Answer:
lithosphere and asthenosphere
Explanation:
Lithosphere is the part of the earth surface which is rigid and hard. It consists of whole crust and the upper mantle.It comprises of number of plates called plate tectonic.
The asthenosphere is the Earth's upper mantle's extremely viscous, mechanically fragile and ductile area. This sits below the lithosphere, some 80 to 200 km below the ground at depths. The boundary between lithosphere and asthenosphere is commonly referred to as LAB.
You are standing on a scale in an elevator. suddenly you notice your weight decreases. what do you conclude? a. the elevator is accelerating downwards. b. the elevator is accelerating upwards. c. the elevator is moving at a constant velocity upwards. d. your diet is working. e. the elevator is moving at a constant velocity downwards.
Answer:
The elevator is accelerating downwards.
Explanation:
When an elevator accelerating downward it moves together with the person inside and the weight of the person does not change, but if the person is standing on a scale the contact force between the person and the scale is reduced. The scale therefore has to push upward with less force on the person to support the person's weight. Therefore the Normal Force is smaller, so the reading on the scale becomes less than the true weight.
When you feel your weight decrease in an elevator, it means that the elevator is accelerating downwards. This is due to the equivalence principle in physics, where the downward acceleration counteracts some of gravity's pull making you feel lighter.
Explanation:If you are standing on a scale in an elevator and suddenly notice your weight decreases, you can conclude that the elevator is accelerating downwards. The weight we feel is a combination of our actual weight and the effect of the elevator's motion. The apparent reduction in weight is because the downwards acceleration of the elevator is counteracting some of the pull of gravity, causing you to feel lighter.
This is a principle of physics known as the equivalence principle, which is a key part of Einstein's theory of general relativity. When the elevator accelerates downwards, we experience a sensation of decreased weight, as the floor of the elevator 'falls' away from us at an accelerated rate.
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A BASE jumper runs off a cliff with a speed of Which of the following is closest to his speed after 0.5 seconds?
A) 10 m/s
B) 8 m/s
C) 6 m/s
D) 3 m/s
E) not given
Answer:
8m/s
Explanation:
The question is incomplete.
But if the given speed is 3m/s
t= 0.5s
From Newton's equation of motion v=u+at
U= 3m/s
V= 3+ 0.5×10 a=10m/s^2
v= 8m/s
Final answer:
The BASE jumper's speed after 0.5 seconds, with gravity approximated as 10 m/s², would be 5 m/s. This is calculated using kinematic equations in physics, which are not explicitly stated in the choices, therefore the correct answer is E) not given.
Explanation:
The subject of the question involves the principles of kinematics in physics. Given that we approximate the acceleration due to gravity (g) as 10 m/s², we can calculate the BASE jumper's speed after 0.5 seconds.
The formula to calculate the speed (v) of a falling object at a given time (t) when released from rest is v = gt. Therefore, after 0.5 seconds, the BASE jumper's speed would be v = 10 m/s² × 0.5 s = 5 m/s. None of the options A) 10 m/s, B) 8 m/s, C) 6 m/s, or D) 3 m/s exactly match this result. Hence, the correct answer is E) not given.
You know that you sound better when you sing in the shower. This has to do with the amplification of frequencies that correspond to the standing-wave resonances of the shower enclosure. A shower enclosure is created by adding glass doors and tile walls to a standard bathtub, so the enclosure has the dimensions of a standard tub, 0.75m wide and 1.5m long. Standing sound waves can be set up along either axis of the enclosure. What are the lowest two frequencies that correspond to resonances on each axis of the shower? These frequencies will be especially amplified. Assume a sound speed of 343 m/s.A) What are the lowest two frequencies that correspond to resonances on the short axis?B) What are the lowest two frequencies that correspond to resonances on the longer axis?
Answer:
Explanation:
For first overtone
Standing waves will be formed lengthwise and breadth-wise in the enclosures having dimension of .75m x 1.5 m
A ) For the formation of lowest two frequencies formed by standing waves along the breadth , fundamental note and first overtone may be considered.
For fundamental note ,
the condition is
wave length λ = 2L = 2 x 0.75 m
λ = 1.5 m
frequency n = v / λ
= 343 / 1.5
= 229 Hz approx
For first overtone
λ = L = 0.75m
frequency n = v / λ
n = 343 / 0.75
= 457 Hz approx
B)
For the formation of lowest two frequencies formed by standing waves along the length , fundamental note and first overtone may be considered.
