Shawna packs blocks at the ABC blocks factory. She packs thousands in crates and tens in stacks. How can she pack an order for 1,250 blocks using just crates and stacks?

Answers

Answer 1

She will pack 1 crate that holds 1,000 and 25 stacks that hold 10.
1,250-1,000=250
250÷10=25

Answer 2

Shawna can pack an order of 1,250 blocks using 1 crate for the thousands and 25 stacks for the tens.

To pack 1,250 blocks using crates and stacks, we need to break down the total number of blocks into thousands and tens:

Step 1: Determine the number of crates (each crate holds 1,000 blocks). 1,250 blocks divided by 1,000 equals 1 crate (1,000 blocks).Step 2: Subtract the blocks already packed in crates: 1,250 - 1,000 = 250 blocks.Step 3: Determine the number of stacks (each stack holds 10 blocks). 250 blocks divided by 10 equals 25 stacks (250 blocks).Therefore, Shawna can pack the order with 1 crate and 25 stacks.

Related Questions

Write an equation in point-slope form of the line through point p(9, -1) with slope -5.

Answers

Sent a picture of the solution to the problem (s).

Josiah invests $360 into an account that accrues 3% interest annually. Assuming no deposits or withdrawals are made, which equation represents the amount of money in Josiah’s account, y, after x years?

Answers

the accumulated value,y

Y=360*(1+0.03)^x

Answer:

Step-by-step explanation:

Beverly made a deposit of $375 into her checking account. Then she withdrew $ 65. The next day, she wrote a check for $ 135. She had $475 before any of these transactions. How much money is in her account now?

Answers

start with 475
add 375(since made deposit)
475+375=850
850-65=785
785+135=$920

what is a fixed charge for borrowing money; usually a percentage of the amount borrowed?

Answers

if you borrow some money from the bank, and they bank says, sure, BUT it'll be for 1 year and with a 11.75% interest.

that simply means, you have to return it in a year, and it has to be that amount PLUS 11.75% of whatever that amount was. the extra amount is the interest.

Find an equation of the tangent line to the bullet-nose curve y=|x|/sqrt(2−x^2) at the point (1,1) I think that square root is what is confusing me on this question

Answers

[tex]\bf y=\cfrac{|x|}{\sqrt{2-x^2}}\qquad \boxed{|x|=\pm\sqrt{x^2}}\qquad y=\cfrac{\sqrt{x^2}}{\sqrt{2-x^2}}\\\\ -------------------------------\\\\ \cfrac{dy}{dx}=\stackrel{quotient~rule}{\cfrac{\frac{1}{2}(x^2)^{-\frac{1}{2}}\cdot 2x\cdot \sqrt{2-x^2}~~-~~\sqrt{x^2}\cdot \frac{1}{2}(2-x^2)^{-\frac{1}{2}}\cdot -2x}{(\sqrt{2-x^2})^2}}[/tex]

[tex]\bf \cfrac{dy}{dx}=\cfrac{\frac{x\sqrt{2-x^2}}{\sqrt{x^2}}~~+~~\frac{x\sqrt{x^2}}{\sqrt{2-x^2}}}{2-x^2}\implies \cfrac{dy}{dx}=\cfrac{\frac{x(2-x^2)~~+~~x(x^2)}{\sqrt{x^2}\sqrt{2-x^2}}}{2-x^2}\\\\\\ \cfrac{dy}{dx}=\cfrac{\frac{2x\underline{-x^3+x^3}}{\sqrt{x^2}\sqrt{2-x^2}}}{2-x^2}\implies \cfrac{dy}{dx}=\cfrac{\frac{2x}{\sqrt{x^2}\sqrt{2-x^2}}}{2-x^2}[/tex]

[tex]\bf \cfrac{dy}{dx}=\cfrac{2x}{\sqrt{x^2}\sqrt{2-x^2}(2-x^2)} \implies \boxed{\cfrac{dy}{dx}=\cfrac{2x}{|x|\sqrt{2-x^2}(2-x^2)}} \\\\\\ \left. \cfrac{dy}{dx} \right|_{1,1}\implies \cfrac{2(1)}{|1|\cdot \sqrt{2-1^2}(2-1^2)}\implies 2\\\\ -------------------------------\\\\ \stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-1=2(x-1)\implies y-1=2x-2 \\\\\\ y=2x-1[/tex]

Determine the number of significant digits in each number and write out the specific significant digits. 405000

Answers

The given number, "405000", has THREE (3) 'significant digits' [also known as: 'significant figures' .].
___________________________________________________________
The THREE (3) significant digits are: "4", "0", and "5" —(the first three digits).
___________________________________________________________

I Need to identify the property that justifies each step to simplify the expression

Answers

What is the expression ? And there are four properties
1) equality of addition , subtraction , multiplication, and division

Walter takes 7/10 of an hour to mow 2/5 of an acre of lawn. At this rate, how many acres will he mow in an hour?

Answers

[tex]\bf \begin{array}{ccll} hours&\stackrel{lawn}{acre}\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ \frac{7}{10}&\frac{2}{5}\\\\ 1&a \end{array}\implies \cfrac{\frac{7}{10}}{1}=\cfrac{\frac{2}{5}}{a}\implies \cfrac{\frac{7}{10}}{\frac{1}{1}}=\cfrac{\frac{2}{5}}{\frac{a}{1}}\implies \cfrac{7}{10}\cdot \cfrac{1}{1}=\cfrac{2}{5}\cdot \cfrac{1}{a} \\\\\\ \cfrac{7}{10}=\cfrac{2}{5a}\implies 35a=20\implies a=\cfrac{20}{35}\implies a=\cfrac{4}{7}[/tex]

Answer:

4/7 acres per hour

Step-by-step explanation:

Let a = {2, 9}, b = {9, 13, 28}, d = {40} and s = sample space = a ∪ b ∪
d. identify bc ∪
a.

Answers

Final answer:

The union of sets a, b, and d (a ∪ b ∪ d) gives you the set {2, 9, 13, 28, 40}. Set 'a' is simply the set containing elements 2 and 9.

Explanation:

To resolve the question, we need to analyze what each symbol means. The ∪ symbol in set theory represents union, meaning everything that is in either of the sets or in both. However, it seems there is a typographical error in your question with 'bc'. As 'c' is not defined, we will proceed by ignoring that particular part and focus on 'a' which is defined.

So, if we're looking to identify a = {2,9}, it simply means the set that contains two elements: 2 and 9.

As your question stands, based on the provided sets, s = a ∪ b ∪ d = {2, 9, 9, 13, 28, 40} but when we simplify the set (since a set does not contain duplicate values), we get s = {2, 9, 13, 28, 40}.

Learn more about Set Theory here:

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#SPJ2

The problem is

2n>14
n=?

Answers

If 2n>14, then
n>14/2
n>7

2n >14
=n>7

so, n can be any number which is greater than 7.

A scientist has four petri dishes of different sizes. Each dish contains a different number of bacteria. Find each population density, to the nearest hundredth. Which statement is true? Dish A has the lowest population density. Dish C has the greatest population density. Dish A and Dish B have approximately the same population density. Dish C and Dish D have approximately the same population density.

Answers

d. Dish C and Dish D have approximately the same population density.

The statement that is True is Option D which says:

"Dish C and Dish D have approximately the same population density."

What is Population Density?

The population density of an area is the Number of Entities in that space/Total Area occupied by the population.

It can also be written as Dp = N/A.

Because the Dp of Dish C and Dish D is approximately 0.68, we can say that they have approximately the same Dp.

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Y=(2x-3)^5(2-x^4)^3 differentiate the function please

Answers

[tex]\bf y=(2x-3)^5(2-x^4)^3\\\\ -------------------------------\\\\ \cfrac{dy}{dx}=\stackrel{\textit{product rule}}{[5(2x-3)^4\cdot 2(2-x^4)3]~~+~~[(2x-3)^5[3(2-x^4)^2(-4x^3)]]} \\\\\\ \cfrac{dy}{dx}=10(2x-3)^4(2-x^4)^3~~-~~12x^3(2x-3)^5(2-x^4)^2 \\\\\\ \cfrac{dy}{dx}=\stackrel{\textit{common factor}}{2(2x-3)^4(2-x^4)^2}~[5(2-x^4)-6x^3(2x-3)] \\\\\\ \cfrac{dy}{dx}=2(2x-3)^4(2-x^4)^2~[10-5x^4-12x^4+18x^3] \\\\\\ \cfrac{dy}{dx}=2(2x-3)^4(2-x^4)^2(10-17x^4+18x^3)[/tex]

how many hours would someone who earns 9.75 per hour have to work to earn 351

Answers

36 hours. This is simple division my dude. 351/9.75 gives you 36. Then to check your answer you would multiply 9.75 by 36 to get 351.

9.75(x) = 351
351/9.75 = 36
x = 36

Thus, 36 hours must be worked in order to get $351 if you have a salary of $9.75

In , is a right angle. find the remaining sides and angles. round your answers to the nearest tenth . show your work. a = 3, c = 1 9

Answers

the answer is either 18.76 or 18.77

Norma and Rene are serving cupcakes at a school party. If they arrange the cupcakes in groups of 2.3.4.5. or 6 they have exactly one cupcake left over. what is the smallest number of cupcakes they could have?

Answers

We are given that there are 5 groups which are:

group of 2

group of 3

group of 4

group of 5

group of 6

and 1 left over

So the smallest number of cupcakes would simply be the sum of all:

smallest number of cupcakes = 2 + 3 + 4 + 5 + 6 + 1

smallest number of cupcakes = 21

long division 573÷15=

Answers

573/15
15 goes int 57 3 times: 45
57-45=12, bring down the 3
15 goes into 123 8 times
123-120=3
573/15= 38 with a remainder of 3
38R3 is the answer

The submarine is traveling at a depth of 152 feet below sea level. The submarine was given instructions to rise 63 feet and then drop 84 feet. Write an expression that describes this situation

Answers

The expression should be -152+63-84

Number 49....I need help

Answers

now, keep in mind that, we'll be using 25mile intervals, notice, that at a cost of 200 bucks, it went for 50 miles, now the charges are just for every 25miles only, so, if you drive 30 miles, you pay for 25miles and if you drive for 49 miles, you still only pay for 25 miles, but because 50/25 is 2 intervals, then if you drive for 50 miles, you're paying for 2 intervals of 25miles, not just one.

now, also let's keep in mind that, when the car was driven for 200 miles, that's 200/25 or 8 25mile intervals, so the 25mile charge kicked in 8 times.

[tex]\bf \stackrel{cost}{y}=\stackrel{fixed~charge}{F}+\stackrel{25mile~intervals}{m}\quad \stackrel{25mile~charge}{x}\implies y=F+mx\\\\ -------------------------------\\\\ \begin{cases} 200=F+2x\implies 200-2x=\boxed{F}\\ 245=F+8x\\ ----------\\ 245=\boxed{200-2x}+8x \end{cases} \\\\\\ 45=6x\implies \cfrac{45}{6}=x\implies \cfrac{15}{2}=x\impliedby \begin{array}{llll} \textit{so the 25mile charge is}\\ \textit{7 bucks and 50cents} \end{array} \\\\\\ [/tex]

[tex]\bf 200=F+2\left( \frac{15}{2} \right)\implies 200=F+15\implies 185=F \\\\\\ \textit{and the \underline{fixed charge} is 185 bucks then, let's check for 450} \\\\\\ \boxed{y=185+\frac{15}{2}x}\qquad \begin{cases} 450~miles\\\\ \cfrac{450}{25}\implies 18~\textit{\underline{25mile intervals}}\\\\ x=18 \end{cases} \\\\\\ y=185+\cfrac{15}{2}\cdot 18\implies y=185+135\implies y=320[/tex]

find the missing values in the ratio table .then write the equivalent ratios .

Answers

The ratio is 3/4
9 shoes to 12 socks
18 shoes to 24 socks

The missing values are 12 and 18.

The ratios are [tex]\dfrac{9}{12}[/tex] and [tex]\dfrac{18}{24}[/tex].

The given table is:

[tex]\begin{center}\begin{tabular}{ c c c c } shoes & 36 & 9 & y \\ socks & 48 & x & 24 \\\end{tabular}\end{center}[/tex]

Since all the columns are pertaining same ratio; thus we have:

[tex]\dfrac{36}{24} = \dfrac{9}{x} = \dfrac{y}{24}\\\\\dfrac{3}{4} = \dfrac{9}{x} = \dfrac{y}{24}\\\\\\or\\\\\dfrac{3}{4} = \dfrac{9}{x}\\\\x = 12\\\\and \\\\\dfrac{3}{4} = \dfrac{y}{24}\\\\y = 18[/tex]

Thus, the missing values x and y are 12 and 18 respectively.

And the are ratios [tex]\dfrac{9}{12}[/tex] and [tex]\dfrac{18}{24}[/tex].

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What is the equation with the difference of 54.57

Answers

100.00-45.43 is equal to 54.57 (as one example).

100.00-45.43 is NOT an equation, however. Please ensure that you have copied down the original problem exactly as presented.

What is 2/3 times 3/4

Answers

2/3(3/4) = 6/12, which simplifies to 1/2

1/2 is your answer

hope this helps

Since you are multiplying, not dividing, the fractions wouldn't need a common denominator... They would stay the same.
[tex] \frac{2}{3} [/tex] × [tex] \frac{3}{4} [/tex]

First, you would cross simplify the equation... But, you don't have to do it now, you can do it at the end (I think this was is easiest).
[tex] \frac{1}{1} [/tex] × [tex] \frac{1}{2} [/tex]

Finally, you would answer the equation.
[tex] \frac{1}{1} [/tex] × [tex] \frac{1}{2} [/tex] = [tex] \frac{1}{2} [/tex]

Your answer would be [tex] \frac{1}{2} [/tex].

I hope this helps!

If an amount of money, called principle, p, is deposited into an account that earns interest at a rate r, compound annually, then in two years that investment will grow to an amount A, given by the formula A=P(1+r)^2. If a principle amount of $5000 grows to $5940.50 in two years, what is the interest rate?

Answers

All u gotta do is plug numbers substituted by the variable into the equation.
A = P(1+r)^t
A = $5940.50
P = $5000
r = ?
t = 2yrs
$5940.50 = $5000(1+r)^t
-------------- --------------------
$5000 $5000
1.1881 = (1+r)^2
sqrt(1.1881) = 1+r
1.09 = 1+r
-1 -1
------- ----
0.09 = r
r = 0.09

Final answer:

By using the compound interest formula A=P(1+r)² and the given values, we find the interest rate to be approximately 0.09, or 9% annually.

Explanation:

To find the interest rate r that grew the principal P from $5000 to $5940.50 over two years with compound interest, we use the formula A=P(1+r)². Here, A is the amount of money accumulated after n years, including interest. We are given that A is $5940.50 and P is $5000.

Let's plug in the values and solve for r:

5940.50 = 5000(1+r)²
1.1881 = (1+r)²

To find r, we take the square root of 1.1881:

Subtracting 1 from both sides to isolate r, we get:

r = 1.09 - 1
r = 0.09

The approximate interest rate is 0.09, which means the annual interest rate is 9%.

It is found that 5 out of every 8 college students like algebra. If a certain college has 4,000 students, how many of them like algebra?

Answers

5 out of 8 turned into a fraction is 5/8. 5/8 turned into a percentage is 62.5%. 62.5% of 4,000 is 2,500. 2,500 students in the college like algebra.
Hope this helped.

to solve this you put it into a ratio
the number of students that like it will go on top and the total college students will be on bottom
5/8
if a college has a total of 4000 students, that will go on bottom and x will be on top
x/4000
to solve for x you would multiply 5 by 4000, and then divide by 8
this would give you x=2500

Two pools are being filled with water. To start, the first pool contains 890 liters of water and the second pool is empty. Water is being added to the first pool at a rate of 20.5 liters per minute. Water is being added to the second pool at a rate of 42.75 liters per minute.

Answers

Let x=amount of time it takes both pipes draining together to empty the pool
First pipe empties at the rate of 540,000/150=3600 liters/min
Second pipe empties at the rate of 540,000/225=2400 liters/min
Together, both pipes empties at the rate of 3600+2400=6000 liters/min, so our equation to solve is:
6000*x=540000

A train moving at a constant speed of 70.0 km/h moves east for 45.0 min, then in a direction 55.0° east of due north for 25.0 min, and then west for 55.0 min. what is the average velocity of the train during this run? (let the +x-axis point towards the east and the +y-axis point towards the north.)

Answers

We know the starting point and the ending point. Find the vector that connects the starting point to the ending point, and then divide this by the total time elapsed (45.0 + 25.0 + 55) min.

The result will be your average velocity (a vector quantity).

To paint a sunset, you make a shade of orange paint using 55 drops of red paint for every 88 drops of yellow paint. If you use 1515 drops of red paint, how many drops of yellow paint would you need?]

Answers

divide 1515 by 55 then multiply by 88 and you get 2424

Write a rule for the linear function in the table.
x; f(x)
2 8
5 17
5 11
11 23

A; f(x) = x + 5
B;f(x) = x + 1
C;f(x) = 2x + 1
D;f(x) = –2x – 1

Answers

the correct answer is A. [tex]$ f(x) = 2x + 1 $.[/tex]

To find the rule for the linear function represented in the table, we can use the formula for a linear function, which is:

[tex]\[ f(x) = mx + b \][/tex]

Where:

- m is the slope of the line

- b is the y-intercept

Given the table:

[tex]\[ \x & : 2, 5, 8, 11 \\f(x) & : 5, 11, 17, 23\end{align}\][/tex]

We can start by finding the slope (m) using the formula:

[tex]\[ m = \frac{{f(x_2) - f(x_1)}}{{x_2 - x_1}} \][/tex]

Let's choose two points from the table, for example, (2, 5) and (5, 11):

[tex]\[ m = \frac{{11 - 5}}{{5 - 2}} \]\[ m = \frac{{6}}{{3}} \]\[ m = 2 \][/tex]

So, we have found that the slope m is 2.

Now, we can use the slope-intercept form of a line to find the y-intercept (b). We can pick any point from the table to do this. Let's use the point (2, 5):

f(x) = mx + b

5 = 2(2) + b

5 = 4 + b

b = 5 - 4

b = 1

So, we have found that the y-intercept b is 1.

Now, we can write the rule for the linear function:

[tex]\[ f(x) = 2x + 1 \][/tex]

Therefore, the correct answer is A. [tex]$ f(x) = 2x + 1 $.[/tex]

The complete question is:

Write a rule for the linear function in the table.

x = 2,5,8,11

f(x) = 5,11,17,23

A. f(x) = 2x + 1

B. f(x) = x + 5

C. f(x) = –2x – 1

D. f(x) = 1/2x+1

Where are the asymptotes of f(x) = tan(4x − π) from x = 0 to x = pi over 2 ?

Answers

[tex]tan(4x- \pi )= \frac{sin(4x- \pi )}{cos(4x- \pi )} [/tex]

The asymptotes are where the graph is undefined. Since: tan(x) =sin(x)/cos(x)
It is where cos(4x-π) = 0

cos(4x-π) = 0 when the inside is -π/2 , π/2 , 3π/2

4x - π = π/2
4x = π/2 + π
4x = 3π/2
x = 3π/8

4x - π = 3π/2
4x = 3π/2 + π
4x = 5π/2
x = 5π/8
This ones outside the interval (5π/8 > π/2) , try -π/2

4x - π = -π/2
4x = -π/2 + π
4x = π/2
x = π/8

Asymptotes are π/8 and 3π/8

Answer:

D 3pi/8 , 5pi/8

Step-by-step explanation:

The science club raised money to clean the beach. They spent $29 on trash bags and $74 on waterproof boots. They still have $47 left. How much did they raise?

Answers

29 + 74 is 103. 103 + 47 is 150. they raised $150

Answer:

They raised $150

Step-by-step explanation:

In order to solve this you just need to reverse the actions that they took in order to get to 47 dollars left, so the total amount they raised will be represented by letter X, so 47 is what is left after spending 29 on trash bags and 74 on waterproof boots, that means that from the total we are withdrawing those amounts and the result will be 47:

Total-Money spent=47

X-29 - 74= 47

x=47+74+29

x=150

So now we know that they originally had 150 dollars and that would be what they raised.

What are the coordinates of the vertices of the triangle under the translation (x, y) mc011-2.jpg (x + 1, y - 4)?

(0, -3), (0, 0), (3, -3)

(-3, 0), (3, -3), (0, -3)

(0, -3), (-3, -3), (-3, 0)

(-3, 0), (0, 0), (-3, -3)

Answers

Original
(-1,1) (-4,1) (-4, 4)

translation (x, y) to (x + 1, y - 4)
(0,-3) (-3,-3) (-3, 0)

answer
(0, -3), (-3, -3), (-3, 0)

it is c :

(0,-3), (-3,-3), (-3,0)

just take the X and Y of the coordinates of the original triangle and substitute it in the given equation (x + 1, y - 4)

try it out yourself it works :)

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