Raul received a score of 72 on a history test for which the class mean was 70 with a standard deviation of 9. he received a score of 71 on a biology test for which the class mean was 70 with standard deviation 7. on which test did he do better relative to the rest of the class?

Answers

Answer 1

Final answer:

Raul did better on the history test relative to his classmates, as indicated by a higher z-score of approximately 0.22, compared to 0.14 for the biology test.

Explanation:

To determine on which test Raul did better relative to the rest of the class, we need to calculate the z-scores for Raul's history and biology test results. A z-score is a statistical measurement that describes a value's relationship to the mean of a group of values, measured in terms of standard deviations from the mean. The formula for calculating a z-score is:

z = (X - μ) / σ

where X is the score, μ is the mean, and σ is the standard deviation. Let's apply this to Raul's scores:

For the history test:

z = (72 - 70) / 9 = 2 / 9 ≈ 0.22

For the biology test:

z = (71 - 70) / 7 = 1 / 7 ≈ 0.14

Comparing the two z-scores, we can see that Raul's z-score for history is higher than his z-score for biology. Hence, Raul did better on the history test relative to the rest of the class.

Related Questions

solve x2-8+41=0 for x

Answers

No real solutions or i square root 33

I'm taking x2 is x^2 or x squared

i stands for imaginary number

[tex]Problem: x^2-8+41= 0 \\ x^2+ 33 = ? \\ = 0 - 33 = (-33) \\ The Value Of 'x' is -33 \\ x= \sqrt{-33} [/tex] [tex]There \\ are \\ NO \\ Solution \\ in \\ this \\ equation! [/tex] [tex]Good Luck! [/tex]

Simplify this and show your work :

Answers

-2(x-3) = 5x+1

-2x +6 = 5x+1

subtract 5 x from each side

-7x+6 = 1

subtract 6 from each side

-7x = -5

divide both sides by -7

x = -5/-7 = 5/7

x = 5/7

0.063 written as fraction or a mixed number

Answers

63/1000 as a fraction

solve these equations fast.

(6 + 3i)(6 − 3i) =

(4 − 5i)(4 + 5i) =

(−3 + 8i)(−3 − 8i) =

Answers

(6 + 3i)(6 − 3i) = 45
(4 − 5i)(4 + 5i) = 41
(−3 + 8i)(−3 − 8i) = 73

Answer:

The correct answers are 45,41,73

Step-by-step explanation:

Find the half-life of an element which decays by 3.411% each day. Hint: use y = ab^t.

Answers

a/2=a((100-3.411)/100)^t

a/2=a(0.96589)^t

0.5=0.96589^t

ln(0.5)=t(ln(0.96589))

t=ln(0.5)/ln(0.96589)

t≈19.97 days (to nearest hundredth of a day)

This is about half life of elements with exponential decay.

Half life = 20 years

We are given a decay rate of 3.411% per day.

We are given;

y = ab^(t)

Where;

t is the half life

y = a/2 is the amount of substance remaining after decay

a is amount of substance initially

b = 100% - 3.411% = 96.589% = 0.96589

Thus;

a/2 = a(0.96589)^(t)

a will cancel out to give;

0.5 = 0.96589^(t)

ln (0.5) = t(ln 0.96589)

t = ln(0.5)/ln(0.96589)

t = 19.968 days

This is approximately 20 days.

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What is 35 divided by 768 plz I am really stuck on this one and need some improvement

Answers

35/ 768 = 0.04557

rounded up will be 0.05

hope this helps

In the diagram, PN is the perpendicular bisector of AB and is also the angle bisector of

Answers

The perpendicular bisector is a line segment that is drawn from a vertex of an angle to the midpoint of another line segment creating a right triangle or a 90° angle in the process. Suppose AB is the base segment of the triangle, therefore the perpendicular sector is also the angle bisector of the other angle of the triangle, supposedly angle C. Angle bisector is a line segment that divides the angle into two equal parts. Imagine a line drawn from the top vertex C extended down to the midpoint of line AB. That is the perpendicular and angle bisector.

