QUESTION 18 I want to build a right triangular garden on the side of my house. Find the sides of the triangle if the hypotenuse is 6 feet and the two sides are equal in length.
Answers
Using the Pythagoras theorem
6² = a²+a²
36 = 2a²
18 = a²
a = √18 = 3√2
Related Questions
A quadratic equation is shown below: 3x2 − 15x + 20 = 0 Part A: Describe the solution(s) to the equation by just determining the radicand. Show your work. (5 points) Part B: Solve 3x2 + 5x − 8 = 0 by using an appropriate method. Show the steps of your work, and explain why you chose the method used. (5 points)
Answers
Answer:
[tex]\text{The roots of }3x^2+5x-8=0\text{ are }x=1,\frac{-8}{3}[/tex]
Step-by-step explanation:
[tex]\text{Part A: Given a quadratic equation }3x^2-15x+20=0[/tex]
[tex]\text{Comparing above equation with }ax^2+bx+c=0[/tex]
a=3, b=-15, c=20
Discriminant can be calculated as
[tex]D=b^2-4ac[/tex]
[tex]D=(-15)^2-4(3)(20)=225-240=-15<[/tex]
The roots are imaginary
The solution is
[tex]x=\frac{-b\pm\sqrt{D}}{2a}[/tex]
[tex]x=\frac{-(-15)\pm \sqrt{-15}}{2(3)}=\frac{15\pm\sqrt{15}i}{6}[/tex]
The roots are not real i.e these are imaginary
[tex]\text{Part B: Given a quadratic equation }3x^2+5x-8=0[/tex]
[tex]\text{Comparing above equation with }ax^2+bx+c=0[/tex]
a=3, b=5, c=-8
Discriminant can be calculated as
[tex]D=b^2-4ac[/tex]
[tex]D=(5)^2-4(3)(-8)=25+96=121>0[/tex]
The roots are real
By quadratic formula method
The solution is
[tex]x=\frac{-b\pm\sqrt{D}}{2a}[/tex]
[tex]x=\frac{-5)\pm \sqrt{121}}{2(3)}=\frac{-5\pm 11}{6}[/tex]
[tex]x=1,\frac{-8}{3}[/tex]
which are required roots.
I choose this method because I can get the solutions directly by substituting the values in formula, and I don't have to guess the possible solutions.
Suppose there are 10,000 civilizations in the milky way galaxy. if the civilizations were randomly distributed throughout the disk of the galaxy, about how far (on average) would it be to the nearest civilization? (hint: start by finding the area of the milky way's disk, assuming that it is circular and 100,000 light-years in diameter. then find the average area per civilization, and use the distance across this area to estimate the distance between civilizations.)
Answers
so the radius is 50, 000 lights year, thus
Area of the galaxy is [tex]A(galaxy)= \pi r^{2}= \pi (50,000)^{2}=25*10^{8} \pi [/tex] (lights year square)
The area per civilisation is [tex] \frac{25*10^{8} \pi }{10,000}=25*10^{4} \pi[/tex]
from this result we can assume as a circle of Radius=[tex]25*10^{2}=2500[/tex] lights year.
and assume that each civilisation lives in a planet at the center of these smaller circles.
Check the figure attached.
Planet A, and B are closest in distance. They are each at the center of a circle with radius 2500, and they are tangent. So the distance of A to B is 2500+2500=5000 (light years).
Answer: 5000 light years
Part B: Find an irrational number that is between 9.5 and 9.7. Explain why it is irrational. Include the decimal approximation of the irrational number to the nearest hundredth
Answers
9.678937... (never ending)...it is irrational because it cannot be made into a fraction because it is infinite.
the decimal approximation to the nearest hundredth is : 9.68
A textile corporation buys equivalent with an initial purchase price of $750000. It is estimated its useful life will be 3 years and at that time it's value will be$75000. The total depreciation is depreciation is divided equally among the three years. What is the total amount of depreciation declared each year?
Answers
Wich of the operations ,+,-,x➗are inverse o each other
Answers
Let $f$ be a function such that $f(x+y) = x + f(y)$ for any two real numbers $x$ and $y$. if $f(0) = 2$, then what is $f(2012)?$
Answers
Given:
f(0) = 2
So first of all, we let x = 2012, y = 0:
Then, F(2012) = 2012 + f(0)
Since f(0) = 2, then f(2012) = 2012 + 2 = 2014.
To add, the process that relates an input to an output is called a
function.
There are always three main parts of a
function, namely:
Input
The Relationship
The Output
The classic way of writing a function is "f(x) = ... ".
What goes into the function is put inside parentheses () after the name of the function: So, f(x) shows us the function is called "f", and "x" goes in.
What a function does with the input can be usually seen as:
f(x) = x2 reveals to us that function "f" takes "x" and squares it.
One number is 2 more than 3 times another. their sum is 22. find the numbers. 8, 14
Answers
x = 3y + 2
3y + 2 + y = 22
4y + 2 = 22
4y = 22 - 2
4y = 20
y = 20/4
y = 5
x = 3y + 2 = 3(5) + 2 = 15 + 2 = 17
ur numbers are 5 and 17
Hence the other number is 2 + 3*x.
Their sum is 22;
x + 2 + 3x = 22
4x + 2 = 22
4x = 20
Therefore, x = 5
[ 2 + 3x = 2 + 3*5 = 2+15 = 17 ]
Hence the two numbers are, 5 and 17.
What are the explicit equation and domain for an arithmetic sequence with a first term of 5 and a second term of 2?
an = 5 − 2(n − 1); all integers where n ≥ 1
an = 5 − 2(n − 1); all integers where n ≥ 0
an = 5 − 3(n − 1); all integers where n ≥ 1
an = 5 − 3(n − 1); all integers where n ≥ 0
Answers
The easiest way to answer this is to try all choices, plug in values for the 1st term and 2nd term then check if the answer matches with 5 and 2. (n = 1 and n = 2)
We know that n starts with 1 because that is our 1st term, we do not have 0th term, therefore that leaves us with 2 choices.
Choice 1: an = 5 − 2(n − 1); all integers where n ≥ 1
n = 1
a1 = 5 – 2 (1 – 1) = 5 – 2 (0)
a1 = 5
n = 2
a2 = 5 – 2 (2 – 1) = 5 – 2 (1)
a2 = 3 (FALSE!)
Choice 2: an = 5 − 3(n − 1); all integers where n ≥ 1
n = 1
a1 = 5 – 3 (1 – 1) = 5 – 3 (0)
a1 = 5
n = 2
a2 = 5 – 3 (2 – 1) = 5 – 3 (1)
a2 = 2 (TRUE)
Therefore the correct answer is:
an = 5 − 3(n − 1); all integers where n ≥ 1
Answer:
A is INCORRECT
Step-by-step explanation:
Just finished the FLVS test
33.
In quadrilateral PQRS, the coordinates are P(0, 0), Q(a + c, 0), R(2a + c, b), and S(a, b). How can you use coordinate geometry to show that the diagonals are perpendicular?
Apply the Distance Formula to show that opposite sides to show they are congruent.
Find the slopes of their product is 1.
Apply the Distance Formula to show that opposite sides to show sides are congruent.
Find the slopes and show that their product is -1.
Answers
A technique that can help you to know if two straight lines are perpendicular is is you find their slopes. Let's say the slope of line 1 is m1 and the slope of line 2 is m2. If m1*m2 yields a product of -1, then the lines are perpendicular. This is because if m1 is the negative reciprocal of m2, the lines are perpendicular. But if m1=m2, the lines are parallel, meaning they don't intersect at all.
Therefore, the answer is: Find the slopes and show that their product is -1.
Answer: The answer is (d) Find the slopes and show that their product is -1.
Step-by-step explanation: Given in the question and shown in the attached figure that the vertices of the quadrilateral PQRS are P(0, 0), Q(a + c, 0), R(2a + c, b), and S(a, b). We are asked to use geometry to show that the diagonals PR and QS are perpendicular to each other.
We know that the two lines are perpendicular if the product of their slopes is --1.
So, first we will find the slopes of PR and QS, multiply them, and check the value.If the value is -1, then the diagonals are perpendicular to each other.
That is, if 'm' and 'p' are the slopes of the diagonals PR and QS, and if m × p = -1, then the two diagonals are perpendicular.
Thus, the correct answer is (d).
SOMEONE PLEASE HELP ME WITH MATH! WILL GIVE BRAINLIEST TO FIRST PERSON WHO ANSWERS!!
Solve each system by substitution.
1. -5x-8y=9
y= -3.
2. y= -3x
-6x-2y=3
3. 6x+5y=10
y=-8x+2
4.6x+2y= -6
y= -3x -3
Thank you!
Answers
-5x+24=9
-5x=-15
x=3
(3,-3)
2. -6x-2(-3x)=3
-6x+6x=3
0=3
No solution
3. 6x+5(-8x+2)=10
6x-40x+10=10
-34x+10=10
-34x=0
x=0
y=-8(0)+2
y=2
(0,2)
4. 6x+2(-3x-3)=-6
6x-6x-6=-6
-6=-6
Infinitely many solutions
You have a cone with a radius of 4 ft and a height of 12 ft. What is the height of the triangle formed by a perpendicular cross-section through the cone’s center?
Answers
ABC is the triangle formed by a perpendicular cross-section through the cone's center.
The height OC of this triangle, is the height of the cone.
So the height is equal to 12 ft.
Answer: 12 ft.
An amusement park is installing a new roller coaster. The park intends to charge $5 per adult and $4 per child for each ride. It hopes to earn back more than the $650,000 cost of construction in four years. With the best of weather, the park can provide 125,000 adult rides and 50,000 child rides in one season
Answers
Answer:
Step-by-step explanation:
5x+ 4y greater than or equal to 650,000
500,000
y greater than or equal to 200,00
Answer is : 5x+4y greater than or equal to 650,000
X less than or equal to 500,000
Y is less than or equal to 200,000
Evaluate P(6,2).
A.) 12
B.) 30
C.) 360
Answers
[tex]6P2=\frac{6!}{(6-2)!}=\frac{4!\cdot 5 \cdot 6}{4!}=5 \cdot 6=30[/tex]
The value of the [tex]\rm ^6p_2[/tex] is 30.
We have to determineThe value of P(6,2).
According to the question
The value of the [tex]\rm ^6p_2[/tex] is determined by using permutation.
The probability of selecting an ordered set of 'r' objects from a group of 'n' number of objects.
The order of objects matters in the case of permutation.
The formula to find [tex]\rm ^np_r[/tex] is given by:
[tex]\rm ^np_r = \dfrac{n!}{(n-r)!}[/tex]
Substitute n = 6 and r = 2 in the formula;
[tex]\rm ^np_r = \dfrac{n!}{(n-r)!}\\ \\ \rm ^6p_2 = \dfrac{6!}{(6-2)!}\\ \\ \rm ^6p_2= \dfrac{6 \times 5\times 4 \times 3\times2 \times 1}{4!}\\ \\ ^6p_2= \dfrac{6 \times 5\times 4 \times 3\times2 \times 1}{4\times 3 \times2 \times 1}\\ \\ ^6p_2= 6 \times 5}\\ \\ ^6p_2= 30[/tex]
Hence, The value of the [tex]\rm ^6p_2[/tex] is 30.
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Juanita’s boss told her that once she has worked with the company for 10 years, her salary will be increased to 3 times what she makes now plus $2,000. If s represents her original salary, which expression represents what her salary will be after 10 years at the company?
Answers
A=3s+2000
Answer:3s+2,000
Step-by-step explanation:
The function h(x) = x2 + 14x + 41 represents a parabola.
Part A: Rewrite the function in vertex form by completing the square. Show your work. (6 points)
Part B: Determine the vertex and indicate whether it is a maximum or a minimum on the graph. How do you know? (2 points)
Part C: Determine the axis of symmetry for h(x). (2 points)
Answers
[tex]h(x)= x^{2} +14x+41[/tex]
The first step of completing the square is writing the expression [tex] x^{2} +14x[/tex] as [tex] (x+7)^{2} [/tex] which expands to [tex] x^{2} +14x+49[/tex].
We have the first two terms exactly the same with the function we start with: [tex] x^{2} [/tex] and [tex]14x[/tex] but we need to add/subtract from the last term, 49, to obtain 41.
So the second step is to subtract -8 from the expression [tex] x^{2} +14x+49[/tex]
The function in completing the square form is
[tex]h(x)= (x+7)^{2}-8 [/tex]
Part B:
The vertex is obtained by equating the expression in the bracket from part A to zero
[tex]x+7=0[/tex]
[tex]x=-7[/tex]
It means the curve has a turning point at x = -7
This vertex is a minimum since the function will make a U-shape.
