The file CEOSAL2.RAW contains data on 177 chief executive officers and can be used to examine the effects of firm performance on CEO salary. (i) Estimate a model relating annual salary to firm sales and market value. Make the model of the constant elasticity variety for both independent variables. Write the results out in equation form. (ii) Add profits to the model from part (i). Why can this variable not be included in logarithmic form
Answers
Find the given attachment for the solution
A model relating a CEO's annual salary to firm's sales, market value, and profits is proposed. The equation takes a logarithmic form of sales and market value for the elasticity. Profits cannot take a logarithmic form due to the possibility of negative values.
Explanation:The objective of this question is to build a model relating CEO's annual salary to firm sales, market value, and profits, using the data from CEOSAL2.RAW. The model would be a constant elasticity variety for the sales and market variables. The standard form of a constant elasticity model is ln(Y) = a + b1*ln(X1) + b2*ln(X2) + u, where Y represents the dependent variable (CEO's annual salary), X1 and X2 represent independent variables (firm sales and market value).
Now adding profits to the model, your equation would be: ln(Y) = a + b1*ln(X1) + b2*ln(X2) + b3*X3 + u, where X3 denotes the firm's profits. It is not in logarithmic form because profits can be negative, and the natural log of a negative number is undefined in real numbers.
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Related Questions
What is 25% of 140? 14 30 35 40
Answers
hi
Here is the answer :
0.25 *140 = 35
Answer: 35
Step-by-step explanation: Well percent means over 100 so we can set up an equation for this problem by reading it from left to right.
What means x, is means equals, 25% is 25/100,
of means times, and 250 means 250.
So we have the equation x = 25/100 · 40.
Simplifying on the right side of the equation,
notice that 25/100 reduces to 1/4.
So we have x = 1/4 · 40.
Think of the 40 as 40/1.
So we can cross-cancel 140 and 4 to 35 and 1
and we have x = (1)(35) over (1)(1) or x = 35.
Now let's check our answer back in the
original problem to see if it makes sense.
We have (35) is 25% of 140.
Well we know that 100% of 140 would be 140.
So 25% of 250 should be a lot less than 140.
So 35 seems to make sense as a pretty good answer.
I have shown my work in the image attached.
What is the explicit formula for this geometric sequence?
8,4, 2, 1, ...
Answers
Answer:
[tex]a_{n}[/tex] = 8 *[tex]0.5^{n-1}[/tex]
Step-by-step explanation:
First find the common ratio
r = 4/8 = 1/2
and first term is 8
a_n = a_1 * r^(n-1)
a_n = 8 * (1/2)^(n-1)
[tex]a_{n}[/tex] = 8 *[tex]0.5^{n-1}[/tex]
Lindsay Electronics, a small manufacturer of electronic research equipment, has approximately 6 comma 500 items in its inventory and has hired Joan Blasco-Paul to manage its inventory. Joan has determined that 11% of the items in inventory are A items, 33% are B items, and 56% are C items. She would like to set up a system in which all A items are counted monthly (every 20 working days), all B items are counted quarterly (every 62 working days), and all C items are counted semiannually (every 121 working days). How many items need to be counted each day? The total number of items that need to be counted each day is nothing items (round your response to the nearest whole number).
Answers
Answer:
The total number of items to be counted each day ≈ 100
Step-by-step explanation:
Lindsay Electronics has 6,500 items in its inventory.
11% of the items in inventory are A items
33% of the items in inventory are B items
56% of the items in inventory are C items
A items are counted every 20 working days
B items are counted every 62 working days
C items are counted every 121 working days
How many items need to be counted each day?
First we will find the number of items of type A, B and C
Number of A items = 11% of 6,500 = 0.11*6500 = 715
Number of B items = 33% of 6,500 = 0.33*6500 = 2145
Number of C items = 56% of 6,500 = 0.56*6500 = 3640
The number of A items to be counted each day is
A items = 715/20
The number of B items to be counted each day is
B items = 2145/62
The number of C items to be counted each day is
C items = 3640/121
The total number of items to be counted each day is
Total items = 715/20 + 2145/62 + 3640/121
Total items = 100.42
Rounding the answer to the nearest whole number yields,
Total items ≈ 100
John placed $2,000 in a savings account which compounds interest annually at a rate of 4.3%. How much will he have in the account after 3 years?
Round your answer to the nearest dollar.
Do NOT round until you have calculated the final answer.
Answers
Answer:
The amount of money he has in the account after 3 years:
A = Money x (1 + rate)^year
= 2000 x (1 + 4.3/100)^3
=2269.3 dollar
Hope this helps!
:)
Answer:
Amount of money in the account: $2,269.25
Interest: $269.25
Step-by-step explanation:
John starts out with $2000 in savings.
(I can't be bothered to find the formula for annual compound interest, so we'll do it manually based on yearly calculations.)
Because it is calculated annually, we must do yearly calculations.
Year One:2,000 x 1.043 = 2,086.00
After the first year, at 4.3% John's $2000 Savings account would mature into $2,086.00. (earning him $86.00 interest for the year)
Year Two:2,086.00 x 1.043 = 2,175.70
After, the second year at 4.3%, $2,086.00 becomes $2,175.70. (making his interest $175.70 total, and $89.70 for the year.)
Year Three:2,175.70 x 1.043 = 2,269.25
After the third, and final year, at 4.3%, $2,175.70 becomes $2,269.25. (making the interest $269.25 or $93.56 for the year.)
What’s the correct answer for this?
Answers
Answer:
D.
Step-by-step explanation:
Density = mass / volume
Density= 3 , mass = 80
3 = 80 / volume
Volume = 80 / 3
Volume = 26.67 cubic inch
Now volume of a cube= 3 (side length)
26.67 = 3(side length)
Side length=26.67 /3
Side length=8.89 inches
Side length ≈ 9 inches
what is the surface area to a cylinder
A. 2(Pi)rh+2(Pi)r^2
B. 1/2Pl+B
C. Ph+2B
D.(Pi)rl+(Pi)r^2
E. Bh
D.(Pi)r^2h
Answers
Answer:
A. 2(Pi)rh+2(Pi)r^2
Step-by-step explanation:
The surface area of a cylinder is the sum of the lateral area and the area of the two circular ends.
The lateral area is the product of the circumference of the cylinder and its height:
lateral area = 2πrh
The area of the two ends is twice the area of each of those circles, so is ...
total end area = 2(πr²)
Then the total surface area of a cylinder is ...
SA = 2πrh +2πr²
if a pack of 12 pencils cost $1.29 how much does a single pencil cost
Answers
Answer:
$0.11 (2 d.p.)
Step-by-step explanation:
Please see the attached picture for the full solution.
The cost of one pencil is 10.75 cents.
First, convert the total cost from dollars to cents.
As we know,
Since $1.29 is equal to 129 cents:
$1.29 * 100
= 129 cents.
Next,
divide 129 cents by 12 pencils to find the cost per pencil:
129 cents / 12 pencils
= 10.75 cents.
So, the cost of one pencil is 10.75 cents.
MULTIPLE CHUICE QUESTION
What is the GCF of 2x4 and 4x2
Answers
Answer:8
Step-by-step explanation:
2x4=2x2x2
4x2=2x2x2
The greatest common factor is 2x2x2=8
Certain transportation company has a fleet of 210 vehicles. The average age of the vehicles is 4.25 years, with a standard deviation of 18 months. In a random sample of 40 vehicles, what is the probability that the average age of vehicles in the sample will be less than 4 years
Answers
Answer:
[tex]z = \frac{4-4.25}{\frac{1.5}{\sqrt{40}}}= -1.054[/tex]
And we can find the following probability:
[tex] P(z<-1.054) = 0.146[/tex]
And the last probability can be founded using the normal standard distribution or excel.
Step-by-step explanation:
For this case we define the random variable X as the ages of vehicles. We know the following info for this variable:
[tex]\bar X = 4.25[/tex] represent the mean
[tex]\sigma =18/12=1.5[/tex] represent the deviation in years
They select a sample size of n=40>30. And they want to find this probability:
[tex] P(\bar X<40)[/tex]
Since the sample size is large enough we can use the central limit theorem and the distribution for the sample mean would be:
[tex]\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}}) [/tex]
We can use the z score formula given by:
[tex] z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
And if we find the z score for 4 we got:
[tex]z = \frac{4-4.25}{\frac{1.5}{\sqrt{40}}}= -1.054[/tex]
And we can find the following probability:
[tex] P(z<-1.054) = 0.146[/tex]
And the last probability can be founded using the normal standard distribution or excel.
A marketing survey involves brand recognition in New York and California. Of 147 New Yorkers surveyed, 79 were familiar with the brand while 78 out of 147 Californians knew this brand as well. Assume that you plan to test the claim that the proportion of New Yorkers who recognize this brand differs from the proportion of Californians who do the same, i.e., p1 ≠ p2. Use the given information to find the pooled sample proportion begin mathsize 14px style p with bar on top end style. Round your answer to three decimal places.
Answers
Answer:
[tex]z=\frac{0.537-0.531}{\sqrt{0.534(1-0.534)(\frac{1}{147}+\frac{1}{147})}}=0.103[/tex]
Now we can calculate the p value with the following probability taking in count the alternative hypothesis:
[tex]p_v =2*P(Z>0.103) =0.918 [/tex]
For this case since the p value is large enough we have enough evidence to FAIL to reject the null hypothesis and we can't conclude that we have significant differences between the two proportions analyzed.
Step-by-step explanation:
Information provided
[tex]X_{1}=79[/tex] represent the number of New Yorkers familiar with the brand
[tex]X_{2}=78[/tex] represent the number of Californians familiar with the brand
[tex]n_{1}=147[/tex] sample of New Yorkers
[tex]n_{2}=147[/tex] sample of Californians
[tex]p_{1}=\frac{79}{147}=0.537[/tex] represent the proportion New Yorkers familiar with the brand
[tex]p_{2}=\frac{78}{147}=0.531[/tex] represent the proportion of Californians familiar with the brand
[tex]\hat p[/tex] represent the pooled estimate of p
z would represent the statistic
[tex]p_v[/tex] represent the value
System of hypothesis
We want to verify if the two proportions of interest for this case are equal, the system of hypothesis would be:
Null hypothesis:[tex]p_{1} = p_{2}[/tex]
Alternative hypothesis:[tex]p_{1} \neq p_{2}[/tex]
The statistic would be given by:
[tex]z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}[/tex] (1)
Where [tex]\hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{79+78}{147+147}=0.534[/tex]
Repalcing the info given we got:
[tex]z=\frac{0.537-0.531}{\sqrt{0.534(1-0.534)(\frac{1}{147}+\frac{1}{147})}}=0.103[/tex]
Now we can calculate the p value with the following probability taking in count the alternative hypothesis:
[tex]p_v =2*P(Z>0.103) =0.918 [/tex]
For this case since the p value is large enough we have enough evidence to FAIL to reject the null hypothesis and we can't conclude that we have significant differences between the two proportions analyzed.
For each of the following situations, state whether a Type I, a Type II, or neither error has been made.
a) A test of H0: p = 0.6 vs. HA: p < 0.6 fails to reject the null hypothesis. Later it is discovered that p = 0.7.
b) A test of H0: μ = 30 vs. HA: μ > 30 rejects the null hypothesis. Later it is discovered that μ = 29.9.
c) A test of H0: p = 0.4 vs. HA: p /= 0.4 rejects the null hypothesis. Later it is discovered that p = 0.55.
d) A test of H0: p = 0.7 vs. HA: p < 0.7 fails to reject the null hypothesis. Later it is discovered that p = 0.6.
Answers
Answer:
Step-by-step explanation:
a) A test of H0: p = 0.6 vs. HA: p < 0.6 fails to reject the null hypothesis. Later it is discovered that p = 0.7.
Answer: No error has been made since there is not enough statistical evidence to reject the null.
b) A test of H0: μ = 30 vs. HA: μ > 30 rejects the null hypothesis. Later it is discovered that μ = 29.9.
A type I error has been made. Rejecting the null hypothesis when it is actually true.
c) A test of H0: p = 0.4 vs. HA: p /= 0.4 rejects the null hypothesis. Later it is discovered that p = 0.55.
A type I error has been made since the p value was greater than 0.4, one will fail to reject the null but in the case the null was rejected.
d) A test of H0: p = 0.7 vs. HA: p < 0.7 fails to reject the null hypothesis. Later it is discovered that p = 0.6.
A type II error has been made since the p value is less than 0.7 and it was expected that the null should be rejected but that ws not the case.
In situation a and d, a Type II error was made as the null hypothesis was not rejected but it should have been. In situation b, a Type I error was made as the null hypothesis was rejected but it shouldn't have been. In situation c, neither error was made as the null hypothesis was correctly rejected.
Explanation:In each of the following situations, different types of errors are made. A type I error is made when the null hypothesis is true, but it is rejected. A type II error is the opposite, when the null hypothesis is false, but it isn't rejected.
a) Type II error: The null hypothesis was not rejected, although the actual population proportion (0.7) was greater than the hypothesized proportion (0.6). b) Type I error: The null hypothesis was rejected, but it was actually true as the actual population mean (29.9) was less than the hypothesized mean (30).c) Neither error: The null hypothesis was rightly rejected, as the actual population proportion (0.55) was not equal to the hypothesised proportion (0.4).d) Type II error: The null hypothesis was not rejected, although the actual population proportion (0.6) was less than the hypothesized proportion (0.7).
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The radius of a circle is 9 feet. What is the circumference?
Answers
Answer:
The answer would be 56.55ft please give brainliest :)
Answer:
55.65
Step-by-step explanation:
Let X1, X2, and X3 represent the times necessary to perform three successive repair tasks at a service facility. Suppose they are normal random variables with means of 50 minutes, 60 minutes, and 40 minutes, respectively. The standard deviations are 15 minutes, 20 minutes, and 10 minutes, respectively. a Suppose X1, X2, and X3 are independent. All three repairs must be completed on a given object. What is the mean and variance of the total repair time for this object.
Answers
Answer:
The mean of the total repair time is 150 minutes.
The variance of the total repair time is 725 minutes^2.
Step-by-step explanation:
To solve this problem, we have to use the properties of the mean and the variance. Our random variable is the sum of 3 normal variables.
In the case, for the mean, we have that the mean of the sum of 3 normal variables is equal to the sum of the mean of the 3 variables:
[tex]y=x_1+x_2+x_3 \\\\E(y)=E(x_1+x_2+x_3)=E(x_1)+E(x_2)+E(x_3)\\\\E(y)=50+60+40=150[/tex]
For the variance, we apply the property for the sum of independent variables (the correlation between the variables is 0):
[tex]V(y)=V(x_1)+V(x_2)+V(x_3)\\\\V(y)=s_1^2+s_2^2+s_3^2\\\\V(y)=15^2+20^2+10^2\\\\V(y)=225+400+100\\\\V(y)=725[/tex]
x² + y² − 10x + 6y − 47 = 0.
Select one:
A. center: (−4, −3); radius: 5
B. center: (5, −3); radius: 9
C. center: (−2, 5); radius: 3
D. center: (1, 3); radius: 9
Answers
The odds of winning a contest are 3:7. What is the probability winning the contest?
Answers
Answer:
0.3
Step-by-step explanation:
Given: The odds of winning a contest are 3:7
To find: probability of winning the contest
Solution:
Probability refers to chances of occurrence of an event.
Odds are defined as (chances for success) : (chances against success)
Probability of winning = (chances for success) : (chances for success + chances against success)
As odds of winning a contest are 3:7,
(chances for success) : (chances against success) = 3:7
So,
Probability of winning the contest = [tex]\frac{3}{3+7} =\frac{3}{10}=0.3[/tex]
Final answer:
To find the probability of winning a contest when given odds, add the two parts of the odds together and divide the favorable outcome by the total outcomes. For odds of 3:7, the probability of winning the contest is 3/10.
Explanation:
The odds of winning a contest are 3:7. What is the probability of winning the contest?
To find the probability from odds, you need to add the two numbers together to get the total possible outcomes. In this case, 3 + 7 = 10. Then, divide the favorable outcome by the total outcomes, so 3/10. This gives a probability of winning the contest as 3/10.
Use the given level of confidence and sample data to construct a confidence interval for the population proportion p.
n= 195, p^=p hat= 0.831, Confidence level=95%
a.) 0.777
Answers
Answer:
The 95% confidence interval for the population proportion is (0.778, 0.884).
Step-by-step explanation:
We have to calculate a 95% confidence interval for the proportion.
The sample proportion is p=0.831.
The standard error of the proportion is:
[tex]\sigma_p=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.831*0.169}{195}}\\\\\\ \sigma_p=\sqrt{0.00072}=0.027[/tex]
The critical z-value for a 95% confidence interval is z=1.96.
The margin of error (MOE) can be calculated as:
[tex]MOE=z\cdot \sigma_p=1.96 \cdot 0.027=0.053[/tex]
Then, the lower and upper bounds of the confidence interval are:
[tex]LL=p-z \cdot \sisgma_p = 0.831-0.053=0.778\\\\UL=p+z \cdot \sisgma_p = 0.831+0.053=0.884[/tex]
The 95% confidence interval for the population proportion is (0.778, 0.884).
Find n(A) for the set A = {300, 301, 302, ..., 3000}
Answers
Answer:
n(A) = 2701
Step-by-step explanation:
If we subtract 299 from the numbers in the set, we get the counting numbers ...
{1, 2, 3, ..., 2701}
The number of elements in the set is 2701:
n(A) = 2701
n(A) is a notation used to denote the number of elements in a set. For the set A = {300, 301, 302, ..., 3000}, n(A) is calculated as 2701.
Explanation:To find n(A) for the set A = {300, 301, 302, ..., 3000}, let's first understand that n(A) means. n(A) is a notation used in set theory to denote the number of elements in a set. In this case, it’s asking for the total number of integers from 300 to 3000.
You can calculate it by using the formula n = the last number - the first number + 1. Substituting the given values, we get n = 3000 - 300 + 1 = 2701. Therefore, n(A) for the set is 2701.
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Jersey constructed a small wooden jewelry box, shown below, for her mother.
'Picture not drawn to scale
What is the volume of the jewelry box?
A. 234 cu in
B.
15
cu in
32 cu in
D.
117 cu in
Answers
Answer:
(D)117 Cubic Inches
Step-by-step explanation:
Dimensions of the box are:
Length[tex]=7\frac{1}{2}\:inch[/tex]
Width[tex]=4\frac{1}{3}\:inch[/tex]
Height[tex]=3\frac{3}{5}\:inch[/tex]
Volume of the Box =Length X Width X Height
[tex]=7\dfrac{1}{2}X4\dfrac{1}{3}X3\dfrac{3}{5}\\\\=\dfrac{15}{2}X\dfrac{13}{3}X\dfrac{18}{5}\\\\=\dfrac{15X13X18}{2X3X5}\\\\=\dfrac{3510}{30}[/tex]
=117 Cubic Inches
The volume of the box is 117 cubic inches.
Answer:
D) 117 cubic inches
Step-by-step explanation:
Have a wonderful day!
Plz help if you can
Thank ya
Answers
Answer:
[tex]90\pi[/tex]
Step-by-step explanation:
The first step is to find the slant height of the cone. Using the pythagorean theorem, you can find that [tex]\sqrt{12^2+5^2}=13[/tex] cm. Plugging this into the equation, you get [tex]\pi \cdot 5 \cdot 13=90\pi[/tex]. Hope this helps!
Metacritic is a website that aggregates reviews of music, games, and movies. For each product, a numerical score is obtained from each review and the website posts the average core as well as individual reviews. The website is somewhat similar to Rotten Tomatoes, but Metacritic uses a different method of scoring that converts each review into score in 100-point scale. In addition to using the reviewers quantitative ratings (stars, 10-point scale), Metacritic manually assesses the tone of the review before scoring. Historical data shows that these converted scores are normally distributed. One of the movies that the Metacritic rated was Zootopia. Based on the data from Metacritic on November 20, 2017, there are n=43 reviews, the sample average score is 77.86, and the sample standard deviation is 11.30.
A 95% confidence interval for the true average score (µ) of Zootopia is:
a) [75.21, 81.50]
b) [76.38, 80.34]
c) [77.15, 82.84]
d) [78.96, 81.76]
e) None of the above
Answers
Answer:
e) None of the above
Step-by-step explanation:
We are in posession of the sample's standard deviation, so we use the student t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 43 - 1 = 42
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 42 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.95}{2} = 0.975[/tex]. So we have T = 2.0181
The margin of error is:
M = T*s = 2.0181*11.3 = 22.80
In which s is the standard deviation of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 77.86 - 22.8 = 55.06
The upper end of the interval is the sample mean added to M. So it is 77.86 + 22.8 = 100.66.
So the correct answer is:
e) None of the above
Answer:
[tex]77.86-2.02\frac{11.30}{\sqrt{43}}=74.38[/tex]
[tex]77.86+2.02\frac{11.30}{\sqrt{43}}=81.34[/tex]
And for this cae none of the options satisfy the result so then the best option would be:
e) None of the above
Step-by-step explanation:
Information given by the problem
[tex]\bar X= 77.86[/tex] represent the sample mean for the score
[tex]\mu[/tex] population mean
s=11.30 represent the sample standard deviation
n=43 represent the sample size
Calculating the confidence interval
The confidence interval for the true mean of interest is given by:
[tex]\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}[/tex] (1)
For this case the degrees of freedom are:
[tex]df=n-1=43-1=42[/tex]
The Confidence is 0.95 or 95%, the significance then is [tex]\alpha=1-0.95=0.05[/tex] and [tex]\alpha/2 =0.025[/tex], the critical value for this case would be [tex]t_{\alpha/2}=2.02[/tex]
And replacing in equation (1) we got:
[tex]77.86-2.02\frac{11.30}{\sqrt{43}}=74.38[/tex]
[tex]77.86+2.02\frac{11.30}{\sqrt{43}}=81.34[/tex]
And for this cae none of the options satisfy the result so then the best option would be:
e) None of the above
8x+112x+392 factor perfect squares
Answers
1
2
0
x
+
120x+392
Step-by-step explanation:
Combine like terms.
8y2 + 8(4y2 − 7) =
Answers
Answer:
= 80y - 56 then it will be the answer, it may be incorrect so i apologize if it is.
Answer:
80y - 56
Step-by-step explanation:
2/3x - 5/6 equal to or greater than 1/2
Answers
The solution to the inequality [tex]\( \frac{2}{3}x - \frac{5}{6} \geq \frac{1}{2} \)[/tex] is [tex]\( x \geq 2 \)[/tex].
Given inequality: [tex]\( \frac{2}{3}x - \frac{5}{6} \geq \frac{1}{2} \)[/tex]
Step 1: To simplify the equation, let's find a common denominator for the fractions. The least common multiple (LCM) of 3 and 6 is 6.
Step 2: Rewrite the fractions with the common denominator, which is 6.
So, [tex]\( \frac{2}{3}x - \frac{5}{6} \)[/tex] becomes [tex]\( \frac{4x}{6} - \frac{5}{6} \).[/tex]
Step 3: Now, we have the equation [tex]\( \frac{4x}{6} - \frac{5}{6} \geq \frac{1}{2} \).[/tex]
Step 4: Combine the fractions on the left side of the equation: [tex]\( \frac{4x - 5}{6} \geq \frac{1}{2} \)[/tex].
Step 5: To get rid of the denominator, multiply both sides of the equation by 6 to clear it.
[tex]\( 6 \times \frac{4x - 5}{6} \geq 6 \times \frac{1}{2} \)[/tex]
This simplifies to: [tex]\( 4x - 5 \geq 3 \)[/tex]
Step 6: Now, let's isolate [tex]\(x\)[/tex] by adding 5 to both sides:
[tex]\( 4x - 5 + 5 \geq 3 + 5 \)[/tex]
[tex]\( 4x \geq 8 \)[/tex]
Step 7: Finally, divide both sides by 4:
[tex]\( \frac{4x}{4} \geq \frac{8}{4} \)[/tex]
[tex]\( x \geq 2 \)[/tex]
Complete correct question:
Solve: [tex]\frac{2}{3} x-\frac{5}{6} \geq \frac{1}{2}[/tex]
-5(-2) please help me and the other people out there
Answers
Answer:
10
Step-by-step explanation:
When two numbers are placed together that close with parenthesis, you are most likely (99.9% of the time), going to be multiplying them.
Note that:
When you multiply two positive numbers, your result is positive.
When you multiply one negative and one positive number, your result will be negative.
When you multiply two negative numbers, your result will be positive.
Multiply -5 with -2: -5 * -2 = 10
10 is your answer.
~
i really need help with this its due todayyy
Answers
Answer:
I will answer a few questions so you can apply the same logic to the others
The volume of a sphere = [tex]\frac{4}{3}[/tex] π [tex]r^{3}[/tex]
1.
We can see that the radius of the sphere is 5cm
Substitute the value into the equation for volume and solve for V
V = [tex]\frac{4}{3}[/tex] * π * [tex]5^{3}[/tex]
V = 523.6 [tex]cm^{3}[/tex]
4.
The diameter is given to us as 6km. To find the radius we take half of this, 3km
Substitute the value into the equation for volume and solve for V
V = [tex]\frac{4}{3}[/tex] * π * [tex]3^{3}[/tex]
V = 113.1 [tex]km^{3}[/tex]
Hopefully that helps you with completing the rest!
The two-way table shows the ages of the players on different soccer teams.
8 Years Old
9 Years Old
10 Years Old
Team A
4
9
2
15
Team B
6
4
3
13
Team
8
3
5
16
Team D
3
7
4
14
Total
21
23
14
|
|
|
|
|
58
Which statement is true?
The probability that a randomly selected player on Team A is 8 years old is 4
21
The probability that a randomly selected 8-year-old player is on Team C is 19
•
The probability that a randomly selected player on Team C is 10 years old is
a
The probability that a randomly selected 10-year-old player is on Team Bis 13
Answers
Answer: C 5/16
stay safe !!!
The probability that a randomly selected player on Team C 10 years old is 5/16.
What is the probability?Probability can be defined as the ratio of the number of favourable outcomes to the total number of outcomes of an event.
We know that, probability of an event = Number of favourable outcomes/Total number of outcomes.
According to the table the total number of 10 years old players on Team C is 5 and the total number of all ages players (8, 9 and 10 years old) on Team C is 16,
So the probability that a randomly selected player on Team C is 10 years old is 5/16.
Therefore, the probability that a randomly selected player on Team C 10 years old is 5/16.
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The value of the coefficient of correlation ( r) a. can never be equal to the value of the coefficient of determination (r2). b. is always larger than the value of the coefficient of determination (r2). c. is always smaller than the value of the coefficient of determination (r2). d. can be equal to the value of the coefficient of determination (r2).
Answers
Answer:
d. can be equal to the value of the coefficient of determination (r2).
True on the special case when r =1 we have that [tex] r^2 = 1[/tex]
Step-by-step explanation:
We need to remember that the correlation coefficient is a measure to analyze the goodness of fit for a model and is given by:
[tex]r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}[/tex]
The determination coefficient is given by [tex] R= r^2[/tex]
Let's analyze one by one the possible options:
a. can never be equal to the value of the coefficient of determination (r2).
False if r = 1 then [tex] r^2 = 1[/tex]
b. is always larger than the value of the coefficient of determination (r2).
False not always if r= 1 we have that [tex] r^2 =1[/tex] and we don't satisfy the condition
c. is always smaller than the value of the coefficient of determination (r2).
False again if r =1 then we have [tex] r^2 = 1[/tex] and we don't satisfy the condition
d. can be equal to the value of the coefficient of determination (r2).
True on the special case when r =1 we have that [tex] r^2 = 1[/tex]
The correct answer is d. can be equal to the value of the coefficient of determination (r²).
The coefficient of correlation (r) and the coefficient of determination (r²) are related statistical measures used to describe the strength and direction of the linear relationship between two variables.
The coefficient of correlation (r) quantifies the strength and direction of this linear relationship, ranging from -1 to 1, where -1 represents a perfect negative correlation, 1 represents a perfect positive correlation, and 0 represents no linear correlation.
On the other hand, the coefficient of determination (r²) is simply the square of the coefficient of correlation and represents the proportion of variance in one variable that can be explained by the linear relationship with the other variable.
Since r² is the square of r, it's entirely possible for them to be equal. In fact, when r is either 1 or -1 (perfect correlations), r² will be equal to 1, indicating that 100% of the variance in one variable is explained by the linear relationship with the other variable.
Similarly, when r is 0 (no linear correlation), r² will be equal to 0, indicating that none of the variance in one variable is explained by the linear relationship with the other variable.
So, the relationship between r and r² depends on the strength of the linear correlation, and they can indeed be equal under certain conditions.
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What is the product? 3x [ -6. -11, -14, -9]
Answers
The product of each number and 3x in the set [-6, -11, -14, -9] is [-18x, -33x, -42x, -27x]. The term 'product' refers to the result of multiplication. This was calculated by individually multiplying each number in the set by 3x.
Explanation:The question is asking what the product would be if you multiplied each number in the array by 3x. In mathematical terms, product refers to the result obtained from multiplying at least two numbers together.
Here's how we'd do this:
Multiply 3x and -6 together, so that's -18x.Next, multiply 3x and -11 to get -33x.Thirdly, 3x multiplied by -14 results in -42x.Lastly, 3x times -9 gives us -27x.So, in conclusion, the set of numbers you get when you multiply the original set by 3x are: [-18x, -33x, -42x, -27x]. You calculate these one at a time, following the laws of multiplication. I hope that helps explain in detail what the term 'product' means in this mathematical context, and how to find it.
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The scores for the Algebra 2 CFE are normally distributed with a mean score of 45 and a standard deviation of 5.6. If you score 52 on the test, what percentage of test takers scored lower than you?
87.49 %
89.44 %
90.32 %
91.15%
Answers
Answer:
89.44%
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question:
[tex]\mu = 45, \sigma = 5.6[/tex]
If you score 52 on the test, what percentage of test takers scored lower than you?
This is the pvalue of Z when X = 52.
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{52 - 45}{5.6}[/tex]
[tex]Z = 1.25[/tex]
[tex]Z = 1.25[/tex] has a pvalue of 0.8944.
So 89.44% of test takers scored lower than you.
Determine whether the following probability experiment represents a binomial experiment and explain the reason for your answer. An investor randomly purchases 3 stocks listed on a stock exchange. Historically, the probability that a stock listed on this exchange will increase in value over the course of a year is 49%. The number of stocks that increase in value is recorded.
Answers
Final answer:
No, the given probability experiment does not represent a binomial experiment because it does not meet the three conditions required for a binomial experiment.
Explanation:
No, the given probability experiment does not represent a binomial experiment. In order for an experiment to be considered a binomial experiment, it must meet three conditions:
1. There must be a fixed number of trials, denoted by 'n'. However, in the given experiment, the number of stocks that the investor purchases is not fixed.
2. There must be only two possible outcomes, called success and failure, for each trial. However, in the given experiment, the outcomes can have three possibilities: the stock can increase, decrease, or have no change in value.
3. The 'n' trials must be independent and repeated using identical conditions. However, in the given experiment, the success or failure of one stock can potentially influence the success or failure of another stock.