Solve for x (round to the nearest degree)

Answer:

  (3, 1)

Step-by-step explanation:

The orthocenter is the point where the altitudes meet. Since all three altitudes meet there, it is only necessary to look at two of them. A graph helps immensely.

In the attached graph, we notice that segment HJ is horizontal, so the x-coordinate of the orthocenter will be that of point I (x=3).

The segment IJ has a rise of 3 for a run of 1, so its perpendicular through point H will have a rise of 1 for a run of -3. That gets you to point (3, 1) from point H, so (3, 1) is the orthocenter.

Answer:

The domain is the set of all first elements of ordered pairs (x-coordinates). The range is the set of all second elements of ordered pairs (y-coordinates). Only the elements "used" by the relation or function constitute the range.

Step-by-step explanation:

The perimeter of a polygon is found by adding up the lengths of all its sides. The given polygon has a perimeter of 600,000 km. A side labeled 'mfi' would be 300,000 km.

To find the perimeter of a polygon, you add up the lengths of all its sides. In this case, the given sides of the polygon are 200,000 km, 100,000 km, and 300,000 km. So adding these together gives you a perimeter of 600,000 km for this polygon.

If you're asked to find the length of a missing side (e.g., the side labeled as 'mfi'), you can subtract the lengths of the known sides from the total perimeter. So, 600,000 km (total perimeter) - 100,000 km - 200,000 km = 300,000 km. Therefore, the length of 'mfi' is 300,000 km.

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The perimeter of the polygon shown is approximately 84.91 centimeters.

According to the given image

∠B = ∠D and AB = AD.

To find the perimeter,  break the polygon into smaller shapes and find the perimeters of those shapes.

Now, the Perimeter of triangle ABD is calculated in the following way:

AB = AD (given) = 6.5 cm

We can use the Pythagorean theorem on triangle ABD to find BD:

[tex]BD^2 = AB^2 - (\frac{1}{2} \times AD)^2\\BD^2 = 6.5^2 - (\frac{1}{2} \times 6.5)^2\\BD^2 = 25.5625\\BD \approx 5.05 cm[/tex]

So, the Perimeter of triangle ABD is

= AB + AD + BD  

[tex]\approx 6.5 cm + 6.5 cm + 5.05 cm \\ \approx 18.05 cm[/tex]

Again, the Perimeter of triangle ABC is

AC = BC + AB = 8.5 cm + 6.5 cm = 15 cm

As ∠ABC is a right angle and AC is the hypotenuse, use the Pythagorean theorem to find AB:

[tex]AB^2 + BC^2 = AC^2\\AB^2 + 8.5^2 = 15^2\\AB^2 = 81\\AB = 9 cm[/tex]

Perimeter of triangle ABC

= AB + BC + AC = 9 cm + 8.5 cm + 15 cm = 32.5 cm

Perimeter of triangle ADC:

Similar to triangle ABC,  find AD using the Pythagorean theorem:

[tex]AD^2 + DC^2 = AC^2\\AD^2 + 7.5^2 = 15^2\\AD^2 = 135\\AD = 3\sqrt{5} cm \approx 11.86 cm[/tex]

Perimeter of triangle ADC

= AD + DC + AC = 11.86 cm + 7.5 cm + 15 cm = 34.36 cm

Finally, to find the perimeter of the entire polygon, add the perimeters of the three triangles:

Perimeter of polygon = Perimeter of triangle ABD + Perimeter of triangle ABC + Perimeter of triangle ADC

Perimeter of polygon is

[tex]\approx 18.05 cm + 32.5 cm + 34.36 cm \approx 84.91 cm[/tex]

Therefore, the perimeter of the polygon is approximately 84.91 centimeters.

Answer:the answer is 40

Step-by-step explanation:

Because you do 5 times x

Answer:-9

Step-by-step explanation:5x+3-48 you do 3-48 you get -45 then you divide 5x by -45 and you get the final answer of -9.

Answer:

Step-by-step explanation:

i don't know I am a forth grader

Answer:

The straight line distance between the school and the candy store is 5.

Step-by-step explanation:

Use Pythagorean theorem

a²+b²=c²

3²+4²=c²

9+16=c²

25=c²

5=c

The straight line distance between the school and the candy store will be 5 miles.

