Answer:
Weight = 4900 N
Explanation:
Given:
Mass of the piano is, [tex]m=500\ kg[/tex]
Acceleration due to gravity is, [tex]g=9.8\ m/s^2[/tex]
Height to which the piano is raised is 8.0 m.
We are asked to determine the weight of the piano.
We know that, weight of a body is nothing but gravitational force acting on it by the center of Earth. It is equal to the product of mass and acceleration due to gravity.
Weight is independent of height til the height is very less than the radius of Earth. At very high altitudes which are comparable to the radius of Earth, the value of 'g' changes and hence the weight. But, here the height is very small and hence the value of 'g' equals 9.8 m/s² only.
Thus, weight of the piano is given as:
Weight = Mass [tex]\times[/tex] Acceleration due to gravity
Weight = [tex]mg[/tex]
Weight = [tex](500\ kg)(9.8\ m/s^2)=4900\ N[/tex]
Weight is a force so, its unit is same as that of force and hence it is measured in Newtons.
Therefore, the weight of the piano is 4900 N.
With each bounce off the floor, a tennis ball loses 23% of its mechanical energy due to friction. When the ball is released from a height of 2.5 m above the floor, what height will it reach after the third bounce?
110 mm
110 cm
11 cm
150 cm
Answer:
110 cm
Explanation:
Gradpoint
According to quantum physics, measuring velocity of a tiny particle with an electromagnet
A. Has no effect on the velocity of the particle.B. Affects the velocity of the particle.
Answer:
Option A.
Explanation:
In quantum physics there is a law to relate the position and the momentum of the particle, it says that if we know with precision where is a quantum particle, we can not know the momentum of this particle, in other words, the velocity of the particle. So, when we measure the velocity of the particle we find the correct value of the particle, but we can not determine with accuracy where is the particle. This law is known as the Heisenberg's uncertainty principle and, its expressed as follows:
[tex] \Delta x \Delta p \geq \frac{h}{4 \pi} [/tex]
where Δx: is the position's uncertainty, Δp: is the momentum's uncertainty and h: is the Planck constant.
Therefore, the correct answer is A: measuring the velocity of a tiny particle with an electromagnet has no effect on the velocity of the particle. It only affects the determination of the particle's position.
I hope it helps you!
A stone is thrown with a speed v0 and returns to earth, as the drawing shows. Ignore friction and air resistance, and consider the initial and final locations of the stone. Which one of the following correctly describes the change ΔPE in the gravitational potential energy and the change ΔKE in the kinetic energy of the stone as it moves from its initial to its final location?
A. ΔPE = 0 J and ΔKE = 0 J
B. ΔPE is positive and ΔKE is negative
C. ΔPE = 0 J and ΔKE is positive
D. ΔPE is negative and ΔKE is positive
E. ΔPE = 0 J and ΔKE is negative
Answer:
If the stone is thrown from the ground, the correct answer is A. If it is thrown from a height h, the correct answer is D.
Explanation:
Hi there!
I can´t see the drawing but let´s assume that initially, the stone is on the ground level. If that is the case, initially, the potential energy will be zero and when it returns to Earth it will also be zero. The potential energy depends on the height of the stone. If the final and initial height of the stone is zero, then the change in potential energy will also be zero:
ΔPE = final PE - initial PE
ΔPE = m · g · hf - m · g · hi (where hf and hi are the final and initial height respectively)
ΔPE = m · g (hf - hi)
ΔPE = m · g (0)
ΔPE = 0
Initially, the kinetic energy (KE) of the stone is the following:
KE = 1/2 · m · v0²
As the stone goes up, the kinetic energy is transformed into potential energy; but as the stone starts to fall, the acquired potential energy is transformed again into kinetic energy, so that the final and initial kinetic energy of the stone is the same.
Then:
ΔKE = final KE - initial KE = 0 (because final KE = initial KE).
Then, the correct answer is A.
Always ΔKE = -ΔPE due to the conservation of energy. Potential energy can´t be acquired by the stone if there is no loss of kinetic energy and vice-versa.
Let´s assume now that the stone is thrown from a height hi to the ground.
The final potential energy will be zero (becuase h = 0) but the initial PE will be:
PE = m · g · h1
Then:
ΔPE = final PE - initial PE = 0 - m · g · h1
Then ΔPE will be negative.
The initial kinetic energy will be:
KE = 1/2 · m · v0²
But the final kinetic energy will be equal to the initial kinetic energy plus the loss of potential energy (remember: if potential energy decreases, another type of energy has to increase, in this case, kinetic energy and vice-versa):
ΔKE = final KE - initial KE
ΔKE = 1/2 · m · v0² + m · g · h1 - 1/2 · m · v0²
ΔKE = m · g · h1
Then ΔKE will be positive and the correct answer would be D.
Beginning at the NW corner of the intersection of Pine & 675, thence north 950 feet, thence west 380 feet, thence south 950 feet, thence east 380 feet. Is this an acceptable metes and bounds description?
Answer:
this description is valid for mediadle displacement, bone is an acceptable description
Explanation:
The description of a person's position must be done with a position vector. These vectors must have magnitude, a given direction and a starting point.
In the description this has a starting point corner NO of pine and 675.
Each displacement occurs with respect to the previous one, indicating the magnitude of the displacement and its direction.
After analyzing this description is valid for mediadle displacement, bone is an acceptable description
A curve plotted as a function of frequency defining the sound pressure level required to give equal loudness is?
Answer:
equal loudness curve
Explanation:
The curves of equal loudness, first established by Munson and Fletcher in 1930 and subsequently recalculated by Robinson and Dadson, show the relationship that must exist between the frequencies and intensities (or sound pressure) of two sine sounds to be perceived equally loudly. , that is, with the same loudness.
The sinusoidal sounds contained along each curve have the same loudness. This frequency dependence would be mainly due to the transfer characteristics of the external and middle ear. It should also be noted that as the sound pressure level increases, the curves become flatter, that is, the frequency dependence is smaller as the sound pressure level increases.
The loudness level of any sound (complex) is determined by comparing its loudness with that of a sinusoidal sound.
A curve plotted as a function of frequency defining the sound pressure level required to give equal loudness is known as an equal-loudness curve. These curves use the phon unit to illustrate how different sound pressure levels are needed at various frequencies for a sound to be perceived as equally loud.
Explanation:The curve plotted as a function of frequency defining the sound pressure level required to give equal loudness is known as an equal-loudness curve. These curves are critical for understanding how the human ear perceives sound at different frequencies and intensity levels, using a unit called a phon to express loudness numerically. Phons and decibels are defined to be the same at 1000 Hz, which serves as a standardized point of reference. The equal-loudness curves show that at different frequencies, different sound pressure levels are required for a sound to be perceived as equally loud. This phenomenon underlines the non-linear nature of human hearing across the frequency spectrum.
Large numbers of people have compared the loudness of sounds at different frequencies and sound intensity levels to determine these curves. Each curve is labeled with its loudness in phons, and all sounds on a given curve are perceived as equally loud. This concept is vital for various applications, including the design of audio equipment, hearing aids, and soundproofing materials, to ensure sound is produced or mitigated in a manner consistent with human loudness perception.
Which of the following is defined as an area of the body surface that is innervated by a single spinal nerve?
A. Transverse process
B. Malar
C. Dermatome
D. Spinous process
Answer:
Dermatome. (Ans. C).
Explanation:
Dermatome is defined as the area of the human anatomy skin which is supplied by single spinal sensory nerve root. At the spinal cord these spinal sensory nerve enter the nerve root, and the branches of spinal sensory reach to the periphery of the body.
The sensory nerve which is present in the periphery of the body are the type of nerve which helps to transmit signals from sensation such as pain, temperature, etc. to the spinal cord from some specific area of the anatomy.
To increase the speed at which Google Analytics compiles reports, what action could be taken?
Answer:
Answer Choose “Faster response” in the sampling pull-down menu
Explanation:
At the top of the report, below the date range selector, select faster response,
This option uses a smaller sampling size to give you faster results. In order to get a better understanding lets define sampling, according to Google analytics website
In data analysis, sampling is the practice of analyzing a subset of all data in order to uncover the meaningful information in the larger data set.
