Answer:
[tex]x=5[/tex]
Step-by-step explanation:
We have been an equation [tex]x^2-3x-4=x^2-5x+6[/tex]. We are asked to find the solution of our given equation.
[tex]x^2-x^2-3x-4=x^2-x^2-5x+6[/tex]
[tex]-3x-4=-5x+6[/tex]
Adding 5x on both sides of our equation we will get,
[tex]-3x+5x-4=-5x+5x+6[/tex]
[tex]2x-4= 6[/tex]
Upon adding 4 on both sides of our equation we will get,
[tex]2x-4+4= 6+4[/tex]
[tex]2x=10[/tex]
Now, we will divide both sides of our equation by 2.
[tex]\frac{2x}{2}=\frac{10}{2}[/tex]
[tex]x=5[/tex]
Therefore, the solution of our given equation is [tex]x=5[/tex].
The value of x from the expression is 5
Simplifying expressionsGiven the equation x²-3x-4 = x²-5x+6
Collect the like terms
x² - x² -3x +5x -4 -6 = 0
Simplify the result
2x - 10 = 0
Add 10 to both sides
2x - 10 + 10 = 10
2x = 10
x = 5
Hence the value of x from the expression is 5
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How do scientists communicate the results of investigations? A. by publishing articles in scientific journals B. by giving talks at scientific conferences C. by exchanging e-mails D. all of the above
Regression and modeling with functions
What is the solution to the system that is created by the equation y=-x+6 and the graph shown below?
Which of the following is a simpler form of the expression sin (theta)sec(theta)÷ cos(theta)tan(theta)
Answer: [tex]sec \theta[/tex].
Step-by-step explanation: Given expression : [tex]\frac{sin \theta \ sec \theta }{cos \theta \ tan \theta} .[/tex]
We know,
[tex]sec \theta = \frac{1}{cos \theta}[/tex]
[tex]tan \theta = \frac{sin \theta}{cos \theta}[/tex]
Substituting those values in given expression, we get
[tex]\frac{sin \theta \ sec \theta }{cos \theta \ tan \theta} .[/tex] =[tex]\frac{sin \theta\ \frac{1}{cos \theta} } {cos \theta\ \frac{sin \theta}{cos \theta} }[/tex]
= [tex]\frac{sin \theta \ cos \theta}{cos \theta \ cos \theta \ sin \theta}[/tex]
Crossing out [tex]sin \theta \ cos \theta[/tex] from top and bottom, we get
=[tex]\frac{1}{cos \theta }[/tex]
= [tex]sec \theta[/tex].
Answer:
The simplified form of the given expression [tex]\frac{\sin\theta \cdot \sec\theta}{\cos\theta\cdot \tan\theta}[/tex] is [tex]\sec\theta[/tex]
Step-by-step explanation:
Given: Expression [tex]\frac{\sin\theta \cdot \sec\theta}{\cos\theta\cdot \tan\theta}[/tex]
We have to writ the given expression in simplified form.
Consider , The given expression [tex]\frac{\sin\theta \cdot \sec\theta}{\cos\theta\cdot \tan\theta}[/tex]
Since, we know,
[tex]\sec\theta=\frac{1}{\cos\theta}[/tex]
and [tex]\tan\theta=\frac{\sin\theta}{\cos\theta}[/tex]
Substitute, we have,
[tex]\frac{\sin\theta \cdot \sec\theta}{\cos\theta\cdot \tan\theta}=\frac{\sin\theta \cdot\frac{1}{\cos\theta}} {\cos\theta\cdot \frac{\sin\theta}{\cos\theta} }[/tex]
Simplify, we have,
[tex]=\frac{\frac{1}{\cos\theta}} {\cos\theta\cdot \frac{1}{\cos\theta} }[/tex]
Simplify further, we get,
[tex]=\frac{1}{\cos\theta}=\sec\theta[/tex]
Thus, The simplified form of the given expression [tex]\frac{\sin\theta \cdot \sec\theta}{\cos\theta\cdot \tan\theta}[/tex] is [tex]\sec\theta[/tex]
Determine whether a triangle can be formed with the given side lengths. If so, use Heron's formula to find the area of the triangle. a = 240 b = 123 c = 207
Find the possible value or values of n in the quadratic equation 2n^2-7n+6=0
The following set of coordinates most specifically represents which figure?
(−5, 6), (−1, 8), (3, 6), (−1, 4)
The correct answer is C: Rhombus. This is how you find your answer: desmos.com because you just plant in the ordered pair into the program and it plots out the shape for you. The only thing you need to know is your shapes and you should be set.
Find f'(x) for f(x) = −7x2 + 4x − 10.
What number must you add to complete the square x^2+12x=-5
A 12
B 36
C 144
D 6
Answer: B. 36
Step-by-step explanation: Trust me!
