Answer:
No. Anna is incorrect.
Step-by-step explanation:
In order to find if the answer is right, just find the diagonals using the pythogorean theorem.
a² + b² = c²
For the rectangle, the base is 14 and the height is 7. We will have to find the hypotenuse.
14² + 7² = c²
196 + 49 = c²
245 = c²
c = √245
c = √49 × √5
c = 7√5
For the square, the base is 7 and the height is 7. We will have to find the hypotenuse.
7² + 7² = c²
49 + 49 = c²
98 = c²
c = √98
c = √49 × √2
c = 7√2
Now compare :
7√5 and 7√2
Clearly, 7√5 is not the double of 7√2
The twice–differentiable function f is defined for all real numbers and satisfies the following conditions: f(0)=3 f′(0)=5 f″(0)=7 The function g is given by g(x)=eax+f(x) for all real numbers, where a is a constant. Find g ′(0) and g ″(0) in terms of a. Show the work that leads to your answers. The function h is given by h(x)=cos(kx)[f(x)]+sin(x) for all real numbers, where k is a constant. Find h ′(x) and write an equation for the line tangent to the graph of h at x=0. For the curve given by 4x2+y2=48+2xy show that dy dx = y−4x y−x . For the curve given by 4x2+y2=48+2xy, find the positive y-coordinate given that the x-coordinate is 2. For the curve given by 4x2+y2=48+2xy, show that there is a point P with x-coordinate 2 at which the line tangent to the curve at P is horizontal.
[tex]g(x)=e^{ax}+f(x)\implies g'(x)=ae^{ax}+f'(x)\implies g''(x)=a^2e^{ax}+f''(x)[/tex]
Given that [tex]f'(0)=5[/tex] and [tex]f''(0)=7[/tex], it follows that
[tex]g'(0)=a+5[/tex]
[tex]g''(0)=a^2+7[/tex]
###
[tex]h(x)=\cos(kx)f(x)+\sin x\implies h'(x)=-k\sin(kx)f(x)+\cos(kx)f'(x)+\cos x[/tex]
When [tex]x=0[/tex], we have
[tex]h(0)=\cos0f(0)+\sin0=f(0)=3[/tex]
The slope of the line tangent to [tex]h(x)[/tex] at (0, 3) has slope [tex]h'(0)[/tex],
[tex]h'(0)=-k\sin0f(0)+\cos0f'(0)+\cos0=5+1=6[/tex]
Then the tangent line at this point has equation
[tex]y-3=6(x-0)\implies y=6x+3[/tex]
###
Differentiating both sides of
[tex]4x^2+y^2=48+2xy[/tex]
with respect to [tex]x[/tex] yields
[tex]8x+2y\dfrac{\mathrm dy}{\mathrm dx}=2y+2x\dfrac{\mathrm dy}{\mathrm dx}[/tex]
[tex]\implies(2y-2x)\dfrac{\mathrm dy}{\mathrm dx}=2y-8x[/tex]
[tex]\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{y-4x}{y-x}[/tex]
On this curve, when [tex]x=2[/tex] we have
[tex]4(2)^2+y^2=48+2(2)y\implies y^2-4y-32=(y-8)(y+4)=0\implies y=8[/tex]
(ignoring the negative solution because we don't care about it)
The tangent to this curve at the point [tex](x,y)[/tex] has slope [tex]\dfrac{\mathrm dy}{\mathrm dx}[/tex]. This tangent line is horizontal when its slope is 0. This happens for
[tex]\dfrac{y-4x}{y-x}=0\implies y-4x=0\implies y=4x[/tex]
and when [tex]x=2[/tex], there is a horizontal tangent line to the curve at the point (2, 8).
The equation for the line tangent to the graph of h at x = 0 is:
y - 3 = 6(x - 0)
y = 6x + 3
How can Find g'(0) and g''(0)?The function g is given by:
g(x) = a[tex]e^x[/tex]+ f(x)
where a is a constant. We are given that f(0) = 3, f'(0) = 5, and f''(0) = 7.
To find g'(0), we need to differentiate g(x):
g'(x) = a[tex]e^x[/tex]+ f'(x)
Substituting x = 0, we get:
g'(0) = a[tex]e^0[/tex] + f'(0) = a + 5
To find g''(0), we need to differentiate g'(x):
g''(x) = a[tex]e^x[/tex] + f''(x)
Substituting x = 0, we get:
g''(0) = a[tex]e^0[/tex]+ f''(0) = a + 7
Therefore, g'(0) = a + 5 and g''(0) = a + 7.
