Sean reads 60 minutes on wednesday
Solution:
Given that,
Let "x" be the number of minutes read on monday
Let "y" be the number of minutes read on tuesday
Let "z" be the number of minutes read on wednesday
He reads 3 times as many minutes on Tuesday as he does on Monday
Number of minutes read on tuesday = 3 times the number of minutes read on monday
y = 3x --------- eqn 1
He reads 4 times as many minutes on Wednesday as he does on Monday
Number of minutes read on wednesday = 4 times the number of minutes read on monday
z = 4x ------- eqn 2
Sean reads 45 minutes on Tuesday
y = 45
Substitute y = 45 in eqn 1
45 = 3x
x = 15
Substitute x = 15 in eqn 2
z = 4(15)
z = 60
Thus he reads 60 minutes on wednesday
Final answer:
Sean reads for 60 minutes on Wednesday, calculated by knowing he reads four times as many minutes on Wednesday as on Monday, and he reads 45 minutes on Tuesday which is three times his Monday reading time.
Explanation:
Since Sean reads 3 times as many minutes on Tuesday as he does on Monday, and he reads 45 minutes on Tuesday, we can determine that he reads 45 minutes ÷ 3 = 15 minutes on Monday. Sean then reads 4 times as many minutes on Wednesday as he does on Monday. So, he must read 15 minutes × 4 = 60 minutes on Wednesday.
At the baseball game, Adam bought 3 hot dogs and 2 sodas for $11. Four innings later, he purchased 2 hot dogs and 3 sodas for $10.25. Wat was the cost of a soda
Answer: the cost of one Soda was $1.75
Step-by-step explanation:
Let x represent the cost of one hot dog.
Let y represent the cost of one Soda.
At the baseball game, Adam bought 3 hot dogs and 2 sodas for $11. It means that
3x + 2y = 11 - - - - - - - - - - 1
In a later time, he purchased 2 hot dogs and 3 sodas for $10.25. It means that
2x + 3y = 10.25 - - - - - - - - -2
Multiplying equation 1 by 2 and equation 2 by 3, it becomes
6x + 4y = 22
6x + 9y = 30.75
Subtracting, it becomes
- 5y = - 8.75
y = - 8.75/- 5
y = 1.75
Substituting y = 1.75 into equation 1, it becomes
3x + 2 × 1.75 = 11
3x + 3.5 = 11
3x = 11 - 3.5 = 7.5
x = 7.5/3 = 2.5
Select the graph of the solution set that would represent the following expression.
3(x - 2) = 5 (x + 1)
Answer:
The solution for the expression is:
[tex]x=-\frac{11}{2}[/tex]
Step-by-step explanation:
Given expression:
[tex]3(x-2)=5(x+1)[/tex]
To graph the solution set.
Solution:
We will first solve for [tex]x[/tex] to find the solution for the expression.
We have:
[tex]3(x-2)=5(x+1)[/tex]
Using distribution:
[tex]3x-6=5x+5[/tex]
Adding 6 both sides.
[tex]3x-6+6=5x+5+6[/tex]
[tex]3x=5x+11[/tex]
Subtracting both sides by [tex]5x[/tex].
[tex]3x-5x=5x-5x+11[/tex]
[tex]-2x=11[/tex]
Dividing both sides by 2.
[tex]\frac{-2x}{-2}=\frac{11}{-2}[/tex]
∴ [tex]x=-\frac{11}{2}[/tex]
The correct graph that represents the solution is given below.
Vicky drew a scale drawing of a city. She used the scale 1 inch : 2 yards. If the actual width of a neighborhood park is 62 yards, how wide is the park in drawing?
Answer:
The park is 31 inches wide in the drawing.
Step-by-step explanation:
Given:
Vicky drew a scale drawing of a city. She used the scale 1 inch : 2 yards.
The actual width of a neighborhood park is 62 yards.
Now, to find the width of park in drawing.
Let the width of park in drawing be [tex]x.[/tex]
The scale drawing of the city is 1 inch : 2 yards.
So, 1 inch is equivalent to 2 yards.
Thus, [tex]x[/tex] is equivalent to 62 yards.
Now, to get the width of park in drawing by using cross multiplication method:
[tex]\frac{1}{2} =\frac{x}{62}[/tex]
By cross multiplying we get:
[tex]62=2x[/tex]
Dividing both sides by 2 we get:
[tex]31=x[/tex]
[tex]x=31\ inches.[/tex]
Therefore, the park is 31 inches wide in the drawing.
Answer:
Answer:
31 inches
Step-by-step explanation:
62 yds divided by 2 equals 31 in
Step-by-step explanation:
If the square root of p2 is an integer greater than 1, which of the following must be true? I. p2 has an odd number of positive factors II. p2 can be expressed as the product of an even number of positive prime factors III. p has an even number of positive factors?
Answer:
Option | and Option || is True
Step-by-step explanation:
Given:
If the square root of [tex]p^{2}[/tex] is an integer greater than 1,
Lets p = 2, 3, 4, 5, 6, 7..........
Solution:
Now we check all option for [tex]p^{2}[/tex]
Option |.
[tex]p^{2}[/tex] has an odd number of positive factors.
Let [tex]p=2[/tex]
The positive factor of [tex]2^{2}=4=1,2,4[/tex]
Number of factor is 3
Let [tex]p=3[/tex]
The positive factor of [tex]3^{2}=9=1,3,9[/tex]
Number of factor is 3
So, [tex]p^{2}[/tex] has an odd number of positive factors.
Therefore, 1st option is true.
Option ||.
[tex]p^{2}[/tex] can be expressed as the product of an even number of positive prime factors
Let [tex]p=2[/tex]
The positive factor of [tex]2^{2}=4=1,2,4[/tex]
[tex]4=2\times 2[/tex]
Let [tex]p=3[/tex]
The positive factor of [tex]3^{2}=9=1,3,9[/tex]
[tex]9=3\times 3[/tex]
So, it is expressed as the product of an even number of positive prime factors,
Therefore, 2nd option is true.
Option |||.
p has an even number of positive factors
Let [tex]p=2[/tex]
Positive factor of [tex]2=1,2[/tex]
Number of factor is 2.
Let [tex]p=4[/tex]
Positive factor of [tex]4=1,2,4[/tex]
Number of factor is 3 that is odd
So, p has also odd number of positive factor.
Therefore, it is false.
Therefore, Option | and Option || is True.
Option ||| is false.
A 16 inch candle is lit and burns at a constant rate of 1.1 inches per hour. Let t represent the never of hours that have elapsed since the candle was lit.
a) write an expression in terms of t that represents the number of incrhs that have burned from the candle since it was lit.
b) write an expression in terms of t that represents the remaining length of the candle (in inches).
Answer:
(a) Number of inches that have burned from the candle since it was lit is (1.1t) inches
(b) The remaining length of the candle is (16 - 1.1t) inches
Step-by-step explanation:
(a). Length of candle before it was lit = 16 inches
Constant rate at which at which candle burns = 1.1 inches per hour
Let t represent the number of hours that have elapsed since the candle was lit
In 1 hour, 1.1 inches of the candle burned
Therefore, in t hours, (1.1t) inches of the candle would have burned since the candle was lit
(b) Remaining length of candle = length of candle before it was lit - length of candle that have burned = 16 inches - 1.1t inches = (16 - 1.1t) inches
The median is:
a. the second quartile
b. the 50th percentile
c. the observation with half of the data on either side of it
d. all of the above
The median is all of the above: the second quartile, the 50th percentile, and the observation with half of the data on either side. It represents the central point of a data set where 50% of the values are below and 50% are above it.
Explanation:The question asks to identify what the median represents in statistical terms. The median is:
a. the second quartile b. the 50th percentile c. the observation with half of the data on either side of it d. all of the aboveThe correct answer is d. all of the above. The median or second quartile (Q₂) is the value that divides the ordered dataset in half. It is also known as the 50th percentile since it implies that 50% of the data lies below this point and 50% lies above it. For example, in a dataset 1, 1, 2, 2, 4, 6, 6.8, 7.2, 8, 8.3, 9, 10, 10, 11.5, the median is 7, meaning that half of the values are smaller than 7 and half of the values are larger than 7.
Find the coordinates of the x- and y-intercepts for an ellipse with the equation (x+1)^2/9 + (y-2)^2/8 = 1
Answer:
x-intercepts: -1±√4.5y-intercepts: 2±8/3Step-by-step explanation:
The x-intercepts are where y = 0.
(x +1)^2/9 +(0 -2)^2/8 = 1
(x +1)^2/9 +1/2 = 1 . . . . . simplify a bit
(x +1)^2 = 9/2 . . . . . . . . .subtract 1/2, multiply by 9; next: square root, add -1
x = -1 ±√4.5 . . . . . x-intercepts
__
The y-intercepts are where x=0.
(0+1)^2/9 +(y-2)^2/8 = 1
1/9 + (y -2)^2/8 = 1 . . . . . simplify a bit
(y -2)^2 = 64/9 . . . . . . . . subtract 1/9, multiply by 8,
y = 2 ±8/3 . . . . . . take the square root, add 2 . . . . y-intercepts
car traveled 576 mi averaging a certain speed. If the car had gone 8 mph faster, the trip would have taken 1 hour less. Find the average speed.
Answer:64mi/hour
Step-by-step explanation:
V=speed × time
V=s×t .....equation (1)
v=576
for taking one hour: t-1
speed is: s+8
From equation(1)
V=(s+8)(t-1)
(s+8)(t-1)=576
Expand the bracket
st-s+8t-8=576
Substitute the value of st which is 576
576-s+8t-8=576
Collect the like terms
-s+8t-8=0
s=8t-8
Subtitude into the value of s
576= (8t-8)×t
576=8t^2-8t
8t^2-8t=576
8t^2-8t-576=0 (divide both by 8)
t^2-t-72=0
By factorization method
Product is (-9 and 8)
(t-9)(t+8)=0
t=9 or t=-8
V=s×t
576=s×9
9s=576
s=576/9
s=64mi/hour
The length of a rectangle is 4 meters less than twice the width. If the area of the rectangle is 240 square meters, find the dimensions.How many meters is the length? How many meters is the width?
Step-by-step explanation:
Let L be the length and W be the width.
The length of a rectangle is 4 meters less than twice the width.
That is
L = 2W - 4
The area of the rectangle is 240 square meters
That is
L x W = 240
(2W - 4) x W = 240
2W² - 4W = 240
W² - 2W - 120 = 0
(W -12 ) (W+10) = 0
W = 12 m or W = -10 m
So width of rectangle is 12 meter
Length = 2 x 12 - 4 = 20 m
Length is 12 meter and width is 20 meter.
An airplane flying into a headwind travels the 1800-mile flying distance between New York City and Albuquerque, New Mexico in 3 hours and 36 minutes. On the return flight, the same distance is traveled in 3 hours and 20 minutes. Find the airspeed of the plane and the speed of the wind, assuming that both remain constant.
airspeed of the plane mph
speed of the wind mph
Answer:
plane speed = 520 mph
wind speed = 20 mph
Step-by-step explanation:
let the speed of the wind be w mph and the speed of the plane be p mph
flying from NY to NM,
time taken = 3 hr 36 min = 3.6 hr
average ground speed = total distance / time taken
= 1800 / 3.6 = 500 mph
since it is a headwind, the plane speed will be slowed down by the head wind, resulting in a lower ground speed.
we can write the following equation:
ground speed = plane speed - wind speed
500 = p - w ------(eq1)
flying from NY to NM (return flight),
time taken = 3 hr 20 min = 3.333 hr
average ground speed = total distance / time taken
= 1800 / 3.333 = 540 mph
on the return trip, the headwind becomes a tailwind, hence the total ground speed would be faster than the plane's air speed , we can write the following equation:
ground speed = plane speed + wind speed
540 = p + w ------(eq2)
with these 2 systems of equations, we can solve for p & w using either substitution of elimination method.
eventually you will end up with
plane speed = 520 mph
wind speed = 20 mph
Speed of airplane is 520 miles per hour and speed of the wind is 20 miles per hour.
Let the speed of an airplane = x miles per minute
And the speed of the wind = y miles per minute
Distance between New York City and Albuquerque = 1800 miles
Airplane covers the distance between New York City and Albuquerque in 3 hours 36 minutes Or 3.6 hours.
In return journey, airplane covers this journey in 3 hours 20 minutes Or 3.33 hours.
Since, airplane takes more time from New York City to Albuquerque,
Therefore, airplane covered this distance against the wind,
And the speed of the airplane against the wind = (x - y) miles per hour
Expression for the speed,
Speed = [tex]\frac{\text{Distance}}{\text{Time}}[/tex]
(x - y) = [tex]\frac{1800}{3.6}[/tex]
x - y = 500 ------- (1)
Speed of airplane in return journey = (x + y) miles per hour
And the equation will be,
x + y = [tex]\frac{1800}{3.33}[/tex]
x + y = 540 ------- (2)
By adding equation (1) and (2),
(x - y) + (x + y) = 500 + 540
2x = 1040
x = 520 miles per hour
From equation (1),
520 - y = 500
y = 20 miles per hour
Therefore, speed of airplane is 520 miles per hour and the speed of wind is 20 miles per hour.
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Your brother has $2000 saved fo a vacation. His airplane ticket is $637. Write and solve an inequality to find out how much he can spend for everything else.
The amount he can spend for everything else is less than or equal to 1363
The inequality is : [tex]s\leq 1363[/tex]
Solution:
Let "s" represent the brother's money to spend
Your brother has $2000 saved for a vacation
His airplane ticket is $637
Write an expression for the total money spent by adding "s" and the price of plane ticket $ 637
We can frame a inequality as:
[tex]s+637\leq 2000[/tex]
Here we have used "less than or equal to" symbol, because he can spent only up to 2000
Solve the inequality for "s"
[tex]s+637\leq 2000\\\\\text{Add -637 on both sides of inequality }\\\\s+637-637\leq 2000-637\\\\s\leq 1363[/tex]
Thus the amount he can spend for everything else is less than or equal to 1363
Find the measure of the exterior angle
Answer:
The answer to your question is a ) 127° b) 80°
Step-by-step explanation:
a) We have to consider that the sum of the interior angles in a triangle equals 180°.
Then,
89 + (5x - 7) + [180 - (14x + 1)] = 180
Simplification
89 + 5x - 7 + 180 - 14x - 1 = 180
5x - 14x = 180 - 89 + 7 - 180 + 1
- 9x = -81
x = -81 / -9
x = 9
Exterior angle = 14(9) + 1
= 127°
b) The process is the same that the previous problem
30 + (4x + 2) + [180 - (8 + 6x)] = 180
Simplification
30 + 4x + 2 + 180 - 8 - 6x = 180
4x - 6x = 180' - 30 - 2 + 8 - 180
-2x = -24
x = -24/-2
x = 12
The measure of the external angle is = 8 + 6(12)
= 8 + 72
= 80°
Can someone please help me with my algebra fraction homework Page's 8,9 and 10. Thank You!
Answer:
8. A
9. C
10. A
Given that lines a and b are parallel, what angles formed on line a when cut by the transversal are congruent with ∠7?
Answer:
∠2 and ∠3
Step-by-step explanation:
Given:
lines a and line b are parallel and cut by transversal.
We need to find the which angles from line a are congruent to ∠7
Solution:
Now we know that;
line a║line b , So by corresponding angle postulate which states that;
"When two parallel lines are cut by a transversal , the resulting corresponding angles are congruent."
so we can say that;
∠2 ≅ ∠6
Also by Vertical angle theorem which states that;
"If two angles are vertical angles, then they are congruent ."
so we can say that;
∠2 ≅ ∠3 and ∠6 ≅ ∠7
So by Transitive Property of Congruence which states that;
When [tex]a \cong b\ \ \ and \ \ \ b\cong c \ \ \ so \ \ \ a\cong c[/tex]
so we can say that;
∠2 ≅ ∠3 ≅ ∠6 ≅ ∠7
Hence measure ∠2 and ∠3 are congruent to measure ∠7.
Answer: it’s C
Step-by-step explanation:
Write y= -3/4 x-6 in standard form using integers.
Answer:
3x + 4y = -24.
Step-by-step explanation:
y= -3/4 x-6
Multiply through by 4:
4y = -3x - 24
3x + 4y = -24.
Ms.Franks drives a maximum of 150 miles per week to and from work. She works 5 days per week. Write an inequality that shows m the number of mies she drives per day
Answer:
Step-by-step explanation:
Let m represent the number of miles that she drives per day.
She works 5 days per week. This means that the total number of miles that she drives in a week would be
5 × m = 5m
Ms.Franks drives a maximum of 150 miles per week to and from work. Therefore, the inequality that shows m the number of miles she drives per day would be
5m ≤ 150
m ≤ 150/5
m ≤ 30
This is timed. Please Help me.
Which is the function g(x) for a restricted domain? g(x) = Negative RootIndex 3 StartRoot x minus 4 EndRoot; x greater-than-or-equal-to –4 g(x) = Negative RootIndex 3 StartRoot x 4 EndRoot + 4; x greater-than-or-equal-to 0 g(x) = Negative RootIndex 3 StartRoot x + 4 EndRoot; x greater-than-or-equal-to –4 g(x) = Negative RootIndex 3 StartRoot x EndRoot minus 4; x greater-than-or-equal-to 0
Answer:
the answer is 2x=9-0
Step-by-step explanation:
put it in the cAC PAPER
Answer:
Its C
Step-by-step explanation:
Correct on ed genuity
g(x) + 3 x+4; x greater or equal to -4
Assigned Media Question Help Determine whether the following probability experiment represents a binomial experiment and explain the reason for your answer. An experimental drug is administered to 180180 randomly selected individuals, with the number of individuals responding favorably recorded.
Answer:
Yes ,it represents a binomial experiment.
Step-by-step explanation:
In order for a probability experiment to represent a binomial experiment ,there are three conditions.
1) There should be a fixed number of trials.
2) Trials should be independent.
3)Each trial can result in two outcomes.
In this experiment ,there is a fixed number of trial ,since it is administered to 180180 individuals.
Outcome on an individual does not affect the outcome of others.
Individuals respond as favorably or not ,so it can be reduced to two outcomes.
All conditions are met, so it can be considered as binomial experiment.
Jane wants to pick out an outfit for the school dance she can choose from 3 pairs of pants 5shirts and 2 pairs of shoes how many differnt outfits does jane have to choose from
Answer:
30
Step-by-step explanation:
we multiply each number. There are 3 pairs of pants 5 shirts and 2 pairs of shoes, so we multiply 3x5x2 to get 30
The number of different outfits that Jane has to choose from is 30
What is the rule of product in combinatorics?If a work A can be done in p ways, and another work B can be done in q ways, then both A and B can be done in p×q ways.
Remember that this count doesn't differentiate between order of doing A first or B first then doing other work after the first work.
Thus, doing A then B is considered same as doing B then A
It is given that:
There are 3 pairs of pants, 5 shirts to choose from and 2 pairs of shoes to choose from.
One outfit would include one-one of these 3 things.
Pants can be chosen in 3 waysShirts can be chosen in 5 waysShoes can be chosen in 2 ways.Thus, they all together can be chosen in 3 × 5 × 2 = 30 ways.
So there are 30 different outfit that Jane has to choose from.
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What is the weight per cm?
Answer:
2/5 g/cm
Step-by-step explanation:
When you want to know "A per B", divide the given quantity of A by the corresponding quantity of B. ("Per" essentially means "divided by".)
It can be convenient to choose table values that make the division easy:
12 g/(30 cm) = 4/10 g/cm = 0.4 g/cm
20 g/(50 cm) = 2/5 g/cm . . . . . . . . . . . . . same as 0.4 g/cm
A uranium mining town reported population declines of 3.2%, 5.2%, and 4.7% for the three successive five-year periods 1985–89, 1990–94, and 1995–99. If the population at the end of 1999 was 9,320:
Answer:
Step-by-step explanation:
Heres the complete question:
A uranium mining town reported population declines of 3.2%, 5.2%, and 4.7% for the three successive five-year periods 1985–89, 1990–94, and 1995–99. If the population at the end of 1999 was 9,320:
How many people lived in the town at the beginning of 1985? (Round your answer to the nearest whole number.)
solution:
Let the population of the town at the beginning of 1985 be P. Then, given that in the first five-year period the population declined by 3.2%, i.e., 0.032, the population of the town at the end of 1989 would be
(1 – 0.032)P = 0.968P.
Again, given that in the second five-year period the population declined by 5.2%, i.e., 0.052, the population of the town at the end of 1994 would be
(1 – 0.052)(0.968P) = 0.948 x 0.968P = 0.917664P.
Finally, given that in the third five-year period the population declined by 4.7%, i.e., 0.047, the population of the town at the end of 1999 would be
(1 – 0.047)(0.917664P) = 0.874533792P.
We are given, 0.874533792P = 9320 or
P = 9320/0.874533792 = 10657.11.
Thus, 10657 people lived in the town at the beginning of 1985
Final answer:
This is a mathematics question requiring the computation of past populations based on given percentage declines and the population at the end of 1999.
Explanation:
The question involves calculating the population of a uranium mining town at a prior date based on given percentage declines over successive five-year periods and the known population at the end of 1999. Since the population at the end of 1999 was 9,320, we work backward using the given percentage declines for each five-year period to estimate the population at the beginning of 1985. The calculation takes into account a 3.2% decline for 1985-89, a 5.2% decline for 1990-94, and a 4.7% decline for 1995-99. By applying these percentage changes in reverse, we can determine the population at the start of 1985.
Using the graph, find the value of y when x = 7. (image down below)
a.
y = 7
c.
y = 2.71
b.
y = 6.1
d.
y = 4.42
I don’t understand how to do this
Step-by-step explanation:
θ is in quadrant IV, so:
sin θ < 0
cos θ > 0
tan θ = sin θ / cos θ < 0
csc θ = 1 / sin θ < 0
sec θ = 1 / cos θ > 0
Without doing any calculations, we can see only the third option fits (in the second option, sin θ / cos θ = -9/18, not -18/9. In the fourth option, csc θ and sec θ are switched).
Let's go ahead and calculate the values. There are several ways to solve this. One way is to use Pythagorean identities (ex., 1 + cot²θ = csc²θ). Another way is to simply draw a triangle in the fourth quadrant.
cot θ = 1 / tan θ, and tan θ = opposite / adjacent. So cot θ = adjacent / opposite. If we draw a triangle with angle θ, where the adjacent side is 9 and the opposite side is -18, then we can use Pythagorean theorem to find the hypotenuse:
c² = a² + b²
c² = (9)² + (-18)²
c = √405
Therefore:
sin θ = -18 / √405
cos θ = 9 / √405
csc θ = √405 / 18
sec θ = √405 / 9
tan θ = -18/9
There are 1200 elephants in a herd. Some have pink and green stripes, some are all pink and some are all blue. One third are pure pink. Is it true that 400 elephants are definitely blue?Why?
Answer: Yes.
The remaining 2/3 elephants left could be a mix of blue and green shared equally.
Step-by-step explanation:
Total number of elephants= 1200
Number of possible colours=3 (blue,green and pink)
Number of pink elephants =1/3 of 1200
Number of pink elephants =1/3×1200
Pink elephants are 400
The remaining fraction will b 1-1/3=2/3
Total number of elephants - number of pink elephants = remaining number of elephants => 1200-400=800
It is true that 400 elephants are definitely blue because the number of elephants remaining is twice 400
Given:
Total number of elephants = 1200
Colours available:
Blue
Pink
Pink & green
Pure Pink = 1/3 of 1200
= 1/3 × 1200
= 1200/3
Pure Pink = 400
Elephants remaining = Total number of elephants - Pure Pink
= 1200 - 400
= 800
Therefore, it is true that 400 elephants are definitely blue because the number of elephants remaining is twice 400
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she has 6 cherry candies, 3 grape candies, and 3 lime candies. If Charlotte randomly pulls one piece of candy out of the bag, what is the probability that it will be cherry? Round to the nearest hundredth.
Answer: [tex]\dfrac{1}{2}[/tex]
Step-by-step explanation:
We know that probability for any event = [tex]\dfrac{\text{Number of favorable outcomes}}{\text{Total outcomes}}[/tex]
Given : Charlotte has 6 cherry candies, 3 grape candies, and 3 lime candies.
I..e Total pieces of candies she has = 6+3+3= 12
Now , If Charlotte randomly pulls one piece of candy out of the bag, what is the probability that it will be cherry is given by :-
[tex]\text{P(cherry)}=\dfrac{\text{Number of cherries}}{\text{Total candies}}\\\\=\dfrac{6}{12}\\\\=\dfrac{1}{2}[/tex]
Hence, the probability that it will be cherry is [tex]\dfrac{1}{2}[/tex] .
The probability that Charlotte will pull a cherry candy out of the bag is 0.50 or 50%.
To determine the probability that Charlotte will randomly pull a cherry candy from the bag, we need to use the basic probability formula:
Probability = (Number of favourable outcomes) / (Total number of possible outcomes)
Step-by-Step Solution
Count the number of cherry candies: Charlotte has 6 cherry candies.Count the total number of candies: She has a total of 6 (cherry) + 3 (grape) + 3 (lime) = 12 candies.Calculate the probability: The probability of drawing a cherry candy is 6 (favourable outcomes) / 12 (total outcomes) = 0.5.Round to the nearest hundredth: Since 0.5 is already a decimal to the nearest hundredth, the final probability is 0.50.Therefore, the probability that Charlotte will pull a cherry candy out of the bag is 0.50 (or 50%).
Working together, Melissa and Jing can mow a lawn in 5 hours. It would take Melissa 8 hours to do the job alone. What is the value of r, the part of the lawn that Jing could complete in 1 hour?A. 0.075.
B. 0.125.
C. 0.375.
D. 0.625.
Answer:
The amount of work completed by Jing in 1 hour is 0.075 which is option A
Step-by-step explanation:
Melissa & Jing can complete the work in 5 hours
This means that the amount of work completed by Melissa & Jing working together in 1 hour is (1÷5) = 0.2
Melissa will do the job in 8 hours, which means that the amount of job completed by Melissa working alone in 1 hour is (1÷8) = 0.125
The amount of work completed by Jing when he works alone in 1 hour will be the difference of amount of work completed by both of them in 1 hour with the amount completed by only Melissa in 1 hour.