What are the coordinates of a point on the unit circle if the angle formed by the positive x-axis and the radius is 60?

Answers

Arc length equal to the radius of a circle

please help me!!!
The scale for the map of Missouri is 1 in = 30 mi. On the map, the distance from Springfield to Columbus is about 5.6 in. How far apart are the two cities? Round your answer to the nearest mile.

Answers

if 1 inch = 30 miles

thn multiply 30 x 5.6

30 x 5.6 = 168 miles apart

The actual distance between Springfield and Columbia is 168 miles.

Therefore, the correct answer is:

b. 168 mi

To find the actual distance between Springfield and Columbia, we can use the scale provided in the map.

Given that 1 inch on the map represents 30 miles in real life, and the distance on the map from Springfield to Columbia is 5.6 inches, we can use the following calculation to find the actual distance:

[tex]\[ \text{Actual distance} = \text{Map distance} \times \text{Scale factor} \][/tex]

[tex]\[ \text{Actual distance} = 5.6 \, \text{inches} \times 30 \, \text{miles/inch} \][/tex]

[tex]\[ \text{Actual distance} = 168 \, \text{miles} \][/tex]

So, the actual distance between Springfield and Columbia is 168 miles.

Therefore, the correct answer is:

b. 168 mi

Teachers of two history classes bought tickets to go on a field trip to a local museum. Mr. Lowe paid $115 for 4 adult tickets and 20 student tickets. Mrs. Tucker paid $135.25 for 5 adult tickets and 23 student tickets. Fill in the missing information in the system of equations for the situation. 4a + As = 115 5a + 23s = B

Answers

4a + 20s = 115
5a + 23s = 135.25

Answer with Step-by-step explanation:

Let a represents the cost of one adult ticket

and s represents the cost of one student ticket

Mr. Lowe paid $115 for 4 adult tickets and 20 student tickets.

i.e. 4a+20s=115

Mrs. Tucker paid $135.25 for 5 adult tickets and 23 student tickets.

i.e. 5a+23s=135.25

We get system of equations:

4a+20s=115

5a+23s=135.25

On comparing the above system with

4a + As = 115

5a + 23s = B

We get

A=20

and B=135.25

Elixir of acetaminophen contains 160 my per 5 milliliters. How much acetaminophen is needed to prepare 2 ounces of elixir?

Answers

60 milliliters is equal to two ounces.

if x>2, then x^2-x-6/x^2-4=

Answers

consider the expression [tex] \frac{x^{2} -x-6}{ x^{2} -4} [/tex]

To factorize the expression in the denominator we use difference of squares: [tex]x^{2} -4=x^{2} - 2^{2} =(x-2)(x+2)[/tex]

To factorize [tex]x^{2} -x-6[/tex] we use the following method:

[tex]x^{2} -x-6=(x-a)(x-b)[/tex]

where a, b are 2 numbers such that a+b= -1, the coefficient of x,

and a*b= -6, the constant.

such 2 numbers can be easily checked to be -3 and 2

(-3*2=6, -3+2=-1)

So [tex]x^{2} -x-6=(x-a)(x-b)=(x+3)(x-2)[/tex]

[tex] \frac{x^{2} -x-6}{ x^{2} -4}= \frac{(x+3)(x-2)}{(x-2)(x+2)}= \frac{x+3}{x+2} [/tex]

[tex]\frac{x+3}{x+2}= \frac{x+2+1}{x+2}= \frac{x+2}{x+2}+ \frac{1}{x+2}=1+ \frac{1}{x+2}[/tex]

for x>2

[tex]\frac{1}{x+2}\ \textless \ \frac{1}{2+2}= \frac{1}{4} [/tex]

thus

for x>2,

[tex]1+ \frac{1}{x+2}\ \textless \ 1+ \frac{1}{4}= \frac{5}{4} [/tex]

Answer:

for x>2

[tex]\frac{x^{2} -x-6}{ x^{2} -4} = \frac{x+3}{x+2} \ \textless \ \frac{5}{4} [/tex], (but the expression is never 0)

Find the area of a regular hexagon with apothem 2√3 mm. Round to the nearest whole number.

