Suppose the length of a rectangle is three time is three time the width. if we let x represent the width of the rectangle, what expression do we us to represent the length?

Answers

Answer 1
Since the length is three times the width (x), length = 3x
Answer 2
The length of a rectangle = 3 times the width.

If x is the width then:

l = 3x

Related Questions

Identify the value of y

Answers

24^2 = 18 * (18 +y)

576 = 324+18y

252 =18y

y = 252/18 =14

 y = 14

The value of y is 14.

What is a circle?

'A circle is a shape consisting of all points in a plane that are at a given distance from a given point, the center. Equivalently, it is the curve traced out by a point that moves in a plane so that its distance from a given point is constant'

According to the given problem,

We know,

⇒ 18 ( 18 + y ) = 24²

⇒ 324 + 18y = 576

⇒ 18y = 576 - 324

⇒ 18y = 252

⇒ y = 252/18

⇒ y = 14

Hence, we can conclude, the value of y is 14.

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A wire is first bent into the shape of a rectangle with width
4in and length 14in. Then the wire is unbent and reshaped into a square. What is the length of a side of the square?

Answers

First find the perimeter of the rectangle: 2w+2l which is 8+28=36. Then find the square root of 36 which is 6 so that is the answer.
First you have to find the area of the wire
Area of a rectangle=L*W= 14*4=56
Then divide that by 4 since a square has 4 equal sides
56/4=14
The length of a side of a square is 14 in

Three times the difference of a number x and seven is twenty-three minus the sum of three times a number x and two. what is the value of x?

Answers

3(x - 7) = 23 - (3x + 2) =
3x - 21 = 23 - 3x - 2 =
3x - 21 = -3x + 21
3x + 3x = 21 + 21
6x = 42
x = 42/6
x = 7 <==

The required value of x is 7.

What are linear equation?

A linear equation only has one or two variables. No variables in a linear equation is raised to power greater than 1 or used as denominator of a fraction.

Now the given statement is,

Three times the difference of a number x and seven is twenty-three minus the sum of three times a number x and two.

So converting them into numerical form,

the difference of a number x and seven = x - 7

Three times the difference of a number x and seven = 3(x - 7)

Similarly,

the sum of three times a number x and two = 3x + 2

∴ Twenty-three minus the sum of three times a number x = 23 - (3x + 2)

Therefore, the required equation is,

3(x - 7) = 23 - (3x + 2)

Expanding the brackets we get,

3x - 21 = 23 - 3x - 2

or, 3x - 21 = 21 - 3x

Taking alike terms together,

3x + 3x = 21 + 21

or, 6x = 42

Dividing both side by 6 we get,

x = 7

which is the required value of x.

Thus, The required value of x is 7.

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A store's cost for a stereo was $27. The markup was 75%. A customer purchased it on sale at 40% off the markup price. What was the purchase price of the stereo

Answers

so the stereo costs $27, so to include a price for profit and other expenses, it gets ballooned to 75% extra, or the new price is 175%, how much is that?

if we take 27 to be the 100%, what's 175% of that?

[tex]\bf \begin{array}{ccllll} amount&\%\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 27&100\\ x&175 \end{array}\implies \cfrac{27}{x}=\cfrac{100}{175}\implies \cfrac{27\cdot 175}{100}=x\implies \boxed{47.25=x}[/tex]

alrite, then a customer showed up and found it on sale, 40% off that price, so if you take out 40% from the 100%, the price the customer found it at is the 60%, 100-40,  of the current price of 47.25

so, if 47.25 is the 100%, what's 60% of that?

[tex]\bf \begin{array}{ccllll} amount&\%\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 47.25&100\\ x&60 \end{array}\implies \cfrac{47.25}{x}=\cfrac{100}{60}[/tex]

solve for "x".

Determine the standard variation of the data below. (1, 2, 3, 4, 5)

Answers

Calculate for the mean/ average of the given numbers:
 
                             μ = (1 + 2 + 3 + 4 + 5) / 5 = 3

Then, we calculate for the summation of the squares of differences of these numbers from the mean, S
 
                             S  = (1 - 3)² + (2 - 3)² + (3 - 3)² + (4 - 3)² + (5 - 3)²
                                S = 10

Divide this summation by the number of items and take the square root of the result to get the standard deviation.

                              SD = sqrt (10 / 5) = sqrt 2  
                                    SD = 1.41

Thus, the standard deviation of the given is equal to 1.41. 
              
