Answer:
See Explaination
Explanation:
a) Assume there are n nits each in x and y.SO we divide them into n/2 and n/2 bits.
x = xL * 2^{n/2} + xR
y = yL * 2^{n/2} + yR
x.y = 2^{n}.(xL.yL) + 2^{n/2}.(xL.yR + xR.yL) +(xR.yR)
If you see there are 4 multiplications of size n/2 and we took all other additions and subtractions as O(n).
So T(n) = 4*T(n/2) + O(n)
Now lets find run time using master theorem.
T(n) = a* T(n/b) + O(n^{d})
a = 4
b = 2
d = 1
if a > b^{d}
T(n) = O(n^v) where v is log a base b
In our case T(n) = O(n^v) v = 2
=> T(n) = O(n^{2})
The splittinng method is not benefecial if we solve by this way as the run time is same even if go by the naive approach
b)
x.y = 2^{n}.(xL.yL) + 2^{n/2}.((xL+xR).(yL+yR)-(xL.yL) - (xR.yR)) +(xR.yR)
Here we are doing only three multipliactions as we changed the term.
So T(n) = 3*T(n/2) + O(n)
a = 3
b = 2
d = 1
if a > b^{d}
T(n) = O(n^v) where v is log a base b
In our case T(n) = O(n^v) v = log 3 base 2
v = 1.584
So T(n) = O(n^{1.584})
As we can see this is better than O(n^{2}).Therefore this algorithm is better than the naive approach.
Write an application that inputs a telephone number as a string in the form (555) 555-5555. The application should use String method split to extract the area code as a token, the first three digits of the phone number as a token and the last four digits of the phone number as a token. The seven digits of the phone number should be concatenated into one string. Both the area code and the phone number should be printed. Remember that you will have to change deliminator characters during the tokenization process.
Answer:
See explaination
Explanation:
// File: TelephoneNumber.java
import java.util.Scanner;
public class TelephoneNumber
{
public static void main(String[] args)
{
Scanner input = new Scanner(System.in);
String inputNumber;
String tokens1[];
String tokens2[];
String areaCode;
String firstThree;
String lastFour;
String allSeven;
String fullNumber;
/* input a telephone number as a string in the form (555) 555-5555BsAt4ube4GblQIAAAAASUVORK5CYII= */
System.out.print("Enter a telephone number as '(XXX) XXX-XXXX': ");
inputNumber = input.nextLine();
System.out.println();
/* use String method split */
tokens1 = inputNumber.split(" ");
/* extract the area code as a token */
areaCode = tokens1[0].substring(1, 4);
/* use String method split */
tokens2 = tokens1[1].split("-");
/* extract the first three digits of the phone number as a token */
firstThree = tokens2[0];
/* extract the last four digits of the phone number as a token */
lastFour = tokens2[1];
/* concatenate the seven digits of the phone number into one string */
allSeven = firstThree + lastFour;
/* concatenate both the area code and the seven digits of the phone number into one full string separated by one space */
fullNumber = areaCode + " " + allSeven;
/* print both the area code and the phone number */
System.out.println("Area code: " + areaCode);
System.out.println("Phone number: " + allSeven);
System.out.println("Full Phone number: " + fullNumber);
}
}
Create a public non-final class called InsertionSorter. It should provide one public class method called sort. Sort should accept an array of Comparable Java objects and sort them in ascending order. However, it should sort the array in place, meaning that you modify the original array, and return the number of swaps required to sort the array. That’s how we’ll know you’ve correctly implemented insertion sort. If the array is null or empty you should return 0. You can assume that the array does not contain any null values.
Answer:
See explaination
Explanation:
public class InsertionSorter {
/* Function to sort array using insertion sort */
int sort(Comparable arr[]) {
int count = 0;
if (arr == null || arr.length == 0)
return 0;
int n = arr.length;
for (int i = 1; i < n; ++i) {
Comparable key = arr[i];
int j = i - 1;
while (j >= 0 && arr[j].compareTo(key) > 0) {
count++;
arr[j + 1] = arr[j];
j = j - 1;
}
arr[j + 1] = key;
}
return count;
}
// Driver method
public static void main(String args[]) {
Integer arr[] = { 50,21,34,26, 18, 31, 37, 54 };
InsertionSorter ob = new InsertionSorter();
int comp = ob.sort(arr);
System.out.println("Comparisons required : "+comp);
for(int i:arr)
System.out.print(i+" ");
}
}
g What field in the IPv4 datagram header can be used to ensure that a packet is forwarded through no more than N routers? When a large datagram is fragmented into multiple smaller datagrams, where are these smaller datagrams reassembled into a single larger datagram? Do routers have IP addresses? If so, how many? How many bits do we have in an IPv6 address? We use hexadecimal digits (each with 4 bits) to represent an IPv6 address. How many hexadecimal digits do we need to represent an IPv6 address?
Answer:
a) Time to live field
b) Destination
c) Yes, they have two ip addresses.
d) 128 bits
e) 32 hexadecimal digits
Explanation:
a) the time to live field (TTL) indicates how long a packet can survive in a network and whether the packet should be discarded. The TTL is filled to limit the number of packets passing through N routers.
b) When a large datagram is fragmented into multiple smaller datagrams, they are reassembled at the destination into a single large datagram before beung passed to the next layer.
c) Yes, each router has a unique IP address that can be used to identify it. Each router has two IP addresses, each assigned to the wide area network interface and the local area network interface.
d) IPv6 addresses are represented by eight our characters hexadecimal numbers. Each hexadecimal number have 16 bits making a total of 128 bits (8 × 16)
e) IPv6 address has 32 hexadecimal digits with 4 bits/hex digit
The TCP/IP concepts of packet forwarding, fragmentation, and reassembly along with IPv4 and IPv6 addressing schemes are explained.
