Perpendicular
Explanation;The crest of a water wave moves perpendicular to the direction the wave energy moves.A transverse wave is a wave in which particles move up and down or side-to-side at right angles or perpendicular to the direction the wave travels.Examples of these waves are: vibrations in strings, ripples on water surface and electromagnetic waves. In a transverse wave, the particles of the medium oscillate in a direction perpendicular to the direction of propagation.If the voltage impressed across a circuit is held constant while the resistance doubles, what change occurs in the current?
Answer:
The current halves
Explanation:
The relationship between voltage, current and resistance in a circuit is given by Ohm's law:
[tex]V=RI[/tex]
where
V is the voltage
R is the resistance
I is the current
We can rewrite the formula as
[tex]I=\frac{V}{R}[/tex]
we see that I is directly proportional to V and inversely proportional to R. In this problem, V is held constant while R is doubled:
[tex]R'=2R[/tex]
so, the new current in the circuit will be
[tex]I'=\frac{V}{R'}=\frac{V}{2R}=\frac{1}{2}I[/tex]
So, the current halves.
If a substance cannot be physically separated into component parts, it is likely to be
A pure substance because it cannot be separated into parts
In the 1950s and 1960s technology such as television and satellites revolutionized life in many big and small ways. Which was one of the results?
The advancements in television and communication technologies during the 1950s and 1960s revolutionized entertainment, news consumption, and long-distance communication by the creation of a shared experience and offering better and cheaper services.
Explanation:
One of the major results of technological advancements like television and satellites revolutionizing life in the 1950s and 1960s was a transformation in modes of communication and entertainment. With the accessibility and popularity of television soaring during this period, there was a shift in the way people consumed news, entertainment and information. In the early 1950's, only around 9 percent of U.S households had a TV which rocketed to approximately 65 percent in just five years. This widespread distribution of television sets played an instrumental role in uniting people through shared experiences whether it was news broadcasts or popular TV shows. A sense of a national, and even global, community was formed through these shared experiences in real-time.
Another crucial impact was the innovations in communication technologies such as microwave transmission and satellites, allowing phone calls to be made in a wireless mode. More affordable and superior quality telephonic communication, especially for long-distance calls, was facilitated. Therefore, the technology of this era not only influenced entertainment and news consumption but also significantly improved communication.
Learn more about Technological advancements in the 1950s and 1960s here:https://brainly.com/question/34702037
#SPJ3
A large man sits on a four-legged chair with his feet off thefloor. The combined mass of the man and chair is 95.0 kg. If thechair legs are circular and have a radius of 0.400 cm at the bottom, what pressure does each legexert on the floor?
Answer:
[tex]4.7\cdot 10^6 Pa[/tex]
Explanation:
The total force exerted by the man on the chair is equal to his weight:
[tex]F=W=mg[/tex]
where m=95.0 kg is the man's mass and g=9.8 m/s^2. Substituting,
[tex]F=(95.0 kg)(9.8 m/s^2)=931 N[/tex]
Since there are 4 legs, we can assume that the force is equally distributed over the 4 legs; so the force supported by each leg is
[tex]F=\frac{931 N}{4}=232.8 N[/tex]
The radius of each leg is [tex]r=0.400 cm=0.004 m^2[/tex], so the area of each leg is
[tex]A=\pi r^2 = \pi (0.004 m)^2=5\cdot 10^{-5} m^2[/tex]
And the pressure exerted on each leg is equal to the ratio between the force supported by each leg and the area:
[tex]p=\frac{F}{A}=\frac{232.8 N}{5\cdot 10^{-5} m^2}=4.7\cdot 10^6 Pa[/tex]
The pressure on each leg is 4655kNm-2.
What is pressure?The term pressure is defined as the ratio of force per unit area. Firts we have to find the force acting on the chair and the area covered by the force.
The force acting on the ground is the weight of the man and the chair.
F = W = mg = 95.0 kg * 9.8 ms-2 = 931 N.
Since this force is evenly distributed, the force on each leg = 931/4 = 232.75 N
The area of each leg = πr^2 = 3.142 * (0.4 * 10^-2)^2 = 5 * 10^-5 m^2
Pressure = force/area = 232.75 N/ 5 * 10^-5 m^2 = 4655kNm-2
Learn more about pressure: https://brainly.com/question/14143095
A ___ is formed from two pieces of different metals stuck together lengthwise.
A. Bimetallic Coil
B. Coolant
C. Hear Pump
D. Furnace
The answer is B
Bimetallic strip is used to create a bimetallic coil for a thermometer which reacts to the heat from a lighter, by uncoiling and then coiling back up when the lighter is removed.
A Bimetallic Coil is formed from two pieces of different metals stuck together lengthwise.
Option A
Explanation:
It is formed with two metal pieces that are stuck together in proper length. It is also called bimetallic strip which is mainly used for converting temperature into mechanical displacement. This coil or strip is consist of two different metal that are "steel and copper" or "steel and brass". With "riveting", welding and brazing the strip in the metals are joined length wise together. The displacement in the sideways of strips is more than smaller length ways expansion. The effect produced is used is basically used in mechanical and electrical devices.
A 10-cm-long spring is attached to theceiling. When a 2.0 kg mass is hung from it,the spring stretches to a length of 15 cm.a.What is the spring constant k?b.How long is the spring when a 3.0kg mass is suspended from it?
(a) 392 N/m
Hook's law states that:
[tex]F=k\Delta x[/tex] (1)
where
F is the force exerted on the spring
k is the spring constant
[tex]\Delta x[/tex] is the stretching/compression of the spring
In this problem:
- The force exerted on the spring is equal to the weight of the block attached to the spring:
[tex]F=mg=(2.0 kg)(9.8 m/s^2)=19.6 N[/tex]
- The stretching of the spring is
[tex]\Delta x=15 cm-10 cm=5 cm=0.05 m[/tex]
Solving eq.(1) for k, we find the spring constant:
[tex]k=\frac{F}{\Delta x}=\frac{19.6 N}{0.05 m}=392 N/m[/tex]
(b) 17.5 cm
If a block of m = 3.0 kg is attached to the spring, the new force applied is
[tex]F=mg=(3.0 kg)(9.8 m/s^2)=29.4 N[/tex]
And so, the stretch of the spring is
[tex]\Delta x=\frac{F}{k}=\frac{29.4 N}{392 N/m}=0.075 m=7.5 cm[/tex]
And since the initial lenght of the spring is
[tex]x_0 = 10 cm[/tex]
The final length will be
[tex]x_f = x_0 +\Delta x=10 cm+7.5 cm=17.5 cm[/tex]
(a) The spring constant of the spring is 392 N/m
(b) Length of the spring is 17.5 cm
[tex]\texttt{ }[/tex]
Further explanationHooke's Law states that the length of a spring is directly proportional to the force acting on the spring.
[tex]\boxed {F = k \times \Delta x}[/tex]
F = Force ( N )
k = Spring Constant ( N/m )
Δx = Extension ( m )
[tex]\texttt{ }[/tex]
The formula for finding Young's Modulus is as follows:
[tex]\boxed {E = \frac{F / A}{\Delta x / x_o}}[/tex]
E = Young's Modulus ( N/m² )
F = Force ( N )
A = Cross-Sectional Area ( m² )
Δx = Extension ( m )
x = Initial Length ( m )
Let us now tackle the problem !
[tex]\texttt{ }[/tex]
Given:
initial length of spring = Lo = 10 cm
mass of object = m = 2.0 kg
extension of the spring = x = 15 - 10 = 5 cm = 0.05 m
mass of second object = m' = 3.0 kg
Asked:
a. spring constant of the spring = k = ?
b. length of spring = L = ?
Solution:
Part a.[tex]F = kx[/tex]
[tex]mg = kx[/tex]
[tex]k = mg \div x[/tex]
[tex]k = 2.0 ( 9.8 ) \div 0.05[/tex]
[tex]\boxed {k = 392 \texttt{ N/m}}[/tex]
[tex]\texttt{ }[/tex]
Part b.[tex]F' = kx'[/tex]
[tex]m' g = k x'[/tex]
[tex]x' = ( m' g ) \div k[/tex]
[tex]x' = ( 3.0 (9.8) ) \div 392[/tex]
[tex]x' = 0.075 \texttt{ m} = 7.5 \texttt{ cm}[/tex]
[tex]\texttt{ }[/tex]
[tex]L = Lo + x'[/tex]
[tex]L = 10 + 7.5[/tex]
[tex]\boxed {L = 17.5 \texttt{ cm}}[/tex]
[tex]\texttt{ }[/tex]
Learn moreYoung's modulus : https://brainly.com/question/6864866Young's modulus for aluminum : https://brainly.com/question/7282579Young's modulus of wire : https://brainly.com/question/9755626[tex]\texttt{ }[/tex]
Answer detailsGrade: College
Subject: Physics
Chapter: Elasticity
What type of device is a car engine?
A.A heat pump that uses heat to do work
B.A heat engine that uses work to move heat
C.A heat pump that uses work to move heat
D.A heat engine that uses heat to do work
A heat engine that uses work to move heat
hope this helps :)
Answer:
D. A heat engine that uses heat to do work
Explanation:
Combustion = Heat
Combustion is used to create motion (work)
If you are testing how the amount of sleep students get affects test performance, what should you change in the experiment? A. The grading of the test B. Which teacher each student has C. How much sleep each student gets D. How many questions are on the test
C. How much sleep each student gets
It says directly that you are trying to test how the amount of sleep a student gets affects their performance. If that is the case, it would make sense to change the hours or amount of sleep each student gets before taking the test.
You are given three pieces of wire that have different shapes (dimensions). You connect each piece of wire separately to a battery. The first piece has a length L and cross-sectional area A. The second is twice as long as the first, but has the same thickness. The third is the same length as the first, but has twice the cross-sectional area. Rank the wires in order of which carries the most current (has the lowest resistance) when connected to batteries with the same voltage difference. Rank the wires from most current (least resistance) to least current (most resistance).
Answer:
[tex]R_3 < R_1 < R_2[/tex]
Explanation:
The resistance of a wire is given by:
[tex]R=\frac{\rho L}{A}[/tex]
where
[tex]\rho[/tex] is the resistivity of the material
L is the length of the wire
A is the cross-sectional area of the wire
1) The first wire has length L and cross-sectional area A. So, its resistance is:
[tex]R_1=\frac{\rho L}{A}[/tex]
2) The second wire has length twice the first one: 2L, and same thickness, A. So its resistance is
[tex]R_2=\frac{2\rho L}{A}[/tex]
3) The third wire has length L (as the first one), but twice cross sectional area, 2A. So, its resistance is
[tex]R_3=\frac{\rho L}{2A}[/tex]
By comparing the three expressions, we find
[tex]R_3 < R_1 < R_2[/tex]
So, this is the ranking of the wire from most current (least resistance) to least current (most resistance).
Which of the following statements is NOT a correct assumption of the classicalmodel of an ideal gas?A. The molecules are in random motion.B. The volume of the molecules is negligible compared with the volume occupied bythe gas.C. The molecules obey Newton's laws of motion.D. The collisions between molecules are inelastic.E. The only appreciable forces on the molecules are those that occur duringcollisions.A sample of an ideal gas is in a tank of constant volume. The sample absorbsheat energy so that its temperature changes from 300 K to 600 K. If v1 is theaverage speed of the gas molecules before the absorption of heat and v2 is theiraverage speed after the absorption of heat, what is the ratio v2/ v1?A. 1/2 B. 1 C. 2 D. 2 E. 4
1) D. The collisions between molecules are inelastic
Explanation:
The kinetic theory of the gases describe the property of the gases by looking at microscopic level. At these level, some assumptions are made on the motion/collisions of the molecules of the gas:
- Molecules move by random motion
- The volume of the molecules is negligible compared with the volume of the gas
- The molecules obey Newton's laws of motion
- The intermolecular forces between the molecules are negligible except during the collisions
- Collisions between molecules are elastic
Therefore, the following statement
D. The collisions between molecules are inelastic
is wrong.
2) [tex]\sqrt{2}[/tex]
The kinetic energy Ek of a gas is directly proportional to its absolute temperature T:
[tex]E_k = \frac{3}{2}kT[/tex]
where k is the Boltzmann's constant. However, the kinetic energy depends on the square of the average velocity of the particles, [tex]v^2[/tex]:
[tex]E_k = \frac{1}{2}mv^2=\frac{3}{2}kT[/tex]
where m is the mass of the particles. This means that the velocity is proportional to the square root of the temperature:
[tex]v \propto \sqrt{T}[/tex]
So, if the temperature of the gas is doubled, the average speed increases by a factor [tex]\sqrt{2}[/tex], and the ratio v2/v1 is
[tex]\frac{v_2}{v_1}=\sqrt{2}[/tex]
Vision is blurred if the head is vibrated at 29 Hz because the vibrations are resonant with the natural frequency of the eyeball held by the musculature in its socket.If the mass of the eyeball is 7.7 g, what is the effective spring constant of the musculature attached to the eyeball?
