boiling point is the temp at which a liquid's vapor pressure equals the external pressure. At higher altitudes the external pressure is lower so vapor pressure becomes equal to external pressure at a lower temperature which is why boiling point decreases with increasing altitude.
I hope this helps you
The fuel tank of an automobile has a capacity of 14.8 gallons. if the density of gasoline is 42.0 lb/ft^3, what is the mass of fuel in kilograms when the tank is full?
Answer: The mass of fuel when the tank was full is 45.255kg.
Explanation:
To calculate the mass of the fuel, we will use the formula given by the equation:
[tex]\text{Density}=\frac{\text{Mass}}{\text{Volume}}[/tex]
Where,
Density = Density of the gasoline = [tex]42lb\ft^3[/tex]
Volume = Capacity of the fuel tank = [tex]14.8gallons=2.376ft^3[/tex] (Conversion factor: [tex]1gallon=0.1605ft^3[/tex] )
Mass = Mass of the fuel = ?
Putting values in above equation, we get:
[tex]42lb/ft^3=\frac{\text{Mass}}{2.376ft^3}\\\\\text{mass}=99.792lbs[/tex]
Converting this quantity into kilograms, we use the conversion factor:
[tex]1lbs=0.4535kg\\\\99.792lbs=99.792\times 0.4535=45.255kg[/tex]
Hence, the mass of fuel when the tank was full is 45.255kg.
How many milliliters of 5.50 m hcl(aq) are required to react with 9.55 g of zn(s)?
Final answer:
To react with 9.55 g of Zn(s), you will need 53.1 mL of a 5.50 M HCl(aq) solution.
Explanation:
To determine the volume of 5.50 M HCl(aq) required to react with 9.55 g of Zn(s), we need to use the balanced chemical equation:
Zn(s) + 2 HCl(aq) → ZnCl2 (aq) + H2(g)
From the equation, we can see that 1 mole of Zn reacts with 2 moles of HCl. First, we need to calculate the moles of Zn using its molar mass and mass given:
Moles of Zn = mass / molar mass = 9.55 g / 65.38 g/mol = 0.146 moles
Since the stoichiometric ratio between HCl and Zn is 2:1, the moles of HCl needed will be double:
Moles of HCl = 2 × moles of Zn = 2 × 0.146 mol = 0.292 mol
Finally, to calculate the volume of HCl, we need to use its molarity:
Volume of HCl = moles of HCl / molarity = 0.292 mol / 5.50 M = 0.0531 L = 53.1 mL
Two liquids – one polar, one nonpolar – have the same molar mass. which one has the higher boiling point?
Question 9 solid sodium chloride is produced by the reaction of chlorine gas and solid sodium . write a balanced chemical equation for this reaction
Wind eroding rocks. Is it a chemical or physical change ?
Insulin, adrenaline, and estrogen are examples of
In the given question, Insulin, adrenaline, and estrogen are examples of hormones. Each hormone has a specific function and plays an important role in maintaining homeostasis in the body.
Insulin is a hormone made up of 51 amino acids and is released by the beta cells of pancreas. It helps in regulating blood glucose level.
Adrenaline is also known as epinephrine. It is produced by the adrenal glands and is involved in the body's "fight or flight" response to stress.
Estrogen is a female sex hormone produced by the ovaries and is involved in the development of female secondary sexual characteristics, such as breast development and the menstrual cycle.
Therefore, examples of hormones are insulin, adrenaline, and estrogen, which are chemical messengers that regulate many physiological processes in the body.
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Under what conditions would you adjust the diaphragm
The diaphragm can be adjusted during deep breathing exercises, forced breathing, and activities that require stabilizing the abdominal cavity's volume and pressure.
Explanation:The diaphragm is a key muscle involved in breathing. It separates the thoracic and abdominal cavities and plays a vital role in the expansion and contraction of the thoracic cavity. The diaphragm contracts during inhalation to increase the volume of the thoracic cavity, allowing air to enter the lungs.
Conversely, it relaxes during exhalation to decrease the volume of the thoracic cavity and expel air from the lungs. The conditions under which you would adjust the diaphragm are: During deep breathing exercises, such as diaphragmatic breathing, where you consciously focus on contracting and relaxing the diaphragm to improve lung function.
During forced breathing or hyperpnea, which occurs during activities like exercise or singing, where the diaphragm and other accessory muscles contract to enhance breathing.
During situations where you need to stabilize the volume and pressure of the abdominal cavity, such as in activities like defecation, urination, or childbirth, which involve cooperation between the diaphragm and abdominal muscles.
