The display provided from technology available below results from using data for a smartphone​ carrier's data speeds at airports to test the claim that they are from a population having a mean less than 5.00 Mbps. Conduct the hypothesis test using these results. Use a 0.05 significance level. Identify the null and alternative​ hypotheses, test​ statistic, P-value, and state the final conclusion that addresses the original claim.

Answers

Answer 1

Answer:

The null and alternative hypothesis are:

[tex]H_0: \mu=5\\\\H_a:\mu< 5[/tex]

Test statistic t=-0.256

P-value = 0.4

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that that smartphone​ carrier's data speeds at airports is less than 5 mbps.

Step-by-step explanation:

The question is incomplete:

Sample mean (M): 4.79

Sample STD (s): 5.8

Sample size (n): 50

This is a hypothesis test for the population mean.

The claim is that that smartphone​ carrier's data speeds at airports is less than 5 mbps.

Then, the null and alternative hypothesis are:

[tex]H_0: \mu=5\\\\H_a:\mu< 5[/tex]

The significance level is 0.05.

The sample has a size n=50.

The sample mean is M=4.79.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=5.8.

The estimated standard error of the mean is computed using the formula:

[tex]s_M=\dfrac{s}{\sqrt{n}}=\dfrac{5.8}{\sqrt{50}}=0.82[/tex]

Then, we can calculate the t-statistic as:

[tex]t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{4.79-5}{0.82}=\dfrac{-0.21}{0.82}=-0.256[/tex]

The degrees of freedom for this sample size are:

[tex]df=n-1=50-1=49[/tex]

This test is a left-tailed test, with 49 degrees of freedom and t=-0.256, so the P-value for this test is calculated as (using a t-table):

[tex]P-value=P(t<-0.256)=0.4[/tex]

As the P-value (0.4) is bigger than the significance level (0.05), the effect is  not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that that smartphone​ carrier's data speeds at airports is less than 5 mbps.


Related Questions

Do political science classes require less writing than history classes? The 55 randomly selected political science classes assigned an average of 16.3 pages of essay writing for the course. The standard deviation for these 55 classes was 4.8 pages. The 54 randomly selected history classes assigned an average of 18.9 pages of essay writing for the course. The standard deviation for these 54 classes was 5 pages. What can be concluded at the α = 0.01 level of significance?

Answers

Answer:

We conclude that political science classes require less writing time than history classes at 0.01 level of significance.

Step-by-step explanation:

We are given that the 55 randomly selected political science classes assigned an average of 16.3 pages of essay writing for the course. The standard deviation for these 55 classes was 4.8 pages.

The 54 randomly selected history classes assigned an average of 18.9 pages of essay writing for the course. The standard deviation for these 54 classes was 5 pages.

Let [tex]\mu_1[/tex] = average writing time required by political science classes.

[tex]\mu_2[/tex] = average writing time required by history classes.

So, Null Hypothesis, [tex]H_0[/tex] : [tex]\mu_1\geq\mu_2[/tex]      {means that political science classes require more or equal writing time than history classes}

Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu_1<\mu_2[/tex]      {means that political science classes require less writing time than history classes}

The test statistics that would be used here Two-sample t test statistics as we don't know about the population standard deviation;

                     T.S. = [tex]\frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }[/tex]   ~ [tex]t__n_1_-_n_2_-_2[/tex]

where, [tex]\bar X_1[/tex] = sample average pages of essay writing for political science classes = 16.3 pages

[tex]\bar X_2[/tex] = sample average pages of essay writing for history classes = 18.9 pages

[tex]s_1[/tex] = sample standard deviation for political science classes = 4.8 pages

[tex]s_2[/tex] = sample standard deviation for history classes = 5 pages

[tex]n_1[/tex] = sample of political science classes = 55

[tex]n_2[/tex] = sample of history classes = 54

Also,  [tex]s_p=\sqrt{\frac{(n_1-1)s_1^{2}+(n_2-1)s_2^{2} }{n_1+n_2-2} }[/tex]  =  [tex]\sqrt{\frac{(55-1)\times 4.8^{2}+(54-1)\times 5^{2} }{55+54-2} }[/tex] = 4.90

So, test statistics  =  [tex]\frac{(16.3-18.9)-(0)}{4.9 \sqrt{\frac{1}{55}+\frac{1}{54} } }[/tex]  ~ [tex]t_1_0_7[/tex]

                               =  -2.77

The value of t test statistics is -2.77.