TTL (Time To Live) field in the IPv4 datagram header can be used to ensure that a packet is forwarded through no more than N routers. When a large datagram is fragmented into multiple smaller datagrams, these smaller datagrams are reassembled into a single larger datagram at the destination host. Routers do have IP addresses, typically one per interface, so the number varies. IPv6 addresses consist of 128 bits; represented using hexadecimal digits (each 4 bits), hence we need 32 hexadecimal digits to represent an IPv6 address.
When Judy logged on the network, she faced the message requesting that she changes her password. So, she changed her password. But, she does not like to remember too many passwords. She wants to keep only one password. So, she tried to change the password again to her original password. But, she cannot change the password. Why can’t she change the password
Answer:
Because reusing the old passwords possess security threats.
Explanation:
A password can be defined as a string of characters or words or phrases that are used to authenticate the identity of the user. It is also known as passcode and should be kept confidential. A password is used to access constricted systems, applications, etc.
A password or passcode is usually composed of alphabets, numbers, symbols, characters, alphanumeric, or a combination of these.
In the given case, Judy was not able to change her passcode to the previous one because reusing old passwords is prohibited in any sites or systems. A system denies the user to reuse the old passwords for various reasons but most importantly due to security reasons. Though it is said that old passwords can be used after 100 times but seldom someone changes a password that much. All systems care for the security of their users thus they deny reusing old passcodes.
what is linux? what is it good for. And why do people use it?
Answer:
Linux is Unix-based and Unix was originally designed to provide an environment that's powerful, stable and reliable yet easy to use. Linux systems are widely known for their stability and reliability, many Linux servers on the Internet have been running for years without failure or even being restarted
Explanation:
Linux is used for commercial networking
Write a program with a method that plays the guess a number game. The program should allow the user to pick a number between 1 and 1000 in his head. The method should guess the user's number in a minimal amount of attempts. The method should ask the user "is the number greater than or less than the number " and the program gives a particular number. The user in some way just inputs (higher or lower) or (greater than or less than). There also has to be a way for the user to say the number has just been guessed. Of course, the user cannot answer incorrectly or change the number midstream. Note - if written efficiently, the method should be able to guess any number in 10 or less attempts.
Answer:
Please check the explanation
Explanation:
That's the code and it is done with the program in c++ according to instructions given in the question using binary search. It can guess the correct number in 10 or fewer attempts and also shows the number of attempts it took to guess the number.
#include <iostream> using namespace std; int guess() { string input; int l = 1, h = 1000; int mid = (l + h) / 2, count = 0; while (1) { //count the number of attemts to guess the number ++count; //cout << count << "\n"; cout << "\n"; cout << "Is " << mid << " correct? (y/n): "; cin >> input; //if input is y print the guessed no. and return if (input == "y") { cout << mid << " guessed in " << count << " attempts!\n"; return 1; } //if input is n ask the user if it's higher or lower than current guess if (input == "n") { cout << "Is the number greater than or less than the number ? (h/l): "; cin >> input; } //if input is higher assign mid incremented by 1 to low //else decrement mid by 1 and assign to high if (input == "h") l = mid + 1; else h = mid - 1; //calculate mid again according to input by user again mid = (l + h) / 2; } } int main() { cout << "****WELCOME TO THE GUESS THE NUMBER GAME!****\n"; cout << "Guess any number between 1 to 1000.\n"; cout << "This game depends on user giving correct answers and not changing their number middle of game.\n"; guess(); }
Write a method that checks whether the input string or a sentence (a string with spaces) is a palindrome or not. The method should be case insensitive and should ignore spaces. Write a test program that prompts the user to input a string and invokes this method. Some example runs are: Enter the input string: madam Input string madam is a palindrome Enter the input string: banana Input string banana is NOT a palindrome Enter the input string: Race Car Input string Race Car is a palindrome Enter the input string: Too HOT to hoot Input string Too HOT to hoot is a palindrome
Answer:
import java.util.Scanner;
public class Pallindrome {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.println("Enter the input string: ");
String word = in.nextLine();
System.out.println(isPallindrome(word));
}
public static String isPallindrome(String word){
String rev ="";
int len = word.length();
for ( int i = len - 1; i >= 0; i-- )
rev = rev + word.charAt(i);
if (word.equals(rev))
return word+" is palindrome";
else
return word+ " is not palindrome";
}
}
Explanation:
Create the method in Java to receive a String parameterUsing a for loop reverse the stringUse another for loop to compare the characters of the original string and the reversed stringIf they are equal print palindromeelse print not palindromeWithin the main method prompt user for a sentenceCall the method and pass the sentence entered by userIn this exercise we have to use the knowledge in computational language in JAVA to describe a code that best suits, so we have:
The code can be found in the attached image.
To make it simpler we can write this code as:
public class Pallindrome {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.println("Enter the input string: ");
String word = in.nextLine();
System.out.println(isPallindrome(word));
}
public static String isPallindrome(String word){
String rev ="";
int len = word.length();
for ( int i = len - 1; i >= 0; i-- )
rev = rev + word.charAt(i);
if (word.equals(rev))
return word+" is palindrome";
else
return word+ " is not palindrome";
}
}
See more about JAVA at brainly.com/question/19705654
Define a JavaScript function named thanos which has a single parameter. This function will be called so that the parameter will be an array. Your function should return a NEW array which contains only the entries at even indices. (Hint: you can tell an index is even if that index mod 2 is equivalent to 0).. Examples: thanos([ ]) would evaluate to [ ] thanos(['0', 2, 4]) would evaluate to ['0', 4]
Answer:
See explaination
Explanation:
function thanos(lst) {
var result = [];
for (var i = 0; i < lst.length; i += 2) {
result.push(lst[i]);
}
return result;
}
// Testing the function here. ignore/remove the code below if not required
console.log(thanos([]));
console.log(thanos(['0', 2, 4]));
In C++ Programming:Given the following header:vector split(string target, string delimiter);
Implement the function split so that it returns a vector of the strings in target that are separated by the string delimiter.For example: split("10,20,30", ",") should return a vector with the strings "10", "20", and "30".Similarly, split("do re mi fa so la ti do", " ") should return a vector with the strings "do", "re","mi", "fa", "so", "la", "ti", and "do".1. Write a program that inputs two strings and calls your function to split the first target string by the second delimiter string and prints the resulting vector all on line line with elements separated by commas.A successful program should be as below with variable inputs:Examples with inputs of :10,20,30and:do re mi fa so la ti doEnter string to split: 10,20,30 Enter delimiter string: , The substrings are: "10", "20", "30"Enter string to split: do re mi fa so la ti do Enter delimiter string: The substrings are: "do", "re", "mi", "fa", "so", "la", "ti", "do"
The provided C++ program reads two strings, calls the `split` function using the given header, and prints the resulting vector with elements separated by commas.
