a)
At constant pressure, the work done for gas to expand is given by:
W = PΔV
⇒W = 1.65 × 10⁵Pa × (0.320 - 0.110)m³= 3.46 × 10⁴J
b)
The total heat (Q) added to the system is used in work done and the remaining energy goes into internal energy.
ΔU = ΔQ-ΔW
⇒ΔU = 1.15 ×10⁵J - 3.46 × 10⁴J = 0.8 × 10⁵ J
c)
It does not matter that the gas is ideal or real because the work done would remain same. It would vary for real gases only at very high pressure.
(a). The work done by the gas is [tex]\boxed{3.47 \times {{10}^4}\,{\text{J}}}[/tex].
(b). The change in the internal energy of the gas is [tex]\boxed{8.03 \times {{10}^4}\,{\text{J}}}[/tex].
(c). There is no effect of the gas being ideal gas or real gas on the work done by the gas.
Further Explanation:
Given:
The initial volume of the gas is [tex]0.110\,{{\text{m}}^{\text{3}}}[/tex] .
The final volume of the gas is [tex]0.320\,{{\text{m}}^{\text{3}}}[/tex] .
The constant pressure at which the expansion of the gas takes place is [tex]1.65 \times {10^5}\,{\text{Pa}}[/tex] .
The amount of heat added to the gas is [tex]1.15 \times {10^5}\,{\text{J}}[/tex].
Concept:
Part (a):
The expansion of the gas is taking place at constant pressure. Therefore, the work done by the gas is:
[tex]W = P\left( {{V_f} - {V_i}}\right)[/tex]
Here, [tex]P[/tex] is the pressure and [tex]{V_f}[/tex] is the final volume and [tex]{V_i}[/tex] is the initial volume of the gas.
Substitute the values of [tex]P[/tex] , [tex]{V_i}[/tex] and [tex]{V_f}[/tex] in above expression .
[tex]\begin{aligned}W&= \left( {1.65 \times {{10}^5}} \right) \times \left( {0.320 - 0.110} \right)\\&= 3.465 \times {10^4}\,{\text{J}}\\&\approx 3.{\text{47}} \times {\text{1}}{{\text{0}}^4}\,{\text{J}}\\\end{aligned}[/tex]
Therefore, the work done by the gas is [tex]\boxed{3.47 \times {{10}^4}\,{\text{J}}}[/tex]
Part (b):
The change in internal energy of the gas is given by the first law of thermodynamics:
[tex]\begin{aligned}\Delta Q = \Delta U + W \hfill\\\Delta U = \Delta Q - W \hfill\\\end{aligned}[/tex]
Here, [tex]\Delta Q[/tex] is the heat added, [tex]\Delta U[/tex] is the change in internal energy of system and [tex]W[/tex] is the work done by the gas.
Substitute the values of [tex]\Delta Q[/tex] and [tex]W[/tex] in above equation.
Part (c):
The ideal gas or the real gas does not affect the process of the expansion of gas because the change in energy of the gas is given by the First law of thermodynamics. The first law of thermodynamics is based on the conservation of energy.
The energy of a system will always remain conserved whether it has the real gas or the ideal gas.
Thus, there is no effect of the gas being ideal gas or real gas on the work done by the gas.
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Answer Details:
Grade: High School
Subject: Physics
Chapter: Law of Thermodynamics
Keywords: Ideal gas, cylinder, first law of thermodynamics, pressure constant, 0.110m^3 to 0.320 m^3, expansion, change in internal energy, work done by gas.
A net force of 125 N accelerates a 25.0 kg mass. What is the resulting acceleration?
Answer: [tex]a=5 m/s^2[/tex]
Explanation:
The acceleration of an object can be calculated by using Newton's second law:
[tex]F=ma[/tex]
where
F is the net force applied on the object
m is the mass of the object
a is its acceleration
In this problem, we have F=125 N and m=25.0 kg, so we can rearrange the equation to calculate the acceleration:
[tex]a=\frac{F}{m}=\frac{125 N}{25.0 kg}=5 m/s^2[/tex]
The radii of the sprocket assemblies and the wheel of the bicycle in the figure are:
4 inches,
2 inches,
and 14 inches respectively.
If the cyclist is pedaling at a rate of 1 revolution per second, find the speed of the bicycle in (a) feet per second and (b) miles per hour.