Now, at 0.01 significance level the t table gives critical value of -2.365 at 107 degree of freedom for left-tailed test.

Since our test statistics is less than the critical value of t, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that political science classes require less writing time than history classes.

A graph shows the horizontal axis numbered 2 to 8 and the vertical axis numbered 10 to 50. A line increases from 0 to 4 then decreases from 4 to 9.
Which type of function best models the data shown on the scatterplot?

Answers

Answer:

Quadratic

Step-by-step explanation:

Took a test and got it right

Answer:

quadratic

Step-by-step explanation:

Is the environment a major issue with Americans? To answer that question, a researcher conducts a survey of 1255 randomly selected Americans. Suppose 735 of the sampled people replied that the environment is a major issue with them. Construct a 95% confidence interval to estimate the proportion of Americans who feel that the environment is a major issue with them. What is the point estimate of this proportion?

Answers

Answer:

The point estimate of this proportion is [tex]\pi = 0.5857[/tex]

The 95% confidence interval to estimate the proportion of Americans who feel that the environment is a major issue with them is (0.5584, 0.6130).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the zscore that has a pvalue of [tex]1 - \frac{\alpha}{2}[/tex].

For this problem, we have that:

[tex]n = 1255, \pi = \frac{735}{1255} = 0.5857[/tex]

The point estimate of this proportion is [tex]\pi = 0.5857[/tex]

95% confidence level

So [tex]\alpha = 0.05[/tex], z is the value of Z that has a pvalue of [tex]1 - \frac{0.05}{2} = 0.975[/tex], so [tex]Z = 1.96[/tex].

The lower limit of this interval is:

[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5857 - 1.96\sqrt{\frac{0.5857*0.4143}{1255}} = 0.5584[/tex]

The upper limit of this interval is:

[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5857 + 1.96\sqrt{\frac{0.5857*0.4143}{1255}} = 0.6130[/tex]

The 95% confidence interval to estimate the proportion of Americans who feel that the environment is a major issue with them is (0.5584, 0.6130).

Answer:

The best point of estimate is given by:

[tex]\hat p =\frac{X}{n}= \frac{735}{1255}=0.586[/tex]

[tex]0.586 - 1.96\sqrt{\frac{0.586(1-0.586)}{1255}}=0.559[/tex]

[tex]0.586 + 1.96\sqrt{\frac{0.586(1-0.586)}{1255}}=0.613[/tex]

And we have 95% of confidence that the true proportion of Americans who feel that the environment is a major issue with them is between 0.559 and 0.613

Step-by-step explanation:

The interest is the real proportion of Americans who feel that the environment is a major issue with them. The best point of estimate is given by:

[tex]\hat p =\frac{X}{n}= \frac{735}{1255}=0.586[/tex]

Confidence interval

The confidence interval for the true proportion of interest is given by this:  

[tex]\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}[/tex]

We want an interval at 95% of confidence, so then the significance level is [tex]\alpha=1-0.95=0.05[/tex] and [tex]\alpha/2 =0.025[/tex]. And the critical value for this case are:

[tex]z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96[/tex]

Replacing into the confidence interval formula we got:

[tex]0.586 - 1.96\sqrt{\frac{0.586(1-0.586)}{1255}}=0.559[/tex]

[tex]0.586 + 1.96\sqrt{\frac{0.586(1-0.586)}{1255}}=0.613[/tex]

And we have 95% of confidence that the true proportion of Americans who feel that the environment is a major issue with them is between 0.559 and 0.613

Mr. De Leon's Geometry class has 34 students. After lunch everyone returns to the classroom. Within an hour, each person produces 800 BTUs. The room is 25 feet by 32 feet by 12 feet. How many BTUs per cubic foot were produced?

Plz provide the work.

Answers

Answer:

2.833  BTUs per cubic foot were produced.

Step-by-step explanation:

BTU's produced by one person = 800

No. of students = 34

Therefore no. of  BTU's produced by 34  person = 800 * 34 = 27,200 BTU

Dimension of class  25 feet by 32 feet by 12 feet

Volume of class = length * width * height = 25 * 12 * 32 = 9,600 cubic feet

________________________________________________

BTUs per cubic foot  produced = Total  BTU's produced by 34  person/ Volume of class

Substituting the value of Total BTU produced and volume of class

BTUs per cubic foot  produced =  27,200 BTU/  9,600 cubic feet

                                                    = 2.833 BTUs per cubic foot

2.833  BTUs per cubic foot were produced.

Jean-Patrick found an old unopened bag of lawn fertilizer in his shed. The bag weighs 36 pounds, and the instructions claim it can cover 10,000 ft^2. If his lawn is 7,000 ft^2, how many pounds will he need? Round to the nearest tenth if needed.

Answers

Answer:

25.2

Step-by-step explanation:

Weight of one bag of  lawn fertilizer = 36

area one bag of  lawn fertilizer can cover = 10,000 ft^2

Total area of lawn in the given problem = 7,000 ft^2

no. of bags of lawn fertilizer needed to cover the lawn = total area of lawn in the given problem / area,  one bag of  lawn fertilizer can cover

                                                             = 7,000/10,000 = 7/10 = 0.7 bags

Weight of full bags has 36 pounds of lawn fertilizer.

therefore,

Pounds of lawn fertilizer in 0.7 part of bag = 36 * 0.7 = 25.2 pounds (Answer)

n is an integer and -2

Answers

Answer:

-1, 0,1

Step-by-step explanation:

Hope this helps.

The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the eighth grade level. In an earlier study, the population proportion was estimated to be 0.21. How large a sample would be required in order to estimate the fraction of tenth graders reading at or below the eighth grade level at the 85% confidence level with an error of at most 0.03

Answers

Answer:

We need a sample size of at least 383.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the zscore that has a pvalue of [tex]1 - \frac{\alpha}{2}[/tex].

The margin of error is:

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

85% confidence level

So [tex]\alpha = 0.15[/tex], z is the value of Z that has a pvalue of [tex]1 - \frac{0.15}{2} = 0.925[/tex], so [tex]Z = 1.44[/tex].

How large a sample would be required in order to estimate the fraction of tenth graders reading at or below the eighth grade level at the 85% confidence level with an error of at most 0.03

We need a sample size of at least n.

n is found with [tex]M = 0.03, \pi = 0.21[/tex]

Then

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

[tex]0.03 = 1.44\sqrt{\frac{0.21*0.79}{n}}[/tex]

[tex]0.03\sqrt{n} = 1.44\sqrt{0.21*0.79}[/tex]

[tex]\sqrt{n} = \frac{1.44\sqrt{0.21*0.79}}{0.03}[/tex]

[tex](\sqrt{n})^{2} = (\frac{1.44\sqrt{0.21*0.79}}{0.03})^{2}[/tex]

[tex]n = 382.23[/tex]

Rounding up

We need a sample size of at least 383.

To estimate the proportion of tenth graders reading at or below the eighth grade level with an 85% confidence level and a 0.03 margin of error, a sample size of 550 students is needed.

To estimate the fraction of tenth grade students with reading skills at or below the eighth grade level with an 85% confidence interval and a margin of error of at most 0.03, we use the following formula for sample size:

⇒ n = (Z² × p × (1 - p)) ÷ E²

Where:

Z is the z-value corresponding to the desired confidence level.p is the estimated population proportion (0.21).E is the desired margin of error (0.03).

For an 85% confidence level, the z-value is approximately 1.44. Plugging in the values:

Calculate the numerator:

⇒ Z² × p × (1 - p) = 1.44² × 0.21 × (1 - 0.21)

≈ 0.494668.

Calculate the denominator:

⇒ E² = 0.03²

= 0.0009.

Divide the numerator by the denominator:

⇒ 0.494668 ÷ 0.0009 ≈ 549.63.

Round up to the next integer: 550.

Therefore, the required sample size is 550 students.

Complete question:

The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the eighth grade level. In an earlier study, the population proportion was estimated to be 0.21. How large a sample would be required in order to estimate the fraction of tenth graders reading at or below the eighth grade level at the 85% confidence level with an error of at most 0.03? Round your answer up to the next integer.

The operator of a beachfront hotel in a tropical island wishes to select a new paint for the hotel’s exterior walls. Three different paints are applied to sample pieces of plywood, then exposed to a heat lamp and sprayed continuously with salt water until the paint begins to peel. Five plywood samples are used for testing each paint. The hours needed in order for the paint to begin to peel are listed below: • Paint A: 25, 27, 28, 28, and 30 hours. • Paint B: 23, 28, 30, 31, and 32 hours. • Paint C: 30, 31, 33, 33, and 37 hours. The hotel operator believes that there is no fundamental difference in longevity/endurance between the three types of paint. Do you agree or disagree? Perform ANOVA to justify your answer.