Below is an updated C++ program that adheres to the given header and meets the specified requirements. It reads two strings, calls the `split` function, and prints the resulting vector:
#include <iostream>
#include <vector>
#include <string>
// Function to split a string by a delimiter
std::vector<std::string> split(std::string target, std::string delimiter) {
std::vector<std::string> substrings;
size_t start = 0;
size_t end = target.find(delimiter);
while (end != std::string::npos) {
substrings.push_back(target.substr(start, end - start));
start = end + delimiter.length();
end = target.find(delimiter, start);
}
substrings.push_back(target.substr(start));
return substrings;
}
int main() {
std::string inputString, delimiter;
std::cout << "Enter string to split: ";
std::getline(std::cin, inputString);
std::cout << "Enter delimiter string: ";
std::getline(std::cin, delimiter);
// Call the split function
std::vector<std::string> result = split(inputString, delimiter);
// Print the resulting vector
std::cout << "The substrings are: ";
for (size_t i = 0; i < result.size(); ++i) {
std::cout << "\"" << result[i] << "\"";
if (i < result.size() - 1) {
std::cout << ", ";
}
}
return 0;
}
This program uses the `split` function to tokenize the input string based on the given delimiter, and it prints the resulting vector as required.
14. Which of the following statements is true? A. The most secure email message authenticity and confidentiality isprovided by signing the message using the sender’s public key and encrypting the message using the receiver’s private key. B. The most secure email message authenticity and confidentiality isprovided by signing the message using the sender’s private key and encrypting the message using the receiver’s public key. C. The most secure email message authenticity and confidentiality isprovided by signing the message using the receiver’s private key and encrypting the message using the sender’s public key. 266 D. The most secure email message authenticity and confidentiality isprovided by signing the message using the receiver’s public key and encrypting the message using the sender’s private key.
Answer:
A. The most secure email message authenticity and confidentiality is provided by signing the message using the sender’s public key and encrypting the message using the receiver’s private key
Explanation:
Public key cryptography helps to send public key in an open and an insecure channel as having a friend's public key helps to encrypt messages to them.
The private key helps to decrypt messages encrypted to you by the other person.
The most secure email message authenticity and confidentiality is provided by signing the message using the sender’s public key and encrypting the message using the receiver’s private key
_____ has many knowledge management applications, ranging from mapping knowledge flows and identifying knowledge gaps within organizations to helping establish collaborative networks. Select one: a. Social network analysis (SNA) b. Branching router-based multicast routing (BRM) c. Online analytical processing (OLAP) d. Drill-down analysis (DDA)
Answer:
A. Social network analysis (SNA).
Explanation:
This is explained to be a process of quantitative and qualitative analysis of a social network. It measures and maps the flow of relationships and relationship changes between knowledge possessing entities. Simple and complex entities include websites, computers, animals, humans, groups, organizations and nations.
The SNA structure is made up of node entities, such as humans, and ties, such as relationships. The advent of modern thought and computing facilitated a gradual evolution of the social networking concept in the form of highly complex, graphical based networks with many types of nodes and ties. These networks are the key to procedures and initiatives involving problem solving, administration and operations.
What are techniques for active listening? Select all
that apply.
1. asking clarifying questions, without
interrupting
2. keeping eye contact
3. indicating full agreement to what is being said
1.) asking clarifying questions, without interrupting
2.) keeping eye contact
Techniques for active listening are
asking clarifying questions, without interruptingkeeping eye contactThe correct options are 1 and 2.
What is active listening?An active listening is when a person actively listens to another person.
A person must maintain eye contact with the speaker while in conversation with him.
Also, they must have two way conversation between them.
Thus, correct options are 1 and 2.
Learn more about active listening.
https://brainly.com/question/3013119
#SPJ2
Direct current is produced by an electric motor. an armature. a solenoid. a battery.
Answer:
D
Explanation:
I just did it
g The state of Massachusetts at one time had considered generating electric power by harvesting energy crops and burning them. Assume that the state requires 4000 MW of electricity and that planted crops yield between 10,000 and 20,000 lb of dry biomass per acre per year that could be burned to produce electricity at 35% efficiency. How many acres would the state need to plant to supply all its electricity in this way? HTML EditorKeyboard Shortcuts
Answer:
The require number of acres is between 220714.991 acres and 4414287.982 acres
Explanation:
Given
Power = 4,000MW
Yield = 10,000lb - 20,000 lb/year
Electricity Efficiency = 35%
Required
Number of acres needed
To calculate the required number of acres, the following steps will be followed.
1. Calculate total energy
2. Calculate the intensity of energy
3. Calculate number of acres.
Calculating the total energy
Energy = Power * Time
From the question;
Power = 4,000MW
The crop yield is measured on a yearly basis. So, time = 1 year.
Convert time to seconds.
First, we convert to days
1 year = 365 days;
Then to hours
= 365 * 24
Then to minutes
= 365 * 24 * 60
Then to seconds
= 365 * 24 * 60 * 60
So,
1 year = 365 * 24 * 60 * 60
1 year = 31,536,000s.
Energy = 4,000 MW * 31,536,000
Emergy = 1.26144E11 MJ
Calculating the intensity of energy.
Energy Intensity = Required Energy * Efficiency
Efficiency = 35%
Calculating Required Energy
When Yield = 10,000 lb
First, we convert this to kilogram
1 lb = 0.453592 kg
10,000 lb = 10,000 * 0.453592
10,000 lb = 4535.92 kg
From energy characterisation factors and method table.
