Simplify the square root of 16x^6th power
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Related Questions
You need to bake some banana bread and some zucchini bread for a fund raiser at school. You plan to bake at least 4 and at most 12 loaves of bread. You need at least twice as many loaves of banana bread as zucchini bread.
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For example, if you bake 3 loaves of zucchini bread you must bake 6 loaves of banana bread. 6 + 3 = 9, which is greater than four and less than 12.
The problem is an algebraic translation of a real-life situation using inequalities. The number of loaves, for both banana and zucchini bread, must be between 4 and 12, with banana bread needing to be twice as many as zucchini.
Explanation:This question deals with the concept of inequality and translating word problems into algebraic expressions. In this question, if x represents the number of zucchini bread loaves you bake and y represents the number of banana bread loaves, then the inequalities can be written as:
4 ≤ x + y ≤ 12y ≥ 2xThese inequalities mean that the total number of loaves of bread, including both banana and zucchini, should be no fewer than 4 and no more than 12, and the number of banana bread loaves should be at least twice the number of zucchini bread loaves.
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Solomon is taking out a 5,320 two year loan with an APR of 10.25%. What will the finance charge be for this loan to the nearest dollar?
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Abeer sat a French test and a Geramn test.
In the French test she scored 34 out of 50.
In the German test she scored 14 out of 20.
In which test did she do better?
You must show your working.
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You need to find the LCM of 50 and 20:
It is 100.
50 x 2 = 100
34 x 2 = 68
That makes the score 68 out of 100 for French.
20 x 5 = 100
14 x 5 = 70
That makes the score 70 out of 100 for German.
Therefore, she scored better in German by 2 marks.
Hope This Helps You!
Good Luck :)
- Hannah ❤
Final answer:
After converting Abeer's scores to percentages, it is clear that she did better in the German test with a score of 70%, as opposed to the French test where she scored 68%.
Explanation:
To find out in which test Abeer did better, we need to compare her test scores in percentages. For the French test, Abeer scored 34 out of 50, which we can convert to a percentage by dividing 34 by 50 and then multiplying by 100:
34 ÷ 50 = 0.68 × 100 = 68%
For the German test, she scored 14 out of 20, which we also convert to a percentage:
14 ÷ 20 = 0.70 × 100 = 70%
By comparing these percentages, we can see that Abeer did better in the German test where she scored 70% compared to the French test where she scored 68%.
Joel earns $1,700 per month. If he spends $425 on rent each month, what percent of his income does he spend on rent? A. 20% B. 331/3% C. 40% D. 25%
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425 / 1700 = 0.25
0.25 x 100 = 25.
25% is your answer, letter D.
Rules for Plotting Points:
1) Start at the origin: _________
2) If your x-value is ___________, move right; if it is ___________, move left;
if it is _____, don’t move.
3) If your y-value is ___________, move up; if it is ___________, move down;
if it is _____, don’t move.
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2. Positive, Negative, 0
3. Positive, Negative, 0
I hope this helps.
2) positive, negative, 0
3) positive, negative, 0
Factor the four-term polynomial.
xz + x + yz + y
A. (z - y)(x + 1)
B.(x - y)(z + 1)
C.(x + y)(z + 1)
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(xz+x) + (yz+y)
x(z+1) + y(z+1)
factor out (z+1)
= (z+1)(x+y)
= solution C.
what are the steps for using a compass and a straightedge to construct the bisector of
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ANSWER:
How to construct a Line Segment Bisector AND a Right Angle
using just a compass and a straightedge.
STEP-BY-STEP EXPLANATION:
Steps:
1)Place the compass at one end of line segment.
2)Adjust the compass to slightly longer than half the line segment length
3)Draw arcs above and below the line.
4)Keeping the same compass width, draw arcs from other end of line.
5)Place ruler where the arcs cross, and draw the line segment.
