The basal diameter of a sea anemone is an indicator of its age, and in a certain population of anemones, the distribution of basal diameters is approximately normal with a mean of 5.3 cm and a standard deviation of 1.8 cm. suppose you randomly select five anemones from this population.
a. what is the probability that all five anemones have a basal diameter more than 5.5 cm? (2pt)

Answers

Answer 1
Final answer:

The probability that all five randomly selected sea anemones from a population with normally distributed basal diameters have a diameter more than 5.5 cm is approximately 4.5%.

Explanation:

To solve this problem, we first need to find the probability that one sea anemone has a basal diameter more than 5.5 cm, given the population's mean basal diameter is 5.3 cm with a standard deviation of 1.8 cm. We calculate the Z-score for a diameter of 5.5 cm to see how many standard deviations this value is away from the mean. The Z-score formula is Z = (X - μ) / σ, where X is the value in question, μ is the mean, and σ is the standard deviation.

The Z-score for a diameter of 5.5 cm is Z = (5.5 - 5.3) / 1.8 ≈ 0.11. Looking this up in a standard normal distribution table, we find that the probability of selecting an anemone with a diameter larger than 5.5 cm is approximately 0.5438. Since the selections are independent, the probability of all five having a diameter more than 5.5 cm is (0.5438)⁵ ≈ 0.045, or 4.5%.

Answer 2

The probability that all five randomly selected anemones have a basal diameter more than 5.5 cm is approximately 0.0056.

To solve this problem, we can use the standard normal distribution. First, we need to standardize the diameter value using the z-score formula:

[tex]z = \frac{x - \mu}{\sigma}[/tex]

where:

- x is the value of the basal diameter,

- [tex]\mu[/tex] is the mean of the basal diameters (5.3 cm),

- [tex]\sigma[/tex] is the standard deviation of the basal diameters (1.8 cm), and

- z is the standardized score.

For a basal diameter of 5.5 cm, the z-score would be:

[tex]z = \frac{5.5 - 5.3}{1.8} = \frac{0.2}{1.8} \approx 0.1111[/tex]

To find the probability that an anemone has a basal diameter more than 5.5 cm, we need to find the area to the right of z = 0.1111 under the standard normal curve.

Using a standard normal table or calculator, we find that this area is approximately 0.4562.

Since each selection is independent (assuming replacement), the probability that all five anemones have a basal diameter more than 5.5 cm is the probability raised to the power of 5:

[tex]P(\text{all five} > \text{ 5.5 cm}) = (0.4562)^5 \approx 0.0056[/tex]

So, the probability that all five randomly selected anemones have a basal diameter more than 5.5 cm is approximately 0.0056.


Related Questions

Calculate the quotient and remainder of –111 divided by 11. (quotient, remainder)

Answers

quotient  10   remainder :1

Final answer:

The quotient of –111 divided by 11 is –10, and the remainder is –1. We obtain this by dividing –111 by 11 and then finding the difference between the product of the quotient and 11 and –111.

Explanation:

To calculate the quotient and remainder of –111 divided by 11, we perform the division as follows:

Divide –111 by 11 to find the quotient. Since 111 is divisible by 11, the quotient is –10.To find the remainder, we calculate –10 multiplied by 11, which is –110, and subtract it from –111. The difference is –1, so the remainder is –1.

Therefore, the quotient is –10 and the remainder is –1.

Ellen Saver went to her bank. She had a balance of $2,447.67 in her savings account. She withdrew $231.49 and the teller credited her account with $36.61. What is her new balance?

$2,179.57
$2,252.79
$2,642.77
$2,715.77

Answers

This is the equation. 2,447.67-231.49+36.61. The answer is $2,252.79

A trial has markers every 1/8 mile. Jody starts at the 2 1/4-mile marker, hikes to the 4 3/8-mile marker, and then hikes back to the 1 1/2 mile marker. Did Jody hike more than 4 miles? Explain.

Answers

I think so because she started at 2 1/4 then hiked to 4 3/8. That is roughly 2 miles and then from there she joked all the way back to 11/2
1) determine how many miles Jody hikes when she leaves from the 2 1/4 mile marker and arrives at the 4 3/8 mile marker, by subtraction:

4 3/8 - 2 2/8 = 2 1/8 miles.

