The basic unit of pressure mapped on weather maps is

Answers

Answer 1
the answer is millibars
Answer 2

The basic unit of pressure mapped on weather maps is Millibar (mb). The correct option is A.

The standard unit for displaying atmospheric pressure on weather maps is the millibar, which is a frequently used unit of pressure in meteorology. It is equal to 100 pascals, or one thousandth of a bar.

Isobars, or lines bridging regions of equal atmospheric pressure, are shown on weather maps, and they are commonly labelled in millibars.

With the aid of this device, meteorologists can quickly analyse and evaluate pressure variations and patterns across various geographic locations, which aids in comprehending weather systems and the circumstances that go along with them.

Thus, the correct option is A.

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Your question seems incomplete, the probable complete question is:

The basic unit of pressure mapped on weather maps is

A) Millibar (mb)

B) Pascal (Pa)

C) Atmosphere (atm)

D) Pound per square inch (psi)


Related Questions

A rightward-moving truck skids to a stop from a very high speed with its wheels locked. What forces are exerted on the object?

Answers

Answer

Friction between the wheels and the ground, normal force, and friction force in the brakes.

Explanation

A truck moves on the surface simply because the driving force is greater than frictional force. The is always the normal force acting perpendicularly on the ground. The frictional force will be applying in two areas that is in the brakes and between the road and the wheels.

So, the forces exerted on the object are; friction and the normal force.

Final answer:

The pram starts moving when the applied force reaches 75 N due to static friction, and then it can be kept moving with a force of 37.5 N due to kinetic friction. The coefficients of static and kinetic friction are 0.75 and 0.375, respectively.

Explanation:

When the pram's brakes are locked, it requires a certain amount of force to overcome the static friction and get it moving. According to the question, the pram starts moving when the applied force is three-quarters of the normal force, which is 100 N.

Therefore, the force required to start moving the pram is (3/4) × 100 N = 75 N. Static friction is what prevents the pram from starting to move until this force is applied.

Once the pram starts moving, the force required to keep it moving drops to half of the force required to start moving it, which is (1/2) × 75 N = 37.5 N, indicating the kinetic friction between the pram and the surface is now in effect.

The coefficient of static friction (μs) is calculated using the formula μs = (force of static friction)/(normal force) = 75 N / 100 N = 0.75. Similarly, the coefficient of kinetic friction (μk) = (force of kinetic friction)/(normal force) = 37.5 N / 100 N = 0.375.

An insulated lunch bag keeps food warm by

Answers

trapping warm air in and keeping cold air out

An insulated lunch bag uses materials that slow down heat transfer.

Importance of Features in Insulated Containers

An insulated lunch bag keeps food warm by utilizing materials that slow down heat transfer, complying with the principles of thermodynamics. To understand which features are most important in minimizing the rate of a hot beverage cooling, we need to consider the mechanisms of heat transfer: conduction, convection, and radiation. A metal lining might conduct heat, leading to quicker heat loss, unless it's part of a vacuum layer such as in a thermos. Insulating cup material, on the other hand, is crucial as materials like polystyrene or foam are poor conductors of heat and therefore reduce heat loss through conduction. The importance of a lid can't be overstated because it traps hot air and reduces heat loss through convection.

A pendulum has 297 J of potential energy at the highest point of its swing. How much kinetic energy will it have at the bottom of its swing?

Answers

If no energy is lost to friction or air resistance, then kinetic energy at the bottom and potential energy at the top are equal.

Provide at least three reasons why friction is needed.

Answers

Uses of Friction. Although you normally hear about trying to reduce or eliminate friction, it actually has some important uses. Since friction is a resistance force that slows down or prevents motion, it is necessary in many applications where you might want to hold items or do things and prevent slipping or sliding.

Friction is a force that exists between two surfaces in contact. Some of the applications of friction in our everyday lives include;

The force of friction between the tyre of a vehicle and the road. The rough surface of the road and the surface of the tyre reduce the possibility of the car skidding off the road.