                            

Answer:

So basically sqrt of 2...

Step-by-step explanation:

In which case would it be best to use the “Factoring Method” to solve the trinomial equation?
x^2 + 4x = -­5
4.3x^2 + 2.4x -­ 3 = 0
x^2 ­ - 4x + 3 = 0

Answers

The best case would be to use factoring in the last equation because it has whole numbers that are "factorable," meaning that its c value has factors that evenly add up to its b value.
In this case, (x-3)(x-1). -1*-3=3 and -1+-3=-4


Julio paid 1.3 times his normal hourly rate for each he works over 31 hours in a week. Last week he worked 35 hours and earned $448.88. What is julios normal hourly rate ?

Answers

Hi, Globabypatricia! :)

All the time worked past 31 hours gets paid 1.3 times.
He worked 4 hours at such a rate.

31+4(1.3)
31+5.2
=36.2
Paid as if he worked 36.2 at a normal rate. 

To find his normal wage, divide 448.88 by 36.2
448.88/36.2
=12.40

His normal wage is $12.40.

To check:
12.40*31=384.40
12.40*1.3=16.12
16.12*4=64.48

384.40+64.48
=$448.88

Hope this helps.
-Benjamin
Good question


Let his hourly rate is x

then:

31x + (35-31)*1.3x = 448.88

solve for x:

31 x + 5.2x = 448.88

36.2 x =448.88

x = 12.4$

not fair hourly rate by the way ;)

Which rate is the lowest price?
$6.30 for 9
$5.50 for 5
$4.20 for 7
$0.80 each

Answers

Answer: $4.20 for 7
This problem can be solved by dividing the pay by the number of items.

$6.30 / 9 = $0.70
$5.50 / 5 = $1.10
$4.20 / 7 = $0.60
$0.80 / 1 = $0.80

This shows that for the third option, $4.20 for 7, the rate per item is the lowest.

(02.03 MC)

The figure shows two triangles on a coordinate grid:


What set of transformations is performed on triangle ABC to form triangle A'B'C'?
A.. A 180-degree counterclockwise rotation about the origin, followed by a translation 5 units down
B. A translation 5 units down followed by a 180-degree counterclockwise rotation about the origin
C. A 270-degree counterclockwise rotation about the origin, followed by a translation 5 units to the right
D. A translation 5 units to the right, followed by a 270-degree counterclockwise rotation about the origin

Answers

pretty sure it is b

i know for sure it isnt C or D

Martin is asked to find the probability of getting one head and three tails on for coin tosses this is a simple event

Answers

The possible outcomes for 1 HEAD and 3 TAILS are

HTTT
THTT
TTHT
TTTH

Assuming the coin is a fair coin, we have:
Probability of tossing head is 0.5
Probability of tossing tail is 0.5

Probability of tossing the coin four times for each outcome combination listed above is

HTTT = 0.5×0.5×0.5×0.5 = 0.0625
THTT = 0.5×0.5×0.5×0.5 = 0.0625
TTHT = 0.5×0.5×0.5×0.5 = 0.0625
TTTH = 0.5×0.5×0.5×0.5 = 0.0625

Hence, probability of getting three tails and one head from 4 tossing is 
4×0.0625 = 0.25

Answer: False

Martin is asked to find the probability of getting one head and three tails on for coin tosses this is a simple event.

A. True

B. False

I need to find the answer to these questions in about 10 minutes or I'm screwed. please help me out.

Answers

For the first figure, the geometric figure used in the construction that is shown is the intersection of the angle bisectors of the triangle is the center of the inscribed circle.

For the second figure, the construction of the above figure in the circle represents how to find the intersection of the perpendicular bisectors of triangle ABC.

For the third figure, the statement that is demonstrated in the in line P intersecting line m perpendicularly is the set of points equidistant from the endpoints of  a line segment  is the perpendicular bisector of the segment.

How do you get rid of an exponent on a variable?

Answers

To get rid of an exponent to do the inverse function which is to take the root, or you can expand it. 
Final answer:

To get rid of an exponent on a variable, apply the inverse operation of the exponent such as division or root operations.

Explanation:

To get rid of an exponent on a variable, you need to apply the inverse operation of the exponent. If the exponent is multiplication, you use division, and if the exponent is an exponentiation, you use a root operation. For example, to get rid of a squared variable, you take the square root of the variable. If you have a variable raised to the third power, you take the cube root of the variable.

