One positive integer is 3 less than twice another. the sum of their squares is 170

Answers

Answer 1
let x=number1 and y=number2
[tex] {x}^{2} + {y}^{2} = 170 \\ 2x - 3 = y \\ {x}^{2} + {(2x - 3)}^{2} = 170 \\ {x}^{2} + 4 {x}^{2} - 12x + 9 = 170 \\ 5 {x}^{2} - 12x + 9 - 170 = 0 \\ 5 {x}^{2} - 12x - 161 = 0 \\ (x - 7)(5x + 23) = 0 \\ x = 7 \: or \: x = \frac{ - 23}{5} [/tex]
x is postive the x must be =7
[tex]y = 2x - 3 \\ y = 2(7) - 3 \\ y = 14 - 3 \\ y = 11[/tex]
checking our soultion
[tex] {x}^{2} + {y}^{2} = 121 \\ {7}^{2} + {11}^{2} = 49 + 121 = 170[/tex]
which makes our soultion correct

Related Questions

Find the solution of the initial value problem. dp/dt=5e^t, p(0)=25

Answers

I hope this helps you!

The equation is  [tex]p = 5e^{t} +20[/tex].

Integration

It is a method of summing up parts to find the whole. It is a reverse process of differentiation.

Given

dp/dt=5e^t

To find

The value of p.

How to get the value of p?

dp/dt=5e^t is given

[tex]\begin{aligned} \dfrac{dp}{dt} &= e^{t} \\\int dp &= \int {5e^{t} } \, dt \\\int dp &= 5 \int {e^{t} } \, dt \\p &= 5e^{t} +c\\\end{aligned}[/tex]

It is given that at t=0, p will be 25, then

[tex]p = 5e^{t} + c\\c = p - 5e^{t}\\c= 25 - 5e^{0}\\c= 25 - 5 * 1\\c= 20[/tex]

Hence the equation will be [tex]p = 5e^{t} +20[/tex].

Thus, the equation is  [tex]p = 5e^{t} +20[/tex].

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PLEASE HELP!!!! WILL GIVE 99 PTS! :)Sam is observing the velocity of a car at different times. After two hours, the velocity of the car is 54 km/h. After four hours, the velocity of the car is 58 km/h.

Part A: Write an equation in two variables in the standard form that can be used to describe the velocity of the car at different times. Show your work and define the variables used. (5 points)

Part B: How can you graph the equation obtained in Part A for the first six hours? (5 points)

Answers

Since we have two points (2,54) and (4,54), we can assume a linear function and solve for the slope and intercept. So if V=kt+b where t is time passed and v is velocity of the car, we can plug in and solve for k and t, that would give t as a function of v, and you can graph it

t = time

v = velocity

you have (2,54) & (4,58)

v-54 = (58-54) / (4-2) *(t-2)

v=4/2(t-2)+54

v =2(t-2)+54

v = 2t-4+54



b - Graph by plotting the given points (2,54) & 4,58) and drawing a straight line through them

The length of a rectangle is 5 in. more than twice its width. its area is 102 in2. find the length of the rectangle

Answers

Let the width be x. 
Length: 5"+2x 

102=(5+2x)x 
102=5x+2x²
0=2x²+5x-102 

x=-8.5 or x=6" (I used my graphing calculator to find this) 

Since width cannot be negative, the only solution left would be 6. The length would be (5+2(6))=11"

Hope I helped :)

At Taft high school 59% of all students participate in after school sports and 23% participate in both after school sports and volunteer activities. What is the probability that a student participates in volunteer activities given that the student participates in after school sports. A. 82% B. 36% C. 59% D. 39%

Answers

The answer is D or 39% 
An easy way to remember this without all the confusing symbols is the formula:

Both/one = other one

Meaning  the both of the probabilities combined divided by one of the probabilities = the other probability.

.23/.59 = other one
0.389 = other one
0.39 = other one

Hope this helps!

how to solve bh+hr=25 when solving for h

Answers

This is what I got. The answer isn't simplified so if ur teacher wants it simplified I can't help u there, but this should be correct.

Four more than the quotient of a number and 3 is at least 9

Answers

The correct answer is 15

 4 + (x/3) = 9 

(x/3) = 9 - 4 

(x/3) = 5 

x = 15 

Explanation of an inequality involving addition and division

The given inequality is: 4 + (x/3) ≥ 9

To express the statement algebraically:

Add four to the quotient of a number and 3.

Set the expression greater than or equal to 9.

Solve for x to find the number that satisfies the inequality.

the teacher separated her class of twenty-eight students into two groups. One group has 4 more than twice as many students as the other group. How many students are in each group?

Answers

x + y = 28
x = 2y + 4

2y + 4 + y = 28
3y + 4 = 28
3y = 28 - 4
3y = 24
y = 24/3
y = 8

x = 2y + 4
x = 2(8) + 4
x = 16 + 4
x = 20

there are 8 students in one group and 20 students in the other group
8 and 20.
One group has 8 children.
8 x 2=16
16+4=20
20+8=28

PLEASE HELP!!!!!!!!!!!
Whats the value of x?
4x=5x-12
x=

Answers

4x = 5x - 12 
4x - 5x = -12
-x = -12
x = 12

Two buses are traveling to a state park. One bus leaves the terminal at 4:00 p.m. and travels at 40 miles per hour. The second bus leaves the terminal at 5:00 p.m. and travels at 60 miles per hour.

How much time passes until the second bus catches up with the first bus?

Answers

Final answer:

The second bus catches up with the first bus in 2 hours.

Explanation:

To calculate how much time passes until the second bus catches up with the first bus, we need to find the distance between them when the second bus starts and the relative speed between the two buses.

When the second bus starts, the first bus has already traveled for 1 hour (from 4:00 p.m. to 5:00 p.m.) at a speed of 40 mph. Therefore, the first bus has covered a distance of 40 miles.

The relative speed between the two buses is the difference in their speeds, which is 60 mph - 40 mph = 20 mph.

Using the formula: t = d / v, where t is the time, d is the distance, and v is the speed, we can calculate the time it takes for the second bus to catch up with the first bus:

t = 40 miles / 20 mph = 2 hours.

Therefore, it takes 2 hours for the second bus to catch up with the first bus.

Do I solve this by equaling both equations to each other?

Answers

Yes, you got it! You would need to set the equations equal to each other, because that represents when their populations are the same. Then, solving for x will find the time in months until you reach that equilibrium in population. If you need help solving for x, just comment on this. Hope it helps!

Kiko is coasting on her bicycle down a hill. After 3 s, her speed is 10 m/s. After 8 s, her speed is 25 m/s. What is her acceleration during this time?

Answers

use formula : acceleration= final velocity- intial velocity ÷ time
a=(vf-vi)÷t
a=(25-10)÷(8-3)
a=15/5
a=3m/s^-2

Kiko is coasting on her bicycle down a hill. After 3 s, her speed is 10 m/s. After 8 s, her speed is 25 m/s. Her acceleration during this time will be  5 m/s².

What is acceleration?

Acceleration is the rate of change in both speed and direction of velocity over time. When anything moves faster or slower in a straight line, it is said to have been accelerated. Because the direction is always shifting, motion on a circle accelerates even while the speed is constant.

It is given that, Kiko is coasting on her bicycle down a hill. After 3 s, her speed is 10 m/s. After 8 s, her speed is 25 m/s.

Acceleration is found as the ratio of the change in speed to the change in a time interval.

Acceleration =  change in speed/ change in a time interval

Acceleration = (25-10) / (8-5)

Acceleration = (15)/(3)

Acceleration = 5 m/s²

Thus, Kiko is coasting on her bicycle down a hill. After 3 s, her speed is 10 m/s. After 8 s, her speed is 25 m/s. Her acceleration during this time will be  5 m/s².

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if 1 inch = 2.54 centimeters how many inches is equal to 254 centimeters

Answers

divide 254 by 2.54 to get 100 inches.
254 cm is exactly 100 in
CM= centimeters and IN= inches

I need help solving this!!!

Numbers 3 and 4, solve algebraically. I don't get #5 question.

Answers

x = # of hours tutoring ES
y = # of hours tutoring HS

equations
20x + 30y = 140
x + y = 6

solve
20x + 30y = 140
x + y = 6

x = 6 - y

substitute x = 6 - y into 20x + 30y = 140

20x + 30y = 140
20(6 - y) + 30y = 140
120 - 20y + 30y = 140
10y = 20
    y = 2

x = 6 - y
x = 6 -2
x = 4

answer
Tutor:
ES = 4 hours and HS = 2 hours

please help i will give a brainlist if you get it right

Answers

Scale factor = 15 ÷ 5 = 3

Perimeter = 3 × 12 = 36 ft.

Evaluate the expression 14.3-2×5^2÷5

Answers

the answer is 4.3
14.3-2×5^2÷5
14.3-2×25÷5
14.3-50÷5
14.3-10
4.3
Calculate 14.3-2x5
Multiply the two end numbers ( 2x5 )
Substantial the numbers to get the answer
4.3

Your cruise ship is leaving for a 610 league adventure. how many nautical miles is this

Answers

This problem is solved using dimensional analysis. It is known that there are 5280 yards in a league and that there are 3 feet in one yard. Finally, it is known that there are 6076 feet in one nautical mile. As a result, we can multiply these dimension together, making certain that the units cancel and leave us with only nautical miles. It is done as follows: (610 leagues)(5280yds/1 league)(3 ft/1yd)(1 nautical mile/6076ft)= 1590 naurtical miles.

Final answer:

A 610-league adventure is equivalent to 1830 nautical miles, calculated by multiplying the number of leagues by the conversion factor, where one league is equal to approximately 3 nautical miles.

Explanation:

To convert the distance from leagues to nautical miles, we need to know the conversion factor. One league is approximately 3 nautical miles. Thus, by multiplying the given number of leagues by this factor, we can determine the distance in nautical miles.

If the cruise ship is embarking on a 610-league adventure, we calculate the equivalent distance in nautical miles as follows:

Multiply the number of leagues (610) by the conversion factor (3).

The calculation would be 610 leagues * 3 nautical miles/league = 1830 nautical miles.

Therefore, a 610-league voyage is equivalent to 1830 nautical miles.

A digital camera memory card is 1/4 full. The card is 2/3 full when 375 more pictures have been taken. How many pictures can the memory card hold?

Answers

Final answer:

The memory card can hold a total of 900 pictures.

Explanation:

The question asks us to find the total capacity of the memory card in a digital camera by using the information that it is 1/4 full before 375 pictures are added, and 2/3 full after these pictures are added.

Let's define the total capacity of the memory card as 'x' pictures.

If 1/4 of the card is full, then it contains x/4 pictures.

After adding 375 pictures, the card becomes 2/3 full, which means:

x/4 + 375 = (2/3)x

To solve for x, we need to get all the x's on one side of the equation and the numbers on the other side:

Multiply both sides of the equation by 12 to get rid of the fractions: 12(x/4) + 12(375) = 12(2/3)xSimplify the equation: 3x + 4500 = 8xSubtract 3x from both sides: 4500 = 5xDivide both sides by 5: 900 = x

Therefore, the memory card can hold a total of 900 pictures.

Help me with this please

Answers

Greetings!

To convert a mixed number into an improper fraction, you multiply the whole number by the denominator. Then, you add that number to the numerator.

Examples:
a)
8 1/4

8*4=32
32+1=33
=33/4

b)
3 4/5
3*5=15
15+4=19
=19/5

I'll let you attempt the last one on your own. :)

Hope this helps.
-Benjamin

The gross income of Abelina Bennett is $215 per week. Her deductions are: $15.16, FICA tax; $29.33, income tax; 2% state tax; 1% city tax; and 3% retirement fund. What is her net income?

Answers

Final answer:

To calculate Abelina Bennett's net income, subtract her deductions from her gross income. Her net income is $157.61 per week.

Explanation:

To calculate Abelina Bennett's net income, we need to subtract her deductions from her gross income. The deductions include FICA tax, income tax, state tax, city tax, and retirement fund.

Step 1: Add up all the deductions:
FICA tax: $15.16
Income tax: $29.33
State tax: 2% of $215 = $4.30
City tax: 1% of $215 = $2.15
Retirement fund: 3% of $215 = $6.45

Step 2: Calculate the total deductions: $15.16 + $29.33 + $4.30 + $2.15 + $6.45 = $57.39

Step 3: Subtract the total deductions from the gross income: $215 - $57.39 = $157.61

Abelina Bennett's net income is $157.61 per week.

A cube has a surface area of 900 cm what is the number of cubic cm in the volume of the cube

Answers

SA = 900cm^2
SA = 6×(s^2), where "s" is one side or edge of each square surface face
900 = 6s^2
150 = s^2
[tex] \sqrt{150} = \sqrt{ {s}^{2} } [/tex]
[tex] \sqrt{25} \times \sqrt{6} = s[/tex]
[tex]5 \sqrt{6} = s[/tex]
So each side is
[tex]5 \sqrt{6} \: cm \: long[/tex]
The volume (V) of a cube is:
[tex]v = {s}^{3} = (5\sqrt{6})^{3} = {12.247}^{3} \\ = 1837 \: {cm}^{2} [/tex]

If there are 400 people in a room, what is the probability of at least 2 people sharing the same birthday?

Answers

Basically a 50% chance.
Final answer:

The probability of at least 2 people out of 400 sharing the same birthday is almost certain due to the 'birthday paradox', due to there being only 365 days in the year but 400 people in the room.