A quadratic function [tex]a x^{2} +bx+c[/tex] can either make U-shape or ∩-shape depends on the value of the constant [tex]a[/tex] that goes with [tex] x^{2} [/tex]. When [tex]a[/tex] is (+), the curve is U-shape. When [tex]a[/tex] (-), the curve is ∩-shape
Part C:
The symmetry line of the curve will pass through the vertex, hence the symmetry line is [tex]x=-7[/tex]
This function is shown in the diagram below
to anyone who may be a lil' sus, the previous answer is correct.
The sum of the first and third of three consecutive even integers is 136. find the three even integers.
Answers
For example: 42 + 46 = 88. I have to increase the numbers more to reach 136. Suppose: 82 + 86 = 168. That exceeded 136. So, it must be between 46 and 82. Suppose again: 66 + 70 = 136. Therefore, the sequence of the consecutive even integers are 66, 68, and 70.
The sum of the first and third even integers is 136. By setting up an equation and solving for x, where x is the first integer, we determine that the consecutive even integers are 66, 68, and 70.
The problem asks us to find three consecutive even integers where the sum of the first and third integer is 136. Let's denote the first integer as x, the second integer as x + 2, and the third integer as x + 4 (since consecutive even numbers have a difference of 2). To solve for the values, we set up the equation x + (x + 4) = 136. Simplifying, we get 2x + 4 = 136. Subtracting 4 from both sides gives us 2x = 132. Dividing both sides by 2, we find out that x = 66. So, the first integer is 66, the second integer is 66 + 2 = 68, and the third integer is 66 + 4 = 70.
Therefore, the three consecutive even integers are 66, 68, and 70.
if 6a-8b=0 and c=12b, the ratio of a to c is equivalent to the ratio of one to what number?
Answers
3a=4b
c=3*(4b)=3*3a=9a
c=9a
How can you eliminate the fraction from each side of the equation to make finding the
solution easier?
The equation is 1/2(x - 4) = 1/3x + 2
Answers
1/2(x - 4) = 1/3x + 2
multiply by : 6
3(x-4) = 2x +4
solution easier:
3x -12 = 2x +4
3x - 2x = 12+4
x = 16
The coordinates of the midpoint of GH¯¯¯¯¯¯¯¯are M(−2, 5) and the coordinates of one endpoint are H(−3, 7) .
The coordinates of the other endpoint are ( __ , __ )
Answers
(-3 + x) / 2 = -2
-3 + x = -4
x = -4 + 3
x = -1
(7 + y) / 2 = 5
7 + y = 10
y = 10 - 7
y = 3
so the other endpoint is (-1,3)
The coordinate point of the other endpoint, G is (-1, 3)
The given parameters;
the midpoint = M(-2, 5)
one end point = H(-3,7)
To find:
the coordinate point of the other endpoint, GLet the coordinate point of the other endpoint = G(x, y)
The coordinate point of the other endpoint, G will be calculated using midpoint formula.
[tex]M(-2, 5) =( \frac{x + (-3)}{2} , \frac{y + 7}{2} )\\\\-2 = \frac{x - 3}{2} \ \ \ and \ \ 5 = \frac{y+ 7}{2} \\\\x-3 = 2(-2)\\\\x - 3 = -4\\\\x = -4 + 3\\\\x = -1\\\\y+ 7 = 2(5)\\\\y + 7 = 10\\\\y = 10 -7\\\\y = 3\\\\G= (-1, 3)[/tex]
Thus, the coordinate point of the other endpoint, G is (-1, 3)
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Oh Plz help - I can't handle this one :)
Answers
b: 4*0.5*1.5 = 3, 6*4 = 24, 6*2.5 = 15.5, 15.5*2 + 3*2 + 24 = 61m^2
c: 5.2*3.5 = 18.2, 2.4*3.5 = 8.4, 2.4*5.2 = 12.48, 12.48*2 + 8.4*2 + 18.2*2 = 78.16ft^2
A bit late but hope it helps
A = 2 *pi * r^2 + 2 * pi * r * h
A = 2 * pi * 5^2 + 2 * pi * 5 * 10
A = 50 pi + 100 pi
A = 150 * pi cm^2 (Exact Answer)
A = 471 cm^2 (Decimal Approximation)
b. A(triangles)
A = (1/2) * b * h * 2
A = (1/2) * 4 * 1.5 * 2
A = 6 m^2
A(rectangles)
A = L * W
A = 4 * 6 + 2.5 * 6 * 2
A = 24 + 30
A = 54 m^2
Total area = 6 + 54 = 60 m^2
c. A(rectangular prism)
A = 2LW + 2LH + 2WH
A = 2 * 5.2*2.4 + 2 * 5.2 * 3.5 + 2 * 2.4 * 3.5
A = 78.16 ft^2
d. A(rectangular prism)
A = 2LW + 2LH + 2WH
A = 2 *12 * 6 + 2 * 12 * 4.5 + 2 * 6 * 4.5
A = 306 ft^2
e. You have a large box to wrap and need to know how much wrapping paper will be needed to wrap the box.
