Round off446,221 to the nearest ten

To determine the dimensions of the rectangle, set up a quadratic equation using the given area and the relationship between the length and width, then solve for the width and consequently the length.

To find the dimensions of the rectangle with an area of 55 yd2 and a length that is 4 yards less than three times the width, we need to set up and solve a quadratic equation. Let the width be x yards. According to the problem, the length is 3x - 4 yards. The area of a rectangle is calculated by multiplying the length by the width, so we have the equation:

x(3x - 4) = 55

Distribute x across the expression:

3x2 - 4x = 55

To solve for x, we need to move all terms to one side of the equation to set it equal to zero:

3x2 - 4x - 55 = 0

This is a quadratic equation that we can solve by factoring, completing the square, or using the quadratic formula. It appears that this equation is not easily factorable; thus, the quadratic formula might be the best approach:

x = ∛{-b ± √{b2 - 4ac}}/2a

In this equation, a = 3, b = -4, and c = -55:

x = ∛{4 ± √{(-4)2 - 4(3)(-55)}}/(2·3)

Simplifying under the square root and solving for x, we get the width of the rectangle, and subsequently, we get the length by substituting x back into 3x - 4.

Answer:

-4< X ≥ 7

Step-by-step explanation:

The sign of < indicates greater than, so that would express numbers greater than -4 and the sign ≥means smaller or less valuable or equal to, so with that you represent equal or less than 7, with that expression you can represent all the real numbers that are greater than -4 and less or equal to 7.

This question is a high school-level mathematics problem involving statistics and data interpretation related to video game scores and soccer game performance.

The question involves analyzing and interpreting different sets of data related to video game scores, hours played, and goals scored in soccer games. This requires an understanding of statistics and mathematical data interpretation techniques. Problems similar to these are often encountered in high school mathematics classes, especially those focusing on statistics and probability.

For example, when dealing with video game scores, a student may need to sumup  numbers, compare totals, or calculate averages. In the case of the hours of video games played, one may need to aggregate data and analyze distributions. With soccer goals per game, the student might have to compute means and assess performance across different groups. Furthermore, the mention of a 'communist model' of grading ties into mathematical concepts of averaging and distribution of data.

These types of problems help students appreciate the practical applications of mathematics in understanding and interpreting real-world scenarios such as video game scoring systems and sports team performance analysis.

Answer:

yoou move the decimal place 3 times to the left

Step-by-step explanation:

Answer:

Move 3 times to the left

Step-by-step explanation:

Answer:

-30, 6

Step-by-step explanation:

6x-5= =30

1x6=6

Answer:

points

Step-by-step explanation:

To find the probability that the proportion of successes in a sample is between 0.18 and 0.23, we approximate the binomial distribution with a normal distribution and calculate the z-scores for the specified values using the distribution N(0.2, sqrt((0.2)(0.8)/200)).

To calculate the probability of the proportion of successes being between 0.18 and 0.23 for a population with a success probability of p = 0.20 and a sample size of n = 200, we use the sampling distribution of the sample proportion.

Firstly, to ensure the use of the normal approximation, we check the conditions: np = 40 and nq = 160, both greater than 5, allowing us to approximate the binomial distribution with a normal distribution where μ = p and σ = sqrt(pq/n).

For n = 200 and p = 0.20, the sampling distribution of the sample proportion p' is approximately N(0.2, sqrt((0.2)(0.8)/200)). Using this distribution, we can calculate the z-scores for 0.18 and 0.23 and then use standard normal distribution tables or software to find the probability that p' falls between these two values.

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Follow below steps:

A patient is to take 4 1/4 tablespoons of medicine per day in 5 equally divided doses. How much medicine is to be taken in each dose?

Convert 4 1/4 tablespoons to a proper fraction, which is 17/4 tablespoons.

Divide 17/4 by 5 to find out how much medicine is to be taken in each dose. This equals 17/4 ÷ 5 = 17/4 × 1/5 = 17/20 tablespoons.