Answers

Join the center of the hexagon with the 2 base angles.

An equilateral triangle, with side length x, is formed.

(remark: a regular hexagon is made up of 6 equilateral triangles with equal length)

The height [tex]2 \sqrt{3} [/tex] forms 2 congruent right triangles with :

hypotenuse= x, side_1=x/2, and side_2= [tex]2 \sqrt{3} [/tex].

From the pythagorean theorem we have:

[tex] x^{2} = ( \frac{x}{2} )^{2}+(2 \sqrt{3})^{2} [/tex]

[tex]x^{2} = \frac{ x^{2} }{4} +12[/tex]

[tex] \frac{3}{4} x^{2} =12[/tex]

[tex] x^{2} = \frac{12*4}{3}=4*4 [/tex]

thus, x=4.

The area of the triangle is 1/2 * 4 * [tex]2 \sqrt{3}[/tex]=6.93 (mm squared)

The area of the hexagon is 6* the area of the triangle = 42 (mm squared)

Answer: a. 42 (mm squared)

Perry has an opportunity to put $2291 into an investment with an APR of 7.6%. How long will it take his investment to double?

Answers

2×2291=2291 (1+0.076)^t==> 2=(1+0.076)^t
Solve for t
Log (2)=t×log (1.076)
T=log (2)÷log (1.076)
T=9.46 years round your answer to get 9 years

One survey estimates that, on average, the retail value of a mid-sized car decreases by 8% annually. If the retail value of a car is V dollars today, which expression represents the car’s value 1 year later?

A. 0.08V
B. 0.92V
C. 1.08V
D. V-0.08

Answers

[tex]\bf \qquad \textit{Amount for Exponential Decay}\\\\ A=I(1 - r)^t\qquad \begin{cases} A=\textit{accumulated amount}\\ I=\textit{initial amount}\to &V\\ r=rate\to 8\%\to \frac{8}{100}\to &0.08\\ t=\textit{elapsed time}\to &1\\ \end{cases} \\\\\\ A=V(1-0.08)^1\implies A=V(0.92)\implies A=0.92V[/tex]

Answer:

i ggot it right on test

What does the value of the GCF
represent?

Answers

GCF its full form is Greatest Common Factor.
It is found when we have two or more numbers and the largest factor are common in both the numbers.

A math teacher gave her class two tests. 27% of the class passed both tests and 51% of the class passed the first test. What percent of those who passed the first test also passed the second test?

Answers

Assume that there are 100 students in the class.

(Working with numbers is easier than working with percentages).

There are 27 students who passed both tests, and 51 who passed only the first test.
The 27 students who passed both tests are included in the 51 who passed the first test.

We are asked "What percent of those who passed the first test also passed the second test?"

so we are asked "what percent of 51 is 27?"

let 51 be 100%
then 27 is [tex] \frac{27*100}{51} [/tex]%=52.941%

Answer: 52.941%

Question 11(Multiple Choice Worth 5 points) (09.03 MC) A group of people were given a personality test to determine if they were Type A or Type B. The results are shown in the table below: Male Female Type A 55 75 Type B 48 22 Compare P(Male | Type A) with P(Male or Type A).

Answers

The solution would be like this for this specific problem:

[tex]\large P(F) \times P(B )= \frac {97} {200} \times \frac {70}{200} = \frac {97 \times 70} {200 \times 200} = 0.16975[/tex]

You need to compare the results of: P(female or type B) which is written in correct symbols as:

[tex]\large P (F\cup B) [/tex]

and P(female | given type B) which is written in correct symbols as:

[tex]\large P(FlB)

\large (F\cup B)=0.835 - 0.17 = 0.665

\large P (FlB) = 0.314

\large P (F \cup B) \ \textgreater \ P (F|B)[/tex]

So, the correct answer would be: P (Female or Type B) > P (Female | Type B).

Answer:

The answer is P(Female or Type B) > P(Female | Type B)

Step-by-step explanation:

Just took the test.

Also check if you want the answer for males or females before you choose because they are completely different questions

Which of the following fractions is an equivalent fraction in lowest terms to the fraction ? -276/-540

A. 23/45
B. -23/45
C. 69/135
D. -69/135

Answers

23/45 would be the most simplified form of 276/540

[tex]\bf \cfrac{-276}{-540}\quad \begin{cases} 276=2\cdot 2\cdot 3\cdot 23\\ 540={2\cdot 2\cdot 3}\cdot 3\cdot 3\cdot 5 \end{cases}\implies \cfrac{\underline{-2\cdot 2\cdot 3}\cdot 23}{\underline{-2\cdot 2\cdot 3}\cdot 3\cdot 3\cdot 5} \\\\\\ \cfrac{23}{3\cdot 3\cdot 5}\implies \cfrac{23}{45}[/tex]

a=one half bh solve for b

Answers

A = [1/2] bh

1) Multiply both sides by 2 =>

2A = 2 * [1/2] bh

2A = [2/2]bh

2A = bh

2) Divide both sides by h =>

2A/h = bh / h

=> 2A/h = b

Answer: b = 2A/h

The primary goal of using correlational research is to

Answers

The Primary goal of using correlation research is to determine the nature and strength of the association between two measured variables.
Here you must know the terms correlation and variable. The term Correlation is simply defined as the relation between two variables. variables are factors that are liable to vary or change.

Final answer:

Correlational research is used to determine whether there's a relationship between two or more variables without establishing a cause-and-effect connection. It identifies how closely connected variables are by observing them as they naturally occur.

Explanation:

The primary goal of using correlational research is to determine whether a relationship exists between two or more variables, but without establishing a cause-and-effect connection. In this method, a researcher may observe variables as they naturally occur with no intervention or manipulation. By examining the degree to which these variables move together, the researcher can identify how closely connected they are. For example, in psychological studies, a correlational research might be used to investigate the relationship between study habits and academic performance. However, it's critical to note that correlation does not imply causation.

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The directions for mixing an insect spray say to use 1 1/2 ounces of chemical in each gallon of water. How many ounces of chemical should be mixed with 3 4/5 gallons of water? First, estimate the answer to the application problem. Then find the exact answer.

Answers

1 1/2 oz to each gallon.
Total required for 3 4/5 gal is the product of 1 1/2 and 3 4/5, which is approximately 4*1 1/2 = 6 oz.

Exact answer
1 1/2 * 3 4/5
=3/2 * 19/5
=57/10
=5.7 oz

[tex]\bf \begin{array}{ccllll} chemical&water\ gallons\\ -----&-------\\ 1\frac{1}{2}&1\\\\ x&3\frac{4}{5} \end{array}\implies \cfrac{1\frac{1}{2}}{x}=\cfrac{1}{3\frac{4}{5}} \\\\\\ \cfrac{\frac{1\cdot 2+1}{2}}{x}=\cfrac{\frac{1}{1}}{\frac{3\cdot 5+4}{5}}\implies \cfrac{\frac{3}{2}}{\frac{x}{1}}=\cfrac{\frac{1}{1}}{\frac{19}{5}}\implies \cfrac{3}{2}\cdot \cfrac{1}{x}=\cfrac{1}{1}\cdot \cfrac{5}{19}\implies \cfrac{3}{2x}=\cfrac{5}{19}[/tex]

[tex]\bf 3\cdot 19=2x\cdot 5\implies 57=10x\implies \cfrac{57}{10}=x\implies \boxed{5\frac{7}{10}=x} \\\\\\ \cfrac{5\cdot 10+7}{10}\implies \cfrac{57}{10}[/tex]

Joe Popoff, a collection agent, collected 90% of a debt of $5,600.00 that had been overdue 90 days. This collection rate was 5% more than the average collection rate for that agenr. The agent charged 25% commission. What are the net proceeds?

Answers

You are given the debt collected by Joe Popoff with a 90% of a debt of $5,600.00 that had been overdue 90 days. This collection rate was 5% more than the average collection rate for that agent. The agent charged 25% commission. You are asked to find the net proceeds.

Amount collected
= $5,600 * 0.90
= $5,040

Commision
= $5,040 * 0.25
= $1,260

Net Proceeds
= $5,040 - $1,260
= $3,780

Ineed help help me please

Answers

The symbol ₁₂P₉ represents the permutations of 9 quantities out of 12.
By definition,
[tex]_{12}P_{9} = \frac{12!}{(12-9)!} = \frac{12!}{3!} [/tex]

From the calculator,
12! = 479,001,600
3! = 6

Therefore
₁₂P₉ = 479001600/6 = 79,833,600

Answer: 79,833,600

6840 round to nearest hundredth

Answers

6800 is 6840 rounded to the nearest hundredth.

The total cost of an item including sales tax is directly proportional to its price. If the total cost of a $25 item is $25.75, what is the total cost on a $60 item?

Answers

[tex]\bf \qquad \qquad \textit{direct proportional variation}\\\\ \textit{\underline{y} varies directly with \underline{x}}\qquad \qquad y=kx\impliedby \begin{array}{llll} k=constant\ of\\ \qquad variation \end{array}\\\\ -------------------------------\\\\[/tex]

[tex]\bf \textit{cost(c) is directly proportional to price(p)}\qquad c=kp \\\\\\ \textit{we also know that } \begin{cases} p=25\\ c=25.75 \end{cases}\implies 25.75=k25\implies \cfrac{25.75}{25}=k \\\\\\ 1.03=k\qquad thus\qquad \boxed{c=1.03p}\\\\ -------------------------------\\\\ \textit{what's \underline{c} when \underline{p} is 60?}\qquad c=1.03(60)[/tex]

Final answer:

The total cost of a $60 item including a 3% sales tax, which has been derived from a $25 item that costs $25.75 after tax, is $61.80.

Explanation:

The total cost of an item including sales tax is directly proportional to its price.

This means that the sales tax is a constant ratio to its price.

For a $25 item, the total cost (including sales tax) is $25.75. Therefore, the sales tax is $0.75. The tax rate is consequently $0.75/$25 = 0.03 or 3%. Now, if you want to find the total cost of a $60 item, you will apply this tax rate to the price.

Thus, the total cost including tax would be $60 + (3% of $60), or $60 + $1.80 = $61.80.

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How are midsegments of trapezoids and triangles alike? How are they different?

Answers

similarity 1.

Midsegments of a triangle and a trapezoid are alike, because their endpoints, are the midpoints of the sides they touch.

similarity 2.
The length of the midsegment of a trapezoid is (large base+small base)/2

whereas, the length of a midsegment of a triangle is base/2.

difference 1:

Midsegments of triangles and trapezoids are different, because we can draw 3 of them in triangles, but only one in trapezoids.

(we can only join the midpoints of the nonparallel sides of a trapezoid to form its only midsegment.)

Final answer:

In both trapezoids and triangles, midsegments connect the midpoints of two sides. They are parallel to one side and their lengths are determined by the measurements of certain sides. The main difference lies in the number of midsegments each shape can have: a trapezoid can have only one, while a triangle can have three.

Explanation:

In both trapezoids and triangles, a midsegment is a line segment that connects the midpoints of two sides. The similarity between these midsegments lies in their properties. In both cases, the midsegments are parallel to one of the sides of the figure (the base for the trapezoids and the third side for the triangles) and their length is equivalent to the average of the two bases in a trapezoid and half the length of the base in a triangle.

However, the main difference between midsegments of trapezoids and triangles is the number of such segments each figure can have. A trapezoid has only one midsegment, that connects the midpoints of the non-parallel sides, while a triangle can have up to three midsegments, one for each side of the triangle.

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What are the orders of 3,7,9,11,13,17 and 19(mod20)?does 20 have primitive roots?

Answers

[tex]3\equiv3\mod{20}[/tex]
[tex]3^2\equiv9\mod{20}[/tex]
[tex]3^3\equiv27\equiv7\mod{20}[/tex]
[tex]3^4\equiv3\cdot3^3\equiv3\cdot7\equiv21\equiv1\mod{20}[/tex]

[tex]7\equiv7\mod{20}[/tex]
[tex]7^2\equiv49\equiv9\mod{20}[/tex]
[tex]7^3\equiv7\cdot7^2\equiv63\equiv3\mod{20}[/tex]
[tex]7^4\equiv7\cdot7^3\equiv21\equiv1\mod{20}[/tex]

[tex]9\equiv9\mod{20}[/tex]
[tex]9^2\equiv3^4\equiv1\mod{20}[/tex]

[tex]11\equiv11\mod{20}[/tex]
[tex]11^2\equiv121\equiv1\mod{20}[/tex]

[tex]13\equiv-7\equiv13\mod{20}[/tex]
[tex]13^2\equiv169\equiv9\mod{20}[/tex]
[tex]13^3\equiv13\cdot13^2\equiv(-7)9\equiv-63\equiv-3\mod{20}[/tex]
[tex]13^4\equiv13\cdot13^3\equiv(-7)(-3)\equiv21\equiv1\mod{20}[/tex]

[tex]17\equiv-3\equiv17\mod{20}[/tex]
[tex]17^2\equiv(-3)^2\equiv9\mod{20}[/tex]
[tex]17^3\equiv(-3)^3\equiv-27\equiv3\mod{20}[/tex]
[tex]17^4\equiv(-3)^4\equiv81\equiv1\mod{20}[/tex]

[tex]19\equiv-1\equiv19\mod{20}[/tex]
[tex]19^2\equiv19(-1)\equiv-19\equiv1\mod{20}[/tex]

Generally speaking, a number [tex]x[/tex] coprime to [tex]n[/tex] will be a primitive root of [tex]n[/tex] if we have [tex]x^n\equiv x\mod{n}[/tex], or [tex]x^{n-1}\equiv1\mod{n}[/tex]. In other words, if [tex]x[/tex] is of order [tex]n-1[/tex] modulo [tex]n[/tex], then [tex]x[/tex] is a primitive root of [tex]n[/tex].

Since none of these numbers has order 19, it follows that 20 does not have any primitive roots.

if you were to load 225 boxes onto a truck and the boxes are created with each crate containing 9 boxes how many crates would you need to load

Answers

You would need 25 Crates because 225 divided by 9 is 25.

225 / 9 = 25 (Total number of boxes / the number of boxes per crate)

You would need to load 25 crates

Evaluate the integral. (use c for the constant of integration.) sin^2(πx) cos^5(πx) dx

Answers

Using the identity cos^2(A)=1-sin^2(A)
transform
integral of sin^2(πx)cos^5(πx)dx
=integral of sin^2(πx)[1-sin^2(πx)]^2 cos(πx)dx
=integral of [sin^2(πx)-2sin^4(πx)+sin^6(πx)]cos(πx)dx
using the substitution u=sin(πx), du=πcos(πx)dx
=integral of [u^2-2u^4+u^6] (du/π)
=1/π[u^3/3-(2/5)u^5+u^7/7] + C
back substitute u=sin(πx)
=1/π[sin(πx)^3/3-(2/5)sin(πx)^5+sin(πx)^7/7]
or
=sin(πx)^3/3π-2sin(πx)^5/5π+sin(πx)^7/7π

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