Answers

Find the given attachment for complete answer and solution

A manager at a shipping company will purchase boxes in the shape of right rectangular prisms. He wants the volume of each box to be exactly 98 cubic feet. Which figure shows a box with the dimensions, in feet, that the manager will purchase?

Answers

The manager needs to select dimensions for a right rectangular prism that when multiplied together equal 98 to achieve a volume of 98 cubic feet. Possible dimensions could be 7 feet by 7 feet by 2 feet, or 14 feet by 7 feet by 1 foot.

The question pertains to calculating the volume of right rectangular prisms (boxes) and understanding the relationship between their dimensions and volume. To find a box with a volume of 98 cubic feet, one can use the formula for the volume of a right rectangular prism, which is Volume = length * width  * height. The manager needs to identify the dimensions that, when multiplied together, equal 98. For instance, if a box has dimensions of 7 feet, 7 feet, and 2 feet, the volume would be 7  * 7 * 2 = 98 cubic feet, as required. Other possible dimensions could be 14 feet by 7 feet by 1 foot, as 14 * 7 * 1 also gives 98 cubic feet.

Katrina bought a package of 500 stickers. These sheet in the package has 20 stickers. 25% of the stickers on each sheet our hearts. The remaining stickers are stars. Select all the statements that are true. A Katrina has 100 heart stickers B Katrina has 375 star stickers C the package contains 20 sheets of stickers D 75% of the stickers on each sheet our stars see the number of heart stickers is the same number I start stickers

Answers

Answer:B

Step-by-step explanation:

Given

There are total of 500 stickers

Each sheet has 20 stickers out of which 25 % is Hearts and remaining are stars

So in each sheet 5 are hearts and 15 are stars

therefore in [tex]\frac{500}{20}=25[/tex] sheet

There are [tex]25\times 5=125[/tex] heart stickers

and [tex]25\times 15=375[/tex] star stickers

So statement B is true


A country's balance of payments is divided up into three categories, the
current account, capital account and financial account. The current account
mainly measures
A) the flow of credit.
B) the flow of goods and services.
c) purchases and sales of nonfinancial assets.
D) purchases of sales of stocks and bonds and other financial assets.

Answers

Answer:

B) the flow of goods and services

Step-by-step explanation:

Balance of payments (BOP) is a statement of all transactions made between one country and the rest of the world at a particular period of time. It is also called balance of international payment. BoP is divided into current and capital account.

1. The current account: This is account of country's net trade in goods and services, net earnings on cross-border investments, and its net transfer payments. The current account measures the flow of goods and services.

2. The capital account: This is a country's imports and exports of capital and foreign aid. It can also be called financial account.

The sum of all transactions recorded in the balance of payments should be zero.

Balance of payment deficit is when a country's import is higher than its export.

Balance of payment surplus is when a country's export is greater than its import.

Use the Venn diagram to calculate probabilities.
Which probabilities are correct? Select two options.
P(AIC) =
PCB) = 0
PLA) =
PC)
PBIA) = 3

Answers

Corrected Question

These are the given probabilities. The Venn diagram is also attached. are (A) P(A|C) = 2/3

(B) P(C|B) = 8/27

(C) P(A) = 31/59

(D) P(C) = 3/7

(E) P(B|A) = 13/27

Answer:

A and C

Step-by-step explanation:

[tex]P(A|C)=\dfrac{P(A\cap C)}{P(C)}= \dfrac{14/59}{21/59}=\dfrac{14}{21}=\dfrac{2}{3}[/tex]

[tex]P(C|B) =\dfrac{P(C\cap B)}{P(B)}= \dfrac{11/59}{27/59}=\dfrac{11}{27}\neq \dfrac{8}{27}\\\\P(A) = \dfrac{31}{59}\\\\P(C) =\dfrac{21}{59}\neq \dfrac{3}{7}\\\\P(B|A)=\dfrac{P(B\cap A)}{P(A)}= \dfrac{13/59}{31/59}=\dfrac{13}{31}\neq\dfrac{13}{27}[/tex]

From the above, only A and C are correct.