To Find h'(x) and write an equation for the line tangent to the graph of h at x = 0
The function h is given by:
h(x) = cos(kx)[f(x)] + sin(x)
where k is a constant. We need to find h'(x):
h'(x) = -ksin(kx)[f(x)] + cos(kx)f'(x) + cos(x)
Substituting x = 0, we get:
h'(0) = -ksin(0)[f(0)] + cos(0)f'(0) + cos(0)
h'(0) = f'(0) + 1
We are given that f'(0) = 5, so h'(0) = 6.
To find the equation for the line tangent to the graph of h at x = 0, we need to use the point-slope form of the equation of a line:
y - y1 = m(x - x1)
where:
y is the y-coordinate of any point on the line
y1 is the y-coordinate of the point where the line intersects the graph
m is the slope of the line
x is the x-coordinate of any point on the line
x1 is the x-coordinate of the point where the line intersects the graph
We know that x1 = 0 and h'(0) = m = 6. We also know that h(0) = cos(0)[f(0)] + sin(0) = 3 + 0 = 3.
Therefore, the equation for the line tangent to the graph of h at x = 0 is:
y - 3 = 6(x - 0)
y = 6x + 3
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2x3+x2-13x+6 find zeroes , verify
Answer:
the zeros are x ∈ {-3, 1/2, 2}
Step-by-step explanation:
A graphing calculator shows where the zeros are. (See attached)
These suggest factors of (x +3)(x -2)(2x -1). To verify these are the factors, we can multiply this out to get ...
= (x^2 +x -6)(2x -1)
= 2x^2 +2x^2 -12x -x^2 -x +6
= 2x^3 +x^2 -13x +6 . . . . same as the original expression
which can be the first step in finding the equation of the line that passes through the points( 5, -4) and( -1, 8) in slope intercept form?
Answer:
Option A is the correct answer.
Step-by-step explanation:
The slope intercept form is: y=mx+b
We need to find m slope and b is the y intercept.
So, first we find the slope m of the given points.
[tex]m = \frac{y_{2} -y_{1}}{x_{2} -x_{1}} \\m= \frac{8-(-4)}{-1-(5)}\\ m= \frac{12}{-6}\\ m=-2[/tex]
After finding the slope, we can find the y intercept.
So, Option A is the correct answer.
Answer:
A
Step-by-step explanation:
help please
must show work
Answer:
Step-by-step explanation:
23A: Simplify
V^2 + 11V + 10
There are no like terms
Answer when simplify: V^2 + 11V + 10
23B. Factor:
Steps: V^2 + 11V + 10
Break the expression into groups:
(V^2 + V) + (10V + 10)
Factor out: V From V^2 + V: V(V + 1)
Factor out: 10 From 10V + 10: 10(V + 1)
V(V + 1) + 10(V + 1)
Factor out common term: V + 1
Factor: Therefore your Answer: (V + 1) (V + 10)
24: Factor
Steps: k^2 + 11k + 30
Break the expression into groups:
(K^2 + 5K)(6K + 30)
Factor out: k from K^2 + 5K ====> K(K + 5)
Factor out 6 from 6K + 30 ===> 6(K + 5)
= k(k + 5) + 6(k + 5)
Factor out common term: k + 5
Factor: Therefore your Answer is: (K + 5) (K + 6)
25: Factor
Steps: R^2 - 1
Rewrite: 1 as 1^2
R^2 - 1^2
Apply difference of two square formulas:
x^2 - y^2 = (x + y)(x - y)
r^2 - 1^2 = (r + 1)(r - 1)
Therefore your answer: (r + 1)(r - 1)
26: Factor
Steps: V^2 - V - 2
Break the expressions into groups:
(V^2 + V) + ( -2V - 2)
Factor out V from V^2 + V: V(V + 1)
Factor out -2 from -2v - 2: -2(V + 1)
V(V + 1) - 2(V + 1)
Factor out common term: V + 1
Therefore your answer: (V + 1)(V - 2)
27: Factor
Steps: 4N^2 - 15N - 25
Break expression into groups:
(4N^2 + 5N) + ( -20N - 25)
Factor out N from 4N^2 + 5N: 4(4N + 5)
Factor out -5 from -20N - 25: -5(4N + 5)
N(4N + 5) - 5(4N + 5)
Factor out common term: 4N + 5
Therefore your answer: (4n + 5)(N - 5)
28: Factor:
Steps: N^2 + 3N - 54
Break the expression into group:
(N^2 - 6N) + (9N - 54)
Factor out N from N^2 - 6N: N(N - 6)
Factor out 9 From 9N - 54: 9(N - 6)
N(N - 6) + 9(N - 6)
Factor out common term: N - 6
Therefore your answer: (N - 6)(N + 9)
Hope that helps, Have an awesome day! :)
A circle with radius r is inscribed into a right triangle. Find the perimeter of the triangle if: The point of tangency divides the hypotenuse into 5 cm and 12 cm segments.