1 kg requires 18 MJ of energy.
4535.92 will require:
4535.92 * 18MJ
= 81646.56 MJ of energy.
Hence, Required Energy = 81646.56 MJ
So, Energy Intensity = 81646.56 MJ * 35%
Energy Intensity = 28576.296 MJ.
Hence, when yield = 10,000 lb; the energy intensity is 28576.296 MJ
When Yield = 20,000 lb
Energy Intensity = Required Energy * Efficiency
If the energy intensity is 28576.296 MJ when yield = 10,000 MJ
Energy Intensity = 2 * 28576.296 MJ
Yield = 2 * 10,000 lb
Hence, Energy Intensity = 2 *28576.296 MJ
Energy Intensity = 57152.592 MJ
Now, the number of acres can be calculated.
Number of acres = Total Energy ÷ Intensity.
Total Energy = 1.26144E11 MJ
When Yield = 10,000 lb, Intensity = 28576.296 MJ
Number of acres = 1.26144E11 ÷ 28576.296
Number of acres = 4414287.982 acres
When Yield = 20,000 lb, Intensity = 57152.592 MJ
Number of acres = 1.26144E11 ÷ 57152.592
Number of acres = 220714.991 acres
Hence, the require number of acres is between 220714.991 acres and 4414287.982 acres
// Marian Basting takes in small sewing jobs. // She has two files sorted by date. // (The date is composed of two numbers -- month and year.) // One file holds new sewing projects // (such as "wedding dress") // and the other contains repair jobs // (such as "replace jacket zipper"). // Each file contains the month, day, client name, phone number, // job description, and price. // Currently, this program merges the files to produce // a report that lists all of Marian's jobs for the year // in date order. // Modify the program to also display her total earnings // at the end of each month as well as at the end of the year.
Answer:
See Explaination
Explanation:
Provided Pseudocode as per your new specifications:
start
Declarations
num weddingMonth
num weddingDay
string weddingClientName
num weddingPhoneNum
string weddingDescription
num weddingPrice
num replaceMonth
num replaceDay
string replaceClientName
num replacePhoneNum
string replaceDescription
num replacePrice
num weddingDate
num replaceDate
num bothAtEnd=0
num END_YEAR=9999
InputFile weddingFile
InputFile replaceFile
ouputFile mergedFile
getReady()
while bothAtEnd<>1
mergeRecords()
endwhile
finishUp()
stop
getReady()
open weddingFile "weddingDress.dat"
open replaceFile "replaceJacketZipper.dat"
open mergedFile “Merged.dat”
readWedding()
readreplace()
checkEnd()
return
readWedding( )
input weddingMonth,weddingDay,weddingClientName,weddingPhoneNum,weddingDescription,weddingPricee from weddingFile
while eof
weddingDate=END_YEAR
endwhile
return
readreplace( )
input replaceMonth,replaceDay,replaceClientName,replacePhoneNum,replaceDescription,replacePricee from replaceFile
while eof
replaceDate=END_YEAR
endwhile
return
checkEnd()
if weddingDate=END_YEAR
if replaceDate=END_YEAR
bothAtEnd=1
endif
endif
return
mergedFile()
if weddingDate<replaceDate
output weddingMonth,weddingDay,weddingClientName,weddingPhoneNum,weddingDescription,weddingPricee to weddingFile
readWedding()
endif
Final answer:
The question is about adding functionality to a computer program to display monthly and yearly earnings for Marian Basting's sewing jobs. This involves data handling, control structures, and algorithms to manage and total earnings in the generated report.
Explanation:
The question pertains to modifying a computer program for Marian Basting, who takes in sewing jobs and tracks them in two sorted files. The program should not only merge the files to produce a date-ordered report of all Marian's jobs for the year but should also be modified to display total earnings at the end of each month and the yearly total earnings. To achieve this, the program would require additional functionality to sum the price of jobs, categorized by month and then aggregated for the year-end total. This could involve processing each entry, keeping a running total, and then displaying the totals when a new month starts or the report ends.
For clarity, here's a hypothetical implementation outline: Load the entries from both files, sort them by date, iterate through the sorted list while maintaining a subtotal for each month's earnings. After processing all entries for a month, display the subtotal. Upon reaching year-end, display the final total. This implementation requires knowledge of programming concepts such as data handling, control structures, and algorithms for sorting and totaling.
Create a SavingsAccount class. Use a static data member annualInterestRate to store the annual interest rate for each of the savers. Each member of the class contains a private data member savingsBalance indicating the amount the saver currently has on deposit. Provide member function calculateMonthlyInterest that calculates the monthly interest by multiplying the savingsBalance by annualInterestRate divided by 12; this interest should be added to savingsBalance. Provide a static member function modifyInterestRate that sets the static annualInterestRate to a new value.
Answer:
Explanation:
#include <iostream>
#include <iomanip>
using namespace std;
#include "SavingsAccount.h"
double SavingsAccount::annualInterestRate = 0.0;
SavingsAccount::SavingsAccount( double bal, double AiR )
{
savingsBalance = ( bal >= 0.0 ? bal : 0.0 );
setAnnualInterestRate( AiR ); //AiR = AnnualInterestRate
}
void SavingsAccount::setAnnualInterestRate( double AiR)
{
annualInterestRate = ( AiR >= 0.0 && AiR <= 1.0) ? AiR : .03;
}
double SavingsAccount::getAnnualInterestRate()
{
return annualInterestRate;
}
void SavingsAccount::calculateMonthlyInterest()
{
savingsBalance += savingsBalance * ( annualInterestRate / 12);
}
void SavingsAccount::modifyInterestRate( double interest )
{
annualInterestRate = (interest >= 0.0 && interest <= 1.0) ? interest : .04;
}
void &SavingsAccount::print() const
{
cout << fixed << setprecision(2) << "$" << savingsBalance;
}
int main()
{
SavingsAccount saver1( 2000.0, .03 );
SavingsAccount saver2( 3000.0, .03 );
cout << "Initial Balance For saver1 Is: " << saver1.print;
cout << "\nInitial Balance For saver2 Is: " << saver2.print << "\n\n";
cout << "Interest Rate For Both Accounts is " << saver1.getAnnualInterestRate << "%";
saver1.calculateMonthlyInterest();
saver2.calculateMonthlyInterest();
cout << "Balance After 3% interest For saver1: " << saver1.print;
cout << "\nBalance After 3% interest For saver2: " << saver2.print;
cout << "\n\nSetting Annual Interest Rate to 4%";
saver1.modifyInterestRate( .04 );
saver2.modifyInterestRate( .04 );
saver1.calculateMonthlyInterest();
saver2.calculateMonthlyInterest();
cout << "\nBalance After 4% Interest For saver1: " << saver1.print;
cout << "\nBalance After 4% Interest For saver2: " << saver2.print;
cout << endl;
return 0;
}
How are graphs used to analyze data?