Answer: A and C

Step-by-step explanation:

Edg 2021

A car travels at an average speed of 52 mph. Jow long does it take to travel 169 miles?

Answers

Final answer:

To calculate the time it takes for the car to travel 169 miles at an average speed of 52 mph, divide the distance by the speed. The car would take approximately 3.25 hours.

Explanation:

To calculate the time it takes for the car to travel 169 miles, we can divide the distance by the average speed. The formula for speed is:

Speed = Distance / Time

Rearranging the formula to solve for time, we get:

Time = Distance / Speed

Plugging in the values, we have:

Time = 169 miles / 52 mph

Calculating this, the car would take approximately 3.25 hours to travel 169 miles.

After getting trounced by your little brother in a​ children's game, you suspect the die he gave you to roll may be unfair. To​ check, you roll it 48 ​times, recording the number of times each face appears. Do these results cast doubt on the​ die is fairness

Answers

Answer:

The results are

Face     Count         Face          Count

1               6                  4                9

2              12                 5                5

3              8                 6               20

These results are not fair, because they clearly shows that the dice was tricked. We deduct this by observing that he obtained the face 6, 20 times out of 48, which represents 42% of chances to get that result.

Now, a fair dice must have equal probabilities per side, or an approximation to that at least. In this case, we don't have such equality.

So, next time your little brother roll the dice, we probably will get 6.

Final answer:

To check the fairness of a die, use statistical testing. Expect each face to appear equally in a fair die. Discrepancies suggest possible bias, but randomness can make results vary. Conduct a hypothesis test, like Chi-square, for a more statistically sound conclusion.

Explanation:

To verify the fairness of the die, we need to conduct a hypothesis test. With a fair six-sided die, each face (numbered 1 to 6) should have an equal probability of appearing on any given roll. That means, if you roll the die 48 times, each face should theoretically appear about 8 times (48 rolls divided by 6 faces).

If the observed frequency of each face being rolled significantly varied from 8, it would suggest that the die might be biased. However, keep in mind that random chance can also result in each face not appearing exactly 8 times. Therefore, a hypothesis test would have more statistical power if more repetitions were performed.

Conduct the hypothesis testing by comparing your observed frequencies to the expected frequencies using a Chi-square test. This would provide a more quantitative and concrete conclusion about whether the die is biased or fair.

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Is 9/10 greater than 3/20

Answers

Answer:

Yes.

Step-by-step explanation:

9/10 is equal to 18/20, which is evidently greater than 3/20.

HURRY PLEASE
morgan poured 3/4 gallon of punch into each of 6 bottles. how many gallons of punch did she pour in all

Answers

Answer:

gallons of punch in all  = 4.5 gallons

Step-by-step explanation:

Morgan poured 3/4 gallons of punch into each of 6 bottles . This means Morgan poured 3/4 gallons of punch in each of the available 6 bottle .

He pours 3/4 gallons of punch in 1 bottle . For 6 bottles the gallons of punch poured is calculated below

1 bottle = 3/4 gallons of punch

6 bottles = ? gallons of punch

cross multiply

gallons of punch in all = 3/4 × 6

gallons of punch in all  = 18/4

gallons of punch in all  = 9/2 gallons

gallons of punch in all  = 4.5 gallons

Which best describes the complement of spinning any number less than 3?
spinning a 4
spinning a 3 or 4
spinning a 1 or 2
spinning a 1, 2 or 3

Answers

Answer:

spinning a 1 or 2

Step-by-step explanation:

less than 3 is 1 or 2

Answer:

B

Step-by-step explanation:

taking the test too

The mayor of a large city claims that the average net worth of families living in this city is at most $300,000. A random sample of 25 families selected from this city produced a mean net worth $288,000. Assume that the net worth of all families in this city have a normal distribution with the population standard deviation of $80,000. What is the parameter of interest?

Answers

Answer:

Check the explanation

Step-by-step explanation:

Below are the null and alternative Hypothesis,

Null Hypothesis, H0: μ = 300000

Alternative Hypothesis, Ha: μ < 300000

Test statistic,

z = (xbar - mu)/(sigma/sqrt(n))

z = (288000 - 300000)/(80000/sqrt(25))

z = -0.75

P-value Approach

P-value = 0.2266

As P-value >= 0.05, fail to reject null hypothesis.