The dimensions of the box are L = 10 in., W = 4 in., H = 6 in.
how would you solve it. I know the answer already. my problem working it out.
4b/2 + 3 = 11 + b.
Answers
4b/2 = 8 +b
multiply both sides by two
(4b/2 = 8 + b) X2 = 4b = 16+2b
subtract 2b from both sides
2b = 16
divide both sides by 2
b=8
1. Simplify any parentheses using the distributive property if needed.
2. Combine like terms if needed.
3. Use the addition principle of equality if needed.
4. Use the multiplication or division principle of equality if needed.
[tex]\frac{4b}{2} + 3 = 11 + b[/tex]
2b + 3 = 11 + b
b + 3 = 11 <-- Subtract b from each side
b = 8 <-- Subtract 3 from each side
So, b is equal to 8.
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e) Isabel’s competition,who sells books and no other products, charges a shipping fee of $1.99 per book plus a fixed fee of $3 for each order. Let x be the number of books purchased and f(x) be the price of shipping one order of books. Write a function that expresses f(x) and explain the value of f(x) for x = 0. (5 points)
f) Graph the function in part e. (10 points)
g) Is your graph discrete or continuous? Explain. (5 points)
Answers
Answer:
Isabel’s competition,who sells books and no other products, charges a shipping fee of $1.99 per book plus a fixed fee of $3 for each order. Let x be the number of books purchased and f(x) be the price of shipping one order of books. Write a function that expresses f(x) and explain the value of f(x) for x = 0. (5 points)
The price of the shipping ( f(x)) is equal to the cost of the fixed fee per order (3) plus the product of the number of books ordered (x) and the cost of the fee per book (1.99).
f(x)= 1.99x +3
for f(0) = 1.99(0)+3
f(0) =3
For F(0) there is a order of 0 books. The price is only for the shippping.
Step-by-step explanation:thats it buddy
A function that expresses f(x) is f(x) = 1.99x + 3. Graph is continuous.
What is continuous function?A continuous function is a function that does not have discontinuities that means any unexpected changes in value. A function is continuous if we can ensure arbitrarily small changes by restricting enough minor changes in its input.
For this case we have the following data:
A shipping fee of $ 1.99 is charged for each book sold.
There is a fixed fee of 3 dollars per order.
We must express the total cost by a function of the form .
If x represents the number of books sold, we have an expression of the form:
f(x) = 1.99x + 3
That is, according to the number of books sold, represented by x, a different value will be obtained for the total cost given by function f (x). For example:
If 3 books are sold, we have:
f(x) = 1.99x + 3
f(0) = 1.99(0) + 3
f(0) = 3
Thus, the value of f(x) for x = 0 is f(0) = 3.
The graph is continuous. Continuous is something that can and must be able to be broken down into fractions and decimals. Discrete means something that cannot be broken down into fractions or decimals.
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2x+3y=-2 4x+7y=-6 solve for the system of equations
Answers
multiply first equation by -2 and add to 2nd equation
-4x-6y=4
4x+7y=-6 +
0x+1y=-2
y=-2
sub back
2x+3y=-2
2x+3(-2)=-2
2x-6=-2
2x=4
x=2
(x,y)
(2,-2)
Use the arc length formula to find the length of the curve y = 5x − 4, −1 ≤ x ≤ 3. check your answer by noting that the curve is a line segment and calculating its length by the distance formula
Answers
The length of the arc is computed from the formula
[tex]S= \int_{-1}^{3} \,\sqrt{1+ (\frac{dy}{dx} )^{2}} \, dx[/tex]
The derivative is
y' = 5
Therefore
[tex]S = \int_{-1}^{3} \sqrt{1+25} \, dx =\sqrt{26}*(3-(-1))=20.396[/tex]
Note that
x = -1 +> y = 5(-1) - 4 = -9
x = 3 => y = 5(3) - 4 = 11
The distance between the points (-1, -9) and (3, 11) from the distance formula is
D = √[(3-(-1))² + (11-(-9))²] = √(16+400) = 20.396
This answer agrees with that obtained by integration.