The friction that exists between the leg and the floor enables us to walk freely without slipping

Friction also enables the smooth belt of a grinder to slide freely over motor

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An 80 kg hockey player is skating at 5 m/s. He collides with the wall and comes to a stop in .2 s. What was the force of his impact on the wall

Answers

F = mass * acceleration
The 80kg hockey player was travelling at 5 m/s when he hit the wall.He stopped in .2 s, which means that he decelerated by 5m/s in .2 seconds.

This means this deceleration was 5 m / 0.2 s² = 25 m/s²

To calculate Force, multiply mass times acceleration
80kg times 25m/s² = 2,000 N

In this question, a hockey player with mass 80kg is skating with velocity 5m/s and then collide with a wall for 0.2 seconds. Force formula is mass multiplied by acceleration.
In this case, the velocity is changed into 5m/s into 0m/s in 0.2 second. Then the acceleration is: (5m/s - 0m/s) / 0.2 second= 25m/s^2

Then, the force on his impact should be: 

force= mass*acceleration
force= 80kg * 25 m/s^2= 2000N

What is the frequency of radiation whose wavelength is 2.40x10-5 cm?

Answers

This problem can be answered using the equation below:


c = frequency x wavelength

where: c is the speed of light, which is equal to 3.00 x 10^8 m / s 

frequency = c / wavelength 
= (3.00 x 10^8m /s) / (2.40 x 10^-5 cm x 1 m /100cm)


= (3.00 x 10^8 m/s) / 2.40 x 10^-7m 


= 1.25 x 10^15/s 1 / s = 1Hz 


Frequency = 1.25 x 10^15Hz

What is your average speed if you walk 2 kilometers in 20 minutes?

Answers

multiply 2 and .33 to get .66...km per hour.
if you the answer in km/h it is 2km/.33h
which is equal to 6.06km/h or 6km/h
In meters per second it is 2000m/1200s
which is equal to 1.67m/s

What happens to the pressure inside a container when you reduce the volume?

Answers

the gas temperature woul increase

48. Protons have ___ charge, neutrons have ___ charge, and electrons have ___ charge.
A. negative; positive; no
B. positive; no; negative
C. positive; negative; no
D. negative; no; positive
E. no; negative; positive

Answers

positive; no; negative

In the four-stroke internal combustion engine, fuel is ignited during the ____ stroke.

Answers

The four strokes in order are the intake stroke, the compression stroke, the power stroke, and the exhaust stroke. Fuel is ignited during the power stroke.
The power stroke, I believe.
Sorry if this does not help.

When two objects are touching and transfer heat, it is called _____?

Answers

friction its like rubbing your hands together 

When the electron in a hydrogen atom moves from n = 5 to n = 2, light with a wavelength of ________ nm is emitted?

Answers

             In order for an electron to move to a higher energy level, the photon is absorbed by
the atom. The energy of the photon must be at least enough to raise the electron
from energy level 2 to level 5. The wavelength w can be found by Rydberg's formula
1/w = R(1/L² - 1/U²), where L and U are the lower and upper energy levels, in this
case 2 and 5. R is the Rydberg constant, experimentally found to be10,967,758
waves per meter for hydrogen. So the wavelength w is: 1/w = R(1/4 - 1/25) = 0.21R
The value we get is w = 4.34 * 10**-7 meter, or 434 nanometers and it is absorbed
by the atom to cause the electron to move to the higher energy level.
Answer choice A above is the best choice. Hope this answers your question.
Final answer:

The wavelength of light emitted when an electron in a hydrogen atom transitions from n = 5 to n = 2 is 434 nm, which falls within the blue spectrum.

Explanation:

When the electron in a hydrogen atom moves from n = 5 to n = 2, light with a specific wavelength is emitted. This transition falls under the Balmer series, which includes the transitions of electrons from higher energy levels to n = 2. The specific wavelengths of the Balmer series for n = 3 to n = 2 is 656 nm (red), for n = 4 to n = 2 is 486 nm (green), for n = 5 to n = 2 is 434 nm (blue), and for n = 6 to n = 2 is 410 nm (violet). Therefore, the wavelength of light emitted when an electron transitions from n = 5 to n = 2 is 434 nm.

If a ball is thrown vertically upward from the roof of 64 foot building with a velocity of 96 ft/sec, then what is the maximum height the ball reaches? what is the velocity of the ball when it hits the ground?\

Answers

The height function would be s(t) = -16t^2 + 64t + 32.

Maximum height ---> set s'(t) = 0.

-32t + 64 = 0. ---> t = 2. s(2) = -16(2)^2 + 64(2) + 32 = the maximum height is 96 feet.

To find the velocity when it hits the ground, set s(t) = 0.

-16t^2 + 64t + 32 = 0. Divide by -16.

t^2 - 4t - 2 = 0. The only positive solution is x = 4.45.

s'(4.45) = -32(4.45) + 64 = It's going -78.4 feet/second when it hits the ground.

Some instruments differentiate individual quanta of electromagnetic radiation based on their energies. assume such an instrument has been adjusted to detect quanta that have 3.50× 10–16 j of energy. what is the wavelength of the detected radiation? give your answer in nanometers.

Answers

There is a relationship between the energy of a photon and its wavelength. This can be expressed as a mathematical equation shown below:

E = hc/λ
where
h is the Planck's constant equal to 6.62607004 × 10⁻³⁴ m² kg / s
c is the speed of light equal to 3× 10⁸ m/s
λ is the wavelength

3.5×10⁻¹⁶ J = (6.62607004 × 10⁻³⁴ m² kg / s)(3× 10⁸ m/s)/λ
Solving for λ,
λ = 56.8×10⁻⁹ m or 56.8 nm

how do you find acceleration

Answers

Acceleration=non-uniform velocity/time
                    =displacement/time^2

Answer:

Acceleration is given by the formula :

a = (v - u)/t

a is the acceleration , u is the initial velocity , v is the final velocity , t is the time in seconds

Who would be a member of the American dental association?
A) a practicing dentist
B) a retired dentist
C) a dental student
D) a dental patient

Answers

Answer:

The correct answer is A)practicing dentist

Explanation:

Hello!

Let's solve this!

The American Dental Association (ADA) is an association of practicing dentists. They are dedicated to promoting dental health and giving assistance to those who need it.

They also give recommendations and talks about oral health.

The correct answer is A)practicing dentist

If a tube is placed vertically into a container of water, and the water level inside the tube is the same as the water level on the outside, what can we determine about the pressure inside the tube?

Answers

it's equal to d external atmospheric pressure

A ball is dropped from a cliff and falls a distance of 20 m to the ground. Determine the velocity it hits the ground at and the time for the ball to fall.
A.v = -10 m/s, t = 2 s
B.v = 20 m/s, t = 4 s
C.v = -20 m/s, t = 2 s
D.v = 10 m/s, t = 2 s

Answers

Use the kinematic equation: d = vi • t + ½ • a • t^2
20=0(t)+(0.5)(9.8)(t^2)
20=4.9(t^2)
t=2.02seconds
---------------------------------
Final Velocity=Initial Velocity +at^2
Vf=(9.8)(2.02^2)
Vf=19.796
Final answer:

The ball hits the ground with a velocity of 19.6 m/s and it takes approximately 2.02 seconds for the ball to fall.

Explanation:

To determine the velocity the ball hits the ground at, we can use the equation v = gt, where g is the acceleration due to gravity, approximately 9.8 m/s². Since the ball falls for 2 seconds, the velocity is given by v = 9.8 m/s² * 2 s = 19.6 m/s. Therefore, the ball hits the ground with a velocity of 19.6 m/s.

To determine the time it takes for the ball to fall, we can use the equation h = (1/2)gt², where h is the height and t is the time. Rearranging the equation, we have t = √(2h/g). Substituting the given height of 20 m, the time is t = √(2 * 20 m / 9.8 m/s²) = √4.08 s ≈ 2.02 s. Therefore, the time for the ball to fall is approximately 2.02 seconds.

How many 750.0-ml wine bottles can be purged with the argon in the canister at a pressure of 1.26 atm and a temperature of 283 k ?

Answers

Approximately 0.0305 wine bottles can be purged with the argon in the canister.

Let's go through the calculations step by step:

Given:
- Pressure (\(P\)) = 1.26 atm
- Volume (\(V\)) = 0.75 L (converted from 750.0 ml)
- Temperature (\(T\)) = 283 K
- Ideal Gas Constant (\(R\)) = 0.0821 L·atm/(mol·K)

Now, use the ideal gas law to find the number of moles [tex](\(n\)):\[ n = \frac{PV}{RT} \][/tex]

[tex]\[ n = \frac{(1.26 \, \text{atm}) \times (0.75 \, \text{L})}{(0.0821 \, \text{L·atm/(mol·K)}) \times (283 \, \text{K})} \]\[ n = \frac{0.945}{23.2263} \]\[ n \approx 0.0408 \, \text{mol} \][/tex]

Now, let's assume that the argon canister contains pure argon, and we need to find out how many moles of argon are in a wine bottle. Argon's molar mass is approximately 39.95 g/mol.

[tex]\[ \text{Moles of argon in a wine bottle} = \frac{\text{Molar mass of argon} \times \text{Volume of the bottle}}{\text{Molar volume at STP}} \]\[ \text{Moles of argon in a wine bottle} = \frac{(39.95 \, \text{g/mol}) \times (0.75 \, \text{L})}{22.4 \, \text{L/mol}} \]\[ \text{Moles of argon in a wine bottle} \approx 1.34 \, \text{mol} \][/tex]

Finally, to find the number of wine bottles that can be purged with the argon in the canister:

[tex]\[ \text{Number of bottles} = \frac{\text{Total moles in canister}}{\text{Moles in one bottle}} \]\[ \text{Number of bottles} = \frac{0.0408 \, \text{mol}}{1.34 \, \text{mol/bottle}} \]\[ \text{Number of bottles} \approx 0.0305 \][/tex]

Therefore, approximately 0.0305 wine bottles can be purged with the argon in the canister.

Ball is thrown upward from the ground with an initial speed of 25 m/s; at the same instant, another ball is dropped from a building 15 m high. after how long will the balls be at the same height?

Answers

0.6 seconds after the balls start moving, they'll be at the same height. The altitude the 1st ball will be at time T is a = 25T - 0.5AT^2 The altitude the 2nd ball will be at time T is a = 15 - 0.5AT^2 Set both expressions equal to each other and solve for T 25T - 0.5AT^2 = 15 - 0.5AT^2 Add 0.5AT^2 to both sides 25T = 15 Divide both sides by 25 T = 15/25 = 3/5 = 0.6 So both balls will be at the same altitude 0.6 seconds after they start moving. Let's verify those results. Assume A = 9.8 m/s^2 0.5 * 9.8 m/s^2 * 0.6s^2 = 4.9 m/s^2 * .36 s^2 = 1.764 m The altitude the 1st ball will be at after 0.6 seconds is 0.6 s * 25 m/s - 1.764m = 15 m - 1.764 m The altitude the 2nd ball will be at after 0.6 seconds is 15 m - 1.764 m Both are the same value so the answer is verified.
Final answer:

The problem involves the principles of projectile motion. The ball thrown upward reaches its peak in 2.5 seconds. The ball dropped from the building cover 15 meters in about 1.75 seconds. Therefore, after the peak, the first ball will take an additional 0.75 second to descend to the point where both balls are at the same height, about 3.25 seconds from the start.

Explanation:

This physics problem involves applying the principles of projectile motion. We start by calculating the time it takes for the ball thrown upward to reach its peak. Since acceleration acting against the motion of the first ball is gravity (9.8 m/s²), using the formula final velocity = initial velocity - (acceleration* time), and since the final upward velocity at the top is 0, we calculate the time it takes the throw up ball to peak as 2.5 seconds (0 = 25m/s - 9.8m/s² * t).

Next, we calculate the time it takes for a ball to fall 15m from rest (assume the drop from the building begins from rest). We use the formula h = 0.5*g*t² which we rearrange to solve for time, yielding t=√(2h/g). Using this formula with h = 15m, we get t ≈ 1.75 seconds.

Therefore, the ball thrown upwards must start to descend after reaching peak so that both balls meet at the same height. Subtracting the two times, we get 2.5 seconds - 1.75 seconds = 0.75 second. Ball 1 will take 0.75 seconds to descend so that both balls reach the same height at the same instance. So, after approximately 3.25 seconds from the start of projectile motion, the two balls will be at the same height.

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What would we need to know to calculate both work and power?

A -energy, force, and time
B -force, distance, and time
C -force, mass, and distance
D -mass, force, and energy

Answers

we would need force, distance and time
B is your answer

A race car is moving with a velocity of 144 kilometers/hour. The driver applies the brakes, and the car comes to a halt in 12.0 seconds. What is the average acceleration of the car during those 12.0 seconds?

Answers

-12 k/s/s (the number is right the abbreviation might not be)

Explain why streets and highways have speed limits and not velocity limits.

Answers

We know that speed is a scalar unit while velocity is a vector. The signs are mostly concerned with the magnitude that the car should travel in, the direction is not as important. 

Hope I helped :) 
Final answer:

Streets and highways implement speed limits, not velocity limits, as speed is concerned with only how fast an object is moving, while velocity includes both speed and direction. Imposing velocity limits is impractical as the direction of a moving vehicle continuously varies. Speed limits are enforced to regulate the speed of vehicles, thereby ensuring road safety.

Explanation:

Streets and highways have speed limits instead of velocity limits because speed concerns only the magnitude of movement while velocity includes both speed and direction. Speed is a scalar quantity, meaning it involves only magnitude. On the other hand, velocity is a vector quantity, taking into account both the speed of an object and its direction of motion.

For instance, when a vehicle runs through an intersection without regard to the speed limit, a traffic signal can make the vehicle slow down. This highlights the need for enforcing speed limits.

The final velocity of a vehicle depends on both the magnitude of acceleration and the distance it covers. A vehicle going twice its speed doesn't stop exactly at twice the distance but goes much further before stopping, as exemplified by reduced speed zones near schools. This concept reinforces the necessity of speed limits to ensure public safety and reduce road accidents.

In conclusion, while speed refers to the rate at which an object moves, velocity refers to both the rate and direction of an object's movement. It's impractical to impose velocity limits because direction varies continuously for a car in motion, hence, speed limits are established to regulate the rapidness of vehicles, ensuring road safety.

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PLEASE HELP!!!
If an airplane were flying west at 100 km/hr and encountered a strong gale blowing east at 100 km/hr, what would be the plane's velocity relative to the ground?

***By the way, theres no picture***

Answers

Answer: 0 km/h

Explanation:
As a vector, the plane's velocity is 100 km/h (west) - 100 km/h (east)  = 0 km/m.
To an observer on the ground, the plane will be standing still.

Which of the following statements about an apple falling from a tree is true? A) Its kinetic energy decreases and its potential energy increases. B) Its potential energy decreases and its kinetic energy increases. C) Its kinetic and potential energies remain constant. D) Its mechanical energy increases.

Answers

your answer would be B because potential energy is an object's potential to move while kinetic energy is the energy of the object in motion. So if the apple is falling, then the potential energy would decrease and its kinetic energy would increase. 

