Answer:
Technician B
Explanation:
Car engine compression refers to when air and gas are mixed together in the cylinders of an engine. This process is required for the car to move and function. If there are any problems with the compression process, then you can expect to experience all kinds of car problems.
It will be easy to tell when you have a low compression problem because you may experience a misfire when you try to start the engine. Either that or the engine will offer poor performance as you’re driving the vehicle down the road. The worst-case scenario would be the car not starting if all the cylinders have no compression.
Generally speaking, if you have low compression in one(single) cylinder, the engine will start but you’ll likely experience misfires and your vehicle will run rough. If you experience no compression in ALL cylinders, your engine simply won’t start. This rule out A statement.
An engine tune-up is a exercise for engines to undergo regularly. It is a way of making a car's work at the level and standard intended by the car manufacturer when the car was first made. All manufacturers will stipulate a schedule of when a car will required an engine tune-up to ensure that a car runs at it's most efficient
Engine tune-up are imperative to ensure that all the power and efficiency that your car is capable are being reached . This bring the answer to the question to Tech B.
Electrically charged sunspot gases which escape the sun's chromosphere and enter the earth's atmosphere near the magnetic north pole cause the _______.
Answer:
Northern Lights ( Aurora Borealis)
Explanation:
When the electricaly charged sunspot gases (they are named a solar wind) escape the sun's chromosphere and penetrates from the earth magnetic sheild which is called earth's magnetosphere then upon there interaction with atoms and molecules of our atmosphere there are little bursts of photons in the form of light which made up these northern lights.
A mass m is oscillating with amplitude A at the end of a vertical spring of spring constant k. The mass is increased by a factor of four.1. What is true about the period? (period does what factor)2. The mass is increased by a factor of four, keeping A and k constant. What is true about the total mechanical energy?3. The mass is increased by a factor of four, keeping A and k constant. What is true about the maximum speed?4. The amplitude is doubled, keeping mass and k constant. What is true about the period?5. The amplitude is doubled, keeping mass and k constant. What is true about the total mechanical energy? Choose the best answer.6. The amplitude is doubled, keeping mass and k constant. What is true about the maximum speed?
Answer:
1. The period doubles
2. The mechanical energy is unchanged
3. The speed is halved
4. The period is unchanged
5. The energy is quadrupled
6. The maximum is speed doubled
Explanation:
1. From Hooke's law we have [tex]T\propto\sqrt{\frac{m}{k} }[/tex]
where T is period, m is mass and k is the spring constant
So If the mass is increased by a factor of 4 then period doubles while k constant
2 According to law of conservation of energy, the energy remains unchanged so therefore the total mechanical energy remain unchanged.
3. From the [tex]w = \sqrt{\frac{k}{m} }[/tex]
where m is mass and w is speed
so we see that mass and speed is inversely proportional therefore if we increase mass speed decreases.
4. The period is independent of amplitude
5. [tex]E=A^{2} [/tex]
where E is energy and A is amplitude
So if the amplitude is doubled the energy is quadrupled.
6. we have the relation
[tex]v_{max}=A [/tex]
where [tex]v_{max}[/tex] is maximum speed and A is amplitude
From the formular we can see they are directly proportional, so if we double amplitude then [tex]v_{max}[/tex] doubles also.
The period would double when the mass of the spring is increased by a factor of four (4).
How to calculate the period.Since all springs obey Hooke’s law, the period is given by this formula:
[tex]T\alpha \sqrt{\frac{m}{k}}\\\\T = 2\pi \sqrt{\frac{m}{k} }[/tex]
Where:
k is the spring constant.m is the mass.We can deduce that, the period is directly proportional to mass of the spring. Thus, the period would double when the mass of the spring is increased by a factor of four (4).
In accordance with the law of conservation of energy, the total mechanical energy of the spring would remain the same because energy can neither be created nor destroyed.
How to calculate the maximum speed.The speed of a spring in simple harmonic motion is an angular speed and it is given by this formula:
[tex]\omega = \sqrt{\frac{k}{m} }[/tex]
We can deduce that, the angular speed is inversely proportional to mass of the spring. Thus, the angular speed would decrease when the mass of the spring is increased by a factor of four (4).
In simple harmonic motion, the period of a spring is independent of its amplitude.
How to calculate the total mechanical energy.Mathematically, the the total mechanical energy of a spring is given by this formula:
[tex]E=A^2[/tex]
We can deduce that, the total mechanical energy is directly proportional to the square of amplitude of the spring. Thus, the total mechanical energy would quadruple when the amplitude of the spring is doubled.
Also, the maximum speed is directly proportional to the amplitude of the spring. Thus, the maximum speed would also double when the amplitude of the spring is doubled.
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Which is a correct statement of what occurs at a turbine during electricity production?
Answer:
The turbine is rotated and rotates the generator to produce electricity.
Explanation:
Within a turbine enters the superheated steam which is at high pressure and high temperature, this steam is previously formed in the boiler when the steam enters the turbine hits each one of the blades of the turbine making it rotate at a given speed, the turbine shaft is coupled to the shaft of an electric generator and thus generates electricity.
