Answer:
A; 8.60
Step-by-step explanation:
[tex]a^{2} +b^{2} = c^{2}[/tex]
[tex]7^{2} + 5^{2} = c^{2}[/tex]
[tex]49+25=c^{2}[/tex]
[tex]74=c^{2}[/tex]
[tex]\sqrt{74} =c[/tex]
8.60 = c
Answer:
8.40 cm
Step-by-step explanation:
7^2+5^2=x^2
49+25=x^2
74=x^2
x≈8.6
Which is equivalent to 80 1/4 x
In this Multiplication in Algebra question, The expression '80 (1/4) x' is equivalent to '20x'. When the constant 80 multiplies with the fraction 1/4, the product then multiplies with the variable 'x' resulting in a simplified expression '20x'.
The given mathematical expression 80 (1/4) x can be simplified using the rules of multiplication in algebra.
Here the number 80 multiplies with the fraction 1/4 and then by the variable 'x'.
To carry out this operation, first multiply 80 by 1/4 which equals to 20, and then multiply this by 'x', so your final result would be 20x. Hence, the expression 80 (1/4) x is equivalent to 20x.
Learn more about Multiplication in Algebra here:
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The probable question may be:
Which is equivalent to 80 (1/4) x
Write an equation for the vertical translation. y = 2/3x; 4 units down
Answer:
y = [tex]\frac{2}{3}[/tex] x - 4
Step-by-step explanation:
Given y = f(x), then
y = f(x) + c represents a vertical translation
• If c > 0 then shift up by c units
• If c < 0 then shift down by c units
Here the translation is 4 units down ⇒ c = - 4, thus
y = [tex]\frac{2}{3}[/tex] x - 4
The equation of a line y = 2/3x moved 4 units down would be y = 2/3x - 4.
Explanation:In the case of a vertical translation, the equation of a line y = mx + b is altered by adding or subtracting a constant value, which moves the line up or down on the coordinate plane. For example, with the given equation of a line, y = 2/3x, to translate it 4 units down, we subtract 4 from y. Therefore, the equation for the vertical translation would be y = 2/3x - 4.
Learn more about Equation of a Line here:https://brainly.com/question/21511618
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The Transitive Property of Congruence allows you to say that if ∠PQR ≅ ∠RQS, and ∠RQS ≅ ∠SQT, then _____.
1.) ∠RQS ≅ ∠PQR
2.) ∠PQR ≅ ∠SQT
3.) ∠PQR ≅ ∠RQS
4.) ∠RQS ≅ ∠RQP
The answer would be 2. Angle PQR = Angle SQT
Hope it helps :)
Answer is 2 for sure Goodluck.
on the first day of a local fair, 55 children, 20 adults, and 25 senior citizens were admitted. if children's tickets cost $5.00 each, adults cost $8.00 each and senior citizen tickets cost $6.00 each, what was the mean ticket price for all 100 people who entered?
Answer:
585$
Step-by-step explanation:
multiply 55 by 5, then multiply 20 by 8, last multiply 25 by 6 and add each of the totals to one another.
The mean ticket price is 5.85
Please help..........
Answer:
C
Step-by-step explanation:
This is saying sum 5 and a number and multiply the result by 4
let n be the number then 5 + n is the sum, and
4(5 + n) is 4 times the resultant sum
Select the correct answer.
Nathan had an infection, and his doctor wanted him to take penicillin. Because Nathan’s father and paternal grandfather were allergic to penicillin, Nathan had a 75% chance of having the same allergy. The doctor performed a skin test to see whether Nathan would react to it. The test is 98% accurate. What is the probability that Nathan is allergic to penicillin and the test predicts it?
Answer:
[tex]P=0.735[/tex]
Step-by-step explanation:
Call A to the event in which Nathan is allergic to penicillin
So
[tex]P (A) = 0.75[/tex]
[tex]P (A') = 1-P (A) = 0.25[/tex]
Call B the event in which the skin test predicts correctly.