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The diaphragm is a muscle that contracts and relaxes to allow breathing. It plays a key role in the process of inspiration, where it moves downward to expand the chest and allow air to enter the lungs.
Explanation:The diaphragm is a dome-shaped, muscular partition separating the thoracic and abdominal cavities in mammals. It plays a crucial role in breathing by contracting and relaxing to change thoracic volume. This action creates pressure variations, facilitating inhalation and exhalation. The diaphragm is essential for respiratory function and overall physiological equilibrium.
The diaphragm is a large, dome-shaped muscle below the lungs that allows breathing to occur when it alternately contracts and relaxes. It plays a crucial role in the process of inspiration, where the diaphragm contracts and moves downward, causing the chest to expand and allowing air to flow into the lungs.
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How many helium atoms are there in a helium blimp containing 535 kg of helium?
A helium blimp containing 535 kg of helium has approximately 8.05 × 10¹⁸ helium atoms, calculated by dividing the mass by the molar mass of helium and then multiplying by Avogadro's number.
Explanation:To determine how many helium atoms are in a helium blimp containing 535 kg of helium, we need to use Avogadro's number and the molar mass of helium. First, we find the number of moles of helium:
Mass of helium (m) = 535 kg = 535,000 g
Molar mass of helium (M) = 4.0026 g/mol
Number of moles (n) = m / M = 535,000 g / 4.0026 g/mol ≈ 133786.85 mol
Avogadro's number (N₀) = 6.02214076 × 10²³ atoms/mol
Number of helium atoms = n × N₀ ≈ 133786.85 mol × 6.02214076 × 10²³ atoms/mol ≈ 8.05 × 10²⁸ atoms
Therefore, a helium blimp containing 535 kg of helium has approximately 8.05 × 10²⁸ helium atoms.
One cup of fresh orange juice contains 124 mg of ascorbic acid (vitamin c, c6h8o6). given that one cup = 236.6 ml, calculate the molarity of vitamin c in organic juice.
Answer : The molarity of vitamin c in organic juice is, [tex]2.97\times 10^{-3}mole/L[/tex]
Solution : Given,
Mass of ascorbic acid (solute) = 124 mg = 0.124 g [tex](1mg=0.001g)[/tex]
Volume of juice = 236.6 ml
Molar mass of ascorbic acid = 176.12 g/mole
Formula used :
[tex]Molarity=\frac{\text{Moles of solute}\times 1000}{\text{Molar mass of solute}\times \text{volume of solution}}[/tex]
Now put all the given values in this formula, we get the molarity of vitamin c in organic juice.
[tex]Molarity=\frac{0.124g\times 1000}{176.12g/mole\times 236.6ml}=2.97\times 10^{-3}mole/L[/tex]
Therefore, the molarity of vitamin c in organic juice is, [tex]2.97\times 10^{-3}mole/L[/tex]
Final answer:
The molarity of vitamin C in orange juice, where one cup contains 124 mg of ascorbic acid and is equal to 236.6 mL, is approximately 0.00297 M.
Explanation:
To calculate the molarity of vitamin C in orange juice, we can use the formula for molarity:
Molarity = moles of solute / liters of solution
First, we need to find the number of moles of ascorbic acid in one cup of orange juice.
1 cup of orange juice contains 124 mg of ascorbic acid. Since the molar mass of ascorbic acid, C6H8O6, is 176.12 g/mol, we convert the mass from mg to grams and then to moles:
124 mg * (1 g / 1000 mg) * (1 mol / 176.12 g) = 0.000704 mol
Next, we convert the volume from milliliters to liters:
236.6 mL * (1 L / 1000 mL) = 0.2366 L
Now, we can calculate the molarity:
Molarity = 0.000704 mol / 0.2366 L ≈ 0.00297 M
Thus, the molarity of vitamin C in the orange juice is approximately 0.00297 M.
how many total atoms are in 0.280 g of P2O5
Answer:
There are 8.43x10²¹ total atoms in 0.280 g of P₂O₅.
Explanation:
Let's follow some steps to calculate the total atoms.