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What is 5 plus 5 minus 5 divided by 5 and then multiplied by 5?

Answers

With the order of operations first, you multiply and divide from left to right:

So you have 5+5-5/5(5)

We will divide first:
5+5-1(5)

Then multiply:
5+5-5

Then add and subtract from left to right:
10-5=5

Hope that helps.

Answer:

45

Step-by-step explanation:

[tex](5+5-5:5)\cdot5\\\\\text{Use PEMDAS}\\\\\text{P Parentheses first}\\\text{E Exponents}\\\text{MD Multiplication and Division (left-to-right)}\\\text{AS Addition and Subtraction (left-to-right)}\\\\=(5+5-1)\cdot5\\\\=(10-1)\cdot5\\\\=9\cdot5\\\\=45[/tex]

In triangle PQR, C is the centroid.

A. If CY = 10, find PC and PY
B. If QC = 10, find ZC and ZQ
C. If PX = 20, find PQ

Answers

Because point C is the centroid of the triangle, therefore:

Segments PZ = ZR;  RY = YQ; QX = XP

A.
If CY = 10, then

PC = 2*CY = 20
PY = PC + CY = 20 + 10 = 30
Answers:     

PC = 20     

PY = 30

B.
If QC = 10, then

ZC = QC/2 = 5
ZQ = ZC + QC = 5 + 10 = 15
Answers:     

ZC = 5       

ZQ = 15

C.
If PX = 20
because the median RX bisects side PQ, therefore PX = QX = 20
PQ = PX + QX = 40
Answer:      

PQ = 40

The sum of the digits of a certain number is 12. When you reverse its digits you decrease the number by 36. Find the number

Answers

x+y=12

x*y =36

8+4=12, so make the digits 84, reverse to make it 48

84-48=36

 the numbers are 8 & 4

HELPPP Plzzzzzzzzzz ASAP
Use Addition of Composite Figures to find the total shaded regions.

1) Find the shaded area. Round your answer to the nearest tenth, if necessary.

Answers

12*6 = 72 - (3*4) = 60 - (4*5) = 40
Come on, Queen. You can do this. It's a square sitting on top of a long skinny rectangle. The rectangle is 12 wide and 2 high. It's area is 12x2=24. The only tough part is figuring out the width of the block sitting on it. The width of the block is what's left after you subtract the 5 and the 3 from the 12. That's (12-5-3)=4. Whaddaya know ! The block is 4 wide and 4 high ... It's a square ! Its area is 4x4=16. Add that to the area of the rectangle and you have the answer.

Find the length of the diameter of a sphere with a surface area of 452.39^2 ft.

Answers

surface area = 4*pi*r^2

using 3.14 for pi

452.39 = 4*3.14*r^2=

452.39=12.56* r^2

r^2 = 452.39/12.56 = 36.0


sqrt(36) = 6= r

diameter = 2r = 6*2= 12

 diameter = 12 feet

For a fixed amount of a gas at a constant temperature, the volume of the gas is inversely proportional to its pressure. At a pressure of 30 pounds per square inch (psi), a gas has a volume of 600 in.3. Which function can be used to model the volume of the gas y, in cubic inches, when the pressure is x psi?

Answers

we know that

A relationship between two variables, x, and y, represent an inverse variation if it can be expressed in the form [tex]y*x=k[/tex] or [tex]y=k/x[/tex]

Let

x-------> the pressure in PSI

y------> the volume of the gas in cubic inches

In this problem we have the point [tex](30,600)[/tex]

so

[tex]x=30\ psi\\y=600\ in^{3}[/tex]

Find the constant k

[tex]y*x=k[/tex]

substitute the values of x and y

[tex]600*30=k[/tex]

[tex]k=18,000\ lb*in[/tex]

the equation is

[tex]y=18,000/x[/tex]

therefore

the answer is

[tex]y=18,000/x[/tex]

Answer:

[tex]y=\frac{18000}{x}[/tex]

Step-by-step explanation:

Let the volume of gas be y

Let the pressure be x

Since we are given that the volume of the gas is inversely proportional to its pressure.

⇒[tex]y \propto \frac{1}{x}[/tex]

Let the proportionality be k

So, [tex]y=\frac{k}{x}[/tex]  ---A

Now we are given that At a pressure of 30 pounds per square inch (psi), a gas has a volume of 600 cubic inches

So, substitute x = 30

y = 600

[tex]600=\frac{k}{30}[/tex]

[tex]600 \times 30=k[/tex]

[tex]18000 =k[/tex]

Substitute the value of k in A

So,  [tex]y=\frac{18000}{x}[/tex]

Hence  function can be used to model the volume of the gas y, in cubic inches, when the pressure is x psi is    [tex]y=\frac{18000}{x}[/tex]

5v + 7f =28.70 if f is 2.85

Answers

5v+7(2.85)=28.70

5v+19.95 = 28.70

5v = 8.75

v = 1.75

Hey!

First, let's write the problem.
[tex]5v+7\left(2.85\right)=28.7[/tex]
Multiply [tex]7[/tex] with [tex]2.85[/tex].
[tex]5v+19.95=28.7[/tex]
Subtract [tex]19.95[/tex] from both sides.
[tex]5v+19.95-19.95=28.7-19.95[/tex]
[tex]5v=8.75[/tex]
Divide both sides by [tex]5[/tex].
[tex]\frac{5v}{5}=\frac{8.75}{5}[/tex]
[tex]v=1.75[/tex]

Let me know if you have any questions regarding this problem!
Thanks!
-TetraFish

Identify a semicircle that contains C.

A.ABC
B.AC
C.CB
D. ACB

Answers

A semicircle that contains C is ACB.

Answer:  The correct option is (D). ACB.

Step-by-step explanation:  We are given to identify a semi-circle that contains the point 'C'.

As shown in the figure, AB is the diameter of the circle with center 'O'.

So, there are two congruent semi-circles made by the diameter AB.

The point 'C' lies on the upper semi-circle made by the diameter AB.

Since the upper semi-circle contains the point 'C', so it is named as the semi-circle ACB.

Thus, the semi-circle ACB contains the point 'C'.

Option (D) is correct.

I don't understand this and would appreciate an explanation as well :)
Solve for the variable in the equations below.
Round your answers to the nearest hundredth.
Do not round any intermediate computations.

e^x = 6

4^(y+3) = 3

[tex]e^x = 6[/tex]
[tex]4^y^+^3 = 3 [/tex]

Answers

We want to solve the two equations
[tex]e^{x}=6[/tex]
and
[tex]4^{y+3}=3[/tex]

First equation.
Take natural log of each side.
[tex]ln(e^{x})=ln(6)\\xln(e)=ln(6)\\ x=ln(6)=1.7918[/tex]
Note that ln(e) = 1 by definition.
Answer: x = 1.79 (nearest hundredth)

Second equation.
Take natural log of each side.
[tex]ln(4^{y+3})=ln(3)\\ (y+3)ln(4)=ln(3)\\ y+3= \frac{ln(3)}{ln(4)} =0.7925\\y=0.7925-3=-2.2075[/tex]
Answer: y = -2.21 (nearest hundredth)

In how many ways can 2 singers be selected from 4 who came to an audition?

A. 6
B. 2
C. 12
D. 4

In a batch of 280 water purifiers, 12 were found to be defective. What is the probability that a water purifier chosen at random will be defective? Write the probability as a percent. Round to the nearest tenth of a percent if necessary.

A. 4.3%
B. 5.6%
C. 95.7%
D. 71.8%

Answers

First part  its 4C2  = 4*3 / 2 = 6

Second part
12 * 100
----------    =   4.3 %
   280

Answer: A. 6

A. 4.3%

Step-by-step explanation:

The total number of singers = 4

To choose singers = 2

The number of ways to choose 2 singers from 4= [tex]^4C_2=\frac{4!}{2!(4-2)!}=3\times2=6[/tex]

Hence, A is the right option.

The total number of water purifiers  T= 280

The number of defective purifiers D= 12

The probability that a water purifier chosen at random will be defective (in percent)=[tex]\frac{\text{T}}{\text{D}}\times100[/tex]

[tex]=\frac{12}{280}\times100\\=0.042857\times100\\=4.2857\%\approx4.3\%[/tex]

Hence, A is the right option.

Solve the equation: h/9 = 7. A. h = 1 2/7 B. h = 63 C. h = –63 D. h = 7/9

Answers

 I did this on a calculator so i'm 100% sure it's correct.
 
The answer is:  B. h= 63
Well, just times 7 and 9 since if you times 9 on both side,  h will be alone. Then just times 7 and 9 and will get 63, which is B.