Final answer:

The parameter of interest is the average net worth of families living in the city. Hypothesis testing can be used to evaluate the mayor's claim using a random sample of households. The test statistic can be calculated using the sample mean, sample standard deviation, and sample size.

Explanation:

The parameter of interest in this question is the average net worth of families living in the city. The mayor claims that the average net worth is at most $300,000. To determine if this claim is true, a random sample of 25 families is selected. The mean net worth of this sample is $288,000. This mean is an estimate of the population mean net worth.

Based on the information given, the population standard deviation of net worth for all families in the city is $80,000. This information allows us to perform hypothesis testing to evaluate the claim made by the mayor.

Null Hypothesis (H0): The average net worth of families living in the city is $300,000.Alternative Hypothesis (Ha): The average net worth of families living in the city is less than $300,000.Using the sample mean of $288,000, the sample standard deviation ($80,000), and the sample size (25), we can calculate the test statistic.The test statistic is calculated as follows:

Test Statistic = (Sample Mean - Population Mean) / (Sample Standard Deviation / sqrt(Sample Size))

Plugging in the values:

Test Statistic = (288,000 - 300,000) / (80,000 / √25)

After calculating the test statistic, we can compare it to the critical value of the test (based on the desired significance level) to determine if we reject or fail to reject the null hypothesis. If the test statistic is less than the critical value, we reject the null hypothesis and conclude that there is evidence to support the claim that the average net worth of families living in the city is less than $300,000.

By providing a random sample from the population, we can use hypothesis testing to evaluate the mayor's claim and determine if there is evidence to support it.

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Determine Whether the triangle with the given side lengths is a right triangle

6,8,10

Right Triangle
Not A Right Triangle

Answers

Answer:

Yes, right triangle

Step-by-step explanation:

Since it is a right triangle, we can use Pythagorean Theorem.

a^2+b^2=c^2

a and b are the legs, or shorter sides, and c is the hypotenuse, or the longest side.

We have 3 side lengths: 6, 8 and 10

6 and 8 are the shorter legs, so they are a and b.

10 is the longest leg, so it is c

Substitute the values into the equation, and see if it is true.

6^2+8^2=10^2

Evaluate the exponents

36+64=100

100=100

Since this is a true statement, these sides can make a right triangle.

yes it would be a right triangle!

In a random sample of 125 highway bridges around the country, 75 were in need of repair.
What is the sample proportion (point estimate) of highway bridges that need repaired? (Only type ONE decimal place)

Answers

Answer:

The sample proportion of highway bridges that need repaired is 0.6.

Step-by-step explanation:

The sample proportion of highway bridges that need repaired is the number of bridges in need of repair divided by the number of bridges around the country.

In this question:

75 bridges in need of repair, out of 125. So

75/125 = 0.6

The sample proportion of highway bridges that need repaired is 0.6.

14/10 divided by blank equals seven

Answers

Answer:

14/10=1.4

7/1.4=5

1.4x5=7

Step-by-step explanation:

Final answer:

In the given equation 14/10 divided by a certain number equals seven, the missing number is 0.2

Explanation:

The subject of this question is Mathematics and it appears to be suitable for a Middle School grade level. You're asking for a number that, when 14/10 or 1.4 is divided by it, the result is seven.

To solve it, one can set it up as an equation in the form of 1.4 / x = 7. To find 'x', multiply both sides by 'x' to get rid of 'x' on the denominator of the left side, so the equation becomes 1.4 = 7x. The next step is to isolate 'x' by dividing both sides of the equation by 7. Solving this equation gives x = 1.4/7 = 0.2.

So, 14/10 divided by 0.2 equals seven.

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A trampoline has a diameter of 10ft. What is it’s area ?

Answers

Answer: 78.5 feet squared for short answer

Step-by-step explanation:

If the diameter is 10 feet, then the radius is half of that, or 5 feet. feet squared is the EXACT answer, and we surely didn't need a calulator for this one. However, a real world answer is probably more appropriate if you were trying to measure the area. So the area of our trampoline is about 78.5 feet squared.

Answer:

78.54 square feet

Step-by-step explanation:

The formula to find the area of a circle is πr², and since we know the diameter is 10 ft we know the radius is 5 feet, so π5²=78.54

HELP ASAP timed question. A table is 4 ft high. A model of the table is 6 in high. What is the ratio of the height of the actual table to the helght of the model table? 3/2 8/1 2.3 1/8

Answers

Answer:

The  ratio of the height of the actual table to the height of the model table is  .