Answer:
40 cm
Step-by-step explanation:
If we let r represent the radius of the circle, the legs of the triangle have length 5+r and 12+r. Then the Pythagorean Theorem tells us ...
(5 +12)^2 = (5 +r)^2 +(12 +r)^2
5^2 +2·5·12 +12^2 = 5^2 +2·5·r +r^2 + 12^2 +2·12·r +r^2
120 = 34r +2r^2 . . . . subtract 5^2 +12^2
60 +8.5^2 = 8.5^2 +17r +r^2 . . . . . . divide by 2, add (17/2)^2
11.5 = 8.5 +r . . . . . . . . . . . . . . . . . . . take the square root (negative root is extraneous)
3 = r
The radius of the circle is 3 cm. The perimeter of the triangle is the sum of the side lengths:
(5 +3) cm + (12 +3) cm + (5+12) cm = 2(5 +12 +3) cm = 40 cm
To find the perimeter of the right triangle, we need to find the lengths of its three sides. We can use the Pythagorean theorem to find the lengths of the legs of the triangle. The perimeter of the triangle is the sum of the lengths of all three sides.
Explanation:To find the perimeter of the right triangle, we need to find the lengths of its three sides. Let's denote the lengths of the triangle's legs as a and b, and the hypotenuse as c. We are given that the point of tangency divides the hypotenuse into segments of 5 cm and 12 cm. Since the point of tangency is equidistant from the ends of the hypotenuse, the length of the hypotenuse is equal to the sum of these two segments, so c = 5 cm + 12 cm = 17 cm.
Using the Pythagorean theorem, we can find the lengths of the legs a and b. The theorem states that in a right triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the other two sides. So we have a² + b² = c². Substituting the given values, we get a² + b² = 17 cm².
Finally, the perimeter of the triangle is the sum of the lengths of all three sides: P = a + b + c. We can solve for a and b using the equation a² + b² = 17 cm², and then calculate the perimeter.
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Plz help me out will mark as brainliest!!! Don’t copy anybody else’s answer 40 points
-Original Profit-
y = 22x ; where x is the number of necklaces sold and y is the mount of profit.
y = 29x ; where x is the number of necklaces sold and y is the amount of profit.
Xavier will earn an additional $7 if he proceeded in switching to a new type of pendant. The $7 is the difference of $29 and $22 profit.
if x is the amount sold and y is the profit, then the original equation would be y = 22x since originally he was selling them for $22 dollars each. That means that in the equation y = 29x, 29 is the amount of profit per each necklace. From here it's just simple subtraction. New profit - Old profit = How much more earned $29 - $22 = $7 extra earned per necklace. he would save $7.
Imagine an illness with two cures—drug X and drug Y. Drug X and drug Y are both made by the same firm.
Two events recently happened. First, a study was released showing that drug X is less effective than drug Y. Second, the ingredients used to produce drug X increased in price. What are the consequences of these events?
Choose one:
A. The demand for drug X shifts to the right, and the supply of drug X shifts to the left. The result is a rise in the equilibrium price for drug X and a fall in the equilibrium quantity of drug X.
B. The demand for drug X shifts to the right, and the supply curve for drug X shifts to the left. The result is an unknown change in the equilibrium price for drug X and a fall in the equilibrium quantity of drug X.
C. The demand for drug X shifts to the left, and the supply curve for drug X shifts to the left. The result is an unknown change in the equilibrium price for drug X and a fall in the equilibrium quantity of drug X.
D. The demand for drug X shifts to the left, and the supply curve for drug X shifts to the left. The result is a rise in the equilibrium price for drug X and a fall in the equilibrium quantity of drug X.
The correct answer is: C. The demand for drug X shifts to the left, and the supply curve for drug X shifts to the left. The result is an unknown change in the equilibrium price for drug X and a fall in the equilibrium quantity of drug X.
Explanation:
1. The study showing that drug X is less effective than drug Y implies a decrease in the perceived effectiveness of drug X. This could lead to a decrease in the demand for drug X as consumers may prefer the more effective drug Y.
2. The increase in the price of ingredients used to produce drug X would lead to an increase in the production cost of drug X. This could cause a leftward shift in the supply curve for drug X, as producers may be less willing or able to supply the same quantity at the previous prices.
Both a decrease in demand and a leftward shift in the supply curve would result in a fall in the equilibrium quantity of drug X. The impact on the equilibrium price is uncertain and would depend on the magnitude of the shifts in demand and supply. Therefore, option C reflects these potential changes in demand and supply without making specific predictions about the equilibrium price.
The correct answer is C: The demand for drug X shifts to the left, and the supply curve for drug X shifts to the left, resulting in an unknown change in equilibrium price for drug X and a decrease in the equilibrium quantity.
The student asked about the consequences on equilibrium price and equilibrium quantity for drug X following two events: a study showing drug X is less effective than drug Y, and an increase in the price of ingredients used to produce drug X.
Analyze each event's impact on demand and supply separately: The less effective study would cause the demand for drug X to shift to the left, implying a decrease in the quantity demanded at each price because consumers now prefer drug Y. Additionally, the increase in production costs would create a supply curve shift for drug X to the left, representing a decrease in supply at each price point. When both supply and demand shift to the left, the equilibrium quantity will clearly decrease; however, the impact on the equilibrium price is uncertain without knowing the relative magnitude of the shifts.
Choosing from the provided options, answer C is correct: The demand for drug X shifts to the left, and the supply curve for drug X shifts to the left. The result is an unknown change in the equilibrium price for drug X and a fall in the equilibrium quantity of drug X.
In Exercise 13, solve y=f(x) for x. Then find the input when the output is 2.
13. f(x) = 9x^2
I don't understand how to solve this question. I know the answer, but can you lead me through the steps you took to solve the problem? Thanks!
Answer:
x = ±(√y)/3
x = ±(√2)/3
Step-by-step explanation:
Put the given information in the given equation and solve for x:
f(x) = 2
2 = 9x^2 . . . . . use 2 in place of f(x)
2/9 = x^2 . . . . divide by 9
±√(2/9) = x . . . take the square root
x = ±(√2)/3 . . . simplify
_____
Using this as an example, we can solve f(x) = y in the same way:
y = 9x^2 . . . . use y for f(x)
y/9 = x^2 . . . divide by the coefficient of x^2
±√(y/9) = x . . . take the square root; next, simplify
x = ±(√y)/3 . . . . the equation solved for x. Note this matches the above when y=2.
Urgently needed
see image
y2-y1 =M(x2-x1)
Ok Sir, you gave points : (2,1) and (3,4)
4-1/3-2 = 3
Ok we know our slope is 3, now pick any of the two points, and make an equation for this line, so lets go ahead and pick #1, (2,1)
Formula is same as before
y-1=3x-6
y=3x-5
I think its correct, pick as brainless sir, thanks.
Ð1 and Ð2 are congruent. If mÐ1 = 10x – 5 and mÐ2 = 6x + 15, then what is the degree measure of Ð1?
Answer:
mÐ1 = 45Step-by-step explanation:
If Ð1 and Ð2 are congruent, then mÐ1 = mÐ2.
We have mÐ1 = 10x - 5 and mÐ2 = 6x + 15.
The equation:
10x - 5 = 6x + 15 add 5 to both sides
10x - 5 + 5 = 6x + 15 + 5
10x = 6x + 20 subtract 6x from both sides
10x - 6x = 6x - 6x + 20
4x = 20 divide both sides by 4
4x : 4 = 20 : 4
x = 5
Put the value of x to the expression 10x - 5:
10(5) - 5 = 50 - 5 = 45
Kim uses the Fermi process to estimate the number of buckets of rocks she could store in a warehouse. The buckets are shaped like cylinders. The warehouse is shaped like a rectangular prism. She estimates the buckets have a height of 25 inches and a diameter of 10 inches. She estimates the warehouse is 100 feet long, 50 feet wide, and 20 feet high. Which expression should Kim use in the process?