1st) Calculate the molar mass of P₂O₅
Look for the atomic weight of each atom in the Periodic table:
- Atomic weight of Phosphorus = 31 g/mol
- Atomic weight of Oxygen = 16 g/mol
Then, multiply each atomic weight by its coefficient to calculate the molar mass of P₂O₅:
(Atomic weight of P .2) + (Atomic weight of O .5)= Molar mass of P₂O₅
(31 g/mol.2) + (16 g/mol.5) = 62 g/mol + 80 g/mol = 142 g/mol
2nd) Calculate the moles of P₂O₅ that are contained in 0.280 g
This step is easy using a Rule of three thinking that if 142 g of P₂O₅ represents a mol of P₂O₅ the 0.280 g will be "x" moles:
142 g -------- 1 mol of P₂O₅
0.280 g -------- x = (0.280 g.1 mol)/142 g =0.002 mol of P₂O₅
This means that 0.002 moles of P₂O₅ weights 0.280g.
3rd) Calculate the moles of P and O
To see clear how many moles of each atoms are in the molecule of P₂O₅ we disassociate it:
P₂O₅ → 2P + 5O
From the reaction we know that 1 mol of P₂O₅ produces 2 moles of phosphorus and 5 moles of oxygen. Now we can make a relation and thinking that if 1 mol of P₂O₅ produces 2 moles of P the 0.002 moles of P₂O₅ that we have will produce "x" moles of P:
1 mol of P₂O₅ ----- 2 moles of P
0.002 mol of P₂O₅ ----- x = (0.002 mol.2moles)/1mol = 0.004 moles of P
We use the same reasoning for oxygen:
1 mol of P₂O₅ ------- 5 moles of O
0.002 mol of P₂O₅ ------- x = (0.002 mol.5moles)/1mol = 0.01 moles of O
Up to here we have 0.004 moles of atoms of phosphorus and 0.01 moles of atoms of oxygen.
4th) Calculate the total atoms
To this step it is important to remember that 1 mol of something representa a quantity of 6.022x10²³ (that is called Avogadro's number) So, 1 mol of atoms represents 6.022x10²³ atoms.
Now, if we know that in 1 mol of phosphorus atoms is equal to 6.022x10²³ atoms of phosphorus the 0.004 moles that we have will be equal to "x" atoms:
1 mol of P ------ 6.022x10²³ atoms of P
0.004 mol of P ------ x = (0.004 . 6.022x10²³)/ 1 = 2.41x10²¹ atoms of P
Use the same reasoning for oxygen:
1 mol of O ------ 6.022x10²³ atoms of O
0.01 mol of O ------ x = (0.01 . 6.022x10²³)/ 1 = 6.022x10²¹ atoms of O
Now that we have the number of atoms of phosphorus and oxygen let's sum them to find the total atoms:
2.41x10²¹ atoms of P + 6.022x10²¹ atoms of O = 8.43x10²¹ total atoms
Finally, there are 8.43x10²¹ total atoms (of phosphorus and oxygen) in 0.280 g of P₂O₅.
Aqueous solutions of three different substances, ax, ay, and az are represented by the three accompanying diagrams. identify each substance as a strong electrolyte, a weak electrolyte, or a nonelectrolyte and explain your reasoning for thinking so
When an antifreeze like salt is used, the freezing point of a solution is lowered. The amount by which it is lowered is called the
given the density of balsa wood is 7.8 pounds per cubic foot. what is the weight, in kilograms, of a piece of balsa wood 4.0 inches by 6.0 inches by 20.0 inches?
Final answer:
To find the weight in kilograms of a balsa wood piece measuring 4.0 inches by 6.0 inches by 20.0 inches, we calculate its volume, apply the given density to find the weight in pounds, and then convert that to kilograms, resulting in approximately 0.980 kilograms.
Explanation:
To calculate the weight of a piece of balsa wood in kilograms, we first need to find its volume in cubic feet and then use the given density to find its weight in pounds. Afterward, we convert that weight to kilograms. The volume is the product of length, width, and height which must be converted from inches to feet (1 inch = 1/12 feet).
Thus, the volume V is calculated as follows:
V = (4.0 inches / 12 inches/foot) × (6.0 inches / 12 inches/foot) × (20.0 inches / 12 inches/foot) = (0.333 feet) × (0.5 feet) × (1.666 feet) = 0.277 cubic feet.
The weight W in pounds is given by the product of the volume V and the density D:
W = V × D = 0.277 cubic feet × 7.8 pounds/cubic foot = 2.161 pounds.
To convert the weight to kilograms, we use the conversion factor 1 pound = 0.453592 kilograms:
Weight in kilograms = 2.161 pounds × 0.453592 kilograms/pound = 0.980 kilograms.
Pure magnesium metal is often found as ribbons and can easily burn in the presence of oxygen. when 4.81 g of magnesium ribbon burns with 7.46 g of oxygen, a bright, white light and a white, powdery product are formed
Final answer:
When magnesium ribbon burns with oxygen, it forms a bright, white light and a white, powdery product called magnesium oxide (MgO).