So:
[tex]P (B) = 0.98\\P (B ') = 1-P (B) = 0.02[/tex]
We look for the probability that Nathan is allergic to penicillin and the test predicts it.
This is [tex]P (A\ and\ B)[/tex].
[tex]P (A\ and\ B) = P (A)*P (B)\\\\P (A\ and\ B) = 0.75 * 0.98\\\\P (A\ and\ B) = 0.735[/tex]
If vector v has an initial point at P1 and a terminal point at P2, write v as multiples of the basis vectors That is, write v in the form v = ai + bj.
P1 = (−5, −2), P2 = (4, 1) and v = ?
Answer:
v=9i+3j
Step-by-step explanation:
The given vector, v has initial point at P1 = (−5, −2) and terminal point at P2 = (4, 1).
The vector v is found by subtraction the initial point from the terminal point.
v=<4,1>-<-5,-2>
v=<4--5,1--2>
v=<9,3>
We write v as multiples of the basis vectors to obtain:
v=9i+3j
Write 4x + y = -17 in slope intercept form.
Answer:
y=-4x-17
Step-by-step explanation:
You want to find the equation for a line that has a slope of -4 and a y-intercept of -17.
First of all, remember what the equation of a line is:
y = mx+b
Where:
m is the slope, and
b is the y-intercept
All you really have to do here is
replace m with -4, which is the slope you gave, and
replace b with -17, the y-intercept you gave,
in the equation y=mx+b.
The equation of the line that has a slope of -4 and a y-intercept of -17 is:
y=-4x-17.
I need help please. Quick.
It would be A.
All of the others include “Natural Numbers” -5 is not a natural number. A natural number is a counting number like 1,2,3,4,5.
Answer: I believe your answer is A.
hope you get 100%! ^.^
Abc is a rectangle find m angle AEB
Check the picture below.
Answer:
The correct answer is last option.
m<AEB = 140
Step-by-step explanation:
From the figure we can see rectangle.
It is given that, m<ADE = 70°
To find the value of m<AEB
From the figure we get Triangle ADE is isosceles triangle
<DAE = 70°
Therefore m<AED = 180 - (70 + 70) = 40°
<AED and <AEB are linear pairs
Therefore m<AEB = 180 - m<AED
= 180 - 40 = 140
The correct answer is last option
140
PLZZ HELP BASIC ALGEBRA
Solve the equation
8+2z=3(2-z)
Answer:
z = [tex]-\frac{2}{5}[/tex] or - 0.4
Step-by-step explanation:
8+2z = 6 - 3z
2z = 6 - 8 - 3z
2z + 3z = - 2
5z = -2
z = [tex]-\frac{2}{5}[/tex] or - 0.4
3^3/3^6
a. 1/27
b 1/9
c 9
d -27
I think the answer is c
Answer:
a. 1/27
Step-by-step explanation:
When dividing exponents and the base is the same, we subtract them
x^a/ x^b = x^(a-b)
3^3/3^6
3^(3-6)
3^(-3)
The negative exponent means it is in the denominator
1/3^3
1/27
Helpppp me 10 pointssss
Answer:
C
Step-by-step explanation:
Find the height (h ) above eye level and add 5 to give height from floor level.
Since the triangle is right use the tangent ratio to find h
tan60° = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{h}{5}[/tex]
Multiply both sides by 5
5 × tan60° = h, hence
h ≈8.66
The height is 8.66 + 5 = 13.66 ≈ 14 ft ( to nearest foot )
Which function is positive for the entire interval [-3, -2]
Answer:
Graph B
Step-by-step explanation:
We are given 4 graphs.
We need to find the function graph which is positive of the entire interval [-3, -2]
It is a closed interval. So it is inclusive of -3 and -2
In these interval the graph of y value must be in positive region.
By looking at the graph, the graph B has positive y-values in the entire interval [-3, -2]
Therefore, the answer is Graph B)
Answer:
Graph 2 represents that the function is positive for the entire interval [-3, -2].
Step-by-step explanation:
We are given four different graphs for different functions. We have to find the graph that is positive for the entire interval [-3,-2].
We make the following observation from the given graphs.
In graph 1, the function has a value of 0 at -3 and and the value decreases from -3 to -2. Thus, the function is negative in the given interval.In graph 2, it can be clearly seen that the function has a positive value, through the entire given interval.In graph 3, the function shows negative value entirely in the given interval.In graph 4, the function exhibits both positive and negative value in the given interval and in not positive in the entire interval.Thus, function in graph 2 is positive for the entire interval [-3, -2].
Probability and Statistics
Suppose the x-axis of a density graph represents someone's height in inches. If the area under the density curve from 60 inches to 70 inches is 0.65, what is the probability of someone's height being anywhere from 60 inches to 70 inches?
A. 70%
B. 65%
C. 75%
D. 60%
Answer:
b
Step-by-step explanation:
Also got B if you it’s not right let me know send me a comment and I will try to help with the best of my ability
Note: Enter your answer and show all the steps that you use
to solve this problem in the space provided.
A radio signal travels at 3.00 · 100 meters per second.
How many seconds will it take for a radio signal to travel from
a satellite to the surface of Earth if the satellite is orbiting at a
height of 3.54 · 10' meters? Show your work.
لیا
Answer:
O.118 seconds will be taken for a radio signal to travel from a satellite to the surface of earth.
Step-by-step explanation:
We are given Speed = 3.00 · 10^8 meters per second.
And Distance = 3.54.10^7 metwers
We need to find time.
We know that,
Distance = Speed * Time
3.54.10^7 = 3.00 · 10^8 * Time
Time = 3.54.10^7 / 3.00 · 10^8
Time = 1.18 X 10^7-8
Time = 1.18 x 10^-1
Time = 0.118 seconds.
So, O.118 seconds will be taken for a radio signal to travel from a satellite to the surface of earth.
Ok I got 8 and I know it is wrong someone please help me
I would go with answer D here just because it is the only option over 13, and the hypotenuse is always larger than the other sides. Im not positive on the math behind it though tbh.
PLEASE HELP
find the vertex of f(x)=x^2+2x+3 (make sure you show your work)
ANSWER
(-1,2)
EXPLANATION
The given quadratic expression is:
[tex]f(x) = {x}^{2} + 2x + 3[/tex]
The coefficient of the quadratic term is already 1.
So we add and subtract the square of half the coefficient of x.
[tex]f(x) = {x}^{2} + 2x + 1 - 1+ 3[/tex]
We factor the first three terms to obtain
[tex]f(x) =(x + 1)^{2} + 2[/tex]
This is now in the form:
[tex]f(x) = a({x - h)}^{2} +k[/tex]
where (h,k) which is equal to (-1,2) is the vertex.
Lines LM and QR are graphed on this coordinate plane. Which point is the intersection of lines LM and QR?
na
A. (-3,1)
B. (-3.-3)
c. (1.-3)
D. (1.3)
The first number is the X coordinate and the second number is the Y coordinate.
Looking left to right the lines intersect at X = 1
Looking up and down they intersect at Y = -3
The answer is C. (1,-3)
what is the center of the circle given by the equation x^2+y^2-14y-15=0
Answer:
(0, 7)Step-by-step explanation:
The equation of a circle in the standard form:
[tex](a-h)^2+(y-k)^2=r^2[/tex]
(h, k) - center
r - radius
We have the equation:
[tex]x^2+y^2-12y-15=0[/tex]
Convert into a standard form using
[tex](a-b)^2=a^2-2ab+b^2\qquad(*)[/tex]
[tex]x^2+\underbrace{y^2-2(y)(7)+7^2}_{(*)}-7^2-15=0\\\\(x-0)^2+(y-7)^2-49-15=0[/tex]
[tex](x-0)^2+(y-7)^2-64=0[/tex] add 64 to both sides
[tex](x-0)^2+(y-7)^2=64[/tex]
The center (0, 7)
The radius: r = √64 = 8
elimination/subtraction
3x - 10y=-70
4x +9y = 63
(can you please explain in step by step?)
Answer:
x = 0, y = 7
Step-by-step explanation:
Solving a system of equations using substitution requires one side to be equal to a variable present in the equation, in this case x or y. We should simplify the equation using elimination before substituting to reduce the chance of error.
In order to use the elimination method, you have to create variables that have the same coefficient—then you can eliminate them. These equations arew already aligned for us.
3x - 10y=-70
- 4x +9y = 63
-x + y = 7
Now, for substitution, the equation must be set to a variable.
-x + y = 7
y = x + 7
Next, plug the equation in where applicable in another equation.
4x +9(x + 7) = 63
4x + 9x + 63 = 63
13x = 0
x = 0
The final step of substitution is to plug the known variable into an equation to find the other variable.
3(0) - 10y=-70
0 - 10y = -70
10y = 70
y = 7
I guarantee you this answer is correct, I worked it out using other methods and graphing prior to submitting this answer.
Answer:
x = 0 , y = 7
Step-by-step explanation:
[tex]3x - 10y = - 70..............(1) \\ 4x + 9y = 63...................(2) \\ (1) \times 4 \\ 12x - 40y = - 280...........(3) \\ (2) \times 3 \\ 12x + 27y = 189...........(4) \\ (4) - (3) \\ 67y = 469 \\ \\ y = \frac{469}{67} \\ y = 7 \\ put \: y = 7 \: into \: (1) \\ 3x - 10(7) = - 70 \\ 3x - 70 = - 70 \\ 3x = - 70 + 70 \\ 3x = 0 \\ x = \frac{0}{3} \\ x = 0[/tex]
what is the value of x to the nearest tenth
You will have to use trig to solve this:
The side you have is adjacent to the known angle
The side you are looking for is opposite the known angle
^^^This means you need to use tan:
tan(24) = [tex]\frac{x}{12}[/tex]
.445222 = [tex]\frac{x}{12}[/tex]
^^^input tan(24) into calculator, then multiply 12 to both sides to isolate and solve for x
5.3 ≈ x
Hope this helped!
A circle is centered at N (-6 -2) The point E (-1, 1) is on the circle. Where does the point H (-10, -7) lie?
so we know the point E is on the circle, thus the distance NE is really the radius of the circle hmmm what would that be?
[tex]\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ N(\stackrel{x_1}{-6}~,~\stackrel{y_1}{-2})\qquad E(\stackrel{x_2}{-1}~,~\stackrel{y_2}{1})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{radius}{r}=\sqrt{[-1-(-6)]^2+[1-(-2)]^2}\implies r=\sqrt{(-1+6)^2+(1+2)^2} \\\\\\ r=\sqrt{5^2+3^2}\implies r=\sqrt{34}\implies r\approx 5.83 \\\\[-0.35em] ~\dotfill[/tex]
[tex]\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ N(\stackrel{x_1}{-6}~,~\stackrel{y_1}{-2})\qquad H(\stackrel{x_2}{-10}~,~\stackrel{y_2}{-7})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ NH=\sqrt{[-10-(-6)]^2+[-7-(-2)]^2} \\\\\\ NH=\sqrt{(-10+6)^2+(-7+2)^2}\implies NH=\sqrt{(-4)^2+(-5)^2} \\\\\\ NH=\sqrt{41}\implies NH\approx 6.4\impliedby \begin{array}{llll} \textit{units away from the center}\\ \textit{is outside the circle} \end{array}[/tex]
recall the radius is about 5.83, anything shorter than that is inside the circle, anything longer than that is outside it.
