suppose someone tells you that she has a triangle with sides having lengths 2.6,8.1 and 8.6. Is this a right triangle? why or why not? Is there an angle in the triangle larger than 90 degree?

Answers

Answer 1

If you're only provided with the lengths of a triangle, and you're asked to determine whether or not the triangle is right or not, you'll need to rely on the Pythagorean Theorem to help you out. In case you're rusty on it, the Pythagorean Theorem defines a relationship between the legs of a right triangle and its hypotenuse, the side opposite its right angle. That relationship is a² + b² = c², where a and b are the legs of the triangle, and c is its hypotenuse. To see if our triangle fits that requirement, we'll have to substitute its lengths into the equation.

How do we determine which length is the hypotenuse, though? Knowledge that the hypotenuse is always the longest length of a right triangle helps here, as we can clearly observe that 8.6 is the longest we've been given for this problem. The order we pick the legs in doesn't matter, since addition is commutative, and we'll get the same result regardless of the order we're adding a and b.

So, substituting our values in, we have:

(2.6)² + (8.1)² = (8.6)²

Performing the necessary calculations, we have:

6.76 + 65.61 = 73.96
72.37 ≠ 73.96

Failing this, we know that our triangle cannot be right, but we do know that 72.37 < 73.96, which tells us something about what kind of triangle it is. Imagine taking a regular right triangle and stretching its hypotenuse, keeping the legs a and b the same length. This has the fact of increasing the angle between a and b. Since the angle was already 90°, and it's only increased since then, we know that the triangle has to be obtuse, which is to say: yes, there's an angle in it larger than 90°.

Related Questions

Write a problem saying a single load of laundry cost $2 and a double load costs $4 the machine only accept quarters what is the answer

Answers

The problem is: A laundromat charges $2 for a single load of laundry and $4 for a double load. The machine only accepts quarters. How many quarters are needed to wash two double loads of laundry?

To solve this problem, we first need to determine the total cost of washing two double loads. Since each double load costs $4, two double loads will cost 2 * $4 = $8.

Next, we need to determine how many quarters are in $8. Since there are 4 quarters in a dollar, there are 4 * 8

= 32 quarters in $8.

Therefore, 32 quarters are needed to wash two double loads of laundry

How would you express as a unit rate: morag typed 60 words in one minute

Answers

Hello There!

I'm not sure what else you need to do as this answer is already in unit rate.

Hope This Helps You!
Good Luck :)

- Hannah ❤

Morag would be typing at a rate of 60 words per minute (wpm) in order to type 60 words in one minute.

What is Unit conversion?

A statement of the connection between units that are used to alter the units of a measured quantity without affecting the value is called a conversion factor. A conversion ratio (or unit factor), if the numerator and denominator have the same value represented in various units, always equals one (1).

To express Morag's typing speed as a unit rate, we would divide the number of words by the number of minutes.

Therefore, the unit rate for Morag typing 60 words in one minute would be 60 words per minute (60 wpm).

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In an x-y plot of an experiment what is usually plotted on the x axis?
a. the independent variable, which is the parameter that was manipulated.
b. th

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The answer is a. In an experiment, you manipulate the independent variable.

Kristina invests $5,000 at 15% simple interest for 2 years.How much interest did Kristina earn over the 2 years?

Answers

using
SI = PRT/100
=( 5000 × 15 × 2)/100
= 50×15×2= 1500$

What is the area of a triangle with verticies at (-2,1), (2,1) and (3,4)

Answers

check the picture below.

notice, is just a triangle with a base of 4, and an altitude of 3.

how many solutions are in 6x+4x-6=24+9x

Answers

One.

To solve this, first combine like terms.

6x + 4x - 6 = 24 + 9x

10x - 6 = 24 + 9x

Then move all like terms to one side.

10x - 9x = 24 + 6

x = 30

10x-6=9x+24
x=30
..........

Jeff invests an amount at 4% interest compounded annually. After 3 years, he has $1687.30. What was the original amount Jeff invested?

$1500

$1200

$1450

$750

Answers

In order to determine the principal amount, remember that $1,687.30 is the principal amount plus all interest accumulated over 3 years.
:
To find the effect of 4% annual interest over 3 years, take 1.04 and raise it to the third power:
1.04³ = 1.125

Divide the final amount, 1687.30 by 1.125 to find the principal amount:
1687.30 ÷ 1.125 = ~1500
Answer is A.

Help with Precalc Vectors? Medal and fan v = (-7,8) Find the magnitude of vector v. Express your answer in radical form sqrt of 113 is what I got for that. second part: use the magnitude and the angle of vector v to write it in the form (lvlcostheta, lvl sin theta). I don't know how to determine the single angle for one vector. Earlier in a different part of the problem, I was asked to find the angle between two vectors, but I don't think you use that here since no second vector is provided. So how would I answer the second part? Thanks(:

Answers

Hello Kaviipik!
Lets find the mag of v = (-7,8). Since we have one order pair we are finding the mag from the origin.
Yes we are using Pythagorean Theorem to calculate the magnitude
[tex]a^2 + b^2 = c^2[/tex]

[tex]\sqrt{v^2} = \sqrt{(-7)^2 + (8)^2}[/tex]
[tex]v = \sqrt{(-7)^2 + (8)^2}[/tex]
[tex]v = \sqrt{49 + 64}[/tex]
[tex]v = \sqrt{113}[/tex]
[tex]v = \sqrt{113} = 10.6301458[/tex]
Now we use
[tex]\theta = tan^{-1} (\frac{b}{a})[/tex]
[tex]\theta = tan^{-1} (\frac{8}{-7})= 48.8[/tex]
[tex](\sqrt{113} \times cos(48.8) , \sqrt{113} \times sin(48.8) )[/tex]

Final answer:

To express the vector v = (-7,8) in the form (|v|cosθ, |v|sinθ), you first correctly found the magnitude |v| using the Pythagorean theorem. Then, to find the angle θ, use the arctangent function applied to the y/x components of your vector. Ensure the angle is in the correct quadrant by modifying it if necessary.

Explanation:

To find the magnitude of the vector v = (-7,8), you've correctly done the Pythagorean theorem and found sqrt(113), which is the absolute value of your vector, written as |v|. Now, to express the vector in the form (|v|cosθ, |v|sinθ), we need to find the angle θ. This is found using the arctangent function (also known as the inverse tangent or atan). θ = atan(y/x), where x and y are the x and y components of your vector respectively. Be careful with the sign as atan can only return values from -π/2 to π/2.

In your case θ = atan(8/-7), but since this gives a negative answer and the vector is in the second quadrant where angles are positive, you should add π to your result to get the correct angle. Then you can substitute |v| and θ into the expressions for the x and y components.

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What is 164% of 25? I have no idea and im in the middle of a test XDDD

Answers

The answer is 41. Hope this helps!

n=6x35+4 what does n represent in a division problem

Answers

answer is 214 - n = 214

What is the meaning of the function of h = f(50, t)? describe the behavior of this function?

Answers

Dependent variable h depends upon two independent variaables, one of which is represented by 50 and the other by the letter t. In other words, h is a function of two variables. Without further detail it is impossible to describe the behavior of this function h=f(50,t).

Suppose that h = f(x,t) = 2x - 1/t. This is my invention.

Then f(50,t) would come out as 2(50) - 1/t, which is a function of just 1 variable.

Simplify 6 - 23 + (-9 + 5) · 2
A. -10
B. -12
C. 6
D. -8

I've been told the answer is A. -10, but I need to know how to get that answer.
Thanks.

Answers

at least u tried to help but the answer is -10 bro

√10, π, 3.5
order least to greatest

Answers

π, √10, 3.5

3.14, 3.16, 3.5

From least to greatest, we have:
___________________________________
" π , √10 , 3.5 " .
___________________________________

We have: "3.5" (given) ;

" π " = 3.14159...

"√10" = 3.162277660168379
___________________________________
So, from least to gretest, we have:
___________________________________
" π , √10 , 3.5 " .
___________________________________

Simplyfy (x - 5 / x^3 + 27) + (2 / x^2 - 9)

Answers

The answer simplified should be x-5/x^3+18+2/x^2. Hope that is helpful.