Answer:
255.4 N/m
Explanation:
We can consider the system eyeball-attached to the musculature as a mass-spring system in simple harmonic motion, whose frequency of oscillation is given by
[tex]f=\frac{1}{2\pi}\sqrt{\frac{k}{m}}[/tex]
where in this case, we know:
f = 29 Hz is the frequency of oscillation
k is the spring constant, which is unknown
m = 7.7 g = 0.0077 kg is the mass of the eyeball
Solving the equation for k, we find the spring constant of the musculature attached to the eyeball:
[tex]k=(2\pi f)^2 m=(2 \pi (29 Hz))^2 (0.0077 kg)=255.4 N/m[/tex]
To find the effective spring constant of the musculature attached to the eyeball, use the formula k = (4π²m)/(frequency²)
Explanation:To determine the effective spring constant of the musculature attached to the eyeball, we can use the formula for the resonant frequency of a mass-spring system:
frequency = 1 / (2π√(m/k))
where m is the mass of the eyeball and k is the spring constant. Rearranging the formula, we can solve for k:
k = (4π2m)/(frequency2)
Plugging in the values, we have m = 7.7 g and frequency = 29 Hz:
k = (4π2(7.7 g))/(29 Hz)2
Learn more about Resonant frequency of a mass-spring system here:https://brainly.com/question/31833343
#SPJ11
a wave travels at a speed of 5.2 m/s. if the distance between crests is 0.40 m, what is the frequency of the wave?
Answer:
13 Hz
Explanation:
The frequency of a wave is given by the equation:
[tex]f=\frac{v}{\lambda}[/tex]
where
f is the frequency
v is the speed of the wave
[tex]\lambda[/tex] is the wavelength
In this problem, we have:
v = 5.2 m/s is the speed of the wave
[tex]\lambda=0.40 m[/tex] is the wavelength (distance between two adjacent crests)
Substituting into the formula, we find the frequency of the wave:
[tex]f=\frac{5.2 m/s}{0.40 m}=13 Hz[/tex]
Answer:
D.13 Hz
Explanation:
A
p
e
x
On a cloudless day, the sunlight that reaches the surface of the earth has an intensity of about 1.40 × 10 3 1.40×103 W/m². What is the electromagnetic energy contained in 6.00 m³ of space just above the earth's surface?
To calculate the electromagnetic energy contained in a given space just above the Earth's surface, multiply the intensity of the sunlight by the volume of the space. In this case, the energy is 8.40 × 10^3 W.
Explanation:The electromagnetic energy contained in a given space can be calculated by multiplying the intensity of the sunlight by the volume of the space.
Given that the intensity of sunlight is 1.40 × 10^3 W/m² and the volume of the space is 6.00 m³, we can calculate the electromagnetic energy as follows:
Energy = Intensity × Volume
Energy = (1.40 × 10^3 W/m²) × (6.00 m³)
Energy = 8.40 × 10^3 W
Learn more about Electromagnetic energy here:https://brainly.com/question/22963020
#SPJ3
A floating object oscillates up and down 2 complete cycles in 1 second as a water wave of wavelength 5 meters passes by. The speed of the wave is
Answer:
10 m/s
Explanation:
The speed of a wave is given by
[tex]v=\lambda f[/tex]
where
[tex]\lambda[/tex] is the wavelength
f is the frequency
For the wave in this problem,
- The frequency is given by the number of oscillations per second, so
[tex]f=\frac{2 cycles}{1 s}=2 Hz[/tex]
- The wavelength is
[tex]\lambda=5 m[/tex]
So, the wave speed is
[tex]v=(5 m)(2 Hz)=10 m/s[/tex]
The speed of the water wave is calculated using the formula speed = frequency × wavelength. With a frequency of 2 Hz and a wavelength of 5 meters, the wave speed is 10 m/s.
Explanation:The student's question is about calculating the speed of a water wave based on the given wavelength and the frequency of an object oscillating on the water's surface. To find the wave speed, we can use the formula speed = frequency × wavelength. Given that the object completes 2 cycles per second (which is the frequency), and the wavelength is 5 meters, we simply multiply the two values.
Speed = Frequency × Wavelength = 2 Hz × 5 m = 10 m/s
Therefore, the speed of the water wave is 10 meters per second (m/s).
A typical american family uses 1000 kWh of electricity a month.
What is the average rms current in the 120 V power line to the house?
On average, what is the resistance of a household?
Given the data in the question;
Electricity used; [tex]E = 1000kWh = 36*10^8J[/tex]
Time; [tex]t = 1 month = 2.592 * 10^6s[/tex]
Voltage; [tex]V = 120V[/tex]
Calculate the average rms current to the house.