For fundamental note ,
the condition is
wave length λ = 2L = 2 x 1.5 m
λ = 3 m
frequency n = v / λ
= 343 / 3
= 114 Hz approx
frequency n = v / λ
n = 343 / 1.5
= 229 Hz approx
A) The lowest two frequencies that correspond to resonances on the short axis for first overtone.
B) Standing waves will be formed lengthwise and breadth-wise in the enclosures having dimension of .75m x 1.5 m
"Sound"Part A )
For fundamental note ,
wave length λ = 2L = 2 x 0.75 m
λ = 1.5 m
frequency n = v / λ
frequency n = 343 / 1.5
frequency n = 229 Hz approx
For first overtone
λ = L = 0.75m
frequency n = v / λ
n = 343 / 0.75
frequency n= 457 Hz approx
Part B)
For fundamental note ,
wave length λ = 2L = 2 x 1.5 m
λ = 3 m
frequency n = v / λ
frequency n= 343 / 3
frequency n= 114 Hz approx
For first overtone
frequency n = v / λ
frequency n = 343 / 1.5
frequency n= 229 Hz approx
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Technician A says that a MAF sensor is a high-authority sensor and is responsible for determining the fuel needs of the engine based on the measured amount of air entering the engine. Technician B says that a cold wire MAF sensor uses the electronics in the sensor itself to heat a wire 20°C below the temperature of the air entering the engine. Who is right?
A) Technician A
B) Technician B
C) Both technicians
D) Neither technician
Answer:
a. Technician A
Explanation:
Technician A says that a MAF sensor is a high-authority sensor and is responsible for determining the fuel needs of the engine based on the measured amount of air entering the engine. Technician B says that a cold wire MAF sensor uses the electronics in the sensor itself to heat a wire 20°C below the temperature of the air entering the engine. Who is right
MAF wich stands for mass airflow sensor determines the mass of air flowing into the engine's air intake system. ... , the wire cools When air flows past the wire, decreasing its resistance, thereby more current flows through the circuit. When the MAf goes bad, it can not sense the amount of air intake into the engine.
The study of the transmission of light and sound in the oceans is an example of ________ oceanography.
Answer:
Physical
Explanation:
The study of the transmission of light and sound in the oceans is an example of Physical oceanography.
Physical oceanography is the analysis of physical conditions and mechanisms in the ocean, particularly ocean waters ' movements and physical characteristics. One of many sub-domains in which oceanography is divided is physical oceanography.
Final answer:
The study of light and sound in oceans relates to physical oceanography, which incorporates wave optics to explain phenomena like diffraction and apply principles to technologies like fiber optics.
Explanation:
The study of the transmission of light and sound in the oceans is an example of physical oceanography. This branch of oceanography explores the wave optics of light as it behaves in different media, specifically how light and sound waves propagate through water. One of the interesting phenomena is the diffraction of waves, which occurs when a wave encounters an obstacle or passes through an aperture and displays bending and spreading. This is not fully explained by geometric optics; instead, it illustrates the intricate nature of wave interactions that can be characterized by wave optics or physical optics. Understanding how light behaves when it exhibits wave characteristics can also lead to practical applications such as fiber optics, which involves the transmission of light down fibers of plastic or glass by employing the principle of total internal reflection.
A box of mass 45 kg slides down a ramp onto a flat surface. The box slides a distance of 4.9 m across the flat surface and then stops. The coefficient of friction between the flat surface and the box is 0.39. What was the speed of the box at the base of the ramp?