There Amount of work completed by Jing in an hour = 0.2 - 0.125 = 0.075
Answer: option A
Step-by-step explanation:
. Patrick, by himself, can paint four rooms in 10 hours. If he hires April to help, they can do the same hob together in 6 hours. If he lets April work alone, how long will it take her to paint four rooms?
Answer: 15 hours
Step-by-step explanation:
Given : Patrick, by himself, can paint four rooms in 10 hours.
i..e Time taken by Patrick to paint the 4 walls = 10 hours.
Since rate of work = [tex]\dfrac{Work}{Time}[/tex]
We consider the entire job as 1.
Then, the rate of work done by Patrick = [tex]\dfrac{1}{10}[/tex]
If he hires April to help, they can do the same hob together in 6 hours.
i.e. the rate of work done by Patrick and April together = [tex]\dfrac{1}{6}[/tex]
Then, the rate of work done by April = rate of work done by Patrick and April together - rate of work done by Patrick
[tex]\dfrac{1}{t}=\dfrac{1}{6}-\dfrac{1}{10}\\\\\Rightarrow\ \dfrac{1}{t}=\dfrac{10-6}{60}=\dfrac{4}{60}\\\\\Rightarrow\ \dfrac{1}{t}=\dfrac{1}{15}\\\\\Rightarrow\ t=15[/tex]
Hence,it will take 15 hours April to paint four rooms .
HELP!! 13 PTS!!!
Write a function of the form f(x) = a/x-h + k
With vertical asymptote is x=-2, horizontal asymptote is y=-5. The graph expands vertically by a factor of 2 and reflects across the x-axis.
Answer:
Step-by-step explanation:
VA= -2
HA= -5
F(x)= 2(x+5)/-(x+2)
Determine whether the underlined value is a parameter or a statistic. A study of 6076 adults in public rest rooms found that 23% did not wash their hands before exiting. Is the value a parameter or a statistic?
A. The value is a parameter because the 6,076 adults in public rest rooms are a sample
B. The value is a parameter because the 6,076 adults in public rest rooms are a population.
C. The value is a statistic because the 6076 adults in public restrooms are a sample
D. The value is a statistic because the 6,076 adults in public rest rooms are a population
Answer:
C
Step-by-step explaination:
A statistic is a data obtained by sampling a population
A sample is a part of a population studied for the purpose of testing of an hypothesis
6076 is a statistical value because it represents a part (sample) of the whole population
The value of 23% is a statistic calculated from a sample of 6076 adults in public restrooms.
Explanation:In this question, the value of 23% represents the proportion of adults in public restrooms who did not wash their hands before exiting. Since this value is calculated from a sample of 6076 adults, it is considered a statistic. A statistic is a number that represents a property of a sample. On the other hand, a parameter is a numerical characteristic of the entire population. In this case, if we had data for all adults in public restrooms, the proportion would be a parameter.
In the sales comparison approach, using comparables that are five and 15 years old when appraising a subject that is 10 years old is an example of what?
Final answer:
In the sales comparison approach, using comparables of different ages requires adjustments for age or vintage to estimate the accurate value of the subject property considering physical and economic differences.
Explanation:
In the sales comparison approach, the use of comparables that vary significantly in age compared to the subject property is an example of adjusting for age or vintage. When appraising a subject property that is 10 years old, by using comparables that are five and 15 years old, an appraiser is attempting to account for differences in physical deterioration, functional obsolescence, and external obsolescence that may exist. A key part of this approach is applying adjustments to the comparables to reflect these differences, thereby arriving at a more accurate value for the subject property.
It is important to ensure that the base year used for comparison is consistent, and adjustments are made for any significant differences in market conditions or property features. The age adjustment is just one of many adjustments that might be made, including location, size, and condition. This process requires careful consideration and professional judgment to ensure that the end value is reflective of the current market.