Plugging in the values and calculating, we find that the 98% confidence interval is approximately (0.5847, 0.6553).
Explanation:To construct a 98% confidence interval for the proportion of all American females who support the death penalty for convicted murders, we can use the formula:
CI = p ± z * √(p * (1-p) / n)
Where:
CI is the confidence intervalp is the sample proportion (0.62)z is the z-score corresponding to the desired confidence level (98% or 0.98)n is the sample size (3100)Using a standard normal distribution table or a calculator, we can find that the z-score for a 98% confidence level is approximately 2.33.
Plugging in the values into the formula:
CI = 0.62 ± 2.33 * √(0.62 * (1-0.62) / 3100)
Calculating the values:
CI = 0.62 ± 2.33 * √(0.62 * 0.38 / 3100)
CI = 0.62 ± 2.33 * √(0.235 / 3100)
CI = 0.62 ± 2.33 * 0.01516
CI = 0.62 ± 0.03535
CI ≈ (0.5847, 0.6553)
Therefore, the 98% confidence interval for the proportion of all American females who support the death penalty for convicted murders is approximately (0.5847, 0.6553).
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The time (in minutes) until the next bus departs a major bus depot follows a uniform distribution from 25 to 46 minutes. Let X denote the time until the next bus departs. The distribution is and is . The mean of the distribution is μ= . The standard deviation of the distribution is σ= . The probability that the time until the next bus departs is between 30 and 40 minutes is P(30
Answer:
The distribution is uniform and is continuous probability distribution.
The mean of the distribution is μ= 35.5 minutes.
The standard deviation of the distribution is σ= 6.06
P(30<x<40)= 0.476
Step-by-step explanation:
a.The amount of time in minutes until the next bus departs is uniformly distributed between 25 and 46 inclusive.
The distribution is uniform and is continuous probability distribution.
b.Let X be the number of minutes the next bus arrives and a= 25 , b= 46. Hence mean = a+b/2= 25+ 46/ 2= 35.5 minutes.
The mean of the distribution is μ= 35.5 minutes.
c. Standard deviation = √(b-a)²/12
Standard deviation= √(46-25)²/12= √(21)²/12= √441/12=√36.75= 6.06
The standard deviation of the distribution is σ= 6.06
d. P(30<x<40)
For this we draw a graph . It is also called the rectangular distribution because its total probability is confined to a rectangular region with base equal to (b-a) and height 1/(b-a) .
This can be calculated as
P(30<x<40)= base * height (in this probability the base is 10)
= (40-30) *(1/ 21)= 10/21= 0.476
The probability that the time until the next bus departs is between 30 and 40 minutes is 10/21.
Explanation:The question is asking for the probability that the time until the next bus departs is between 30 and 40 minutes. Since the distribution is uniform, we can find the probability by calculating the fraction of the total range that falls within the desired interval. In this case, the total range is 46-25=21 minutes, and the desired interval is 40-30=10 minutes.
So the probability is 10/21, which can be simplified to 10/21.
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How many times larger is the value of 0.75 than the value of 0.0075
A recipe for a loaf of bread calls for of a cup of flour. If Milo used 12 cups of flour, how many loaves of bread did he prepare?
A.
18
B.
16
C.
15
D.
12
E.
8
Answer: The answer is D 12 i am pretty sure.
Step-by-step explanation:
Answer:
D
Step-by-step explanation:
Find the Surface Area.
18m2
20m2
16m2
15m2
Answer:
20 meters square
Step-by-step explanation:
Surface Area of this square based pyramid = A = base area + 4* (face area)
A = (2 *2) + 4* ( (1/2)*2 * 4) )
A = 4 + 4*(4)
A = 4 + 16 = 20
A = 20 square meters
100 POINTS.
PLEASE PROVIDE STEPS.