It is a type of triangle in which one angle is 90 degrees and it follows the Pythagoras theorem and we can use the trigonometry function. The Pythagoras is the sum of the square of two sides is equal to the square of the longest side.

After school, Isaac skateboards directly from school to an ice cream parlor and then from the ice cream parlor to a candy store.

The ice cream parlor is 3 miles south of the school and the candy store is 4 miles east of the ice cream parlor.

Then the straight line distance between the school and the candy store will be

[tex]\rightarrow \sqrt{4^2 + 3^2}\\\\\rightarrow \sqrt{16 + 9}\\\\\rightarrow \sqrt{25}\\\\\rightarrow 5[/tex]

More about the right-angle triangle link is given below.

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Answer:

86

Step-by-step explanation:

Area = Square - Circle

Area of Square = 10² = 100 m²

Area of Circle = π(5²) = 25π m²

Area of Shaded Region = 100 - 25π = 21.5 m² approx.

answer: second choice

Answer:

The final value of  [tex]b=\frac{29}{11}[/tex]  .

Step-by-step explanation:

Given:

[tex]2b + 8 - 5b + 3 = -13 + 8b - 5[/tex]

We have to find the value of [tex]b.[/tex]

[tex]2b + 8 - 5b + 3 = -13 + 8b - 5[/tex]

Steps to be followed:

Subtract 8b both side.

[tex]2b + 8 - 5b + 3-8b = -13 + 8b - 5-8b[/tex]

[tex]2b - 5b -8b+ 3 +8= -13 - 5[/tex]

[tex]2b - 5b -8b+ 3 +8= -13 - 5[/tex]

[tex]-11b+11=-18[/tex]

[tex]-11b+11=-18[/tex]

[tex]-11b+11-11=-18-11[/tex]

[tex]-11b=-29[/tex]

[tex]-11b=-29[/tex]

[tex]b=\frac{-29}{-11} =\frac{29}{11}[/tex]

So the final value of b is 29/11.

Answer:

$747.50

Step-by-step explanation:

650×15/100=$97.50 which is then added to 650 Becoz his pay is 15% rising=747.50

Step-by-step explanation:

[tex]\displaystyle \boxed{y = -cos\:(2x - \frac{\pi}{2}) + 1} \\ \\ y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 1 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{\frac{\pi}{4}} \hookrightarrow \frac{\frac{\pi}{2}}{2} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\pi} \hookrightarrow \frac{2}{2}\pi \\ Amplitude \hookrightarrow 1[/tex]

OR

[tex]\displaystyle y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 1 \\ Horisontal\:[Phase]\:Shift \hookrightarrow 0 \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\pi} \hookrightarrow \frac{2}{2}\pi \\ Amplitude \hookrightarrow 1[/tex]

You will need the above information to help you interpret the graph. First off, keep in mind that although this looks EXACTLY like the sine graph, if you plan on writing your equation as a function of cosine, then there WILL be a horisontal shift, meaning that a C-term will be involved. As you can see, the centre photograph displays the trigonometric graph of [tex]\displaystyle y = -cos\:2x + 1,[/tex]in which you need to replase "sine" with "cosine", then figure out the appropriate C-term that will make the graph horisontally shift and map onto the sine graph [photograph on the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the cosine graph [centre photograph] is shifted [tex]\displaystyle \frac{\pi}{4}\:unit[/tex]to the left, which means that in order to match the sine graph [photograph on the left], we need to shift the graph FORWARD [tex]\displaystyle \frac{\pi}{4}\:unit,[/tex]which means the C-term will be positive, and by perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{\frac{\pi}{4}} = \frac{\frac{\pi}{2}}{2}.[/tex]So, the cosine graph of the sine graph, accourding to the horisontal shift, is [tex]\displaystyle y = -cos\:(2x - \frac{\pi}{2}) + 1.[/tex]Now, with all that being said, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph hits [tex]\displaystyle [-\pi, 1],[/tex]from there to [tex]\displaystyle [-2\pi, 1],[/tex]they are obviously [tex]\displaystyle \pi\:units[/tex]apart, telling you that the period of the graph is [tex]\displaystyle \pi.[/tex]Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = 1,[/tex]in which each crest is extended one unit beyond the midline, hence, your amplitude. Now, there is one more piese of information you should know -- the sine graph in the photograph farthest to the right is the OPPOCITE of the sine graph in the photograph farthest to the left, and the reason for this is because of the negative inserted in front of the amplitude value. Whenever you insert a negative in front of the amplitude value of any trigonometric equation, the whole graph reflects over the midline. Keep this in mind moving forward. Now, with all that being said, no matter how far the graph shifts vertically, the midline will ALWAYS follow.

I am delighted to assist you at any time.

The equations that can be used to the value of x are 1) x+90+(x-10)=180 and 2) x+90+(2x+40)=180.

Step-by-step explanation:

Two properties can be used to find the value of the x.

1) Sum of Interior angles of a triangle is 180°.

⇒x+90°+(x-10)°=180.

2x+80°=180°.

2x=180°-80°.

2x=100°.

x=50°.

⇒(x-10)°=40°.

2) The Angle of the straight line is 180°.

From the given diagram, BC is a straight line ray with C as intersecting point. this will result in two angles. (refer the diagram).

The sum of those two angles will be 180°.

⇒ (x-10)°+ (2x+40)°=180°.

(3x+30)°=180°.

3x=150°.

x=50°.

∴(x-10)°=40° and (2x+40)° = 140°.

∴The equations that can be used to the value of x are x+90+(x-10)=180 and x+90+(2x+40)=180.

The slope-intercept form of the equation of the line with a slope of -2/5 that passes through (15, -9/2) is y = -2/5x + 3/2.

To write the slope-intercept form of the equation of a line, we use the formula y = mx + b, where m represents the slope and b represents the y-intercept. In this case, the slope is -2/5. To find the y-intercept, we substitute the coordinates of the point (15, -9/2) into the equation. Thus, we have:

y = -2/5x + b

-9/2 = -2/5(15) + b

-9/2 = -6 + b

b = -9/2 + 6 = 3/2

Therefore, the equation of the line with a slope of -2/5 that passes through (15, -9/2) is y = -2/5x + 3/2.

Final answer:

The equation of the line with a slope of -2/5 that passes through (15, -9/2) in slope-intercept form is y = (-2/5)x + 3.

Explanation:

The student is asking for the slope-intercept form of an equation of a line with a given slope and a point through which it passes. The slope-intercept form is given by y = mx + b, where m represents the slope and b represents the y-intercept. Given that the slope (m) is -2/5 and the line passes through the point (15, -9/2), we can substitute the slope and the point's coordinates into the slope-intercept formula to find b. Doing so, we get -9/2 = (-2/5)(15) + b. Solving for b, we find that the intercept is 3. Finally, the equation of the line in slope-intercept form is y = (-2/5)x + 3.

Answer:

the answer is 1,208.74

Answer:

27 is the right answer

Step-by-step explanation:

10+17=27 :)

Answer:

114, 156

Step-by-step explanation:

Answer: 114,156

Step-by-step explanation:

To add 84,396+29,760 you must add each row.

6+0 = 6

9+6 = 15 (Carry up the one)

3+7 = 10 + 1 = 11 (Carry up the one)

4+9 = 13 + 1 = 14 (Carry up the one)

8+2 = 10 + 1 = 11

So the answer will be 114,156

Answer:It is greater than 10 because as you add both distances from the image its greater than 10 by a bit, looking at  the angle it gives you a bigger perspective in how far the cue ball is from the pocket

Its basically 8+6 which equals 14 but adding the way the angle is going the distance is shorter than 14 but greater than 10

Answer:

10 inches

Explanation:

correct on edge

ar(ΔABO) = ar(ΔCDO)

Explanation:

The image attached below.

Given ABCD is a trapezoid with legs AB and CD.

AB and CD are non-parallel sides between the parallels AD and BC.

In ΔABD and ΔACD,

We know that, triangles lie between the same base and same parallels are equal in area.

⇒ AD is the common base for ΔABD and ΔACD and they are lie between the same parallels AD and BC.

Hence, ar(ΔABD) = ar(ΔACD) – – – – (1)

Now consider ΔABO and ΔCDO,

Subtract ar(ΔAOD) on both sides of (1), we get

ar(ΔABD) – ar(ΔAOD) = ar(ΔACD) – ar(ΔAOD)

⇒ar(ΔABO) = ar(ΔCDO)

Hence, ar(ΔABO) = ar(ΔCDO).

Answer:

2x² − 5y² − xy

Step-by-step explanation:

 3x²-  4y²  + 5xy + 20

−

 x²  +   y²  + 6xy + 20

________________

2x² − 5y² − xy    + 0

[tex]\bf \textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ V=457.17\\ h = 15 \end{cases}\implies 457.17=\cfrac{\pi r^2(15)}{3}\implies 457.17=5\pi r^2 \\\\\\ \cfrac{457.17}{5\pi }=r^2\implies \sqrt{\cfrac{457.17}{5\pi }}=r\implies 5.39 \approx r~\hfill \boxed{\stackrel{diameter = 2r}{2(5.39) = 10.78}}[/tex]

-18 < 5x - 3        Isolate/get x by itself, first add 3 to both sides of the equation

-18 + 3 < 5x - 3 + 3

-15 < 5x      Divide 5 on both sides

-3 < x         Your answer is A

You flip the sign [</>] if you multiply or divide a negative number to both sides of the equation.

a^2 + b^2 = c^2

65^2 + 34^2 = c^2

4225 + 1156 = c^2

5381 = c^2

c ≈ 73.3552997404

Hope this helps! ;)

Answer:

-4

Step-by-step explanation:

y-3=-4(x-5)

y=-4x+20+3

y=-4x+23

y=mx+b where m=slope and b=y-intercept

Answer:

John scored 20 goals he attempted 28.

Step-by-step explanation:

Given:

John scored 5:7 of the goals he attempted at the soccer game.

During three games, if John scored 20 goals.

Now, to find the number of attempts.

Let the number of attempts be [tex]x.[/tex]

The number of goals = 20.

As, given John scored 5:7 of the goals he attempted at the soccer game.

So, 5 is equivalent to 7.

Thus, 20 is equivalent to [tex]x.[/tex]

Now, to solve by using cross multiplication method:

[tex]\frac{5}{7} =\frac{20}{x}[/tex]

By cross multiplying we get:

[tex]5x=140[/tex]

Dividing both sides by 5 we get:

[tex]x=28.[/tex]

Therefore, he attempt 28.

9m = 6.48

Divide both sides by 9:

m = 0.72

19m = 13.68

Divide both sides by 19:

m = 0.72

So a one minute call costs 72 cents. We can now set up an equation like this:

c = 0.72m

Answer:

ju mmmmmmjjum,,,,i,,,,, enjoy

Step-by-step explanation:

Answer:

its option b: (-2,-1)

Step by step:

y=2x

-2=2(-1)

-2=-2

Infinitely many solutions

Therefore the cost of a bag of chips is $0.75

therefore the cost of a cheeseburger is $3.

Step-by-step explanation:

i) let the cost of a cheesburger be x.

ii) let the cost of a bag of chips be y

iii) therefore it is given that x + y = 3.75

iv) it is also given that 2x + 3y = 8.25

v) multiplying the equation in iii) by 2 we get 2x + 2y = 7.50

vi) subtracting the equation in v) from the equation in iv) we get y = $0.75

vii) Therefore the cost of a bag of chips is $0.75

viii) Substituting the value of y found in vii) into iii) we get x = 3.

ix) therefore the cost of a cheeseburger is $3.

Answer:

see the explanation

Step-by-step explanation:

Let

x ----> number of adult tickets

y ----> number of children tickets

we know that

Jane sold 100 tickets for her school auction

so

[tex]x+y=100[/tex] ----> equation A

Jane collected a total of $944

[tex]12x+8y=944[/tex] ----> equation B

Solve the system by graphing

Remember that the solution is the intersection point both graphs

using a graphing tool

The solution is the point (36,64)

see the attached figure

therefore

The number of adult tickets sold was 36 and the number of children tickets sold was 64

Answer:

e=-2

Step-by-step explanation:

9e-7=7e-11

9e-7e-7=-11

2e-7=-11

2e=-11+7

2e=-4

e=-4/2

e=-2

Answer:

e=2

Step-by-step explanation: