please help
What is the value for X?
- 24
-9
-21
-14
what is the measure of <1?
- 45
- 60
- 120
-125
Answers
Answer:
x = 21∠1 = 120°Step-by-step explanation:
The two interior same-side angles are supplementary, so ...
... (5x +15)° +(3x -3)° = 180°
... 8x +12 = 180 . . . . . . . . . divide by °, collect terms
... 8x = 168 . . . . . . . . . . . . subtract 12
... x = 21 . . . . . . . . . . . . . . . divide by 8
Obtuse ∠1 has the same measure as its corresponding angle, (5x+15)°, so is ...
... ∠1 = (5·21 +15)° = 120°
Related Questions
Which expressions are equivalent to ? Check all that apply.
Answers
To determine if expressions are equivalent, we simplify them or substitute variables with actual values to see if they yield the same result. We simplify by eliminating terms where possible, grouping like terms, and applying mathematical operations.
Explanation:Without the original mathematical expressions, it's difficult to provide direct answers to your question. Normally, we determine whether expressions are equivalent by simplifying them using algebraic rules or substituting variable with actual values to see if they produce the same results.
For example, the expressions 2(3 + 5) and 6 + 10 are equivalent because they both simplify to 16. We identify equivalent expressions by simplifying which includes eliminating terms where possible, grouping like terms, and applying mathematical operations.
Ultimately, the exact process may vary depending on the complexity and specific form of the expressions in question.
Learn more about Equivalent here:https://brainly.com/question/34140345
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The expressions equivalent to [tex]$\sqrt[3]{128}^x$[/tex] are (c) [tex]$(4 \sqrt[3]{2})^x$[/tex] and (d) [tex]$\left(4\left(2^{\frac{1}{3}}\right)\right)^x$[/tex] due to their compatible structures with the original expression.
To determine which expressions are equivalent to [tex]$\sqrt[3]{128}^x$[/tex], let's simplify the given expression first:
[tex]\[\sqrt[3]{128}^x = 2^x \times \sqrt[3]{2}^x\][/tex]
Now, let's compare this with the provided options:
a. [tex]$128^{\frac{x}{3}}$[/tex] - Not equivalent.
b. [tex]$128^{\frac{3}{x}}$[/tex] - Not equivalent.
c. [tex]$(4 \sqrt[3]{2})^x$[/tex] - Equivalent, as [tex]$4 = 2^{\frac{3}{2}}$[/tex].
d. [tex]$\left(4\left(2^{\frac{1}{3}}\right)\right)^x$[/tex] - Equivalent, as [tex]$2^{\frac{1}{3}} = \sqrt[3]{2}$[/tex].
e. [tex]$(2 \sqrt[3]{4})^x$[/tex] - Not equivalent.
Therefore, the expressions (c) [tex]$(4 \sqrt[3]{2})^x$[/tex] and (d) [tex]$\left(4\left(2^{\frac{1}{3}}\right)\right)^x$[/tex] are equivalent to [tex]$\sqrt[3]{128}^x$[/tex].
Find the equation of the circle with center at the origin that contains the point ( 12 , 9 ) (12,9).
Answers
Equation of circle: (x-12)+(y-9)=r^2
r=√12^2+9^2=√169
r^2=(√169)^2=169
hence, (x-12)+(y-9)=169
Which value can fill in the blank in the function f(x)=|x| to make it's graph wider than that of the parent function, f(x)=|x|
Answers
For example f(x) = |0.5x|
To widen [tex]\( |x| \)[/tex]'s graph, use [tex]\( f(x) = |ax| \)[/tex] where [tex]\( a > 1 \),[/tex] stretching horizontally by multiplying [tex]\( x \) by \( a \).[/tex]
To make the graph of the function [tex]\( f(x) = |x| \)[/tex] wider than that of the parent function [tex]\( f(x) = |x| \)[/tex], we need to stretch the graph horizontally.
In the absolute value function [tex]\( f(x) = |x| \)[/tex], the "wideness" of the graph is determined by the coefficient of [tex]\( x \)[/tex], which affects the slope of the graph. When the coefficient of [tex]\( x \)[/tex] is greater than 1, the graph becomes wider, and when it's less than 1, the graph becomes narrower.