Answer:
π³/1296
Step-by-step explanation:
∫ [ (asin x)² dx / √(4 − 4x²) ]
Factoring the denominator:
∫ [ (asin x)² dx / √(4 (1 − x²)) ]
∫ [ (asin x)² dx / (2√(1 − x²)) ]
½ ∫ [ (asin x)² dx / √(1 − x²) ]
If u = asin x, then du = dx / √(1 − x²).
½ ∫ u² du
⅙ u³ + C
Substitute back:
⅙ (asin x)³ + C
Evaluate between x=0 and x=½.
⅙ (asin ½)³ − ⅙ (asin 0)³
⅙ (π/6)³ − ⅙ (0)³
π³/1296
Answer:
[tex]\dfrac{\pi^3}{1296}[/tex]
Step-by-step explanation:
Given integral:
[tex]\displaystyle \int^{1/2}_0 \dfrac{\arcsin^2 (x)}{\sqrt{4-4x^2}}\;dx[/tex]
To evaluate the integral, begin by simplifying the denominator of integrand:
[tex]\begin{aligned}\sqrt{4-4x^2}&=\sqrt{4(1-x^2)} \\ &=\sqrt{4}\sqrt{1-x^2}\\&=2\sqrt{1-x^2}\end{aligned}[/tex]
Therefore:
[tex]\displaystyle \int^{1/2}_0 \dfrac{\arcsin^2 (x)}{2\sqrt{1-x^2}}\;dx[/tex]
Now, evaluate the integral using the method of substitution.
[tex]\textsf{Let $u = \arcsin(x)$}[/tex]
Find du/dx using the common derivative of arcsin(x):
[tex]\boxed{\begin{array}{c}\underline{\textsf{Derivative of $\arcsin(x)$}}\\\\\dfrac{\text{d}}{\text{d}x}\left(\arcsin(x)\right)=\dfrac{1}{\sqrt{1-x^2}}\end{array}}[/tex]
Therefore:
[tex]\dfrac{d}{dx}(u)=\dfrac{d}{dx}\left(\arcsin(x)\right) \\\\\\\dfrac{du}{dx}=\dfrac{1}{\sqrt{1-x^2}}[/tex]
Rearrange to isolate dx:
[tex]dx=\sqrt{1-x^2}\;du[/tex]
Calculate the new limits:
[tex]x=0 \implies u = \arcsin(0)=0[/tex]
[tex]x=\dfrac{1}{2} \implies u = \arcsin\left(\dfrac{1}{2}\right)=\dfrac{\pi}{6}[/tex]
Rewrite the original integral in terms of u and du:
[tex]\displaystyle \int^{\pi / 6}_0 \dfrac{u^2}{2\sqrt{1-x^2}}\;\sqrt{1-x^2}\;du \\\\\\\int^{\pi / 6}_0 \dfrac{u^2}{2}}\;du[/tex]
Evaluate:
[tex]\begin{aligned}\displaystyle \int^{\pi / 6}_0 \dfrac{u^2}{2}}\;du &=\left[\dfrac{u^3}{6}\right]^{\pi / 6}_0\\\\&=\dfrac{\left(\frac{\pi}{6}\right)^3}{6}-\dfrac{(0)^3}{6} \\\\&=\dfrac{\frac{\pi^3}{216}}{6}-0 \\\\ &=\dfrac{\pi^3}{1296}\end{aligned}[/tex]
Therefore, the value of the integral is:
[tex]\Large\boxed{\dfrac{\pi^3}{1296}}[/tex]
Mary lives on a corner lot. The neighborhood children have been cutting diagonally across her lawn instead of walking around the yard. If the diagonal distance across the lawn is 50 ft and the longer part of the sidewalk is twice the shorter length, how many feet are the children saving by cutting the lawn? round to the nearest foot if necessary.
Answer:
17 feet
Step-by-step explanation:
Length of the diagonal=50 feet
Let the shorter part of the sidewalk =x
Since the longer part of the sidewalk is twice the shorter length,
Length of the longer part of the sidewalk =2x
First, we determine the value of x.
Using Pythagoras Theorem and noting that the diagonal is the hypotenuse.