Explanation:

The probability that at least 2 people out of 400 sharing the same birthday is almost certain due to the 'birthday paradox.' This is because there are only 365 days in a year for birthdays, but we have 400 people in the room.

To calculate this probability, we assume that every person is equally likely to be born on any day of the year (ignoring leap years). The first person can have their birthday on any of 365 days. The second person has a 364/365 chance of not having the same birthday as the first. The third person has a 363/365 chance of not sharing a birthday with the first two, and so on. By the time we reach the 366th person, the probability of them not sharing a birthday with anyone else is zero, since all 365 possible birthdays have been taken.

So, the overall probability of at least 2 people sharing a birthday is 1 minus the probability of all 400 people having unique birthdays. When you calculate it with 400 people, the result is almost 1, which indicates that it's nearly certain at least 2 people share a birthday.

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Which expression is equivalent to the given expression?


13x – 29x


A.x(29 – 13)

B.13(x + 29)

C.x(13 – 29)

D.13(x – 29)

Answers

The answer is C.x(13-29)

Let f (x) = 2x - 1, g(x) = 3x, and h(x) = x2 + 1. Compute the following: f (h(x)) and . g (f (x))

Answers

Answer is below.........

1) After striking a pair of arcs from each endpoint of a line segment, what is the next step in constructing the segment's perpendicular bisector?

Answers

After striking a pair of arcs from each endpoint of a line segment, just join the intersection point of the 1st pair (above the segment) with the intersection point
of the 2nd pair (under the segment)
And this is how you construct the segment's perpendicular bisector


C) Use a straight edge to draw a vertical line between the points where each pair of arcs intersect.

what is the common factor of 24a^3c and 3a

Answers

The common factor of 24a^3c and 3a is 3a

24a^3c /3a = 8a^2c

3a/3a = 1

hope this helps

Please check my answer!

Hogan needs to rent a car while on vacation. The cost of the vehicle is $21 per day. He gives the office manager $180 up front. If x represents the number of days and y represents the total cost of the rental, which equation will help Hogan determine if he owes the agency money at the end of his trip or if the agency owes him money?

Answers

The first one.... y=$21x-$180
Hope this helps!!

Answer:

[tex]y=21x-180[/tex]

Step-by-step explanation:

The cost of the vehicle is $21 per day. He gives the office manager $180 up front.

The upfront is a type of advance payment that is deducted from the final amount.

Let x represents the number of days and y represents the total cost of the rental.

So, the correct equation here is :

[tex]y=21x-180[/tex]

Given the system of constraints, name all vertices of the feasible region. Then find the maximum value of the given object function.

Answers

Refer to the figure shown below.

The feasible region that satisfies all the constraints is the shaded region.
The bounding vertices are
A (0, 3)
B (0, 0)
C (5, 0)
D (1.5, 3.5)

All the functions that define the constraints are either linear or constant.
The maximum value is at vertex D, and equal to 3.5.

One number is 3 less than twice another. If their sum is 39, find the numbers.
Which of the following systems of equations represents the word problem?

A) y=2x-3 and y=x+39
B) y=2x-3 and x+y=39
C) y=2(x-3) and x+y=39

Answers

Based on the given information, we know that x+y=39

Let "one number" be y
Let the other number be x
This would mean y=2x-3
2x="two times the other number"
-3= "three less"

The correct answer:
B) y=2x-3 and x+y=39
the answer to that is

B.y=2x-3 and x+y=39

Find the range of the logarithmic function f(x) = log4 x.

Answers

all real numbers. the domain is all numbers grater than zero

estimate 63 times 39

estimate 62.93 times 73

estimate 34.44 times 57

Answers

2,457
4,593.89
1,973.08

Estimate of 63 times 39: Approximately 2400.

Estimate of 62.93 times 73: Roughly 4410.

Estimate of 34.44 times 57: About 2040.

To estimate the products, you can round the numbers and then perform the multiplication.

Here are the estimates for the given multiplication problems:

Estimate of 63 times 39:

Round 63 to 60 and 39 to 40.

Calculate 60 times 40, which is 2400.

Estimate of 62.93 times 73:

Round 62.93 to 63 and 73 to 70.

Calculate 63 times 70, which is 4410.

Estimate of 34.44 times 57:

Round 34.44 to 34 and 57 to 60.

Calculate 34 times 60, which is 2040.

These are rough estimates and may not be entirely accurate, but they provide a quick way to get an idea of the approximate result of the multiplication.

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