On the ride "spindletop" at the amusement park six flags over texas, people stood against the inner wall of a hollow vertical cylinder with radius 2.5 m. the cylinder started to rotate, and when it reached a constant rotation rate of 0.60 rev/s, the floor on which people were standing dropped about 0.5 m. the people remained pinned against the wall.

Answer: no ailment found in the body

Explanation: a body is said to be physically fit if it dies not deviate from the standard way a body should be that is it should have no sickness not injury

Answer: Option (D) is the correct answer.

Explanation:

The given reaction is a nuclear fusion reaction because in a nuclear fusion two small nuclei combine together to result in the formation of a large nuclei along with the release of energy.

The complete given reaction will be as follows.

     [tex]^{2}_{1}H + ^{3}_{1}H \rightarrow ^{4}_{2}He + ^{1}_{0}n + Energy[/tex]

Thus, we can conclude that along with the release of helium atom there will be release of one neutron and energy.

To reduce the dissipated power by 10% while maintaining the same leakage current, the voltage needs to be reduced in such a way that the new power dissipation equals 90% of the original power, due to the direct proportionality between power and voltage in the formula P = IV.

The question asks: If the total dissipated power is to be reduced by 10%, how much should the voltage be reduced to maintain the same leakage current? Power dissipation in an electrical circuit is described by the formula P = IV, where P is the power in watts, I is the current in amperes, and V is the voltage in volts.

To find the new voltage required to reduce the power dissipation by 10%, we first have to understand that if the leakage current remains constant, the power reduction is directly proportional to the reduction in voltage. Given the initial power Pm = 1.0 × 10³ W, reducing this power by 10% results in Pnew = 0.9Pm = 0.9 × 1.0 × 10³ W.

Since P = IV and I remains constant, the new power equation after reduction can be written as 0.9Pm = I × Vnew. Substituting the values and assuming the initial current remains unchanged, we solve for Vnew, resulting in a voltage reduction proportionate to the desired 10% power reduction.

THE ANSWER IS D YOUR WELCOME:)

The answer is FALSE.

Answer:

False.

Explanation:

Any individual cant really become an expert in anything. Induvisuals might just be a normal person, and some be experts, To me about 20% of people can be experts 60% might just be a normal person. Some people have cancer, health problems, and diseases, or sicknesses. and some might not be good at some point at something.

Answer:

Radiation

Explanation:

Infrared radiation, that portion of the electromagnetic spectrum that extends from the long wavelength, or red, end of the visible-light range to the microwave range. ... Most of the radiation emitted by a moderately heated surface is infrared; it forms a continuous spectrum.

The automobile taking approx. 178.54s (or around 3 minutes) while traveling 180ft is calculated using fundamental kinematic equations to determine constant acceleration and then time.

To solve this, we need to utilise some basic kinematic equations. First, let's find the acceleration using the formula a = (vf - vi)/s where vf = final velocity, vi = initial velocity, and s = displacement distance. Substituting in the provided values: a = (84ft/s - 72ft/s)/180ft = 0.067 ft/s².

Next, we use the equation t = (vf - vi) / a where t = time, vf = final velocity, vi = initial velocity, and a = acceleration. Substituting in the relevant values, we get t = (84ft/s - 72ft/s) / 0.067ft/s² ≈ 178.54s or approximately 3 minutes.

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The currents (Amperes) in the two cases are calculated as power/voltage: 

510000W / 12000V = 42.5 A 
510000W / 47000V = 10.85 A 

And that the power wasted in the two cases is calculated as current^2 x resistance:

(42.5 A)^2 (2.5 Ohms) = 4,515.625 W 
(10.85 A)^2 (2.5 Ohms) = 294.30625 W 

So the amount of power saved is the difference:
4,515.625 - 294.30625  = 4221.32 Watts

This is the main reason why distribution grids aim to operate at the highest voltages possible.

The pressure of an enclosed fluid on which force is applied is 150 N over an area of 10 cm² will be 1500 N/m² or 1500 Pa.

In the physical sciences, pressure is defined as the perpendicular force per unit area or the stress at a particular location within a confined fluid The force divided by the area over which it is exerted, or one-half pound per square inch, determines the pressure that a 42-pound box with an 84-square-inch bottom will impose on a surface.

Atmospheric pressure, which at sea level is roughly 15 pounds per square inch, is the amount of weight that the atmosphere exerts on each unit area of the Earth's surface. One pascal equals one newton per square meter when expressed in SI units, which is how pressure is calculated.

According to the question :

Pressure, P = F / A

P = 150 N

A = 10 cm² or

A = 0.1 m²

P = 150 / 0.1

P = 1500 Pa.

Hence, the Pressure on the enclosed fluid is 1500 Pa.

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A ray is an ultrathin beam of light that travels in a straight line until it meets a reflecting or refracting surface. Geometric optics is the branch of physics that models the path of light as straight lines called rays.

A ray can be considered as an ultrathin beam of light that travels in a straight line until it meets a reflecting or refracting surface. In physics, the path of light is often modeled as straight lines called rays in the field of geometric optics. When light encounters objects several times larger than its wavelength, it behaves like a ray with subtle wave characteristics.

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Answer: The correct answer is (d).

Explanation:

Magnet has two poles: South pole and North pole. The same poles of the magnets repel each other. The opposite poles of the magnets attract each other.

In the absence of other magnet, a freely swinging magnet points in North-South direction. The earth has a magnetic field. The magnetic field of the bar magnet is same as the magnetic field of the earth's magnet.

The position of  the earth's magnetic poles are not fixed. The south pole of the earth's magnet lies in the geographic north as it attracts the north pole of the freely swinging magnet.

If one part of a freely suspended magnet always points to Earth's magnetic pole in the Northern Hemisphere.

The magnitude of the frictional force between the block and the surface while the block is moving is 9m.

The magnitude of the frictional force between the block and the surface while the block is moving can be determined using the principle of conservation of momentum.

When the bullet passes through the block, the total momentum of the system is conserved. The initial momentum of the bullet is mv and the initial momentum of the block is 0.

After the collision, the final momentum of the bullet is (1/3)mv and the final momentum of the block is (4m)(v/3). Setting the initial and final momenta equal, we can solve for the magnitude of the frictional force.

Initial momentum of the system = Final momentum of the system

mv + 0 = (1/3)mv + (4m)(v/3)

Simplifying the equation, we get:

mv = 2mv/9

Cancelling out the m and solving for v, we get:

v = 9m

Therefore, the magnitude of the frictional force between the block and the surface while the block is moving is 9m.

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One of the most significant properties of water is its ability to dissolve a wide variety of substances. Solutions in which water is properly the dissolving medium are called aqueous solutions. For electrolytes, water comes by the most primary solvent.  

Notes:

Keywords: classify, each of these soluble solutes, as a strong electrolyte, a weak, a nonelectrolyte. drag each item to the appropriate bin, acids, bases, dissolve, ionize, conduct electricity, water

A molecules speed up because the temp is rising there for the molecules speed up

hope this helped =^-^=

I believe that the correct given values are:

density = 755 kg/m^3

volume = 640 cm^3

First let us convert volume to m^3 units.

volume = 640 cm^3 * (1 m / 100 cm)^3 = 6.4 x 10^-4 m^3

so the mass is:

mass = 755 kg/m^3 * (6.4 x 10^-4 m^3)

mass = 0.4832 kg = 483.2 g

The mass of the piece of maple wood is calculated to be approximately 0.4832 kg by rearranging the formula for density (D = M/V) to solve for mass (M = D*V), and then substituting in the provided density and volume values.

The student is asked to find the mass of a piece of maple wood, given its volume and density. We use the formula for density which is D = M/V, where D is the density, M is the mass, and V is the volume. To find the mass, we rearrange the formula to M = D*V. Given that the density of maple wood is about 755 kg/m³ and the volume is 640 cm³ (which is equivalent to 0.00064 m³), we calculate the mass as follows: M = 755 kg/m³ * 0.00064 m³ = 0.4832 kg.

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The force on the child midway up is equivalent to half the child's weight, which is expressed as F = m*g/2, where m is the mass of the child and g is the acceleration due to gravity.

To calculate the magnitude of a force on a child midway up a ride in terms of mg (Gravitational force), we first must acknowledge that this is a situation involving rotational mechanics and centripetal forces. We shall employ the concept of moment of inertia, that acts equivalent to mass in linear motion for cases of rotational motion.

The child can be considered as a point mass, with a moment of inertia Ic = mR². For the given values in the text, the moment of inertia Ic of the child would be (18.0 kg)(1.25 m)² = 28.13 kg · m². This value would assist us in calculating the force in the upcoming steps.

Due to the ride's circular motion, the child experiences a centripetal acceleration. Set this centripetal acceleration equal to the acceleration due to gravity: 9.8 m/s². Since we are midway up the circle, the total acceleration would be divided by two:

a_c = g/2 = 4.9 m/s².

The force causing this centripetal acceleration, in terms of mg, can be acquired by using Newton's second law, F = ma. Thus:

F = m*a_c = m*g/2 = mg/2.

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From the statement, since rocket was launched so this means that it start from zero, hence initial velocity is zero. 
Since the rocket was launched vertically straight up, the force acting on this motion is gravity.