2) determine how many miles she hikes, leaving the 4 3/8 mile marker and arriving at the 1 1/2 mile marker.  Again, subtract:

4 3/8 - 1 4/8 =   3 11/8 - 1 4/8 = 2 7/8 miles.

Adding together 2 1/8 miles and 2 7/8 miles, we get 5 miles.

Did Jody hike more than 4 miles?  You decide.


Sam’s parents agreed to pay 25 percent of the cost of a new bike if Sam paid the rest.If Sam’s parents paid $65, what was the price of Sam’s new bike?

Answers

$260 Is the cost of Sam's new bike.
100 divided by 25 equals 4. If 25% of 100% was paid (65$), multiply 65 by the remaining "3 25%" (65 multiplied by 3 equals 195). Sam paid a total of $195 (75%), his parents paid a total of $65 (25%), and the total cost of the bike was $260.

Is the difference of 1.48-0.25 less than or greater than one explain

Answers

Greater because it's 1.23 so
1 < 1.23

Find 1/4+13/20
. Write your answer as a fraction in simplest form.

Answers

The LCD here is 20.  Thus, 1/4 = 5/20.  The sum of 5/20 and 13/20 is 18/20, which can be reduced to 9/10.

A fraction is a way to describe a part of a whole. The sum of the two of the given fractions is equal to 9/10.

What is a Fraction?

A fraction is a way to describe a part of a whole. such as the fraction ¼ can be described as 0.25.

The given fractions can be added as shown below.

(1/4) + (13/20)

Taking the LCM of the denominator which is equal to 20,

= (1×5 / 4×5) + (13/20)

= (5/20) + (13/20)

= (5 + 13)/20

= 18/20

Divide both the numerator and the denominator by 2,

= 9/10

Hence, the sum of the two of the given fractions is equal to 9/10.

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You have deposited $800 in a savings account, which pays three percent interest compounded quarterly. Find the amount in the account for 5 years

Answers

$928.95 
You take $800 and multiply it by  0.0075 which is 1/4 of 3% since there are 4 quarters per year. Every time you multiply it you add the previous number and you have to do this 20 times since there are 20 quarters in 5 years. For example, 800 x 0.0075 = 6 + 800 = 806 x 0.0075 = 6.045 + 806 = 812.045 x 0.0075 = 6.0903375 + 812.045 = 818.1353375 and you just keep doing thing until you reach your total amount of quarters. Then you just round your decimal point to the hundredth place.

The weights of steers in a herd are distributed normally. the standard deviation is 200 lbs and the mean steer weight is 1300 lbs. find the probability that the weight of a randomly selected steer is between 1000 and 1437 lbs. round your answer to four decimal places.

Answers

Given a mean = 1300 and a Ď = 200, we can calculate that the lower bound of 1000 is (1000 - 1300) / 200 = -1.5 standard deviations below the mean. The upper bound is (1437 - 1300) / 200 = 0.685 standard deviations from the mean. Using the cumulative distribution function, we can calculate that the probability a randomly chosen steer lies on the interval [1000, 1437] is CDF(0.685) - CDF(-1.5) = 0.68652083824480004 p = 0.6865


A box of crayons costs $1.75, including tax. Mr. Valentino wants to purchase boxes of crayons for his class and has a $25 budget. Write an inequality to solve for the number of boxes of crayons Mr. Valentino can purchase with his budget

a.$1.75x ≤ $25

b.$1.75x ≥ $25

c.$25x ≤ $1.75

d.$25x ≥ $1.75

it is multiple choice

Answers

1.75x < = 25....with x being the number of boxes of crayons

the reason it is less then or equal is because he can only spend at most $ 25
Final answer:

The correct inequality to solve for the number of boxes of crayons Mr. Valentino can purchase with his budget is $1.75x ≥ $25.

Explanation:

The correct inequality to solve for the number of boxes of crayons Mr. Valentino can purchase with his budget of $25 is b. $1.75x ≥ $25.

This inequality states that the product of the cost per box, $1.75, and the number of boxes, x, must be greater than or equal to $25 to remain within his budget.