What are the vertices for the final image after applying the composition T−2,4 ◦ RO,180° to ΔXYZ? i need x y and z
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y= (-4, 1)
z=(-6, 1)
The operations on geometric shapes that involves moving, flipping, change of shape, reflection and new shape creation through operations on another shape is known as transformations
The coordinates of the vertices of the image ΔX'Y'Z' after the composite transformation T₍₋₂, ₄₎ [tex]\circ[/tex] R₀ 180° are X'(-4, -1), Y'(-5, 2), and Z'(-6, 1)The reason the above values are correct is as follows:
The given transformation sequence is T₍₋₂, ₄₎ [tex]\circ[/tex] R₀ 180°
Where;
T₍₋₂, ₄₎ = A translation two (2) units to the left and four (4) units upwards
R₀ 180° = A rotation of 180° about the origin
The image and preimage of a 180° rotation transformation about the origin is as follows;
Preimage (x, y) [tex]\underset \longrightarrow {R_o \ 180 ^{\circ} }[/tex]Image(-x, -y)
It is to be noted that the first transformation to be performed in a composite transformation is the transformation to the right
The composite transformation is therefore presented as follows;
Combined; (x, y) [tex]\underset \longrightarrow {T_{-2, \ 4} \circ R_o \ 180 ^{\circ} }[/tex] (-x - 2, -y + 4 )
The coordinates of the vertices points on triangle ΔXYZ are X(2, 5), Y(3, 2), Z(4, 3)
Therefore;
The coordinates of the vertices points on triangle ΔX'Y'Z' after the composite transformations are;
X(2, 5) [tex]\underset \longrightarrow {T_{-2, \ 4} \circ R_o \ 180 ^{\circ} }[/tex] (-2 - 2, -5 + 4 ) = X'(-4, -1)Y(3, 2) [tex]\underset \longrightarrow {T_{-2, \ 4} \circ R_o \ 180 ^{\circ} }[/tex] (-3 - 2, -2 + 4 ) = Y'(-5, 2)Z(4, 3) [tex]\underset \longrightarrow {T_{-2, \ 4} \circ R_o \ 180 ^{\circ} }[/tex] Z(-4 - 2, -3 + 4 ) = Z'(-6, 1)Which gives that the coordinates of the triangle ΔX'Y'Z' after the transformation, T₍₋₂, ₄₎ [tex]\circ[/tex] R₀ 180° are;
X'(-4, -1), Y'(-5, 2), and Z'(-6, 1)
Learn more about composite transformations here:
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What is the parents function of f(x)=3x-5
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[tex]\bf \bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\ \bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\ \left. \qquad \right. \textit{reflection over the x-axis} \\\\ \bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\ \left. \qquad \right. \textit{reflection over the y-axis}[/tex]
[tex]\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\ \left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\ \left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\ \bullet \textit{ vertical shift by }{{ D}}\\ \left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\ \left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\ \bullet \textit{ period of }\frac{2\pi }{{{ B}}}[/tex]
now, that said, A and D are just transformations of it.
[tex]\bf f(x)=\stackrel{A}{3}x\stackrel{D}{-5}\qquad \qquad \stackrel{parent~function}{f(x)=x}[/tex]
You need at least 5000 points to earn a gift card from your bank. You currently have 2700 points. What inequality represents the number of points you need to earn a gift card.
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1300 is less than or equal to x
Which is the symbol < with the line on the bottom
I hope this helps.
YOU'RE WELCOME :D
If the area of a square is 196 square meters, what is its perimeter
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n²=196
n=√196, or 14
Then P=4(14)=56 meters
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Use the information about sports in the photo to explain how inequalities can be used to describe school sports. Include an inequality describing the number of schools needed to add girls’ track and field so that the number is greater than the number of schools currently participating in girls’ basketball.
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The height, h, of a falling object t seconds after it is dropped from a platform 300 feet above the ground is modeled by the function h(t)=300-16t2. Which expression could be used to determine the average rate at which the object falls during the first 3 seconds of its fall.
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[tex] \frac{h(3)-h(0)}{3}=\\ \frac{300-16*3^2-(300-16*0^2)}{3}=\\ \frac{300-16*3^2-(300)}{3}=\\ \frac{-16*3^2}{3}=\\ -16*3=-48[/tex]
Answer:
-96 feet/sec.
Step-by-step explanation:
The height h of a falling object after t second when it is dropped from a platform 300 feet above the ground is modeled by the function h (t) = 300 - 16t²
Then speed or average rate by which the object falls from height h will be [tex]\frac{d[h(t)]}{dt}=\frac{d(300-16t)^{2} }{dt}[/tex]
Speed = [tex]\frac{d}{dt}(300)[/tex] - [tex]\frac{d}{dt}(16t^{2} )[/tex]
= -16 (2t)
Speed = -32t
After 3 second speed of object will be
Speed = -32(3)
= -96 feet/second
Therefore, the average rate will be -96 feet/sec. during the first 3 seconds of its fall.
Dale drove 845 miles in 13 hours. at the same rate, how long would it take him to drive 585 miles?
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Ray's gym charges an initial sign-up fee of $25.00 and a monthly fee of $15.00.
Write a function that describes the gym's total membership fee for x months.
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25 represents the y intercept
15 represents the amount per month that it is increasing
15 times the the number of months plus $25 sign up fee equals total amount paid
What %of 200 miles is 150 miles
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150/200 = .75
Move the decimal point two places to the right to make it a percentage.
.75 = 75%
150 miles is 75% of 250 miles.
Rachel deposited $6,449.82 into a savings account with an interest of 6.9% compounded annually. About how long will it take for the accout to be worth $8,000?
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Answer:
3 years and 3 months.
Step-by-step explanation:
Since, the amount formula in compound interest,
[tex]A= P(1+\frac{r}{100})^t[/tex]
Where,
P = principal amount,
r = rate per period,
t = number of periods,
Here, A = $ 8,000, r = 6.9%, P = $6,449.82,
By substituting the values,
[tex]8000 = 6449.82(1+\frac{6.9}{100})^t[/tex]
[tex]\frac{8000}{6449.82}=(1+\frac{6.9}{100})^t[/tex]
[tex]\ln (\frac{8000}{6449.82})=t\ln(1.069)[/tex]
[tex]\implies t = \frac{\ln (\frac{8000}{6449.82})}{\ln(1.069)}=3.228[/tex]
Hence, it would be take 3.228 years or 3 years and 3 months.
6 ( y + 8 ) = 3 ( 2y - 7 )
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6 ( y + 8 ) = 3 ( 2y - 7 )
6y + 48 = 6y - 21
-48 -48
6y = 6y - 27
+27 +27
33y÷33 = 6y÷33
y=2/11 or 0.18
Hope this helps!
When the federal reserve wants more money to be printed, which agency will be in charge of printing it?
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Answer:
The U.S. Treasury.
Step-by-step explanation:
Which of the f-values satisfy the following inequality? f+8≤12 Choose all answers that apply:
A
f = 4
B
f = 5
C
f = 6
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LINEAR PROGRAMMING help must answer both questions and explain ur answer for brainliest.
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FREE POINTS!!!!!!!!!!!
2+3(8-2)= x
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Answer:
30
Step-by-step explanation:
What is the area of the region of the complex plane defined by $|z|<5$?
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This will be the same area as that inside a circle with a radius of 5
So....the area will be ≈ pi * 5^2 ≈ 25 pi units^2
The area of the region of the complex plane defined by |z|<5 is 78.5 square units.
Explanation:The region of the complex plane defined by |z|<5 is the inside of the circle with radius 5 centered at the origin. To find the area of this region, we can use the formula for the area of a circle, which is A = πr². In this case, the radius is 5, so the area is A = 3.14 × 5² = 78.5 square units.
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The table below represents a linear function f(x) and the equation represents a function g(x): x f(x) −1 −7 0 −1 1 5 g(x) g(x) = 5x − 4 Part A: Write a sentence to compare the slope of the two functions and show the steps you used to determine the slope of f(x) and g(x). (6 points) Part B: Which function has a greater y-intercept? Justify your answer. (4 points)
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Rewriting the table for f(x):
x -1 0 1
f(x) -7 -1 5
Notice that for every increase of one unit in 'x', there are an increase 6 units on f(x). Hence, the gradient of the slope of f(x) is 6.
g(x) = 5x - 4 ⇒ This function follows the general form of the straight line equation, y = mx + c, where 'm' is the gradient and 'c' is the y-intercept.
Hence, the gradient of the slope of g(x) is 5.
The slope of f(x) is steeper than the slope of g(x).
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Question B:
The y-intercept is the value of y where a straight line crosses the y-axis (or when x is zero).
From the table of f(x), the y-intercept is -1 (this is the value of 'y' when 'x' is zero)
From the given function g(x) = 5x - 4, the y-intercept is -4.
f(x) has a greater y-intercept.
find the x and y intercepts -3x-6y=12
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Answer:
x-intercept: -4y-intercept -2Step-by-step explanation:
The x-intercept is found where the graph crosses the x-axis, at y=0. Substituting that into the equation and solving for x, we get ...
-3x = 12
x = 12/-3 = -4 . . . . . x-intercept = -4
The y-intercept is found where the graph crosses the y-axis, at x=0. Substituting that into the equation and solving for y, we get ...
-6y = 12
y = 12/-6 = -2 . . . . . y-intercept = -2
_____
A graphing calculator confirms these values.
Solve. 5t<-15
A) t > 3
B) t < 3
C) t > -3
D) t < -3
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Hope this helps!!
The solution to -5m = -20 is negative.
True or false
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False
a negative number times a negative number would have a positive answer
Which number is a composite number?
17
27
37
47
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Convert the complex number from rectangular form to polar form. z = -14 + 8i
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now.... that angle is correct for that tangent value, however, let's take a peek at our a,b elements, "a" is negative and "b" is positive, that means the x-coordinate is negative and the y-coordinate is positive, that means, the II quadrant, NOT the IV quadrant.
so, let's get the twin of -29.74°, but adding 180° to it, and we'll land at 150.26° or thereabouts, which is in the II quadrant, where our a,b point is at.
[tex]\bf \begin{cases} r=2\sqrt{65}\\ \theta =150.26^o \end{cases}\implies 2\sqrt{65}[cos(150.26^o)+i~sin(150.26^o)][/tex]
Final answer:
To convert z = -14 + 8i to polar form, calculate the magnitude as √(260)≅17, and the argument by adding π to the arctan(8/-14), which accounts for the angle being in the second quadrant. Express the number in polar form using these values.
Explanation:
To convert the complex number z = -14 + 8i from rectangular form to polar form, we start by finding the magnitude (r) and the argument (θ) of the complex number. The magnitude is given by √(x² + y²), which in our case is √((-14)² + 8²) = √(196 + 64) = √(260)≅17. The argument θ is the angle with respect to the positive x-axis which can be found using the arctan function: θ = arctan(y/x). However, since our x is negative and y is positive, our complex number is in the second quadrant, so we need to add π radians (or 180 degrees) to the arctan(y/x) value to obtain the correct argument in the complex plane.
θ = arctan(8/-14) + π ≅ arctan(-4/7) + π. We then get the polar form: z = r(cos(θ) + i sin(θ)) or z = r eˣiθ. Substituting the magnitude and argument into this formula, we find the polar form of the complex number z.
When adding two numbers, such as 123 and 423, care is taken to first line them up and then add like digits. How does expanding this expression to [(1 × 102) + (2 × 101) + (3 × 100)] + [(4 × 102) + (2 × 101) + (3 × 100)] make the operation more like a polynomial addition problem?
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When you add polynomials, you can only combine like terms.
When you add expanded numbers, you can only combine like powers of 10.
123 + 423 =
= (100 + 20 + 3) + (400 + 20 + 3)
= (1 * 10^2 + 2 * 10^1 + 3 * 10^0) + (4 * 10^2 + 2 * 10^1 + 3 * 10^0)
= (1 * 10^2 + 4 * 10^2) + (2 * 10^1 + 2 * 10^1) + (3 * 10^0 + 3 * 10^0)
= 5 * 10^2 + 4 * 10^1 + 6 * 10^0
= 500 + 40 + 6
= 546