PLEASE HELP!!

What is the length of the midsegment of this trapezoid?

Enter your answer in the box.

PLEASE HELP!!What Is The Length Of The Midsegment Of This Trapezoid?Enter Your Answer In The Box.

Answers

Answer 1

Answer:

7 units

Step-by-step explanation:

PLEASE HELP!!What Is The Length Of The Midsegment Of This Trapezoid?Enter Your Answer In The Box.
Answer 2

The length of the midsegment of this trapezoid will be 7 units.

What is mean by Rectangle?

A rectangle is a two dimension figure with 4 sides, 4 corners and 4 right angles. The opposite sides of the rectangle are equal and parallel to each other.

Given that;

The coordinates of the vertices of the trapezoid are,

A = (-2, 4)

B = (4, 3)

C = (4 , -5)

D = (- 2, - 2)

Now,

Since, We know that;

The length of the midsegment of a trapezoid is always equal to the half of the sum of the parallel sides.

Here, Line AD and BC are parallel lines.

And, The length of AD = √(- 2 - (-2))² + (- 2 - 4)²

                                   = √-6²

                                  = 6

And, The length of BC = √(4 - 4)² + (- 5 - 3)²

                                   = √-8²

                                   = 8

Thus, The length of the midsegment of this trapezoid = (6 + 8)/2

                                                                                    = 14/2

                                                                                    = 7 units.

Therefore, The length of the midsegment of this trapezoid will be 7 units.

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Related Questions

On anne's bicycle, the ratio of pedal turns to rear-wheel turns in second gear is 4 to 7. if her rear wheel turns 875 times per mile,how many times does she turn the pedal in one mile?hint:set up and solve as a propportion to find x.

Answers

Let the number of times she turns the pedal in one mile be x.

Given that her rear miles turns 875 times in one mile and the ratio of pedal turns to rear wheel turns is 4 to 7, then

[tex] \frac{4}{7} = \frac{x}{875} \\ \\ \Rightarrow 7x=4(875)=3,500 \\ \\ \Rightarrow x= \frac{3,500}{7} =\bold{500}[/tex]

Therefore, she turns the pedal 500 times in one mile.
4 pedal turns (PT) = 7 rear-wheel turns (RT) RT=4PT/7 If RT = 875 xPT = 875RT substituting RT as 4PT/7 xPT = 875*4PT/7 x = 500 Therefore she needs to turn the pedal 500 times to 875 rear-wheel turns in one mile.

what is the solution to 7ln(x+2.8)=11.2

Answers

Attached solution with steps.

To maximize learning, a ________ should be presented on a(n) ________ schedule.

Answers

To maximize learning, a CS + UCS should be presented on a(n) continuous schedule.

 

In here, CS means conditional stimulus while UCS is the unconditioned stimulus. Taking for example, let us imagine that the smell of food is the unconditioned stimulus, the feeling of hunger in response to that specific smell is a unconditioned response, and then the sound of the whistle is the conditioned stimulus.

what is the equation of the graphed line in point-slope form?

a. y – 1 = (x + 3)
b. y – 1 = (x – 3)
c. y + 1 = (x – 3)
d. y + 1 = (x + 3)

Answers

(3,1)(-3,-3)
slope = (-3 - 1) / (-3 - 3) = -4/-6 = 2/3

y - y1 = m(x - x1)
slope(m) = 2/3
(3,1)...x1 = 3 and y1 = 1
now we sub
y - 1 = 2/3(x - 3) <==

Answer:

[tex]y-1 = \frac{2}{3}(x-3)[/tex]

Step-by-step explanation:

To find the equation of graphed line we pick two points from the line

(3,1) and (-3,-3)

Equation of a line is y=mx+b

where 'm' is the slope and b is the y intercept

slope [tex]m= \frac{y2-y1}{x2-x1} =\frac{1+3}{3+3} = \frac{2}{3}[/tex]

we use point slope formula

y-y1= m(x-x1)

here point(x1,y1) is (3,1)  and slope m = 2/3

Plug in all the value

[tex]y-1 = \frac{2}{3} (x-3)[/tex]

Which formula gives the coordinates of the midpoint of the segment connecting points (a,
b.and (c, d)?

Answers

midpoint formula : (x1 + x2)/2 , (y1 + y2)/2
(a,b)...x1 = a and y1 = b
(c,d)...x2 = c and y2 = d

so ur formula would be :
m = (a + c)/2 , (b + d)/2 <==

Answer:

Formula that gives coordinates of the mid point of the segment connecting is [tex](\frac{a+c}{2},\frac{b+d}{2})[/tex]

Step-by-step explanation:

Given point are ( a , b ) and ( c , d )

To find : Coordinates of the mid point of the segment connecting given points.

We know that if point are [tex](x_1,y_1)\:\:and\:\:(x_2,y_2)[/tex]

then coordinate of the midpoints given by [tex](\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})[/tex]

So, Coordinates of the given points = [tex](\frac{a+c}{2},\frac{b+d}{2})[/tex]

Therefore, Formula that gives coordinates of the mid point of the segment connecting is [tex](\frac{a+c}{2},\frac{b+d}{2})[/tex]

Find the percent change from 48 to 228. Tell whether it is a percent increase or decrease. If necessary, round your answer to the nearest percent.

Answers

228 - 48 = 180

180/48 = 3.75

Its increase 375%

Which algebraic expression has a term with a coefficient of 3?

Answers

Greetings!

A coefficient is a constant value, multiplying the variable in an expression/equation.

Examples:
[tex]4x^2+3y^3[/tex]

The coefficient of the second term would be three. 

Hope this helps.
-Benjamin

the correct answer is option (b) 3x² - 7.

The coefficient is the numerical factor in front of the variable. Let's calculate the coefficient for each option:

a) The coefficient of x in 2x is 2, not 3.

b) The coefficient of x² in 3x² is 3, which matches our requirement.

c) The coefficient of x in 4x is 4, not 3.

d) There is no x term in x³ + 2, so the coefficient for x is 0.

Therefore, the correct answer is option (b) 3x² - 7.

In option (b), the term with the coefficient of 3 is 3x². The coefficient of this term is indeed 3 because it's the number multiplied by x squared. The other terms in the expression do not have a coefficient of 3.

In options (a) and (c), the coefficients for the x terms are 2 and 4, respectively, which do not match the requirement.

Option (d) doesn't have an x term; it only has x raised to the power of 3 (x³), and the coefficient for this term is 0.

So, by process of elimination and calculation, we determine that option (b) is the correct answer with the term 3x² having a coefficient of 3.

complete question

Which algebraic expression has a term with a coefficient of 3?

a) 2x + 5  

b) 3x² - 7  

c) 4x - 3  

d) x³ + 2

He measure of an angle is 78° less than the measure of its complement. what is the measure of the angle?

Answers

When we say two angles are complementary, we mean that they add up to a right angle – 90 degrees. Now, we haven’t been given either of the angles directly, but we’ve been given their relationship, and we’ve been given the fact that they’re complementary. If we call the angle’s complement θ, we can express the fact that our angle is 78 degrees less than that with the expression (θ-78). Putting our information together, we have:

θ+(θ-78)=90
2θ-78=90

From there, it’s fairly straightforward algebra; just solve for θ. Remember though, the answer they’re looking for is the (θ-78) term, so make sure to evaluate that once you’ve found θ.

Alex sells cars at Keith Palmer Ford. He earn$400 a week plus $150 per car he sells. if he earn $1450 last week, how many cars did he sell? brainly

Answers

1450-400=1050
1050/150=7
7 cars

How many seconds are there in (a) one hour and thirty-five minutes and (b) one day?

Answers

There are 5700 seconds in an hour.



Ashley is making cookies. the recipe calls for 3/4 of a cup of sugar. she needs to make five batches of cookies. how many cups of sugar does ashley need?

Answers

Ashley needs 3 3/4 cups of sugar.
Hope this helps!!

please show work along with answer:
[tex] \frac{1 + \tan(x) }{1 + \cot(x) } [/tex]

Answers

Hello,

[tex] \dfrac{1+tan(x)}{1+cotg(x)} = \dfrac{1+ \frac{sin(x)}{cos(x)} }{1+ \frac{cos(x)}{sin(x)}} \\\\ = \dfrac{cos(x)+sin(x)}{cos(x)*( \frac{sin(x)+cos(x)}{sin(x)} } )\\\\ = \dfrac{sin(x)}{cos(x)} \\\\ \boxed{=tan(x)}\\\\ [/tex]



The ______ is the total area drained by a river and its tributaries.

Answers

The drainage basin is the total area drained by a river and its tributaries

Solve for 8x please

Answers

The answer is A..... hope this helps :D

8x=-c+k
x=-c+k/8
The first option is the answer

You have exactly 10 minutes to get to class for

your big test on lateral numbers! Your friend Gus

(who’s weirdly in to this sort of thing) says that class

is exactly 10,000 feet away. Let’s say you travel to

class at a rate of r feet/minute. You would like to get

there a few minutes early. More specifically, let’s say

you will arrive t minutes early.


a) Write an equation that relates r and t.

Answers

Rate = distance/Time

Rate = 10000 ft/ 10 min

R = 10000/10

R = 1000

You will have to travel 1000 feet per minute nonstop, or 0.189 miles per minute


hope this helps

Which expressions are equivalent to ? Check all that apply.

Answers

Final answer:

To determine if expressions are equivalent, we simplify them or substitute variables with actual values to see if they yield the same result. We simplify by eliminating terms where possible, grouping like terms, and applying mathematical operations.

Explanation:

Without the original mathematical expressions, it's difficult to provide direct answers to your question. Normally, we determine whether expressions are equivalent by simplifying them using algebraic rules or substituting variable with actual values to see if they produce the same results.

For example, the expressions 2(3 + 5) and 6 + 10 are equivalent because they both simplify to 16. We identify equivalent expressions by simplifying which includes eliminating terms where possible, grouping like terms, and applying mathematical operations.

Ultimately, the exact process may vary depending on the complexity and specific form of the expressions in question.

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The expressions equivalent to [tex]$\sqrt[3]{128}^x$[/tex] are (c) [tex]$(4 \sqrt[3]{2})^x$[/tex] and (d) [tex]$\left(4\left(2^{\frac{1}{3}}\right)\right)^x$[/tex] due to their compatible structures with the original expression.

To determine which expressions are equivalent to [tex]$\sqrt[3]{128}^x$[/tex], let's simplify the given expression first:

[tex]\[\sqrt[3]{128}^x = 2^x \times \sqrt[3]{2}^x\][/tex]

Now, let's compare this with the provided options:

a. [tex]$128^{\frac{x}{3}}$[/tex] - Not equivalent.

b. [tex]$128^{\frac{3}{x}}$[/tex] - Not equivalent.

c. [tex]$(4 \sqrt[3]{2})^x$[/tex] - Equivalent, as [tex]$4 = 2^{\frac{3}{2}}$[/tex].

d. [tex]$\left(4\left(2^{\frac{1}{3}}\right)\right)^x$[/tex] - Equivalent, as [tex]$2^{\frac{1}{3}} = \sqrt[3]{2}$[/tex].

e. [tex]$(2 \sqrt[3]{4})^x$[/tex] - Not equivalent.

Therefore, the expressions (c) [tex]$(4 \sqrt[3]{2})^x$[/tex] and (d) [tex]$\left(4\left(2^{\frac{1}{3}}\right)\right)^x$[/tex] are equivalent to [tex]$\sqrt[3]{128}^x$[/tex].

I need help from a math genius

Answers

The answer to the first one is (B. 24)

The answer to the second is (B. 14)
1. 24=38+(8/8)
2. 14=6+8
3. 5=2+3
4. 10=2X5

Let g(x)=2x and h(x)=x^2+4

(g o h)(0)

Answers

Answer would be 0 because whatever you get when you plug in g&h in the equation you have to multiply that by 0. And a number multiplied by 0 is always 0.
Hope this helped. Have a great day!

y=x+2;x=-3 solve each system by graphing step by step

Answers

I will solve for you right now.
to graph a line, you need to use the equation y=mx+b
y=x+2
go to the positive number 2 on the y-axis and plot a point
now, since its postive, your line is gonna go like this:
            p
          p 
       p
     p
   p   
p
so go up one, and to the right one from the 2 on the y-axis
and then go down one, to the left one from the 2 on the y-axis
connect the dots and this is your first line

now for the second line, go to the -3 on the x-axis and draw a vertical line up and down
this is your second line
now find where the two lines interesect and that is your answer

it'll be a point and look something like this if you write it out (x,y)
take the two points out nd write your answer in this form: x=a, y=b

tah dah!

What numbers have the absolute value of 1/2

Answers

1/2 and -1/2

hope it helps, brianliest pls

How do you solve rearranging equations

Answers

step one: you can add, subtract, multiply and divide by anything, as long as you do the same thing to both sides of the equals sign. In an equation, the equals sign acts like the fulcrum of a balance: if you add 5 of something to one side of the balance, you have to add the same amount to the other side to keep the balance steady. The same thing goes for an equation - doing the same operation to both sides keeps the meaning of the equation from changing.Show me an examplestep two: to move or cancel a quantity or variable on one side of the equation, perform the "opposite" operation with it on both sides. 

if a project will take 35 employees 2,940 hours to complete, how many hours will each employee have to work?

Answers

The answer is 84 hours for each employee. You divide the number of hours by the number of total employees. 



Evaluate BC for A = 5, B = -4, and C = 2.

Answers

8 becuase C(2) x B(4) = 8

Answer: -8

Step-by-step explanation: Substitute the value of the variable into the expression and then simplify you should get the answer -8

BC= (-4)(2)=-8

Find the equation of the circle with center at the origin that contains the point ( 12 , 9 ) (12,9).

Answers

Radius is the length of line from centre to (12,9)
Equation of circle: (x-12)+(y-9)=r^2
r=√12^2+9^2=√169
r^2=(√169)^2=169
hence, (x-12)+(y-9)=169

Which value can fill in the blank in the function f(x)=|x| to make it's graph wider than that of the parent function, f(x)=|x|

Answers

 Multiply x by any number between 0 and 1
For example f(x)  = |0.5x|

To widen [tex]\( |x| \)[/tex]'s graph, use [tex]\( f(x) = |ax| \)[/tex] where [tex]\( a > 1 \),[/tex] stretching horizontally by multiplying [tex]\( x \) by \( a \).[/tex]

To make the graph of the function [tex]\( f(x) = |x| \)[/tex] wider than that of the parent function [tex]\( f(x) = |x| \)[/tex], we need to stretch the graph horizontally.

In the absolute value function [tex]\( f(x) = |x| \)[/tex], the "wideness" of the graph is determined by the coefficient of [tex]\( x \)[/tex], which affects the slope of the graph. When the coefficient of [tex]\( x \)[/tex] is greater than 1, the graph becomes wider, and when it's less than 1, the graph becomes narrower.

So, to make the graph wider, we can introduce a coefficient [tex]\( a \)[/tex] to the [tex]\( x \)[/tex]term inside the absolute value function. The function becomes [tex]\( f(x) = |ax| \), where \( a \)[/tex] is a positive constant greater than 1.

For example, if [tex]\( a = 2 \)[/tex], the function becomes [tex]\( f(x) = |2x| \)[/tex]. This means every \( x \) value in the function is multiplied by 2 before taking the absolute value. As a result, the graph stretches horizontally, making it wider than the parent function.

In conclusion, to make the graph wider than the parent function [tex]\( f(x) = |x| \)[/tex], we can use the function [tex]\( f(x) = |ax| \)[/tex], where [tex]\( a \)[/tex] is a positive constant greater than 1.

Find the length of the arc subtended by a central angle of 30degrees on a circle of radius 2 feet

Answers

1847483993722748494736384 is your answer lolz

What is the perimeter of a polygon with vertices at

(−1, 3) , ​ (−1, 6) ​, (2, 10) , ​ (5, 6) ​​, and ​​ ​ (5, 3) ​?