So, to make the graph wider, we can introduce a coefficient [tex]\( a \)[/tex] to the [tex]\( x \)[/tex]term inside the absolute value function. The function becomes [tex]\( f(x) = |ax| \), where \( a \)[/tex] is a positive constant greater than 1.
For example, if [tex]\( a = 2 \)[/tex], the function becomes [tex]\( f(x) = |2x| \)[/tex]. This means every \( x \) value in the function is multiplied by 2 before taking the absolute value. As a result, the graph stretches horizontally, making it wider than the parent function.
In conclusion, to make the graph wider than the parent function [tex]\( f(x) = |x| \)[/tex], we can use the function [tex]\( f(x) = |ax| \)[/tex], where [tex]\( a \)[/tex] is a positive constant greater than 1.
y=x+2;x=-3 solve each system by graphing step by step
Answers
y=x+2
go to the positive number 2 on the y-axis and plot a point
now, since its postive, your line is gonna go like this:
p
p
p
p
p
p
so go up one, and to the right one from the 2 on the y-axis
and then go down one, to the left one from the 2 on the y-axis
connect the dots and this is your first line
now for the second line, go to the -3 on the x-axis and draw a vertical line up and down
this is your second line
now find where the two lines interesect and that is your answer
it'll be a point and look something like this if you write it out (x,y)
take the two points out nd write your answer in this form: x=a, y=b
tah dah!
please show work along with answer:
[tex] \frac{1 + \tan(x) }{1 + \cot(x) } [/tex]
Answers
[tex] \dfrac{1+tan(x)}{1+cotg(x)} = \dfrac{1+ \frac{sin(x)}{cos(x)} }{1+ \frac{cos(x)}{sin(x)}} \\\\ = \dfrac{cos(x)+sin(x)}{cos(x)*( \frac{sin(x)+cos(x)}{sin(x)} } )\\\\ = \dfrac{sin(x)}{cos(x)} \\\\ \boxed{=tan(x)}\\\\ [/tex]
I need help from a math genius
Answers
The answer to the second is (B. 14)
2. 14=6+8
3. 5=2+3
4. 10=2X5
if a project will take 35 employees 2,940 hours to complete, how many hours will each employee have to work?
Answers
What is the value of x? The triangle is similar.
Answers
20/12 = 30/(7x - 3)
From there, simply solve for x.
what is the equation of the graphed line in point-slope form?
a. y – 1 = (x + 3)
b. y – 1 = (x – 3)
c. y + 1 = (x – 3)
d. y + 1 = (x + 3)
Answers
slope = (-3 - 1) / (-3 - 3) = -4/-6 = 2/3
y - y1 = m(x - x1)
slope(m) = 2/3
(3,1)...x1 = 3 and y1 = 1
now we sub
y - 1 = 2/3(x - 3) <==
Answer:
[tex]y-1 = \frac{2}{3}(x-3)[/tex]
Step-by-step explanation:
To find the equation of graphed line we pick two points from the line
(3,1) and (-3,-3)
Equation of a line is y=mx+b
where 'm' is the slope and b is the y intercept
slope [tex]m= \frac{y2-y1}{x2-x1} =\frac{1+3}{3+3} = \frac{2}{3}[/tex]
we use point slope formula
y-y1= m(x-x1)
here point(x1,y1) is (3,1) and slope m = 2/3
Plug in all the value
[tex]y-1 = \frac{2}{3} (x-3)[/tex]
Which algebraic expression has a term with a coefficient of 3?
Answers
A coefficient is a constant value, multiplying the variable in an expression/equation.
Examples:
[tex]4x^2+3y^3[/tex]
The coefficient of the second term would be three.
Hope this helps.
-Benjamin
the correct answer is option (b) 3x² - 7.
The coefficient is the numerical factor in front of the variable. Let's calculate the coefficient for each option:
a) The coefficient of x in 2x is 2, not 3.
b) The coefficient of x² in 3x² is 3, which matches our requirement.
c) The coefficient of x in 4x is 4, not 3.
d) There is no x term in x³ + 2, so the coefficient for x is 0.
Therefore, the correct answer is option (b) 3x² - 7.
In option (b), the term with the coefficient of 3 is 3x². The coefficient of this term is indeed 3 because it's the number multiplied by x squared. The other terms in the expression do not have a coefficient of 3.
In options (a) and (c), the coefficients for the x terms are 2 and 4, respectively, which do not match the requirement.
Option (d) doesn't have an x term; it only has x raised to the power of 3 (x³), and the coefficient for this term is 0.
So, by process of elimination and calculation, we determine that option (b) is the correct answer with the term 3x² having a coefficient of 3.
complete question
Which algebraic expression has a term with a coefficient of 3?
a) 2x + 5
b) 3x² - 7
c) 4x - 3
d) x³ + 2
Alex sells cars at Keith Palmer Ford. He earn$400 a week plus $150 per car he sells. if he earn $1450 last week, how many cars did he sell? brainly
Answers
1050/150=7
7 cars
Solve for 8x please
Answers
x=-c+k/8
The first option is the answer
How many seconds are there in (a) one hour and thirty-five minutes and (b) one day?
Answers
What numbers have the absolute value of 1/2
Answers
hope it helps, brianliest pls
What is the perimeter of a polygon with vertices at
(−1, 3) , (−1, 6) , (2, 10) , (5, 6) , and (5, 3) ?
Enter your answer in the box. Do not round any side lengths.
Answers
we know that
the perimeter of a polygon is the sum of the length sides
in this problem we have five vertices
so
the polygon has five sides
Let
[tex]A(-1,3)\\B(-1,6)\\C(2,10)\\D(5,6)\\E(5,3)[/tex]
the perimeter is equal to
[tex]P=AB+BC+CD+DE+AE[/tex]
The formula to calculate the distance between two points is equal to
[tex]d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}[/tex]
Step 1
Find the distance AB
[tex]A(-1,3)\\B(-1,6)[/tex]
substitute the values in the formula
[tex]d=\sqrt{(6-3)^{2}+(-1+1)^{2}}[/tex]
[tex]d=\sqrt{(3)^{2}+(0)^{2}}[/tex]
[tex]dAB=3\ units[/tex]
Step 2
Find the distance BC
[tex]B(-1,6)\\C(2,10)[/tex]
substitute the values in the formula
[tex]d=\sqrt{(10-6)^{2}+(2+1)^{2}}[/tex]
[tex]d=\sqrt{(4)^{2}+(3)^{2}}[/tex]
[tex]dBC=5\ units[/tex]
Step 3
Find the distance CD
[tex]C(2,10)\\D(5,6)[/tex]
substitute the values in the formula
[tex]d=\sqrt{(6-10)^{2}+(5-2)^{2}}[/tex]
[tex]d=\sqrt{(-4)^{2}+(3)^{2}}[/tex]
[tex]dCD=5\ units[/tex]
Step 4
Find the distance DE
[tex]D(5,6)\\E(5,3)[/tex]
substitute the values in the formula
[tex]d=\sqrt{(3-6)^{2}+(5-5)^{2}}[/tex]
[tex]d=\sqrt{(-3)^{2}+(0)^{2}}[/tex]
[tex]dDE=3\ units[/tex]
Step 5
Find the distance AE
[tex]A(-1,3)\\E(5,3)[/tex]
substitute the values in the formula
[tex]d=\sqrt{(3-3)^{2}+(5+1)^{2}}[/tex]
[tex]d=\sqrt{(0)^{2}+(6)^{2}}[/tex]
[tex]dAE=6\ units[/tex]
Step 6
Find the perimeter
the perimeter is equal to
[tex]P=AB+BC+CD+DE+AE[/tex]
substitute the values
[tex]P=3+5+5+3+6=22\ units[/tex]
therefore
the answer is
the perimeter of the polygon is [tex]22\ units[/tex]
He measure of an angle is 78° less than the measure of its complement. what is the measure of the angle?
Answers
θ+(θ-78)=90
2θ-78=90
From there, it’s fairly straightforward algebra; just solve for θ. Remember though, the answer they’re looking for is the (θ-78) term, so make sure to evaluate that once you’ve found θ.
On anne's bicycle, the ratio of pedal turns to rear-wheel turns in second gear is 4 to 7. if her rear wheel turns 875 times per mile,how many times does she turn the pedal in one mile?hint:set up and solve as a propportion to find x.
Answers
Given that her rear miles turns 875 times in one mile and the ratio of pedal turns to rear wheel turns is 4 to 7, then
[tex] \frac{4}{7} = \frac{x}{875} \\ \\ \Rightarrow 7x=4(875)=3,500 \\ \\ \Rightarrow x= \frac{3,500}{7} =\bold{500}[/tex]
Therefore, she turns the pedal 500 times in one mile.
Let g(x)=2x and h(x)=x^2+4
(g o h)(0)
Answers
Hope this helped. Have a great day!
The ______ is the total area drained by a river and its tributaries.
Answers
Find the percent change from 48 to 228. Tell whether it is a percent increase or decrease. If necessary, round your answer to the nearest percent.
Answers
180/48 = 3.75
Its increase 375%
To maximize learning, a ________ should be presented on a(n) ________ schedule.
Answers
To maximize learning, a CS + UCS should be presented on a(n) continuous schedule.
In here, CS means conditional stimulus while UCS is the unconditioned stimulus. Taking for example, let us imagine that the smell of food is the unconditioned stimulus, the feeling of hunger in response to that specific smell is a unconditioned response, and then the sound of the whistle is the conditioned stimulus.
Ashley is making cookies. the recipe calls for 3/4 of a cup of sugar. she needs to make five batches of cookies. how many cups of sugar does ashley need?
Answers
Hope this helps!!
How do you solve rearranging equations
Answers
Evaluate BC for A = 5, B = -4, and C = 2.
Answers
Answer: -8
Step-by-step explanation: Substitute the value of the variable into the expression and then simplify you should get the answer -8
BC= (-4)(2)=-8
what is the solution to 7ln(x+2.8)=11.2
Answers
Why might algebra tiles not be a good tool to use to factor x2 + 18x + 80? Explain.
Answers
Algebra tiles would not be a good tool to use to factor the trinomial because you would need to drag an x-squared tile, 18 x-tiles, and 80 plus tiles. That is a total of 99 tiles. It would take a lot of time to drag that many tiles on the board and there might not be enough space to hold all of them. You would also need to determine how to arrange all those tiles to make a rectangle. Since 80 is a multiple of 10, you might recognize that 10 and 8 are the factors that add to 18, which would give you the values to use in the X method.
Find the length of the arc subtended by a central angle of 30degrees on a circle of radius 2 feet
Answers
Which of the following is equivalent to [tex]( \frac{1}{2} ) ^{-2t} [/tex]
[tex](( \frac{1}{2}) ^{2} ))\ x^{t} [/tex]
[tex] \frac{1 ^{t} }{2 ^{2} } [/tex]
[tex](2 ^{2} ) ^{t} [/tex]
[tex]2 ^{2} * 2^{t} [/tex]
Answers
You have exactly 10 minutes to get to class for
your big test on lateral numbers! Your friend Gus
(who’s weirdly in to this sort of thing) says that class
is exactly 10,000 feet away. Let’s say you travel to
class at a rate of r feet/minute. You would like to get
there a few minutes early. More specifically, let’s say
you will arrive t minutes early.
a) Write an equation that relates r and t.
Answers
Rate = 10000 ft/ 10 min
R = 10000/10
R = 1000
You will have to travel 1000 feet per minute nonstop, or 0.189 miles per minute
hope this helps
Which formula gives the coordinates of the midpoint of the segment connecting points (a,
b.and (c, d)?
Answers
(a,b)...x1 = a and y1 = b
(c,d)...x2 = c and y2 = d
so ur formula would be :
m = (a + c)/2 , (b + d)/2 <==
Answer:
Formula that gives coordinates of the mid point of the segment connecting is [tex](\frac{a+c}{2},\frac{b+d}{2})[/tex]
Step-by-step explanation:
Given point are ( a , b ) and ( c , d )
To find : Coordinates of the mid point of the segment connecting given points.
We know that if point are [tex](x_1,y_1)\:\:and\:\:(x_2,y_2)[/tex]
then coordinate of the midpoints given by [tex](\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})[/tex]
So, Coordinates of the given points = [tex](\frac{a+c}{2},\frac{b+d}{2})[/tex]
Therefore, Formula that gives coordinates of the mid point of the segment connecting is [tex](\frac{a+c}{2},\frac{b+d}{2})[/tex]