Answer: 20.396
Obtained by integration and verified by the distance formula.
The arc length is 4√26, which is confirmed by the distance formula for a line segment yielding approximately 20.396 units.
To find the length of the curve y = 5x − 4 over the interval −1 ≤ x ≤ 3, we can use the arc length formula for a function y = f(x). The formula for the arc length L is given as:
L = ∫ab√(1 + (dy/dx)2) dx, where dy/dx is the derivative of y with respect to x.
1. Calculate the derivative dy/dx:
y = 5x − 4, so dy/dx = 5.
2. Substitute the derivative into the arc length formula:
L = ∫-13√(1 + 5²) dx = ∫-13√26 dx.
3. Integrate the function:
L = √26 ∫-13 dx = √26 [x]-13 = √26 (3 − (-1)) = 4√26 ≈ 20.396.
To verify this using the distance formula (since the curve is a straight line), we take the points (−1,−9) and (3,11) from the given curve:
4. Apply the distance formula:
Distance = √((x2 - x1)² + (y2 - y1)²), where (x1, y1) = (-1, -9) and (x2, y2) = (3, 11).
Therefore,
Distance = √((3 - (-1))² + (11 - (-9))²) = √((4)² + (20)²) = √(16 + 400) = √416 = 4√26 ≈ 20.396.
Thus, the arc length calculated using the formula and the distance formula are consistent.
The arc length is 4√26, which is confirmed by the distance formula for a line segment yielding approximately 20.396 units.
Use the functions h(x) = 2x + 5 and t(x) = 7x − 6 to complete the function operations listed below.
Part A: Find (h + t)(x). Show your work. (3 points)
Part B: Find (h ⋅ t)(x). Show your work. (3 points)
Part C: Find h[t(x)]. Show your work. (4 points)
Answers
h ( x ) = 2 x + 5 and t ( x ) = 7 x - 6
Part A:
( h + t ) ( x ) = ( 2 x + 5 ) + ( 7 x - 6 ) = 9 x - 1
Part B :
( h · t ) ( x ) = ( 2 x + 5 ) · ( 7 x - 6 ) = 14 x² - 12 x + 35 x - 30 =
= 14 x² + 23 x - 30
Part C :
h [ t ( x ) ] = h ( 7 x - 6 ) = 2 · ( 7 x - 6 ) + 5 = 14 x - 12 + 5 =
= 14 x - 7
In a store 60 cans of soup are arranged to be this play into equal rows why does the fraction 10 over 60 not represent the situation explain
Answers
This is given by the fraction 60 over 10.
The fraction 10 over 60 is not used to represent this situation because the fraction 10 over 60 gives the number of rows which is needed for 1 can. That is number of rows per can. But there is nothing like a fraction of a row. Hence the fraction 10 over 60 cannot be used to represent the situation.
Walter bought a square plot of land. the perimeter is 544 feet. how wide is the property?
Answers
perimeter of a square = is side times 4
so divide 544 by 4
544/4 = 136
the property is 136 feet wide
(48.9, -53.3) (84.6, -19.9) (-62.6, 81.7) (-14.4 ,-42.6) (71.2, -84.1) (71.2, 76.8 ) state the domain
Answers
Angles θ and Φ are supplementary, and theta equals 3pi/7 find the measure of theta
Answers
Φ + 3π/7 = π
Φ = π - 3π/7
Φ =4π/7
From Plato: Φ =7π/7 or π.
I want to make sure of my answer is right?
Answers
20 2/7 = 142/7 -20/35
find common denominator ( in this case it is 35)
35/7 =5 , multiply 142*5=710, 7*5 =35
142/7 = 710/35
710/35 - 20/35 = 710-20 = 690
690/35 now simplify that fraction
690/35 = 19.714
19*35 = 665
690-665=25
19 25/35
25/35 can reduce to 5/7
answer = 19 5/7