First we determine the power
Power is the amount of energy transferred per unit time:
[tex]Power = \frac{E}{t}[/tex]
So we substitute in our values
[tex]Power = \frac{36*10^8J}{2.592*10^6s}\\\\Power = 1.388 * 10^3 J/s \\\\Power = 1.388 * 10^3 W[/tex]
Next we Calculate the Current
From Ohms Law:
[tex]P = I * V[/tex]
We substitute in our values
[tex]1.388*10^3W = I \ *\ 120V \\\\I = \frac{1.388*10^3W}{120V} \\\\I = 11.57 W/V\\\\I = 12A[/tex]
Therefore, the average rms current in the power line to the house is 12A
The resistance of a household
From Ohm's Law:
[tex]R = \frac{V}{I}[/tex]
We substitute in our values
[tex]R = \frac{120V}{12A}\\\\R = 10ohms[/tex]
Therefore, The average resistance of a household is 10Ω.
Learn more; https://brainly.com/question/13037925
The intensity of sunlight under the clear sky is 1160 w/m2 . how much electromagnetic energy is contained per cubic meter near the earth's surface? the speed of light is 2.99792 × 108 m/s. answer in units of j/m3
Answer:
= 3.869 × 10^-6 J/m³
Explanation:
Intensity is given as W/m^2 which is equivalent to J/ (s*m^2)
Speed of light is 2.99792 × 10^8 m/s.
Therefore;
Electromagnetic energy per cubic meter = Intensity/speed of light
= 1160 J/ (s*m³)/ 2.99792 × 10^8 m/s.
= 3.869 × 10^-6 J/m³
a car with apowerful engine can go from 0 km/h to 100 km/h in 8 s
ok interesting what is you question
What galaxies would you most likely find at the center of a large cluster of galaxies?
A large elliptical galaxy
Answer:
A Super Massive black hole
Explanation:
Does the system's kinetic energy increase, decrease, or stay the same? or is there not enough information to tell?
A process occurs in which a system's potential energy increases while the environment does work on the system. The kinetic energy of a system decreases while its potential energy and thermal energy are unchanged.
What is Kinetic energy?Kinetic energy is the energy which is present in the body of an object which is under motion. Kinetic energy of an object transforms into potential energy and in the form of work when the object changes its state of motion to rest.
When a process occurs, the potential energy of the system increases while the environment does some work on the system. In this case, the kinetic energy of the object decreases while the potential energy and thermal energy of the system remains unchanged. This is because kinetic energy is used in doing work.
Learn more about Kinetic energy here:
https://brainly.com/question/26472013
#SPJ6
Your question is incomplete, most probably the complete question is:
A process occurs in which a system's potential energy increases while the environment does work on the system. Does the system's KINETIC energy increase, decrease, or stay the same?
The amount of energy needed to power a 0.10-kw bulb for one minute would be just sufficient to lift a 1.0-kg object through a vertical distance of
Answer:
612.2 m
Explanation:
The work needed to lift the object is equal to its increase in gravitational potential energy:
[tex]W=\Delta U=mg \Delta h[/tex] (1)
where
m = 1.0 kg is the mass
g = 9.8 m/s^2
[tex]\Delta h[/tex] is the vertical distance
The power provided is
[tex]P=0.10 kW = 100 W[/tex]
In one minute (t = 1 min = 60 s), the work provided is
[tex]W=Pt=(100 W)(60 s)=6000 J[/tex]
Substituting this into (1) and solving for [tex]\Delta h[/tex], we find
[tex]\Delta h=\frac{W}{mg}=\frac{6000 J}{(1.0 kg)(9.8 m/s^2)}=612.2 m[/tex]
The amount of energy needed to power a 0.10-kW bulb for one minute is equivalent to the work done in lifting a 1.0 kg object through a vertical distance. The distance is calculated using the formula Work = Force * Distance. The distance is found to be 0.61 meters.
