Susan was recently fired from her executive IT position. You have concerns that she has enough knowledge and expertise to sabotage company documents—and you need to delete her access. However, upon beginning, you find information that should be retained in her user directory for future company needs. Consider the process you would take to ensure that Susan no longer has access and that data is retained. In situations like this, do you think the benefits outweigh the risks enough to retain user information? Why or why not?

Answer:

See explaination

Explanation:

#function to count number of characters, words in a given file and returns a list of words

def GetGoing(filename):

file = open(filename)

numbrOfCharacters =0

numberOfWords = 0

WordList = []

#iterate over file line by line

for line in file:

#split the line into words

words = line.strip().split()

#add counn of words to numberOfWords

numberOfWords = numberOfWords + len(words)

#find number of characters in each word and add it to numbrOfCharacters

numbrOfCharacters = numbrOfCharacters + sum(len(word) for word in words)

#append each word from a line to WordList

for word in words:

WordList.append(word)

#display the result

print("The number of characters: ", numbrOfCharacters)

print("The number of Words: ", numberOfWords)

#return the list of words

return WordList

#find matches for keywords given in textlist

def FindMatches(keywordlist, textlist):

for keyword in keywordlist:

keyword = keyword.lower()

print ("The number of occurrences of {} is: {}".format(keyword,len([i for i, s in enumerate(textlist) if s == keyword])))

#main

booktext = GetGoing("constitution.txt")

FindMatches (['War', 'Peace', 'Power'], booktext)

Answer:

a) Time to live field

b) Destination

c) Yes, they have two ip addresses.

d) 128 bits

e) 32 hexadecimal digits

Explanation:

a) the time to live field (TTL) indicates how long a packet can survive in a network and whether the packet should be discarded. The TTL is filled to limit the number of packets passing through N routers.

b) When a large datagram is fragmented into multiple smaller datagrams, they are reassembled at the destination into a single large datagram before beung passed to the next layer.

c) Yes, each router has a unique IP address that can be used to identify it. Each router has two IP addresses, each assigned to the wide area network interface and the local area network interface.

d) IPv6 addresses are represented by eight our characters hexadecimal numbers. Each hexadecimal number have 16 bits making a total of 128 bits (8 × 16)  

e) IPv6 address has 32 hexadecimal digits with 4 bits/hex digit

The TCP/IP concepts of packet forwarding, fragmentation, and reassembly along with IPv4 and IPv6 addressing schemes are explained.

TTL (Time To Live) field in the IPv4 datagram header can be used to ensure that a packet is forwarded through no more than N routers. When a large datagram is fragmented into multiple smaller datagrams, these smaller datagrams are reassembled into a single larger datagram at the destination host. Routers do have IP addresses, typically one per interface, so the number varies. IPv6 addresses consist of 128 bits; represented using hexadecimal digits (each 4 bits), hence we need 32 hexadecimal digits to represent an IPv6 address.

Answer:

Explanation:

#include <iostream>

#include <iomanip>

using namespace std;

#include "SavingsAccount.h"

double SavingsAccount::annualInterestRate = 0.0;

SavingsAccount::SavingsAccount( double bal, double AiR )

{

  savingsBalance = ( bal >= 0.0 ? bal : 0.0 );

  setAnnualInterestRate( AiR ); //AiR = AnnualInterestRate

}

void SavingsAccount::setAnnualInterestRate( double AiR)

{

  annualInterestRate = ( AiR >= 0.0 && AiR <= 1.0) ? AiR : .03;

}

double SavingsAccount::getAnnualInterestRate()

{

  return annualInterestRate;

}

void SavingsAccount::calculateMonthlyInterest()

{

  savingsBalance += savingsBalance * ( annualInterestRate / 12);

}

void SavingsAccount::modifyInterestRate( double interest )

{

  annualInterestRate = (interest >= 0.0 && interest <= 1.0) ? interest : .04;

}  

void &SavingsAccount::print() const  

{

  cout << fixed << setprecision(2) << "$" << savingsBalance;

}

int main()

{

  SavingsAccount saver1( 2000.0, .03 );

  SavingsAccount saver2( 3000.0, .03 );

  cout << "Initial Balance For saver1 Is: " << saver1.print;

  cout << "\nInitial Balance For saver2 Is: " << saver2.print <<  "\n\n";

  cout << "Interest Rate For Both Accounts is " <<       saver1.getAnnualInterestRate << "%";

  saver1.calculateMonthlyInterest();

  saver2.calculateMonthlyInterest();

  cout << "Balance After 3% interest For saver1: " << saver1.print;

  cout << "\nBalance After 3% interest For saver2: " << saver2.print;  

  cout << "\n\nSetting Annual Interest Rate to 4%";

  saver1.modifyInterestRate( .04 );

  saver2.modifyInterestRate( .04 );

  saver1.calculateMonthlyInterest();

  saver2.calculateMonthlyInterest();

  cout << "\nBalance After 4% Interest For saver1: " << saver1.print;

  cout << "\nBalance After 4% Interest For saver2: " << saver2.print;

  cout << endl;

return 0;

}

Answer:

Please check the explanation

Explanation:

That's the code and it is done with the program in c++ according to instructions given in the question using binary search. It can guess the correct number in 10 or fewer attempts and also shows the number of attempts it took to guess the number.

​ #include <iostream> using namespace std; int guess() { string input; int l = 1, h = 1000; int mid = (l + h) / 2, count = 0; while (1) { //count the number of attemts to guess the number ++count; //cout << count << "\n"; cout << "\n"; cout << "Is " << mid << " correct? (y/n): "; cin >> input; //if input is y print the guessed no. and return if (input == "y") { cout << mid << " guessed in " << count << " attempts!\n"; return 1; } //if input is n ask the user if it's higher or lower than current guess if (input == "n") { cout << "Is the number greater than or less than the number ? (h/l): "; cin >> input; } //if input is higher assign mid incremented by 1 to low //else decrement mid by 1 and assign to high if (input == "h") l = mid + 1; else h = mid - 1; //calculate mid again according to input by user again mid = (l + h) / 2; } } int main() { cout << "****WELCOME TO THE GUESS THE NUMBER GAME!****\n"; cout << "Guess any number between 1 to 1000.\n"; cout << "This game depends on user giving correct answers and not changing their number middle of game.\n"; guess(); } ​

Answer:

Check the explanation

Explanation:

PYTHON CODE :

#import random function

from random import randint

#class Queue declaration

class Queue:

#declare methods in the Queue

def __init__(self):

self. items = []

def isEmpty(self):

return self. items == []

def enqueue(self, item):

self.items. insert(0, item)

def dequeue(self):

return self. items. pop()

def size(self):

return len(self. items)

def getInnerList(self):

return self.items

#This is customer Queue

class Customer:

#declare methods

def __init__(self,n):

self.numberOfItems=n

def __str__(self):

return str(self. numberOfItems)

def getNumberOfItems(self):

return self. numberOfItems

#This is expresscheker customer queue

class Expresschecker:

def __init__(self,n):

self.numberOfItems=n

def __str__(self):

return str(self. numberOfItems)

def getNumberOfItems(self):

return self. numberOfItems

#Returns random checkout time, based on number of items

def checkOut(Expresschecker):

items = Expresschecker. getNumberOfItems()

if items <= 10:

return randint(2, 5)

if items <= 20:

return randint(6, 9)

return randint(10, 14)

#Initiate queue for the Expresschecker

Expresschecker = Queue()

#declare total customers

totalcheckoutCustomers = 10

#express Customers shopping..

for i in range(totalcheckoutCustomers):

#Each putting Between 1 to 25 items

randomItemsQty = randint(1, 25)

customer = Customer(randomItemsQty)

#Getting into queue for checkout

Expresschecker. enqueue(customer)

#====Now all express Customers having

#random qty of items are in Queue======

#intial time

totalTime=0

#define the size of the queue

totalcheckoutCustomers = Expresschecker. size()

#using for-loop until queue is empty check out

#the items in the express cheker queue

while not(Expresschecker. isEmpty()):

totalTime+=randint(1,5)

#Picking a customer

expresscustomer = Expresschecker. dequeue()

#Processing the customer

timeTaken = checkOut(expresscustomer)

#add the time for each custimer

totalTime+=timeTaken

#compute average waiting time

averageWaitingTime = totalTime/totalcheckoutCustomers

#display the average waiting time

print("Average waiting time for the express customer queue is "

+str(averageWaitingTime)+" minutes ")

print("Remaining Custimers in the express customer Queue is: ",

Expresschecker. size())

#Returns random checkout time, based on number of items

def checkOut(customer):

items = customer. getNumberOfItems()

if items <= 10:

return randint(1, 5)

if items <= 20:

return randint(6, 10)

return randint(11, 15)

#in

customersQueue = Queue()

totalCustomers = 20 #Change number of customers here

#Customers shopping..

for i in range(totalCustomers):

#Each putting Between 1 to 25 items

randomItemsQty = randint(1, 25)

customer = Customer(randomItemsQty)

#Getting into queue for checkout

customersQueue. enqueue(customer)

#====Now all Customers having random qty

#of items are in Queue======

totalTime=0

totalCustomers = customersQueue. size()

while not(customersQueue. isEmpty()):

totalTime+=randint(1,5)

#Picking a customer

customer = customersQueue. dequeue()

#Processing the customer

timeTaken = checkOut(customer)

totalTime+=timeTaken

#Result=============================

averageWaitTime = totalTime/totalCustomers

print("Average wait time for the customer queue is

"+str(averageWaitTime)+" minutes ")

print("Remaining Customers in the customer Queue is:

",customersQueue. size())

Answer:

See Explaination

Explanation:

Provided Pseudocode as per your new specifications:

start

Declarations

num weddingMonth

num weddingDay

string weddingClientName

num weddingPhoneNum

string weddingDescription

num weddingPrice

num replaceMonth

num replaceDay

string replaceClientName

num replacePhoneNum

string replaceDescription

num replacePrice

num weddingDate

num replaceDate

num bothAtEnd=0

num END_YEAR=9999

InputFile weddingFile

InputFile replaceFile

ouputFile mergedFile

getReady()

while bothAtEnd<>1

mergeRecords()

endwhile

finishUp()

stop

getReady()

open weddingFile "weddingDress.dat"

open replaceFile "replaceJacketZipper.dat"

open mergedFile “Merged.dat”

readWedding()

readreplace()

checkEnd()

return

readWedding( )

input weddingMonth,weddingDay,weddingClientName,weddingPhoneNum,weddingDescription,weddingPricee from weddingFile

while eof

weddingDate=END_YEAR

endwhile

return

readreplace( )

input replaceMonth,replaceDay,replaceClientName,replacePhoneNum,replaceDescription,replacePricee from replaceFile

while eof

replaceDate=END_YEAR

endwhile

return

checkEnd()

if weddingDate=END_YEAR

if replaceDate=END_YEAR

bothAtEnd=1

endif

endif

return

mergedFile()

if weddingDate<replaceDate

output weddingMonth,weddingDay,weddingClientName,weddingPhoneNum,weddingDescription,weddingPricee to weddingFile

readWedding()

endif

Final answer:

The question is about adding functionality to a computer program to display monthly and yearly earnings for Marian Basting's sewing jobs. This involves data handling, control structures, and algorithms to manage and total earnings in the generated report.

Explanation:

The question pertains to modifying a computer program for Marian Basting, who takes in sewing jobs and tracks them in two sorted files. The program should not only merge the files to produce a date-ordered report of all Marian's jobs for the year but should also be modified to display total earnings at the end of each month and the yearly total earnings. To achieve this, the program would require additional functionality to sum the price of jobs, categorized by month and then aggregated for the year-end total. This could involve processing each entry, keeping a running total, and then displaying the totals when a new month starts or the report ends.

For clarity, here's a hypothetical implementation outline: Load the entries from both files, sort them by date, iterate through the sorted list while maintaining a subtotal for each month's earnings. After processing all entries for a month, display the subtotal. Upon reaching year-end, display the final total. This implementation requires knowledge of programming concepts such as data handling, control structures, and algorithms for sorting and totaling.

Answer:

import java.util.Scanner;

public class Pallindrome {

   public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       System.out.println("Enter the input string: ");

       String word = in.nextLine();

       System.out.println(isPallindrome(word));

   }

   public static String isPallindrome(String word){

       String rev ="";

       int len = word.length();

       for ( int i = len - 1; i >= 0; i-- )

           rev = rev + word.charAt(i);

       if (word.equals(rev))

           return word+" is palindrome";

       else

           return word+ " is not palindrome";

   }

}

Explanation:

In this exercise we have to use the knowledge in computational language in JAVA to describe a code that best suits, so we have:

The code can be found in the attached image.

To make it simpler we can write this code as:

public class Pallindrome {

  public static void main(String[] args) {

      Scanner in = new Scanner(System.in);

      System.out.println("Enter the input string: ");

      String word = in.nextLine();

      System.out.println(isPallindrome(word));

  }

  public static String isPallindrome(String word){

      String rev ="";

      int len = word.length();

      for ( int i = len - 1; i >= 0; i-- )

          rev = rev + word.charAt(i);

      if (word.equals(rev))

          return word+" is palindrome";

      else

          return word+ " is not palindrome";

  }

}

See more about JAVA at brainly.com/question/19705654

Answer:

Explanation:

#include <iostream>

using namespace std;

int main ()

{

   int responses[30],count[6];

   int score = 0;

   string resp = " ";

   for (int i = 0; i < 30; i++)

   {

    responses[i] = 0;

   }

   for (int i = 0; i < 6; i++)

   {

    count[i,1]=0;

    count[i,2]=0;

    count[i,0]=0;

   }

   while ((resp != "Y") && (resp != "y"))

   {

    for (int i = 0; i < 30; i++)

    {

        while ((score > 5) || (score < 1))

           {

            cout << "Student " << (i+1)<< " please enter a value (1-5):";

            cin >> score;

        }

           responses[i] = score;

           if((score > 5)||(score<1))

           {

               if(score==1) count[1]++;        

               if(score==2) count[2]++;        

               if(score==3) count[3]++;        

               if(score==4) count[4]++;        

               if(score==5) count[5]++;        

           }

           score = 0;

    }

    cout<< "Response               Frequency              Percentage"<<endl;;

    cout<< "    1                      "<<count[1]<<"               "<<(count[1]/30)<<"%"<<endl;

    cout<< "    2                      "<<count[2]<<"               "<<(count[2]/30)<<"%"<<endl;

    cout<< "    3                      "<<count[3]<<"               "<<(count[3]/30)<<"%"<<endl;

    cout<< "    4                      "<<count[4]<<"               "<<(count[4]/30)<<"%"<<endl;

    cout<< "    5                      "<<count[5]<<"               "<<(count[5]/30)<<"%"<<endl;

    cout<< "Do you want to exit? Press Y to exit any other key to continue: ";

    cin>> resp;

   }

   return 0;

}

Answer:

See explaination

Explanation:

// File: TelephoneNumber.java

import java.util.Scanner;

public class TelephoneNumber

{

public static void main(String[] args)

{

Scanner input = new Scanner(System.in);

String inputNumber;

String tokens1[];

String tokens2[];

String areaCode;

String firstThree;

String lastFour;

String allSeven;

String fullNumber;

/* input a telephone number as a string in the form (555) 555-5555BsAt4ube4GblQIAAAAASUVORK5CYII= */

System.out.print("Enter a telephone number as '(XXX) XXX-XXXX': ");

inputNumber = input.nextLine();

System.out.println();

/* use String method split */

tokens1 = inputNumber.split(" ");

/* extract the area code as a token */

areaCode = tokens1[0].substring(1, 4);

/* use String method split */

tokens2 = tokens1[1].split("-");

/* extract the first three digits of the phone number as a token */

firstThree = tokens2[0];

/* extract the last four digits of the phone number as a token */

lastFour = tokens2[1];

/* concatenate the seven digits of the phone number into one string */

allSeven = firstThree + lastFour;

/* concatenate both the area code and the seven digits of the phone number into one full string separated by one space */

fullNumber = areaCode + " " + allSeven;

/* print both the area code and the phone number */

System.out.println("Area code: " + areaCode);

System.out.println("Phone number: " + allSeven);

System.out.println("Full Phone number: " + fullNumber);

}

}

The provided C++ program reads two strings, calls the `split` function using the given header, and prints the resulting vector with elements separated by commas.

Below is an updated C++ program that adheres to the given header and meets the specified requirements. It reads two strings, calls the `split` function, and prints the resulting vector:

#include <iostream>

#include <vector>

#include <string>

// Function to split a string by a delimiter

std::vector<std::string> split(std::string target, std::string delimiter) {

   std::vector<std::string> substrings;

   size_t start = 0;

   size_t end = target.find(delimiter);

   while (end != std::string::npos) {

       substrings.push_back(target.substr(start, end - start));

       start = end + delimiter.length();

       end = target.find(delimiter, start);

   }

   substrings.push_back(target.substr(start));

   return substrings;

}

int main() {

   std::string inputString, delimiter;

   std::cout << "Enter string to split: ";

   std::getline(std::cin, inputString);

   std::cout << "Enter delimiter string: ";

   std::getline(std::cin, delimiter);

   // Call the split function

   std::vector<std::string> result = split(inputString, delimiter);

   // Print the resulting vector

   std::cout << "The substrings are: ";

   for (size_t i = 0; i < result.size(); ++i) {

       std::cout << "\"" << result[i] << "\"";

       if (i < result.size() - 1) {

           std::cout << ", ";

       }

   }

   return 0;

}

This program uses the `split` function to tokenize the input string based on the given delimiter, and it prints the resulting vector as required.

Answer:

See explaination

Explanation:

function thanos(lst) {

var result = [];

for (var i = 0; i < lst.length; i += 2) {

result.push(lst[i]);

}

return result;

}

// Testing the function here. ignore/remove the code below if not required

console.log(thanos([]));

console.log(thanos(['0', 2, 4]));

Answer:

Check Explanation.

Explanation:

Task: (1). Apply Underline to cell B5 and Double Underline to cell B6.

(2). Ungroup the worksheets.

(3).use the Format Cells dialog box to ensure that the Underline styles Single and Double are applied, rather than Single Accounting or Double Accounting.

Steps to follow;

Step one: On the Excel document that you are working on, make sure you highlight from B6 cell to F6 cell.

Step two: Then, press CTRL+SHIFT+F.

Step three: from action in step two above, the "format cells dailogue box" will come up, click underline > (underline type) dropdown list > ok.

Step four: next, highlight from B7 to F7.

Step five: press CTRL+SHIFT+F. As in step two above.

Step Six: do the same thing as in Step three above.

Please note that to apply the SINGLE UNDERLINE, you need to type the data in the cell for cells of B6 to F6 ONLY.

Also, for DOUBLE UNDERLINE for B7 to F7; just type the data in the cell and it will apply.

Answer:

See explaination

Explanation:

#Define the function square_all() having a list of

#integers. This function will return a list of square

#of all integer included in the given list.

def square_all(num_list):

#Create an empty list to store resultant list.

sq_list = []

#Start a for loop till the length of the given list.

for index in range(0, len(num_list)):

#Multiply the current list value with its value

#and append the resultant value in the list

#sq_list in each iteration.

sq_list.append(num_list[index] * num_list[index])

#Return the final list of squares of all integrs in

#the list num_list.

return sq_list

#Declare and initialize a list of integers.

intList = [2, 4]

#Call the function square_all() and pass the above list

#as argument of the function. Display the returned list.

print(square_all(intList))

Answer:

Answered below

Explanation:

A software warranty is a written promise or guarantee from a software manufacturer or company to repair or replace a product of it has a fault within a particular period of time. Such faults must arise from the manufacturer's errors.

During the warranty period given, the software developer must fix all the defects and bugs within the software so long as it occurred due to a development fault and there is evidence of system failure.

Some software programs and applications really do require a warranty with a longer duration. Such softwares include those used in big businesses and corporations like banks, medical softwares, nuclear softwares and aviation softwares. The warranties are like a testament of reliability of the software in such critical and delicate sectors.

An open source software for a video game may not require a warranty or the warranty period might not be long compared to business softwares.

Answer:

regression line is  Y  =    124.9281    +    0.9370    *x

SSE=    (SSxx * SSyy - SS²xy)/SSxx =     7317401.270      

Explanation:

See the attached image file

Answer:

Check the explanation

Explanation:

Each Bagel-type small monster has 0.35 probability of being a Sesame Seed-subtype and 0.2 probability of being a Whole Wheat-subtype.

The probability that exactly 8 of them are Whole Wheat-subtype is [tex]\binom{10}{8}(0.2)^8(0.8)^2[/tex] using multiplication principle, because first need to choose which 8 are Whole Wheat-subtype, and if exactly 8 of them are Whole Wheat-subtype, then other two are not Whole Wheat-subtype. The former has probability 0.2, while the latter has probability 1-0.2 = 0.8 .

Kindly check the attached images below for the complete answer to the question above

1.) asking clarifying questions, without interrupting

2.) keeping eye contact

Techniques for active listening are

The correct options are 1 and 2.

An active listening is when a person actively listens to another person.

A person must maintain eye contact with the speaker while in conversation with him.

Also, they must have two way conversation between them.

Thus, correct options are 1 and 2.

Learn more about active listening.

https://brainly.com/question/3013119

#SPJ2

Answer:

Graphs and charts are visual representations of data in the form of points, lines, bars, and pie charts. Using graphs or charts, you can display values you measure in an experiment, sales data, or how your electrical use changes over time. Types of graphs and charts include line graphs, bar graphs, and circle charts.

Explanation:

Graphs are used to visually display data, making it easier to identify trends and patterns. They simplify complex data and allow for effective comparisons, aiding better understanding and data-driven decision-making.

Graphs are a powerful tool used to display data visually, making it easier to see trends and patterns compared to numerical data in a table. In high school mathematics, understanding how to interpret various types of graphs is crucial.

Here are some key reasons why graphs are employed:

Overall, utilizing graphs not only aids in understanding data better but also helps in making data-driven decisions effectively.

Answer:

D

Explanation:

I just did it

Answer:

See explaination

Explanation:

#include <iostream>

#include <fstream>

using namespace std;

int main()

{

int size = 10;

string inputFileName, outputFileName;

cout << "Please enter input file name, including full path: ";

cin >> inputFileName;

cout << "Please enter output file name, including full path: ";

cin >> outputFileName;

ifstream inFile(inputFileName.c_str());

ofstream outFile(outputFileName.c_str());

// checking whether input and output files are good to open

if(!inFile.is_open())

{

cout << "Cannot open " << inputFileName << endl;

exit(EXIT_FAILURE);

}

if(!outFile.is_open())

{

cout << "Cannot open " << outputFileName << endl;

exit(EXIT_FAILURE);

}

// declare an array of string to store 1024 words

string words[size];

// read the file for exactly 1024 words

// assuming each line of input file contains only 1 word

int count = 0;

string word;

while(getline(inFile, word))

{

if(count == size)

break;

words[count++] = word;

}

inFile.close();

// now we need to print the words array in reverse order both to the console and to the output file, simultaneously

cout << "WORDS:\n------\n";

for(int i = size - 1; i >= 0; i--)

{

if(words[i] != "")

{

cout << words[i] << endl;

outFile << words[i] << endl;

}

}

outFile.close();

system("pause");

return 0;

}

Final answer:

The question is about creating a program for file reading and writing, including array manipulation and outputting content in reverse. The program must handle input/output operations, file size variations, and ensure resource management by closing files properly.

Explanation:

The student's question pertains to writing a program that can read and write files, and specifically handle reading words into an array and then outputting them in reverse order to a file and the screen. The steps to achieve this involve prompting the user for file paths, checking the success of opening files, handling files of various sizes, and managing resources correctly by closing files. A 'pause' before the program ends is also required, likely to allow the user to see the output before the program closes.

To begin, here's a simplified pseudo-code outline:

Note: When implementing the read operation, the program should consider the file size which may be larger than the array and handle it appropriately, perhaps by reading in chunks if necessary.

Answer:

If there is a majority element in the array it will be the median. Thus,

just run the linear time median finding algorithm, and compare the result with all the  elements of the array (also linear time). If [tex]\frac{n}{2}[/tex]elements are the same as the median, the  median is a ma majority element. If not, there is none.

Suppose now that the elements of the array are not from some ordered domain like the  integers, and so there can be no comparisons of the form "is the ith element of the array  greater than the jth element of the array?" However you can answer questions of the  form:

"Are the ith and jth elements of the array the same?" in constant time. Such

queries constitute the only way whereby you can access the array. (Think of the elements  of the array as GIF files, say.) Notice that your solution above cannot be used now.

Answer:

Option D 0 <= index < phrase.length() - key.length()

Explanation:

The index has to be between the range of 0 <= index < phrase length - key length to prevent index out of bound error. This is because the substring method will have to extract part of the string with a certain length from the original string starting from the index-position. If the key length is longer than the string area between phrase[index] and  phase.length(), an index out of bound runtime error will be thrown.

Final answer:

This response examines the role of smartphones, laptops, and GPS devices in daily life, considering how they affect communication, work, travel, and convenience.

Explanation:

Understanding how electronic devices shape our daily lives can provide insight into their pervasive influence and the reliance we've developed on technology. For this exercise, we'll examine three common devices: a smartphone, a laptop, and a GPS device.

Smartphones have become nearly indispensable in modern life. They serve as communication hubs, personal assistants, and portable entertainment systems. The smartphone keeps us connected through calls, texts, emails, and social media. It also helps manage our schedules, set alarms, and capture memories through its camera. Life without smartphones would mean a return to separate devices for each of these functions and a significant loss in convenience and efficiency.

Laptops offer portable computing power that enables us to work, learn, and play from virtually anywhere. They are essential for students and professionals alike, as they support software for creating documents, managing data, and facilitating online meetings. The absence of laptops would drastically change the landscape of mobile work and education, likely requiring a heavier reliance on desktop computers and physical media.

A GPS device provides accurate navigation and location tracking, which is especially useful for travel and logistics. The utility of GPS extends beyond simple navigation to include applications in science, military, and emergency services. Without GPS technology, we would need to rely on physical maps and alternative methods for location tracking, potentially complicating travel and critical operations.

Answer:

A. Social network analysis (SNA).

Explanation:

This is explained to be a process of quantitative and qualitative analysis of a social network. It measures and maps the flow of relationships and relationship changes between knowledge possessing entities. Simple and complex entities include websites, computers, animals, humans, groups, organizations and nations.

The SNA structure is made up of node entities, such as humans, and ties, such as relationships. The advent of modern thought and computing facilitated a gradual evolution of the social networking concept in the form of highly complex, graphical based networks with many types of nodes and ties. These networks are the key to procedures and initiatives involving problem solving, administration and operations.

Answer:

The answer to this question can be described as follows:

Explanation:

The mission-critical System-

A vital mission program is necessary for an organization's life. If a critical task program disrupted, industrial control should be severely affected.  The essential support device is often referred to as critical task equipment.

Safety system for nuclear reactors-

The nuclear power plant is used to control the system, and it also contains and continues reactions.  It's also usually used only for energy production, and also used experiments and clinical isotope manufacture.  

If another system of nuclear power fails, this could result in a continuous nuclear reaction in a range of aspects like irradiated leaks. These same persons across the area may experience serious radioactivity symptoms.

The main task in their personal life-  

They realize, that without power, they turn down your entire life when you've never encountered a dark off with more than 30 minutes. Essentially, people wouldn't have been allowed to do what you'll do, entirely frozen.  

Consumer survey: big financial transfer controlling business-

That company is the infrastructure and software supplier for banks, traders, distributors, and institutional investors to take out money transfers. With all the money transfers they depend on, you must establish a successful company to become the 'guy behind the button', etc.

Answer:

Because reusing the old passwords possess security threats.

Explanation:

A password can be defined as a string of characters or words or phrases that are used to authenticate the identity of the user. It is also known as passcode and should be kept confidential. A password is used to access constricted systems, applications, etc.

A password or passcode is usually composed of alphabets, numbers, symbols, characters, alphanumeric, or a combination of these.

In the given case, Judy was not able to change her passcode to the previous one because reusing old passwords is prohibited in any sites or systems. A system denies the user to reuse the old passwords for various reasons but most importantly due to security reasons. Though it is said that old passwords can be used after 100 times but seldom someone changes a password that much. All systems care for the security of their users thus they deny reusing old passcodes.

Answer:

The require number of acres is between 220714.991 acres and 4414287.982 acres

Explanation:

Given

Power = 4,000MW

Yield = 10,000lb - 20,000 lb/year

Electricity Efficiency = 35%

Required

Number of acres needed

To calculate the required number of acres, the following steps will be followed.

1. Calculate total energy

2. Calculate the intensity of energy

3. Calculate number of acres.

Calculating the total energy

Energy = Power * Time

From the question;

Power = 4,000MW

The crop yield is measured on a yearly basis. So, time = 1 year.

Convert time to seconds.

First, we convert to days

1 year = 365 days;

Then to hours

= 365 * 24

Then to minutes

= 365 * 24 * 60

Then to seconds

= 365 * 24 * 60 * 60

So,

1 year = 365 * 24 * 60 * 60

1 year = 31,536,000s.

Energy = 4,000 MW * 31,536,000

Emergy = 1.26144E11 MJ

Calculating the intensity of energy.

Energy Intensity = Required Energy * Efficiency

Efficiency = 35%

Calculating Required Energy

When Yield = 10,000 lb

First, we convert this to kilogram

1 lb = 0.453592 kg

10,000 lb = 10,000 * 0.453592

10,000 lb = 4535.92 kg

From energy characterisation factors and method table.

1 kg requires 18 MJ of energy.

4535.92 will require:

4535.92 * 18MJ

= 81646.56 MJ of energy.

Hence, Required Energy = 81646.56 MJ

So, Energy Intensity = 81646.56 MJ * 35%

Energy Intensity = 28576.296 MJ.

Hence, when yield = 10,000 lb; the energy intensity is 28576.296 MJ

When Yield = 20,000 lb

Energy Intensity = Required Energy * Efficiency

If the energy intensity is 28576.296 MJ when yield = 10,000 MJ

Energy Intensity = 2 * 28576.296 MJ

Yield = 2 * 10,000 lb

Hence, Energy Intensity = 2 *28576.296 MJ

Energy Intensity = 57152.592 MJ

Now, the number of acres can be calculated.

Number of acres = Total Energy ÷ Intensity.

Total Energy = 1.26144E11 MJ

When Yield = 10,000 lb, Intensity = 28576.296 MJ

Number of acres = 1.26144E11 ÷ 28576.296

Number of acres = 4414287.982 acres

When Yield = 20,000 lb, Intensity = 57152.592 MJ

Number of acres = 1.26144E11 ÷ 57152.592

Number of acres = 220714.991 acres

Hence, the require number of acres is between 220714.991 acres and 4414287.982 acres

Answer:

Linux is Unix-based and Unix was originally designed to provide an environment that's powerful, stable and reliable yet easy to use. Linux systems are widely known for their stability and reliability, many Linux servers on the Internet have been running for years without failure or even being restarted

Explanation:

Linux is used for commercial networking

Answer:

A. The most secure email message authenticity and confidentiality is provided by signing the message using the sender’s public key and encrypting the message using the receiver’s private key

Explanation:

Public key cryptography helps to send public key in an open and an insecure channel as having a friend's public key helps to encrypt messages to them.

The private key helps to decrypt messages encrypted to you by the other person.

The most secure email message authenticity and confidentiality is provided by signing the message using the sender’s public key and encrypting the message using the receiver’s private key

Answer:

Following are the program in java language that is mention below

Explanation:

import java.util.*;  // import package

public class Half_XmasTree // main class

{

public static void main(String args[])  // main method

{

int k,i1,j1; // variable declaration  

Scanner sc2=new Scanner(System.in);   // create the object of scanner

System.out.println("Enter the Number of rows : ");

k=sc2.nextInt(); // Read input by user

for(i1=0;i1<k;i1++)  //iterating the loop

{

for(j1=0;j1<i1;j1++)  // iterating the loop

System.out.print(" ");

for(int r=k-i1;r>0;r--)  //iterating loop

System.out.print("*");  // print *

System.out.println();

}

}

}

Output:

Following are the attachment of output

Following are the description of program

The Half_XmasTree program illustrates the use of loops

Loops are used for operations that must be repeated until a certain condition is met.

The Half_XmasTree program written in Java where comments are used to explain each action is as follows:

import java.util.*;

public class Half_XmasTree{

public static void main(String args[]){

   //This creates a Scanner object

   Scanner input =new Scanner(System.in);

   //This prompts the user for the number of rows

   System.out.print("Number of rows: ");

   //This gets input the user for the number of rows

   int rows=input.nextInt();

   //The following iteration prints the half x-mas tree

   for(int i=0; i<rows;i++){

       for(int j=0;j<i;j++){

           System.out.print(" ");

       }

       for(int r=rows-i;r>0;r--){

           System.out.print("*");

       }

       System.out.println();

   }

}

}

Read more about loops at:

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