For example, if you wanted to estimate the number of trees in a 100-acre area where the distribution of trees was fairly uniform, you could count the number of trees in 1 acre and multiply by 100, or count the trees in a half acre and multiply by 200 to get an accurate representation of the entire 100 acres.
To speed up Go_ogle Analytics reports, you can reduce the date range and complexity of the report, or increase server resources.
Explanation:To increase the speed at which Go_ogle Analytics compiles reports, several actions could be taken. First, one can reduce the amount of data that is being processed by adjusting the date range of the reports. By analyzing a smaller chunk of data, the report can be generated much faster.
Secondly, one can adjust the complexity of the report. The more complex the report, the more data needs to be processed, hence it will take longer. Reducing the complexity and only focusing on the key metrics can help speed up the report compilation.
Lastly, one can increase the capacity of their server resources. If a company has the means, it can invest in dedicated server resources for Go_ogle Analytics, allowing it to process reports faster.
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At a fabrication plant, a hot metal forging has a mass of 67.2 kg and a specific heat capacity of 438 J/(kg C°). To harden it, the forging is quenched by immersion in 786 kg of oil that has a temperature of 37.1 °C and a specific heat capacity of 2950 J/(kg C°). The final temperature of the oil and forging at thermal equilibrium is 58.3 °C.
Assuming that heat flows only between the forging and the oil, determine the initial temperature in degrees Celsius of the forging.
Answer:
Tm = 1,728.38 °C
Explanation:
mass of metal forging (Mm) = 67.2 kg
specific heat capacity of metal forging (Cm) = 438 J/kg°C
initial temperature of metal forging (Tm) = ?
final equilibrium temperature (Te) = 58.3 °C
mass of oil (Mo) = 786 kg
specific heat capacity of oil (Co) = 2950 J/kg°C
temperature of oil (To) = 37.1 °C
Mm × Cf × (Tm - Te) = Mo × Co × (Te - To)
Tm = [tex]\frac{Mo x Co x (Te - To) }{Mm x Cf}[/tex] + Te
Tm = [tex]\frac{786 x 2950 x (58.3 - 37.1) }{67.2 x 438}[/tex] + 58.3
Tm = 1,728.38 °C
A ball is fixed to the end of a string, which is attached to the ceiling at point P. As the drawing shows, the ball is projected downward at A with the launch speed v0. Traveling on a circular path, the ball comes to a halt at point B. What enables the ball to reach point B, which is above point A? Ignore friction and air resistance.
Answer:
The ball's initial kinetic energy
The ball comes to a stop at B. At this point its initial kinetic energy is converted into potential energy
Explanation:
A ball is fixed to the end of a string, which is attached to the ceiling at point P. As the drawing shows, the ball is projected downward at A with the launch speed v0. Traveling on a circular path, the ball comes to a halt at point B. What enables the ball to reach point B, which is above point A? Ignore friction and air resistance.
From conservation of energy which states that energy can neither be created nor be destroyed, but can be transformed from one form to another.
Ki+Ui=Kf+Uf
Ki=initial kinetic energy
Ui=initial potential energy
Kf=final kinetic energy
Uf=final potential energy
we know that [tex]\frac{1}{2} mu^{2} +mgha=\frac{1}{2} mv^{2} +mghb[/tex]
m=mass of the ball
ha=downward height a
hb=upward height b
u=initial velocity u
v=final velocity v, which is 0
g=acceleration due to gravity
v=0 at final velocity
1/2mu^2+mgha=0+1/2mv^2
ha=hb+Ki/mh
From the above equation, we can conclude that the ball's initial kinetic energy is responsible for making the ball reach point B.
Point B is higher than point A from the motion gained by the ball
A soccer ball is kicked from point Pi at an angle above a horizontal field. The ball follows an ideal path before landing on the field at point Pf . Which of the following statements is true when the ball is at point X?
A. The horizontal velocity vector points to the right & equals v cos θ.
B. The vertical velocity points up & equals v sin θ.
C. The acceleration vector points up.
D. The total velocity equals the initial velocity v.
Answer:
A. The horizontal velocity vector points to the right & equals v cos θ.
Explanation:
The motion describes a parabolic path, where the horizontal speed is constant and the horizontal velocity vector always points to the right and equals v*cos θ.
A solid cone is 10 cm high. where is its center of mass?
Answer:
The center of mass of a cone is located along a line. This line is perpendicular to the base and reaches the apex. The center of mass is a distance 3/4 of the height of the cone with respect to the apex.
Explanation:
The center of mass of a solid cone is located one-third of the way up from the base.
Explanation:The center of mass of a solid cone is located at one-third of its height from the base. In this case, the cone is 10 cm high, so the center of mass is located 10 cm * (1/3) = 3.33 cm from the base.
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Slow moving vehicles must display ___________ emblem at the rear to warn of their low speed.A. a red square B. a yellow triangular C. an orange triangular
Answer:
option C
Explanation:
The correct answer is option C
An orange triangular sign on the rear of the vehicle will show that the vehicle will move at a slow speed.
Warning Sign is an important method of conveying the message. Warning sign helps for the smooth movement of the traffic.
A car with an orange sign on the rear will inform the fellow driver that the vehicle is slow and they can overtake it.
The element lead (Pb) has a density 11.3 times that of water. Copper (Cu) has a density 7.9 times the density of water. A 5 kg mass of lead and a 5 kg mass of copper are both completely submerged in a bucket of water. Which mass has the LARGER buoyant force acting on it?
A) The buoyant force on the lead mass is larger.
B) The buoyant force on the copper mass is larger.
C) The buoyant force is the same on both masses.
Answer:
The answer is B
Explanation:
Density of the element lead (Pb) is:
[tex]d_{Pb} =11,3kg/dm^3[/tex]
Density of the element Copper (Cu) is:
[tex]d_{Cu} =7,9kg/dm^3[/tex]
First we need o find the volume of both materials:
[tex]V_{Pb}=5/11,3=440cm^3[/tex]
[tex]V_{Cu}=5/7,9=630cm^3[/tex]
And the buoyant forces on elements are:
[tex]P_{Pb}=440*1*9,81/1000=4,32N[/tex]
[tex]P_{Pb}=630*1*9,81/1000=6,18N[/tex]
A 2.0-g piece of Mg reacts with HNO3. Which conditions would produce the GREATEST reaction rate
0.5 M HNO3 at 20 C
0.5 M HNO3 at 40
1.0 M HNO3 at 20
1.0 M HNO3 at 40
Answer:
1.0 M HNO3 at 40°C
Explanation:
Rate of chemical reaction: This can be defined as the number of moles of reactant, converted or product formed per unit time.
Factors that affect rate of chemical reaction:
(a) Temperature: Generally, an increase in temperature increase the rate of chemical reaction by (1) increasing the number of particles with energy equal to or greater than the activation energy, (2) Increasing the average speed of all the reactant particles, due to greater kinetic energy, leading to higher frequency of collision.
(b) Concentration: An increase or decrease in the concentration of the reactant will result to a corresponding increase or decrease in the effective collision of the reactant and hence in the reaction rate.
other factors that affect the rate of chemical reaction are
(i) Nature of the reactant
(ii) Surface area of reactant
(iii) presence of light
(iv) presence of catalyst.
From the question above,
The condition with the highest temperature and concentration will produce the GREATEST reaction rate.
And that is 1.0 M HNO3 at 40 °C
Object A has a position as a function of time given by rA(t) = (3.00 m/s)t i ^ + (1.00 m/s2)t2j^. Object B has a position as a function of time given byrB(t) = (4.00 m/s)ti^ + (-1.00 m/s2)t2j^. All quantities are SI units. What is the distance between object A and object B at time t = 3.00 s?A) 3.46 m B) 15.0 m C) 18.3 m D) 34.6 m E) 29.8 m
Explanation:
Given that
[tex]rA(t)=(3.00 m/s)t\hat{i}+ (1.00 m/s^2)t^2\hat{j}\texttt{ and }rB(t)=(4.00 m/s)t\hat{i}+ (-1.00 m/s^2)t^2\hat{j}[/tex]
We need to find distance when t = 3 s
Substituting t = 3 s
[tex]rA(t)=(3.00 m/s)\times 3\hat{i}+ (1.00 m/s^2)\times 3^2\hat{j}=9\hat{i}+9\hat{j}\\\\rB(t)=(4.00 m/s)\times 3\hat{i}+ (-1.00 m/s^2)\times 3^2\hat{j}=12\hat{i}-9\hat{j}[/tex]
[tex]\texttt{Displacement = }12\hat{i}-9\hat{j}-(9\hat{i}+9\hat{j})=3\hat{i}-18\hat{j}[/tex]
[tex]\texttt{Magnitude = }\sqrt{3^2+(-18)^2}=18.3m[/tex]
Option C is the correct answer.
