Answer:
5.33 cm
Explanation:
The lens equation states that:
[tex]\frac{1}{f}=\frac{1}{p}+\frac{1}{q}[/tex]
where
f is the focal length
p is the distance of the object from the lens
q is the distance of the image from the lens
In this problem,
p = 8 cm
q = 16 cm ( the sign is positive since the image is real, which means it is formed on the other side of the lens)
Substituting into the equation,
[tex]\frac{1}{f}=\frac{1}{8 cm}+\frac{1}{16 cm}=\frac{3}{16 cm}[/tex]
[tex]f=\frac{16}{3}cm=5.33 cm[/tex]
Bernoulli's principle can be used to explain the lift force on an airplane wing. How must an airplane's wing be designed to ensure that Bernoulli's principle is applicable? Bernoulli's principle can be used to explain the lift force on an airplane wing. How must an airplane's wing be designed to ensure that Bernoulli's principle is applicable? Airplane wings must be designed to ensure that air molecules move more rapidly over the top surface of the wing, creating a region of lower pressure. Airplane wings must be designed to ensure that air molecules are deflected downward after hitting the wing. Airplane wings must be designed to ensure that air molecules move more rapidly past the bottom surface of the wing, creating a region of higher pressure. Airplane wings must be designed to ensure that air molecules are deflected upward after hitting the wing. Airplane wings must be designed so that they are thick enough to ensure a significant pressure difference between the top and bottom surfaces of the wings.
Answer:
Airplane wings must be designed to ensure that air molecules move more rapidly over the top surface of the wing, creating a region of lower pressure.
Explanation:
Answer:
Airplane wings must be designed to ensure that air molecules move more rapidly over the top surface of the wing, creating a region of lower pressure.
Explanation:
Swiss physicist Daniel Bernoulli proposed a principle for fluid flow, which can be stated as follows: "If the speed of a fluid particle increases as it flows along a current line, the fluid pressure must decrease and vice versa".
This knowledge allows us to understand why airplanes are able to fly. In the upper part of the wing the air velocity is higher (the particles travel a greater distance at the same time), therefore, the pressure on the upper surface is less than on the lower surface, which ends up creating a holding force from below to up.
With this principle, we can say that the wings of the airplane must be designed to ensure that air molecules move more quickly over the upper surface of the wing, creating a region of less pressure.
Dos bolas, de masas mA = 40 g y mB =60 g, esta?n suspendidas como se observa en la figura. La bola ma?s ligera se jala en un a?ngulo de 60° con respecto a la vertical y se libera. A) ?Cua?l es la velocidad de la bola ma?s ligera antes del impacto? B) ?Cua?l es la velocidad de cada bola despue?s de la colisio?n ela?stica? C) ?Cua?l sera? la altura ma?xima de cada bola despue?s de la colisio?n ela?stica?
The conservation laws of energy, momentum, and kinetic energy are used to determine pre-collision and post-collision velocities of two balls, as well as their maximum heights after an elastic collision.
Explanation:The student has asked about the velocities of two balls before and after an elastic collision and the maximum height they reach after the collision. Assuming no air resistance, the conservation of energy principle can be used to find the initial velocity of the lighter ball by equating potential energy at 60° to kinetic energy at the point just before impact.
Afterward, the conservation of momentum and kinetic energy can be used to determine the velocities of both balls post-collision. The final velocities can then be used with the conservation of energy again to find the maximum height each ball reaches after the elastic collision.
It's important to remember that, for an elastic collision, both conservation of momentum and conservation of kinetic energy hold true. So, the total kinetic energy before and after the collision remains constant, as well as the total momentum of the system. Applying these laws yields the final velocities for each mass, and subsequently, energy conservation can determine the maximum heights.
Which is an example of a mixture? A. water B. trail mix C. hydrogen D. carbon dioxide
B. trail mix
because you can easily take all the peaces out unlike water you cant physically take the oxygen out
please make me the brainliest
What is the difference between transverse and longitudinal waves?
Transverse waves always carry more energy than do longitudinal waves.
Transverse waves always travel at smaller speeds than do longitudinal waves.
Transverse waves always have greater frequencies than do longitudinal waves.
In a transverse wave the disturbance always occurs parallel to the line of travel of the wave, whereas in a longitudinal wave the disturbance always occurs perpendicular to the direction in which the wave travels.
In a transverse wave the disturbance always occurs perpendicular to the direction in which the wave travels, whereas in a longitudinal wave the disturbance always occurs parallel to the line of travel of the wave.
is there any multiple choice answers
A light beam travels at 1.94×108 in quartz. The wavelength of the light in quartz is 355 .Part AWhat is the index of refraction of quartz at this wavelength?Part BIf this same light travels through air, what is its wavelength there?
A) 1.55
The speed of light in a medium is given by:
[tex]v=\frac{c}{n}[/tex]
where
[tex]c=3\cdot 10^8 m/s[/tex] is the speed of light in a vacuum
n is the refractive index of the material
In this problem, the speed of light in quartz is
[tex]v=1.94\cdot 10^8 m/s[/tex]
So we can re-arrange the previous formula to find n, the index of refraction of quartz:
[tex]n=\frac{c}{v}=\frac{3\cdot 10^8 m/s}{1.94\cdot 10^8 m/s}=1.55[/tex]
B) 550.3 nm
The relationship between the wavelength of the light in air and in quartz is
[tex]\lambda=\frac{\lambda_0}{n}[/tex]
where
[tex]\lambda[/tex] is the wavelenght in quartz
[tex]\lambda_0[/tex] is the wavelength in air
n is the refractive index
For the light in this problem, we have
[tex]\lambda=355 nm\\n=1.55[/tex]
Therefore, we can re-arrange the equation to find [tex]\lambda_0[/tex], the wavelength in air:
[tex]\lambda_0 = n\lambda=(1.55)(355 nm)=550.3 nm[/tex]
Final answer:
The index of refraction of quartz at the given wavelength is approximately 1.55. The wavelength of the same light in air would be approximately 549 nm.
Explanation:
Part A: Index of Refraction of Quartz
The index of refraction (n) is given by the formula n = c/v, where c is the speed of light in a vacuum, and v is the speed of light in the material. Here, we are given the speed of light in a quartz (v_quartz) as 1.94×108 m/s. Using the speed of light in a vacuum (c) as 3.00×108 m/s, we can calculate the index of refraction of quartz as follows:
n_quartz = c / v_quartz
n_quartz = (3.00×108 m/s) / (1.94×108 m/s)
n_quartz = 1.55
Part B: Wavelength in Air
Since the frequency of light remains constant when transitioning between mediums, its wavelength in air (λ_air) can be found using the same frequency. Using the formula λ = v/f, where v_air is the speed of light in air and f is the frequency, we get:
λ_air = c / f
Since c = v_air and n_quartz = c / v_quartz,
we can write
f = v_quartz / λ_quartz
Now, plug the value of f back into the first equation:
λ_air = v_air / (v_quartz / λ_quartz)
λ_air = (3.00×108 m/s) / (1.94×108 m/s) × 355 nm
λ_air ≈ 549 nm
The product nuclei may or may not be _______
Answer:
i have no clue
Explanation:
An unknown particle moves in a straight line through crossed electric and magnetic fields with e = 1.5 kv/m and b = 0.034 t. if the electric field is turned off, the particle moves in a circular path of radius r = 2.7 cm. what might the particle be
Answer:
Alpha particle
Explanation:
Initially, the particle moves in a straight line. This means that the electric force and the magnetic force are equal:
[tex]qE=qvB[/tex]
where q is the charge, E is the electric field, v is the speed and B is the magnetic field.
In this problem,
E = 1.5 kV/m = 1500 V/m
B = 0.034 T
Solving the equation for v we find the speed of the particle
[tex]v=\frac{E}{B}=\frac{1500 V/m}{0.034 T}=4.41\cdot 10^4 m/s[/tex]
Now the electric field is turned off, so the particle starts moving in a circular motion, where the magnetic force acts as centripetal force:
[tex]qvB=m\frac{v^2}{r}[/tex]
where
r = 2.7 cm = 0.027 m is the radius of the circular path
Solving the problem for q/m, we find charge-to-mass ratio of the particle
[tex]\frac{q}{m}=\frac{v}{Br}=\frac{4.41\cdot 10^4 m/s}{(0.034 T)(0.027 m)}=4.8\cdot 10^7 C/kg[/tex]
And this corresponds to the q/m ratio of an alpha particle, which has:
[tex]q=2e=3.2\cdot 10^{-19}C\\m=4a.m.u.=6.64\cdot 10^{-27} kg[/tex]
The mass of the particle depends on the type of particle, and the radius of
the path of the particle depend on its mass.