You can solve this inequality by dividing both sides by $1.75 to find the minimum number of boxes he can buy and still stay within his budget.

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The population and areas of four states are shown.

Answers

I believe the answer is the second option. Hope i helped.

The answer is B) The state with the second lowest population has the lowest population density.

What are the steps for using a compass and straightedge to construct a square? Drag and drop the steps in order from start to finish.

1.Construct a line perpendicular to line m through point F. Label a point on this line as point G.
2.Use a straightedge to draw line m and label a point on the line as point F.
3.Without changing the compass width, place the compass point on point H and draw an arc in the interior of ∠HFK .
4.Use the straightedge to draw JH¯¯¯¯¯ and JK¯¯¯¯¯.
5.With the compass open to the desired side length of the square, place the compass point on point F and draw an arc on line m and an arc on FG←→ . Label the points of intersection as points H and K.
6.Keeping the same compass width, place the compass on point K and draw an arc in the interior of ∠HFK to intersect the previously drawn arc. Label the point of intersection as point J.

Answers

The steps for using a compass and straightedge to construct a square are given as follows:

1. Use a straightedge to draw line m and label a point on the line as point F

2. Construct a line perpendicular to line m through point F. Label a point on this line as point G.

3. With the compass open to the desired side length of the square, place the compass point on point F and draw an arc on line m and an arc on FG←→ . Label the points of intersection as points H and K.

4. Without changing the compass width, place the compass point on point H and draw an arc in the interior of ∠HFK.

5. Keeping the same compass width, place the compass on point K and draw an arc in the interior of ∠HFK to intersect the previously drawn arc. Label the point of intersection as point J.

6. Use the straightedge to draw JH¯¯¯¯¯ and JK¯¯¯¯¯.

These are the right answers

The rate in which a function increases or decreases between its points are called the slope, or the rate of change. For any function, the rate of change is calculated by the slope formula. Slope formula: where m = slope (a, f(a)) and (b, f(b)) are two points on the function. Here is an example: For the function, f(x) = 2x - 1, calculate the rate of change between the points, (-1, f(-1)) and (4, f(4)). Let(-1,f(-1))=(a,f(a)) and (4,f(4))=(b,f(b)). Use the given functin, f(x)=2x-1, to complete the points. For (-1, f(-1): For (4,f(4)) f(x)=2x-1 f(x)=2x-1 f(-1)=2(-1)-1 f(4)=2(4)-1 f(-1)=-3 f(4)=7 (-1,f(-1))=(-1,-3) (4,f(4))=(4,7) Next, calculate the slope for the function, using the points (-1, -3) and (4, 7). For the formula, let(-1,-3) =(a,f(a)) and (4,7) = (b,f(b)): The slope of the function, f(x)=2x-1, between the points (-1, -3) and (4,7) is 2. For each function, use the slope formula to calculate the rate of change between the points. In your final answer, include all of your calculations. f(x): (a, f(a) and (b,f(b) 1.) f(x)=x - 3 (0,f(0)) and (6,f(6)) 2.) f(x) = -x (-4,f(-4)) and(2,f(2)) 3.) f(x)=x2 (-2,f(-2)) and (0,f(0)) 4.) f(x)=x3 (-1,f(-1)) and (1,f(1)) 5.) f(x)=2x (0,f(0)) and (4,f(4))

Answers

I'll focus on one example:    f(x)=x^2:    (-2,f(-2)) and (0,f(0)) 4)

Find the average rate of change of f(x) = x^2 from x = -2 to x = 0:
           f(0) - f(-2)           (0)^2 - (-2)^2)         0-4
arc = ------------------ = ----------------------  = ---------- = -2 (answer)
              0-(-2)                         2                    2

1. f(x)=1/2x-3     f(x)=1/2x-3

  f(0)=1/2(0)-3   f(6)=1/2(6)-3

  f(0)=-3             f(6)=0

m=f(b) - f(a)/b - a = 0- (-3)/6 - 0  = 3/6 = 1/2

2.  f(x) = -x         f(x) = -x

    f(-4) = -(-4)    f(2) = -2

    f(-4) = 4         f(2) = -2

m=f(b) - f(a)/b - a = -2 - 4/2 - (-4) = -6/6 = -1

3. f(x) = x^2     f(x) = x^2

   f(-2) = -2^2  f(0) = 0^2

   f(-2) = -4      f(0) = 0

m=f(b) - f(a)/b - a = 0 - (-2)/0 - (-2) = 2/2 = 1

4. f(x) = x^3     f(x) = x^3

   f(-1) = -1^3  f(1) = 1^3

   f(-1) = -1      f(1) = 1

m=f(b) - f(a)/b - a = 1 - (-1)/1 - (-1) = 2/2 = 1

5. f(x) = 2^x    f(x) = 2^x

   f(0) = 2^0    f(4) = 2^4

   f(0) = 1        f(4) = 16

m=f(b) -f(a)/b - a = 4 - 0/ 4 - 0 = 4/4 = 1

i hope this is right, have a good day

12x−3y=, when x=−1/4 and y=3

Answers

Substitute -1/4 for x  in   12x-3y, and 3 for y:  12(-1/4) - 3(3)  = -3-9 = -12
(answer)
12x-3y
12(-1/4)-3(3)
-3-9
-12

which is the solution set of the compound inequality 3.5x - 10 > -3 and 8x - 9 < 39

Answers

Hello! So, for the first inequality, we have to add 10 to both sides. When you do that, 3.5x > 7. Then, you have to divide both sides by 3.5. When you do that, you get x > 2. Then, for the second inequality, you have to add 9 to both sides, then you would get 8x < 48. Divide both sides by 8 and you get x < 6. The compound inequality for this question would be 2 < x < 6.

If 9:7 is the ratio, there are here 116 more boys than girls how many total students are there

Answers

now, let's say there are "b" boys and "g" gals... ok... well, we know there are 116 more boys than gals..... so, if there are "g" gals then there must be "g + 116" boys.

[tex]\bf \cfrac{boys}{girls}\qquad 9:7\qquad \cfrac{9}{7}\implies \cfrac{9}{7}=\cfrac{\stackrel{boys}{g+116}}{\stackrel{girls}{g}}\implies 9g=7g+812 \\\\\\ 2g=812\implies g=\cfrac{812}{2}\implies g=\stackrel{girls}{406}[/tex]

what's the total class?  well is g + b or g + ( g + 116).

Janet earns $300 per week plus a commission of 10% on all sales that she makes. Write a formula for E, Janet's weekly earnings, in term of s, her sales for the week. Then solve your firmula for s

Answers

10/100= 0.1
0.1 x 300

E= 0.1(s) (300)
E = 300 + 0.1s
s being the sales that she makes
s = (E - 300) / 0.1

find the discriminant & describe the nature of the roots 2x2=3x+5

Answers

[tex]\bf 2x^2=3x+5\implies 2x^2-3x-5=0 \\\\\\ \begin{array}{llccll} &{{ 2}}x^2&{{ -3}}x&{{ -5}}&=0\\ &\uparrow &\uparrow &\uparrow \\ &a&b&c \end{array} \\\\\\ discriminant\implies b^2-4ac= \begin{cases} 0&\textit{one solution}\\ positive&\textit{two solutions}\\ negative&\textit{no solution} \end{cases}\\\\ -------------------------------\\\\ (-3)^2-4(2)(-5)[/tex]

the ratio of the sides of two squares is 3:1. what is the ratio of their perimeters?

Answers

Final answer:

The ratio of the perimeters of two squares with a side ratio of 3:1 is 3:1.

Explanation:

The ratio of the sides of two squares is 3:1. To find the ratio of their perimeters, we need to compare the lengths of their sides. Let's assume the length of the larger square is 3x and the length of the smaller square is x. The perimeter of the larger square is 4 times the length of its side, so it is 4 × 3x = 12x. The perimeter of the smaller square is 4 times the length of its side, so it is 4 × x = 4x. Therefore, the ratio of their perimeters is 12x:4x. Simplifying this ratio gives us 3:1.

Given:

A = O, WA = NO, AS = OT.


SSS

SAS

ASA

AAS

Answers

i think it would be sss hope it helps!!

The price of an item selling at 150% of its $63 value is

Answers

I'm pretty sure what you should do in this situation is multiply 63 by 150% (63x1.5) which would give you 94.5. The reasoning is, if you know some math terms, you would know that if a world problem has the word of in between two numbers or something (in this case $63 and 150%), it means multiply them.
:D

Answer:

94.50

Step-by-step explanation:

i used a calculator

You have a 5" by 7" photo that you would like to have enlarged to fit an 8" by 10" frame. Would the two photographs be similar? Explain

Answers

5/8 = 0.625

7/10 = 0.7

 the 2 ratios are different so it would not be similar

Sent a picture of the solution to the problem (s).

A random sample is drawn from a population with mean μ = 66 and standard deviation σ = 5.5. use table 1.
a. is the sampling distribution of the sample mean with n = 16 and n = 36 normally distributed? yes, both the sample means will have a normal distribution. no, both the sample means will not have a normal distribution. no, only the sample mean with n = 16 will have a normal distribution. no, only the sample mean with n = 36 will have a normal distribution.
b. can you use the standard normal distribution to calculate the probability that the sample mean falls between 66 and 68 for both sample sizes? yes, for both the sample sizes, standard normal distribution could be used. no, for both the sample sizes, standard normal distribution could not be used. no, only for the sample size with n = 16, standard normal distribution could be used. no, only for the sample size with n = 36, standard normal distribution could be used.
c. calculate the probability that the sample mean falls between 66 and 68 for n = 36. (round intermediate calculations to 4 decimal places, "z" value to 2 decimal places, and final answer to 4 decimal places.)

Answers

Final answer:

The sampling distributions of both sample sizes are normally distributed due to the Central Limit Theorem. The standard normal distribution can be used to calculate the probability for both sample sizes. The probability that the sample mean falls in a particular range for a given sample size can be found by calculating the z-scores for that range and looking at the area under the standard normal curve.

Explanation:

The subject of this question relates to the concepts of sampling distribution, normal distribution, and probability in the field of statistics. To answer this:

a. The sampling distribution of the sample means for both n = 16 and n = 36 will be normally distributed. According to the Central Limit Theorem, if the sample size is large enough (generally n > 30), the sampling distribution of the mean tends to be normal regardless of the shape of the population distribution.

b. Yes, a standard normal distribution could be used for both sample sizes to calculate the probability that the sample mean falls between 66 and 68. Since we are dealing with standard normal distribution, we first need to convert the samples into z-scores.

c. To calculate the probability for n = 36, we need to calculate the z-score for both 66 and 68 using the formula z = (X - μ) / (σ / sqrt(n)), where X is the sample mean, μ is the population mean, σ is the standard deviation, and n is the sample size. The probability that the sample mean falls between 66 and 68 for n = 36 is then simply the area under the standard normal curve bounded by these two z-scores.

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When certain kinds of chemicals are combined, the rate at which the new compound is formed is modeled by the autonomous differential equation dX/dt = k(a-X)(B-X) where k > 0 is a constant of proportionality and B > a > 0. Here X(t) denotes the number of grams of the new compound formed in time t. (a) Use a phase portrait of the differential equation to predict the behavior of X(t) as t -> infinity. (b) Consider the case when a = B. Use a phase portrait of the differential equation to predict the behavior of X(t) as t -> infinity when X(0) < a. When X(0) > a. (c) Verify that an explicit solution of the DE in the case when k=1 and a=B is X(t)=a-1/(t+c). Find a solution that satisfies X(0) = a/2. Then find a solution that satisfies X(0)=2a. Graph these two solutions. Does the behavior of the solutions as t->infinity agree with your answers to part (b)?

Answers

Final answer:

To predict the behavior of the autonomous differential equation as t -> infinity, analyze the phase portrait of the system. The behavior of X(t) as t approaches infinity depends on the initial conditions. Verify the explicit solution of the DE when k=1 and a=B. Graph the solutions and observe their behavior as t-> infinity.

Explanation:

To predict the behavior of the autonomous differential equation dX/dt = k(a-X)(B-X) as t -> infinity, we can analyze the phase portrait of the system. The phase portrait will show the equilibrium points and the direction of the solutions as time increases. In this case, there will be two equilibrium points, one at X = a and one at X = B, assuming a < B. The behavior of X(t) as t approaches infinity depends on the initial conditions. If X(0) < a, the solution will approach X = a, and if X(0) > a, the solution will approach X = B.

To verify the explicit solution of the differential equation when k=1 and a=B, we substitute these values into the equation: X(t) = a - 1/(t+c). For the solution that satisfies X(0) = a/2, we substitute t=0 and X(0) = a/2 into the equation and solve for c. Similarly, for the solution that satisfies X(0) = 2a, we substitute t=0 and X(0) = 2a into the equation and solve for c. We can then graph these two solutions and observe that as t approaches infinity, X(t) approaches a for both solutions, which confirms our analysis from part (b).

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Ingrid collected 6 cans of food and 18 boxes of food for the food bank. Which describes the relationship between cans of food and boxes of food?

Answers

The relationship between the cans of food and boxes of food that Ingrid collected can be determined by the mathematical equations involving addition/subtraction and multiplication/division.

 For addition/subtraction:

   D = x – y

Where D is difference, x is the number of cans of food, and y is the boxes. Substituting the known values,

    D = 6 – 8 = -2

 For multiplication/division:

   R = x/y

Where R is the ratio. Substituting the known values,

   R = 6/8 = ¾ = 0.75

The relationship between the number of cans of food and boxes of food collected by Ingrid is a ratio of 1 can to 3 boxes after simplification. This means there is 1 can for every 3 boxes.

Ingrid collected 6 cans of food and 18 boxes of food for the food bank. To describe the relationship between cans of food and boxes of food, we can use a mathematical ratio.

The ratio of cans to boxes is calculated by dividing the number of cans by the number of boxes. This gives us:

6 cans : 18 boxes

To simplify this ratio, we divide both numbers by their greatest common divisor, which is 6:

6 ÷ 6 = 1

18 ÷ 6 = 3

Therefore, the simplified ratio is:

1 can : 3 boxes

This means there is 1 can of food for every 3 boxes of food. This ratio helps us understand the proportional relationship between the two quantities.

Worth 37 points answer asap
this is a college question

a farmer is given 500 ft of fencing. He will be constructing a rectangular coral to keep pigs and sheep, however he wants to keep them separate so there will be a wall of fence in the middle of the coral as well (the dividing wall will be parallel to 2 of the sides). What are the dimensions of the coral that will maximize the area, and what is the area?

Answers

hi therrre you are an awesome person


Let the width of the corral be x and the length of the whole (undivided) corral be y.  We want to maximize the area.  A = xy.
He has 500 feet of fencing, 3x of which is taken up by the shorter ends and the dividing wall of the corral, and 2y of which is taken up by the longer sides.
Then 3x+2y=500 ft.  Supposing that we choose to solve for x first:  2y=500-3x, or 
        500-3x
y = ------------
            2
                                                                          500-3x
Then the formula for the area becomes A = x[-----------]
                                                                                2

2A = 500x -3x^2.  We must differentiate both sides with respect to x:

2(dA/dx) = 500 - 6x and seet this derivative equal to zero to find the critical value(s):

0 = 500 - 6x   becomes 6x = 500, or x = 250/3, or 83 1/3 feet.  Earlier, we saw that
        500-3x
y = ------------
            2

so, to calculate y, we substitute x=83 1/3 feet into that formula:

        500-3(250/3)
y = -------------------- ft = 250/2 ft = 125 ft.

           2


The area is then A = xy, or (83 1/3 ft)(125 ft) = 10,416 2/3 square feet.

Which doubles fact would you use to find 6+7

A. 2+2=4
B. 4+4=8
C. 6+6=12
D. 8+8=16

Answers

I will choose C. as my answer because round it to the nearest one is 10 which is only 3 away from the intended answer.

The amount of cholesterol in a person's body produced by their liver and other cells is proposed to be normally distributed with mean 75% and standard deviation 0.5%. the probability that a person produces more than 76.7% of the cholesterol in their body is

Answers

Final answer:

After standardizing the given value using a Z-score, it is found that the probability of a person producing more than 76.7% of the cholesterol in their body is essentially zero.