The distance between object A and object B is approximately 18.248 meters. (Choice C)
How to calculate the distance between two objects
In this question we must apply the concepts of vector difference, dot product and norm to determine the distance between objects A and B, in meters:
[tex]r_{B/A} = \sqrt{(\vec r_{B}-\vec r_{A})\,\bullet\,(\vec r_{B}-\vec r_{A})}[/tex] (1)
Where:
[tex]\vec r_{A}[/tex] - Vector distance of object A, in meters.[tex]\vec r_{B}[/tex] - Vector distance of object B, in meters. [tex]r_{B/A}[/tex] - Distance of B relative to A, in meters.If we know that [tex]\vec r_{A} = (3\cdot t, t^{2})\,\left[m\right][/tex], [tex]\vec r_{B} = (4\cdot t,-t^{2})\,\left[m\right][/tex] and [tex]t = 3\,s[/tex], then the distance of B relative to A is:
[tex]r_{B/A}=\sqrt{t^{2}+4\cdot t^{4}}[/tex]
[tex]r_{B/A} = t\cdot \sqrt{1+4\cdot t^{2}}[/tex]
[tex]r_{B/A} = 3\cdot \sqrt{1+4\cdot 3^{2}}[/tex]
[tex]r_{B/A} \approx 18.248\,m[/tex]
The distance between object A and object B is approximately 18.248 meters. (Choice C) [tex]\blacksquare[/tex]
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The engine in an imaginary sports car can provide constant power to the wheels over a range of speeds from 0 to 70 miles per hour (mph). At full power, the car can accelerate from zero to 32.0mph in time 1.10s .A)At full power, how long would it take for the car to accelerate from 0 to 64.0mph ? Neglect friction and air resistance. =4.40sPart BA more realistic car would cause the wheels to spin in a manner that would result in the ground pushing it forward with a constant force (in contrast to the constant power in Part A). If such a sports car went from zero to 32.0mph in time 1.10s , how long would it take to go from zero to 64.0mph ?am not sure how to do part B
Answer:
a) 4.40 s
b) 2.20 s
Explanation:
Given parameters are:
At constant power ,
initial speed of the car, [tex]v_0=0[/tex]
final speed of the car, [tex]v=32[/tex] mph
At full power,
initial speed of the car, [tex]v_0=0[/tex]
final speed of the car, [tex]v=64[/tex] mph
a)
At constant power, [tex]KE = \frac{1}{2} mv^2[/tex]
At full power, [tex]KE = \frac{1}{2} m(2v)^2[/tex]
So [tex]KE_f = 4KE_i[/tex]
So, time to reach 64 mph speed is 4 times more than the initial time
[tex]t = 4*1.10 =4.40[/tex] s
b)
[tex]v=v_0+at\\a=\frac{v-v_0}{t}=\frac{32-0}{1.1/3600}=104727.27[/tex] [tex]miles/hours^2[/tex]
For final 64 mph speed,
[tex]v=v_0+at\\t=\frac{v-v_0}{a}=\frac{64-0}{104727.27} = 6.111*10^{-4}[/tex] [tex]hours[/tex] = [tex]6.111*10^{-4}*3600=2.20[/tex] s
You are in an airplane going down a runway currently going 24 m/s and accelerating at 8m/s for 800 meters until take off. How long does it take the plane to go those 800 meters?
Answer:
Time taken to cover the distance 11.45 s.
Explanation:
The given parameters:
Initial Velocity(u)=24 m/s
Acceleration (a)=8 [tex]m/s^{2}[/tex]
Distance or Displacement(s)=800 m
Displacement or Distance is equal in the above because it travels in a straight line.