The area of the right triangle shown is 24 square feet. Which equations can be used to find the lengths of the legs of the triangle? Check all that apply.

0.5(x)(x + 2) = 24

x(x + 2) = 24

x2 + 2x – 24 = 0

x2 + 2x – 48 = 0

x2 + (x + 2)2 = 24

x2 + (x + 2)2 = 100

Please help me quickly, I really need the help. I'll even mark brainiest if you do it correctly. I really need this and I need whoever does this to pay attention to the whole "Check all that apply". I'm adding the picture below.

Answers

Given : A  = 24 sq feet

A = 0.5 base x height

base = x , height = x+2

A = 0.5 x(x+2)  = 24 sq feet

1) 0.5 x(x+2) = 24 (A) 

2) x^2 + 2x - 48 = 0 (D)

To check the rest un-wrap the bracket:

x^2 + (x+2)^2 = 24

x^2 + x^2 + 4 + 4x = 24

2x^2 + 4x - 20 = 0

x^2 + 2x - 10= 0 (NO)

Likewise:

x^2 + (x+2)^2 = 100

x^2 + x^2  +4 + 4x = 100

2x^2 + 4x + 4 = 100

2x^2 + 4x - 96 = 0

3) x^2 + 2x - 48 = 0 (F)


To sum up: that's what apply:

1) 0.5 x(x+2) = 24 (A) 

2) x^2 + 2x - 48 = 0 (D)

3) x^2 + 2x - 48 = 0 (F)

The equation that can be used to find the lengths of the legs of the triangle is [tex]\rm 0.5(x)(x + 2) = 24[/tex]

Given that

The area of the right triangle shown is 24 square feet.

We have to determine

Which equations can be used to find the lengths of the legs of the triangle?

According to the question

From the given figure the base of the triangle is x.

And the height of the triangle is (x+2).

What is the area of a triangle?

The area of the triangle is given by half the product of the height and base.

[tex]\rm Area = \dfrac{1}{2} \times base \times height\\ [/tex]

Substitute all the values in the formula;

[tex]\rm Area \ of \ right \ triangle= \dfrac{1}{2} \times base \times height\\ \\ \rm 24= \dfrac{1}{2} \times x \times (x+2)\\\\ \rm 0.5(x)(x + 2) = 24[/tex]

The equation can be used to find the lengths of the legs of the triangle is [tex]\rm 0.5(x)(x + 2) = 24[/tex].

Hence, the equation can be used to find the lengths of the legs of the triangle is [tex]\rm 0.5(x)(x + 2) = 24[/tex].

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A new machine can make 10,000 aluminum cans three times faster than an older machine. with both machines working, 10,000 cans can be made in 9 hours. how long would it take the new machine, working alone, to make the 10,000 cans?

Answers

it takes at least 12 hours for the newer machine to make 10,000 cans

Since the new machine is three times faster, it takes (12 hours) / 3 = 4 hours for the new machine to make 10,000 cans alone.

Let's denote the time it takes the older machine to make 10,000 cans as "t" hours.

The new machine can make 10,000 cans three times faster than the older machine, which means it takes "t/3" hours for the new machine to make 10,000 cans.

When both machines are working together, they can make 10,000 cans in 9 hours.

Now, we can set up an equation based on the work rates of the two machines:

Work rate of the older machine + Work rate of the new machine = Combined work rate

The work rate is the amount of work (number of cans made) per unit of time (hours).

For the older machine:

Work rate of the older machine = 10,000 cans / t hours

For the new machine:

Work rate of the new machine = 10,000 cans / (t/3) hours

Combined work rate when both machines work together:

Combined work rate = 10,000 cans / 9 hours

Now, the equation becomes:

10,000 cans / t hours + 10,000 cans / (t/3) hours = 10,000 cans / 9 hours

To solve for "t," we can start by finding a common denominator for the fractions on the left side of the equation:

t/3 is the same as (1/3)t. So the equation becomes:

10,000 cans / t hours + 10,000 cans / (1/3)t hours = 10,000 cans / 9 hours

Now, to combine the fractions, we find the common denominator, which is 3t:

(3t * 10,000 cans) / (3t * t hours) + (t * 10,000 cans) / (3t * t hours) = 10,000 cans / 9 hours

(30,000t + 10,000t) / (3t^2 hours) = 10,000 cans / 9 hours

Combine the terms on the left side of the equation:

40,000t / (3t^2 hours) = 10,000 cans / 9 hours

Now, cross-multiply to solve for "t":

40,000t * 9 hours = 10,000 cans * 3t^2 hours

360,000t hours = 30,000t^2 hours

Now, rearrange the equation:

30,000t^2 - 360,000t hours = 0

Divide by 30,000t to simplify the equation:

t - 12 = 0

Now, solve for "t":

t = 12 hours

Therefore, it takes the older machine 12 hours to make 10,000 cans.

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State the Midpoint formula?

How are the midpoint formula and the Distance formula alike? How are they different?

Give a real-world example that could be addressed using the distance formula.

Give a real-world example that could be addressed using the midpoint formula.

Answers

Let point A (x₁, y₁) and point B (x₂, y₂)

Mid-point formula is given by: [tex][ \frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}] [/tex]

The distance formula is given by: [tex] \sqrt{(x_1-x_2)^2+(y_1-y_2)^2} [/tex]

The two formula are alike because they both need the information of two coordinate points 

They are different because the mid point formula is adding up then divide by two, whereas the distance formula is subtracting then square the answer.

--------------------------------------------------------------------------------------------------------------
Real life problem involving distance formula:

Plane A is spotted on a radar with cartesian coordinate (450, 640).
Plane B is spotted on the same radar with cartesian coordinate (350, 540)

Work out the distance between plane A and plane B.
--------------------------------------------------------------------------------------------------------------
Real life problem involving mid point formula

Ms. Holland arranges a treasure hunt for a group of scouts. She marks two points, C and D, with cartesian coordinate (-5, 6) and (7, 10) respectively. The clue is that the treasure is buried in the middle point between C and D. Work out the coordinate where the treasure is buried.
 

What is the missing step in this proof?

Answers

The answer is the third choice..
Statement: Angle 1 and angle 4 are congruent, and angle 3 and angle 5 are congruent.
Reason: Alternate Interior Angles Theorem

Hope this helps!

The missing step in the proof is;

Statement: ∠1 ≅ ∠4 and ∠3 ≅ ∠5Reason: Alternate interior angle theorem.

The correct answer choice is option C.

What is alternate interior angles theorem?

Alternate angle theorem states that when two parallel lines are cut by a transversal, the resulting alternate interior or exterior angles are congruent.

It is used to prove that alternate interior angles are equal if two parallel lines are cut by a transversal,

Hence, angle 1 is congruent to angle 4 and angle 3 is congruent to angle 5.

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Which is a sum of cubes? a3 + 18 a6 + 9 a9 + 16 a12 + 8
a3 + 18
a6 + 9
a9 + 16
a12 + 8

Answers

Answer: [tex]a^{12}+8[/tex]


Step-by-step explanation:

let's check all the expressions

1. [tex]a^3+18[/tex]

here 18 is not a perfect cube.

2. [tex]a^6+9[/tex]

here 9 is not a perfect cube.

3.[tex]a^9+16[/tex]

here 16 is not a perfect cube.

4.[tex]a^{12}+8[/tex]

here 8 is a perfect cube, thus we can write above expression by using laws of exponents as

[tex](a^4)^3+2^3[/tex]

Thus, [tex]a^{12}+8[/tex] is a sum of cubes.

Solve the equation: 2.6 = -0.2t

Answers

2.6 = -0.2t...divide both sides by -0.2
2.6 / -0.2 = t
-13 = t <==
2.6=-0.2t
T=2.6/-0.2=-13

T= -13

Hope this helps!

A school director must randomly select 6 teachers to participate in a training session. There are 34 teachers at the school. In how many different ways can these teachers be selected, if the order of selection does not matter?

Answers

The selection of r object out of n, is carried out in C(n, r) many ways, 

where [tex]C(n, r)= \frac{n!}{r!(n-r!)} [/tex]

n! meaning 1*2*3*....*(n-1)*n


According to this, the selection of 6 teachers out of 34, can be carried out in C(34, 6) many different ways.

[tex]C(34, 6)= \frac{34!}{6!(34-6!)}=\frac{34!}{6!(28!)}= \frac{34*33*32*31*30*29*28!}{6!28!}= \frac{34*33*32*31*30*29}{6!}[/tex]

[tex]=\frac{34*33*32*31*30*29}{6*5*4*3*2*1}= 34*11*4*31*29=1,344,904[/tex]
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