Step-by-step explanation:

As given

A table is 4 ft high. A model of the table is 6 in. high.

As

1 foot = 12 inch

Now convert 4 ft into inches .

4 ft = 4 × 12

    = 48 inches

Height of the actual table = 48 inches

Now the ratio of the height of the actual table to the height of the model

table .

Therefore the  ratio of the height of the actual table to the height of the model table is  .

Which sentence is written correctly? Kino said that if play practice does not start on time, the director “will be mad.” Kino said that if play practice does not start on time, the director “Will be mad”. Kino said that if play practice does not start on time, the director “will be mad”. Kino said that if play practice does not start on time, the director “Will be mad.”

Answers

Final answer:

The correct sentence is: Kino said that if play practice does not start on time, the director "will be mad."

Explanation:

The correct sentence is: Kino said that if play practice does not start on time, the director "will be mad."

In this sentence, the verb "will" is correctly written in lowercase, as it is not a proper noun or the start of a sentence. Additionally, the punctuation marks, such as the quotation marks and the comma, are correctly placed.

It is important to use proper capitalization and punctuation to ensure clear and effective communication in writing.

Learn more about Sentence structure here:

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The snack bar at the soccer field is charging $12 for 9 hamburgers. At that rate, how many hamburgers could you get for $20?

Answers

Answer:

6

Step-by-step explanation:

12 = 9 so u do 12 divided by 9

$20 to get 15 hamburgers. By dividing the price to produce one unit of your product by the number of items you have created, you can use the total variable cost.

locate total variables cost?

By dividing the price to produce one unit of your product by the number of items you have created, you can determine the total variable cost.

Multiply the cost of producing one unit of your product by the total number of items you have produced to determine variable costs. Total Variable Costs = Cost Per Unit x Total Number of Units is the calculation for this cost.

For instance, if producing one unit of your product costs $12 and you produced 9 pieces, your total variable cost would be $12 x 9, or $108.

$12/9  = 1.34 then $20 to get 15 hamburgers.  

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The Cartesian coordinates of a point are given.(a) (6, −6)(i) Find polar coordinates (r, θ) of the point, where r > 0 and 0 ≤ θ < 2π.(r, θ) = (ii) Find polar coordinates (r, θ) of the point, where r < 0 and 0 ≤ θ < 2π.(r, θ) = (b) (−1, 3)(i) Find polar coordinates (r, θ) of the point, where r > 0 and 0 ≤ θ < 2π.(r, θ) = (ii) Find polar coordinates (r, θ) of the point, where r < 0 and 0 ≤ θ < 2π.(r, θ) =

Answers

Final answer:

To find the polar coordinates (r, θ) of a point given in Cartesian coordinates (x, y), we can use the equations (r, θ) = (√(x² + y²), atan2(y, x)).

Explanation:

To find the polar coordinates (r, θ) of a point given in Cartesian coordinates (x, y), we can use the following equations:

(r, θ) = (√(x² + y²), atan2(y, x))

(a)(i) For the Cartesian coordinates (6, -6),

(r, θ) = (√(6² + (-6)²), atan2(-6, 6))

(r, θ) = (√(36 + 36), atan2(-6, 6))

(r, θ) = (6√2, -45°)

(a)(ii) For the Cartesian coordinates (6, -6),

(r, θ) = (-√(6² + (-6)²), atan2(-6, 6) + π)

(r, θ) = (-6√2, -45° + π)

(b)(i) For the Cartesian coordinates (-1, 3),

(r, θ) = (√((-1)² + 3²), atan2(3, -1))

(r, θ) = (√(1 + 9), atan2(3, -1))

(r, θ) = (√10, 116.57°)

(b)(ii) For the Cartesian coordinates (-1, 3),

(r, θ) = (-√((-1)² + 3²), atan2(3, -1) + π)

(r, θ) = (-√10, 116.57° + π)

HELP!! pls pls pls

The average price of a movie ticket in 1990 was $4.22. Since then, the price has increased by approximately 3.1% each year. Write an exponential function to model this situation, then find the price of a ticket in 2016. Is this growth or decay?

Answers

Answer:

$9.33

Exponential growth.

Step-by-step explanation:

The formula for an exponential function is:

abˣ = y OR

a(1 + r)ˣ = y

a is the initial value (4.22)

r is the rate of increase (3.1% or 0.031 in dec. form) where 1 + r is b

x is the time (26 years)

y is the ending value.

If we plug those values in, the equation will turn out to be 4.22(1 + 0.031)²⁶ = y

Plug it into a calculator and you will get 9.333354216

This is exponential growth because x, the initial value, increases to get to y, the ending value.

Please help 15 points

Answers

Answer:

D) Alternate exterior angles

Step-by-step explanation:

Alternate Exterior Angles are a pair of angles on the outer side of each of those two lines but on opposite sides of the transversal.

It was claimed that when tossing a fair coin 4 times it is quite likely to not obtain 2 heads and 2 tails. However, when tossing a fair coin 4,000 times one should expect to obtain number of tails in the range between 1940 and 2060. Let us compare the situation for 2 versus 2,000 coins. Let X be the number of heads when tossing a fair coin 2 times and let Y be the number of heads when tossing a fair coin 2,000 times.
1. P(940 ≤ Y ≤ 1,060) is equal to:______.2. E(X) is equal to:______.3. The standard deviation of X is equal to:______.4. E(Y) is equal to:_______.

Answers

Final answer:

The expected value of flipping a coin twice (X) is 1 head, with a standard deviation of 0.7071. The expected value of flipping a coin 2,000 times (Y) is 1,000 heads, but we cannot calculate P(940 ≤ Y ≤ 1,060) from the given information.

Explanation:

The question involves the concept of probability, expected value (E), and standard deviation (SD) in the context of flipping coins. We'll address each part of the query using basic probability and statistics principles.

P(940 ≤ Y ≤ 1,060) would require the use of the Central Limit Theorem for large sample sizes; however, with the information given, we cannot calculate this probability without additional statistical tables or tools, so we must refuse to answer this part.

The expected value of X, E(X), when flipping a coin twice would be the sum of products of each outcome's value and its probability. E(X) = (0 * 0.25) + (1 * 0.5) + (2 * 0.25) = 1.

The standard deviation of X requires calculating the variance first, then the square root of the variance. σ(X) = √[((0-1)^2 * 0.25) + ((1-1)^2 * 0.5) + ((2-1)^2 * 0.25)] = √(0.5) = 0.7071.

The expected value of Y, E(Y), when flipping a coin 2,000 times is simply 0.5 * 2,000 = 1,000 because the probability of a head for each flip is 0.5.

The probability P(940 ≤ Y ≤ 1,060) is approximately 99.63%, E(X) equals to 1, and the standard deviation of X is approximately 0.707. E(Y) is 1000.

To understand the probability and expectations for tossing fair coins, we will address your questions step by step.

P(940 ≤ Y ≤ 1,060) involves using the normal approximation to the binomial distribution.

For large numbers of coin tosses, the binomial distribution can be approximated by a normal distribution.

Since we are tossing the coin 2,000 times, our mean (μ) and variance (σ²) need to be calculated.

μ = n * p = 2000 * 0.5 = 1000 σ² = n * p * (1 - p) = 2000 * 0.5 * 0.5 = 500

Hence σ ≈ 22.36.

Now, we standardize the range [940, 1060].

Z-score = (940 - 1000) / 22.36 ≈ -2.68 and (1060 - 1000) / 22.36 ≈ 2.68.

From the Z-table, P(-2.68 ≤ Z ≤ 2.68) is approximately 0.9963, or 99.63%.

E(X) represents the expected number of heads when tossing 2 coins. Since each coin is fair and has a probability of 0.5 for heads,

E(X) = n * p = 2 * 0.5 = 1.

Standard Deviation = √(n * p * (1 - p)). Here, n = 2, p = 0.5.

= √(2 * 0.5 * 0.5) = √0.5 = 0.707.

E(Y) is the expected number of heads when tossing 2,000 coins. Similarly,

E(Y) = n * p = 2000 * 0.5 = 1000.

Therefore, probability P(940 ≤ Y ≤ 1,060) is 99.63%, E(X) is 1, and the standard deviation is 0.707. E(Y) is 1000.

The radial spokes of a bicycle tire are 13 inches long. What is the diameter of the tire?

Answers

Answer:

the answer is 5

Step-by-step explanation:

the

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