We have to apply Second Equation of Motion,
s=ut+[tex]\frac{1}{2} at^{2}[/tex]
800=24t + 4[tex]t^{2}[/tex]
200=6t + [tex]t^{2}[/tex]
[tex]t^{2}[/tex] + 6t - 200=0
Solving, the quadratic equation to find out the roots, we get that the possible values of t will be 11.45 s and a negative value.
The negative value will be neglected as time cannot be negative.
Hence, the time taken is 11.45 s.
boy pulls a 5.0-kg sled with a rope that makes a 60.0° angle with respect to the horizontal surface of a frozen pond. The boy pulls on the rope with a force of 10.0 N; and the sled moves with constant velocity. What is the coefficient of friction between the and the ice?
(a) 0.09
(b) 0.12
(c) 0.18
(d) 0.06
(e) 0.24
Answer:
0.1
Explanation:
mass, m = 5 kg
θ = 60°
Force, F = 10 N
velocity is constant , it means the net force is zero.
So, the component of force along the surface is equal to the friction force
FCosθ = friction force
10 x cos 60 = μ x m x g
where, μ is the coefficient of friction
5 = μ x 5 x 9.8
μ = 0.1
Thus, the coefficient of friction is 0.1
A certain radioactive isotope placed near a Geiger counter registers 120 counts per minute. If the half-life of the isotope is one day, what will the count rate be at the end of four days?
Answer:
The count rate at the end of four days will be 7.5 counts per minute.
Explanation:
First it is important to know that half-life is the time to a piece of radioactive material to decay 50%. So if we know we start with 120 counts per minute and we already know the half-life of the isotope is 1 hour we expect that past 1 hour the material decays 50% (it's halved) so we will count 60 counts per minute, now if we wait another hour 60 counts will decay in to 30 counts per minute and so on. That should be translate to a math equation as:
final counts = initial counts * [tex](\frac{1}{2})^{\#half\,life\,periods}[/tex]
After 4 days we have 4 half-life periods passed so:
final counts= 120 counts per minute * [tex](\frac{1}{2})^{4}[/tex]
final material = 7.5 counts per minute
Examine the five words and/or phrases and determine the relationship among the majority of words/phrases. Choose the one option that does not fit the pattern. A. abyssal clay B. calcareous ooze C. coarse lithogenic sediment D. manganese nodule E. siliceous ooze
Answer:
The Correct Option is C (coarse lithogenic sediment)
Explanation:
This is because all other options are found on sea floors, except for coarse lithogenic sediments that are as a result of erosion on land. Both calcareous and siliceous ooze are common sea sediments. Abyssal clay and manganese nodule are red clay and rock concretion respectively found in the bottom of the sea.
Calculate the magnitude of the flux of a constant electric field of 5.00 N/C in the z-direction through a rectangle with area 4.00 m2 in the xy-plane. (a) 0 (b) 10.0 N m2/C (c) 20.0 N m2/C (d) more information is needed
Answer:
The magnitude of the flux is [tex]2.00 N m^2/C[/tex]
Explanation:
The electric flux through a planar area is defined as the product of electric field and the component of the area perpendicular to the field.
Electric flux = Electric field * Area * (angle between the planar area and the electric flux)
The equation is
[tex]\phi = E A cos(\theta)[/tex]
Where:
[tex]\phi[/tex]is the Electric Flux
A is the Area
E is the Electric field
[tex]\theta[/tex] is angle between a perpendicular vector to the area and the electric field
Now substituting the values,
[tex]\phi = 5.00 \times 4.00 \times cos(0)[/tex]
[tex]\phi = 5.00 \times 4.00 \times 1[/tex]
[tex]\phi = 2.00 N m^2/C[/tex]
The flux of a constant electric field in the z-direction through a rectangle in the xy-plane is zero, because the angle between the direction of the electric field and the direction of the normal to the area is 90 degrees, which makes the dot product zero.
Explanation:To calculate the magnitude of the flux of an electric field, we use the equation: Φ = E . A where Φ is the electric flux, E is the electric field, and A is the area of the surface. The dot (.) represents a dot product, which means we consider the angle between the field and the area. In this problem, the electric field (E) is given as 5.00 N/C and the area of the rectangle (A) is 4.00 m². Also, because the electric field is in the z-direction (up and down), and the rectangle is in the xy-plane (flat), the angle between the field and the area is 90 degrees.
However, the dot product for angles of 90 degrees is zero because cos(90°) = 0. So, regardless of the magnitudes of the electric field and the area, the flux is zero because Φ = E . A = EAcos(90°) = 0. Therefore, the correct answer is (a) 0.
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At an uncontrolled intersection, when must the car on the right yield to the car on the left?
Answer: the car on the right should yield to the car that arrived first. That is When the car on the left arrives first
Explanation:
It must be noted that the law did not grant the 'right-of-way'. The law only says when the right of way must be yielded. The law does state who must yield the right of way neither does the law give right of way to anyone.
Yielding the right of way to another vehicle simply means that you are letting them go before you in a traffic situation.
Therefore, When two vehicles approaches an intersection without no traffic signs or signals, (that is, an uncontrolled intersection) the two vehicles must slow down. Always Yield to vehicles already in the uncontrolled intersection and drivers who arrive at the uncontrolled intersection before you.
The vehicle on the left should always yield to the right of the way to the vehicle on the right. The driver with ''right-of-way'' must pay attention to avoid a collision.
If a solution surrounding a cell is hypotonic relative to the inside of the cell, in which direction will water move?
Answer:
If the cell is placed in a surrounding solution which is hypotonic in nature.
Then the water from outside of the cell to the inside of the cell. The water will keep on moving from the outside of the cell to the inside of the cell.
The flow of water will take place until the outside environment of the cell and the inside of the cell becomes equal.
The flow of water will take place from the outside of the cell to the inside of the cell.
Answer:
The direction of motion of water molecules will be into the cell.
Explanation:
A hypotonic solution is one which has the less concentration of solute in the solvent as compared to the solution on the other side of the semi-permeable membrane. This creates an osmotic pressure gradient across the semi-permeable membrane which is responsible for the flow of water molecules across the membrane until the concentration becomes equal for both the solutions.(A semi-permeable membrane is a sheet or a plane barrier which does not allows the molecules over certain size to pass through it. Here the membrane does not allows the molecules larger in size than that of water molecules to pass through it.)Two train whistles have identical frequencies of 1.64 102 Hz. When one train is at rest in the station and the other is moving nearby, a commuter standing on the station platform hears beats with a frequency of 4.00 beats/s when the whistles operate together. What are the two possible speeds that the moving train can have?
Answer:
Vs = 6.73 m/s or Vs = 16.3 m/s
Explanation:
frequency of the trains whistle (f) = 1.64 x 10^{2} Hz = 164 Hz
frequency of beats heard = 4 beats/s = 4 Hz
velocity of the stationary train (Vr) = 0
velocity of sound in air (V) = 343 m/s
velocity of the moving train (Vs) = ?
we can get the velocity of the moving train from the formula below
Fn = f x [tex]\frac{V + Vr}{V - Vs}[/tex] ...equation 1
where Fn = net frequency
case one - assuming the train is approaching the station Fn = 164 + 4 = 168 Hzsubstituting the known values into equation 1
168 = 164 x [tex]\frac{343 + 0}{343 - Vs}[/tex]
1.02 = [tex]\frac{343 + 0}{343 - Vs}[/tex]
Vs = [tex]343 - \frac{343 + 0}{1.02}[/tex]
Vs = 6.73 m/s
case two - assuming the train is leaving the station Fn = 164 - 4 = 160 Hzsubstituting the known values into equation 1
168 = 160 x [tex]\frac{343 + 0}{343 - Vs}[/tex]
1.05 = [tex]\frac{343 + 0}{343 - Vs}[/tex]
Vs = [tex]343 - \frac{343 + 0}{1.05}[/tex]
Vs = 16.3 m/s
You have an empty 20 oz. soda bottle and you blow air over the opening to excite a fundamental standing wave. Now, you slice off the bottom of the bottle (it’s plastic) without changing its length very much. You blow over the opening and excite a fundamental standing wave in the bottle with its bottom end open. The frequency of the standing wave in the second case:______________________________.