Hope this helps :)


Which one of the following scenarios accurately describes a condition in which resonance can occur?

A. A column of air has a height equal to 1 ⁄ 8 of the wavelength of the sound waves produced by a tuning fork vibrating over the column of air in an open pipe that's partially immersed in water.
B. A vibrating tuning fork is struck and begins to vibrate as the object used to strike it is placed away from the tuning fork.
C. A pipe's length is equal to 1 ⁄ 2 of the wavelength of the sound waves produced by a tuning fork vibrating over one end of the pipe that's open to the air at both ends.
D. A person is holding a tuning fork on one end of a football field and another person is holding a separate tuning fork on the opposite end of the field.

Answers

Final answer:

Scenario C correctly describes resonance, where a pipe open at both ends has a length equal to half the wavelength of the sound from the tuning fork, allowing for a standing wave and resonant sound.

Explanation:

The scenario that accurately describes a condition in which resonance can occur is scenario C: A pipe's length is equal to 1 ⁄ 2 of the wavelength of the sound waves produced by a tuning fork vibrating over one end of the pipe that's open at both ends. In this case, the half-wavelength of the sound matches the length of the pipe, allowing a standing wave to be set up with antinodes at both ends and a node in the middle. This results in constructive interference and a resonant amplification of the sound.

A force of 150 N accelerates a 25 kg wooden chair across a wood floor at 4.3 m/s2 . How big is the frictional force on the block? What is the coefficient of friction between the chair and floor?

Answers

We can first calculate the net force using the given information.

By Newton's second law, F(net) = ma:

F(net) = 25 * 4.3 = 107.5

We can now calculate the frictional force, f, which is working against the applied force, F(app) (this is why the net force is a bit lower):

f = F(net) - F(app) = 150 - 107.5 = 42.5 N

Now we can calculate the coefficient of friction, u, using the normal force, F(N):

f = uF(n) --> u = f/F(N)
u = 42.5/[25(9.8)]
u = 0.17

If the acceleration of an object is negative, the object must be slowing down. true or false

Answers

True, because when you are slowing down you LOSE speed.

If the acceleration of an object is negative, the object must be slowing down, which is true, as acceleration is the rate at which an object changes its velocity, if the acceleration is negative, it means that the velocity is decreasing over time.

What is acceleration?

Acceleration is a vector quantity that describes the rate at which an object's velocity changes and is the derivative of velocity with respect to time, so if the acceleration is negative, it means that the velocity is decreasing with respect to time. and can happen if the object is moving in the opposite direction from its initial velocity. This can be described by taking an example: if a car is moving forward with a velocity of 30 meters per second and its acceleration is -5 meters per second squared, it means that its velocity is decreasing at a rate of 5 meters per second.

Hence, if the acceleration of an object is negative, the object must be slowing down, which is true.

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A wave has a frequency of 8500HZ and a wavelength of 1.5 m what is the speed of the wave?

Answers

using
v= πF
v = 1.5 × 8500 = 12750ms-¹

What does buoyancy depend on?

A. the density of the object and the density of the fluid

B. atmospheric pressure and the density of the object

C. The density of the object and the force of gravity

D. the density of the surrounding air and the density of water

Answers

Answer:

D.  the density of the surrounding air and the density of water.

The buoyancy depends on D. the density of the surrounding air and the density of water.

Is buoyancy depending on density?

be aware of how the buoyant pressure most effective depends on the density of the fluid ρ in which the object is submerged, the acceleration due to gravity g, and the quantity of the displaced fluid V f V_f Vf​V, start subscript, f, quit subscript. fairly the buoyant force doesn't rely upon the general depth of the item submerged.

what is buoyancy provide an explanation for?

the tendency of a frame to glide or to upward push whilst submerged in a fluid trying out an item's buoyancy.  chemistry: the electricity of a fluid to exert upward pressure on a frame positioned in it the buoyancy of water also : the upward force exerted.

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