To find the speed of the bicycle, we can consider the gearing ratio between the sprocket assemblies and the wheel. The speed in feet per second can be calculated using the cyclist's pedalling rate and the circumference of the wheel. We can use conversion factors to convert the speed to miles per hour.
Explanation:In order to find the speed of the bicycle, we need to consider the gearing ratio between the sprocket assemblies and the wheel. The ratio of the radii of the sprocket assemblies and the wheel can be used to determine the wheel's rotational speed.
Let's say the cyclist is pedaling at a rate of 1 revolution per second on the sprocket assembly with a radius of 4 inches. The sprocket assembly is connected to another sprocket assembly with a radius of 2 inches, which is then connected to the wheel with a radius of 14 inches.
The ratio of the radii between the sprocket assembly and the wheel is 14/2 = 7.
Therefore, the speed of the bicycle in feet per second can be calculated by multiplying the cyclist's pedalling rate by the circumference of the wheel:
Speed (feet per second) = 1 revolution/second x 2π x 14 inches = 28π inches/second = 28π/12 feet/second
To find the speed of the bicycle in miles per hour, we can convert the speed from feet per second to miles per hour:
1 mile = 5280 feet and 1 hour = 3600 seconds, so:
Speed (miles per hour) = (28π/12 feet/second) x (5280 feet/1 mile) x (1 hour/3600 seconds)
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A hydraulic press for compacting powdered samples has a large cylinder which is 10.0 cm in diameter, and a small cylinder with a diameter of 2.0 cm. A lever is attached to the small cylinder as shown in The sample, which is placed on the large cylinder, has an area of 4.0 cm2.
What is the pressure on the sample if F = 270 N is applied to the lever?
The hydraulic pressure on sample is [tex]3.35*10^{7} N/m^{2}[/tex].
What is hydraulic pressure?Hydraulic pressure is the force imparted per unit area of a liquid on the surfaces which it has contact.
The magnitude of force acting on the small cylinder is equal to [tex]F_{N}[/tex].
In static equilibrium, all the torques should add up to zero:[tex]F_{N}l - 270(2l)= 0\\F_{N} = 270(2)\\F_{N} = 540 N[/tex]
The pressure applied to the fluid (through the small cylinder):
[tex]P= \frac{540}{\pi (\frac{2*10^{-2} }{2} )^2}[/tex]
[tex]P = 1.71*10^{6} Pa[/tex]
The force of fluid on the large cylinder:
[tex]F= P\pi R^{3} \\F= 1.71*10^{6} \pi (0.05^{2} )\\F= 1.34*10^{4} N[/tex]
The pressure on the sample:
[tex]P_{S} =\frac{F}{A} \\P_{S}= \frac{1.34*10^{4} }{4*10^{-4} } \\P_{S}= 3.35*10^{7} N/m^{2}[/tex]
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Which of these is true about legos? XD (please don`t use google) A. They are for adults (XD)
B. They are made out of plastic
C. They are awesome (XD)
Answer:
B
Explanation:
On earth you have a mass of 70 kg and a weight of approximately 700 N. The planet Mars has an acceleration due to gravity that is approximately 0.38 times as much as the earth (3.7 ms 2 ). Which statement would be true if you were on Mars?
A) Your mass would be 26.6 kg.
B) Your weight would be 266 N.
C) Your weight would be 1842 N.
D) Your mass would be 184.2 kg.
On Mars, your mass would be 26.6 kg.
Explanation:On Mars, the weight of an object is calculated by multiplying its mass by the acceleration due to gravity on Mars, which is approximately 0.38 times the acceleration due to gravity on Earth. Since your mass remains the same at 70 kg, the weight on Mars would be 70 kg multiplied by 0.38, which equals 26.6 kg. Therefore, statement A, which says that your mass would be 26.6 kg on Mars, is true.
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Will Upvote!!
If the mass of two objects increases, the force of gravity between them
increases
decreases
remains the same
could increase or decrease, depending on the shape of the objects
Why is the combination of two protons and two neutrons stable, but two protons and one neutron is not?
Answer:
There are not enough neutrons to overcome the electrical repulsion of the protons.
Explanation:
Neutrons help stabilize a nucleus by attracting other nucleons (protons and neutrons). Although protons also attract other nucleons using the strong nuclear force, they repel other protons with the electrical force.
Hope this helps!
When comparing two circuits, you note that circuit one has twice the voltage and half the resistance of circuit two. This means that
Answers:
1. both circuits will have the same current.
2. both circuits will have alternating current.