[tex]50^2=(2x)^2+x^2\\5x^2=2500\\$Divide both sides by 5\\x^2=500\\x=\sqrt{500}=10\sqrt{5} \:ft[/tex]
The length of the shorter side =[tex]10\sqrt{5} \:ft[/tex]
The length of the longer side =[tex]20\sqrt{5} \:ft[/tex]
Total Distance =[tex]10\sqrt{5}+ 20\sqrt{5}=67 \:feet[/tex]
Difference in Distance
67-50=17 feet
The children are saving 17 feet by cutting the lawn diagonally.
PLEASE- The label of a certain cheese states that it weighs 8 ounces. The actual weight of the product sold is allowed to be 0.2 ounces above or below that. Write a compound inequality that represents this situation.
Answer:
7.8《 X《 8.2
Step-by-step explanation:
Let X be the weight of the product
8 - 0.2《 X《 8 + 0.2
7.8《 X《 8.2
Answer:
7.8《 X《 8.2
Step-by-step explanation:
Let X be the weight of the product
8 - 0.2《 X《 8 + 0.2
7.8《 X《 8.2p
Please help!! MATH! WILL MARK BRAINLIEST!!
Answer:
Step-by-step explanation:
How can you use a rational exponent to
represent a power involving a radical?
Answer:
[tex]\sqrt[n]{x^m}=x^{\frac{m}{n}}[/tex]
Step-by-step explanation:
A radical represents a fractional power. For example, ...
[tex]\sqrt{x}=x^{\frac{1}{2}}[/tex]
This makes sense in view of the rules of exponents for multiplication.
[tex]a^ba^c=a^{b+c}\\\\a^{\frac{1}{2}}a^{\frac{1}{2}}=a^{\frac{1}{2}+\frac{1}{2}}=a\\\\(\sqrt{a})(\sqrt{a})=a[/tex]
So, a root other than a square root can be similarly represented by a fractional exponent.
____
The power of a radical and the radical of a power are the same thing. That is, it doesn't matter whether the power is outside or inside the radical.
[tex]\sqrt[n]{x^m}=x^{\frac{m}{n}}=(\sqrt[n]{x})^m[/tex]
In cooking class, Sofia measures a stick of butter. It is 13 centimeters long, 3 centimeters
wide, and 3 centimeters tall. What is the volume of the stick of butter?
Answer: 117 centimeters
Step-by-step explanation:
Answer:
117 cm³
Step-by-step explanation:
To calculate the volume of a Rectangular Prism, we must use the formula:
l×w×h=V.
In this case, l= 13, w= 3, and h= 3.
When these values are substituted in, we get:
13×3×3= 117 cm³
Please help me!!
Gggggg
Answer:
divide the numbers that are on the paper
Step-by-step explanation:
Answer:
divide
Step-by-step explanation:
hope ur having a good day :)
if h(x)=1-2/3x, find h(-6).
Answer:
5
Step-by-step explanation:
Put -6 where x is and do the arithmetic.
[tex]h(x)=1-\dfrac{2}{3}x\\\\h(-6)=1-\dfrac{2}{3}(-6)=1-\dfrac{-12}{3}=1-(-4)=1+4\\\\\boxed{h(-6)=5}[/tex]
2 ( n-1 ) + 4n= 2( 3n-1 )
Answer:
infinite solutions
Step-by-step explanation:
2 ( n-1 ) + 4n= 2( 3n-1 )
Distribute
2n -2 +4n = 6n -2
Combine like terms
6n -2 = 6n -2
Subtract 6n from each side
6n-2-6n = 6n-2-6n
-2 = -2
This is always true so there are infinite solutions
What is the volume of the triangular prism? A) 15 cm3 B) 18 cm3 C) 21 cm3 D) 24 cm3
Answer:
See Explanation Below
Step-by-step explanation:
The image of the trianglular prism is missing.
However, I'll answer your question using the attachment below.
The volume of a triangular prism is calculated as follows.