Answer:
The frequency of the standing wave in the second case is higher than that in the first case
Explanation:
The frequency and wavelength of a wave are related.
The moment you sliced the bottle, you've reduced the wavelength of the bottle.
When wavelength decreases, frequency increases and vice versa.
So, When frequency increases in the second case, more wave crests pass a fixed point each second. That means the wavelength shortens. So, as frequency increases, wavelength decreases. The opposite is also true—as frequency decreases, wavelength increases.
Evidence that the cosmic background radiation really is the remnant of a Big Bang comes from predicting characteristics of remnant radiation from the Big Bang and comparing these predictions with observations. Four of the five statements below are real. Which one is fictitious?
Answer:
B) The cosmic background radiation is expected to contain spectral lines of hydrogen and helium, and it does.
Explanation:
An ideal gas is enclosed in a cylinder with a movable piston on top of it. The piston has a mass of 8,000 g and an area of 5.00 cm2 and is free to slide up and down, keeping the pressure of the gas constant.
a. How much work is done on the gas as the temperature of 0.280 mol of the gas is raised from 15.0 degrees C to 27.0 degrees C?
b. What does the sign of your answer to part (a) indicate?
A. The surroundings do positive work on the gas.
B. The gas does positive work on its surroundings.
C. There is no work done by the gas of the surroundings.
Answer:
Explanation:
Given
mass of gas [tex]m=8000 gm=8 kg[/tex]
Area of Piston [tex]A=5 cm^2[/tex]
[tex]T_1=15^{\circ}C[/tex]
[tex]T_2=27^{\circ}C[/tex]
no of moles [tex]n=0.28[/tex]
Work done on the gas is given by
[tex]W=-P\Delta V[/tex]
[tex]P\Delta V[/tex] can also be written as [tex]nR\Delta T[/tex]
as PV=nRT
[tex]W=-nR\Delta T[/tex]
[tex]W=-0.28\times 8.314\times (27-15)[/tex]
[tex]W=-27.93 J[/tex]
negative sign indicates that work is done on the system i.e. surrounding done a positive work on the gas
Arnold Strongman and Suzie Small each pull very hard on opposite ends of a massless rope in a tug-of-war. The greater force on the rope is exerted by
A. Arnold, of course
B. Suzie, surprisingly
C. both the same, interestingly enough
Answer:
The greater force on the rope is exerted by:
C. both the same, interestingly enough
Explanation:
The option c is correct as the rope is mass-less. Both Arnold and Suzie are pulling hard on opposite ends. But the tension of the rope is same at every point so that means both are exerting the same force on both ends of rope.The analogy for the given situation is that as when a vehicle moves on a road, the force exerted by the wheel of vehicle on the road is equal to the force exerted by the road on the wheel of vehicle.The options A and B can be possible if anyone of them exert more power on the ground through feet in this way, one can exert more force and can win.High energy environments are most likely to contain which one of the following?
a.large particles such as gravel
b.silt-sized particles
c.manganese nodules
d.cosmogenous sediments
e.clay-sized particles
Answer:
a.large particles such as gravel
Explanation:
A high energy environment is composed of the Aquas sedimentary environment and features the high energy of turbulent waves and currents in motion and contains the large parts of gravel that is an aggregation of rocks fragments and are formed as result of the weathering and erosion of rocks.High energy environments are typically associated with larger particles such as gravel due to the ability of these environments to move larger matter. Smaller particles are generally found in lower energy environments.
Explanation:High energy environments, such as fast-flowing rivers or coastal areas with strong waves, are most capable of moving larger particles. So, among these options, the environments with high energy are most likely to contain large particles such as gravel (a). The other particles listed (silt, manganese nodules, cosmogenous sediments, clay) require less energy to be moved, so they are likely to be found in lower energy environments.
Learn more about High Energy Environments here:https://brainly.com/question/34101951
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The following is a limitation of a bar chart schedule. a. Scheduling information is presented at a summary level b. activity interrelations are not considered c. ease of preparation d. ease of interpretation e. None of the above
Answer:
b. activity interrelations are not considered
Explanation:
A bar chart schedule or Gantt chart is used to visualize task that scheduled over time.