 
A. The acceleration of the motion is then given by:

a= F/m - g 

Then we can use the general equation:

V^2 = Vo^2 + 2*a*h

where V is final velocity, Vo is initial velocity, a is acceleration, h is height 

Since we know that Vo = 0, so 

V^2 = 2*a*h 

V^2 = 2 (F/m – g) h
V = sqrt [2 h (F/m – g)]

B. Given that:

h = 86 m

F = 10 N

m = 340 g = 0.34 kg

Find for V:

V = sqrt [2 * 86 (10 / 0.34 – 9.8)]

V = 58.08 m/s

To find the rocket's speed at height h, use Newton's second law of motion and kinematic equations. The rocket's speed can be expressed as v = sqrt(2gh - 2Fthrusth/m). For the given values, the rocket's speed is 136.36 m/s.

a. To find the rocket's speed at height h, we can apply the principles of Newton's second law of motion. Since air resistance is neglected, the only force acting on the rocket is the thrust force. The thrust force can be written as Fthrust = ma, where m is the mass of the rocket and a is the acceleration. The acceleration is given by a = g - g'' where g is the acceleration due to gravity and g'' is the acceleration due to the thrust force. Since g'' is directed opposite to the gravitational acceleration, we subtract it. On rearranging the equation, we get g'' = g -a. Substituting this into the equation Fthrust = ma, we obtain Fthrust = m(g - a). Solving for a, we get a = g - Fthrust/m. At height h, the rocket's speed can be found using the kinematic equation v² = u² + 2as, where v is the final velocity, u is the initial velocity, a is the acceleration, and s is the displacement. Since the initial velocity is 0, we have v² = 2as. Substituting the expression for acceleration, we get v² = 2gh - 2Fthrusth/m. Taking the square root of both sides, we have v = sqrt(2gh - 2Fthrusth/m).

b. Substituting the given values Fthrust = 10 N, m = 0.34 kg, h = 86 m, and g = 9.8 m/s² into the expression v = sqrt(2gh - 2Fthrusth/m), we can calculate the rocket's speed as it reaches a height of 86 m. Plugging in the values, we get v = sqrt(2 * 9.8 * 86 - 2 * 10 * 86 / 0.34) = 136.36 m/s.

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Final answer:

If the pulley is not set parallel to the track, it will introduce a perpendicular component of the tension force, resulting in a reduction in the acceleration of the system. The normal force from the track will also increase, opposing the motion. This would be a systematic error as it stems from a consistent deviation from the correct setup.

Explanation:

If the pulley is not set so that the string is parallel to the track, it will introduce a component of the tension force that is perpendicular to the track. This perpendicular component will result in a normal force from the track which will oppose the motion of the system. Consequently, the acceleration of the system will be reduced. This effect can be understood by breaking down the tension force into components parallel and perpendicular to the track.

When the string is not parallel to the track, let's say at an angle theta, the tension force can be resolved into two components:

1. A component parallel to the track (T_parallel = T * cos(theta))

2. A component perpendicular to the track (T_perpendicular = T * sin(theta))

The parallel component (T_parallel) is responsible for providing the force that accelerates the system. The tension force is equal to the product of mass and acceleration (T_parallel = m * a). Therefore, any decrease in the parallel component of the tension force will result in a decrease in acceleration.

The perpendicular component (T_perpendicular) introduces a force perpendicular to the track, which is counterbalanced by the normal force from the track. As the angle theta increases, the normal force increases, opposing the motion and reducing the acceleration of the system.

This would be a systematic error because it is a consistent deviation from the correct setup. Systematic errors occur due to flaws in the experimental setup or technique. In this case, the error arises from the misalignment of the pulley and the track.

The average speed of the particle that travels 15 times around a 10 cm radius circle in 42 seconds is 0.224 m/s.

To calculate the average speed of a particle, we use the formula: Speed = Distance ÷ Time. In this case, the distance travelled is the circumference of the circle (2πr) multiplied by the number of times the particle goes around the circle. Given that the particle travels 15 times around a 10 cm radius circle, the total distance is 2π*0.1m*15 = 9.42m. Since the time taken is 42 seconds, the average speed of the particle is then 9.42m ÷ 42s = 0.224 m/s.

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The particle's average speed is calculated by dividing the total distance travelled (15 times around the circle) by the total time taken (42 seconds). The speed is approximately 0.224 m/s.

The subject of your question is physics, specifically dealing with the concept of speed in circular motion. To solve this, we need to understand that the particle is traveling in a circular path with a known radius 15 times in a given time of 42 seconds. Therefore, the total distance travelled by the particle can be calculated using the formula for the circumference of a circle, which is 2πr (where r is the radius), multiplied by the number of circles made.

First, we need to convert the radius from cm to meters because the standard unit of measurement for speed is m/s. So, 10cm = 0.10m. Now, calculating the total distance travelled: 15 circles * 2 * π * 0.10m = 9.42m.

The speed of any object is defined as the ratio of the distance travelled to the time taken. So, the average speed of the particle will be calculated as (total distance / total time). Accordingly, the speed of particle would be 9.42m / 42s = 0.224m/s.

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Electric motor

Answer:

A). Electric generator

Explanation:

Answer:

Explanation:

Drag each tile to the correct box.

Lori’s family is on a road trip. They split their drive into the five legs listed in the table. Find the average velocity for each leg of the trip. Then arrange the legs of the trip from lowest velocity to highest.

Leg Distance (km) Time (min)

A 15 10

B 20 15

C 24 12

D 36 9

E 14 14

leg A

leg B

leg C

leg D

leg E