Explanation:
When magnesium ribbon burns with oxygen, it forms a bright, white light and a white, powdery product called magnesium oxide (MgO). The chemical equation for this reaction is:
2Mg (s) + O₂(g) → 2MgO (s)
This is an example of a combination reaction where an element (magnesium) combines with oxygen to form an oxide. The reaction is accompanied by the release of heat and light.
Which base would not effectively deprotonate acetylene? (ch3)2nli ch3och2mgbr lioch3 ch3li kh?
Acetylene has a chemical formula which can be written as:
C2H2
We can see that there are two positive ions, H+. Now what deprotonation means is that the H+ is removed from acetylene to form acetylene ion and water. In this case, I believe that the answer would be:
LiOCH3
LiOCH₃ would not effectively deprotonate acetylene
Further explanationThe equilibrium reaction can be determined if the pKa or Ka values of the acid and conjugate acids (acids in the product) are known.
So it can be concluded that the reacting acid can protonate the base or vice versa base compounds can deprotonating the acid in the reaction, so that the reaction can proceed to the right to form a product or not
In an acid-base reaction, it can be determined whether or not a reaction occurs by knowing the value of pKa or Ka from acid and conjugate acid
Acids and bases according to Bronsted-Lowry
Acid = donor (donor) proton (H + ion)Base = proton (receiver) acceptor (H + ion)If the acid gives (H⁺), then the remaining acid is a conjugate base because it accepts protons. Conversely, if a base receives (H⁺), then the base is formed can release protons and is called the conjugate acid from the original base.
The value of the equilibrium constant (K)
Can be formulated:
K acid-base reaction = Ka acid on the left / K acid on the right.
or:
pK = acid pKa on the left - pKa acid on the right
K = equilibrium constant for acid-base reactions
pK = -log K
[tex]\large{\boxed{\bold{K\:=\:10^{-pK}}}}[/tex]
K value> 1) indicates the reaction can take place, or the position of equilibrium to the right.
There is some data that we need to complete from the problem above, the pKa value of the conjugated acid from the base of the compounds above
1. (CH₃)₂NLi, pKa = 382. CH₃OCH₂MgBr, pKa = 503. LiOCH₃, pKa = 164. CH₃Li, pKa = 505. KH, pKa = 50Whereas the pKa of Acetylene (C₂H₂) itself is = 25
From the conjugated acid pKa value of some of the bases above shows only LiOCH₃ bases that cannot deprotonate acetylene because the pKa value is smaller than the pKa acetylene
The reactions that occur are:
LiOCH₃ + HC ≡ CH ---> HOCH₃ + LiC = CH
The value of the equilibrium constant K is
pK = pKa acetylene - pKa HOCH₃
pK = 25-16
pK = 9
[tex]K\:=\:10^{-pK}[/tex]
[tex]K\:=\:10^{-9}[/tex]
K values <1 indicate a reaction cannot occur
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Keywords : pKa, acetylene, deprotonate, the conjugate acid
A student tests four solids for their ability to complete an electrical circuit when dissolved in water by observing their ability to close a circuit containing a light bulb and obtains the following results:
As a scuba diver descends under water, the pressure increases. at a total air pressure of 2.85 atm and a temperature of 25.0 ∘c, what is the solubility of n2 in a diver's blood? [use the value of the henry's law constant k calculated in part a, 6.26×10−4mol/(l⋅atm).] assume that the composition of the air in the tank is the same as on land and that all of the dissolved nitrogen remains in the blood. express your answer with the appropriate units.
The solubility of nitrogen in a diver's blood at a pressure of 2.85 atm and a temperature of 25.0 ∘c is 1.78 x 10^-3 moles per litre, according to Henry's law.
Explanation:In this context, we will use Henry's law to calculate the solubility of N2 in a diver's blood. According to Henry's law, the solubility of a gas in a liquid is directly proportional to the partial pressure of the gas above the liquid. The equation is: C = P * k, where C is the solubility of the gas in the liquid, P is the partial pressure of the gas, and k is Henry's law constant.
In the given situation, the total pressure is 2.85 atm (which is the sum of the partial pressures of all gases), and the value of Henry's law constant (k) for N2 is 6.26×10−4mol/(l⋅atm). So, the solubility of nitrogen can be calculated by multiplying the pressure by Henry's law constant: C = 2.85 atm * 6.26×10−4mol/(l⋅atm) = 1.78 x 10^-3 mol/L.
Therefore, at a pressure of 2.85 atm and a temperature of 25.0 ∘c, the solubility of nitrogen in a diver's blood is 1.78 x 10^-3 moles per litre.
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Which substance is the reducing agent in this reaction? 16h++2cr2o72−+c2h5oh→4cr3++11h2o+2co2?
Answer is: the reducing agent is C₂H₅OH.
Balanced chemical reaction:
16H⁺ + 2Cr₂O₇²⁻ + C₂H₅OH → 4Cr³⁺ + 11H₂O + 2CO₂.
Oxidation half reaction: Cr₂O₇²⁻ + 14H⁺ + 6e⁻ → 2Cr³⁺ + 7H₂O/ ×2.
2Cr₂O₇²⁻ + 28H⁺ + 12e⁻ → 4Cr³⁺ + 14H₂O.
Reduction half reaction: C₂H₅OH + 3H₂O → 2CO₂ + 12H⁺ + 12e⁻.
Net reaction: 2Cr₂O₇²⁻ + 28H⁺ + C₂H₅OH + 3H₂O → 4Cr³⁺ + 14H₂O + 2CO₂ + 12H⁺.
Reducing agent is element or compound who loose electrons in chemical reaction. Ethanol (C₂H₅OH) lost electrons and it is oxidized to carbon dioxide (CO₂).
The reducing agent in the reaction is [tex]\boxed{\text{C}_{2}\text{H}_{5}\text{OH}}[/tex].
Further Explanation:
Redox reaction:
Redox is a term that is used collectively for the reduction-oxidation reaction. It is a type of chemical reaction in which the oxidation states of atoms are changed. In this reaction, both reduction and oxidation are carried out simultaneously. Such reactions are characterized by the transfer of electrons between the species involved in the reaction.
The process of gain of electrons or the decrease in the oxidation state of the atom is called reduction while that of loss of electrons or the increase in the oxidation number is known as oxidation. In redox reactions, one species lose electrons and the other species gain electrons. The species that lose electrons and itself gets oxidized is called as a reductant or reducing agent. The species that gains electrons and gets reduced is known as oxidant or oxidizing agent. The presence of redox pair or redox couple is a must for the redox reaction.
The general representation of a redox reaction is,
[tex]\text{X}+\text{Y}\rightarrow\text{X}^{+}+\text{Y}^{-}[/tex]
The oxidation half-reaction can be written as:
[tex]\text{X}\rightarrow\text{X}^{+}+e^{-}[/tex]
The reduction half-reaction can be written as:
[tex]\text{Y}+e^{-}\rightarrow\text{Y}^{-}[/tex]
Here, X is getting oxidized and its oxidation state changes from to +1 whereas B is getting reduced and its oxidation state changes from 0 to -1. Hence, X acts as the reducing agent, whereas Y is an oxidizing agent.
Rules to calculate the oxidation states of elements:
1. The oxidation number of free element is always zero.
2. The oxidation number of oxygen is generally taken as -2, except for peroxides.
3. The oxidation state of hydrogen is normally taken as +1.
4. The sum of oxidation numbers of all the elements present in a neutral compound is zero.
5. The oxidation numbers of group 1 and group 2 elements are +1 and +2 respectively.
The oxidation state of O is -2.
The expression to calculate the oxidation number in [tex]\text{Cr}_{2}\text{O}_{7}^{2-}[/tex] is:
[tex]\left[2(\text{Oxidation state of Cr})+7(\text{oxidation state of O})\right]=-2[/tex] ...... (1)
Rearrange equation (1) for oxidation number of Cr
[tex]2(\text{Oxidation number of Cr})=\left[(-2)-7(\text{oxidation number of O})\right][/tex] …… (2)
Substitute -2 for oxidation state of O in equation (2).
[tex]\begin{aligned}\text{Oxidation state of Cr}&=\dfrac{[(-2)-7(-2)]}{2}\\&=\dfrac{[-2+14]}{2}\\&=+6\end{aligned}[/tex]
The charge on Cr is +3 so its oxidation state is also +3. The oxidation state of Cr changes from +6 to +3. This shows it decreases during the reaction and therefore Cr is an oxidizing agent.
The oxidation state of O is -2 and the oxidation state of H is +1.