Explanation:The amount of energy needed to power a 0.10-kW bulb for one minute is 6 Joules. This energy is equivalent to the work done in lifting a 1.0 kg object through a vertical distance. To calculate the distance, we can use the formula:
Work = Force * Distance
In this case, the force is equal to the weight of the object, which is 1.0 kg * 9.8 m/s² (acceleration due to gravity). So, the distance is equal to:
Distance = Work / (Force * Acceleration due to gravity)
Substituting the values, we get:
Distance = 6 J / (1.0 kg * 9.8 m/s²) = 0.61 meters
Learn more about Energy calculation here:https://brainly.com/question/31994371
#SPJ11
A proton and an electron in a hydrogen atom are separated on the average by about 5.3 × 10−11 m. What is the magnitude and direction of the electric field set up by the proton at the position of the electron? The Coulomb constant is 8.99 × 109 N · m2 /C 2 . 1. 5.12068 × 1011 N/C away from the proton 2. 8.19309 × 10−8 N/C toward the proton 3. 27.1396 N/C away from the proton 4. 27.1396 N/C toward the proton 5. 5.12068 × 1011 N/C toward the proton 6. 8.19309 × 10−8 N/C away from the proton
Answer:
1. 5.12068 × 1011 N/C away from the proton
Explanation:
The electric field produced by a single point charge is given by:
[tex]E=k\frac{q}{r^2}[/tex]
where
k is the Coulomb's constant
q is the magnitude of the charge
r is the distance from the charge
In this problem, we have:
[tex]q=1.6\cdot 10^{-19}C[/tex] is the charge of the proton
[tex]r=5.3\cdot 10^{-11} m[/tex] is the distance at which we want to calculate the field
[tex]k=8.99\cdot 10^9 Nm^2C^{-2}[/tex] is the Coulomb's constant
Substituting into the formula,
[tex]E=(8.99\cdot 10^9 Nm^2C^{-2})\frac{1.6\cdot 10^{-19}C}{(5.3\cdot 10^{-11}m)^2}=5.12068\cdot 10^{11} N/C[/tex]
And the direction of the electric field produced by a positive charge is away from the charge, so the correct answer is
1. 5.12068 × 1011 N/C away from the proton
The magnitude of the electric field set up by the proton at the position of the electron in a hydrogen atom is approximately 5.14 x 10¹¹ N/C. This is based on the formula for the electric field E = kQ/r². The direction of the electric field is away from the proton.
Explanation:The electric field created by a charge is given by the formula E = kQ/r², where Q is the charge, r is the distance, and k is the Coulomb constant. In this case the magnitude of the charge of a proton (Q) is +1.602 x 10⁻¹⁹ C, the average distance (r) between a proton and an electron in a hydrogen atom is 5.3 x 10⁻¹¹ m, and the Coulomb constant (k) is 8.99 x 10⁹ N.m²/C².
Using these values in the formula gives E = (8.99 x 10⁹ N.m²/C²)(1.602 x 10⁻¹⁹ C)/(5.3 x 10⁻¹¹ m)² = 5.14 x 10¹¹ N/C. Therefore, the magnitude of the electric field set up by the proton at the position of the electron is approximately 5.14 x 10¹¹ N/C.
As for the direction of the electric field, electric field lines point in the direction that a positive test charge would move if placed in the field. Since the proton has a positive charge, the field lines (and hence the direction of the electric field) point away from the proton. So, the correct answer is ~5.14 x 10¹¹ N/C away from the proton.
Learn more about Electric Field here:https://brainly.com/question/8971780
#SPJ3
A tow truck pulls a 500 kg car so that the car accelerates 2 m/s2. What is the net force on the car?
250 N
498 N
1000 N
502 N
I shall draw this out as these tend to be answered best visually
Which one of the following lists is a correct representation of electromagnetic waves from longer wavelength to shorter wavelength?Answerradio waves, UV, X-rays, microwaves, infrared, visible, gamma raysradio waves, microwaves, visible, X-rays, infrared, UV, gamma raysradio waves, infrared, microwaves, UV, visible, X-rays, gamma raysradio waves, microwaves, infrared, visible, UV, X-rays, gamma raysradio waves, infrared, X-rays, microwaves, UV, visible, gamma rays
Answer:
radio waves, microwaves, infrared, visible, UV, X-rays, gamma rays
Explanation:
Electromagnetic waves consist of oscillating electric and magnetic fields which vibrate in a direction perpendicular to the direction of motion of the wave (transverse wave). Electromagnetic waves travel in a vacuum with a speed of [tex]c=3.0\cdot 10^8 m/s[/tex] (speed of light), and they are classified into 7 different types according to their wavelength.
From longer to shorter wavelength, these types are:
Radio waves (wavelength > 30 cm)
Microwaves (30 cm - [tex]5 \mu m[/tex])
Infrared ([tex]5 \mu - 750 nm[/tex])
Visible light (750 nm - 380 nm)
UV radiation (380 nm - 8 nm)
X-rays (8 nm - 6 pm)
Gamam rays (< 6 pm)
. A 0.145 kg baseball pitched at 35.0 m/s is hit on a horizontal line drive straight back at the pitcher at 56.0 m/s. If the contact time between the bat and ball is 5.00 × 10−3 ????, calculate the force (assumed to be constant) between the ball and bat.
Answer:
2639 N
Explanation:
The impulse on the baseball is given by:
[tex]I=F \Delta t[/tex] (1)
where F is the force exerted on the ball and [tex]\Delta t[/tex] the contact time between the bat and the ball.
The impulse is also equal to the change in momentum of the ball:
[tex]I=\Delta p = m (v-u)[/tex] (2)
where m is the ball's mass, v is its final velocity, u is its initial velocity.
By using (1) and (2) simultaneously we can write an expression for F, the force exerted on the ball:
[tex]F=\frac{m(v-u)}{\Delta t}[/tex]
where:
m = 0.145 kg
u = 35.0 m/s
v = -56.0 m/s
[tex]\Delta t=5.00 \cdot 10^{-3}s[/tex]
Substituting,
[tex]F=\frac{(0.145 kg)((-56.0 m/s)-35.0 m/s)}{5.00\cdot 10^{-3} s}=-2639 N[/tex]
and the negative sign means that the force is simply in the opposite direction to the ball's initial direction.
A very long, straight wire carries a current of 19.0 A in the +k direction. An electron 1.9 cm from the center of the wire in the î direction is moving with a speed of 3.23 106 m/s. Find the force on the electron when it moves in the following directions. (a) directly away from the wire 0 Correct: Your answer is correct. N î + 0 Correct: Your answer is correct. N ĵ + N k (b) parallel to the wire in the direction of the current N î + 0 Correct: Your answer is correct. N ĵ + 0 Correct: Your answer is correct. N k (c) perpendicular to the wire and tangent to a circle around the wire in the + ĵ direction 0 Correct: Your answer is correct. N î + 0 Correct: Your answer is correct. N ĵ + N k
(a) [tex]1.03\cdot 10^{-16} N[/tex], -k direction
First of all, let's find the magnetic field produced by the wire at the location of the electron:
[tex]B=\frac{\mu_0 I}{2 \pi r}[/tex]
where
I = 19.0 A is the current in the wire
r = 1.9 cm = 0.019 m is the distance of the electron from the wire
Substituting,
[tex]B=\frac{(1.256\cdot 10^{-6})(19.0A)}{2 \pi (0.019 m)}=2\cdot 10^{-4} T[/tex]
and the direction is +j direction (tangent to a circle around the wire)
Now we can find the force on the electron by using:
[tex]F=qvBsin \theta[/tex]
where
[tex]q=1.6\cdot 10^{-19}C[/tex] is the electron's charge
[tex]v=3.23\cdot 10^6 m/s[/tex] is the electron speed
[tex]B=2\cdot 10^{-4} T[/tex] is the magnetic field
[tex]\theta[/tex] is the angle between the direction of v and B
In this case, the electron is travelling away from the wire, while the magnetic field lines (B) form circular paths around the wire: this means that v and B are perpendicular, so [tex]\theta=90^{\circ}, sin \theta=1[/tex]. So, the force on the electron is
[tex]F=(1.6\cdot 10^{-19}C)(3.23\cdot 10^6 m/s)(2\cdot 10^{-4} T)(1)=1.03\cdot 10^{-16} N[/tex]
The direction is given by the right hand rule:
- Index finger: direction of motion of the electron, +i direction (away from the wire)
- Middle finger: direction of magnetic field, +j direction (tangent to a circle around the wire)
- Thumb: direction of the force --> since the charge is negative, the sign must be reversed, so it means -k direction (anti-parallel to the current in the wire)
(b) [tex]1.03\cdot 10^{-16} N[/tex], +i direction
The calculation of the magnetic field and of the force on the electron are exactly identical as before. The only thing that changes this time is the direction of the force. In fact we have:
- Index finger: direction of motion of the electron, +k direction (parallel to the current in the wire)
- Middle finger: direction of magnetic field, +j direction (tangent to a circle around the wire)
- Thumb: direction of the force --> since the charge is negative, the sign must be reversed, so it means +i direction (away from the wire)
(c) 0
In this case, the electron is moving tangent to a circle around the wire, in the +j direction. But this is exactly the same direction of the magnetic field: this means that v and B are parallel, so [tex]\theta=0, sin \theta=0[/tex], therefore the force on the electron is zero.
You stretch a spring by a distance of 0.05 m. The spring has a spring constant of 125 N/m. When you release the spring, it snaps back. What is the kinetic energy of the spring as it reaches its natural length?