Answer:
Graphs and charts are visual representations of data in the form of points, lines, bars, and pie charts. Using graphs or charts, you can display values you measure in an experiment, sales data, or how your electrical use changes over time. Types of graphs and charts include line graphs, bar graphs, and circle charts.
Explanation:
Graphs are used to visually display data, making it easier to identify trends and patterns. They simplify complex data and allow for effective comparisons, aiding better understanding and data-driven decision-making.
Graphs are a powerful tool used to display data visually, making it easier to see trends and patterns compared to numerical data in a table. In high school mathematics, understanding how to interpret various types of graphs is crucial.
Here are some key reasons why graphs are employed:
Visualizing trends: For example, a line graph can show how temperature changes over time, making it easy to spot trends such as increases or decreases.Simplifying complex data: Complicated data sets can often be more easily interpreted when presented in a pie chart, bar graph, or scatter plot rather than a dense table.Comparing data: Graphs allow for side-by-side comparison of different data sets. For example, bar graphs can compare the population of different cities.Overall, utilizing graphs not only aids in understanding data better but also helps in making data-driven decisions effectively.
Q2 - Square Everything (0.25 points) Write a function called square_all that takes an input called collection that you assume to be a list or tuple of numbers. This function should return a new list, which contains the square of each value in collection. To do so, inside the function, you will define a new list, use a loop to loop through the input list, use an operator to square the current value, and use the append method to add this to your output list. After the loop, return the output list.g
Answer:
See explaination
Explanation:
#Define the function square_all() having a list of
#integers. This function will return a list of square
#of all integer included in the given list.
def square_all(num_list):
#Create an empty list to store resultant list.
sq_list = []
#Start a for loop till the length of the given list.
for index in range(0, len(num_list)):
#Multiply the current list value with its value
#and append the resultant value in the list
#sq_list in each iteration.
sq_list.append(num_list[index] * num_list[index])
#Return the final list of squares of all integrs in
#the list num_list.
return sq_list
#Declare and initialize a list of integers.
intList = [2, 4]
#Call the function square_all() and pass the above list
#as argument of the function. Display the returned list.
print(square_all(intList))
Univariate linear regression Note: Solutions to this problem must follow the method described in class and the linear regression handout. There is some flexibility in how your solution is coded, but you may not use special functions that automatically perform linear regression for you. Load in the BodyBrain Weight.csv dataset. Perform linear regression using two different models: M1: brain_weight = w0 + w1 x body_weight M2: brain_weight = w0 + w1 x body_weight + w2 x body_weight2
a. For each model, follow the steps shown in class to solve for w. Report the model, including w values and variable names for both models.
b. Use subplots to display two graphs, one for each model. In each graph, include: • Labeled x and y axes • Title • Scatterplot of the dataset • A smooth line representing the model
c. For each model, calculate the sum squared error (SSE). Show your 2 SSE values together in a bar plot.
d. Which model do you think is better? Why? Is there a different model that you think would better represent the data?
Body weight (kg) Brain weight (g)
0.023 0.4
0.048 0.33
0.075 1.2
0.12 1
0.122 3
0.2 5
0.28 1.9
0.55 2.4
0.75 12.3
0.785 3.5
0.93 3.5
1.04 5.5
1.35 8.1
1.41 17.5
2.5 12.1
3 25
3.3 25.6
3.6 21
4.288 39.2
5.3 41.6
6.8 179
10 115
10.55 179.5
27.66 115
35 56
36.33 119.5
52.16 440
55.5 175
60 81
62 1320
85 325
93 225
100 157
110 288
110 442
187.1 419
192 180
207 406
250 334
465 423
480 712
521 655
529 680
1400 590
2547 4603
6654 5712
Answer:
regression line is Y = 124.9281 + 0.9370 *x
SSE= (SSxx * SSyy - SS²xy)/SSxx = 7317401.270
Explanation:
See the attached image file
For credit card processing, stock exchanges, and airline reservations, data availability must be continuous. There are many other examples of mission-critical applications. Research the Internet to find four additional mission-critical applications and explain why data availability must be continuous for these applications. If you use information from the Web, use reputable sites. Do not plagiarize or copy from the Web. Be sure to cite your references.
Answer:
The answer to this question can be described as follows:
Explanation:
The mission-critical System-
A vital mission program is necessary for an organization's life. If a critical task program disrupted, industrial control should be severely affected. The essential support device is often referred to as critical task equipment.
Safety system for nuclear reactors-
The nuclear power plant is used to control the system, and it also contains and continues reactions. It's also usually used only for energy production, and also used experiments and clinical isotope manufacture.
If another system of nuclear power fails, this could result in a continuous nuclear reaction in a range of aspects like irradiated leaks. These same persons across the area may experience serious radioactivity symptoms.
The main task in their personal life-
They realize, that without power, they turn down your entire life when you've never encountered a dark off with more than 30 minutes. Essentially, people wouldn't have been allowed to do what you'll do, entirely frozen.
Consumer survey: big financial transfer controlling business-
That company is the infrastructure and software supplier for banks, traders, distributors, and institutional investors to take out money transfers. With all the money transfers they depend on, you must establish a successful company to become the 'guy behind the button', etc.
Consider the following method substringFound, which is intended to return true if a substring, key, is located at a specific index of the string phrase. Otherwise, it should return false.
public boolean substringFound(String phrase, String key, int index)
{
String part = phrase.substring(index, index + key.length());
return part.equals(key);
}
Which of the following is the best precondition for index so that the method will return the appropriate result in all cases and a runtime error can be avoided?
A. 0 <= index < phrase.length()
B. 0 <= index < key.length()
C. 0 <= index < phrase.length() + key.length()
D. 0 <= index < phrase.length() - key.length()
E. 0 <= index < phrase.length() - index
Answer:
Option D 0 <= index < phrase.length() - key.length()
Explanation:
The index has to be between the range of 0 <= index < phrase length - key length to prevent index out of bound error. This is because the substring method will have to extract part of the string with a certain length from the original string starting from the index-position. If the key length is longer than the string area between phrase[index] and phase.length(), an index out of bound runtime error will be thrown.
Write a program to determine all pairs of positive integers, (a, b), such that a < b < n and (a 2 b 2 1)/(ab) is an integer. Here n is an integer and n > 1. Note: Your method should take n as a parameter and return nothing. You should print inside the method.c
Answer:
following are the code to this question:
#include <iostream> //defining header file
using namespace std;
void me(int n) //defining a method me, that accept an integer value
{
int a,b,t1,t2; //defining integer variable
for(a = 1; a<n; a++) //defining loop to calculates a variable value
{
for(b=a+1; b<n; b++) //defining loop to calculates a variable value
{
t1=(a*a)+(b*b)+1; //hold value in t1 value
t2=a*b; // calculates multiplication value and hold in t2 variable
if(t1%t2==0) //defining condition that check calculated value is equal to 0
{
cout<<"("<<a<<","<<b<<")"; //print a and b value.
}
}
}
}
int main() //defining main method
{
int n; // defining integer variable
cout<< "Enter a number: "; //print message
cin>> n; // input value
if(n>1) //defining condition that check value is greater then 1
{
me(n); //call method and pass the value
}
else
{
cout<<"Enter a number, which is greater then 1"; //print message
}
return 0;
}
Output:
Enter a number: 3
(1,2)
Explanation:
In the given C++ language code, a method "me" is defined, that accepts an integer value "n" as its parameter and this method does not return any value because its return type is void, inside the method two for loop is declared, that calculates a and b value and hold in t1 and t2 variable.
In the next step, if the condition is used, that checks module of t1 and t2 is equal to 0, then it will print a, b value. Inside the main method an integer variable n is declared, that accepts a value from the user end, and use if block that checks user input is greater then 1, then we call method otherwise, print a message.Write a telephone lookup program. Read a data set of 1,000 names and telephone numbers from a file that contains the numbers in random order. Handle lookups by name and also reverse lookups by phone number. Use a binary search for both lookups.
Answer:
See explaination
Explanation:
PhoneLookup.java
import java.io.FileReader;
import java.io.IOException;
import java.util.Scanner;
public class PhoneLookup
{
public static void main(String[] args) throws IOException
{
Scanner in = new Scanner(System.in);
System.out.println("Enter the name of the phonebook file: ");
String fileName = in.nextLine();
LookupTable table = new LookupTable();
FileReader reader = new FileReader(fileName);
table.read(new Scanner(reader));
boolean more = true;
while (more)
{
System.out.println("Lookup N)ame, P)hone number, Q)uit?");
String cmd = in.nextLine();
if (cmd.equalsIgnoreCase("Q"))
more = false;
else if (cmd.equalsIgnoreCase("N"))
{
System.out.println("Enter name:");
String n = in.nextLine();
System.out.println("Phone number: " + table.lookup(n));
}
else if (cmd.equalsIgnoreCase("P"))
{
System.out.println("Enter phone number:");
String n = in.nextLine();
System.out.println("Name: " + table.reverseLookup(n));
}
}
}
}
LookupTable.java
import java.util.ArrayList;
import java.util.Collections;
import java.util.Scanner;
/**
A table for lookups and reverse lookups
*/
public class LookupTable
{
private ArrayList<Item> people;
/**
Constructs a LookupTable object.
*/
public LookupTable()
{
people = new ArrayList<Item>();
}
/**
Reads key/value pairs.
atparam in the scanner for reading the input
*/
public void read(Scanner in)
{
while(in.hasNext()){
String name = in.nextLine();
String number = in.nextLine();
people.add(new Item(name, number));
}
}
/**
Looks up an item in the table.
atparam k the key to find
atreturn the value with the given key, or null if no
such item was found.
*/
public String lookup(String k)
{
String output = null;
for(Item item: people){
if(k.equals(item.getName())){
output = item.getNumber();
}
}
return output;
}
/**
Looks up an item in the table.
atparam v the value to find
atreturn the key with the given value, or null if no
such item was found.
*/
public String reverseLookup(String v)
{
String output = null;
for(Item item: people){
if(v.equals(item.getNumber())){
output = item.getName();
}
}
return output;
}
}
Item.java
public class Item {
private String name, number;
public Item(String aName, String aNumber){
name = aName;
number = aNumber;
}
public String getName(){
return name;
}
public String getNumber(){
return number;
}
}
input.txt
Abbott, Amy
408-924-1669
Abeyta, Ric
408-924-2185
Abrams, Arthur
408-924-6120
Abriam-Yago, Kathy
408-924-3159
Accardo, Dan
408-924-2236
Acevedo, Elvira
408-924-5200
Acevedo, Gloria
408-924-6556
Achtenhagen, Stephen
408-924-3522
Note: Replace all the "at" with at symbol
) Write the code to display the content below using user input. The program Name is Half_XmasTree. This program MUST use (ONLY) for loops to display the output below from 10 to 1 therefore ...1st row prints 10 star 2nd row prints 9… 3rd print 8 stars and so forth... This program is controlled by the user to input the amount of row. A good test condition is the value of ten rows. The user will demand the size of the tree. Remember the purpose of print() and println()
Answer:
Following are the program in java language that is mention below
Explanation:
import java.util.*; // import package
public class Half_XmasTree // main class
{
public static void main(String args[]) // main method
{
int k,i1,j1; // variable declaration
Scanner sc2=new Scanner(System.in); // create the object of scanner
System.out.println("Enter the Number of rows : ");
k=sc2.nextInt(); // Read input by user
for(i1=0;i1<k;i1++) //iterating the loop
{
for(j1=0;j1<i1;j1++) // iterating the loop
System.out.print(" ");
for(int r=k-i1;r>0;r--) //iterating loop
System.out.print("*"); // print *
System.out.println();
}
}
}
Output:
Following are the attachment of output
Following are the description of program
Declared a variable k,i1,j1 as integer type .Create a instance of scanner class "sc2" for taking the input of the rows.Read the input of row in the variable "K" by using nextInt() method .We used three for loop for implement this program .In the last loop we print the * by using system.println() method.The Half_XmasTree program illustrates the use of loops
Loops are used for operations that must be repeated until a certain condition is met.
The Half_XmasTree programThe Half_XmasTree program written in Java where comments are used to explain each action is as follows:
import java.util.*;
public class Half_XmasTree{
public static void main(String args[]){
//This creates a Scanner object
Scanner input =new Scanner(System.in);
//This prompts the user for the number of rows
System.out.print("Number of rows: ");
//This gets input the user for the number of rows
int rows=input.nextInt();
//The following iteration prints the half x-mas tree
for(int i=0; i<rows;i++){
for(int j=0;j<i;j++){
System.out.print(" ");
}
for(int r=rows-i;r>0;r--){
System.out.print("*");
}
System.out.println();
}
}
}
Read more about loops at:
https://brainly.com/question/24833629
1. Your task is to process a file containing the text of a book available as a file as follows:A function GetGoing(filename) that will take a file name as a parameter. The function will read the contents of the file into a string. Then it prints the number of characters and the number of words in the file. The function also returns the content of the file as a Python list of words in the text file.A function FindMatches(keywordlist, textlist): The parameter keywordlist contains a list of words. The parameter textlist contains text from a book as a list of words. For each word in keywordlist, the function will print the number of times it occurs in textlist. Nothing is returned.If you implemented the functions correctly then the following program:booktext = GetGoing('constitution.txt') FindMatches (['War', 'Peace', 'Power'], booktext) Will read the file "constitution.txt" and print something like the following:The number of characters is: 42761The number of words is: 7078The number of occurrences of War is: 4The number of occurrences of Peace is: 2The number of occurrences of Power is: 11
Answer:
See explaination
Explanation:
#function to count number of characters, words in a given file and returns a list of words
def GetGoing(filename):
file = open(filename)
numbrOfCharacters =0
numberOfWords = 0
WordList = []
#iterate over file line by line
for line in file:
#split the line into words
words = line.strip().split()
#add counn of words to numberOfWords
numberOfWords = numberOfWords + len(words)
#find number of characters in each word and add it to numbrOfCharacters
numbrOfCharacters = numbrOfCharacters + sum(len(word) for word in words)
#append each word from a line to WordList
for word in words:
WordList.append(word)
#display the result
print("The number of characters: ", numbrOfCharacters)
print("The number of Words: ", numberOfWords)
#return the list of words
return WordList
#find matches for keywords given in textlist
def FindMatches(keywordlist, textlist):
for keyword in keywordlist:
keyword = keyword.lower()
print ("The number of occurrences of {} is: {}".format(keyword,len([i for i, s in enumerate(textlist) if s == keyword])))
#main
booktext = GetGoing("constitution.txt")
FindMatches (['War', 'Peace', 'Power'], booktext)
g Given an array, the task is to design an efficient algorithm to tell whether the array has a majority element, and, if so, to find that element. The elements of the array are not necessarily from some ordered domain like the integers, and so there can be no comparisons of the form "is A[i] ≥ A[j]?". (Think of the array elements as GIF files, say.) However you can answer questions of the form: "is A[i] = A[j]?" in constant time
Answer:
If there is a majority element in the array it will be the median. Thus,
just run the linear time median finding algorithm, and compare the result with all the elements of the array (also linear time). If [tex]\frac{n}{2}[/tex]elements are the same as the median, the median is a ma majority element. If not, there is none.
Suppose now that the elements of the array are not from some ordered domain like the integers, and so there can be no comparisons of the form "is the ith element of the array greater than the jth element of the array?" However you can answer questions of the form:
"Are the ith and jth elements of the array the same?" in constant time. Such
queries constitute the only way whereby you can access the array. (Think of the elements of the array as GIF files, say.) Notice that your solution above cannot be used now.
Perhaps programs used for business purposes ought to conform to higher standards of quality than games. With respect to software warranties, would it make sense to distinguish between software used for entertainment purposes (such as a first-person shooter game) and software used for business (such as for medical testing)?
Answer:
Answered below
Explanation:
A software warranty is a written promise or guarantee from a software manufacturer or company to repair or replace a product of it has a fault within a particular period of time. Such faults must arise from the manufacturer's errors.
During the warranty period given, the software developer must fix all the defects and bugs within the software so long as it occurred due to a development fault and there is evidence of system failure.
Some software programs and applications really do require a warranty with a longer duration. Such softwares include those used in big businesses and corporations like banks, medical softwares, nuclear softwares and aviation softwares. The warranties are like a testament of reliability of the software in such critical and delicate sectors.
An open source software for a video game may not require a warranty or the warranty period might not be long compared to business softwares.
With the sheets grouped, apply Underline to cell B5 and Double Underline to cell B6. Ungroup the worksheets. Note, use the Format Cells dialog box to ensure that the Underline styles Single and Double are applied, rather than Single Accounting or Double Accounting.