The expression to calculate the oxidation in [tex]\text{C}_{2}\text{H}_{5}\text{OH}[/tex] is:
[tex]\left[2(\text{oxidation state of C})+1(oxidation state of O)+6(oxidation state of H)\right]=0[/tex] ...... (3)
Rearrange equation (3) for oxidation state of C
[tex]2(\text{oxidation state of C})=\left[-1(oxidation state of O)-6(oxidation state of H)\right][/tex] ...... (4)
Substitute -2 for oxidation state of O and +1 for oxidation state of H in equation (4).
[tex]\begin{aligned}\text{Oxidation state of C}&=\dfrac{[-1(-2)-6(+1)]}{2}\\&=\dfrac{[+2-6]}{2}\\&=-2\end{aligned}[/tex]
The oxidation state of O is -2.
The expression to calculate the oxidation state in [tex]\text{CO}_{2}[/tex] is:
[tex]\left[(\text{oxidation state of C})+2(oxidation state of O)\right]=0[/tex] ...... (5)
Rearrange equation (5) for oxidation state of C
[tex](\text{oxidation state of C})=\left[-2(oxidation state of O)\right][/tex] ...... (6)
Substitute -2 for oxidation state of O in equation (6).
[tex]\begin{aligned}\text{Oxidation state of C}&=[-2(-2)]\\&=+4\end{aligned}[/tex]
The oxidation state of C changes from -2 to +4. This shows it increases during the reaction and therefore [tex]\textbf{C}_{2}\textbf{H}_{5}\textbf{OH}[/tex] acts as a reducing agent.
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Answer details:
Grade: High School
Subject: Chemistry
Chapter: Redox reactions
Keywords: redox reaction, C2H5OH, Cr, C, CO2, Cr2O72-, oxidation, reduction, reductant, oxidant, reducing agent, oxidizing agent, electrons, redox pair, redox couple, oxidation state, oxidized, reduced, simultaneously.
You wish to calculate the mass of hydrogen gas that can be prepared from 4.93 g of srh2 and 4.14 g of h2o.
Draw the structural formula of (3e,5z)-5-ethyl-3,5-nonadiene. an alternative name for this compound is (3e,5z)-5-ethylnona-3,5-diene, which follows the rules outlined in the 1993 iupac recommendations.
Which is the next logical step in balancing the given equation?
3CO(g) + Fe2O3(s) Fe(s) + 3CO2(g)
A.Place the coefficient 2 in front of iron(III) oxide.
B.Place the coefficient 2 in front of iron(III) oxide.
C.Place the coefficient 2 in front of elemental iron.
D.Replace the coefficient 3 in carbon monoxide with 6.
somebody help pleaseeee ):
Answer: C. Place the coefficient 2 in front of elemental iron.
Explanation: The given chemical reaction is
3CO(g) + Fe2O3(s) → Fe(s) + 3CO2(g)
As we can see that stiochiometric coefficient of Carbon is balanced and oxygen coefficient is also balanced. The atom left with unbalanced coefficient is Fe.
Thus By Placing the coefficient 2 in front of the elemental iron will lead to the balanced equation.
Thus the balanced equation can be written as -
3CO(g) + Fe2O3(s) → 2Fe(s) + 3CO2(g)
The mass of a mouse is around 22 grams (0.022 kg). What is the weight of a mouse on the Moon?
Answer: The weight of the mouse on the Moon is 0.036 N
Explanation:
Weight is defined as the force exerted by the body on any surface. It is also defined as the product of mass of the body multiplied by the acceleration due to gravity.
Mathematically,
[tex]W=mg[/tex]
where,
W = weight of the mouse
m = mass of the mouse = [tex]22g=0.022kg[/tex]
g = acceleration due to gravity on moon = [tex]1.625m/s^2[/tex]
Putting values in above equation, we get:
[tex]W=0.022kg\times 1.625 m/s^2=0.036N[/tex]
Hence, the weight of the mouse on the Moon is 0.036 N
If the atomic number of an element is 6 and its mass number is 15, how many neutrons are in the atom's nucleus?
Atomic Number is the same as the number of protons in an element.
Mass Number is the number of Protons + Neutrons in an element.
Atomic Number: 6 means 6 Protons
Mass Number: 15 means 15 atoms that are a proton/neutron.
We are given out of the 15 atoms, 6 of them are protons, so the other 9 must be Neutrons.
15 - 6 = 9 so there must be 9 Neutrons.
There are 9 Neutrons in atom's nucleus.
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A solution is made by mixing 15.0 g of sr(oh)2 and 55.0 ml of 0.200 m hno3.
a. write a balanced equation for the reaction that occurs between the solutes.
b. calculate the concentration of each ion remaining in solution.
c. is the resultant solution acidic or basic?
After a balanced neutralization reaction between Sr(OH)2 and HNO3, the unused Sr(OH)2 determines the solution is basic.
Explanation:To address this question, let's first write down the balanced equation for the reaction between strontium hydroxide (Sr(OH)2) and nitric acid (HNO3) which is:
Sr(OH)2 (aq) + 2HNO3 (aq) → Sr(NO3)2 (aq) + 2H2O (l)
Now let's calculate the moles of HNO3 added:
Volume of HNO3 = 55.0 mL = 0.055 L
Concentration of HNO3 = 0.200 M
Moles of HNO3 = Volume × Concentration = 0.055 L × 0.200 M = 0.011 mol
Next, calculate the moles of Sr(OH)2:
Mass of Sr(OH)2 = 15.0 g
Molar mass of Sr(OH)2 = 121.63 g/mol (approximately)
Moles of Sr(OH)2 = Mass ÷ Molar mass = 15.0 g ÷ 121.63 g/mol = 0.123 mol
According to the stoichiometry of the balanced equation, we need twice as many moles of HNO3 to react completely with Sr(OH)2. In this scenario, we have excess Sr(OH)2 (0.123 mol) compared to HNO3 (0.011 mol). Hence, all of the HNO3 will react, leaving some Sr(OH)2 unreacted.
After reaction, moles of Sr(OH)2 remaining = 0.123 mol - (0.011 mol × 1/2) = 0.1175 mol
The concentration of remaining Sr(OH)2 can be calculated by assuming the final volume is the sum of the volumes of the solutions mixed, which is an approximation for dilute solutions.
Since all the HNO3 has reacted, the resulting solution will be basic due to the excess Sr(OH)2 remaining.
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(a) The balanced equation for the reaction between the solutes is: [tex]\text{Sr(OH)}_2(aq) + 2\text{HNO}_3(aq) \rightarrow \text{Sr(NO}_3\text{)}_2(aq) + 2\text{H}_2\text{O}(l)[/tex]. (b) The concentrations of ions are: Sr²⁺ is 2.136 M, NO₃⁻ is 0.2 M, and OH⁻ is 4.272 M. (c) Resultant solution is basic in nature.
To solve the given problem, let's follow the steps one by one:
(a) Write a balanced equation for the reaction that occurs between the solutes.
Strontium hydroxide Sr(OH)₂ reacts with nitric acid HNO₃ to form strontium nitrate Sr(NO₃)₂ and water:
[tex]\text{Sr(OH)}_2(aq) + 2\text{HNO}_3(aq) \rightarrow \text{Sr(NO}_3\text{)}_2(aq) + 2\text{H}_2\text{O}(l)[/tex]
(b) Calculate the concentration of each ion remaining in solution.
1. Determine the moles of each reactant:
- Moles of Sr(OH)₂:
[tex]\text{Molar mass of Sr(OH)}_2 = 87.62 \, (\text{Sr}) + 2 \times 16.00 \, (\text{O}) + 2 \times 1.01 \, (\text{H}) = 121.64 \, \text{g/mol} \\\\\text{Moles of Sr(OH)}_2 = \frac{15.0 \, \text{g}}{121.64 \, \text{g/mol}} \approx 0.123 \, \text{mol}[/tex]
- Moles of HNO₃:
[tex]\text{Molarity of HNO}_3 = 0.200 \, \text{M} \\\\\text{Volume of HNO}_3 = 55.0 \, \text{mL} = 0.055 \, \text{L} \\\\\text{Moles of HNO}_3 = 0.200 \, \text{mol/L} \times 0.055 \, \text{L} = 0.011 \, \text{mol}[/tex]
2. Determine the limiting reactant:
According to the balanced equation, 1 mole of Sr(OH)₂ reacts with 2 moles of HNO₃. Therefore, the reaction requires:
[tex]\text{Moles of HNO}_3 \text{ required} = 0.123 \, \text{mol Sr(OH)}_2 \times 2 = 0.246 \, \text{mol}[/tex]
Since we only have 0.011 moles of HNO₃, it is the limiting reactant.
3. Calculate the remaining moles of Sr(OH)₂:
[tex]\text{Moles of Sr(OH)}_2 \text{ reacted} = \frac{0.011 \, \text{mol HNO}_3}{2} = 0.0055 \, \text{mol} \\\\\text{Remaining moles of Sr(OH)}_2 = 0.123 \, \text{mol} - 0.0055 \, \text{mol} = 0.1175 \, \text{mol}[/tex]
4. Determine the concentrations of ions in the solution:
- Volume of the final solution = volume of HNO₃ + volume of water from Sr(OH)₂ dissolution (approximately equal to volume of water added):
Assuming the solution volume remains approximately 55.0 mL + a negligible volume from Sr(OH)₂, the final volume is roughly 0.055 L.
- Concentration of Sr²⁺ ions:
Since only 0.0055 moles of Sr(OH)₂ reacted to form Sr(NO₃)₂, 0.1175 moles of Sr(OH)₂ remain, giving the concentration of Sr²⁺:
[tex]\text{Concentration of Sr}^{2+} = \frac{0.1175 \, \text{mol}}{0.055 \, \text{L}} \approx 2.136 \, \text{M}[/tex]
- Concentration of NO₃⁻ ions:
All HNO₃ dissociates, producing:
[tex]\text{Concentration of NO}_3^{-} = \frac{0.011 \, \text{mol}}{0.055 \, \text{L}} = 0.2 \, \text{M}[/tex]
- Concentration of OH⁻ ions:
From Sr(OH)₂, OH⁻ concentration:
[tex]\text{OH}^{-} \text{ from Sr(OH)}_2: \text{2 moles OH}^{-}\text{ per mole of Sr(OH)}_2 \\\\\text{Concentration of OH}^{-} = 2 \times \frac{0.1175 \, \text{mol}}{0.055 \, \text{L}} \approx 4.272 \, \text{M}[/tex]
(c) Is the resultant solution acidic or basic?
To determine if the solution is acidic or basic, we compare the concentrations of H⁺ and OH⁻. Since HNO₃ (a strong acid) was completely neutralized and excess Sr(OH)₂ (a strong base) remains, the solution will be basic due to the presence of significant OH⁻ ions.
Summary
- Balanced equation:
[tex]\text{Sr(OH)}_2(aq) + 2\text{HNO}_3(aq) \rightarrow \text{Sr(NO}_3\text{)}_2(aq) + 2\text{H}_2\text{O}(l)[/tex]
- Concentrations of ions in solution:
[tex]\text{Sr}^{2+}: 2.136 \, \text{M} \\\\ \text{NO}_3^{-}: 0.2 \, \text{M} \\\\ \text{OH}^{-}: 4.272 \, \text{M} \\\\[/tex]
- Resultant solution is basic due to the presence of excess OH⁻ ions.
What is the cause of mechanical weathering? A. Rainwater
B. Sunlight C. Natural Acids D. Physical forces
Answer: Option (D) is the correct answer.
Explanation:
When big rocks are broken down into smaller rocks due to the natural processes then this process of breaking is known as mechanical weathering.
Mechanical weathering is also known as physical weathering. It arises due to physical forces caused by rainwater and change in temperature etc.
Thus, we can conclude that out of the given options, physical forces is the cause of mechanical weathering.
Write a balanced chemical equation, including states of matter, for the combustion of gaseous benzene, c6h6.
The balanced chemical equation for the combustion of benzene is C6H6(g) + 15O2(g) → 6CO2(g) + 3H2O(g). AS is expected to be positive in this process.
Explanation:The balanced chemical equation for the combustion of benzene, C6H6, is:
C6H6 (g) + 15O2 (g) → 6CO2 (g) + 3H2O (g)
In this process, AS (entropy change) is expected to be positive since the reaction produces more gas molecules (CO2 and H2O) than the reactant (benzene).
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How could you separate a mixture of olive oil, water and table salt by physical means?
Fritz haber was awarded a nobel prize for the processes he invented in which nitrogen and hydrogen gases are combined to make ammonia (nh3) a valuable chemical and a vital nutrient in modern agriculture.if we had 11.3 g of nitrogen and 2 g of hydrogen, how much nitrogen would remain if all the hydrogen was consumed?
3H2 + N2 ........> 2NH3
This means that each 6 grams of hydrogen react with 28 grams of nitrogen. To know how many grams of nitrogen are required to react with 2 grams of hydrogen, we will simply do cross multiplication as follows:
mass of nitrogen = (2 x 28) / 6 = 9.334 grams
Therefore, if we have 11.3 grams of nitrogen, 9.334 grams would react with 2 grams of hydrogen.
remaining mass of nitrogen = 11.3 - 9.334 = 1.966 grams
What might happen to a liquid with a freezing point of 32 degrees if its temperature dropped below 30 degrees?
Diatomic molecules of gases at room temperature are due to _________ bonds. ionic
covalent
metallic
none of the above