Explanation:

The question is asking for the probability that a person produces more than 76.7% of the cholesterol in their body, given this production is normally distributed with a mean of 75% and a standard deviation of 0.5%. To calculate this, we can utilize Z-score which standardizes the deviation of a value from the mean, considering the standard deviation.

The Z-score for the value 76.7% is calculated as follows: (76.7 - 75) / 0.5 = 3.4.

Using the standard normal distribution, the probability of a Z-score being above 3.4 is extremely low, it's practically zero. Therefore, the probability that a person produces more than 76.7% of the cholesterol in their body is essentially zero.

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"15. describe the three data fragmentation strategies. give some examples of each."

Answers

1. Horizontal fragmentation – a table is separated into groups of rows rationally and each fragment (group/sunset) comprises unique rows and it is kept at different node. All rows have the same attributes and the SELECT statement yields the contents of the fragments.
2. Vertical fragmentation – the table is distributed into rational groups of attributes (columns). Each fragment covers a unique columns and is stored at a dissimilar position. The content in the fragment is attained by using the “PROJECT” statement.
3. Mixed fragmentation –This approach is the mix of horizontal and vertical strategies. In other words, each row fragment may be a blend of groups of attributes.

Kersha has two jobs. During the day she works as an office clerk, and in the evening she works as a cashier. Her office job pays her $12.00 per hour. Her cashier job pays her $8.25 per hour. In one week, Kersha worked 55 hours. She earned a total of $585.

How many hours did Kersha work in each job?

a.) Office clerk: 35 hours; cashier: 20 hours

b.) Office clerk: 31 hours; cashier: 24 hours

c.) Office clerk: 20 hours; cashier: 35 hours

d.) Office clerk: 28 hours; cashier: 27 hours

Answers

Let x =  hours worked as a clerk ($12 per hour).
Let y = hours worked as a cashier ($8.25 per hour).

She worked 55 hours, therefore
x + y = 55             (1)

She earned $585, therefore
12x + 8.25y = 585        (2)

From (1), obtain
y = 55 - x           (3)

Substitute (3) into (2).
12x + 8.25(55 - x) = 585
12x + 453.75 - 8.25x = 585
3.75x = 131.25
x = 35
y = 55 - x = 55 - 35 = 20

Answer: a)  Office clerk: 35 hours; cashier: 20 hours.

The Sugar Sweet Company will choose from two companies to transport its sugar to market. The first company charges $3157 to rent trucks plus an additional fee of $50.25 for each ton of sugar. The second company does not charge to rent trucks but charges $275.75 for each ton of sugar.

For what amount of sugar do the two companies charge the same?

What is the cost when the two companies charge the same?

Answers

Let x = the amount of sugar transported.

First company:
The cost is $3157 truck rental plus $50.25 per ton of sugar.
Total cost = 3157 + 50.25x dollars

Second company:
There is no charge for truck rental, but it costs $275.75 per ton of sugar.
The total cost is
275.75x

When the two costs are the same, then
275.75x = 3157 +50.25x
225.5x = 3157
x = 14 tons
The total cost is 275.75*14 = $3,860.50

Answer:
14 tons
$3,860.50

Both companies will charge the same $3,860.50 for 14 tons of sugar.

Calculus

Given that The Sugar Sweet Company will choose from two companies to transport its sugar to market, and the first company charges $3157 to rent trucks plus an additional fee of $50.25 for each ton of sugar, while the second company does not charge to rent trucks but charges $275.75 for each ton of sugar, to determine for what amount of sugar do the two companies charge the same, and what is the cost when the two companies charge the same, the following calculation must be made:

Company 1 =

3157 + 50.25 x 10 = 3157 + 502.5 = 3659.503157 + 50.25 x 20 = 3157 + 1005 = 41623157 + 50.25 x 15 = 3157 + 753.75 = 3910.753157 + 50.25 x 14 = 3157 + 703.50 = 3860.50

Company 2 =

275.75 x 10 = 2757.50275.75 x 20 = 5515275.75 x 15 = 4136.25275.75 x 14 = 3860.50

Therefore, both companies will charge the same $3,860.50 for 14 tons of sugar.

Learn more about calculus in https://brainly.com/question/2811530

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