V = ½lbh
Where l = length of the prism
b = base of the prism
h = height of the prism
V = volume of the prism.
From the attachment,
Length, l = 6 cm
Base, b = 3 cm
And Height, h = 4 cm
By substituting each of these values in the formula given above
V = ½lbh becomes
V = ½ * 6 * 3 * 4
V = 3 * 3 * 4
V = 36 cm³
If you follow these steps you'll get the volume of the trianglular prism as it is in your question.
Answer:
its 15
Step-by-step explanation:
ik its 15 because when i put in 24 it was wrong and gave me the awnser which was 15
What is the degree of the polynomial?
f(x) = 4x^3 - 17x^2 + x + 9|
Answer:
Degree 3
Step-by-step explanation:
Highest valued exponent of x variable is 3
A bag contains eleven equally sized marbles, which are numbered. Two marbles are chosen at random and replaced after each selection.
Eleven numbered marbles are shown. Marbles 2, 5, 6, 7, 8, 10, 11 are white. Marbles 1, 3, 4, 9 are purple.
What is the probability that the first marble chosen is shaded and the second marble chosen is labeled with an odd number?
StartFraction 10 Over 121 EndFraction
StartFraction 24 Over 121 EndFraction
StartFraction 6 Over 11 EndFraction
StartFraction 10 Over 11 EndFraction
EndFraction
StartFraction 24 Over 121 EndFraction
StartFraction 6 Over 11 EndFraction
StartFraction 10 Over 11 EndFraction
Answer:
StartFraction 24 Over 121 EndFraction
Step-by-step explanation:
Does anybody know how to do #11, I figured out #10
Answer:
no
Step-by-step explanation:
63-28=subtracting by adding up
Answer:
35
Step-by-step explanation:
On subtracting 28 from 63 by adding up we get 35.
To subtract by adding up is special method to find the difference between two numbers. For 63-28, we can do it in the following steps:
We start by using the smaller number, here 28. And add a number to 28 such that it we receive a number that is easy to use further. So, here we can add 2 to it which gives us:
[tex]28 + 2= 30[/tex]
Now we take 30 and we can add another 30 to it. This gives us:
[tex]30+30 = 60[/tex]
Now the goal is to add a number such that the sum of the number and 60 make 63. So, we add 3 to 60 which gives us:
[tex]60+3 = 63[/tex]
Now we need to take the second number we have added in each of the steps (2, 30 and 3) and add them. The sum of these numbers will give us the difference between 63 and 28. Thus we can write it as:
[tex]63-28 = 2+30+3\\\\63-28 = 35[/tex]
Thus on subtracting 28 from 63 by adding up method we get the answer as 35.
Calculate the divergence of the following radial field. Express the result in terms of the position vector r and its length StartAbsoluteValue Bold r EndAbsoluteValue. FequalsStartFraction left angle x comma y comma z right angle Over x squared plus y squared plus z squared EndFraction equalsStartFraction Bold r Over StartAbsoluteValue Bold r EndAbsoluteValue squared EndFraction Choose the correct answer below. A. The divergence of F is 0. B. The divergence of F is StartFraction negative 2 Over StartAbsoluteValue Bold r EndAbsoluteValue Superscript 4 EndFraction . C. The divergence of F is StartFraction 1 Over StartAbsoluteValue Bold r EndAbsoluteValue squared EndFraction . D. The divergence of F is StartFraction negative 1 Over StartAbsoluteValue Bold r EndAbsoluteValue squared EndFraction
Answer:
C. The divergence of F is StartFraction 1 Over StartAbsoluteValue Bold r EndAbsoluteValue squared EndFraction
∇•F = 1/|r|²
Step-by-step explanation:
The position vector r = (x, y, z)
r = xi+yj+zk
|r| = √x²+y²+z²
|r|² = x²+y²+z²
Given the radial field F = r/|r|²
Divergence of the radial field is expressed as:
∇•F = {δ/δx i+ δ/δy j + δ/δy k} • {(r/|r|²)
∇•F = {δ/δx i+ δ/δy j + δ/δy k} • {xi/|r|² + yj/|r|² + zk/|r|²}
∇•F = δ/δx(x/|r|²) + δ/δy(y/|r|²)+δ/δz(z/|r|²)
Check the attachment for the complete solution.