The particle might be an alpha particle.
Reasons:
The given parameters are;
Electric potential of the field, E = 1.5 kV/m
Magnetic field strength, B = 0.034 T
Radius of the circular path, r = 2.7 cm
Required:
Finding the type of particle in the question
Solution:
When moving in a straight line, we have;
B·q·v = F = q·E
Therefore;
E = B·v
When the particle moves in a circular path, we have;
[tex]q\cdot E = B \cdot q \cdot v = \mathbf{\dfrac{m \cdot v^2}{r}}[/tex]
Therefore;
[tex]v = \dfrac{B \cdot q \cdot r }{m}[/tex]
Which gives;
[tex]E = \dfrac{B \cdot q \cdot r }{m} \times B = \dfrac{B^2 \cdot q \cdot r }{m}[/tex]
[tex]\mathrm{The \ mass \ of \ the \ particle, \, m} = \mathbf{\dfrac{B^2 \cdot q \cdot r }{E}}[/tex]
q = n × e
Therefore;
[tex]m = \mathbf{\dfrac{B^2 \cdot n \cdot e \cdot r }{E}}[/tex]
Where;
n = The number of electron charge
Which gives the mass in kilograms as follows;
[tex]m = \dfrac{0.034^2 \times n\times 1.6 \times 10^{-19} \times 0.027 }{1500} = \mathbf{3.32928 \times 10^{-27} \times n}[/tex]
The particle is larger than a subatomic particle
Therefore;
[tex]\dfrac{m}{n} = 3.32928 \times 10^{-27}[/tex]
For an alpha particle, we have;
m ≈ 6.645 × 10⁻²⁷ kg
n = 2
n = 2
Therefore;
[tex]\dfrac{6.645 \times 10^{-27}}{2} \approx \mathbf{3.3225 \times 10^{-27}} \approx 3.32928 \times 10^{-27}[/tex]
Therefore, the particle might be an alpha particle.
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Some elements have a low degree of freedom and high intermolecular forces between its molecules. These elements are ________ at room temperature.
Solid
Explanation;Some elements have a low degree of freedom and high intermolecular forces between its molecules. These elements are solid at room temperature.Elements can be classified based on physical states, or the states of matter. At room temperature and pressure the Physical States, or states of matter, are solids, gases or liquids and these are referred to as the 3 states of matter. Some elements such as most metals are solids at room temperatures, others such as oxygen, hydrogen, nitrogen, etc are a gases and others are liquids.Answer: Solid
Explanation:
because solids particles close together making it harder for them to move.
Which shows the formula for converting from degrees Celsius to degrees Fahrenheit?
This is a question that makes us REALLY want to know what "Which" means.
If you included a list of answer choices with your question, then the correct formula isn't on it.
The formula for converting temperature from degrees Celsius to degrees Fahrenheit is:
°F = 1.8 · (°C) + 32
Explanation:
The two scales for measuring the temperature of an object are Celsius scale and Fahrenheit scale. Mathematically, it can be written as :
[tex]^{\circ} F=(\dfrac{9}{5}\times ^{\circ}C)+32[/tex]
Where
°F = degree Fahrenheit
°C = degree Celsius
For example, if T = 30°C. It can be converted to °F as :
[tex]^{\circ} F=(\dfrac{9}{5}\times 30)+32[/tex]
[tex]^{\circ} F=86[/tex]
So, 30°C is equal to 86 Fahrenheit. Hence, this is the required solution.
Participating in team sports can have a positive effect on all aspects of life. Please select the best answer from the choices provided. T F
Answer: True
Explanation:
Participating in team sports can lead to the development of healthy fellowship and brotherhood behavior among the participants. It induces team spirit and allows to lead a healthy competition. It can be a good recreational activity which can be used for removing the emotional and physiological stress. Hence, can improve positivity in all aspects of life.
If the mass of the earth and all objects on it were suddenly doubled, but the size remained the same, the acceleration due to gravity at the surface would become
A) 1/2 of what it now is.
B) 2 times what it now is.
C) 1/4 of what it now is.
D) the same as it now is.
E) 4 times what it now is.
its a i just have to type more but its a
The answer is B) 2 times what it is now.
You can increase the capacitance of a capacitor by A. Decreasing the plate spacing B. Increasing the plate spacing. ° C. Decreasing the area of the plates. D. Increasing the area of the plates. E. Both A and D F. Both B and C
You can increase the capacitance of a capacitor by decreasing the plate spacing (A) or by increasing the area of the plates (D).
'A' and 'D' both do the job, so the correct choice is (E) .
Capacitance is the effect of a capacitor. We can increase the capacitance of the capacitor by decreasing the plate spacing and by increasing the area of the plates.
What is capacitance?The capacitance is the effect of a capacitor, while a capacitor is a device that stores the electrical energy into it. The energy stored in a capacitor can be calculated by the formula,
[tex]U = \dfrac{1 \times Q^2}{2 \times C} = \dfrac{1 \times Q}{2 \times V} = \dfrac{1}{2}CV^2[/tex]
What affects the capacitance of a capacitor?The following things affect the capacitance of a capacitor:
The area of the plates, (Directly proportional).The distance between the plates, (Inversely proportional).The ability of the dielectric to support electrostatic forces (the dielectric).Thus, We can increase the capacitance of the capacitor by decreasing the plate spacing and by increasing the area of the plates.
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The work function for silver is 4.73 eV. (a) Find the cutoff wavelength for silver. (b) What is the lowest frequency of light incident on silver that releases photoelectrons from its surface? Hz (c) If photons of energy 6.41 eV are incident on silver, what is the maximum kinetic energy of the ejected photoelectrons? eV
(a) 263 nm
First of all, let's convert the work function for silver from eV to Joules:
[tex]\phi = 4.73 eV \cdot (1.6\cdot 10^{-19} J/eV)=7.57\cdot 10^{-19} J[/tex]
The energy of the incoming photon is given by:
[tex]E=\frac{hc}{\lambda}[/tex]
where h is the Planck constant, c is the speed of light, [tex]\lambda[/tex] is the photon's wavelength.
The cutoff wavelength is the minimum wavelength for which the photon has enough energy to extract the photoelectron from the material: that means, the wavelength at which the energy of the photon is at least equal to the work function of the material,
[tex]E=\phi[/tex]
Substituting and solving for the wavelength,
[tex]\frac{hc}{\lambda}=\phi\\\lambda=\frac{hc}{\phi}=\frac{(6.63\cdot 10^{-34}Js)(3\cdot 10^8 m/s)}{7.57\cdot 10^{-19} J}=2.63\cdot 10^{-7} m = 263 nm[/tex]
(b) [tex]1.14\cdot 10^{15}Hz[/tex]
The lowest frequency of light incident on silver that releases photoelectrons from its surface is the frequency corresponding to the wavelength we found at point (a); using the relationship between frequency and wavelength:
[tex]f = \frac{c}{\lambda}[/tex]
And substituting numbers, we find
[tex]f = \frac{3\cdot 10^8 m/s}{2.63\cdot 10^{-7} m}=1.14\cdot 10^{15}Hz[/tex]
(c) 1.68 eV
The equation for the photoelectric effect is:
[tex]E=\phi + K_{max}[/tex]
where
E is the energy of the incoming photon
[tex]\phi[/tex] is the work function
[tex]K_max[/tex] is the maximum kinetic energy of the photoelectrons
Since
E = 6.41 eV
[tex]\phi = 4.73 eV[/tex]
The maximum kinetic energy of the photoelectrons is
[tex]K_{max}=E-\phi=6.41 eV-4.73 eV=1.68 eV[/tex]
Strip electrons from an atom and the atom becomes a
It becomes a positive ion
A simple ideal Brayton cycle uses argon as the working fluid. At the beginning of the compression, P1 = 15 psia and T1 = 70°F, the maximum cycle temperature is 1220°F, and the pressure in the combustion chamber is 150 psia. The argon enters the compressor through a 3 ft2 opening with a velocity of 200 ft/s. Determine the rate at which entropy is generated by the cycle. The temperature of the source is the same as the maximum cycle temperature, and the temperature of the sink is the same as the minimum cycle temperature.
Entropy generation in an ideal Brayton cycle is zero since all processes are reversible and there are no irreversibilities within the system to generate entropy.
Explanation:The student's question relates to finding the rate of entropy generation for an ideal Brayton cycle using argon as the working fluid. However, the Brayton cycle, as an ideal cycle, does not lead to entropy generation within the system because all processes are reversible. Entropy may change as heat crosses the system boundaries, but this is not the same as entropy generation due to irreversibilities. Calculating entropy changes in an actual Brayton cycle requires knowledge of each process's irreversibilities, which cannot be determined without additional data on the components' efficiencies and the specific entropy values of argon at the given states. Further calculations for ideal processes can be simplified using the assumption of adiabatic and isentropic compression and expansion.
Which wave requires a physical medium through which to travel?
Sound wave requires a physical medium to travel.
What is sound wave?A sound wave can be defined to be comprises of substituting compressions and rarefactions or areas of high and low pressure, moving at a specific speed. Sound wave also comprises of an occasional (that is, wavering or vibrating) variety of pressure happening around the balance pressure winning at a specific time and spot.Sound wave requires a medium in order to propagate while the light wave doesn't need the medium to propagate.Sound is a longitudinal wave.Basically Sound is a energy which moves from one point to the another in the form of wave.The intensity of sound will be completely different.E.g: Cell phone ringing - It gives both sound wave, vibrations, pressure, etc..Sound can be differentiated according to the intensities.Waves below 20 Hz are called infrasonic waves (infrasound), while higher frequencies above 20,000 Hz are known as ultrasonic waves (ultrasound).
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What type of heat transfer occurs when particles bump into each other?
A.Convection
B.Insulation
C.Thermal Conduction
D.Thermal Radiation
What type of heat transfer occurs when particles bump into each other?
A.Convection
B.Insulation
C.Thermal Conduction
D.Thermal Radiation
Thermal conduction.
The particles bump into nearby particles and make them vibrate more which passes through the substance from the hot end to the cold end
A total charge of 6.3×10−8 C is distributed uniformly throughout a 2.7-cm radius sphere. The
volume charge density is:
Answer:
The volume charge density of the sphere is [tex]7.64\times 10^{-4}\ C/m^3[/tex].
Explanation:
It is given that,
Charge, [tex]q=6.3\times 10^{-8}\ C[/tex]
Radius of the sphere, r = 2.7 cm = 0.027 m
Total charge contained divided by its volume is called volume charge density. Mathematically, it is given by :
[tex]\rho=\dfrac{Q}{V}[/tex]
[tex]\rho=\dfrac{Q}{4/3\pi r^3}[/tex]
[tex]\rho=\dfrac{6.3\times 10^{-8}}{4/3\pi (0.027)^3}[/tex]
[tex]\rho=7.64\times 10^{-4}\ C/m^3[/tex]
So, the volume charge density of the sphere is [tex]7.64\times 10^{-4}\ C/m^3[/tex]. Hence, this is the required solution.
Viewers of Star Trek hear of an antimatter drive on the Starship Enterprise. One possibility for such a futuristic energy source is to store antimatter charged particles in a vacuum chamber, circulating in a magnetic field, and then extract them as needed. Antimatter annihilates with normal matter, producing pure energy. What strength (in T) magnetic field is needed to hold antiprotons, moving at 5.70 ✕ 107 m/s in a circular path 2.60 m in radius? Antiprotons have the same mass as protons but the opposite (negative) charge. (Enter the magnitude.)
Answer:
0.23 T
Explanation:
The magnetic force exerted on the antiproton must be equal to the centripetal force, since it is a circular motion, therefore we can write:
[tex]qvB = m\frac{v^2}{r}[/tex]
where
[tex]q=1.6\cdot 10^{-19}C[/tex] is the charge of the antiprotons
[tex]v=5.70\cdot 10^7 m/s[/tex] is the speed of the antiprotons
B is the magnitude of the magnetic field
[tex]m=1.67\cdot 10^{-27}kg[/tex] is the antiproton mass
r = 2.60 m is the radius of the orbit
Solving the equation for B, we find the strength of the magnetic field:
[tex]B=\frac{mv}{qr}=\frac{(1.67\cdot 10^{-27} kg)(5.70\cdot 10^7 m/s)}{(1.6\cdot 10^{-19}C)(2.60 m)}=0.23 T[/tex]
To hold antiprotons in a magnetic field, while moving at 5.70 × 10⁷ m/s in a circular path of radius 2.60 m, the strength of the magnetic field required is approximately 0.60 T.
Explanation:The question deals with the concept of holding antiprotons in a magnetic field, typically a topic in physics related to magnetic force on charged particles. The formula governing this phenomenon is F = qvBsin(θ), where F is the magnetic force, q is the charge, v is the speed, B is the magnetic field strength, and θ is the angle between the velocity and the magnetic field.
Here, sin(θ) is 1 because the field and velocity are perpendicular. The force in this case is a centripetal force because the particle is moving in a circle, so F can be equated to mv²/r. Solving for B, we have B = mv/(qr).
Given that the speed (v) of the antiprotons is 5.70 × 10⁷ m/s and the radius (r) of the circular path is 2.60 m, the mass (m) of a proton (same as an antiproton) is 1.67 × 10⁻²⁷ kg, and the charge (q) equivalent to the basic charge of an electron is 1.60 x 10⁻¹⁹ C, we can substitute these values into the equation:
B = (1.67 × 10⁻²⁷ kg × 5.70 × 10⁷ m/s) / (1.60 x 10⁻¹⁹ C × 2.60 m) ≈ 0.60 T (or Tesla)
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Based on the model you saw in the study, predict what will happen to the motion of the water molecules as the temperature decreases?
From the information given about the topic I would say that the molecules will move more quickly.
The molecules will move more slowly
Can work be done on a system if there is no motion?
there is no motion in the direction of the force, then no work is done by that force. ... But the work done on the box is zero since by moving in a straight line at constant speed, its energy is remaining the same.
Work can be performed on a system without observable motion. An example of this is potential energy, where work is spent to change an object's state even if it doesn't result in movement. However, in general physics, work is defined as force multiplied by displacement.
Yes, work can be done on a system even if there is no observable motion. This is often the case when an object is experiencing balanced forces, meaning it remains static or in a state of Static Equilibrium. For instance, if you push a wall, you are exerting energy and doing 'work' but since the wall doesn't move, there is no physical work done.
Another example is potential energy, which is considered as 'stored energy'. It can be associated with the work done to change the position or state of an object, like stretching a spring or lifting a boulder; in these cases work is done even if there isn't resultant motion.
However, in physics, work is technically defined as the product of the force applied to an object and the distance over which that force is applied. Thus, if there is no movement or displacement, then no work is done according to the work-energy theorem. So, defining 'work' might be dependent on the context or specifics of a given problem.
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TRUE OR FALSE? earth revolves around the sun tilted on its axis
The axis of the Earth's rotation is tilted relative to the plain of the Earth's revolution around the Sun.
The question is worded very poorly, but you'd have to say it's TRUE.
True. The tilt of the axis is what leads to varying seasons around the year.
Jorge traveled 5 miles to school. After school, he traveled 1 mile to the Boys and Girls club and then traveled 6 miles back home. What was the distance of Jorge’s trip?
A. 0 miles
B. 5 miles
C. 11 miles
D. 12 miles
I'm not completely sure what you mean by his "trip".
You've described three trips that day:
==> from home to school
==> from school to the club, and
==> from the club to home.
You also clearly listed the distance for each of those trips, so I don't think that's what you're asking.
I think you're asking about Jorge's total distance for the day, after he finished all three trips.
That distance is (5mi + 1mi + 6mi) = 12 miles. (choice-D)
A gas bottle contains 0.650 mol of gas at 730 mm Hg pressure. If the final pressure is 1.15 atm, how many moles of gas were added to the bottle?
Answer: 0.129 moles of gas were added to the bottle
Explanation:
According to the ideal gas equation:'
[tex]PV=nRT[/tex]
P = Pressure of the gas
V= Volume of the gas
T= Temperature of the gas
R= Gas constant
n= moles of gas
As Volume , gas constant and temperature are constant
[tex]\frac{P_1}{n_1}=\frac{P_2}{n _2}[/tex]
where,
[tex]P_1[/tex] = initial pressure of gas =730 mm Hg =0.960 atm (760 mmHg = 1 atm)
[tex]P_2[/tex] = final pressure of gas = 1.15 atm
[tex]n_1[/tex] = initial number of moles = 0.650
[tex]n_2[/tex] = final number of moles = ?
Now put all the given values in the above equation, we get the final moles of gas.
[tex]\frac{0.960}{0.650}=\frac{1.15}{n_2}[/tex]
[tex]n_2=0.779[/tex]
Therefore, the number of moles of gas will be 0.779
Thus moles of gas were added to the bottle are (0.779-0.650) = 0.129
Final answer:
To determine how many moles of gas were added to the gas bottle, we used the Ideal Gas Law relation between pressure and moles, converting pressures to the same units and found approximately 0.129 moles were added.
Explanation:
To determine how many moles of gas were added to the bottle, we can use the Ideal Gas Law: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature. Since the volume and temperature of the gas are constant (not mentioned in the problem, so assumed constant), the relationship between pressure and moles of gas is a direct one. This means that by dividing the final pressure by the initial pressure, we should get the ratio of the final moles to the initial moles.
Firstly, we need to make sure pressure units are consistent. We convert the initial pressure from mm Hg to atm: 730 mm Hg × (1 atm / 760 mm Hg) = 0.9605 atm.
Now, we use the ratio of the pressures to find out the number of moles after additional gas was added:
Initial moles (ni) = 0.650 mol at Pi = 0.9605 atm
Final pressure (Pf) = 1.15 atm
Ratio of pressures = Pf / Pi = 1.15 atm / 0.9605 atm
Final moles (nf) = ni × (Pf / Pi)
nf = 0.650 mol × (1.15 / 0.9605)
nf ≈ 0.779 moles
The amount of moles added can be found by subtracting the initial moles from the final moles:
n added = nf - ni
n added = 0.779 mol - 0.650 mol
n added ≈ 0.129 moles
If a certain material heats up quickly and cools down quickly, the material likely has
Low specific heat in the material
Which of the following are found within the electromagnetic spectrum? Check all that apply. sound waves visible light X rays ultraviolet radiation gamma rays microwave radiation
Answer:
Visible light
X rays
ultraviolet radiation
gamma rays
microwave radiation
Explanation:
Electromagnetic waves consist of oscillating electric and magnetic fields which vibrate in a direction perpendicular to the direction of motion of the wave (transverse wave). Electromagnetic waves have all same speed in a vacuum ([tex]c=3.0\cdot 10^8 m/s[/tex], known as speed of light) and are classified into 7 different types according to their frequency and wavelength. This classification is called electromagnetic spectrum.
From lowest to highest wavelength, the 7 types are:
Gamma rays
X-rays
Ultraviolet radiation
Visible light
Infrared radiation
Microwaves
Radio waves
Sound waves, on the contrary, do not belong to the electromagnetic spectrum, since they are another type of wave called mechanical waves (which consist of vibrations of the particles in a medium).
In a crystal of salt there are electrons and positive ions. How does the net charge of the electrons compare with the net charge of the ions?
Final answer:
In a crystal of salt, the net charge of the electrons is equal to the net charge of the ions, resulting in a zero net charge due to the formation of ionic bonds between oppositely charged ions.
Explanation:
In a crystal of salt, such as sodium chloride (NaCl), the net charge of the electrons compares with the net charge of the ions to ensure overall electrical neutrality. Each sodium ion (Na+) loses one electron becoming positively charged, while each chlorine ion (Cl-) gains an electron becoming negatively charged. There is an equal number of Na+ and Cl- ions, resulting in a balanced, zero net charge within the crystalline structure.
Salt crystals are formed through ionic bonds, which occur when metals like sodium lose electrons to become positively charged, and nonmetals like chlorine gain electrons to achieve a negatively charged state. The opposite charges attract, creating a strong electrostatic force that holds the ions together. Ionic compounds are electrically neutral because of this balance between the positively and negatively charged ions.
Nuclei that lie outside the ______ undergo spontaneous radioactive decay.
Nuclei outside the band of stability undergo radioactive decay, transforming into more stable isotopes. Instability does not necessarily mean rapid decay, as exemplified by uranium-238. Unstable nuclides like those experiencing beta decay transform into other elements or isotopes through the process of radioactive transformation.
Nuclei that lie outside the band of stability undergo spontaneous radioactive decay. These unstable nuclei that are to the left or to the right of the band on the chart of nuclides will transform into other nuclei that are in, or closer to, a state of stability. This decay changes the number of protons and neutrons in the nucleus, resulting in a different element or isotope that is more stable.
It's important to note that being "unstable" does not necessarily imply a substance will decay quickly. For instance, uranium-238 is a prime example of an unstable nucleus due to its ability to decay over a stretched period; while it is unstable, it does not instantly decompose.
All forms of beta decay are a consequence of the parent nuclide's instability, leading to a transformation that results in a subsequent product of decay. Terms like "radioactive transformation" may be more accurate than "decay," since the process involves the original nucleus splitting into new nuclei rather than vanishing entirely.
A batter hits a foul ball. The 0.140-kg baseball that was approaching him at 40.0 m/s leaves the bat at 30.0 m/s in a direction perpendicular to the line between the batter and the pitcher. What is the magnitude of the impulse delivered to the baseball?
Given in the question,
mass of foul ball = 0.140 kg
initial speed with which ball was hit with the bat = 30 m/s
final speed = 40 m/s
According to the scenario the whole scene is making a right angle triangle
So, to the solve the question we will use pythagorus theorem
Hypotenuse² = base² + height²Here,
Hypotenuse= Magnitude of impulse
Base = 1st change of momentum
height = 2nd change of momentum
1st impulse (1st change of momentum)
p = m(1)v(1) = (0.14 kg)(40.0 m/s) = 5.6 kg m / s = 5.6 N s
2nd impulse (2nd change of momentum)
p = m(2)v(2) = (0.14 kg)(30.0 m/s) = 4.2 kg m / s = 4.2 N s
Magnitude of impulse (hypotenuse of triangle)
impulse² = (5.6)² + (4.2)²
impulse² = 31.36 + 17.64
impulse² = 49
impulse² = √49
impulse = 7.0 N s
The magnitude of the impulse delivered to the baseball by applying the impulse-momentum theorem is calculated to be 9.8 kg.m/s.
Explanation:The magnitude of the impulse delivered to the baseball can be found by applying the impulse-momentum theorem. The theorem asserts that the change in momentum of an object equals the impulse imposed on it. In the context of this question, the momentum change is the final momentum minus the initial one (m*(vf) - m*(vi)). This equals 0.140 Kg * 30.0 m/s - (-0.140 Kg * 40.0 m/s). Calculating this we get 9.8 kg.m/s as the magnitude of the impulse delivered to the baseball.
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What are the three major categories of galaxies?
On 1930 the astronomer Edwin Hubble classified the galaxies into elliptical, spiral and irregular, being the first two classes the most frequent.
However, it should be noted that this classification is based only on the visual appearance of the galaxy, and does not take into account other aspects, such as the rate of star formation or the activity of the galactic nucleus.
The classification is as follows:
1. Elliptical galaxies:Their main characteristic is that the concentration of stars decreases from the nucleus, which is small and very bright, towards its edges. In addition, they contain a large population of old stars, usually little gas and dust, and some newly formed stars.
They are symbolized by the letter E and subdivided into eight classes, from E0 with zero eccentricity (spherical) to E7 (called husiform).
2. Spiral galaxies:They have the shape of flattened disks containing some old stars and also a large population of young stars, enough gas and dust, and molecular clouds that are the birthplace of the stars.
They are symbolized with the letter S and depending on the minor or major development that each arm possesses, it is assigned a letter: a, b or c (for example: Sa, Sb, Sc, SBa, SBb, SBc).
These galaxies, are also divided into two types:
-Lenticular galaxies
-Barred spiral galaxies
3. Irregular Galaxies:They are symbolized by the letter I (or IR), although they are usually dwarf or rare and do not have well-defined structure and symmetry.
They are classified in:
-Irregular type 1 (Magellanic), which contain large numbers of young stars and interstellar matter.
-Regular type 2, less frequent and whose content is difficult to identify.
This type of irregular galaxies are generally located close to larger galaxies, and usually contain large amounts of young stars, gas and cosmic dust.