It is also important to say that when the steam comes out of the turbine comes out at low pressure, this way the internal operating process is carried out within the turbine.
The geologic time scale originally ordered earth’s rocks by
The geologic time scale originally ordered Earth’s rocks by relative age.
Explanation:
Geologic time scale is the measure of events occurred in year wise from the starting of universe. Mostly dating of rocks and fossil fuels are doing the trends still now. In order to measure the age of rocks, geological time scale have preferred relative age mode.
In this system, the age of rocks are measured and compared layer by layer. So the lowest layer of rock will be having the maximum age. As we don’t know the starting time of universe, so this method of comparison between the layers to order the rocks is best. So, depending upon the position of the rocks, the age can be determined.
physical science!!!!!!helpppp
Answer:
Option B
10.36 m/s
Explanation:
Using the first given equation, then velocity=distance/time
Since distance is provided as 200 m and time, t is 19.3 seconds then substituting these figures yields
v=200/19.3=10.3626943
Rounding off to 2 decimal places, then
v=10.36 m/s
pulse train with a frequency of 1 MHz is counted using a modulo-1024 ripple-counter built with J-K flip flops. For proper operation of the counter, the maximum permissible propagation delay per flip flop stage is ______ n sec.
Answer:
The maximum permissible propagation delay per flip flop stage is 100 n sec
Explanation:
1024 ripple counter has 10 J-K flip flops(210 = 1024).
So the total delay will be 10×x where x is the delay of each J-K flip flops.
The period of the clock pulse is 1× 10⁻⁶ s.
Now
10x <= 10⁻⁶ s
x <= 100 ns
x= 100 ns for prpoer operation.
pulse train with a frequency of 1 MHz is counted using a modulo-1024 ripple-counter built with J-K flip flops. For proper operation of the counter, the maximum permissible propagation delay per flip flop stage is 100 n sec.
A fully loaded, slow-moving freight elevator has a cab with a total mass of 1700 kg, which is required to travel upward 45 m in 2.1 min, starting and ending at rest. The elevator's counterweight has a mass of only 840 kg, so the elevator motor must help pull the cab upward. What average power is required of the force the motor exerts on the cab via the cable?
Answer:
3,010 W
Explanation:
mass of elevator (Me) = 1700 kg
mass of counter weight (Mc) = 840 kg
travel distance (d) = 45 m
time (t) = 2.1 min = 126 s
What average power is required of the force the motor exerts on the cab via the cable?
from Newtons second law of motion
force exerted by the elevator motor + force exerted by the elevator counter weight = force exerted by the elevator cab weight
therefore
force exerted by the elevator motor = force exerted by the elevator counter weight - force exerted by the elevator cab weight
force exerted by the elevator motor (Fm) = (Me x g) - (Mc x g)
force exerted by the elevator motor (Fm) = (1700 x 9.8) - (840 x 9.8)
force exerted by the elevator motor (Fm) = 8428 N
average power exerted by the motor = Fm x speed
where speed = distance / time
average power exerted by the motor = Fm x (distance / time)
average power exerted by the motor = 8428 x (45/126) = 3,010 W
Suppose a yo-yo has a center shaft that has a 0.250 cm radius and that its string is being pulled.
(a) If the string is stationary and the yo-yo accelerates away from it at a rate of 1.50 m/s2, what is the angular acceleration of the yo-yo?
(b) What is the angular velocity after 0.750 s if it starts from rest?
(c) The outside radius of the yo-yo is 3.50 cm. What is the tangential acceleration of a point on its edge? Ans:
(a) 600 rad/s2,
(b) 450 rad/s,
(c) 21.0 m/s
Answer:
600 rad/s²
450 rad/s
21 m/s²
Explanation:
r = Radius
[tex]\omega_f[/tex] = Final angular velocity
[tex]\omega_i[/tex] = Initial angular velocity
[tex]\alpha[/tex] = Angular acceleration
t = Time taken
Linear acceleration is given by
[tex]a=r\alpha\\\Rightarrow \alpha=\dfrac{a}{r}\\\Rightarrow \alpha=\dfrac{1.5}{0.25\times 10^{-2}}\\\Rightarrow \alpha=600\ rad/s^2[/tex]
Angular acceleration of the yo-yo is 600 rad/s²
[tex]\omega_f=\omega_i+\alpha t\\\Rightarrow \omega_f=0+600\times 0.75\\\Rightarrow \omega_f=450\ rad/s[/tex]
angular velocity of the yo-yo is 450 rad/s
[tex]a=r\alpha\\\Rightarrow a=3.5\times 10^{-2}\times 600\\\Rightarrow a=21\ m/s^2[/tex]
Tangential acceleration of a point on its edge is 21 m/s²
The angular acceleration, angular velocity and tangential acceleration are;
A) 600 rad/s²
B) 450 rad/s,
C) 21 m/s²
What is the angular velocity and acceleration?A) We are given;
Radius; r = 0.25 cm = 0.0025 m
Linear acceleration; a = 1.5 m/s²
Formula for Angular Acceleration is;
α = a/r
Thus; α = 1.5/0.0025
α = 600 rad/s²
B) We are given;
time; t = 0.75 s
final angular velocity is gotten from;
ω_f = ω_i + αt
ω_f = 0 + (600 * 0.75)
ω_f = 450 rad/s
C) We are given;
Radius; r = 3.5 cm = 0.035 m
Formula for tangential acceleration is;
α_t = rα
α = 0.035 * 600
α = 21 m/s²
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Approximately how far is the sun from the center of the galaxy?
Answer:
About 8 kpc
Explanation:
The milky way galaxy is the galaxy we live in. Its composed of the solar system, billion stars, gas, dust and dark matter.
At its center it contains a super massive black hole called Sagittarius. This object is millions of times as massive as the sun.
The sun is about 8 kpc to the center of the milky way galaxy, this is about 26,000 light years away.
1000 parsecs distance is approximately 3262 light years.
A light year is the distance light can travel in a period of 1 year.
One object is fired at an angle of ten degrees above the horizontal. A second object is fired at an angle of ten degrees below the horizontal, and a third is fired in an exactly horizontal direction. All three are fired at the same time, but with different (and nonzero) speeds. Neglect air resistance and assume that the objects are fired over a perfectly level plain. Which of the objects strikes the ground first?
Answer:
The fired object at an angle of ten degrees below the horizontal
Explanation:
The second object strikes the ground first because independently of the magnitude of the speeds, this object has a speed component in the direction toward the floor allows it to reach the ground faster than the other objects.
Then the answer is:
The fired object at an angle of ten degrees below the horizontal
What situation primarily involves heat transfer by convection?
Answer:
Heating of a fluid bulk from the bottom.
Explanation:
Whenever a fluid bulk is heated form the lower layers then due to the variation of the density of the fluid at different temperature we observe the movement of molecules leading to convection.
When the lowest level of the fluid is heated it gains temperature and the molecular bulk expands on heating and its density becomes low with respect to the bulk fluid around it and hence it flows upwards to the top most layer being lighter in weight and the lowest layer is occupied by the subsequent colder and denser layer.Then again the lowest layer is heated and the process continues forming a cycle heating through the bulk transfer of fluid layers called convention.The situation that primarily involves heat transfer by convection is when a fluid (liquid or gas) moves and carries heat energy along with it.
Convection is a mode of heat transfer that occurs through the movement of a fluid. It involves the transfer of heat by the actual movement or circulation of the fluid particles. Convection typically occurs in liquids and gases, where the particles can freely move.
Similarly, natural convection occurs when heated air or fluid rises due to its lower density compared to the surrounding cooler air or fluid. This can be observed, for instance, in the circulation of air near a hot stove or the movement of hot water in a boiling pot.
Convection is also prevalent in weather phenomena such as ocean currents and winds, where the movement of fluids carries heat energy from one region to another.
Overall, situations that involve the transfer of heat through the movement of fluids, whether natural or forced convection, primarily involve heat transfer by convection.
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A student was producing 75 watts of power while applying a constant force of 225 newtons to slide a box of books 2.0 meters across the floor. How long did it take the student to slide the box of books?
Answer:
time taken = 6 secs
Explanation:
Power (P) = Force(F) * displacement(d)/ TIME (t)
75= 225 * 2.0/t
t= 225*2/75
t= 6 sec
The force on a wire carrying 8.75 A is a maximum of 1.28 N when placed between the pole faces of a magnet
If the pole faces are 55.5 cm in diameter, what is the approximate strength of the magnetic field?
The force on a wire carrying [tex]8.75\ A[/tex] is a maximum of [tex]1.28\ N[/tex] when placed between the pole faces of a magnet. The strength of the magnetic field is [tex]0.207\ T[/tex].
The force (F) experienced by a current-carrying wire in a magnetic field is given by the formula:
Force (F) = Magnetic Field (B) × Current (I) × Length (L) × sin(θ)
Given data:
Force [tex](F) = 1.28\ N[/tex]
Current[tex](I) = 8.75\ A[/tex]
Length [tex](L) = 55.5\ cm[/tex]
To find the magnetic field strength (B).
Assuming the wire is placed perpendicular to the magnetic field (θ = 90°), sin(90°) = 1, and the equation simplifies to:
[tex]B = F / (I \times L)[/tex]
Convert the length from centimeters to meters (1 cm = 0.01 m):
[tex]Length (L) = 55.5\ cm \times 0.01\ m/cm \\L = 0.555\ m[/tex]
Now, plug in the values and calculate B:
[tex]B = 1.28 / (8.75 \times 0.555)[/tex]
Calculating gives approximately:
[tex]B = 0.207\ T[/tex]
Therefore, the strength of the magnetic field is 0.207 teslas.
