Question 10 Multiple Choice Worth 5 points)
(09.02 LC)
A quadratic equation is shown below:
x2 - 14x +41 = 0
Which of the following is the first correct step to write the above equation in the form (x - p)2 = 9, where p and q are
integers?
Add 8 to both sides of the equation
Add 9 to both sides of the equation
Subtract 8 from both sides of the equation
Subtract 9 from both sides of the equation

Answers

Answer 1

Answer:

Add 8 to both sides of the equation

Step-by-step explanation:

We have been given the quadratic equation;

x^2 - 14x +41 = 0

we are required to complete the square in order to express it in the form;

(x - p)^2 = q

In order to do this we need to find a constant c, such that;

[tex]c=(\frac{b}{2})^{2}[/tex]

where b is the coefficient of x in the quadratic equation. In our case b = -14. Therefore,

[tex]c=(\frac{-14}{2})^{2}=49[/tex]

Therefore, for us to complete the square, the left hand side of the quadratic equation should be;

x^2 - 14x +49

Since we already have 41, we can simply add 8 to make it 49. Thus, the first correct step to write the above equation in the form (x - p)2 = 9, where p and q are integers is to Add 8 to both sides of the equation


Related Questions

Apples sell for $1.90 per pound, and bananas sell for $0.75 per pound. Troy bought some apples and some bananas. Together they weighed 3.8 pounds, and cost $5.84.

How many pounds of apples and how many pounds of bananas did Troy buy?

2.6 pounds of apples; 1.2 pounds of bananas

1.9 pounds of apples; 1.9 pounds of bananas

1.5 pounds of apples; 2.3 pounds of bananas

1.2 pounds of apples; 2.6 pounds of bananas

Answers

Answer:

2.6 pounds of apples; 1.2 pounds of bananas

Step-by-step explanation:

A = pounds of apples and B = pounds of bananas

The total weight is 3.8 pounds, so:

A + B = 3.8

Apples are $1.90 per pound and bananas are $0.75 per pound, and the total cost is $5.84, so:

1.90A + 0.75B = 5.84

We can solve the system of equations using either elimination or substitution.

Using substitution:

1.90A + 0.75(3.8 - A) = 5.84

1.90A + 2.85 - 0.75A = 5.84

1.15A = 2.99

A = 2.6

B = 3.8 - A

B = 1.2

Divide 21a^3-14a by -7
A.-3a^3+2a
B.-3a^3-2a
C.-3a^2+2
D.3a^3+2a

Answers

Answer:

The correct answer is A:-3a^3+2a

For this case we must find the quotient of [tex]21a^3-14a[/tex] between -7:

That is to say:

[tex]\frac {21a ^ 3-14a} {- 7} =\\\frac {21a ^ 3} {- 7} + \frac {-14a} {- 7}[/tex]

We know that:

[tex]\frac {21} {7} = 3\\\frac {14} {7} = 2\\\frac {+} {-} = -[/tex]

Finally:

[tex]-3a ^ 3 + (2a) =\\-3a ^ 3 + 2a[/tex]

Answer:

[tex]-3a ^ 3 + 2a[/tex]

Option A

Solve 3(x-2) < 18.


Please help.

Answers

Hello!

The answer is:

The correct option is the first option,

[tex]{x|x<8}[/tex]

Why?

To solve the problem, we need to remember that the way to solve inequalities is almost the same that solving normal equations.

So, we are given the inequality, we have:

[tex]3(x-2)<18[/tex]

Now, solving we have:

[tex]3(x-2)<18\\\\(x-2)<\frac{18}{3} \\\\x-2<6\\\\x<6+2\\\\x<8[/tex]

Hence, we have that solution to the inequality is:

[tex]x<8[/tex]

So, the correct option is the first option,

[tex]{x|x<8}[/tex]

Have a nice day!