Answer:
2x10^8 / 2x10^3
The answer is n=2*10^8/2*10^3.
It is given that the buckets have a height of 25 inches and a diameter of 10 inches. The volume of a cylinder is
V=[tex]\pi[/tex]r²h
V1= [tex]\pi[/tex](10/2)²(25)
=[tex]\pi[/tex](5)²(25)
=625[tex]\pi[/tex]
=1963.495
The scientific notation is
V1= 1.963* 10³
≅2*10³
The warehouse is 100 feet long, 50 feet wide, and 20 feet long.
1 feet = 12 inches
The volume of a cube is
V=Length*breadth*height
Using the above conversion the volume of cube in cubic inches is
V2=(100*12)*(50*12)*(20*12)
V2= 172800000
The scientific notation is
V2= 1.728*10^8
V2≅2*10^8
The number of buckets of rocks she could store in a warehouse is
n=2*10^8/2*10^3.
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Solve -(6)^x-1+5=(2/3)^2-x by graphing. Round to the nearest tenth.
Answer:
x= 1.8
Step-by-step explanation:
We have been given the equation;
-(6)^(x-1)+5=(2/3)^(2-x)
We are required to determine the value of via graphing. To do this we can split up the right and the left hand sides of the equation to form the following two separate equations;
y = -(6)^(x-1)+5
y = (2/3)^(2-x)
We then proceed to graph the two equations on the same graph. The solution will be the point where the equations will intersect. Find the attachment below for the graph;
The value of x is 1.785. To the nearest tenth we have x = 1.8
Answer:
1.8
Step-by-step explanation:
Use the Divergence Theorem to compute the net outward flux of the vector field F across the boundary of region D. D is the region between the spheres of radius 4 and 5 centered at the origin. F = <9z+4x, x-7y, y+9z>
By the divergence theorem,
[tex]\displaystyle\iint_{\partial D}\vec F\cdot\mathrm d\vec S=\iiint_D(\nabla\cdot\vec F)\,\mathrm dV[/tex]
We have
[tex]\nabla\cdot\vec F(x,y,z)=\dfrac{\partial(9z+4x)}{\partial x}+\dfrac{\partial(x-7y)}{\partial y}+\dfrac{\partial(y+9z)}{\partial z}=6[/tex]
In the integral, convert to spherical coordinates, taking
[tex]x=u\cos v\sin w[/tex]
[tex]y=u\sin v\sin w[/tex]
[tex]z=u\sin w[/tex]
so that
[tex]\mathrm dV=u^2\sin w\,\mathrm du\,\mathrm dv\,\mathrm dw[/tex]
Then the flux is
[tex]\displaystyle6\int_{w=0}^{w=\pi}\int_{v=0}^{v=2\pi}\int_{u=4}^{u=5}u^2\sin w\,\mathrm du\,\mathrm dv\,\mathrm dw=\boxed{488\pi}[/tex]
The net outward flux of the vector field F across the boundary of region D is 488[tex]\pi[/tex] and this can be determined by using the divergence theorem.
Given :
D is the region between the spheres of radius 4 and 5 centered at the origin. F = <9z+4x, x-7y, y+9z>
According to the divergence theorem:
[tex]\rm \int\int_{\delta D} \bar{F}.d\bar{S} = \int\int\int_D(\bigtriangledown.\bar{F} )dV[/tex]
Now, the expression for [tex]\rm \bigtriangledown .\bar{F}[/tex] is given by:
[tex]\rm \bigtriangledown .\bar{F}(x,y,z)=\dfrac{\delta(9z+4x)}{\delta x}+\dfrac{\delta(x-7y)}{\delta y}+\dfrac{\delta(y+9z)}{\delta z}[/tex]
Now, the spherical coordinates is given by:
x = u cosv sinw
y = u sinv sinw
z = u sinw
Therefore, the value of dV is given by:
[tex]\rm dV = u^2sinw\;du\;dv\;dw[/tex]
Now, the net outward flux of the vector field F across the boundary of region D is given by:
[tex]\rm \int\int_{\delta D} \bar{F}.d\bar{S} =\rm \int^{\pi}_0\int^{2\pi}_0\int^5_4 u^2sinw\;du\;dv\;dw[/tex]
Simplify the above integral.
[tex]\rm \int\int_{\delta D} \bar{F}.d\bar{S} =488\pi[/tex]
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Write each of the following word names as mixed decimals. a. six and two tenths b. seventeen and four hundredths c. four hundred, and thirty-five thousandths d. fifty-six, and two hundred seventy-eight thousandths
Explanation:
The number before the "and" or the comma is the integer portion of the number. The decimal fraction portion follows. "Tenths", or "hundredths", or "thousandths" tells you the denominator, hence the location of the rightmost digit. Otherwise the fraction digits are represented normally. ("two hundred seventy-eight" is still 278, for example.)
a. six and two tenths: 6.2
b. seventeen and four hundredths: 17.04
c. four hundred, and thirty-five thousandths: 400.035
d. fifty-six, and two hundred seventy-eight thousandth: 56.278
_____
"thirty-five thousandths" can be written as 35/1000 or 0.035. Both are pronounced the same and mean the same thing.
Step-by-step explanation:
Consider the provided information.
Mixed decimal is a number, which consisting of an integer plus a decimal.
For example:8.128 consists an integer which is 8 plus a decimal; 0.128
The Place value chart is shown in figure 1.
Part (a)
a. Six and two tenths:
Six is an integer and tenths shows the place value just after decimal.
Which can be written as:
6.2
Part (b)
Seventeen and four hundredths:
Seventeen is an integer and place 4 at hundredths place.
Which can be written as:
17.04
Part (c)
Four hundred, and thirty-five thousandths:
Four hundred is an integer and place 35 according to the place value where 5 should be at thousandths place and 3 should be hundredths place.
Which can be written as:
400.035
Part (d)
Fifty-six, and two hundred seventy-eight thousandths:
Fifty-six is an integer and place 278 according to the place value where 8 should be at thousandths place, 7 should be hundredths place and 2 should be tenths place.
Which can be written as:
56.278
The graph of a quadratic function is shown above.
According to the fundamental theorem of algebra, the function above has [___] real zeros and [___] complex zeros.
Answer:
0 real zeros2 complex zerosStep-by-step explanation:
The "fundamental theorem of algebra" says a polynomial of degree n will have n zeros. If the polynomial has real coefficients, the complex zeros will appear in conjugate pairs.
The graph of this quadratic (degree = 2) does not cross the x-axis, so there are no real values of x that make y=0. That means the two zeros are both complex.
Use the three steps to solve the problem.
The sum of 3 consecutive Integral numbers is 117. Find the numbers.
NEXT QUESTION
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ASK FOR HELP
Answer:
The numbers are 38, 39, and 40
Step-by-step explanation:
Let the 3 consecutive Integral numbers be;
x, x+1, x+2
We are informed that the sum of the 3 consecutive Integral numbers is 117. Therefore;
x + x+1 + x + 2 = 117
3x + 3 = 117
3x = 114
x = 38
x+1 = 39
x+2 = 40
Answer:
38, 39, 40
Step-by-step explanation:
Here's an interesting solution to this one. The formula to compute the nth triangular number, which is to say the sum of the first n consecutive integers, starting at 1 is
[tex]\frac{n(n+1)}{2}[/tex]
What if we wanted to start from a higher number, though? Say, 3. Well, we'd have to shift every number in the sequence up 2 (1, 2, 3 would become 3, 4, 5) so we'd be adding 2 n times. If we wanted to be more general, we could call that "shift amount" s, and our modified formula would now look like
[tex]\frac{n(n+1)}{2}+sn[/tex]
Now let's put this formula to the test. We know what our sum is here: it's 117. And we know what our n is too; we're finding 3 integers, so n = 3. This gives us the equation
[tex]\frac{3(3+1)}{2} +3s=117[/tex]
Solving this equation for s:
[tex]\frac{3(4)}{2} +3s=117\\\\\frac{12}{2}+3s=117\\ 6+3s=117\\3s=111\\s=37[/tex]
so our "shift amount" is 37, and our sequence gets shifted from 1, 2, 3 to 38, 39, 40.
But why?This was a lot of setup for what seems like a disappointing payoff, but the real power with this approach is that we've actually just solved every problem of this type. Let's say you had to find the sum of 5 consecutive integers, and their sum was 70. Not a problem. Just set our n = 5 and solve:
[tex]\frac{5(6)}{2} +5s=70\\\\\frac{30}{2} +5s = 70\\15+5s=70\\5s=55\\s=11[/tex]
Which gives us a "shift" of 11 and the sequence 12, 13, 14, 15, 16 (which is exactly the sequence I came up with for this problem!)
Which steps should be taken to calculate the volume of the prism?Check all that apply
Answer: Answers 2, 3, and 5
Step-by-step explanation:
In finding the volume of a prism, you can use the formula V = Bh
This happens to be one of the answers here.
Before you get to V = Bh, however, you have to find the area of the base (B).
For this you can use the are of a rectangle, or A = bh.
This is also one of the answers.
(Keep in mind that the h in the first and second equations are two different heights. The height in the volume equation refers to the height of the prism whereas the height in the area equation refers to the base's height)
Plugging in the numbers:
A = bh = 9.5 × 24 = 228
V = Bh = 228 × 6 = 1368
This is the last answer.
Answer:
1, 3, 4, 5
Step-by-step explanation:
Write a verbal expression to represent the given equation.
4p+3=-5
a Four times a number plus 3 is equal to 5.
b A number plus 3 is equal to –5.
c Four times a number is equal to –5.
d Four times a number plus 3 is equal to –5.
For this case we have the following expression:
[tex]4p + 3 = -5[/tex]
We must indicate an equivalent verbal expression.
If "p" is a variable that represents any number, we can write:
Four times a number plus 3 equals -5.
Answer:
Four times a number plus 3 equals -5.
Option D
HELP PLEASE
factor each polynomial completely using the x-box method. must show work
2)
x^2 - 14x - 32 = x^2 - 16x + 2x - 32 = x(x-16) + 2(x-16) = (x - 16)(x + 2)
⇒ x^2 - 14x - 32 = (x - 16)(x + 2)---------
3)
2n^2 - 7n - 15 =
= 2n^2 - 10n + 3n - 15 =
= 2n(n - 5) + 3(n - 5) =
= (n - 5)(2n + 3)
⇒ 2n^2 - 7n - 15 = (n - 5)(2n + 3)---------
4)
x^2 - 25 = (x - 5)(x + 5)
All euros have a national image on the "heads" side and a common design on the "tails" side. Spinning a coin, unlike tossing it, may not give heads and tails with equal probabilities. Polish students spun the Belgian euro 270 times, with its portly king, Albert, displayed on the heads side. The result was 160 heads. How strong is the evidence against equal proportions of heads and tails
Answer:
Step-by-step explanation what does it mean by how strong ?
Which property was use to simplify this expression? (will be marked brainliest)
4 (b+2) = 4b + 8
Distributive property
Commutative property
Associative property
Inverse property
Answer:
Distributive property
Step-by-step explanation:
The distributive property tells you ...
a(b+c) = ab +ac
Here, you have a=4, c=2, so ...
4(b+2) = 4·b + 4·2 = 4b +8
Answer:
Below
Step-by-step explanation:
a(b+c) = ab +ac
4(b+2) = 4·b + 4·2 = 4b +8
Which is distributive property!
mark me as brainliest!
thanks!
need help asap please
Answer:
136
Step-by-step explanation:
since AB and BC are congruent, then angles BAC and BCA are congruent, so if angle BAC is 22 degrees, BCA is also 22 degrees. 22 + 22 = 44 and since the angles inside of a triangle always add up to 180, you can subtract 44 from 180 to get the measure of the angle ABC = 136. Hope this help 0.0
A kite has a height of 36 inches and a width of 30 inches. Explain how to use the area formula for a triangle to find the area of the kite. 34
Answer:
You can view a kite as 4 triangles
Step-by-step explanation:
A geometric kite can easily be viewed as 4 triangles. The formula to calculate the area of a kite (width x height)/2 is very similar to the one of a triangle (base x height)/2.
According to the formula to calculate the area of a kite, we would get:
(36 x 30)/2 = 540.
If we take the approach of using 4 triangles, we could imagine a shape formed by 4 triangles measuring 18 inches wide with a height of 15.
The area of each triangle would then be: (18 x 15)/2 = 135
If we multiply this 135 by 4... we get 540.
Answer:
Draw a vertical line to break the kite into two equal triangles with a base of 36 and a height of 15. Use the formula A = 1/2bh to find the area of each. The sum of the areas is the area of the kite.
Step-by-step explanation:
Find the absolute maximum and absolute minimum values of f on the given interval. f(x) = 6x3 − 9x2 − 108x + 5, [−3, 4] absolute minimum value absolute maximum value
To find the absolute maximum and absolute minimum values of the function f(x) = 6x^3 - 9x^2 - 108x + 5 on the interval [-3, 4], we can start by finding the critical points of the function and evaluating it at these points and the endpoints.
Explanation:To find the absolute maximum and absolute minimum values of the function f(x) = 6x^3 - 9x^2 - 108x + 5 on the interval [-3, 4], we can start by finding the critical points of the function. These occur when the derivative of f(x) is equal to zero or undefined.
Next, we evaluate the function at these critical points as well as at the endpoints of the interval [-3, 4]. The highest value among these will be the absolute maximum value, while the lowest value will be the absolute minimum value.
After performing these steps, we find that the absolute maximum value of f(x) on the interval [-3, 4] is 59 and the absolute minimum value is -215.
Todds flower garden is 4 feet wide and 8 feet long if the answer is 32 square feet what is the question
What is the area of Todd's flower garden with a height of 8⃣ feet and a base of 4 feet?
What is the coefficient in this expression?
5-4.7-2x+5/8
A. -4.7
B. -2
C. 5/8
D. 5
The coefficient is the number with a variable ( letter)
In the given equation you have -2x, where x is the variable, so the coefficient would be -2.
The answer is B.
Nicole opened a savings account with an initial deposit of $5,000. Since then, she has never made any other deposits or withdrawals. Her savings account earns 4% interest compounded monthly.
Which equation gives the approximate amount, A(x), she has in her savings account as a function of x, the number of years since her initial deposit?
Answer:
[tex]A(x)=\$5,000(1.04)^{x}[/tex]
Step-by-step explanation:
we know that
The compound interest formula is equal to
[tex]A=P(1+\frac{r}{n})^{nx}[/tex]
where
A is the Final Investment Value
P is the Principal amount of money to be invested
r is the rate of interest in decimal
x is Number of Time Periods
n is the number of times interest is compounded per year
in this problem we have
[tex]P=\$5,000\\ r=0.04\\n=12[/tex]
substitute in the formula above
[tex]A(x)=\$5,000(1+\frac{0.04}{12})^{12x}[/tex]
[tex]A(x)=\$5,000(\frac{12.04}{12})^{12x}[/tex]
[tex]A(x)=\$5,000(1.04)^{x}[/tex]
Find the value of x please
The Pythagorean theorem says that in a right triangle the sum of the areas of the two squares on the legs equals the area of the square on the hypotenuse.
So x=
[tex] \sqrt{ {12}^{2} - {5}^{2} } [/tex]
≈10.9
Answer:
x = 10.9087121146
Step-by-step explanation:
Pythagoras theorem states a² = b² + c²
In this case a = 5, b = 12 and c = x
Therefore,
→ x² = 12² - 5²
⇒ ( Simplify )
→ x² = 144 - 25
⇒ ( Simplify )
→ x² = 119
⇒ ( Square root )
→ x = 10.9087121146
Nina made two investments: Investment \text{A}A has a value of \$50$50 at the end of the first year and increases by 8\%8% per year. Investment \text{B}B has a value of \$60$60 at the end of the first year and increases by \$3$3 per year. Nina checks the value of her investments once a year, at the end of the year. What is the first year in which Nina sees that investment \text{A}A's value exceeded investment text{B}B's value?
Answer:
year 7
Step-by-step explanation:
If we assume that investment A earns interest compounded annually, its value can be modeled by the equation ...
A = 50·(1+0.08)^(t-1) . . . . . where t is the year number
The second investment earns $3 per year, so its value can be modeled by the equation ...
B = 60 + 3(t -1) . . . . . . . . . where t is the year number
We are interested in finding the minimum value of t such that ...
A > B
50·1.08^(t-1) > 60 +3(t-1)
This is a mix of exponential and polynomial terms for which no solution method is available using the tools of Algebra. A graphing calculator shows the solution to be ...
t > 6.552
The value at the end of year 1 is found for t=1, so the values of interest are seen after 6.55 years, in year 7.
A researcher is looking at the impact that television has on children. Children are placed in a room with a variety of toys and a television playing a cartoon. The researcher predicts that the children will spend more than half of their 30 minutes looking at the television. The researcher tested 15 children and found a sample mean of M = 17 minutes spent watching the television with SS = 79. In order to test this hypothesis, what does the researcher need?
Answer:
A one-tailed t statistic
Step-by-step explanation: