smog is a homogeneous mixture heterogeneous mixture​

The answer is C) Effluent

Bending your knees when you land from a jump increases the impact time, reducing the average force on your body and preventing injuries such as bone fractures.

When you jump from an elevated position and bend your knees upon reaching the ground, you increase the time of impact, which decreases the average force your body experiences compared to landing stiff-legged. This is due to the impulse-momentum theorem, which states that the change in momentum of an object is equal to the impulse applied to it. The impulse is the product of the average force and the time over which that force acts. By bending the knees, the stopping distance is increased, which spreads the force over a longer time period and reduces the strain on the body, particularly the joints and bones. This is crucial because bones in a body can fracture if the force on them is too great. An example of this concept in action is with kangaroos, where the shock of hopping is cushioned by the bending of their hind legs.

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1. 1.59 s

The period of a pendulum is given by:

[tex]T=2\pi \sqrt{\frac{L}{g}}[/tex]

where L is the length of the pendulum and g the gravitational acceleration.

In this problem,

L = 0.625 m

g = 9.81 m/s^2

Substituting into the equation, we find

[tex]T=2\pi \sqrt{\frac{(0.625 m)}{9.81 m/s^2}}=1.59 s[/tex]

2. 54,340 oscillations

The total number of seconds in a day is given by:

[tex]t=24 h \cdot 60 min/h \cdot 60 s/min =86,400 s[/tex]

So in order to find the number of oscillations of the pendulum in one day, we just need to divide the total number of seconds per day by the period of one oscillation:

[tex]N=\frac{t}{T}=\frac{86,400 s}{1.59 s}=54,340[/tex]

3. 0.842 m

We want to increase the period of the pendulum by 16%, so the new period must be

[tex]T'=T+0.16T=1.16 T = 1.16 (1.59 s)=1.84 s[/tex]

Now we can re-arrange the equation for the period of the pendulum, using T=1.84 s, to find the new length of the pendulum that is required to produce this value of the period:

[tex]L=g(\frac{T}{2\pi})^2=(9.81 m/s^2)(\frac{1.84 s}{2\pi})^2=0.842 m[/tex]

It makes them be three forces

Answer: less

Explanation:

1. [tex]-8.78 \cdot 10^5 J[/tex]

The energy lost by the water is given by:

[tex]Q=m C_s \Delta T[/tex]

where

m = 3.0 kg = 3000 g is the mass of water

Cs = 4.179 J/g•°C is the specific heat

[tex]\Delta T=10.0C-80.0C=-70.0 C[/tex] is the change in temperature

Substituting,

[tex]Q=(3000 g)(4.179 J/gC)(-70.0 C)=-8.78 \cdot 10^5 J[/tex]

2. [tex]3.24 \cdot 10^4 J[/tex]

The energy added to the aluminium is given by:

[tex]Q=m C_s \Delta T[/tex]

where

m = 0.30 kg = 300 g is the mass of aluminium

Cs = 0.900 J/g•°C is the specific heat

[tex]\Delta T=150.0 C-30.0C =120.0 C[/tex] is the change in temperature

Substituting,

[tex]Q=(300 g)(0.900 J/gC)(120.0 C)=3.24 \cdot 10^4 J[/tex]

3a. [tex]-5.6^{\circ}C[/tex]

The temperature change of the water is given by

[tex]\Delta T=\frac{Q}{m C_s}[/tex]

where

[tex]Q = -232 kJ=-2.32\cdot 10^5 J[/tex] is the heat lost by the water

[tex]m=10.0 kg=10000 g[/tex] is the mass of water

Cs = 4.179 J/g•°C is the specific heat

Substituting,

[tex]\Delta T=\frac{-2.32\cdot 10^5 J}{(10000g)(4.179 J/gC)}=5.6^{\circ}C[/tex]

3b. [tex]+10.2^{\circ}C[/tex]

The temperature change of the copper is given by

[tex]\Delta T=\frac{Q}{m C_s}[/tex]

where

[tex]Q = 1.96 kJ=1960[/tex] is the heat added to the copper

[tex]m= 500 g[/tex] is the mass of copper

Cs = 0.385 J/g•°C is the specific heat

Substituting,

[tex]\Delta T=\frac{1960 J}{(500g)(0.385 J/gC)}=10.2^{\circ}C[/tex]

4. 42.9 g

The mass of the water sample is given by

[tex]m=\frac{Q}{C_S \Delta T}[/tex]

where

[tex]Q=4300 J[/tex] is the heat added

[tex]\Delta T=39 C-15 C=24C[/tex] is the temperature change

Cs = 4.179 J/g•°C is the specific heat

Substituting,

[tex]m=\frac{4300 J}{(4.179 J/gC)(24 C)}=42.9 g[/tex]

5. 115.5 J

The heat used to heat the copper is given by:

[tex]Q=m C_s \Delta T[/tex]

where

m = 5.0 g is the mass of copper

Cs = 0.385 J/g•°C is the specific heat

[tex]\Delta T=80.0 C-20.0C =60.0 C[/tex] is the change in temperature

Substituting,

[tex]Q=(5.0 g)(0.385 J/gC)(60.0 C)=115.5 J[/tex]

6. 0.185 J/g•°C

The specific heat of iron is given by:

[tex]C_s = \frac{Q}{m \Delta T}[/tex]

where

Q = -47 J is the heat released by the iron

m = 10.0 g is the mass of iron

[tex]\Delta T=25.0-50.4 C=-25.4 C[/tex] is the change in temperature

Substituting,

[tex]C_s = \frac{-47 J}{(10.0 g)(-25.4 C)}=0.185 J/gC[/tex]

These questions relate to calculating heat energy changes using the concept of specific heat. Specific heat, an intensive property, is used to calculate how much heat is lost or gained during temperature changes of different substances. The formula q=mcΔT, where 'q' is heat energy, 'm' is mass, 'c' is specific heat and 'ΔT' is the temperature change, is used for the calculations.

The specific heat of a substance is an intensive property that defines how much heat energy is needed to raise 1 gram of the substance by 1 degree Celsius.

For the first question, when 3.0 kg of water is cooled from 80.0°C to 10.0°C, we use the formula q=mcΔT, where m is mass, c is specific heat and ΔT is the change in temperature. Substituting the given values, we get q = 3000g * 4.179 J/g°C *(10.0°C - 80.0°C) which gives -881,940 Joules (roughly -882 kJ). The negative sign indicates that heat energy is lost.

For the second question, we apply the same formula, with m=0.30 kg, c=0.900 J/g°C and ΔT = 150.0°C - 30.0°C, giving 32.4 kJ heat energy needed.

For the third question, we reverse the equation to solve for temperature. For 10.0 kg of water losing 232 kJ, ΔT = q / (mc), or 232,000J / (10,000g * 4.179 J/g°C), resulting in an approximately 5.54°C temperature loss. For 500g of copper gaining 1.96 kJ of heat, the equation gives a temperature change of about 10°C.

The same principles are applied to answer the remaining questions.

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Answer:

-3 m/s

Explanation:

The problem can be solved by using the law of conservation of momentum.

In fact, the system squid+water inside is initially at rest, so the total momentum is zero:

[tex]p_i=0[/tex]

while the final momentum is:

[tex]p_f = m_s v_s + m_w v_w[/tex]

where

[tex]m_s=1.5 kg[/tex] is the mass of the squid

[tex]v_s[/tex] is the velocity of the squid

[tex]m_w = 0.10 kg[/tex] is the mass of water

[tex]v_w = 45 m/s[/tex] is the water velocity

Since the total momentum must be conserved,

[tex]p_i = p_f = 0[/tex]

So we have

[tex]m_s v_s + m_w v_w =0\\v_s = -\frac{m_w v_w}{m_s}=-\frac{(0.10 kg)(45 m/s)}{1.5 kg}=-3 m/s[/tex]

where the negative sign means the direction is opposite to that of the water.

The final velocity of the squid after the ejection of the water is 3 m/s backwards.

The given parameters;

Apply the principle of conservation of linear momentum;

m₁u₁ + m₂u₂ = m₁v₁  +  m₂v₂

1.5(0) + 0.1(0) = 1.5v₁  +  45(0.1)

0 = 1.5v₁  + 4.5

1.5v₁ = -4.5

[tex]v_1 = \frac{-4.5}{1.5} \\\\v_1 = -3 \ m/s[/tex]

Thus, the final velocity of the squid after the ejection of the water is 3 m/s backwards.

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(a) [tex]9.1 \cdot 10^{-21} kg m/s[/tex]

The magnitude of the linear momentum of an object is given by

[tex]p=mv[/tex]

where

m is the object's mass

v is its speed

In this case, we have

[tex]m=1.67\cdot 10^{-27} kg[/tex] (mass of the proton)

[tex]v=5.45\cdot 10^6 m/s[/tex] (speed of the proton)

So, the momentum is

[tex]p=(1.67\cdot 10^{-27} kg)(5.45\cdot 10^6 m/s)=9.1 \cdot 10^{-21} kg m/s[/tex]

b) 7.0 kg m/s

In this case, we have

m = 16.0 g = 0.016 kg (mass of the bullet)

v = 435 m/s (speed of the bullet)

By applying the same formula, the linear momentum is

[tex]p=(0.016 kg)(435 m/s)=7.0 kg m/s[/tex]

c) 797.5 kg m/s

In this case, we have

m = 72.5 kg (mass of the sprinter)

v = 11.0 m/s (speed of the sprinter)

By applying the same formula, the linear momentum is

[tex]p=(72.5 kg)(11.0 m/s)=797.5 kg m/s[/tex]

d) [tex]1.8\cdot 10^{29} kg m/s[/tex]

In this case, we have

[tex]5.98\cdot 10^{24} kg[/tex] (mass of the Earth)

[tex]v=2.98\cdot 10^4 m/s[/tex] (speed of the Earth)

By applying the same formula, the linear momentum is

[tex]p=(5.98\cdot 10^{24} kg)(2.98\cdot 10^4 m/s)=1.8\cdot 10^{29} kg m/s[/tex]

All electromagnetic waves have the same speed when they're all in the same medium.

Note: Sound waves don't belong on this list, because they're not electromagnetic waves. The speed of sound in air is only about 0.0001 percent of the speed of electromagnetic waves in air.

Answer:

The electric potential (voltage) [tex]V[/tex] produced by a point charge [tex]Q[/tex], at any point in space, is given by the following equation:

[tex]V=k\frac{Q}{r}[/tex]

Where:

[tex]k=8.99(10)^{9} Nm^{2}/C^{2}[/tex] is the Coulomb's constant

[tex]r[/tex] is the distance  

The result is a scalar quantity, is defined as the electric potential energy per unit of charge and determines the electric influence exerted by the charge on that point of space.

Answer:

v=k*q/d

Explanation:

The formula v=k*q/r is also correct but in this case v=k*q/d was given as a choice.

Answer:

200

Explanation:

Melting point of a substance is 200.

The temperature at which a solid and liquid phase can coexist in equilibrium and the point at which matter transforms from a solid to a liquid is known as a substance's melting point. Pure solutions and liquids fall within this definition.

It is important to specify melting point because it relies on pressure. Melting point tables frequently use standard pressures like 100 kPa or 1 atmosphere. The liquefaction point is another name for the melting point.

The temperature at which a liquid changes to a solid (the reverse of melting) is the freezing point or crystallization point. The freezing point and the melting point do not necessarily occur at the same temperature.

Therefore, Melting point of a substance is 200.

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C. The molecules will move more slowly

Answer: B.Heat is never converted completely into mechanical energy.

Explanation:

According to the second principle of thermodynamics:  

"The amount of entropy in the universe tends to increase over time"

However the first formulation of this law (by Sadi Carnot) states:

"There is an upper limit to the efficiency of conversion of heat to work, in a heat engine "

This means the heat cannot be completely transformed into mechanical energy in a machine. That is why a machine's effieciency is always less than 100%

Answer:

B

Explanation:

Use logic

A positron, or an anti-electron, is a particle with a positive charge and the mass of an electron.

Answer:

The boiling point of water is around 185.9ºF or 85.5ºC

Explanation:

The boiling point of water depends on the atmospheric pressure. So, the higher the elevation, the lower the atmospheric pressure, therefore the boiling point of water is lower as well. Assuming that sea level pressure is constant ,(760 mmHg, 29.92inches Hg or 14.69psi) the boiling point of water is 212ºF (100ºC). Approximately, for every 500 foot (150m) of elevation increase, the boiling point temperature decreases 1ºF (0.55ºC).

Yes sirree !  Uh huh, uh huh.  Truer words are rarely spoken.

Answer:

You forgot to put the question it's asking but its Gamma ray

Explanation:

Natalia is studying a wave produced in her magnetics lab. This wave can move through the empty space in a vacuum and carries a lot of energy.

What wave is Natalia most likely studying?

Gamma ray is the answer

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1. The problem statement, all variables and given/known data A parallel-plate capacitor of capacitance C with circular plates is charged by a constant current I. The radius a of the plates is much larger than the distance d between them, so fringing effects are negligible. Calculate B(r), the magnitude of the magnetic field inside the capacitor as a function of distance from the axis joining the center points of the circular plates. 2. Relevant equations When a capacitor is charged, the electric field E, and hence the electric flux Φ, between the plates changes. This change in flux induces a magnetic field, according to Ampère's law as extended by Maxwell: ∮B⃗ ⋅dl⃗ =μ0(I+ϵ0dΦdt). You will calculate this magnetic field in the space between capacitor plates, where the electric flux changes but the conduction current I is zero.

The electric field E, and consequently the electric flux, between the plates of a capacitor vary as it charges.

Electric flux is defined as the quantity of electric lines of force or electric field lines that cross a specific region is a property of an electric field.  According to this theory, electric field lines begin with positive electric charges and end with negative charges. An electric field's important characteristic is its electric flux. It can be thought of as the quantity of forces interacting in a particular space.

As a function of distance from the axis, the strength of the magnetic field B(r) inside the capacitor is

∫ Bdl = μ₀ I enclosed

B x 2λr =  μ₀ I (λ r² / λ a²)

Br = μ₀ In / 2λa²

Thus, the electric field E, and consequently the electric flux, between the plates of a capacitor vary as it charges.

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Well, if the skydiver is at constant velocity, than there’s no acceleration, as stated by Newton’s first law. Thus the total net force would equate to 0. In order to make this statement true, the answer would have to be exactly 600 N.

Force is defined as the product of mass and acceleration .it is a vector quantity. The force acting on the skydiver must be 600 N which should be acting upward.

Force is defined as the action on any object that has the ability to change the shape, size, and direction of an object is in motion or in static condition.

It is a vector quantity defined as the product of mass and acceleration. Acceleration is the rate  change of velocity with respect to the time

Force is given by;

[tex]\rm {Force = Mass \times Acceleration}[/tex]

As the definition of acceleration if the velocity change is zero in that condition the force acting is zero. that's why force will also be zero

[tex]\rm {F +ma+mg =0 }[/tex]

If acceleration is zero in that condition

[tex]\rm {F =-mg }[/tex]

[tex]\rm {F = -600 N }[/tex]

where - ve shows the direction of force is negative

therefore a force of exactly 600 N is acting upward on the skydiver.

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Answer:

3.12 m

Explanation:

The fundamental frequency of an open-closed tube is given by

[tex]f_1 = \frac{v}{4L}[/tex]

where

f1 is the fundamental frequency

v is the speed of sound in air (343 m/s)

L is the length of the tube

If we use the model mentioned, we can consider L to be the effective length of the instrument. This means we can re-arrange the formula and use the fundamental frequency, f1 = 27.5 Hz, to find L:

[tex]L=\frac{v}{4 f_1}=\frac{343 m/s}{4(27.5 Hz)}=3.12 m[/tex]

The imaginary second level is 60 dB more intense than the real level of the caller.

60 dB means a multiplication of  10⁶  = 1 million.

That's how many equally-talented callers it would take to be 60 dB louder than him.

The number of callers would be required to reach the pain level of 120 db is 10⁶ , that is, one million.

Decibel is the unit of sound. Its symbol is ‘dB’. We can define decibel as:

A unit of measurement used to express the ratio of one value of a power or field quantity to another on a logarithmic scale, the logarithmic quantity being called the power level or field level, respectively.

60 dB = 10 log₁₀ (P₁/P)

120 dB =  10 log₁₀( P₂/P₀)

The man have to produce square of his intensity level to reach the pain level of 120 dB.

The number of callers would be required to reach the pain level of 120 db is 10⁶ , that is, one million.

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The most common atom of iron has 26 protons and 30 neutrons in its nucleus. What are its atomic number, atomic mass, and number of electrons if it is electrically neutral? This atom has atomic number 26, atomic mass 56, and has 26 electrons.

Answer :The mass number is 56.

Explanation:

Mass number is defined as the sum of number of protons and neutrons that are present in an atom.

Mass number = Number of protons + Number of neutrons = 26+ 30 =56

Atomic number is defined as the number of protons or number of electrons that are present in an atom.

Atomic number = Number of electrons = Number of protons = 26

Hence, neutrons and protons affects the mass number and thus the mass number will be 56.

An object's gravitational potential energy is

(mass) x (gravity) x (height above ground) .

I don't see the object's speed anywhere in that formula, do you ?

An object's speed has no effect whatsoever on its potential energy ... only if it changes the object's height above ground.

It is b because it will always triple

If the number of particles in a sample of gas is doubled, the volume of gas doubles because more number of molecules added to the system.

An increase in the number of gas particles in the container increases the volume of the gas because more space is occupied by the gas particles that enters to the system.

So we can conclude that if the number of particles in a sample of gas is doubled, the volume of gas doubles because more number of molecules added to the system.

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B because it is the only evidence that displays an effect from the field without contact

The dielectric constant of the dielectric material is 3.5.

Given that the capacitance of the parallel-plate capacitor without the dielectric is 1.2 nF, and the capacitance increases by 3.0 nF when the gap is filled with the dielectric, we can find the dielectric constant using the equation:

C' = KC

Since the original capacitance is 1.2 nF and the increased capacitance is 1.2 + 3.0 = 4.2 nF, we can plug these values into the equation and solve for K:

KC = C'

K * 1.2 nF = 4.2 nF

K = 4.2 nF / 1.2 nF = 3.5

Therefore, the dielectric constant of the dielectric material is 3.5.

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I have found this tool to hep you solve your question.

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To determine the compression of the spring when a 4.0 kg object is dropped from 1.0 meter, we use the conservation of energy principle. The gravitational potential energy of the dropped object is converted into the spring's elastic potential energy. Calculations show the spring will compress approximately 9.0 cm.

We can solve the problem of the 4.0 kilogram object being dropped onto a spring by considering the conservation of energy. The gravitational potential energy at the height of 1.0 meter will convert into the elastic potential energy of the spring once the spring is compressed and the system momentarily comes to rest.

The gravitational potential energy (PE) can be calculated using the formula PE = mgh, where m is the mass, g is the acceleration due to gravity (9.8 m/s2), and h is the height from which the object is dropped. Therefore, PE = 4.0 kg * 9.8 m/s2 * 1.0 m = 39.2 Joules.

The elastic potential energy stored in a compressed spring is given by the formula PEspring = 1/2 * k * x2, where k is the spring constant and x is the compression distance. Setting the gravitational potential energy equal to the spring's elastic potential energy gives 39.2 J = 1/2 * 850 N/m * x2. Solving for x gives x = sqrt((2 * 39.2) / 850) which approximately equals 0.09 meters or 9.0 cm.

Answer:

c) quadruple in magnitude

Explanation:

The power dissipated in the circuit is given by:

[tex]P=I^2 R[/tex]

where

I is the current in the circuit

R is the total resistance of the circuit

In this problem:

- The current is doubled: I' = 2 I

- The resistance is kept constant: R' = R

So, the power dissipated is

[tex]P' = (I')^2 R' = (2I)^2 R=4 I^2 R=4 P[/tex]

so, the power dissipated increase by a factor 4 (quadruples).

Final answer:

When the current through a resistor with constant resistance is doubled, the power dissipated will quadruple instead of just doubling because power is proportional to the square of the current. Correct answer is (c).

Explanation:

Understanding Power Dissipation in Circuits

When we talk about power dissipation in a circuit, we are often referring to the power consumed by a resistor. The power dissipated by a resistor is given by the formula P = I² * R, where P stands for power, I is the current through the resistor, and R is the resistance. If the current flowing through a circuit with constant resistance is doubled, the power dissipation is affected as follows:

Original power dissipation: P = I² * R

After doubling the current: [tex]P_{new[/tex] = (2I)² * R = 4 * I² * R

Thus, the power dissipated by the circuit after doubling the current will quadruple in magnitude, since 4 times the original I² * R would be 4 * P. Therefore, the correct answer is (c) quadruple in magnitude.

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