Answer:

$2.84 is your answer

Backward compatible typically means that the new invention would be compatible with previous inventions. So in this case, the new processor is compatible with the older processors. This is intended so that programs made for older processors can be used on the new one without the need for further modification. 

Answer:

bouncing a check

Step-by-step explanation:

Bouncing a check occurs when you write a check for more money than you have in your account.

A bank charges a fee any time you bounce a check.  

The store that you write a bounced check to will also charge you a fee.

Answer:

The answer is 4.2 feet

Step-by-step explanation:

There are 60 different ways to arrange 3 out of 5 books on a shelf with the order mattering. So option (c) is correct.

To calculate the number of ways to arrange 3 out of 5 books with order mattering, we'll use the permutation formula [tex]\( P(n, k) = \frac{{n!}}{{(n-k)!}} \)[/tex], where ( n ) is the total number of items and ( k ) is the number of items to arrange.

In this case, we have ( n = 5 ) books and we want to arrange ( k = 3 ) of

them. So, [tex]\( P(5, 3) = \frac{{5!}}{{(5-3)!}} \)[/tex].

Let's break down the calculation step by step:

Calculate ( 5! ):

[tex]\( 5! = 5 \times 4 \times 3 \times 2 \times 1 = 120 \).[/tex]

Calculate [tex]\( (5-3)! = 2! \)[/tex]:

[tex]\( (5-3)! = 2! = 2 \times 1 = 2 \).[/tex]

Divide [tex]\( 5! \) by \( (5-3)! \)[/tex]:

[tex]\( \frac{{5!}}{{(5-3)!}} = \frac{{120}}{{2}} = 60 \).[/tex]

So, there are 60 different ways to arrange 3 out of 5 books on a shelf with the order mattering.

The correct answer is: c. 60

Complete Question:

In how many ways can you arrange 3 out of 5 books (A, B, C, D, and E) on a shelf, if the order of each arrangement matters (so ABC is different from CBA)?

a. 5

b. 120

c. 60

d. 10

Answer:

Perimeter of one end zone = 126.66 yards.

Step-by-step explanation:

Perimeter of the football field between the pylons = Perimeter of  ABCD in the figure = [tex]306\frac{2}{3}[/tex]

Now in figure we can see, If we remove the length of line segment AB and CD, we will left with sides of end zones AD and BC.

AD + BC = 306.67 - 200 ( each increment by 10 , therefore 10 x 10 + 10 x 10 = 200) = 106.67 yards

In figure, we can see AD = PQ = BC = half of 106.67 yards

So, PQ + AD = 106.67

Now, For one end zone which is of triangular shape, Perimeter = PQ + AD + AP + QD = 106.67 + 10 + 10 = 126.67 yards

Note:- In figure, we can see AP = QD = 10 (∵ increment by 10 yards)

Thus, the perimeter of one end zone is 126.67 yards.

The perimeter of one end zone is 126.67 yards.

To calculate this, we first need to know the total perimeter of the football field. The numbers on the field indicate 10-yard increments, so we can count 10 yards between each pair of pylons. There are 10 pairs of pylons on the field, so the total perimeter of the field is 10 * 10 = 100 yards.

The football field is 120 yards long, including the end zones. This means that each end zone is 10 yards long. Therefore, the perimeter of one end zone is 2 * 10 = 20 yards.

However, the end zones are not straight lines. They are curved, with a radius of 10 yards. This means that the perimeter of one end zone is not just 20 yards. We need to use the formula for the circumference of a circle to find the perimeter of the curved part of the end zone.

The formula for the circumference of a circle is C = 2πr, where C is the circumference, r is the radius, and π is a mathematical constant approximately equal to 3.14159.

Plugging in the values for the radius of the end zone, we get C = 2π(10) ≈ 62.83 yards.

Therefore, the perimeter of one end zone is 20 + 62.83 = 82.83 yards.