3. circuit two will have more current.
4. circuit one will have more current.
...?
Answer: option 4: circuit one will have more current.
Explanation:
Ohm's law states that the current in a circuit is proportional to voltage.
[tex]I \propto V \\ \Rightarrow I=\frac{V}{R}[/tex]
Let the current in the first circuit be I, voltage be V and resistance be R, the,
[tex]I_1=\frac{V_1}{R_1}[/tex]
The voltage in the second circuit is
[tex]V_2=\frac{V_1}{2}[/tex]
The resistance in the second circuit is:
[tex]R_2=2R_1[/tex]
[tex]\Rightarrow I_2=\frac{V_2}{R_2}=\frac{V_1/2}{2R_1}=\frac{I_1}{4}[/tex]
Hence, circuit one has 4 times more current than circuit two.
What is the the steadiest firing position?
Which of the following is the correct unit for force?
A. Watts
B. Joules
C. Meters
D. Newton
a toy car moves 8 m in 4 s at the constant velocity. whats the car's velocity?
The velocity of the toy car is 2m/s.
HOW TO CALCULATE VELOCITY:
The velocity of a body, also called its average speed, can be calculated by dividing the distance traveled by that body by the time taken. That is;Velocity (m/s) = Distance (m) ÷ time (s)
According to this question, a toy car moves 8m in 4s. The velocity of the toy car can be calculated as follows:Velocity = 8m ÷ 4s
Velocity = 2m/s.
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A rock is dropped from a bridge. what happens to the magnitude of the acceleration and the speed of the rock as it falls?
A falling skydiver has a mass of 105 kg. What is the magnitude of the skydiver's acceleration when the upward force of air resistance has a magnitude that is equal to one-half of his weight?
The magnitude of the skydiver's acceleration when the upward force of air resistance is half of his weight is 4.9 m/s² downward. This is found using Newton's Second Law and the skydiver's weight calculated from his mass and the acceleration due to gravity.
Explanation:When the upward force of air resistance is equal to one-half of the skydiver's weight, the net force on the skydiver is only half of his weight acting downward. The skydiver's weight (W) can be calculated using the equation W = mg, where m is the mass and g is the acceleration due to gravity. For a mass (m) of 105 kg and assuming the acceleration due to gravity (g) is approximately 9.8 m/s2, the skydiver's weight would be 105 kg × 9.8 m/s2 = 1029 N. Half of this weight is 1029 N / 2 = 514.5 N.
According to Newton's Second Law (F = ma), the net force is equal to the mass multiplied by the acceleration. In this case, the net force is also the unbalanced force acting on the skydiver, which is half the skydiver's weight. Therefore, we have F = ma, which means 514.5 N = 105 kg × a. Solving for a, the acceleration, we get a = 514.5 N / 105 kg which is approximately 4.9 m/s2. Therefore, the magnitude of the skydiver's acceleration in this case is 4.9 m/s2 downward.
An object is dropped from a 400-ft tower.
a) when does it hit the ground?
b) how fast is it going at the time of impact?
So,a)It will hit ground at 4.52seconds.b)At 145 ft/s fast is it going at the time of impact
An object is dropped from a 400-ft tower:
a) When does it hit the ground? Using the formula: time = [tex]\sqrt[1]{2*height/g}[/tex], where g is the acceleration due to gravity (32 ft/s²), the time taken to hit the ground is approximately 4.52 seconds.
b) How fast is it going at the time of impact? The velocity of the object when it hits the ground can be calculated as velocity = g * time, which gives a velocity of about 145 ft/s.
If two objects are traveling at the same speed, why might one object have more inertia than another object? Give an example of two objects for which this is true?
Answer:
The object has larger mass. Examples would be like-cars of a different build driving at the same mph, or animals that typically run at the same speed but have different weights.
Explanation:
The more inertia that an object has, the more mass that it has.
find the magnitude: || 5-3i || ...?
An archer pulls back the string of a bow to release an arrow at a target. Which kind of potential energy is transformed to cause the motion of the arrow?
Answer: elastic potential energy
Explanation:
The form of energy stored in the string of the bow is elastic potential energy. Elastic potential energy is the energy stored in an elastic object (such as the string of a bow) when the object is compressed/stretched by a certain amount x with respect to its natural length. The elastic potential energy stored in the object is given by
[tex]U=\frac{1}{2}kx^2[/tex]
where k is the spring constant of the elastic string, and x is the compression/stretching.
Which of the following statements is true?
-the freezing and boiling temperatures of a substance are the same.
-the freezing and condensation temperatures of a substance are the same.
-the freezing and melting temperatures of a substance are the same.
-the freezing, melting, and boiling temperatures of a substance are the same.
Please help!!
Correct answer choice is :
C) The freezing and melting temperatures of a substance are the same.
Explanation:
Fluids have a particular temperature at which they convert into solids, identified as their freezing point. In theory, the melting point of a solid should be the same as the freezing point of the liquid. In practice, small variations among these measures can be seen. The freezing point of a matter is the same as that substance's melting point. At this distinct temperature, the substance can exist as either a solid or a liquid. At temperatures below the freezing/ melting point, the substance is a solid.
Answer: The correct answer is "The freezing and melting temperatures of a substance are the same".
Explanation:
Freezing temperature: It is the temperature at which the liquid becomes the solid.
Melting temperature: It is the temperature at which the solid starts converted into liquid.
The freezing point of a substance is the same as the melting point of the substance. During melting and freezing of the substance, the temperature remains same as the energy is spent in changing the phase of the substance not in changing the temperature.
Latent heat is there. It is a hidden heat. It is required to change phase of the substance without showing temperature on thermometer.
Boiling temperature: It is the temperature at which liquid gets converted into vapors. At this temperature, vapor pressure of the liquid equals to the pressure surrounding the liquid.
Until a train is a safe distance from the station, it must travel at 5 m/s. Once the train is on open track, it can speed up to 45 m/s. If it takes a train 8 seconds to reach 45 m/s, what is the acceleration of the train?
______ m/s2
Answer: accelration=changespeed/changetime
changetime=8
changespeed=45-5=40
40/8=5
5m/s^2 is acceleration
Explanation:
A VW Beetle goes from 0 to 60.0 mi/h with an acceleration of +2.35 m/s^2. (a) How much time does it take for the beetle to reach this speed? (b) A top-fuel dragster can go from 0 to 30 mi/h in 0.600 s. Find the acceleration (in m/s^2) of the dragster?
The VW Beetle takes 25.53 seconds to reach a speed of 60.0 mi/h with an acceleration of 2.35 m/s². The top-fuel dragster has an acceleration of 22.36 m/s² to go from 0 to 30 mi/h in 0.600 seconds.
Explanation:To calculate the time it takes for the VW Beetle to reach a speed of 60.0 mi/h, we need to use the equation v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time taken. Rearranging the equation to solve for t, we have t = (v - u) / a. Plugging in the values, we get t = (60.0 mi/h - 0) / 2.35 m/s² = 25.53 s.
To find the acceleration of the top-fuel dragster, we use the equation a = (v - u) / t, where a is the acceleration, v is the final velocity, u is the initial velocity, and t is the time taken. Rearranging the equation to solve for a, we have a = (v - u) / t. Plugging in the values, we get a = (30 mi/h - 0) / 0.600 s = 50 mi/h/s = 22.36 m/s².
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A car travels around a racetrack at aconstant speed. During what parts of the coursedoes the car experience acceleration?
Answer:
If the racetrack’s length is 36 inches and is set to a height of 8 inches, 16 inches and 24 inches and each roll of the toy car is 7.8 seconds, 7.3 seconds and 6.6 seconds respectively, then, it only shows that the higher the racetrack, the faster the toy car will roll down because velocity, which measures how fast something is moving, is affected by gravity. Motion, as shown in this kind of scenario, is a kind of concept that depicts movement or change in position under given circumstances or factors over a period of time.
Explanation:
a lift is ascending with acceleration g/3. what will be the time period of a simple pendulum suspended from the ceiling if its time period in stationary lift is T ...?
Shawn runs 4 times around a 400 meter oval track and stops at the same point he sstarted
a projectile is fired with an initial speed of 500m/s and angle of elevation 30 degrees. find the range, max height and speed at impact
To find the range, maximum height, and speed at impact of a projectile fired with an initial speed of 500m/s and angle of elevation 30 degrees, we can use the equations of projectile motion.
Explanation:To find the range, maximum height, and speed at impact of a projectile fired with an initial speed of 500m/s and angle of elevation 30 degrees, we can use the equations of projectile motion.
Range: The horizontal distance covered by the projectile is the range. In this case, we can use the formula:
R = (V02 * sin(2θ)) / g
where R is the range, V0 is the initial speed, θ is the angle of elevation, and g is the acceleration due to gravity.
Substituting the given values into the formula, we have:
R = (5002 * sin(2 * 30)) / 9.8
R = (250000 * sin(60)) / 9.8
R ≈ 1450.83 meters
Maximum Height: The maximum height reached by the projectile can be found using the formula:
H = (V02 * sin2(θ)) / (2 * g)
Substituting the given values into the formula:
H = (5002 * sin2(30)) / (2 * 9.8)
H ≈ 3060.45 meters
Speed at Impact: The speed at impact is the magnitude of the velocity of the projectile when it hits the ground. Since the projectile is fired at an angle and lands at a lower height than its initial position, the speed at impact will be lower than the initial speed. However, we need more information to calculate the exact speed at impact.
if i jump on a trampoline. is it an inelastic or elastic collision?
How much work is done when a 48-kg stack of books are lifted 2m with a net force of 25 N ?
A. 12.4 J
B. 100 J
C. 50 J
D. 96 J ...?
Answer:
C). W = 50 J
Explanation:
As we know that the work done is the product of force and displacement
so here it is given that the net force on the stack of books is 25 N
[tex]F = 25 N[/tex]
also the displacement of the stack of books is 2m as it is lifted upwards
so we have
[tex]d = 2 m[/tex]
now by the formula of work done we know
[tex]W = F.d[/tex]
now plug in all values in it
[tex]W = (25)(2)[/tex]
[tex]W = 50 J[/tex]
Which of the following best describes the difference between speed and acceleration? A. Acceleration is the distance an object travels within a specific unit of time, whereas speed is the rate at which the acceleration or direction of an object is changing.
B. Speed is the distance an object travels within a specific unit of time, whereas acceleration is the rate at which the speed or direction of an object is changing.
C. Acceleration is the distance an object travels within a specific unit of time, whereas speed is a measure of the force necessary to change the acceleration of an object.
D. Speed is the distance an object travels within a specific unit of time, whereas acceleration is a measure of the force necessary to change the speed of an objectWhich of the following best describes the difference between speed and acceleration? A. Acceleration is the distance an object travels within a specific unit of time, whereas speed is the rate at which the acceleration or direction of an object is changing.
B. Speed is the distance an object travels within a specific unit of time, whereas acceleration is the rate at which the speed or direction of an object is changing.
C. Acceleration is the distance an object travels within a specific unit of time, whereas speed is a measure of the force necessary to change the acceleration of an object.
D. Speed is the distance an object travels within a specific unit of time, whereas acceleration is a measure of the force necessary to change the speed of an object.
Answer:
Speed is the distance an object travels within a specific unit of time, whereas acceleration is the rate at which the speed or direction of an object is changing.
(Apex) Pretest
The option that best describes the difference between speed and acceleration is : ( B ) Speed is the distance an object travels within a specific unit of time, whereas acceleration is the rate at which the speed or direction of an object is changing.
Difference between and Acceleration and SpeedAcceleration is the rate of change of velocity with time while speed is the rate of change distance with time.
Acceleration is a vector quantity because it has magnitude and direction while speed is a scalar quantity.
Hence we conclude that Speed is the distance an object travels within a specific unit of time, whereas acceleration is the rate at which the speed or direction of an object is changing.
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what two kinds of motion combine to to produce projectile motion
based on the law of conservation of energy. how can we reasonably improve a machines ability to do work? A.move the machine to a different gravitational field B.increase the friction between its moving parts C. reduce the friction between its moving parts or D. redefine the machines system boundaries?
The correct answer is
C. reduce the friction between its moving parts
In fact, by reducing the friction between the moving parts of the machine, it is possible to reduce the energy wasted due to this friction; therefore, more input energy is converted into useful work, and this will improve the efficiency of the machine.
Answer: We can reasonably improve a machines ability to do work by reducing the friction between the moving parts of machine. The correct answer is C.
Explanation:
According to the law of conservation of energy, the energy can neither be created nor destroyed. The energy can be converted from one form to another.
The energy is wasted due to the friction. It reduces the efficiency of the machines to do the work. There will be energy loss due to the friction. By reducing the friction, More energy can be converted into the work.
Therefore, we can reasonably improve a machines ability to do work by reducing the friction between the moving parts of machine.
Classify which is specific defense or nonspecific defense:
- skin
- macrophages
- bacteria
- mucous
- fever
- B cells
- T cells
- antibodies