If you could live on the moon through one lunar cycle, how you would experience the phases of the moon?
A ferris wheel of radius 100 feet is rotating at a constant angular speed Ï rad/sec counterclockwise. using a stopwatch, the rider finds it takes 5 seconds to go from the lowest point on the ride to a point q, which is level with the top of a 44 ft pole. assume the lowest point of the ride is 3 feet above ground level.
Angular speed is 0.188 rad/s ,
Tangential speed is 18.8 ft/s ,
Time for one revolution is 33.4 s.
Given :
Ferris wheel of radius 100 ft.
The lowest point of the ride is 3 feet above ground level.
Solution :
Refer the attached diagram for better understanding.
From the diagram we know that,
[tex]\rm y = 100-(44-3)=59 \; ft[/tex]
y = 59 ft
Now applying pythagorean theorem,
[tex]x^2 + 59 ^2= 100^2[/tex]
[tex]x=\sqrt{100^2-59^2}[/tex]
[tex]\rm x = 80.7403\;ft[/tex]
Now to calculate angle [tex]\theta\\[/tex],
[tex]\rm cos\theta = \dfrac{59}{100}=0.59[/tex]
[tex]\rm \theta = 53.84^\circ=0.9397\;radians[/tex]
Now the arc length pq is given by,
[tex]\rm S =pq=0.9397\times100[/tex]
[tex]\rm S = 93.97\; ft[/tex]
Now the angular velocity is given by,
[tex]\omega = \dfrac {0.9397}{5}[/tex]
[tex]\rm \omega = 0.188\;rad/sec[/tex]
Now the tangential velocity is given by,
[tex]\rm v={100}\times{0.188}[/tex]
[tex]\rm v = 18.8\;ft/sec[/tex]
Now the time for a single revolution is given by,
[tex]\rm T = \dfrac{2\pi}{0.188}[/tex]
[tex]\rm T= 33.4\; sec[/tex].
Therefore, angular speed is 0.188 rad/sec , tangential speed is 18.8 ft/s ec and time for one revolution is 33.4 sec.
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A mass weighing 16 pounds is attached to a spring whose spring constant is 49 lb/ft. what is the period of simple harmonic motion?
Final answer:
To find the period of simple harmonic motion for the given mass and spring constant, first convert units, then apply the period formula to get approximately 0.6283 seconds.
Explanation:
The period of simple harmonic motion for a mass-spring system can be calculated using the formula for the period T of a simple harmonic oscillator:
T = 2π√(m/k)
where m is the mass in kilograms, k is the spring constant in newtons per meter (N/m), and π is approximately 3.1416. To use this formula, we must convert the mass from pounds to kilograms and the spring constant from pounds per foot to newtons per meter. The period T is the time it takes for one complete cycle of oscillation.
First, convert 16 pounds to kilograms (1 pound is approximately 0.453592 kilograms):
16 pounds × 0.453592 = 7.257 kilograms
Now, convert the spring constant from lb/ft to N/m (1 lb/ft is approximately 14.5939 N/m):
49 lb/ft × 14.5939 = 715.6011 N/m
Using the conversion values:
T = 2π√(7.257 kg / 715.6011 N/m) = 2π√(0.010139 kg/N·m)
Perform the calculation to determine the period:
T = 2π√(0.010139) ≈ 2π√(0.01) ≈ 2π(0.1) ≈ 0.6283 seconds
Thus, the period of simple harmonic motion for the given mass-spring system is approximately 0.6283 seconds.
How many miles can you get on one tank of gas which holds 18 gallons and you get 22 miles per gallon
The impact of the type of material of which the slope is made on acceleration
The impact of the material type with which the slope is made affects the acceleration. Acceleration will be higher and smoother if the material of the slope surface is smoother as opposed to a texture which is not smooth. Smoother surface allows more acceleration because it will have less friction and resistance. Otherwise the friction will slow the object down for example a grassy ground will have more friction than a well maintained marble floor.
Which activity can substantially increase the activity level of a person's lifestyle? driving a car using an escalator washing dishes walking to school
Answer: walking to school
Physical activity refers to the movement of skeleton muscles which requires the expenditure of energy by the body. This involves daily movement or motion activities an human being perform in order to carry out a desired function. For example, walking to class, cleaning a house and mowing the lawn all these activities involves the movement of muscles. Exercise is also a physical activity which is required to be done to maintain the fitness of the body.
Walking to school will substantially increase the activity level of a person's lifestyle because it favors the movement of muscles and bones and ensures the entire body activity by the expenditure of energy. This will help in booting up of stamina and endurance. Therefore, will make a person physically fit to lead a healthy life style.
I need help with this Physics problem. I've been stuck forever:
Two packages at UPS start sliding down the 18° ramp. Package A has a mass of 5.08 kg and a coefficient of friction of 0.18. Package B has a mass of 10.74 kg and a coefficient of friction of 0.13. How long does it take package A to reach the bottom? (s=2.08 m)
Thanks!
To find the time it takes for Package A to reach the bottom, we need to consider the forces acting on it. The main forces are the gravitational force and the frictional force. By calculating these forces and using Newton's second law and the equation for displacement, we can find the time it takes for Package A to reach the bottom of the ramp.
Explanation:To find the time it takes for Package A to reach the bottom of the ramp, we need to consider the forces acting on it. The two main forces are the gravitational force pulling it down the ramp and the frictional force opposing its motion.
First, let's calculate the gravitational force acting on Package A. The gravitational force is given by the formula Fg = m × g, where m is the mass of the object and g is the acceleration due to gravity. Given that the mass of Package A is 5.08 kg and the acceleration due to gravity is 9.8 m/s², we can calculate Fg = 5.08 kg × 9.8 m/s² = 49.784 N.
The frictional force can be calculated using the formula Ff = μ × Fn, where μ is the coefficient of friction and Fn is the normal force. The normal force can be calculated using the formula Fn = mg × cos(θ), where θ is the angle of the ramp. Given that θ is 18° and g is 9.8 m/s², we can calculate Fn = 5.08 kg × 9.8 m/s² × cos(18°) = 48.583 N. Now we can calculate the frictional force Ff = 0.18 × 48.583 N = 8.745 N.
The net force acting on Package A is the difference between the gravitational force and the frictional force. Fnet = Fg - Ff = 49.784 N - 8.745 N = 41.039 N. We can use Newton's second law, Fnet = ma, to find the acceleration of Package A. Given that the mass of Package A is 5.08 kg, we have 41.039 N = 5.08 kg × a. Solving for a, we find a = 8.08 m/s².
Finally, we can use the equation s = ut + (1/2)at² to find the time it takes for Package A to reach the bottom, where u is the initial velocity (which is 0 in this case) and s is the distance traveled. Given that s = 2.08 m and a = 8.08 m/s², we have 2.08 m = 0 + (1/2) × 8.08 m/s² × t². Solving for t, we find t ≈ 0.32 s.
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A bird is flying due east. Its distance from a tall building is given by x(t)=30.0m+(11.7m/s)t−(0.0450m/s3)t3. A) What is the instantaneous velocity of the bird when t = 8.00 s
To find the bird's instantaneous velocity at t = 8.00 s, the derivative of the position function x(t) is calculated to get the velocity function v(t), and then t = 8.00 s is substituted into this function to obtain the velocity at that instant.
Explanation:The question asks for the instantaneous velocity of a bird at a specific time given its position as a function of time, x(t). To find the instantaneous velocity, we need to take the derivative of the position function with respect to time. Given the position function x(t) = 30.0 m + (11.7 m/s)t - (0.0450 m/s3)t3, the derivative of this function will give us the velocity function v(t).
Therefore, v(t) = dx(t)/dt = 11.7 m/s - 3*(0.0450 m/s3)*t2. Plugging in t = 8.00 s into this velocity function, we get v(8.00 s) = 11.7 m/s - 3*(0.0450 m/s3)*(8.00 s)2, which we can calculate to find the instantaneous velocity at t = 8.00 seconds.
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Water is sold on half-liter bottles. What is the mass, in kg and in g, of the water in such a full bottle?
∵ 1 litre is considered to be 1 kg or 1000 g
∴ half-liter i.e., 1/2 litre should equal to 1/2 kg and 1000/2 g = 500 g
Can the liquid be measured in kg?
Liquids are also measured in kg, but liquids such as gasoline and diesel are supplied in bulk and it is easier to measure the volume dispensed when it is dispensed, so they are measured in litres.
What is the relationship between liter and kilogram?
A liter of water has a mass of almost exactly one kilogram when measured at its maximum density, which occurs at about 4°C. It therefore follows that one thousandth of a liter, called a milliliter (1 ml), of water has a mass of about 1 g; 1000 liters of water have a mass of about 1000 kg (1 ton or megagram).
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As a train accelerates away from a station, it reaches a speed of 4.9 m/s in 5.1 s. If the train's acceleration remains constant, what is its speed after an additional 7.0s has elapsed?
The speed of the rain after accelerating for addition [tex]7\text{ s}[/tex] will be [tex]\boxed{11.62\text{ m/s}}[/tex].
Explanation:
Given:
The speed of the train after [tex]5.1\text{ s}[/tex] is [tex]4.9\text{ m/s}[/tex].
The initial speed of the train is [tex]0\text{ m/s}[/tex].
Concept:
The acceleration of a body is defined as the rate at which the velocity of the body in motion changes every second. If the acceleration of the body is in the direction of motion of the body, the body will be accelerated.
As the train stars from rest and accelerates away from the station, the speed of the train will increase according to the first equation of motion.
The expression for the first equation of motion for the motion of the train is:
[tex]\boxed{v_f=v_i+at}[/tex]
Here, [tex]v_f[/tex] is the final speed of the train, [tex]v_i[/tex] is the initial speed of the train, [tex]a[/tex] is the acceleration of the train and [tex]t[/tex] is the time taken by the train.
Substitute the values of velocity for first [tex]5.1\text{ s}[/tex] of motion of the train.
[tex]\begin{aligned}4.9&=0+a.(5.1)\\a&=\dfrac{4.9}{5.1}\text{ m/s}^2\\&=0.96\text{ m/s}^2\end{aligned}[/tex]
Now, the for the speed of the train after it travels for addition [tex]7.0\text{ s}[/tex] or a total of [tex]12.1\text{ s}[/tex].
[tex]\begin{aligned}v_f&=0+(0.96)(12.1)\text{ m/s}\\v_f&=11.62\text{ m/s}\end{aligned}[/tex]
Thus, The speed of the rain after accelerating for addition [tex]7\text{ s}[/tex] will be [tex]\boxed{11.62\text{ m/s}}[/tex].
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Answer Details:
Grade: Senior School
Subject: Physics
Chapter: Laws of motion
Keywords:
train, accelerates, constant, rest, equation of motion, initial, final, velocity, time taken, addition 7 seconds, acceleration.
In a video game, a ball moving at 0.6 meter/second collides with a wall. After the collision, the velocity of the ball changed to -0.4 meter/second. The collision takes 0.2 seconds to occur. What’s the acceleration of the ball during the collision?
During football practice, a football is kicked with a speed of 22 m/s at an angle of 60.0° relative to the positive x direction. at that instant, an observer rides past the football in a car that moves with a constant speed of 11 m/s in the positive x direction. determine the initial velocity of the ball relative to the observer in the car.
Final answer:
The initial velocity of the football relative to an observer moving at 11 m/s in the positive x direction is solely its vertical component since the horizontal velocities cancel each other out.
Explanation:
To determine the initial velocity of the football relative to the observer in the car, we must consider the velocity of the football and the velocity of the car. The football's velocity (22 m/s) can be broken down into horizontal and vertical components.
The horizontal component (Vx) is calculated using the formula Vx = V * cos(θ), and the vertical component (Vy) is V * sin(θ), where V is the speed of the football and θ is the angle of kick relative to the positive x direction. Given V = 22 m/s and θ = 60°, we get Vx = 22 * cos(60°) and Vy = 22 * sin(60°).
The observer's velocity must be subtracted from the football's horizontal component to determine the relative horizontal velocity (Vx_relative). Therefore, Vx_relative = Vx - velocity of the car.
Now to calculate the total initial velocity of the football relative to the observer, we must combine the relative horizontal velocity with the unchanged vertical component Vectorially.
Equations and calculations:
Vx = V * cos(θ) = 22 * cos(60°) = 11 m/s.Vy = V * sin(θ) = 22 * sin(60°)Vx_relative = Vx - velocity of the car = 11 m/s - 11 m/s = 0 m/s.Thus, the initial velocity relative to the observer combines Vx_relative = 0 m/s and Vy (unchanged).The initial velocity of the football relative to the observer in the car is therefore the same as its vertical component because the horizontal components cancel out.
Which is a transverse wave that requires a medium to move?
If you get the answer, how do you know?
Activation energy can be provided by the kinetic energy of moving molecules. true or false?
Answer:
False
Explanation:
Activation energy is simply the initial energy input which is needed to proceed a chemical reaction. The source of this energy is heat, which is obtained when reactant molecules absorb thermal energy from their surroundings. This thermal energy provides the kinetic energy of moving molecules, by speeding up the motion of the reactant molecules.
Therefore, the correct option is false.
In the circuit shown in the figure above where R1 and R2 have equal resistance values, when switch S1 is closed, what voltage would you measure across R2 with your meter? A. 1 V B. 3 V C. 6 V D. 0 V
The voltage measured across the resistance [tex]R_{2}[/tex] will be [tex]\boxed{3\text{ V}}[/tex].
Explanation:
The two resistances in the given circuit are connected end to end. This connection of the resistors is termed as the series connection of the resistance.
Write the expression for the equivalent resistance of the two resistors.
[tex]R_{eq}=R_{1}+R_{2}[/tex]
Substitute the value of resistance in equation.
[tex]\begin{aligned}R_{eq}&=3\,\Omega+3\,\Omega\\&=6\,\Omega\end{aligned}[/tex]
Since the two batteries are connected in series. So the net voltage in the circuit will be [tex]6\text{ V}[/tex].
Write the expression for the total current drawn from the voltage source.
[tex]\boxed{I=\dfrac{V}{R}}[/tex]
Substitute the values of voltage drop and the total resistance in above expression.
[tex]\begin{aligned}I&=\dfrac{6}{6}\text{ A}\\&=1\text{ A}\end{aligned}[/tex]
The current in a series circuit remains constant through all the elements. Therefore, the current through each resistor will be [tex]1\text{ A}[/tex].
Write the expression for the voltage across the resistance [tex]R_{2}[/tex].
[tex]V'=I\times{R_{2}}[/tex]
Substitute the value of resistance and current in above expression.
[tex]\begin{aligned}V'&=(1\text{ A})\times(3\,\Omega)\\&=3\text{ V}\end{aligned}[/tex]
Thus, the voltage measured across the resistance [tex]R_{2}[/tex] will be [tex]\boxed{3\text{ V}}[/tex].
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Answer Details:
Grade: High School
Subject: Physics
Chapter: Electric Current
Keywords:
circuit, resistance, current, voltage drop, potential difference, measure across, equal resistance, current drawn.
A hot-air balloonist, rising vertically with a constant velocity of magnitude v = 5.00 m/s , releases a sandbag at an instant when the balloon is a height h = 40.0 m above the ground (Figure 1) . After it is released, the sandbag is in free fall. For the questions that follow, take the origin of the coordinate system used for measuring displacements to be at the ground, and upward displacements to be positive.
A) Compute the position of the sandbag at a time 1.05 s after its release.
B)Compute the velocity of the sandbag at a time 1.05 s after its release.
c) How many seconds after its release will the bag strike the ground?
(a). Position of sandbag at time [tex]1.05\text{ s}[/tex] after its release is [tex]\boxed{39.84\text{ m}}[/tex] above the ground.
(b). Velocity of the sandbag after time [tex]1.05\text{ s}[/tex] is [tex]\boxed{5.3\text{ m/s}}[/tex].
(c). The time taken after release the bag to strike the ground is [tex]\boxed{3.41\text{ s}}[/tex].
Further explanation:
Here, all the actions performed is under free fall. So, we will use the kinematic equations of motion for free falling body.
Given:
The velocity of rising of hot air balloon is [tex]5\text{ m/s}[/tex].
Height of hot air balloon when sandbag released is [tex]40\text{ m}[/tex].
Calculation:
Part (a)
Position of sandbag at time [tex]1.05\text{ s}[/tex] after its release.
When sandbag released the hot air balloon was rising up with the velocity of [tex]5\text{ m/s}[/tex].
So, initial velocity of sandbag will be [tex]5\text{ m/s}[/tex] in upward direction.
So, the time taken by the sand bag to reach at its top position is given by,
[tex]\boxed{v = u - gt}[/tex] …… (1)
Here, [tex]v[/tex] is the final velocity, [tex]u[/tex] is the initial velocity, [tex]g[/tex] is the acceleration due to gravity and negative sign is due upward motion of sandbag, [tex]t[/tex] is the time required to reach at top position.
Substitute values for v and u in equation (1).
[tex]\begin{aligned}0&=5-9.8t\\9.8t&=5\\t&=0.51\text{ s}\\\end{aligned}[/tex]
So, the distance travel by sandbag to top position can be calculated as,
[tex]\boxed{{v^2}={u^2}-2g{s_1}}[/tex]
Substitute values for [tex]v[/tex] and u in above equation.
[tex]\begin{aligned}{0^2}&={5^2}-2\times9.8\times{s_1}\\19.6{s_1}&=25\\{s_1}&=1.27\text{ m}\\\end{aligned}[/tex]
After that sandbag will start falling.
The time remain from the given time is,
[tex]\begin{aligned}{t_1}&=1.05-0.51\\{t_1}&=0.54\text{ s}\\\end{aligned}[/tex]
The distance travel by sandbag in [tex]0.54\text{ s}[/tex] in downward direction can be calculated as,
Substitute [tex]0[/tex] for [tex]u[/tex] and [tex]0.54\text{ s}[/tex] for [tex]t[/tex] in above equation.
[tex]\begin{aligned}{s_2}&=0\times0.54+\frac{1}{2}\times9.8{\left({0.54}\right)^2}\\&=1.43\text{ m}\\\end{aligned}[/tex]
So, the position of the sandbag after [tex]1.05\text{ s}[/tex] from the ground can be calculated as,
[tex]\begin{aligned}h&=40+{s_1}-{s_2}\\&=40+1.27-1.43\\&=39.84\text{ m}\\\end{aligned}[/tex]
Part (b)
Velocity of the sandbag after time [tex]1.05\text{ s}[/tex].
The velocity of the sandbag after time [tex]t[/tex] can be calculated as,
[tex]\boxed{v=u+gt}[/tex]
Substitute the values for [tex]u[/tex] and t in above equation.
[tex]\begin{aligned}v&=0+9.8\times0.54\\&=5.3\text{ m/s}\\\end{aligned}[/tex]
Thus, the velocity of the sandbag after time [tex]1.05\text{ s}[/tex] is [tex]\boxed{5.3\text{ m/s}}[/tex].
Part (c)
The time taken after release the bag to strike the ground.
The total distance the top most position of the bag and the ground is,
[tex]\begin{aligned}S&=40+{s_1}\\&=40+1.27\\&=41.27\text{ m}\\\end{aligned}[/tex]
Now, time taken by the bag to strike the ground from its top most position,
[tex]\boxed{S=ut+\dfrac{1}{2}g{t_2}^2}[/tex]
Substitute [tex]41.27{\text{ m}}[/tex] for [tex]S[/tex] and [tex]0[/tex] for [tex]u[/tex] in above equation.
[tex]\begin{aligned}41.27&=0\timest+\dfrac{1}{2}\times9.8{t_2}^2\\41.27&=4.9{t_2}^2\\{t_2}^2&=\dfrac{{41.27}}{{4.9}}\\&=2.9{\text{ s}}\\\end{aligned}[/tex]
Now, the total time taken by bag to strike the ground from the instant of release is,
[tex]\begin{aligned}T&={t_2}+t\\&=2.9+0.51\\&=3.41\text{ s}\\\end{aligned}[/tex]
Thus, the time taken after release the bag to strike the ground is [tex]\boxed{3.41\text{ s}}[/tex].
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Answer detail:
Grade: Senior School
Subject: Physics
Chapter: Kinematics
Keywords:
Hot air balloon, constant velocity, height of, position of sandbag, velocity of sandbag, total time, rising up, 5m/s, 40m, 1.05 s, displacement, balloonist, strike the ground.
This chemical equation represents the burning of methane, but the equation is incomplete. What is the missing coefficient in both the reactants and the products? CH4 + ____O2 → CO2 + ____H2O
Final answer:
The missing coefficients in the chemical equation for the combustion of methane are '2' for both O2 on the reactant side and H2O on the product side, making the balanced equation CH4 + 2O2 → CO2 + 2H2O.
Explanation:
The chemical equation in question represents the combustion of methane, which is a reaction where methane burns in the presence of oxygen to produce carbon dioxide and water. To balance the equation, we look at the number of atoms on both sides of the reaction and adjust them by adding coefficients. The balanced chemical equation is CH4 + 2O2 → CO2 + 2H2O. This indicates that one methane molecule reacts with two oxygen molecules to yield one carbon dioxide molecule and two water molecules. It is important in chemical equations to use the smallest possible whole-number coefficients to maintain the law of conservation of mass. The combustion of methane is an exothermic reaction as it releases energy in the form of heat and light.
During what process does the gases that make up the solution we breathe are separated
To solve this we must be knowing each and every concept related to solution. Therefore, respiration is the process with which gases that make up the solution we breathe are separated.
What is solution?Solution is a homogeneous mixture which contain two component that are solute and solvent . Solute is the amount of component which is in small amount whereas solvent is a component which is in large amount.
Respiration is the process with which gases that make up the solution we breathe are separated. Respiration is a mechanism that occurs inside cells to produce energy by breaking down glucose molecules. The process may be neatly separated into two groups based on the usage of oxygen: anaerobic and aerobic respiration.
Therefore, respiration is the process with which gases that make up the solution we breathe are separated.
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A ball thrown horizontally at 22.2 m/s from the roof of a building lands 36.0 m from the base of the building. how high is the building?
The height of the building is 12.898 meters.
First, we calculate the time of flight using the horizontal distance and the horizontal velocity:
[tex]\[ t = \frac{d}{v_x} \][/tex]
where [tex]\( t \)[/tex] is the time of flight, [tex]\( d \)[/tex] is the horizontal distance (36.0 m) and is the horizontal velocity (22.2 m/s). Plugging in the values:
[tex]\[ t = \frac{36.0 \text{ m}}{22.2 \text{ m/s}} \][/tex]
[tex]\[ t = 1.6216 \text{ s} \][/tex]
Now, we use the time of flight to find the height of the building using the vertical motion equation:
[tex]\[ h = \frac{1}{2} g t^2 \][/tex]
where [tex]\( h \)[/tex] is the height of the building, [tex]\( g \)[/tex] is the acceleration due to gravity (approximately [tex]\( 9.81 \text{ m/s}^2 \)[/tex]), and [tex]\( t \)[/tex] is the time of flight we just calculated. Plugging in the values:
[tex]\[ h = \frac{1}{2} \times 9.81 \text{ m/s}^2 \times (1.6216 \text{ s})^2 \][/tex]
[tex]\[ h = \frac{1}{2} \times 9.81 \text{ m/s}^2 \times 2.6297 \text{ s}^2 \][/tex]
[tex]\[ h = 4.905 \text{ m/s}^2 \times 2.6297 \text{ s}^2 \][/tex]
[tex]\[ h = 12.898 \text{ m} \][/tex]
which matches mandeleevs prediction for the properties of eka-aluminum?
A soccer player is running upfield at 10m/s and comes to a stop in 3 seconds facing the same direction. What is his acceleration?
Answer : His acceleration is, [tex]-3.3m/s^2[/tex]
Explanation :
By the 1st equation of motion,
[tex]v=u+at[/tex] ...........(1)
where,
v = final velocity = 0 m/s
u = initial velocity = 10 m/s
t = time = 3 s
a = acceleration = ?
Now put all the given values in the above equation 1, we get:
[tex]0m/s=10m/s+a\times (3s)[/tex]
[tex]a=-3.3m/s^2[/tex]
Therefore, his acceleration is, [tex]-3.3m/s^2[/tex]
To protect her new two-wheeler, Iroda Bike buys a length of chain. She finds that its linear density is 0.88 lb/ft. If she wants to keep its weight below 1.9 lb, what length of chain is she allowed?
Final answer:
Iroda can buy up to approximately 2.16 feet of chain to keep its weight under 1.9 lb, using the chain's linear density of 0.88 lb/ft to calculate the maximum length.
Explanation:
To calculate the length of chain Iroda Bike can buy without exceeding her weight limit of 1.9 lb, we can use the chain's linear density of 0.88 lb/ft. The length of the chain allowed (L) can be found with the equation:
Weight = (Linear Density) x (Length)
1.9 lb = 0.88 lb/ft x L
Solving for Length (L), we get:
L = 1.9 lb / 0.88 lb/ft = 2.1591 feet
Therefore, Iroda can buy up to approximately 2.16 feet of chain to keep its weight under 1.9 lb.
A fan is to accelerate quiescent air to a velocity of 8 m/s at a rate of 9 m3 /s. determine the minimum power that must be supplied to the fan. take the density of air to be 1.18 kg/m3
Select all that apply.
A scientific theory _____.
is true all the time
is supported by evidence
can evolve over time
is a guess
A runner runs 4875 ft in 6.85 minutes. what is the runnerâs average speed in miles per hour?
Which item is made from an alloy?
steel tray
glass plate
credit card
copper wire
Which body exerts the force that propels the sprinter, the blocks or the sprinter?
The wonders and mysteries of plants provide evidence for:
:creation
:accidental chance
:intelligent design
:evolution
:natural chemical origins
Answer:
Creation and intelligent design
Explanation:
Jeff’s father is installing a do-it-yourself security system at his house. He needs to get a device from his workshop that converts electric energy to sound energy. Which device is Jeff’s father looking for? switch motor buzzer bulb battery
Answer:
buzzer
Explanation: