/Percentage of candy bar sold

Where:

Number of candy bars sold=24 candy bars

Percentage of candy bar sold=30%

Let plug in the formula

Total sold candy bars =24/0.30

Total sold candy bars=80 candy bars

Inconclusion the total number of candy bars that he has sold is 80 candy bars.

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Answer:

Do the one that looks like this

here is also a really cute pic

Keywords:

Water, plant, water, liters, daily, milliliters, divide

For this case we must find the amount of liters of water that students used daily, for 28 days, to water a plant, knowing that they used a total of 23.8 liters of water at the end of 28 days. For this, we must divide and the result convert it to milliliters. So:

Let "x" be the number of liters of water that students used per day:

[tex]x = \frac {23.8\ liters} {28\ days}\\x = 0.85\ liters\ per\ day.[/tex]

Thus, the students used 0.85 liters of water per day.

On the other hand, we know that: 1 liter equals 1000 milliliters. Then, by rule of three:

1 L -------------> 1000 mL

0.85L ---------->?

Where "?" represents the amount of daily water watered in milliliters

[tex]? = \frac {0.85 * 1000} {1}\\? = 850\ mL[/tex]

Thus, the students used 850 milliliters of water per day.

Answer:

850 milliliters of water per day.

They use 0.85 liters = 850 mililiters each day.

Comparison is an effort to compare two or more objects in terms of shape or size, or number

Proportional Comparisons are comparisons of two or more numbers where one number increases, the other numbers also increase

[tex]\frac {x1} {y1} = \frac {x2} {y2}[/tex]

  so that if:

  x = 2

  then

[tex]y =  \frac {y} {x} \times \: 2[/tex]

While the reversal value comparison is the comparison of two or more numbers where one number increases, the other number decreases in value

  Can be formulated

 [tex]\displaystyle \frac {x1} {y2} = \frac {x2} {y1}[/tex]

so that if:

  x = 2

  then

[tex]\displaystyle y = \frac {x} {y} \times \: 2[/tex]

students use a total of 23.8 liters of water over the 28 days

The amount of water used in a day

From this we can make a comparison:

[tex]28~days=23.8~liters[/tex]

[tex]1~day=x~liter[/tex]

[tex]\displaystyle \frac{1~day}{28~day} =\frac{x~liters}{23.8}[/tex]

[tex]\displaystyle x~=~\frac{1~\times~23.8}{28}[/tex]

x = 0.85 liters

From the unit of volume, we convert liters to milliliters

1 liter = 10³ milliliters

0.85 liters we move the comma 3 units to the right becomes:

[tex]\displaystyle 0.85 = 0~\boxed{,}\rightarrow~8~\rightarrow~5~\rightarrow~0~\boxed{,}[/tex]

= 850 mililiters

1,092 flowers are arranged into 26 vases  

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Keywords: water a plant, liters, mililiters,students

8.0

Hope this helped it probbaly didnt just have a nice day

Final answer:

The percent error in Clara's estimate of the hiking trail length is calculated using the difference between actual and estimated lengths, resulting in an 8.0% error. Option B is correct.

Explanation:

To calculate the percent error in Clara's estimate of the hiking trail's length, we use the formula: percent error = (|Actual length - Estimated length| / Actual length) × 100. Clara estimated the length to be 5.75 km, while the actual length is 6.25 km.

First, calculate the absolute difference between the actual and estimated lengths: |6.25 km - 5.75 km| = 0.5 km.

Then, divide this difference by the actual length: 0.5 km / 6.25 km = 0.08.

Finally, convert this to a percentage by multiplying by 100: 0.08 × 100 = 8.0%.

Therefore, the percent error in Clara's estimate is 8.0%, making option B the correct answer.