Identify the volume and surface area of the sphere
volume = 4/3 x PI x r^3
in terms of pi. multiply r^3 x 4/3 = 18432PI
surface area = 4pir^2
in terms of pi multiply r^2 x 4 = 2304PI
Find the length of arc xpy with a radius of 12m. leave in terms of pi./Users/alymcclellan/Desktop/Screen Shot 2017-07-31 at 10.25.17 PM.png
Which of the following are pairs of congruent segments?
Check all that apply.
If a wheel with a radius of 70 inches spins at a rate of 600 revolutions per minute, find the approximate linear velocity in miles per hour. use pi= 3.14
The function y=-2+5sin(pi/12(x-2)), what is the minimum value?
Answer:
-7
Step-by-step explanation:
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Answer:
-7
Step-by-step explanation:
We are given that a function
[tex]y=-2+5 sin(\frac{\pi}{12}(x-2))[/tex]
We have to find the minimum value of y.
We know that range of sin x is [-1,1].
[tex]-1\leq sin(\frac{\pi}{12}(x-2))\leq 1[/tex]
[tex]-5\leq 5sin(\frac{\pi}{12}(x-2))\leq 5[/tex]
[tex]-5-2\leq -2+5sin(\frac{\pi}{12}(x-2))\leq 5-2[/tex]
[tex]-7\leq -2+5sin(\frac{\pi}{12}(x-2))\leq 3[/tex]
[tex]-7\leq y\leq 3[/tex]
Maximum value of y=3
Minimum value of y=-7
Hence, the minimum value of given function =-7
angie andKenny play online video games angie buys 1 software package and 3 months of game play. Kenny buys 1 software package and 4 months of game play. each software package costs $20. if there total cost is $117 what is the cost of one month game play
Find the midpoint of C and E. Simplify completely.
1. (–4,–3)
2. (0,–3)
3. (–4,–1)
4. (0,–1)
5. none of these
C=(-4,-4)
E = (4,-2)
-4 +4 = 0/2 =0
-4+-2 = -6/2 = -3
(0,-3)
if you roll a normal dice 120 times. How many odd numbers would you expect to get
Answer:
60 odd numbers
Step-by-step explanation:
A normal dice has 6 different sides numbered from 1 to 6, each side has the same probability of appearing when you roll the dice, i.e., in the long run each number will appear 1/6 of the times. We have three different odd numbers in a normal dice each will appear 1/6 of the times in the long run. Therefore, in the long run we hope to get 3/6 = 1/2 of the times an odd number and rolling the dice 120 times will produce about 120(1/2) = 60 odd numbers.
BC is tangent to circle A at B and to circle D at C. What is AD to the nearest tenth? Look at image attached.
Answer:
1. 19.2
Step-by-step explanation:
Please find the attachment.
Since we know that radius is perpendicular to tangent of a circle. So AB will be perpendicular to BC at c and DC is perpendicular to CB at C.
Now we will construct a perpendicular line to radius AB at point E from the center of our small circle. Since we have two right angles at point B and C so we will also have right angles at point E and D as well.
Length of CD is is 7 so length of BE will be 7 as well and length of EA will be 10-7=3. Length of DE will be equal to length BC that is 19.
Now we have formed a right triangle and now we will use Pythagoras theorem to find the length of AD.
[tex](AD)^{2}=(DE)^{2}+(EA)^{2}[/tex]
Upon substituting our values in above formula we will get,
[tex](AD)^{2}=(19)^{2}+(3)^{2}[/tex]
[tex](AD)^{2}=361+9[/tex]
[tex](AD)^{2}=370[/tex]
Upon taking square root of both sides of our equation we will get,
[tex]AD=\sqrt{370}[/tex]
[tex]AD=19.2353840616713448\approx 19.2[/tex]
Therefore, the length of AD will be 19.2 and 1st option is the correct choice.
The proof that ΔQPT ≅ ΔQRT is shown. Given: SP ≅ SR Prove: ΔQPT ≅ ΔQRT What is the missing reason in the proof? Statements Reasons 1. SP ≅ SR 1. given 2. ST ⊥ PR 2. converse of the perpendicular bisector theorem 3. PT ≅ RT 3. ? 4. QT ⊥ PR 4. ST and QT name the same line. 5. QP ≅ QR 5. perpendicular bisector theorem 6. ΔQPT ≅ ΔQRT 6. HL theorem definition of perpendicular bisector definition of congruence reflexive property substitution property
Answer:
A. definition of perpendicular bisector
Step-by-step explanation:
I JUST TOOK THE TEST!!!!!!
Answer:
The correct option is a) perpendicular bisector definition.
Step-by-step explanation:
Given :
Triangle QPT is similar to triangle QRT.
[tex]\rm SP \cong SR[/tex]
To find : Why [tex]\rm PT \cong RT[/tex]
Solution :
According to perpendicular bisector definition -
Perpendicular Bisector is a line or a segment perpendicular to a segment that passes through the midpoint of the segment. Any point on the perpendicular bisector is equidistant from the endpoints of the line segment.
Therefore, [tex]\rm PT \cong RT[/tex]
Hence option a) is correct.
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(08.06)The following data show the height, in inches, of 11 different garden gnomes:
2 9 1 23 3 7 10 2 10 9 7
After removing the outlier, what does the mean absolute deviation of this data set represent?
On average, the height of a garden gnome varies 3.2 inches from the mean of 7 inches.
On average, the height of a garden gnome varies 3.6 inches from the mean of 6 inches.
On average, the height of a garden gnome varies 3.2 inches from the mean of 6 inches.
On average, the height of a garden gnome varies 3.6 inches from the mean of 7 inches.
Answer:
The correct statement is:
On average, the height of a garden gnome varies 3.2 inches from the mean of 6 inches.
Step-by-step explanation:
We are given a data of 11 gardens as:
2 9 1 23 3 7 10 2 10 9 7
Now on removing the outlier i.e. 23 (since it is the very large value as compared to other data points) the entries are as follows:
x |x-x'|
2 4
9 3
1 5
3 3
7 1
10 4
2 4
10 4
9 3
7 1
Now mean of the data is denoted by x' and is calculated as:
[tex]x'=\dfrac{2+9+1+3+7+10+2+10+9+7}{10}\\\\x'=\dfrac{60}{10}\\\\x'=6[/tex]
Hence, Mean(x')=6
Now,
∑ |x-x'|=32
Now mean of the absolute deviation is:
[tex]\dfrac{32}{10}=3.2[/tex]
This means that , On average, the height of a garden gnome varies 3.2 inches from the mean of 6 inches.
What is the value of x 20 35 60 70
What are all the possible 3 digit number combinations 0-9?
Will give brainliest to correct and best explained answer.
You are helping a partner in your group with their problem. What mistake did they make solving the system?
3x+y-9
-2x+y=4
Students work when solving the second equation for y:
Y=2x+4
-2x+(2x+4)=4
-2x+2x+4=4
4=4
The students response is there are indefinitely many solutions and this is not correct. Explain the mistake.
Rewrite the equation in vertex form and then give the vertex of the quadratic equation
For the ordered pair, give three other ordered pairs with θ between −360° and 360° that name the same point. (3, 135°)
Three other ordered pairs with θ between −360° and 360° that name the same point as (3, 135°) are (−243, −45°), (−177, −15°), and (315, 495°).
Explanation:The ordered pairs (−243, −45°), (−177, −15°) and (315, 495°) all name the same point as (3, 135°) with θ between −360° and 360°.
To find these ordered pairs, you can add or subtract 360° to the given angle of 135° while keeping the x-coordinate constant at 3.
For example, you could subtract 360° from 135° to get −225° and combine it with the x-coordinate of 3 to get the ordered pair (3, −225°).
In the triangle below, what ratio is sin θ?
Answer: The required ratio is [tex]\dfrac{12}{13}.[/tex]
Step-by-step explanation: In the given triangle, we are to find the ratio of sinθ.
We know that
in a right-angled triangle, the ratio sine of an angle is given by the length of the perpendicular divided by the length of the hypotenuse.
For the given right-angled triangle, we get
[tex]\sin\theta=\dfrac{perpendicular}{hypotenuse}\\\\\\\Rightarrow \sin\theta=\dfrac{36}{39}\\\\\\\Rightarrow \sin\theta=\dfrac{12}{13}.[/tex]
Thus, the required ratio is [tex]\dfrac{12}{13}.[/tex]
What is the solution to the following system of equations? X-2y=2, x-2y=-2
The given system of equations, x - 2y = 2 and x - 2y = -2, are parallel lines and do not intersect, thus there is no common solution to the system.
Explanation:In mathematics, to find the solution to a system of equations, we generally try to find the values of variables that satisfy all the equations in the system. When looking at the given equations: x - 2y = 2 and x - 2y = -2, we can see that there is something strange. These two equations are equivalent to each other, meaning they represent the same line. This is due to the fact that both equations have the same coefficients for the x and y variables (1 and -2 respectively). So, if two lines are equivalent, they are essentially the same line. This means there are infinitely many solutions which satisfy this system of equations, since all points on the line satisfy both equations. However, if two lines have the same coefficients but different constants (the numbers without the variables), as in our case, then they are parallel and do not intersect, indicating that there's no solution for the system of equations. Therefore, this system of equations has no solution.
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A=1/2(a+b)h solve for h
Difference between algebra 1 and pre-algebra
Answer:
Step-by-step explanation:
The prefix Pre stands for before and algebra is math so pre algebra is informing you about what you will be learning before it actually happens.
Algebra is math for ninth graders that if you fail makes you have to take it until you pass it.