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Final answer:
To find the strength of the magnetic field, use the formula for magnetic force on a current-carrying wire with the given values to calculate the approximate field strength. The magnetic field's approximate strength is 4.85 T.
Explanation:
The strength of the magnetic field can be calculated using the formula for magnetic force on a current-carrying wire:
B = F / (I * L * sinθ),
where B is the magnetic field strength, F is the force on the wire, I is the current, L is the length of the wire, and θ is the angle between the wire and the magnetic field.
Substitute the given values: I = 8.75 A, F = 1.28 N, L = 55.5 cm = 0.555 m, and sinθ = 1 (as the wire is perpendicular to the magnetic field).
Calculating, we find that the approximate strength of the magnetic field is around 4.85 T.
The Hubble constant, $H_{0}$, is the ratio of the recessional velocity of a galaxy to its distance. The Hubble constant is estimated to be 70 km/sec per million parsecs of distance. (One parsec is equal to 3.26 light years.) Based on this ratio, how many billions of light years away would a galaxy be if it had a recessional velocity of 300,000 km/sec?
Answer:
14 billion light years away
Explanation:
v = Recessional velocity = 70km/s/million parsec
D = Proper distance
Hubble constant
[tex]70\ km/s=3260000\ ly\\\Rightarrow 1\ km/s=\dfrac{3260000}{70}\ ly[/tex]
From Hubble's law we have the relation
[tex]v=H_0D\\\Rightarrow D=\dfrac{v}{H_0}\\\Rightarrow D=\dfrac{3260000}{70}\times 300000}\\\Rightarrow D=13971428571.42857\ ly[/tex]
The distance in light years of the galaxy is 14 billion light years away
Two technicians are discussing the IAT sensor. Technician A says that the IAT sensor is more important to the operation of the engine (higher authority) than the ECT sensor. Technician B says that the PCM will add fuel if the IAT indicates that the incoming air temperature is cold. Who is right?
A. Technician A
B. Technician B
C. Both Technician and Technician B
D. Neither A nor B
Answer:
Technician B
Explanation:
Two technicians are discussing the IAT sensor. Technician A says that the IAT sensor is more important to the operation of the engine (higher authority) than the ECT sensor. Technician B says that the PCM will add fuel if the IAT indicates that the incoming air temperature is cold. Who is right?
ECT is the engine coolant temperature
The Intake Air Temperature sensor (IAT) records the temperature of the air entering the engine. The engine computer (PCM) estimates air density so it can balance air air/fuel mixture.PCM will add fuel if the IAT indicates that the incoming air temperature is cold
Assessing and monitoring your fluid levels will help you optimize your car's _______.
A. fuel mileage and longevity
B. appearance and attractiveness
C. traction and weight distribution
Answer:
A. fuel mileage and longevity
Explanation:
For a person purchasing a car, car longevity is one of the main concern. They are also interested in many things such as maximum mileage and service life.
By properly monitoring and assessing few measures one can maintain the efficiency and longevity of the car. One such thing is by monitoring the liquid levels of the car. Certain liquids like the coolant or radiator water level should be well maintain in proper level in order to run the car economically.
Thus by doing this, one can optimize the car's longevity and the fuel mileage.
Hence the correct option is (A).
Final answer:
Monitoring fluid levels can optimize a car's fuel mileage and longevity. Hybrid cars are noted for their fuel efficiency, while vehicle weight and aerodynamic design also play roles in gas mileage. Efficient driving habits and vehicle technology contribute to both cost savings and environmental responsibility.
Explanation:
Assessing and monitoring your fluid levels is important for maintaining your vehicle and optimizing its fuel mileage and longevity. Proper fluid levels ensure that your car operates efficiently, which can lead to improved fuel efficiency, thus making the vehicle more cost-efficient and environmentally responsible. Option A
For instance, maintaining the correct level of engine oil can reduce friction in the engine, which can prevent excessive fuel consumption. Furthermore, ensuring proper coolant levels can help manage the vehicle's temperature, preventing overheating that might otherwise lead to engine damage and reduce fuel efficiency.
In addition to regular maintenance, driving behaviors such as adhering to speed limits and accelerating smoothly also contribute to fuel economy, as indicated by the feedback from eco-driving aids like the one in the Ford Fusion that displays a plant with leaves when driving efficiently.
Studies have shown that hybrid cars are not only reliable but also have a significant advantage in terms of fuel efficiency over conventional cars. A Toyota Prius, for example, gets notable gas mileage, boasting 48 miles per gallon on the highway and 51 mpg in the city, while a Ford Fusion hybrid gets 47 mpg in both city and country conditions. These hybrid vehicles incorporate technology that enhances their overall fuel efficiency, providing cost savings over the long term and contributing positively to environmental sustainability.
It's also worth noting that the weight of a vehicle affects its fuel economy. Heavier vehicles typically consume more fuel. Therefore, car manufacturers aim to reduce the weight of cars to improve their miles per gallon. Such considerations also extend to the design of the cars. Aerodynamic shaping can reduce drag force, further enhancing a car's gas mileage. Lastly, road wear and tear incurred by heavy vehicles suggests a deeper relationship between weight distribution, axle weight, and the environmental impact of driving.
Adding gallium, boron, or indium to pure silicon or germanium will create a material with an excess of ?
Answer:
Adding gallium, boron, or indium to pure silicon or germanium will create a material with an excess of holes which is called a p-type material.
Explanation:
gallium, boron or indium are elements with three valency electron, and they are called Acceptor impurities. When acceptor impurities are added to pure silicon, it is called dopping
dopping: This is the process by which impurities is added to semi conductors in order to alter its electrical conductivity. The impurities is called dopants.
Adding gallium, boron, or indium to pure silicon or germanium will create a material with an excess of holes which is called a p-type material.
Answer: the excess material created is called "Hole".
Explanation: When the semiconductor such as silicon or germanium with four electrons in the outermost shell known as valence electron is added to either of electrons from indium,gallium or boron which has three valency electrons, a hole is created.
A hole which has positive charge is caused as a result of the movement of valence electrons from an atom to another atom.
A hole brings about conduction in semiconductor materials, (i.e when the free electrons with negative charge and holes with positive charge move in opposite direction in the semiconductor, conduction takes place).
A ball is thrown horizontally from the top of a building 30.2 m high. The ball strikes the ground at a point 94.7 m from the base of the building. The acceleration of gravity is 9.8 m/s 2 . Find the time the ball is in motion. Answer in units of s. 015 (part 2 of 4) 10.0 points Find the initial velocity of the ball. Answer in units of m/s. 016 (part 3 of 4) 10.0 points Find the x component of its velocity just before it strikes the ground. Answer in units of m/s. 017 (part 4 of 4) 10.0 points Find the y component of its velocity just before it strikes the ground. Answer in units of m/s.
Answer:
1) The ball is in motion for 2.48 seconds.2) Initial velocity of ball is 38.16 m/s 3) x component of velocity before hitting the ground is 38.16 m/s 4) y component of velocity before hitting the ground is 24.33 m/sExplanation:
1) Consider the vertical motion of ball
Displacement, s = 30.2 m
Initial velocity, u = 0 m/s
Acceleration, a = 9.81 m/s²
Substituting in s = ut + 0.5 at²
30.2 = 0 x t + 0.5 x 9.81 x t²
t = 2.48 s
The ball is in motion for 6.16 seconds.
2) Consider the horizontal motion of ball
Displacement, s = 94.7 m
Time, t = 2.48 s
Acceleration, a = 0 m/s²
Substituting in s = ut + 0.5 at²
94.7 = u x 2.48 + 0.5 x 0 x 2.48²
u = 38.16 m/s
Initial velocity of ball = 38.16 m/s
3) x component of velocity will not change since acceleration is zero along x direction.
x component of velocity before hitting the ground = 38.16 m/s
4) Consider the vertical motion of ball
Initial velocity, u = 0 m/s
Acceleration, a = 9.81 m/s²
Time, t = 2.48 s
Substituting in v = u + at
v = 0 + 9.81 x 2.48
v = 24.33 m/s
y component of velocity before hitting the ground = 24.33 m/s
Final answer:
The time the ball is in motion is 2.18 seconds. The initial velocity of the ball is 43.47 m/s. The x component of the velocity just before it strikes the ground is 43.47 m/s and the y component of the velocity is 21.36 m/s.
Explanation:
To find the time the ball is in motion, we can use the equation h = 0.5 * g * t^2, where h is the height of the building, g is the acceleration due to gravity, and t is the time. Rearranging the equation, we get t = sqrt(2h/g). Substituting the given values, the time the ball is in motion is sqrt(2 * 30.2 / 9.8) = 2.18 seconds.
The initial velocity of the ball can be found using the equation v = d / t, where v is the velocity, d is the horizontal distance, and t is the time. Rearranging the equation, we get v = d / t. Substituting the given values, the initial velocity of the ball is 94.7 / 2.18 = 43.47 m/s.
The x component of the velocity just before the ball strikes the ground is equal to the initial velocity, since there is no horizontal acceleration. Therefore, the x component of the velocity is 43.47 m/s.
The y component of the velocity just before the ball strikes the ground can be found using the equation v = u + gt, where v is the final velocity, u is the initial velocity, g is the acceleration due to gravity, and t is the time. Rearranging the equation, we get v - u = gt. Substituting the given values, the y component of the velocity is 9.8 * 2.18 = 21.36 m/s.
Which of the following is an effect of an ankle sprain? A. A decrease in the neural control to muscles that stabilize the patella B. Decreased neural control to stabilizing muscles of the core of the ankle C. A decrease in the neural control to the gluteus medius and gluteus maximus muscles D. Decreased neural control of the rotator cuff muscles
Answer:
C. A decrease in the neural control to the gluteus medius and gluteus maximus muscles
Explanation:
An ankle sprain is an injury that is caused by the twisting, rolling or turning the ankle in awkward manner. It can tear the ligaments of the bone muscles that helps to hold together the ankle bones.
When we get an ankle sprain, the neural control of the gluteus medius as well as the gluteus maximus muscles decreases. Thereby limiting the control of the lower extremities during any functional activities.
Hence the correct option is (C).
The velocity of the source is positive if the source is ______________. Note that this equation may not use the sign convention you are accustomed to. Think about the physical situation before answering.
Answer:
source is travelling away from the listener.
Explanation:
we know that
[tex]f_l=f_s\frac{v+v_L}{v+v_s}[/tex]
v= speed of sound
v_L= speed of listener
v_s=speed of the source
Let us consider the case when vL is zero.
We can see from equation that if we put +ve value for vs , then fL turns out to be less than fs.
(As denominator becomes greater than numerator part in right side term)
Frequency as heard by listener is less than the frequency of source when source is moving away from listener.
Therefore in this equation velocity of source is positive if the source is travelling away from the listener.
Final answer:
The velocity of the source is positive if the source is moving in the direction of the chosen reference or coordinate system. In physics, velocity is a vector quantity that not only indicates the speed of movement but also the direction of the object.
Explanation:
The velocity of a source is positive if it is moving in the same direction as the chosen positive reference direction in a coordinate system.
Therefore, a positive velocity indicates that an object is moving in the same direction that has been defined as positive in the coordinate system. Often, the positive direction is arbitrarily chosen, such as to the right or upwards on a graph. Conversely, a negative velocity indicates movement in the opposite direction of the chosen positive direction.
Additionally, if we discuss displacement, the final displacement being positive indicates that the object's position changed in the direction of the positive axis as well. The sign of velocity affects how we perceive acceleration too; for instance, if an object has a positive velocity and is speeding up, its acceleration is also positive. This means that the acceleration is in the same direction as the motion.
An Atwood machine is constructed using a hoop with spokes of negligible mass. The 2.5 kg mass of the pulley is concentrated on its rim, which is a distance 20.3 cm from the axle. The mass on the right is 1.33 kg and on the left is 1.78 kg. 3.7 m 2.5 kg 20.3 cm ω 1.78 kg 1.33 kg What is the magnitude of the linear acceleration of the hanging masses? The acceleration of gravity is 9.8 m/s 2 . Answer in units of m/s 2 .
Final answer:
The magnitude of the linear acceleration of the hanging masses in an Atwood machine can be calculated using the formula: a = (m2 - m1)g / (m1 + m2). The given masses are 1.33 kg on the right and 1.78 kg on the left. Plugging in these values, the magnitude of the acceleration is 1.3816 m/s^2.
Explanation:
In an Atwood machine, the magnitude of the linear acceleration of the hanging masses can be calculated using the formula:
a = (m2 - m1)g / (m1 + m2)
Where:
a is the magnitude of the linear acceleration
m1 is the mass on the left (1.78 kg)
m2 is the mass on the right (1.33 kg)
g is the acceleration due to gravity (9.8 m/s^2)
Plugging in the given values, we get:
a = (1.33 kg - 1.78 kg) * 9.8 m/s^2 / (1.78 kg + 1.33 kg)
a = -0.44 kg * 9.8 m/s^2 / 3.11 kg
a = -1.3816 m/s^2
Since the question asks for the magnitude of the acceleration, we take the absolute value:
a = 1.3816 m/s^2
Starting from rest at a height equal to the radius of the circular track, a block of mass 24 kg slides down a quarter circular track under the influence of gravity with friction present (of coefficient µ). The radius of the track is 15 m. The acceleration of gravity is 9.8 m/s 2 .Starting from rest at a height equal to the radius of the circular track, a block of mass 24 kg slides down a quarter circular track under the influence of gravity with friction present (of coefficient µ). The radius of the track is 15 m. The acceleration of gravity is 9.8 m/s 2 . If the kinetic energy of the block at the
bottom of the track is 3900 J, what is the
work done against friction?
Answer in units of J.
Answer:
The work done against friction is 372 joules
Explanation:
It is given that,
Mass of block, m = 24 kg
Radius of the track, r = 15 m
Acceleration due to gravity, [tex]a=9.8\ m/s^2[/tex]
If the kinetic energy of the block at the bottom of the track is, 3900 J
Let P is the work done against friction. It is given by :
[tex]P=mgh[/tex]
Here, h = r
[tex]P=24\ kg\times 9.8\ m/s^2\times 15\ m[/tex]
P = 3528 J
Since it ends up with 3900 J, the work done is given by or the lost in energy will be :
W = 3900 - 3528
W = 372 joules
So, the work done against friction is 372 joules. Hence, this is the required solution.
If you use a horizontal force of 33.0 N to slide a 11.0 kg wooden crate across a floor at a constant velocity, what is the coefficient of kinetic friction between the crate and the floor?