6.1 m/s
0.77 m/s
3.0 m/s
19 m/s
Answer:
6.1 m/s
Explanation:
Gradpoint
20 cubic inches of a gas with an absolute pressure of 5 psi is compressed until its pressure reaches 10 psi. What's the new volume of the gas? (Assume that there's no change in temperature.)A. 100 cubic inchesB. 10 cubic inchesC. 40 cubic inchesD. 5 cubic inches
Answer:
B. [tex]V_{f}= 10\,cubic\,inches [/tex]
Explanation:
Assuming we are dealing with a perfect gas, we should use the perfect gas equation:
[tex]PV=nRT [/tex]
With T the temperature, V the volume, P the pressure, R the perfect gas constant and n the number of mol, we are going to use the subscripts i for the initial state when the gas has 20 cubic inches of volume and absolute pressure of 5 psi, and final state when the gas reaches 10 psi, so we have two equations:
[tex]P_{i}V_{i}=n_{i}RT_{i} [/tex] (1)
[tex] P_{f}V_{f}=n_{f}RT_{f}[/tex] (2)
Assuming the temperature and the number of moles remain constant (number of moles remain constant if we don't have a leak of gas) we should equate equations (1) and (2) because [tex] T_{i}=T_{f}[/tex], [tex]n_{i}=n_{f} [/tex] and R is an universal constant:
[tex]P_{i}V_{i}= P_{f}V_{f} [/tex], solving for [tex]V_{f} [/tex]
[tex]V_{f} =\frac{P_{i}V_{i}}{P_{f}} =\frac{(5)(20)}{10} [/tex]
[tex]V_{f}= 10 cubic\,inches [/tex]
Unless otherwise posted, what is the speed limit for cars in a residential area?_
A) 20 mph
B) 25 mph
C) 30 mph
Final answer:
The typical speed limit in a residential area is 25 miles per hour, which corresponds with option B) 25 mph. Always check local signs as limits can vary. Over this limit, like driving 31 mph in a 30 mph zone, may be tolerated but it's best to strictly follow posted speeds to ensure safety and avoid penalties.
Explanation:
The speed limit for cars in a residential area, unless otherwise posted, is generally 25 miles per hour (mph). This means that option B) 25 mph is typically the correct choice for such a setting. However, it's important to always observe local traffic signs as speed limits can vary depending on specific city, county, or state regulations.
For instance, the information given states that 50 kilometers per hour is approximately 31 miles per hour, suggesting that some residential areas might have a speed limit close to this value. However, in the context of the United States, 25 mph is a common residential speed limit, which is enforced to ensure the safety of the neighborhood, including pedestrians, cyclists, and playing children.
It's also important to note that speedometers and radar measurements can vary in accuracy. Therefore, while you may not get in trouble for driving slightly over the speed limit, such as 31 mph in a 30 mph zone, it's safest to adhere strictly to posted limits to avoid traffic violations and fines.
An object will be stable if __________.
a. its center of gravity lies outside
b. its base of support its center of gravity lies over
c. its base of support
d. its center of gravity is below
e. its highest point
Answer:
option (b)
Explanation:
An object is said to be in stable equilibrium if its potential energy is minimum and the force acting on the object is zero.
When the base of an object is too broad so that the vertical line passing through its centre of gravity line passes though this base, it is said to be in stable equilibrium. \
Thus, option (b) is correct.
Final answer:
An object will be stable when its center of gravity lies over c. its base of support.
Explanation:
An object will be stable if its center of gravity lies over its base of support, which corresponds to option (b). Considering a person standing with feet narrowly-separated, they would be in a stable equilibrium to sideway displacements, as their center of gravity is above the base of support. However, even small displacements can make them unstable if it takes their center of gravity outside the base.
Therefore, enhanced stability can be achieved by lowering the center of gravity or expanding the base by spreading the feet farther apart. Furthermore, using a support device such as a cane increases stability by broadening the base of support. These principles are crucial in understanding why, for instance, children learning to walk experience more instability due to their higher center of gravity positioned between their shoulders.
Torque can cause the angular momentum vector to rotate in UCM. This motion is called ___________.
Torque can cause the angular momentum vector to rotate in UCM. This motion is called _Conservation of Angular momentum__________.
Answer:
Conservation of Angular momentum
Explanation:
The motion of an object in a circular path at constant speed is known as uniform circular motion (UCM). An object in UCM is constantly changing direction, and since velocity is a vector and has direction, you could say that an object undergoing UCM has a constantly changing velocity, even if its speed remains constant.
The law of conservation of angular momentum states that when no external torque acts on an object, no change of angular momentum will occur.
Key Points
When an object is spinning in a closed system and no external torques are applied to it, it will have no change in angular momentum.
The conservation of angular momentum explains the angular acceleration of an ice skater as she brings her arms and legs close to the vertical axis of rotation.
If the net torque is zero, then angular momentum is constant or conserved.
Angular Momentum
The conserved quantity we are investigating is called angular momentum. The symbol for angular momentum is the letter L. Just as linear momentum is conserved when there is no net external forces, angular momentum is constant or conserved when the net torque is zero. We can see this by considering Newton’s 2nd law for rotational motion:
τ→=dL→dt, where
τ is the torque. For the situation in which the net torque is zero,
dL→dt=0.
If the change in angular momentum ΔL is zero, then the angular momentum is constant; therefore,
⇒
L =constant
L=constant (when net τ=0).
This is an expression for the law of conservation of angular momentum.
Example and Implications
An example of conservation of angular momentum is seen in an ice skater executing a spin, The net torque on her is very close to zero,
because (1) there is relatively little friction between her skates and the ice, and (2) the friction is exerted very close to the pivot point.
Conservation of angular momentum is one of the key conservation laws in physics, along with the conservation laws for energy and (linear) momentum. These laws are applicable even in microscopic domains where quantum mechanics governs; they exist due to inherent symmetries present in nature.
Precession is the rotation of the angular momentum vector in uniform circular motion (UCM) caused by torque. Torque's direction aligns with the direction of the angular momentum it produces. Any alteration in angular momentum is influenced by the average torque and the time period of its exertion, adhering to the conservation laws of angular momentum.
Explanation:The motion caused by torque making the angular momentum vector to rotate in UCM is called precession. In other words, precession is the circular motion of the pole of the axis of a spinning object around another axis due to torque. This is similar to how a spinning top wobbles as it continues to spin.
For example, if we consider a merry-go-round, torque is perpendicular to the plane formed by radius and force. This direction aligns with the direction your right thumb would point to if you curled your fingers in the direction of the force. This shows that the direction of the torque is the same as that of the angular momentum it produces.
It's important to note that angular momentum, like energy and linear momentum, is conserved when the net external torque is zero. This is a universally applicable law underlying unity in physical laws. The change in angular momentum is given by the product of average torque and the time interval during which the torque is exerted, embodying the conservation laws of angular momentum.
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Rotor windings in wound rotor motors are connected to ? on the shaft of the motor. Brushes allow those windings to be connected to external resistors to control the speed of the motor.
Answer:
Slip Rings
Explanation:
The wound rotor motor has a three-phase winding with each one connected to seperate slip rings. These slip rings contain brushes which form a secondary circuit where resistance can be inserted and this will allow for the rotor current to run more in phase with the stator current which will result in increased torque that is created
Josh manages security at a power plant. The facility is sensitive, and security is very important. He would like to incorporate two-factor authentications with physical security. Which of the options below is the best way to meet this requirement?
Under some circumstances, a star can collapse into an extremely dense object made mostly of neutrons and called a neutron star. The density of a neutron star is roughly 1014 times as great as that of ordinary solid matter. Suppose we represent the star as a uniform, solid, rigid sphere, both before and after the collapse. The star's initial radius was 8.0×105 km (comparable to our sun); its final radius is 16 km. the original star rotated once in 35 days, find the angular speed of the neutron star.
Answer:
The angular speed wf of the neutron star is calculated to be [tex]5.19*10^{3} [/tex] rad/s
Explanation:
The reason for such a rapid spin-rate is due to the principle of angular momentum. The angular momentum of a system can be given as:
Angular Momentum (L) = Mass * Radius^2 * Angular Velocity (w)
Applying this principle to our context, we would say that the angular momentum of the star before and after collapsing is constant. In order to not break this principle, we know that the mass of the star did not change but the radius shrank by a significant amount after collapsing, and so in order to keep the angular momentum (L) constant after collapse, the star had to increase it's angular velocity, which is evident in our answer.
The calculations of the answer are as follows:
Star's Initial Radius Ri = [tex]8.0 * 10^{5}[/tex] km ( [tex]8.0 * 10^{8}[/tex] m)
Star's Initial Angular Velocity wi = [tex]\frac{2\pi} {35 days * 24 hrs * 3600 sec}[/tex] = [tex]2.077 * 10^{-6}[/tex] rad/sec
Star's final radius Rf = [tex]16 * 10^{3}[/tex] m
Now, we can equate the initial and final states of the star i.e. the angular momentum of star before and after the collapse as following:
Li = Lf (where i and f denote initial and final state)
Solving of Final Angular Velocity we have:
wf = wi * (Ri / Rf) ^ 2
Plugging in our known values:
wf = [tex]2.077 * 10^{-6}[/tex] x [tex](\frac{8 * 10^{8}}{16 * 10^{3}} )^{2}[/tex] = 5.19 * 10^3 rad/s
Final answer:
The neutron star's angular speed is found by using the conservation of angular momentum. With the star's initial rotation period of 35 days, the initial angular speed is calculated and then adjusted for the changes in the radius of the star upon collapse. The resulting angular speed of the neutron star is approximately 6.57 x 10³ radians/second.
Explanation:
When a star collapses into a neutron star, its angular momentum is conserved. To calculate the neutron star's angular velocity, we use conservation of angular momentum. The original star rotated once every 35 days, and we can convert this period into angular speed, \, using the formula \ = [tex](2\pi)[/tex] / T, where T is the period of rotation in seconds.