Answer:
KE = 0.16 J
Explanation:
As we know that total energy is always remains conserved
so here we can say that initial potential energy stored in the spring is equal to the kinetic energy of the object when it comes to relaxed state
So here we have
[tex]U = \frac{1}{2}kx^2[/tex]
here we know that
[tex]k = 125 N/m[/tex]
x = 0.05 m
now from above equation
[tex]U = \frac{1}{2}(125)(0.05)^2[/tex]
[tex]U = 0.16 J[/tex]
so total potential energy here is same as the final kinetic energy which is 0.16 J
A proton travels with a speed of 4.2×106 m/s at an angle of 30◦ west of north. A magnetic field of 2.5 T points to the north. Find the magnitude of the magnetic force on the proton. (The magnetic force experienced by the proton in the magnetic field is proportional to the component of the proton’s velocity that is perpendicular to the magnetic field.)
Answer:
[tex]8.4\cdot 10^{-13} N[/tex]
Explanation:
The magnitude of the magnetic force on the proton is given by:
[tex]F=qvB sin \theta[/tex]
where:
[tex]q=1.6\cdot 10^{-19} C[/tex] is the proton charge
[tex]v=4.2\cdot 10^6 m/s[/tex] is the proton velocity
[tex]B=2.5 T[/tex] is the magnetic field
[tex]\theta=30^{\circ}[/tex] is the angle between the direction of v and B
Substituting into the formula, we find
[tex]F=(1.6\cdot 10^{-19}C)(4.2\cdot 10^6 m/s)(2.5 T) sin 30^{\circ}=8.4\cdot 10^{-13} N[/tex]
In a mass spectrometer, a specific velocity can be selected from a distribution by injecting charged particles between a set of plates with a constant electric field between them and a magnetic field across them (perpendicular to the direction of particle travel). If the fields are tuned exactly right, only particles of a specific velocity will pass through this region undeflected. Consider such a velocity selector in a mass spectrometer with a 0.115 T magnetic field.a. What electric field strength, in volts per mater, is needed to select a speed of 3.7 x 10^6 m/s?b. What is the voltage, in kilovolts, between the plates if they are separeted by 0.75 cm?
(a) [tex]4.26\cdot 10^5 V/m[/tex]
In a velocity selector, the speed of the beam is related to the magnitude of the electric field and of the magnetic field by the formula:
[tex]v=\frac{E}{B}[/tex]
where
E is the magnitude of the electric field
B is the magnitude of the magnetic field
In this problem, we have
[tex]B=0.115 T[/tex] (magnetic field)
[tex]v=3.7\cdot 10^6 m/s[/tex] (speed of the particles)
Solving the equation for E, we find the electric field:
[tex]E=vB=(3.7\cdot 10^6 m/s)(0.115 T)=4.26\cdot 10^5 V/m[/tex]
(b) 3.2 kV
The relationship between electric field and potential difference between the two plates is:
[tex]V=Ed[/tex]
where, in this problem:
[tex]E=4.26\cdot 10^5 V/m[/tex] is the magnitude of the electric field
[tex]d=0.75 cm=0.0075 m[/tex] is the separation between the plates
Substituting into the equation, we find the potential difference:
[tex]V=(4.26\cdot 10^5 V/m)(0.0075 m)=3195 V=3.2 kV[/tex]
On Halloween, you take a glow stick, crack the capsule inside and shake it until it glows. This is an example of light energy being created from ___________________ energy.
This is chemical energy the substance that makes it glow are chemicals.
Answer:
Chemical .
Explanation:
On Halloween, you take a glow stick, crack the capsule inside and shake it until it glows. This is an example of light energy being created from ___________________ energy
From the principle of the conservation of energy which states that energy can neither be created nor destroyed but can converted from one form to another
Phenyl oxalate ester is responsible for the luminescence in a glow stick.When it reacts with hydrogen peroxide, the liquid inside a glow stick to glow.
therefore we can say that chemical energy is been converted to light energy
the glow lights are by no means radioactive. it can be made to glow again by putting it in a freezer.
Electromagnetic force is present when electromagnetic fields
a- become charged as they lose electrons.
b- become stable as they come in contact with other forces.
c- interact with charged particles.
d- gain energy from other forces.
b is the correct answer
Answer:
c- interact with charged particles.
Explanation:
When a charged particle is placed in the field of the other charged particle then it will experience electromagnetic force on it.
As we know that force on a charged particle due to some other electric field is given by
F = qE
here we know
q = charge
E = electric field intensity
Similarly when a charged particle is placed in external magnetic field then the force on that moving charge is given by
[tex]F = q(v\times B)[/tex]
so here if charge is moving in the magnetic field due to some other system then the force on it is given by above equation.
So here we can say that electromagnetic force is present when electromagnetic fields
c- interact with charged particles.