Answer:

[tex]\large\boxed{\{x\ |\ x<8\}}[/tex]

Step-by-step explanation:

[tex]3(x-2)<18\qquad\text{use the distributive porperty}\ a(b+c)=ab+ac\\\\(3)(x)+(3)(-2)<18\\\\3x-6<18\qquad\text{add 6 to both sides}\\\\3x-6+6<18+6\\\\3x<24\qquad\text{divide both sides by 3}\\\\\dfrac{3x}{3}<\dfrac{24}{3}\\\\x<8}[/tex]

What is the simplified form of x plus 4 over x squared minus 3x minus 10⋅x minus 3 over x squared plus x minus 12? (6 points)


1 over the quantity x minus 3 times the quantity x plus 4


1 over the quantity x minus 3 times the quantity x plus 2


1 over the quantity x plus 4 times the quantity x minus 5


1 over the quantity x plus 2 times the quantity x minus 5

Answers

Answer:

The simplified form is 1 over the quantity x plus 2 times the quantity

x minus 5 ⇒ 1/(x+2)(x-5) ⇒ last answer

Step-by-step explanation:

* Lets write the product of the two fraction

∵ [tex]\frac{x+4}{x^{2}-3x-10} *\frac{x-3}{x^{2}+x-12}[/tex]

- At first factorize the denominators

# x² - 3x - 10

∵ x² = x × x ⇒ 1st term in the 1st bracket and 1st term in the

  2nd bracket

∵ -10 = 2 × -5 ⇒ 2nd term in the 1st bracket and 2nd term in the

  2nd bracket

∵ x × - 5 = -5x ⇒ ext-reams

∵ x × 2 = 2x ⇒ means

∵ 2x + -5x = -3x ⇒ middle term

∴ x² - 3x - 10 = (x + 2)(x - 5)

# x² + x - 12

∵ x² = x × x ⇒ 1st term in the 1st bracket and 1st term in the

  2nd bracket

∵ -12 = -3 × 4 ⇒ 2nd term in the 1st bracket and 2nd term in the

  2nd bracket

∵ x × 4 = 4x ⇒ ext-reams

∵ x × -3 = -3x ⇒ means

∵ 4x + -3x = x ⇒ middle term

∴ x² + x - 12 = (x - 3)(x + 4)

* Lets write the fractions after factorization

∴ [tex]\frac{x+4}{(x+2)(x-5)}*\frac{x-3}{(x-3)(x+4)}[/tex]

- lets simplify the fractions by cancel (x - 3) up with (x - 3) down

 and cancel(x + 4) up with (x + 4) down

∴ [tex]\frac{1}{(x+2)(x-5)}*1=\frac{1}{(x+2)(x-5)}[/tex]

* The simplified form is 1 over the quantity x plus 2 times the

  quantity x minus 5


PLEASE HELP BRAINIEST ANSWER IS WORTH 20 POINTS
The table below shows data for a class's mid-term and final exams:

Mid-Term Final
100 98
100 95
100 93
95 91
95 88
92 82
92 78
88 78
85 65
75 60

Which data set has the largest IQR?

A.Mid- term exams

B.Final exams

C.They have the same IQR

D.There is not enough information

Answers

Answer:

B. Final Exams.

Step-by-step explanation:

The IQR is the difference between the lower and upper quartiles of the data and is a measure of the spread of the data.

Mid Term Exam:

First find the Median

This is (95+92)/2 = 93.5.

The Lower quartile is the median of the bottom 5 values = 88.

The upper quartile is the median of the top 5 values = 100

So the IQR = 100 - 88 = 12.

Final Exam.

We find the IQR of the Final exam data in a similar way:

It comes to 93 - 78 = 15.

how many ounces are equal to 7pounds

Answers

7 Pounds Equals 112.0000oz.

Have A Great Day!

a circle has a radius of 2 cm. find the length s of the arc intercepted by a central angle of 1.9 radians.​

Answers

Answer:

3.8 cm

Step-by-step explanation:

The arc length formula is s = r·Ф, where Ф is the central angle in radians.

Here, s = (2 cm)(1.9 rad) = 3.8 cm

Final answer:

The length of the arc intercepted by a central angle of 1.9 radians in a circle with a radius of 2 cm is 3.8 cm, calculated by multiplying the radius (2 cm) by the angle in radians (1.9).

Explanation:

A circle has a radius of 2 cm and we need to find the length (s) of the arc intercepted by a central angle of 1.9 radians. The formula to find the arc length 's' for a circle is s = r * Θ, where 'r' is the radius and 'Θ' is the central angle in radians. We have 'r' = 2 cm and 'Θ' = 1.9 radians.

To find the arc length 's', we simply multiply the radius by the angle:

s = 2 cm * 1.9 radians = 3.8 cm.

Therefore, the length of the arc intercepted by a central angle of 1.9 radians in a circle with a radius of 2 cm is 3.8 cm.

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A mouse is trapped in a maze. To find his way out he walks 10 m, makes a 90° right turn, walks 5 m, makes another 90°, and walks 7 m. What is the magnitude of the resultant vector? Round to the nearest tenth

Answers

Final answer:

The mouse's overall displacement or the magnitude of the resultant vector after moving through the maze is 17.7 m, calculated based on principles of vectors in physics and using the Pythagorean theorem.

Explanation:

To find the magnitude of the resultant vector, indicating the mouse's displacement after traversing through the maze, we can use the principles of vectors in physics. The mouse goes through three separate displacement vectors, one of 10 m (right), another of 5 m (downward), and the last one of 7 m (right) again.

We can consider these displacements as components of two dimensions: X (horizontal) and Y (vertical). We sum the horizontal (rightward) displacements and vertical (downward) displacements separately. The horizontal displacement is 10 m + 7 m = 17 m (rightward). The vertical displacement is 5 m (downward).

To find the magnitude of the resultant displacement, we apply the Pythagorean theorem. The magnitude is the square root of the sum of the squares of the horizontal and the vertical displacement, so sqrt((17 m)^2 + (5 m)^2) = 17.7 m (rounded to the nearest tenth).

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at a party there are 12 diet sodas and 8 regular sodas. there are also 14 snack bagsof cheetos and 6 snack bags of pretzels. if you grab a soda and a snack bag without looking, what is the probability that you will get a diet soda and a snack bag of cheetos?​

Answers

The probability of grabbing a diet soda and a snack bag of Cheetos is 42%.

The question is asking to find the probability of selecting a diet soda and a bag of Cheetos at a party. To calculate this probability, we need to look at the total number of each item and determine how many favorable outcomes there are based on the selections made.

Calculate the total number of sodas: 12 diet sodas + 8 regular sodas = 20 sodas.Calculate the probability of selecting a diet soda: P(diet soda) = 12 diet sodas / 20 total sodas = 0.6 or 60%.Calculate the total number of snack bags: 14 bags of Cheetos + 6 bags of pretzels = 20 snack bags.Calculate the probability of selecting a bag of Cheetos: P(Cheetos) = 14 bags of Cheetos / 20 total snack bags = 0.7 or 70%.Finally, calculate the probability of both events happening together, which is the product of the individual probabilities: P(diet soda and Cheetos) = P(diet soda)
* P(Cheetos) = 0.6
* 0.7 = 0.42 or 42%.

Solve for the variable in the equations below. Round your answers to the nearest hundredth. Do not round any intermediate computations.

Answers

Answer:

Part 1) [tex]x=-0.07[/tex]

Part 2) [tex]y=2.48[/tex]

Step-by-step explanation:

Part 1) we have

[tex]15^{-9x} =6[/tex]

Solve for x

Apply log both sides

[tex]log(15^{-9x})=log(6)[/tex]

[tex]-x*(9log(15))=log(6)[/tex]

[tex]x=-log(6)/(9log(15))[/tex]

[tex]x=-0.07[/tex]

Part 2) we have

[tex]e^{y}=12[/tex]

Apply ln both sides

[tex]ln(e^{y})=ln(12)[/tex]

[tex]y*ln(e)=ln(12)[/tex]

Remember that

[tex]ln(e)=1[/tex]

[tex]y=ln(12)[/tex]

[tex]y=2.48[/tex]

Answer with explanation:

The two equations which we have to solve for x and y and the way of finding it's solution is

   [tex]1.\rightarrow 15^{-9x}=6\\\\\text{Taking log on both sides}\\\\\rightarrow -9x \log 15=\log 6\\\\\rightarrow x \log 15^{-9}=\log 6\\\\\rightarrow x=\frac{\log 6}{\log 15^{-9}}}\\\\\rightarrow x=\log_{15^{-9}} 6\\\\2.\rightarrow e^y=12\\\\\text{Taking log on both sides}\\\\\rightarrow y \log e=\log 12\\\\\rightarrow y= \log 12[/tex]

Solve for an angle in right triangles.

Answers

C is 90°fare and height

Answer:

[tex] \sin(x) = \frac{4}{6 } \\ x = arcsin( \frac{2}{3} ) \\ x = 41.81 \: degrees [/tex]

Step-by-step explanation:

Google search inverse trigonometry geometry for an explanation

answer technically should say

measure of angle A equals 41.81 degrees

there should be the letter m in front of the angle symbol.

The figure is made up of a cylinder, a cone, and a half sphere. The radius of the half sphere is 3 inches. What is the volume of the composite figure?

Answers

Looks like your figure is missing...

Could you repost it with the figure next time?

Someone will solve it for sure.

Regards;

Leukonov.

In the diagram a || b, if m∠6 = 21°, what is m∠4?

A) 21°

B) 10.5°

C) 159°

D) 339°

Answers

Answer:D

Step-by-step explanation:

Final answer:

In corresponding angles formed by parallel lines intersected by a transversal line, the angles are equal. So, if the measure of angle 6 is 21°, the measure of corresponding angle 4 will also be 21°.

Explanation:

The subject of this question is geometry, specifically dealing with parallel lines and the angles formed when a line intersects them. In the given diagram, we are told that lines a and b are parallel (represented as a || b). Therefore, we can use the properties of parallel lines to find the measure of angle 4. When a line intersects two parallel lines, it forms corresponding angles which are equal. Since we know the measure of angle 6, which is 21°, and angle 4 and 6 are corresponding angles, therefore the measure of angle 4 is also 21°. So, the answer is A) 21°.

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Write an equation to solve each problem and then solve it. The sum of three consecutive integers is 54. Find the integers. if the smallest integer is x, what will the equation be?

Answers

Answer:

It is 17,18 and 19

Step-by-step explanation:

Consecutive numbers are

x, x+1, x+2

x+x+1+x+2=54

3x+3=54

-3       -3

3x=51

x=17

17

17+1=18

17+2=19

17, 18 and 19

How many terms does the polynomial have? a 2 + b - cd 3 2 3 4

Answers

ANSWER

3

EXPLANATION

The given polynomial is

[tex] {a}^{2} + b - cd[/tex]

The terms of the polynomial are:

First term:

[tex] {a}^{2} [/tex]

Second term:

[tex]b[/tex]

Third term:

[tex] - cd[/tex]

Therefore the given polynomial has 3 terms.

Find the exact value of tan 195 degrees

Answers

Answer:

0.267949192 8s the value of tan 195°

Please help I’m really slow.

Answers

Formula All area of prism : 2lw+2wh+2lh

l : 6/ w : 3 / h: 7

All area: 2(6*3)+2(3*7)+2(6*7)
All area: 162

At a college production of A Streetcar Named Desire, 400 tickets were sold. The ticket prices were $8, $10, and $12, and the total income from ticket sales was $3700. How many tickets of each type were sold if the combined number of $8 and $10 tickets sold was 7 times the number of $12 tickets sold?​

Answers

Answer:

There are 200 $8 tickets

There are 150 $10 tickets

There are 50 $12 tickets

Step-by-step explanation:

Let a = number of $8 tickets

Let b = number of $10 tickets

Let +c = number of $12 tickets

given:

(1) a+b+c = 400

(1) 8a+10b+12c = 3700

(1) a+b = 7c

--------------

This is 3 equations and 3 unknowns, so

it should be solvable

Substitute (3) into (1)

(1) 7c+c = 400

(1) 8c= 400

(1) c = 50

Plug this value into (2)

(2) 8a+10b+12*50= 3700

(2) 8a+10b+600= 3700

(2) 8a+10b= 3100

(2) 4a+5b= 1550

and

(1) a+b+c= 400

(1) a+b+50= 400

(1) a+b= 350

Multiply both sides of (1) by +4+

(1) 4a+4b= 1400

Subtract (1) from (2)

(2) 4a+5b+=+1550+

(1) -4a-4b= -1400

b= 150

and, since

(3) a+b= 7c

(3) a+150= 7*50

(3) a= 350-150

(3) a= 200

_________________

There are 200 $8 tickets

There are 150 $10 tickets

There are 50 $12 tickets

____________________________

check:

(2) 8*200+10*150+12*50= 3700

(2) 1600+1500+600= 3700

(2) 3700= 3700

Each type was sold are 200 for $8, 150 for $10, and 50 for $12 if the ticket prices were $8, $10, and $12, and the total income from ticket sales was $3700.

What is a linear equation?

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

It is given that:

At a college production of A Streetcar Named Desire, 400 tickets were sold. The ticket prices were $8, $10, and $12, and the total income from ticket sales was $3700.

Let x be the number of $8 tickets

Let y be the number of $10 tickets

Let z be the number of $12 tickets

From the data given in the question, we can frame three linear equation in three variables:

x + y + z = 400

8x + 10y + 12z = 3700

x + y = 7z

After solving the above equations by elimination method:

We get:

x = 200

y = 150

z = 50

Thus, each type was sold are 200 for $8, 150 for $10, and 50 for $12 if the ticket prices were $8, $10, and $12, and the total income from ticket sales was $3700.

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Find the solutions(s) to 9x^2-54x=0

Answers

Answer:

Two solutions were found :

x = 6

x = 0

Step-by-step explanation:

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "x2"   was replaced by   "x^2".  

Step by step solution :

Step  1  :

Equation at the end of step  1  :

 32x2 -  54x  = 0  

Step  2  :

Step  3  :

Pulling out like terms :

3.1     Pull out like factors :

  9x2 - 54x  =   9x • (x - 6)  

Equation at the end of step  3  :

 9x • (x - 6)  = 0  

Step  4  :

Theory - Roots of a product :

4.1    A product of several terms equals zero.  

When a product of two or more terms equals zero, then at least one of the terms must be zero.  

We shall now solve each term = 0 separately  

In other words, we are going to solve as many equations as there are terms in the product  

Any solution of term = 0 solves product = 0 as well.

Solving a Single Variable Equation :

4.2      Solve  :    9x = 0  

Divide both sides of the equation by 9:

                    x = 0  

Solving a Single Variable Equation :

4.3      Solve  :    x-6 = 0  

Add  6  to both sides of the equation :  

                     x = 6

Answer:

x = 6...... x = 0

Step-by-step explanation:

a p e x.

Step-by-step explanation:

what is b in 12-b=12.5

Answers

Answer:

b=-.5

Step-by-step explanation:

Final answer:

The value of b in the equation 12 - b = 12.5 is determined by subtracting 12 from both sides and then multiplying by -1, resulting in b = -0.5.

Explanation:

The student is asking to solve for b in the equation 12 - b = 12.5. To find the value of b, you need to isolate the variable on one side of the equation. This is done by subtracting 12 from both sides, resulting in -b = 12.5 - 12, which simplifies to -b = 0.5. To get b by itself and not -b, you multiply both sides of the equation by -1, giving b = -0.5.

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Floras flowers sells 3 rose for 13.50 $. The Green Thumb sells 4 roses for 15 $. Discount Flowers sells 6 roses for 23 $. Who sells roses at the lowest price?

Answers

Green thumbs sells lowest price. If you divide the$amount by the amount of roses, you'll get

Flora's : $13.50/3= $4.50 each rose

Green: $15/4= $3.75 each rose

Discount F: $23/6= $3.83 each rose

Use the functions a(x) = 3x + 10 and b(x) = 5x − 6 to complete the function operations listed below.

Part A: Find (a + b). Show your work.

Part B: Find (a - b). Show your work.

Part C: Find (a * b). Show your work.

Answers

Answer:

(a + b) = 8x +4

(a - b) = -2x +16

(a * b) = [tex]15x^{2}+32x-60[/tex]

Step-by-step explanation:

We have been given the functions;

a(x) = 3x + 10 and b(x) = 5x − 6

Part A:

(a + b) = a(x) + b(x) # we simply add the two given functions

(a + b) = 3x + 10 + 5x − 6

(a + b) = 8x + 4

Part B:

(a - b) = a(x) - b(x) # we simply subtract the two given functions

(a - b) = (3x + 10 ) - (5x − 6)

(a - b) = 3x + 10 -5x +6

(a - b) = -2x + 16

Part C:

(a * b) = a(x)*b(x)

# we simply find the product of the two given functions

(a * b) = (3x + 10)*(5x − 6)

(a * b) = [tex]15x^{2}-18x+50x-60=15x^{2}+32x-60[/tex]

Part A

The functions a(x) = 3x + 10 and b(x) = 5x − 6 to complete the function operations listed below.

(a+b)(x)=a(x)+b(x)

(a+b)(x)=(3x+10)+(5x-6)

(a+b)(x)=3x+5x+10-6

(a+b)(x)=8x+4

Part B.

(a-b)(x)=a(x)-b(x)

(a-b)(x)=(3x+10)-(5x-6)

Expand the parenthesis to get:

(a-b)(x)=3x+10-5x+6

(a-b)(x)=3x-5x+10+6

(a-b)(x)=-2x+16

Part C

(a*b)(x)=a(x)*b(x)

(a*b)(x)=(3x+10)*(5x-6)

We expand to get:

[tex]a \times b = 15 {x}^{2} - 18x + 50x - 60[/tex]

[tex]a \times b = 15 {x}^{2} + 32x - 60[/tex]

Suppose θ is an angle in the standard position whose terminal side is in Quadrant IV and . Find the exact values of the five remaining trigonometric functions of θ.

Answers

If [tex]\theta[/tex] falls in quadrant IV, then we know [tex]\sin\theta<0[/tex] and [tex]\cos\theta>0[/tex]. By definition of cosecant,

[tex]\csc\theta=\dfrac1{\sin\theta}[/tex]

so we also know that [tex]\csc\theta<0[/tex]. Recall that

[tex]\cot^2\theta+1=\csc^2\theta[/tex]

which means

[tex]\csc\theta=-\sqrt{\cot^2\theta+1}=-\dfrac{\sqrt{10}}3[/tex]

[tex]\implies\sin\theta=-\dfrac3{\sqrt{10}}[/tex]

By definition of cotangent,

[tex]\cot\theta=\dfrac{\cos\theta}{\sin\theta}\implies\cos\theta=\dfrac1{\sqrt{10}}[/tex]

[tex]\implies\sec\theta=\sqrt{10}[/tex]

We also immediately know that

[tex]\tan\theta=-\dfrac{21}7[/tex]

The listed answers are unsimplified relative to the ones we've come up with here, but with some manipulation we find

[tex]\sin\theta=-\dfrac3{\sqrt{10}}=-\dfrac{7\cdot3}{7\sqrt{10}}=-\dfrac{21}{\sqrt{490}}[/tex]

[tex]\cos\theta=\dfrac1{\sqrt{10}}=\dfrac7{7\sqrt{10}}=\dfrac7{\sqrt{490}}[/tex]

[tex]\csc\theta=\dfrac1{\sin\theta}=-\dfrac{\sqrt{490}}{21}[/tex]

[tex]\sec\theta=\dfrac1{\cos\theta}=\dfrac{\sqrt{490}}7[/tex]

[tex]\tan\theta=\dfrac1{\cot\theta}=-\dfrac{21}7[/tex]

so that the third option is correct.

How do I solve this question? It says determine the next 3 terms in each arithmetic sequence. -24, -14, -4,6

Answers

16 and 26 and 36 because each time you need to add 10

Answer:

16, 26, 36

Step-by-step explanation:

[tex]a_1=-24\\a_2=-24+10=-14\\a_3=-14+10=-4\\a_4=-4+10=6\\\\\text{Add the common difference d = 10 to the previous term.}\\\\a_5=a_4+10\to a_5=6+10=16\\a_6=a_5+10\to a_6=16+10=26\\a_7=a_6+10\to a_7=26+10=36\\\vdots[/tex]

I need help please and thank you . I am try to pass this.

Answers

Answer:

11 ≤ n

Explanation:

[tex] \frac{66}{6} = 11[/tex]

More than indicates the minimum value, so you use the greater than or equal to.

The above answer is written in reverse, which the exact same result.

I am joyous to assist you anytime.

4x+2y=-6, 5y=-30x+5​

Answers

Answer:

(x,y)=(85/562, -20/281)

Step-by-step explanation:

4x+2y=-6.5y=-30x+5

{4x+2y=-30x+5

{-6.5y=-30x+5 simplify the expression

{34x+2y=5

{300x-65y=50 multiply

{2210x+130y=325

{600x-1307=100 eliminate on evariable by adding the equations

2810x=425 divide both sides by 2810

x=85/562 substitute the value of x into the equation

34*85/562+2y=5 solve the equation

y=-20/281 a possible solution

(x,y)=(85/562,-20/281) check the solution

4*85/562+2*(-20/281)=-6.5*(-20/281)=-30*85/562+5 simplify the expression

130/281=130/281=130/281 the orderred pair is a solution

The slope of the line passing through the points (2,7) and (-4, 8) is
-6
-1/2
-1/6

Answers

Answer:

I think is 1/6 the answer

Formula for slope is:

[tex]\frac{y_{2} -y_{1}}{x_{2}-x_{1}}[/tex]

In this case...

[tex]y_{2} =8\\y_{1} =7\\x_{2} =-4\\x_{1} =2[/tex]

so...

[tex]\frac{8-7}{-4-2}[/tex]

[tex]\frac{1}{-6}[/tex]

[tex]\frac{-1}{6}[/tex] <---------------------------the slope of the line

Hope this helped!

~Just a girl in love with Shawn Mendes

Please help me I need all right

Answers

Answer:

Jimmy and Jane

Step-by-step explanation:

They have used Pythagoras to find the length of BC. Moe is wrong because she wrote ( 1 - 4 ) ² but it's meant to be ( 4 - 1 ) ² and Alice is wrong because she forget to square 3,4 and x

??????????? Neeeeed help

Answers

Answer:

it would be 3 tons and 80 ibs

hope that helps...if i am wrong, i am sorry :-)

Step-by-step explanation:

In the following diagram, a circle is inscribed in a square. How can you find the area of the shaded region?

Notice that the shaded region of the figure is composed of four identical pieces. However, each piece has a curved side, which makes it very difficult to find its area using a direct method. In this type of diagram, the easiest way to find the area uses an indirect method. Look at the diagram using a different perspective. The shaded region is composed of four identical pieces. OR, the shaded region is the area of the square minus the area of the circle. Since you know how to find the area of both a square and a circle, this is a much easier method for solving!
Area of square: s2 = (6 cm)2 = 36 cm2
Area of circle: r2 ≈ (3.14)(3 cm)2 ≈(3.14)(9 cm2) ≈ 28.26 cm2
Area of shaded region: 36 cm2 - 28.26 cm2 = 7.74 cm2
The area of the shaded region is approximately 7.74 square centimeters.
Answer the questions based on the following diagram. Note: The two triangles meet at the center of the circle.


What is the approximate area of the circle? Use 3.14 in your calculation.

What is the area of one of the triangles?

What is the approximate area of the shaded region of the diagram?

Answers

Answer:

approx area of circ.=254.34

area of triangl=40.5

shaed region=173.34

just add sq. units

Step-by-step explanation:

areas of the triangle are 9*9=81

r=9

a=pi*r^2

=3.14*81

=254.34

254.34-81=173.34

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