[tex]\bf \textit{difference of squares} \\ \quad \\ (a-b)(a+b) = a^2-b^2\qquad \qquad a^2-b^2 = (a-b)(a+b)\\ \quad \\ \textit{difference of cubes} \\ \quad \\ a^3+b^3 = (a+b)(a^2-ab+b^2)\qquad (a+b)(a^2-ab+b^2)= a^3+b^3 \\\\ -------------------------------\\\\[/tex]

[tex]\bf \cfrac{x-5}{x^3+27}+\cfrac{2}{x^2-9}\implies \cfrac{x-5}{x^3+3^3}+\cfrac{2}{x^2-3^2} \\\\\\ \cfrac{x-5}{(x+3)(x^2-3x+3^2)}+\cfrac{2}{(x-3)(x+3)}\\\\\\ \cfrac{x-5}{(x+3)(x^2-3x+9)}+\cfrac{2}{(x-3)(x+3)} \\\\\\ \textit{so, we'll use the LCD of }(x-3)(x+3)(x^2-3x+9) \\\\\\ \cfrac{(x-3)(x-5)~~+~~(x^2-3x+9)2}{(x-3)(x+3)(x^2-3x+9)} \\\\\\ \cfrac{x^2-8x+15~~+~~2x^2-6x+18}{(x-3)(x+3)(x^2-3x+9)}\implies \cfrac{3x^2-14x+33}{(x-3)(x+3)(x^2-3x+9)}[/tex]

How do you solve an inequality

Answers

We can often solve inequalities by adding or subtracting a number from both sides

Answer:

you solve an inequality by doing the inverse equation on each side of the equation.

Step-by-step explanation:

A boat was sailing for 4 hours and covered 224 miles. A jet is ten times as fast as the boat. Find the jet’s speed.

Answers

First, you would need to find out how many miles the boat can sail in 1 hour. To do this, you would divide the total number of miles traveled by the time it took to travel it.
224 ÷ 4 = 56
56 mi/1 h

Next, you would multiply the number of miles the boat traveled, 56, by 10.

56 x 10 = 560

The jet flew 560 mi/per hour

I hope this helps!

224/4 = 56 miles per hour
56 x 10 = 560 miles per hour

equivalent ratios number 1 to 50

Answers

are you meaning something like 1 to 50= 2 to 100 or something like 1 to 50, 1:50,1/50 they all r the same??

2:100 will be equivalent to 1:50

How do i know that the variable x has a uniform distribution function?

Answers

you will have to solve for x to know what x equals

Hi, How do you find the first and second derivatives of the function.
y=(x^2-7/63x) (x^4+1/x^3)

I think for the first derivative dy/dx it's 2/63x-3/63x^-3+4/9x^-5 but I'm not sure, and I have no clue for the second derivative d^2y/dx^2.

Answers

The first hand derivative of the function is [tex]6x^5 - \frac{35}{63}x^4 - \frac{1}{x^2} - \frac{4}{63x^3}[/tex] and the second derivative is [tex]30x^4 - \frac{20}{9}x^3 + \frac{2}{x^3} - \frac{2}{3x^4} \\[/tex]. To find the first derivative, apply the product rule to the given function. Then, differentiate the first derivative to obtain the second derivative. Simplify each step carefully.

To find the first derivative of the given function [tex]y = \left( x^2 - \frac{7}{63}x \right) \left( x^4 + \frac{1}{x^3} \right)[/tex], we'll use the product rule, which states that if [tex]y = u(x) \cdot v(x)[/tex], then [tex]y' = u' \cdot v + u \cdot v'[/tex].

First, define u(x) and v(x) as following:

[tex]u(x) = x^2 - \frac{7}{63}x = x^2 - \frac{1}{9}x[/tex][tex]v(x) = x^4 + \frac{1}{x^3}[/tex]

Compute u'(x):

[tex]u'(x) = 2x - \frac{1}{9}[/tex]

Compute v'(x):

[tex]v'(x) = 4x^3 + (-3)x^{-4} = 4x^3 - \frac{3}{x^4}[/tex]

Apply the product rule: [tex]y' = u' \cdot v + u \cdot v'[/tex]

Thus,

[tex]y' = \left(2x - \frac{1}{9}\right)\left( x^4 + \frac{1}{x^3} \right) + \left( x^2 - \frac{1}{9}x \right) \left( 4x^3 - \frac{3}{x^4} \right)[/tex]

Simplify this expression step-by-step to find the first derivative.

[tex]y' = \left(2x - \frac{1}{9}\right)\left( x^4 + \frac{1}{x^3} \right) + \left( x^2 - \frac{1}{9}x \right) \left( 4x^3 - \frac{3}{x^4} \right)[/tex][tex]y'[/tex] [tex]&= \left(2x \cdot x^4 + 2x \cdot \frac{1}{x^3} - \frac{1}{9} \cdot x^4 - \frac{1}{9} \cdot \frac{1}{x^3} \right)[/tex][tex]&\quad + \ \left( x^2 \cdot 4x^3 - x^2 \cdot \frac{3}{x^4} - \frac{1}{9}x \cdot 4x^3 + \frac{1}{9}x \cdot \frac{3}{x^4} \right)[/tex][tex]y'[/tex] [tex]&= 2x^5 + \frac{2}{x^2} - \frac{1}{9}x^4 - \frac{1}{9x^3} \\[/tex] [tex]&\quad + \ 4x^5 - \frac{3}{x^2} - \frac{4}{9}x^4 + \frac{1}{3x^3}[/tex][tex]y'[/tex] [tex]&= 6x^5 - \frac{1}{x^2} - \frac{5}{9}x^4 + \frac{2}{9x^3}[/tex][tex]y'[/tex] [tex]&= 6x^5 - \frac{5}{9}x^4 - \frac{1}{x^2} + \frac{2}{9x^3}[/tex]

To find the second derivative, differentiate the first derivative, carefully differentiating each term:

[tex]y'' &= \frac{d}{dx}\left( 6x^5 \right) - \frac{d}{dx}\left( \frac{5}{9}x^4 \right) - \frac{d}{dx}\left( \frac{1}{x^2} \right) + \frac{d}{dx}\left( \frac{2}{9x^3} \right) \\[/tex][tex]y''[/tex] [tex]&= 30x^4 - \frac{5}{9} \cdot 4x^3 - \left( -2x^{-3} \right) + \left( -\frac{2}{9} \cdot 3x^{-4} \right) \\[/tex][tex]y''[/tex] [tex]&= 30x^4 - \frac{20}{9}x^3 + \frac{2}{x^3} - \frac{2}{3x^4} \\[/tex]

So, for the function [tex]y = \left( x^2 - \frac{7}{63}x \right) \left( x^4 + \frac{1}{x^3} \right)[/tex], we have:

First derivative [tex](y')[/tex] [tex]&= 6x^5 - \frac{5}{9}x^4 - \frac{1}{x^2} + \frac{2}{9x^3}[/tex]Second derivative [tex](y'')[/tex] [tex]&= 30x^4 - \frac{20}{9}x^3 + \frac{2}{x^3} - \frac{2}{3x^4} \\[/tex]

What is the answer to this question ?

Answers

A is not commutative with the above expression
your answer is A

PLZ HELP I WILL MAKE YOU BRAINLIEST!! IT IS GOOD FOR YOUR PROFILE!

Rewrite as a square or a cube:
1 11/25

Answers

1 11/25 = 36/25
= (6/5)^2

Answer:

1 11/25 = 36/25

= (6/5)^2

Step-by-step explanation:

What is the reason for each step in the solution of the inequality?

−2(x+3)−4>4x+30

Select the reason for each step from the drop-down menus.

2nd picture is drop down box answers.

Answers

-2(x + 3) - 4 > 4x + 30 : Given
-2x - 6 - 4 > 4x + 30 : distributive property
-2x - 10 > 4x + 30 : combine like terms
-6x - 10 > 30 : subtraction property
-6x > 40 : addition property
x < -20/3 : division property

[tex]-2(x + 3) - 4 \ \textgreater \ 4x + 30[/tex] : Given
[tex]-2x - 6 - 4 \ \textgreater \ 4x + 30[/tex] : Distributive property
[tex]-2x - 10 \ \textgreater \ 4x + 30[/tex] : Combine like terms
[tex]-6x - 10 \ \textgreater \ 30[/tex] : Subtract
[tex]-6x \ \textgreater \ 40[/tex] : Add
[tex]x \ \textless \ - \dfrac{20}{3} [/tex] : divide

How does the throughput of pci express version 3.0 compare to pcie version 2.0?

Answers

PCI(e) version 3.0 has a throughput twice as fast as that of its predecessor. Version 2.0 had a maximum throughput of 16Gb/second, while version 3.0 increased the maximum theoretical speed to 32Gb per second. This allows for much faster data transfer when using objects like solid state hard drives and ethernet cards.

Jasmine finished the bike trail in 2.5 hours at an average rate of 2.5 miles per hour.Lucy biked the same trail at a rate of 6 1/5 mile per hour.How long did it take lucy to bike the trail?

Answers

2.5 hours at a rate of 2.5 miles per hour = 2.5 * 2.5 = 6.25 miles

the trail was 6.25 miles long

Lucy rode at 6 1/5 mile per hour

so 6.25 / 6 1/5 = 1.008 = 1.01 hours

A 27 oz bottle of a new soda costs $2.25. What is the unit rate, rounded to the nearest tenth of a cent?

Answers

27 / 2.25 =
1 / x =
Divide 2.25 by 27 to get
.08 dollars per ounce

Final answer:

The unit rate is the cost per ounce of soda. By dividing the total cost by the total ounces, we get the price per ounce in dollars ($0.08333), and converting this to cents gives us $8.3 cents per ounce.

Explanation:

The term unit rate refers to a rate in which the second term is 1. In this case, we want to find out how much 1 ounce of soda costs.

First, you want to divide the total cost of the bottle by the total ounces in the bottle. So you divide $2.25 by 27. The answer you get is the price of one ounce of soda in dollars. When calculating it, you get approximately $0.08333.

To get the rate in cents, convert the dollars to cents by multiplying by 100 (since 1 dollar is 100 cents). The answer ($8.33) is the cost of one ounce to the nearest tenth of a cent.

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what is the solution of -8/2y-8=5/y+4 - 7y+8/y^2-16? y = –4 y = –2 y = 4 y = 6

Answers

Please clarify whether you meant (-8/2)y or -8 / (2y - 8).

It's always a good idea to use parentheses for clarity; it reduces or removes the need for guessing.

Here is my interpretation of your equation:

-8/2y-8=5/y+4 - 7y+8/y^2-16 becomes

-8 / (2y-8) = 5 / (y+4) - 7y + 8 / (y^2-16) (note use of parentheses)

Factoring all of the denominators results in:

-8 / [2(y-4)] = 5 / (y+4) - 7y + 8 / [(y-4)(y+4)]

The LCD is 2(y-4)(y+4). You must multiply each and every term in the above equation by this LCD to clear fractions:

-8(y+4) = 5(2)(y-2) - 7(y+4)(y-4) + 8/2

Then -8y - 32 = 10y -20 -7y^2 + 4

I believe the "-7y^2" term is incorrect.

In retrospect, you could simply substitute each of the given answers (y-values), one at a time, to determine which, if any, makes the equation true:

-8 / (2y-8) = 5 / (y+4) - 7y + 8 / (y^2-16) (note use of parentheses)

Let's test y = 4. Is this a solution? Subst. 4 for y in the above equation, we get:

-8 / (8-8) and several more terms. No, 4 is not a solution, because
-8 / (0) is undefined. Eliminate y = 4 as a solution. Try y = -4 and the other given possible solutions. Do any of them make this equation true?

Answer:

d. 6

Step-by-step explanation:

just took the pretest:) have such a fantastic day loves, you're doing AMAZING!

How many times does 1/2 fit into 30

Answers

It fits in the 30, 60 times.

30 ÷ [tex] \frac{1}{2} [/tex]

To divide by a fraction, multiply by its reciprocal (find reciprocal by flipping the fraction)

Ex. 30 * 2

Multiply 30 by 2 to get 60.

Calculate the mean of the number set 5 10 12 4 6 11 13 5

Answers

For calculating the mean, you want to add up all of the numbers then divide by how many numbers there are. So you'd do:

5+10+12+4+6+11+13+5 then divide that by 8

The answer to your question is: 8.25

Find the gradient of the function at the given point. function point f(x, y, z) = x2 + y2 + z2 (3, 9, 8)

Answers

Answer:

[tex]\displaystyle \nabla f(3, 9, 8) = 6 \hat{\i} + 18 \hat{\j} + 16 \hat{\text{k}}[/tex]

General Formulas and Concepts:

Calculus

Differentiation

DerivativesDerivative Notation

Derivative Rule [Basic Power Rule]:

f(x) = cxⁿf’(x) = c·nxⁿ⁻¹

Multivariable Calculus

Differentiation

Partial DerivativesDerivative Notation

Gradient: [tex]\displaystyle \nabla f(x, y, z) = \frac{\partial f}{\partial x} \hat{\i} + \frac{\partial f}{\partial y} \hat{\j} + \frac{\partial f}{\partial z} \hat{\text{k}}[/tex]

Gradient Property [Addition/Subtraction]: [tex]\displaystyle \nabla \big[ f(x) + g(x) \big] = \nabla f(x) + \nabla g(x)[/tex]

Gradient Property [Multiplied Constant]: [tex]\displaystyle \nabla \big[ \alpha f(x) \big] = \alpha \nabla f(x)[/tex]

Step-by-step explanation:

Step 1: Define

Identify.

[tex]\displaystyle f(x, y, z) = x^2 + y^2 + z^2[/tex]

[tex]\displaystyle P(3, 9, 8)[/tex]

Step 2: Find Gradient

[Function] Differentiate [Gradient]: [tex]\displaystyle \nabla f = \frac{\partial}{\partial x} \Big( x^2 + y^2 + z^2 \Big) \hat{\i} + \frac{\partial}{\partial y} \Big( x^2 + y^2 + z^2 \Big) \hat{\j} + \frac{\partial}{\partial z} \Big( x^2 + y^2 + z^2 \Big) \hat{\text{k}}[/tex][Gradient] Rewrite [Gradient Property - Addition/Subtraction]: [tex]\displaystyle \nabla f = \bigg[ \frac{\partial}{\partial x}(x^2) + \frac{\partial}{\partial x}(y^2) + \frac{\partial}{\partial x}(z^2) \bigg] \hat{\i} + \bigg[ \frac{\partial}{\partial y}(x^2) + \frac{\partial}{\partial y}(y^2) + \frac{\partial}{\partial y}(z^2) \bigg] \hat{\j} + \bigg[ \frac{\partial}{\partial z}(x^2) + \frac{\partial}{\partial z}(y^2) + \frac{\partial}{\partial z}(z^2) \bigg] \hat{\text{k}}[/tex][Gradient] Differentiate [Derivative Rule - Basic Power Rule]: [tex]\displaystyle \nabla f = 2x \hat{\i} + 2y \hat{\j} + 2z \hat{\text{k}}[/tex][Gradient] Substitute in point: [tex]\displaystyle \nabla f(3, 9, 8) = 2(3) \hat{\i} + 2(9) \hat{\j} + 2(8) \hat{\text{k}}[/tex][Gradient] Evaluate: [tex]\displaystyle \nabla f(3, 9, 8) = 6 \hat{\i} + 18 \hat{\j} + 16 \hat{\text{k}}[/tex]

∴ the gradient of the function at the given point is <6, 18, 16>.

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Topic: Multivariable Calculus

Unit: Directional Derivatives

Help Algebra Question

Answers

The solution is option D.

0     4
- 6     1
3    -4

Rember row times column.

=>
a11 = 4*0 + 0*(-3) = 0

a12 = 4*1 + 0*1 = 4 + 0 = 4

a21 = -1*0 + 2*(-3) = 0 - 6 = -6

a22 = -1*1 + 2*1 = -1 + 2 = 1

a31 = -3*0 + (-1)*(-3) = 0 + 3 = 3

a32 = -3*1 + (-1)*1 = -3 - 1 = -4

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