Answer:
μ= 0.3
Explanation:
Given that
F= 33 N
m = 11 kg
Given that crate is moving with constant velocity is means that acceleration of the crate is zero.If acceleration of the system is zero then the total force on the system will be balance.
Therefore
F= Friction force
F= μ m g
μ=Coefficient of friction
33 = μ x 10 x 11 ( take g= 10 m/s²)
3 = 10 μ
μ= 0.3
Therefore coefficient of friction will be 0.3 .
How much work did the movers do (horizontally) pushing a 41.0-kgkg crate 10.6 mm across a rough floor without acceleration, if the effective coefficient of friction was 0.60?
Final answer:
The work done by movers to push a 41.0 kg crate across a rough floor for 10.6 meters against a coefficient of friction of 0.60, with no acceleration, is 2547.816 joules.
Explanation:
The student is asking about the amount of work done by movers in pushing a 41.0 kg crate across a rough floor where there is friction but without acceleration. The coefficient of friction is given as 0.60. To solve this problem, we use the formula:
Work done (W) = Force (F) x Distance (d)
Since the crate is moved horizontally with no acceleration, the force applied by the movers is equal to the frictional force, which is given by:
F = μ x Normal force (N)
The normal force is equal to the weight of the crate, which is mass (m) times the acceleration due to gravity (g), N = m x g. Therefore:
F = μ x m x g
Now, we know the mass (m=41.0 kg), acceleration due to gravity (g ≈ 9.8 m/s²), coefficient of friction (μ = 0.60), and distance (d = 10.6 m). Plugging these values in, we get:
F = 0.60 x 41.0 kg x 9.8 m/s² = 240.36 N
W = 240.36 N x 10.6 m = 2547.816 J
Therefore, the work done by the movers is 2547.816 joules.
The world's fastest humans can reach speeds of about 11 m/s.In order to increase his gravitational potential energy by an amount equal to his kinetic energy at full speed, how high would such a sprinter need to climb?
Answer:
The sprinter need to climb 6.17 m
Explanation:
From the question,
Ep = Ek...................... Equation 1
Where Ep = potential energy, Ek = kinetic energy.
therefore,
mgh = 1/2mv².................... Equation 2
Where m = mass of the human, v = speed, h = height, g = acceleration due to gravity.
making h the subject of formula in equation 2
h = 1/2v²/g...................... Equation 3
Given: v = 11 m/s
Constant: g = 9.8 m/s²
Substituting these values into equation 3,
h = 1/2(11²)/9.8
h = 6.17 m.
Therefore the sprinter need to climb 6.17 m
Feces is usually about 40 percent water and 60 percent solid matter. Reducing the water content to 20 percent would most likely result in
Answer:
Constipation
Explanation:
An organism's bowel movement depends on the amount of water it has consumed. If the organism has not consumed enough water then the stool becomes hard and dry.
This makes it difficult for the organism to pass the stool. This condition is known as constipation.
Hence, here if the water content is reduced to 20 percent then this would likely result in constipation.
in the northern hemisphere the magnetic compass will normally indicate a turn toward the west.
Answer:
in the northern hemisphere the magnetic compass will normally indicate a turn toward the west if "A right turn is entered from a North Heading"
Explanation:
The face towards which the magnetic needle aligns are north and south magnetic poles. The magnetic compass does not work in southern hemisphere, because of the fact opposite poles attract. Exactly while turning right due to the opposite force the magnetic needle will deviate. Magnetic deviations do occur because of the presence of magnetized iron in the ship and also in aircraft. The magnetic north is not the actual or the exact north pole.
Which of the following supports the claim that the atom is like a solid positive cookie with negative electrons embedded within it? (This model is known as the Plum Pudding Model of the atom, and is illustrated to the right).
a. Law of Constant Composition, Law of Multiple Proportions, Law of Conservation of Mass Alpha particles are scattered at a variety of angles (over 90 degrees) when bombarded at gold foil.
b. When light from hydrogen emissions passes through a diffracting grating, there are distinct bands of color.
c. The Cathode Ray Tube experiment, in which the ray was attracted to the south pole of the magnet.
Answer:
a. Law of Constant Composition, Law of Multiple Proportions, Law of Conservation of Mass Alpha particles are scattered at a variety of angles (over 90 degrees) when bombarded at gold foil.
Explanation:
Which of the following supports the claim that the atom is like a solid positive cookie with negative electrons embedded within it? (This model is known as the Plum Pudding Model of the atom, and is illustrated to the right).
a. Law of Constant Composition, Law of Multiple Proportions, Law of Conservation of Mass Alpha particles are scattered at a variety of angles (over 90 degrees) when bombarded at gold foil.
b. When light from hydrogen emissions passes through a diffracting grating, there are distinct bands of color.
c. The Cathode Ray Tube experiment, in which the ray was attracted to the south pole of the magnet.
the plumbudding model of the atom was postulated by JJ Thompson and plum pudding model. . ... Thomson had discovered that atoms are composite objects, made of pieces with positive and negative charge, and that the negatively charged electrons within the atom were very small compared to the entire atom.
so a. correctly typifies the thompson model of the atom
Final answer:
Option c, the Cathode Ray Tube experiment, supports the claim that the atom is like a solid positive cookie with negative electrons embedded within it.
Explanation:
The correct option that supports the claim that the atom is like a solid positive cookie with negative electrons embedded within it is option c. The Cathode Ray Tube experiment, in which the ray was attracted to the south pole of the magnet, is consistent with the Plum Pudding Model of the atom. This model describes atoms as having a diffuse positive charge with embedded electrons.
An object is thrown straight up with a velocity, in ft/s, given by v(t)= -32t + 83, where t is in seconds, from a height of 46 feet.
a) What is the object's initial velocity?
b) What is the object's maximum velocity?
c) What is the object's maximum displacement?
d) When does the maximum displacement occur?
e) When is the object's displacement 0?
f) What is the object's maximum height?
Explanation:
We have velocity
v(t)= -32t + 83
Integrating
s(t) = -16t²+83t+C
At t = 0 displacement is 46 feet
46 = -16 x 0²+83 x 0+C
C = 46 feet
So displacement is
s(t) = -16t²+83t+46
a) Initial velocity is
v(0)= -32 x 0 + 83 = 83 ft/s
Initial velocity = 83 ft/s
b) Maximum velocity is when the object reaches ground, that is s(t) = 0 ft
Substituting
0 = -16t²+83t+46
t = 5.70 seconds
Substituting in velocity equation
v(t)= -32 x 5.70 + 83 = -99.4 ft/s
Object's maximum speed = 99.4 ft/s
c) Maximum displacement is when the velocity is zero
That is
-32t + 83 = 0
t = 2.59 s
Substituting in displacement equation
s(2.59) = -16 x 2.59²+83 x 2.59+46 = 153.64 ft
Object's maximum displacement = 153.64 ft
d) Maximum displacement occur at t = 2.59 seconds.
e) Refer part b
The displacement is zero when t = 5.70 seconds
f) Same as option d
Object's maximum height = 153.64 ft
Answer:
The initial velocity is 83 ft/s.
The maximum velocity of object is -82.76 ft/s.
The maximum displacement is 107.64 ft.
Time for maximum displacement is 2.59 s.
The object's displacement is zero at 5.18 s.
The maximum height of object is, 107.64 ft.
Explanation:
Given data:
Equation for the velocity is, [tex]v(t)=-32t+83[/tex].
Height is, [tex]H'=46\;\rm feet[/tex].
(a)
At initial, the time function is zero. Which means, t = 0.
Then, initial velocity is:
[tex]v(t=0)=-32(0)+83\\v(t=0)= 83\;\rm ft/s[/tex]
Thus, the initial velocity is 83 ft/s.
(b)
The maximum velocity of object is at ground. Then, equation for maximum distance covered is obtained as,
[tex]v(t)=\frac{dH}{dt} \\dH=\int\limits^H_0 {v(t)} \, dt \\dH=\int\limits^H_0 {(-32t+83)} \, dt[/tex]
Integrating as,
[tex]H =-16t^2+83t[/tex]
Maximum velocity is at ground, hence H=0. Solving as,
[tex]0 =-16t^2+83t\\16t=83\\t=5.18 \;\rm s[/tex]
Now, maximum velocity is,
[tex]v(t=5.18)=-32(5.18)+83\\v(t=5.18)=-82.76 \;\rm ft/s[/tex]
Thus, maximum velocity of object is -82.76 ft/s.
(c)
The maximum displacement will be at corresponding to zero velocity. Then,
[tex]v(t)=-32t+83\\0=-32t+83\\t=2.59 \;\rm s[/tex]
Then, maximum displacement is,
[tex]H =-16(2.59^2)+83(2.59)\\H = 107.64\;\rm ft[/tex]
Thus, maximum displacement is 107.64 ft.
(d)
The maximum displacement occurs at zero velocity. And, time is,
[tex]v(t)=-32t+83\\0=-32t+83\\t=2.59 \;\rm s[/tex]
Thus, time for maximum displacement is 2.59 s.
(e)
The object displacement is zero when it reaches back to the ground. At ground, H=0. Which means time is,
[tex]0 =-16t^2+83t\\\\16t=83\\t=5.18 \;\rm s[/tex]
Thus, object's displacement is zero at 5.18 s.
(f)
The maximum height of object is equal to maximum displacement. Thus, maximum height of object is, 107.64 ft.
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Why do scientists often take several measurements of the same object, average them together, and use the average value as the measurement?
Answer:
To minimize the practical errors and improve the accuracy.
Explanation:
Scientists take several measurements and use the average of all the measured values to minimize the practical errors due to unavoidable circumstances and be close to the true value.True value is the actual value of a measured parameter without any error, it is the value which is proposed in the design of a certain object.Variations may occur in the measurement due to wear and tear, dust and air pressure. It is almost impossible to create ideal surrounding for the measurement procedure.