Answer:
Check Explanation.
Explanation:
Task: (1). Apply Underline to cell B5 and Double Underline to cell B6.
(2). Ungroup the worksheets.
(3).use the Format Cells dialog box to ensure that the Underline styles Single and Double are applied, rather than Single Accounting or Double Accounting.
Steps to follow;
Step one: On the Excel document that you are working on, make sure you highlight from B6 cell to F6 cell.
Step two: Then, press CTRL+SHIFT+F.
Step three: from action in step two above, the "format cells dailogue box" will come up, click underline > (underline type) dropdown list > ok.
Step four: next, highlight from B7 to F7.
Step five: press CTRL+SHIFT+F. As in step two above.
Step Six: do the same thing as in Step three above.
Please note that to apply the SINGLE UNDERLINE, you need to type the data in the cell for cells of B6 to F6 ONLY.
Also, for DOUBLE UNDERLINE for B7 to F7; just type the data in the cell and it will apply.
Asks the user for the full path of a file to be read - path should include the folder and filename.
Asks the user for the full path of a file to be written - path should include the folder and filename.
Declares an array of strings of 1024 words.
Opens the input and output files.
Reads the file word by word into the array.
Prints the content of the array in reverse order to both screen and output file at the same time.
Remember :
Check that input file opened successfully.
Input file can be quite smaller than 1024 words, exactly 1024 words or much larger than 1024 words.
Close the files before program ends.
Put a 'pause' in your program before it ends.
Answer:
See explaination
Explanation:
#include <iostream>
#include <fstream>
using namespace std;
int main()
{
int size = 10;
string inputFileName, outputFileName;
cout << "Please enter input file name, including full path: ";
cin >> inputFileName;
cout << "Please enter output file name, including full path: ";
cin >> outputFileName;
ifstream inFile(inputFileName.c_str());
ofstream outFile(outputFileName.c_str());
// checking whether input and output files are good to open
if(!inFile.is_open())
{
cout << "Cannot open " << inputFileName << endl;
exit(EXIT_FAILURE);
}
if(!outFile.is_open())
{
cout << "Cannot open " << outputFileName << endl;
exit(EXIT_FAILURE);
}
// declare an array of string to store 1024 words
string words[size];
// read the file for exactly 1024 words
// assuming each line of input file contains only 1 word
int count = 0;
string word;
while(getline(inFile, word))
{
if(count == size)
break;
words[count++] = word;
}
inFile.close();
// now we need to print the words array in reverse order both to the console and to the output file, simultaneously
cout << "WORDS:\n------\n";
for(int i = size - 1; i >= 0; i--)
{
if(words[i] != "")
{
cout << words[i] << endl;
outFile << words[i] << endl;
}
}
outFile.close();
system("pause");
return 0;
}
Final answer:
The question is about creating a program for file reading and writing, including array manipulation and outputting content in reverse. The program must handle input/output operations, file size variations, and ensure resource management by closing files properly.
Explanation:
The student's question pertains to writing a program that can read and write files, and specifically handle reading words into an array and then outputting them in reverse order to a file and the screen. The steps to achieve this involve prompting the user for file paths, checking the success of opening files, handling files of various sizes, and managing resources correctly by closing files. A 'pause' before the program ends is also required, likely to allow the user to see the output before the program closes.
To begin, here's a simplified pseudo-code outline:
Ask the user for the input file path (including the directory and file name).Ask the user for the output file path (including the directory and file name).Declare an array of strings, sized to 1024 elements.Open the input file and check if it opens successfully. If not, display an error message.Open the output file for writing.Read the words from the input file into the array until the file ends or the array is full.Output the array contents in reverse order to the screen and write them to the output file.Close both files.Implement a pause at the end of the program.Note: When implementing the read operation, the program should consider the file size which may be larger than the array and handle it appropriately, perhaps by reading in chunks if necessary.
QUESTION
UNi-Library is conducting a survey to rate the quality of their services in order to improve their
services. In the survey, 30 students were asked to rate the quality of the service in the library on a
scale of 1 to 5 (1 indicating very bad and 5 indicating excellent). You have to store the 30 responses of
the students in an array named responses [ ]. Then, you have to count the frequency of each scale
and store it in an array named frequency[ ]. Use the appropriate looping structure to enter the
responses and to count the frequency. You are also required to display the percentage of the
frequency of each scale. Display the scale, frequency and its percentage as shown below.
The program also allows the user to repeat this process as often as the user wishes.
*Write a complete C++ program*
Answer:
Explanation:
#include <iostream>
using namespace std;
int main ()
{
int responses[30],count[6];
int score = 0;
string resp = " ";
for (int i = 0; i < 30; i++)
{
responses[i] = 0;
}
for (int i = 0; i < 6; i++)
{
count[i,1]=0;
count[i,2]=0;
count[i,0]=0;
}
while ((resp != "Y") && (resp != "y"))
{
for (int i = 0; i < 30; i++)
{
while ((score > 5) || (score < 1))
{
cout << "Student " << (i+1)<< " please enter a value (1-5):";
cin >> score;
}
responses[i] = score;
if((score > 5)||(score<1))
{
if(score==1) count[1]++;
if(score==2) count[2]++;
if(score==3) count[3]++;
if(score==4) count[4]++;
if(score==5) count[5]++;
}
score = 0;
}
cout<< "Response Frequency Percentage"<<endl;;
cout<< " 1 "<<count[1]<<" "<<(count[1]/30)<<"%"<<endl;
cout<< " 2 "<<count[2]<<" "<<(count[2]/30)<<"%"<<endl;
cout<< " 3 "<<count[3]<<" "<<(count[3]/30)<<"%"<<endl;
cout<< " 4 "<<count[4]<<" "<<(count[4]/30)<<"%"<<endl;
cout<< " 5 "<<count[5]<<" "<<(count[5]/30)<<"%"<<endl;
cout<< "Do you want to exit? Press Y to exit any other key to continue: ";
cin>> resp;
}
return 0;
}