Answer:
outside the circle
Step-by-step explanation:
trust me. i did it on khan academy
Determine if the graph is symmetric about the x-axis, the y-axis, or the origin. r = -3 + 3 sin θ
Answer:
y-axis
Step-by-step explanation:
Elimination method
2x-7y=0
4x+9y=0
Answer:
The answer to the question
A rectangular area is to be enclosed with 12m of fencing.
A) what is the maximum area that can be enclosed if the fencing is used on all four sides. What are the dimensions of this optimal shape?
B) Suppose an existing hedge is used to enclose one side. Determine the maximum area that can be enclosed. What are the dimensions in this shape?
C) Suppose two perpendicular hedges enclose the area on two sides. What are the dimensions of the maximum area that can be enclosed?
The correct answer is B
a ticket office sold 553 tickets one day. the receipts totaled $3936. how many $9 adult tickets and how many $6 child tickets were sold
This is the assumption method ;)
Take all tickets to be adult tickets
$9 x 553 = $4977
Then..... $4977 - $3936 = $1041
The difference between the child and adult ticket is $3, so divide $1041 by $3
$1041 divided by $3 = 347
347 is the number of child tickets sold
347 x $6 = $2082
So 553 - 347 = 206 ( no. of adult tickets )
206 x $9 = $1854
Child tickets sold : 347
Adult tickets sold : 206
:0 ITS MAGIC IM SO SMART
Answer:
347 child tickets and 206 adult tickets are sold
Step-by-step explanation:
Let x be the no. of child tickets sold
Let y be the no. of adult tickets sold
A ticket office sold 553 tickets one day.
Equation becomes : [tex]x+y=553[/tex] ---A
Cost of 1 child ticket = $6
Cost of x child tickets = 6x
Cost of 1 adult ticket= $9
Cost of y adult tickets = 9y
Now we are given that the receipts totaled $3936.
So, Equation becomes : [tex]6x+9y=3936[/tex] ---B
Plot A and B
[tex]x+y=553[/tex] ---Green
[tex]6x+9y=3936[/tex] ---Purple
Intersection point = (x,y)=(347,206)
Refer the attached figure
Hence 347 child tickets and 206 adult tickets are sold
pls help math
12x+110=6(x+100)
15 points
move parentheses by 6. 12x+110=6x+600
move variable to its left side and change its term 12x+110-6x=100
collect like terms and subtract 12 the divide both sides by 6.
answer 81.666666666666
Answer:
[tex]x = 230/3\\[/tex]
Step-by-step explanation:
Step 1: Distribute
12x + 110 = 6(x + 100)
12x + 110 = (6 * x) + (6 * 100)
12x + 110 = 6x + 600
Step 2: Subtract 6x from both sides
12x + 110 - 6x = 6x + 600 - 6x
6x + 110 = 600
Step 3: Subtract 110 from both sides
6x + 110 - 110 = 600 - 110
[tex]6x = 490[/tex]
Step 4: Divide both sides by 6
[tex]6x / 6 = 490 / 6[/tex]
[tex]x = 490 / 6[/tex]
[tex]x = (460/2) / (6/2)[/tex]
[tex]x = 230/3[/tex]
Answer: [tex]x = 230/3\\[/tex]
Which of the following is the midpoint between (-8, -1) and (-2, -5)?
(-5, 3)
(5, 3)
(5, -3)
(-5, -3)
Answer:
[-5, -3]
Step-by-step explanation:
Just find the *median* of each coordinate.
find the value of 9!/(9-32)
Step-by-step explanation:
[tex]n!=1\cdot2\cdot3\cdot...\cdot n\\\\\dfrac{9!}{9-32}=\dfrac{1\cdot2\cdot3\cdot4\cdot5\cdot6\cdot7\cdot8\cdot9}{-23}=-\dfrac{362880}{23}[/tex]