10 POINTS ! PLZ HURRY AND ANSWER (:
Answer:
The top question = 189.25 rounded = 189.3 sq in
explanation: area= radius square x pi so radious is 5..sq will 25 then 25xpi(3.14)=78.50 78.50/2= 39.25 + 150 (area of rect) =189.25 rounded to 189.3
for the bottom question = 488 square cm
Step-by-step explanation:
17x22= 374
22-10=12
12x19=228 / 2 = 114
114 + 374 = 488 sq cm
Assume that when adults with smartphones are randomly selected, 58% use them in meetings or classes. If 10 adult smartphone users are randomly selected, find the probability that at least 5 of them use their smartphones in meetings or classes.
Answer:
79.85% probability that at least 5 of them use their smartphones in meetings or classes.
Step-by-step explanation:
For each adult, there are only two possible outcomes. Either they use their smartphone during meetings or classes, or they do not. The probability of an adult using their smartphone in these situations are independent of other adults. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
And p is the probability of X happening.
Assume that when adults with smartphones are randomly selected, 58% use them in meetings or classes.
This means that [tex]p = 0.58[/tex]
10 adults selected.
This means that [tex]n = 10[/tex]
Find the probability that at least 5 of them use their smartphones in meetings or classes.
[tex]P(X \geq 5) = P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10)[/tex]
In which
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 5) = C_{10,5}.(0.58)^{5}.(0.42)^{5} = 0.2162[/tex]
[tex]P(X = 6) = C_{10,6}.(0.58)^{6}.(0.42)^{4} = 0.2488[/tex]
[tex]P(X = 7) = C_{10,7}.(0.58)^{7}.(0.42)^{3} = 0.1963[/tex]
[tex]P(X = 8) = C_{10,8}.(0.58)^{8}.(0.42)^{2} = 0.1017[/tex]
[tex]P(X = 9) = C_{10,9}.(0.58)^{9}.(0.42)^{1} = 0.0312[/tex]
[tex]P(X = 10) = C_{10,10}.(0.58)^{10}.(0.42)^{0} = 0.0043[/tex]
[tex]P(X \geq 5) = P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10) = 0.2162 + 0.2488 + 0.1963 + 0.1017 + 0.0312 + 0.0043 = 0.7985[/tex]
79.85% probability that at least 5 of them use their smartphones in meetings or classes.
Solve the right triangle shown in the figure. Around lengths to two decimal places and express angles to the nearest tenth of a degree.
Answer:
a = 65.37
b = 46.11
B = 35.2
Step-by-step explanation:
sin 54.8 = a / 80
a = 80 sin 54.8 = 65.3715 = 65.4
[tex]b^{2} = c^{2} - a^{2}[/tex]
b=[tex]\sqrt{80^2 - 65.3715^2}[/tex]
b=46.1147 = 46.11
B = 180 - 90 - 54.8 = 35.2
The sides and the angles as follows:
Therefore,
∠A = 54.8°
∠B = 35.2°
∠C = 90°
a ≈ 65.37
b ≈ 46.64
c = 80
The triangle is a right angle triangle. Using trigonometric ratios, let's find a.
sin 54.8 = opposite / hypotenuse
sin 54.8 = a / 80
a = 80 sin 54.8
a = 65.3715918668
a ≈ 65.37
let's use Pythagoras theorem to find b.
c² = a² + b²
b² = c² - a²
b² = 80² - 65²
b² = 6400 - 4225
b² = 2175
b = √2175
b = 46.6368952654
b ≈ 46.64
let's find ∠B
∠A + ∠B + ∠C = 180°
∠B = 180 - 54.8 - 90
∠B = 35.2°
Therefore,
∠A = 54.8°
∠B = 35.2°
∠C = 90°
The sides are as follows:
a ≈ 65.37
b ≈ 46.64
c = 80
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Increasing numbers of businesses are offering child-care benefits for their workers. However, one union claims that more than 85% of firms in the manufacturing sector still do not offer any child-care benefits to their workers. random sample of 330 manufacturing firms is selected and asked if they offer child-care benefits. Suppose the P-value for this test was reported to be p = 0.1071. State the conclusion of interest to the union. Use alpha=0.05 .
Final answer:
With a p-value of 0.1071 exceeding the significance level of 0.05, we do not reject the null hypothesis and conclude there is insufficient evidence to support the union's claim about child-care benefits in manufacturing firms.
Explanation:
The reported p-value of 0.1071 is greater than the significance level alpha (0.05). Based on this result, the appropriate statistical decision would be to do not reject the null hypothesis.
Therefore, at the 5 percent significance level, there is insufficient evidence to support the claim made by the union that more than 85% of firms in the manufacturing sector do not offer child-care benefits to their workers.
The higher p-value suggests that the data collected from the random sample of 330 manufacturing firms does not provide strong enough evidence to refute the possibility that the percentage of firms not offering child-care benefits is at or below 85%.
Find the missing side of the triangle. Leave your answer in simplest radical
form.
Answer:
that answer is D
Step-by-step explanation:
I used pythagreum theurum a^2+b^2=c^2
then i divided square root 260 by 4 the largest perfect square factor which gives us 2 square root 65 because 4 is a perfect square that equal 2
Valerie is taking a road trip over spring break. At 4:30 p.m. she looks down at her speedometer and notices that she is going 45 mph. Ten minutes later she looks down at the speedometer again and notices that she is going 55 mph. When was she moving exactly 50 mph?Select one:a. 4:30 p.m.b. 4:35 p.m.c. 4:40 p.m.d. Cannot be determined
Answer:
b. 4:35 p.m
Step-by-step explanation:
Her speed in t minutes after 4:30 p.m. is modeled by the following equation:
[tex]v(t) = v(0) + at[/tex]
In which v(0) is her speed at 4:30 pm and a is the acceleration.
At 4:30 p.m. she looks down at her speedometer and notices that she is going 45 mph.
This means that [tex]v(0) = 45[/tex]
Ten minutes later she looks down at the speedometer again and notices that she is going 55 mph.
This means that [tex]v(10) = 55[/tex]
So
[tex]v(t) = v(0) + at[/tex]
[tex]55 = 45 + 10a[/tex]
[tex]10a = 10[/tex]
[tex]a = 1[/tex]
So
[tex]v(t) = 45 + t[/tex]
When was she moving exactly 50 mph?
This is t minutes after 4:30 p.m.
t is found when v(t) = 50. So
[tex]v(t) = 45 + t[/tex]
[tex]50 = 45 + t[/tex]
[tex]t = 5[/tex]
5 minutes after 4:30 p.m. is 4:35 p.m.
So the correct answer is:
b. 4:35 p.m
Explain the steps involved in adding two rational
expressions.
Answer:
Factor the denominators of each expression to find the LCD.
Rename each expression, if needed, by multiplying by a form of one to get the LCD.
Add the numerators, keeping the denominators the same.
If possible, simplify by factoring the numerator and dividing out common factors from both the numerator and denominator.
Step-by-step explanation:
If the assignment your working on is Explaining How to Add Rational Expressions, this is correct according to edg... Good Luck!!!
A normal deck of cards has 52 cards, consisting of 13 each of four suits: spades, hearts, diamonds, and clubs. Hearts and diamonds are red, while spades and clubs are black. Each suit has an ace, nine cards numbered 2 through 10, and three face cards. The face cards are a jack, a queen, and a king. Answer the following questions for a single card drawn at random from a well-shuffled deck of cards.
What is the probability of drawing a king of any suit?
What is the probability of drawing a face card that is also a spade?
Answer:
a) 1/3
Step-by-step explanation:
a) Probability of drawing a king of any suit
Number of kings = 4
P(king) = 4/52
= 1/13
b) Probability of drawing a face card that is also a spade
Number of face =3
P(king) = 3/ 52
Which step should Richard perform last. WILL MARK BRAINLIEST PLZ HELP. ASAP.
Answer:
81+90
Step-by-step explanation:
9^2 + 2[(5+2)^2 -4]
PEMDAS says parentheses first , working inside out
9^2 + 2[(7)^2 -4]
PEMDAS says parentheses first, doe the exponents inside the parentheses
9^2 + 2[49 -4]
Then the subtraction inside the parentheses
9^2 + 2[45]
Then Exponents
81 +2[45]
Then Multiplication
81+90
Finally add
Answer:
A
Step-by-step explanation:
9² + 2[(5+2)² - 4]
81 + 2[(7)² - 4]
81 + 2[49 - 4]
81 + 2(45)
81 + 90
171
124
8x-9x please help I need it bad
Answer:
-x
Step-by-step explanation:
8x - 9x
Factor out an x
x(8-9)
x (-1)
-x
The pita‑franchise owner has observed in the past that waiting times tend to have a long tail to the right, with most customers served relatively quickly and a few rare customers required to wait a very long time.Is a two‑sample t ‑test appropriate in this setting?The two‑sample t ‑test is appropriate because this is a comparison of the means of two continuous, random variables.The two‑sample t ‑test is not appropriate because the two samples do not have the same size.The two‑sample t ‑test is not appropriate because the sample standard deviations are not equal.The two‑sample t ‑test is not appropriate because the distributions are not normal and the sample sizes are too small.The two‑sample t ‑test is appropriate because the samples are random and contain no outliers, and the populations are normal.
Answer:
The two‑sample t ‑test is not appropriate because the distributions are not normal and the sample sizes are too small.
Step-by-step explanation:
The complete question is:
The owner of a pita franchise with two locations is interested in the average time that customers spend waiting for service at each store. She believes that the average waiting time at the original location is higher than the average waiting time at the new location.
The pita‑franchise owner has observed in the past that waiting times tend to have a long tail to the right, with most customers served relatively quickly and a few rare customers required to wait a very long time.Is a two‑sample t ‑test appropriate in this setting?The two‑sample t ‑test is appropriate because this is a comparison of the means of two continuous, random variables.The two‑sample t ‑test is not appropriate because the two samples do not have the same size.The two‑sample t ‑test is not appropriate because the sample standard deviations are not equal.The two‑sample t ‑test is not appropriate because the distributions are not normal and the sample sizes are too small.The two‑sample t ‑test is appropriate because the samples are random and contain no outliers, and the populations are normal.
For two sample t-test the distributions must be normal. Here the data, as mentioned in the questions is skewed to the right with long waiting times in the past.
Final answer:
The two-sample t-test is not appropriate for the pita-franchise owner's observations because the waiting times are not normally distributed and the sample sizes are small. A test that does not assume normality, like the Mann-Whitney U test, would be more suitable in this situation.
Explanation:
The two-sample t-test is a statistical method used to determine if the means of two groups are significantly different. One key assumption for a two-sample t-test, however, is that the data should come from populations that are approximately normally distributed, especially if the sample sizes are not large. If the assumption of normality is violated and the sample size is small, as indicated by a distribution with a long tail to the right, the two-sample t-test may not be appropriate. To make an informed decision, it would also be necessary to consider the equality of variances, sample sizes, and independence of the samples.
In the context of a pita-franchise with long-tailed waiting times, the distribution is not normal, indicating that the normality assumption is not met. Consequently, using the two-sample t-test might lead to inaccurate results, especially if the sample sizes are too small to compensate for the lack of normality. In such cases, a different test like the Mann-Whitney U test, which does not assume normality, might be a better choice.