Enter your answer in the box. Do not round any side lengths.​

Answers

(-6,6) to (2,10) and (2,10) to (5,6) = square root of 3 squared plus 4 squared = 5 3 plus 5 plus 5 plus 3 plus 6 = 22

we know that

the perimeter of a polygon is the sum of the length sides

in this problem we have five vertices

so

the polygon has five sides

Let

[tex]A(-1,3)\\B(-1,6)\\C(2,10)\\D(5,6)\\E(5,3)[/tex]

the perimeter is equal to

[tex]P=AB+BC+CD+DE+AE[/tex]

The formula to calculate the distance between two points is equal to

[tex]d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}[/tex]

Step 1

Find the distance AB

[tex]A(-1,3)\\B(-1,6)[/tex]

substitute the values in the formula

[tex]d=\sqrt{(6-3)^{2}+(-1+1)^{2}}[/tex]

[tex]d=\sqrt{(3)^{2}+(0)^{2}}[/tex]

[tex]dAB=3\ units[/tex]

Step 2

Find the distance BC

[tex]B(-1,6)\\C(2,10)[/tex]

substitute the values in the formula

[tex]d=\sqrt{(10-6)^{2}+(2+1)^{2}}[/tex]

[tex]d=\sqrt{(4)^{2}+(3)^{2}}[/tex]

[tex]dBC=5\ units[/tex]

Step 3

Find the distance CD

[tex]C(2,10)\\D(5,6)[/tex]

substitute the values in the formula

[tex]d=\sqrt{(6-10)^{2}+(5-2)^{2}}[/tex]

[tex]d=\sqrt{(-4)^{2}+(3)^{2}}[/tex]

[tex]dCD=5\ units[/tex]

Step 4

Find the distance DE

[tex]D(5,6)\\E(5,3)[/tex]

substitute the values in the formula

[tex]d=\sqrt{(3-6)^{2}+(5-5)^{2}}[/tex]

[tex]d=\sqrt{(-3)^{2}+(0)^{2}}[/tex]

[tex]dDE=3\ units[/tex]

Step 5

Find the distance AE

[tex]A(-1,3)\\E(5,3)[/tex]

substitute the values in the formula

[tex]d=\sqrt{(3-3)^{2}+(5+1)^{2}}[/tex]

[tex]d=\sqrt{(0)^{2}+(6)^{2}}[/tex]

[tex]dAE=6\ units[/tex]

Step 6

Find the perimeter

the perimeter is equal to

[tex]P=AB+BC+CD+DE+AE[/tex]

substitute the values

[tex]P=3+5+5+3+6=22\ units[/tex]

therefore

the answer is

the perimeter of the polygon is [tex]22\ units[/tex]

Why might algebra tiles not be a good tool to use to factor x2 + 18x + 80? Explain.

Answers

Algebra tiles would not be a good tool to use to factor the trinomial because you would need to drag an x-squared tile, 18 x-tiles, and 80 plus tiles. That is a total of 99 tiles. It would take a lot of time to drag that many tiles on the board and there might not be enough space to hold all of them. You would also need to determine how to arrange all those tiles to make a rectangle. Since 80 is a multiple of 10, you might recognize that 10 and 8 are the factors that add to 18, which would give you the values to use in the X method.

What is the value of x? The triangle is similar.

Answers

The ratios between the sides of any two similar triangles are equivalent. You can use that fact to set up an equality between the ratios of the sides on triangle UKL and triangle UWV:

20/12 = 30/(7x - 3)

From there, simply solve for x.

Which of the following is equivalent to [tex]( \frac{1}{2} ) ^{-2t} [/tex]
[tex](( \frac{1}{2}) ^{2} ))\ x^{t} [/tex]
[tex] \frac{1 ^{t} }{2 ^{2} } [/tex]
[tex](2 ^{2} ) ^{t} [/tex]
[tex]2 ^{2} * 2^{t} [/tex]

Answers

[tex]\bf \left( \cfrac{1}{2} \right)^{-2t}\implies \left( \cfrac{2}{1} \right)^{2t}\implies (2)^{2t}\implies 2^{2\cdot t}\implies (2^2)^t[/tex]
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