Firstly, convert the days into seconds: 35 days × 24 hours/day × 3600 seconds/hour = 3,024,000 seconds. Now, calculate the initial angular speed: \initial = [tex](2\pi)[/tex] / 3,024,000 = 2.08 x 10⁻⁶ radians/second.
Since angular momentum L = I\ must be conserved (where I is the moment of inertia and \ is the angular velocity), and I = (2/5)mR² for a sphere, where m is mass and R is the radius, the relation can be expressed as I-initial\initial = I-final\final. Mass m cancels out and assuming the radius R changes from 8.0 x 10⁵ km to 16 km, we can solve for \final.
The final angular velocity \final = (Rinitial2 / Rfinal2) \initial = ((8.0 x 10⁵ km)² / (16 km)²) (2.08 x 10⁻⁶ radians/second) = (6.4 x 10¹¹ / 256) (2.08 x 10⁻⁶ radians/second) = 6.57 x 10³ radians/second.
Therefore, the angular speed of the neutron star is approximately 6.57 x 10³ radians/second, significantly faster than its predecessor due to the drastic reduction in radius.
A car traveling at 7.3 m/s accelerates at the rate of 0.82 m/s2 for an interval of 7.4 s. Find vf.
Explanation:
We have equation of motion v = u + at
Initial velocity, u = 7.3 m/s
Final velocity, v = ?
Time, t = 7.4 s
Acceleration,a = 0.82 m/s²
Substituting
v = u + at
v = 7.3 + 0.82 x 7.4
v = 13.368 m/s
Final velocity is 13.37 m/s
A car traveling at 22 m/s comes to an abrupt halt in 0.1 second when it hits a tree. What is the deceleration in meters per second per second (i.e. m/s/s or m/s2)?
Answer:
220 m/s²
Explanation:
given,
initial speed of car= 22 m/s
final speed of car= 0 m/s
time taken by car to stop= 0.1 s
acceleration of car is equal to change in velocity per unit time
[tex]a = \dfrac{\Delta v}{t}[/tex]
[tex]a = \dfrac{v_f-v_i}{t}[/tex]
[tex]a = \dfrac{0-22}{0.1}[/tex]
a = -220 m/s²
negative sign represent deceleration of the body
hence, deceleration of car is equal to a = 220 m/s²
To avoid compromising your car's aerodynamic properties, you should avoid ________.A. running your air conditioning system B. taking turns at high speeds C. carrying large loads on the outside of the vehicle
Answer:
C) True carrying large loads on the outside of the vehicle
Explanation:
The aerodynamic property of an object depends on its outer shape. In general, objects should be thin in the front and not completely flat in the back, to avoid the eddies that create a great Arrate, losing all the aerodynamics of the system.
With this we can review the final statements
A) False The air conditioner is used with the glasses raised, so the exterior shape of the car does not change and its aerodynamics remains unchanged.
B) Phallus. This does not change the outer shape, I get a small inclination,
C) True. External loads dramatically change the external shape of the vehicle significantly reducing its aerodynamic characteristics.
To avoid compromising your car's aerodynamic properties, avoid carrying large loads on the outside of the vehicle and taking turns at high speeds.
Explanation:To avoid compromising your car's aerodynamic properties, you should avoid carrying large loads on the outside of the vehicle. Large loads increase drag and disrupt the flow of air around the car, negatively affecting its aerodynamics. It is also advisable to avoid taking turns at high speeds as it can create instability and affect the car's balance. Running the air conditioning system does not directly impact the aerodynamic properties of the car, so it is not necessary to avoid running your air conditioning system.
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If an apprentice makes 55% of Journeyman wages, what would an apprentice make per hour if the Journeyman scale is $17.64?
Answer:
$9.702 per hour
Explanation:
The apprentice earns 55% of what the journeyman earns on a hourly scale.
Amount the apprentice makes per hour = 55% of $17.64
= (55/100) *17.64
= 0.55 *17.64
= $9.702
The apprentice would make $9.70 per hour if the Journeyman scale is $17.64, as 55% of $17.64 is $9.70.
Explanation:Given:
Journeyman scale = $17.64/hour
Apprentice wages = 55% of Journeyman wages
Calculation:
Apprentice wages = 0.55 * $17.64
Apprentice wages = $9.702
Therefore, an apprentice would make $9.70 per hour.
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Suppose you are driving due east, traveling a distance of 1500 min 2 minutes. You then turn due north and travel the same distance in the same time. What can be said about the average speeds and the average velocities for the two segments of the trip?
(a) The average speeds are the same, and the average velocities are the same.
(b) The average speeds are the same, but the average velocities are different.
(c) The average speeds are different, but the average velocities are the same.
Answer:
(b) The average speeds are the same, but the average velocities are different.
Explanation:
The average speed is a scalar quantity which is calculated on the total distance travelled. Distance is the length of path traced and the speed is calculated as distance per unit time.
Mathematically:
[tex]v=\frac{d}{t}[/tex]
[tex]v=\frac{(1500+1500)}{2\times 60}\ m.s^{-1}[/tex]
While the velocity is a vector quantity calculated on the displacement and is defined as the rate of displacement.
Mathematically:
[tex]\vec v=\frac{\vec s}{t}[/tex]
[tex]\vec v=\frac{\sqrt{1500^2+1500^2} }{2\times 60}\ m.s^{-1}[/tex]
A 1000-N boulder on the right end of a seesaw is raised when the left end of the seesaw is pushed downward. If both ends of the seesaw are equal distances from the fulcrum, then to raise the boulder, the left end should be pushed downward with a minimum force of
a. 500 N
b. 750 N.
c. more than 1000 N.
d. 1000 N.
Answer:
d. 1000 N.
Explanation:
For the seesaw to be in equilibrium the moment on left of the fulcrum and the moment to the right of the fulcrum must be equal.
Let L be the distance on either side of fulcrum at which the boulder is kept
F be the minimum force used to pushdown the left end
According to principle
L×1000= L×F
F= 1000 N
Hence option D is correct
When the termination is a terminal block, care must be taken to ensure a good electrical connection without damaging the conductor. Terminals should not be used for more than ? conductor(s), unless they are identified for such use
a) one
b) two
c) three
Answer:
When the termination is a terminal block, care must be taken to ensure a good electrical connection without damaging the conductor. Terminals should not be used for more than one
Explanation:
The Terminal block being a modular block, having insulated frame, which can secure more than two wires in it. It has a conducting strip in it. These terminal clocks helps in making the connection safer as well as organised. These terminal blocks are used for power distribution in safer way. Its potential is it can distribute power from single to multiple output. The conductor is used for making it proper contact.
A simple pendulum with a length of 2.23 m and a mass of 6.74 kg is given an initial speed of 2.06 m/s at its equi- librium position. Assume it undergoes simple harmonic motion. Determine (a) its period, (b) its total energy, and (c) its maximum angular displacement.
Answer:
a) T = 2.997 s
b) K = 14.3 J
c) φ = 0.444 rad
Explanation:
a) Determine its period
The pendulum simple’s period is:
T = 2π[tex]\sqrt{\frac{l}{g} }[/tex]
Where l: Pendulum’s length
g = 9.8 m/s2
T = 2π[tex]\sqrt{\frac{2.23}{9.8} }[/tex]
T = 2.997 s
b) Total energy
Initially his total energy is kinetic
K = [tex]\frac{mv^{2} }{2}[/tex]
K = [tex]\frac{(6.74)(2.06)^{2} }{2}[/tex]
K = 14.3 J
c) Maximum angular displacement
φ = [tex]cos^{-1}(1-\frac{E}{mgl} )[/tex]
φ = [tex]cos^{-1}(1-\frac{14.3}{(6.74)(9.8)(2.23)} )[/tex]
φ = 0.444 rad
Final answer:
The period of the pendulum is 4.46 seconds. The total energy of the pendulum is 14.58 Joules. The maximum angular displacement of the pendulum is 26.86 degrees.
Explanation:
To determine the period of the pendulum, we can use the formula:
T = 2π√(L/g)
where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity. Plugging in the values given, we get:
T = 2π√(2.23/9.8) = 4.46 seconds
The total energy of the pendulum is given by the formula:
E = mgh + (1/2)mv²
where E is the total energy, m is the mass, g is the acceleration due to gravity, h is the height, and v is the velocity. Since the pendulum is at its equilibrium position, the height is zero, so we only need to calculate the kinetic energy:
E = (1/2)mv² = (1/2)(6.74)(2.06)² = 14.58 Joules
The maximum angular displacement of the pendulum can be found using the formula:
θ = sin⁻¹(A/L)
where θ is the angular displacement, A is the amplitude, and L is the length of the pendulum. Plugging in the values given, we get:
θ = sin⁻¹(1/2.23) = 26.86 degrees
There is one type of intermolecular force that can be found in all molecules and atoms. Which force is it?
Answer: London dispersion forces (i.e LDF), also known loosely Van dear Waals forces.
Explanation: The London dispersion forces is named after the German - American physicist called Fritz London.
The London dispersion forces describes the interaction between two atoms A and B after London discovered the "quantum mechanical theory".
London dispersion theory is similar to the quantum mechanical theory of "light dispersion", that is why it is called "dispersion effect". In Physics,dispersion can be explained as the variation of a quantity with frequency, which is the fluctuation of the electrons in the case of the London dispersion.
The intermolecular force found in all molecules and atoms is the London dispersion force, which occurs due to temporary fluctuations in electron distribution resulting in temporary dipoles and weak attractive forces.
Explanation:The intermolecular force that can be found in all molecules and atoms is the London dispersion force. This force occurs due to temporary fluctuations in electron distribution, which can create temporary dipoles. These temporary dipoles can induce neighboring molecules or atoms to have temporary dipoles as well, leading to a weak attractive force.
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The instructions for a 13-foot ladder state that the bottom of the ladder must be set at least 5 feet from a building. How high can the ladder safely reach on the garage?
Answer:
The height at which the ladder safely reach on the garage is 12 meters.
Explanation:
It is given that,
Height of the ladder, H = 13 foot
Bottom of the ladder, B = 5 feet
To find,
How high can the ladder safely reach on the garage?
Solution,
The ladder and the wall follows the Pythagoras theorem. 13 foot is the height of the ladder. Distance between wall and the ladder is 5 feet. Let L is the height at which the ladder safely reach on the garage. On using Pythagoras theorem we get :
[tex]H^2=B^2+L^2[/tex]
[tex]L^2=H^2-B^2[/tex]
[tex]L^2=13^2-5^2[/tex]
L = 12 m
So, the height at which the ladder safely reach on the garage is 12 meters. Hence, this is the required solution.
How far will it go, given that the coefficient of kinetic friction is 0.10 and the push imparts an initial speed of 3.9 m/s ?
The question is asking for the distance an object will travel given its initial speed and a coefficient of friction. However, without knowing the object's mass, we cannot calculate the exact distance.
Explanation:The question is asking you to calculate the distance an object will travel, given an initial speed and friction. This is a physics problem that can be solved using the principles of friction and kinetic energy.
Since we know the coefficient of kinetic friction (μk) and initial speed (v), we can calculate the distance travelled. The frictional force is equal to μk * m * g, where m is the mass of the object and g is the gravity. However, we do not have the mass of the object.
As we have incomplete information provided in the question, we cannot calculate the exact distance travelled. The chapter references given also do not give us the necessary information to solve the problem. With full information, we would use the formula relating kinetic energy to work done by friction to find the distance:
1/2 * m * v² = μk * m * g * d, which simplifies to d = v² / (2 * g * μk)
Learn more about Kinetic Friction here:https://brainly.com/question/36370309
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During an investigation, a scientist heated 123.6 g of copper carbonate till it decomposed to form a black residue. The total mass of the black residue formed was 79.6 g. Does the law of conservation of mass hold true in this case? Use complete sentences to justify your answer based on numerical calculations
Answer:
See below explanation
Explanation:
The correspondent chemical reaction for copper carbonate decomposed by heat is:
CuCO₃ (s) → CuO (s) + CO₂ (g)
Considering all molar mass (MM) for each element ( we consider rounded numbers) :
MM CuCO₃ = 123 g/mol
MM CuO = 79 g/mol
MM CO₂ = 44 g/mol
Statement mentions that scientis heated 123.6 g of CuCO₃ (almost a MM), until a black residue is obtained, which weights 79.6 g : this solid residue is formed by CuO, and the remaining mass (approximatelly 44 g) belongs to teh second product, this is, CO₂; as it is a gas compund, it is not certainly included on the solid residue.
So, law of conservation mass is true for this case, since: 123.6 g = 79.6 g + 44 g. As explained, on the solid residue, we don not include the 44 g, which "escaped" from our system, since it is a gas compound (CO₂)
Two cars are traveling along perpendicular roads, car A at 40 mi/hr, car B at 60 mi/hr. At noon, when car A reaches the intersection, car B is 90 mi away, and moving toward it. At 1 p.m. the distance between the cars is changing, in miles per hour, at the rate of:
Answer:
[tex]\frac{dD}{dt} = -4 miles/hour[/tex]
negative sign indicates that the distance is decreasing with time
Explanation:
Let at any time t after noon that is 12 p.m.
distance traveled by car A = 40t
distance traveled by car B = 90-60t
then distance between the two cars at time t
[tex]D^2= (40t)^2+(90-60t)^2[/tex]............1
also, at time 1 p.m.
distance [tex]D^2= (40\times1)^2+(90-60\times1)^2[/tex]
D=50 Km
differentiating equation 1 w.r.t. t we get
[tex]2D\frac{dD}{dt}= 2\times40t\times40+2(90-60t)(-60)[/tex]
put t= 1 and D= 50 we get
[tex]2\times50\frac{dD}{dt}= 3200\times1-3600\times1[/tex]
[tex]\frac{dD}{dt} = -4 miles/hour[/tex]
Warm-water hydrothermal vents form: a. turbidity currents.b. cold seeps. c. white smokers. d. black smokers. e. abyssal hills.
Answer:
d) Black smokers
Explanation:
Hydrothermal vents form at locations where seawater meets magma.
A venting black smoker emits jets of particle-laden fluids. The particles are predominantly very fine-grained sulfide minerals formed when the hot hydrothermal fluids mix with near-freezing seawater. These minerals solidify as they cool, forming chimney-like structures. “Black smokers” are chimneys formed from deposits of iron sulfide, which is black. “White smokers” are chimneys formed from deposits of barium, calcium, and silicon, which are white.
Because deposits from hydrothermal vent fluid can contain iron, manganese, copper, zinc, and other minerals, vents have relevance to certain types of ore deposits.
The correct answer is (d) black smokers
At the bottom of the hill, the roller coaster is moving at 34.2929 m/s. If the mass of the cart is 1125.00 kg, how much kinetic energy does it have?
Answer:
661748 J
Explanation:
kinetic energy =(1/2) (mass ) (SPEED)^2
= (0.5) ( 1125.00)( 34.2929)^2
= 661748 J UP TO 6 SIGNIFICANT FIGURES
A 24 year old motorcycle driver would not be required to wear protective eyewear when riding in Florida.
A) True
B) False
Answer:
False
Explanation:
A 24 year old motorcycle driver would not be required to wear protective eyewear when riding in Florida,This is a False statement.
The law is all riders would have to wear protective eyewear when riding in Florida.
A hot-air balloon is 11.0 m above the ground and rising at a speed of 7.00 m/s. A ball is thrown horizontally from the balloon basket at a speed of 9.00 m/s. Ignore friction and air resistance and find the speed of the ball when it strikes the ground.
Answer:
18.6 m/s
Explanation:
[tex]h[/tex] = Initial height of the balloon = 11 m
[tex]v_{o}[/tex] = initial speed of the ball
[tex]v_{oy}[/tex] = initial vertical speed of the ball = 7 m/s
[tex]v_{ox}[/tex] = initial horizontal speed of the ball = 9 m/s
initial speed of the ball is given as
[tex]v_{o} = \sqrt{v_{ox}^{2} + v_{oy}^{2}} = \sqrt{9^{2} + 7^{2}} = 11.4 m/s[/tex]
[tex]v_{f}[/tex] = final speed of the ball as it strikes the ground
[tex]m[/tex] = mass of the ball
Using conservation of energy
Final kinetic energy before striking the ground = Initial potential energy + Initial kinetic energy
[tex](0.5) m v_{f}^{2} = (0.5) m v_{o}^{2} + mgh \\(0.5) v_{f}^{2} = (0.5) v_{o}^{2} + gh\\(0.5) v_{f}^{2} = (0.5) (11.4)^{2} + (9.8)(11)\\(0.5) v_{f}^{2} = 172.78\\v_{f} = 18.6 m/s[/tex]
Answer:
0.95 second
Explanation:
height, h = 11 m
ux = 9 m/s
uy = 7 m/s
Let it takes time t to strike the ground.
Use second equation of motion
[tex]h = u_{y}t + 0.5 gt^{2}[/tex]
- 11 = 7 t - 0.5 x 9.8 t²
-11 = 7t - 4.9t²
4.9t² - 7t - 11 = 0
[tex]t=\frac{-7\pm \sqrt{49+4\times4.9\times11}}{9.8}[/tex]
[tex]t=\frac{-7\pm 16.27}{9.8}[/tex]
take positive sign
t = 0.95 second
Thus, the time taken to reach the ground is 0.95 second.