A rock is rolling down a hill. At position 1, its velocity is 2.0 m/s. Twelve seconds later, as it passes position 2, its velocity is 44.0 m/s. What is the acceleration of the rock?
Answer:
The correct answer is 3.5 m/s²
Explanation:
To determine the average acceleration of the rock,
the change in velocity is divided by the time interval (in seconds)
change in velocity = V₂ - V₁
where V₁ is the initial velocity (2.0 m/s) and V₂ is the final velocity (44.0 m/s)
change in velocity = 44 - 2 = 42 m/s
The time interval is 12 seconds (no need for conversion as it is in seconds already)
average acceleration of the rock = 42 ÷ 12 = 3.5 m/s²
An inattentive driver is traveling 15.0 m/s when he notices a red light ahead. his car is capable of decelerating at a rate of 3.35 m/s2 . part a if it takes him 0.210 s to get the brakes on and he is 66.0 m from the intersection when he sees the light, will he be able to stop in time
A long jumper jumps at a 20-degree angle and attains a maximum altitude of 0.6 m. What is her initial speed? [10m/s] How far is her jump? [6.59m]
I need someone to explain to me how to get the answers listed above my showing a detailed step to step process.
The initial speed of the long jumper is calculated by finding the upward component of her velocity caused by her jumping at a 20-degree angle and achieving a maximum height of 0.6 m, then determining the total velocity by dividing this by the sine of the launch angle. The distance of her jump is found by applying these values in the formula for the range of a projectile. Both calculations assume no air resistance.
Explanation:In this problem, the initial speed of the jumper is determined using the physics concepts of projectile motion.
To find the initial speed, first, we compute the upward component of the velocity using the formula ਙ = √(2*g*h), where g is the acceleration due to gravity (approximately 9.81 m/s²), and h is the maximum height (in this case, 0.6 m). The upward component of the velocity comes out to be approximately 3.443 m/s.
Second, we determine the initial speed by dividing the upward component of the velocity by the sine of the angle, which in this case is 20 degrees. This gives us an initial speed of approximately 10 m/s.
The distance of the jump (or the range of the projectile) can be calculated using the formula R = (vₒ²/g) * sin(2θ), where R is the range, vₒ is the initial velocity, g is the acceleration due to gravity, and θ is the launch angle. Substituting the values, the range comes out to be approximately 6.59 m.
These answers are based on ignoring any effects of air resistance.
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what is the density of a salt solution if 50.0 ml has a mass of 57.0 g?
Density of given salt solution is 1.14 gram / milliliter
Given:
Mass of salt solution = 57 gram
Volume of salt solution = 50 milliliter
Find:
Density of a salt solution
Computation:
⇒ Density = Mass / Volume
⇒ Density of a salt solution = Mass of salt solution / Volume of salt solution
⇒ Density of a salt solution = 57 / 50
⇒ Density of a salt solution = 1.14 gram / milliliter
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Why does a gun recoil when a bullet is fired?
Why does a gun recoil when a bullet is fired?
Explanation:When a bullet is fired, the gun exerts a force on the bullet through the trigger (this is action) in a particular direction. According to Newton's Third Law, we know to every action there is an equal and opposite reaction; action and reaction act on different bodies. So, the bullet will also exert an equal and opposite reaction on the gun in the opposite direction. That is why a gun recoils when a bullet is fired from it.
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What does newtons first law of motion state about objects on which forces are balanced?
which of the following correctly describes a longitudinal wave
What happens to the gas pressure within a sealed gallon can when it is heated? when it is cooled?
Why is force not on a scalar quantity??
Answer:
Explanation:
Scalar quantity is described as such quantities measured which has only magnitude but not direction.
Force when applied on any object is always denoted and comes with direction. It is always necessary to represent force is acting on which direction.
Hence force is not a scalar quantity. It is a vector quantity as it has magnitude as well as direction.
A fairgrounds ride spins its occupants inside a flying saucer-shaped container. if the horizontal circular path the riders follow has a 5.00 m radius, at how many revolutions per minute will the riders be subjected to a centripetal acceleration whose magnitude is 1.50 times that due to gravity?
The centripetal acceleration (a ) of an object moving in a circular path of radius r at a constant speed and v is = a = v²/r
The riders are subjected to a centripetal acceleration that is 1.50 times the acceleration due to gravity, a = 1.50 × g.
a = r ×ω ²
1.50 g = r ×ω ²
ω ² = √1.50 g / r
rpm = ω/2π ×60
rpm= √1.50⋅g/ r/2 π ×60
rpm = 9.50
Therefore, the riders will be subjected to approximately 9.50 revolutions per minute.
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A scale model of a race car is 18.2 centimeters long and 6.9 centimeters long. each centimeter on the model represents 0.3 meters on the actual car. how long is the actual car
The actual car is 5.46 meters long.
To determine the length of the actual car based on its scale model, first note the given details:
The model car is 18.2 centimeters long.Each centimeter on the model represents 0.3 meters on the actual car.We can calculate the length of the actual car using the formula:
Length of actual car = (Length of model car in cm) × (Scale factor in meters/cm)
Substituting the given values:
Length of actual car = 18.2 cm × 0.3 meters/cm = 5.46 meters
Thus, the actual car is 5.46 meters long.
A baseball player uses a pitching machine to help him improve his batting average. he places the 54.6 kg machine on a frozen pond. the machine fires a 0.149 kg baseball horizontally at a speed of 42.6 m/s. what is the magnitude of the recoil velocity of the machine? answer in units of m/s.
The recoil velocity of the machine is 0.11 m/s in opposite direction.
What is law of conservation of momentum?According to the law of conservation of momentum, when two or more bodies are operating upon one another in an isolated system, their combined momentum stays constant unless an external force is added. Because of this, momentum cannot be created or destroyed.
The mass of the pitching machine is : M = 54.6 kg
The mass of the baseball is: m = 0.149 kg.
The velocity of the baseball is: v = 42.6 m/s.
The velocity of the machine is: V = ?
From law of conservation of momentum;
Momentum of the machine = - momentum of the ball
MV = - mv
V = -mv/M
= - (0.149×42.6)/54.6 m/s
= - 0.11 m/s.
Hence, the recoil velocity of the machine is 0.11 m/s in opposite direction.
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Photovoltaic energy is the conversion of _________ into electricity through a photovoltaic cell. A) sunlight B) hydropower C) wind energy D) nuclear energy
Diamond has a density of 3.26 g/cm3 . what is the mass of a diamond that has a volume of 0.247 cm3 ? answer in units of g.
You're driving along at 25m/s with your aunt's valuable antiques in the back of your pickup truck when suddenly you see a giant hole in the road 55 m ahead of you. fortunately, your foot is right beside the brake and your reaction time is zero!
This question is about the physics of a car's stopping distance and the effect of reaction time on it.
Explanation:The subject of this question is Physics and it is appropriate for high school level students.
In this scenario, the driver is traveling at a speed of 25m/s when they see a hole 55m ahead of them. Since their reaction time is zero, meaning they immediately apply the brakes, the total displacement during the reaction time is 15.0m greater than if they reacted instantly. The stopping distance, in this case, would be the same for both dry and wet concrete, so we need to calculate the distance the car travels during the reaction time and add that to the stopping distance.
To summarize, this question is about the physics of a car's stopping distance and the effect of reaction time on it.
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Without friction, what force is needed to maintain a 1,000 kg car in uniform motion for 30 minutes?
A protostar forms once the nebular cloud condenses and the core begins
Answer:
Explanation:
A protostar forms once the nebular cloud condenses and the core begins HEAT.
A protostar is a very young star that is still gathering mass from its parent molecular cloud. The protostellar phase is the earliest one in the process of stellar evolution. A protostar is the earliest stage in star formation in the universe. When the gas cloud begins to collapse on its own weight, the core begins to heat up. The heat is due to the force of compression of the dust and gas under its gravity. When the pressure and temperatures become high enough, the hydrogen in the core begins to fuse.
larry lightweight stands on a pair of bathroom scales each scale reads 300 N what is larry's mass
Answer:
Mass = 30.6 kg
Explanation:
Given
Weight scale reading W = 300 N
Solution
Weight W = Mass (m) x Acceleration due to gravity (g)
W = mg
m = W/g
m = 300 / 9.81
m = 30.6 Kg
A bathroom scale measures weight which is a force in newtons or pounds. It is calibrated to provide information about mass by dividing the weight measurement by 9.80 in most countries. In this case, if each scale reads 300 N, Larry's mass would be approximately 30.61 kg.
Explanation:A bathroom scale measures weight, which is a force in newtons or pounds. When you stand on a bathroom scale, the springs inside the scale compress in proportion to your weight, similar to rubber bands expanding when pulled. This compression provides a measure of your weight.
However, the scale is calibrated to provide information about mass, so the weight measurement is divided by 9.80 in most countries to give a reading in mass units of kilograms.
In this case, if each scale reads 300 N, we can use the formula F = mg, where F is the force (300 N), m is the mass (unknown), and g is the acceleration due to gravity (approximately 9.80 m/s²). Rearranging the formula, we have m = F/g. Substituting the given values, we get m = 300 N / 9.80 m/s² = 30.61 kg.
The eye of a category 2 hurricane is 450 nautical miles away and forecast to come ashore at your coastal location. the tropical storm-force winds extend 150 nautical miles. if the hurricane's forward speed is 20 knots, how long before tropical storm-force winds begin to affect your community?
Answer:
30 hours
Explanation:
Total distance from the coast to the storm = 450+150 = 600 Nmi
Speed of the hurricane = 20 knots = 20 Nmi/h
Time taken by the hurricane to reach the coast
[tex]\text{Time}=\frac{\text{distance}}{\text{Speed}}\\\Rightarrow \text{Time}=\frac{600}{20}=30 \\\Rightarrow \text{Time}=30 hours[/tex]
∴ Tropical storm-force winds begin to affect the community by 30 hours
Time taken by the eye to reach the coast
\text{Time}=\frac{450}{30}=15 hours[/tex]
Does the sun always shine directly overhead at the equator at noon
A package was determined to have a mass of 5.7 kilograms. What's the force of gravity acting on the package on earth? A. 37.93 N B. 1.72 N C. 13.44 N D. 55.86 N
Answer:
D.55.86 N
Explanation:
three strategies which local municipality is implementing in addressing the issue
Having and drinking hygienic
water is human right and is vital to life. The water should be tested, treated
and filtered to remove any contaminants that can lead do sickness. Some of the
strategies in which local municipality is implementing in addressing the topic of lack of clean water are:
1. Good monitoring of the water supplies
2. Desalination – this is removal of mineral components from saline water
especially salt. The procedure is more expensive but is a way to reuse water
3. Campaign for more proficient and more wisely usage of the
water in order to make the people conscious of the fact how important the
natural resource water is.
Bonnie and clyde are sliding a 300 kg bank safe across the floor to their getaway car. the safe slides with a constant speed if clyde pushes from behind with 445 n of force while bonnie pulls forward on a rope with 350 n of force. what is the safe's coefficient of kinetic friction on the bank floor?
The total force to slide the bank safe is 795 N. The normal force exerted by the safe on the floor is 2943 N. Hence, the coefficient of kinetic friction on the bank floor is 0.27.
Explanation:Solution:
To find the coefficient of kinetic friction, we first need to determine the total force used to move the safe. Bonnie and Clyde are both applying their forces to move the safe in the same direction. So, we add Clyde’s force to Bonnie's force. This gives us a total force of 795 N (445 N + 350 N).
Since the safe slides at a constant speed, it means the applied force is equal to the friction force. Therefore, the friction force is also 795 N. We calculate the normal force which is the weight of the safe, that is mass times the gravity. The mass of the safe is 300 kg and the gravity is approximately 9.81 m/s². Therefore, the normal force is 2943 N (300 kg×9.81 m/s²).
Now, we use the formula of kinetic friction, which is the friction force divided by the normal force, to find the coefficient of kinetic friction. Therefore, the coefficient of kinetic friction on the bank floor is 0.27 (795 N / 2943 N).
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Two friends, barbara and neil, are out rollerblading. with respect to the ground, barbara is skating due south at a speed of 5.9 m/s. neil is in front of her. with respect to the ground, neil is skating due west at a speed of 1.4 m/s. find neil's velocity (a) magnitude and (b) direction relative to due west, as seen by barbara.
It is given that,
Speed of Barbara w.r.t ground, [tex]v_b=-5.9\ m/s[/tex] ( in south)
Speed of neil w.r.t ground, [tex]v_n=-1.4\ m/s[/tex] ( in west)
So, Neil's velocity as seen by Barbara is :
[tex]v^2=\sqrt{(1.4\ m/s)^2+(5.9\ m/s)^2}[/tex]
[tex]v=6.06\ m/s[/tex]
Direction relative to due wet is :
[tex]tan\theta=\dfrac{5.9\ m}{1.4\ m}[/tex]
[tex]\theta=tan^{-1} (4.21)[/tex]
[tex]\theta=76.6\ ^0[/tex]
So, with respect to barbara, Neil is travelling with velocity of 6.06 m/s making an angle of [tex]76.6^0[/tex] due west.
Hence, this is the required solution.
A runner makes one lap around a 200 m track in a time of 25.0 s. What was the runner's average speed?
Does knowing the distance between two objects give you enough information to locate the objects
No, because a single distance could
correspond to a variety of different positions of the objects.
The wavelength of red light is 650 nanometers. how much bigger is the wavelength of a water wave that measures 2 meters?
we know that
[tex] 1 [/tex] nanometer is equal to [tex] 10^{-9} [/tex] meters
so
[tex] 650\ nm [/tex]------> convert to meters
by proportion
[tex] \frac{1}{10^{-9}}\frac{nm}{m} = \frac{650}{x} \frac{nm}{m} \\ \\ x=650*10^{-9} \ nm\\ \\ x=6.5*10^{-7} \ m [/tex]
[tex] Wave\ length\ of\ red\ light = 6.5*10^{-7}\ m [/tex]
[tex] Wave\ length\ of\ a\ water = 2\ m [/tex]
To calculate how much bigger is the wavelength of a water
Divide [tex] 2\ m [/tex] by [tex] 6.5*10^{-7}\ m [/tex]
so
[tex] \frac{2}{6.5*10^{-7}} =3.08*10^{6} [/tex]
therefore
the answer is
[tex] 3.08*10^{6}\ times\ bigger [/tex]
The wavelength of the water wave is 3 x 10⁶ times bigger than that of the red light.
The wavelength of a waveform signal that is propagating in space or over a wire is measured by the separation between identical points, adjacent crests in the adjacent cycles.
Given that the wavelength of red light is 650 nanometers.
We know that 1 nanometer = 10⁻⁹meter
In order to convert 1 nanometer into meter, it should be multiplied by 10⁻⁹.
So, 650 nm = 650 x 10⁻⁹
650 nm = 0.65 x 10⁻⁶
The wavelength of the given water wave = 2 m
So, comparing the wavelength of the red light with that of the water wave,
2/ 0.65 x 10⁻⁶ = 3 x 10⁶
Therefore, the wavelength of the water wave is 3 x 10⁶ times bigger than that of the red light.
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A car is rounding a curve that is the arc of a circle with a radius of r . if the car has a constant speed of 10 m/s, and its acceleration is 5 m/s2 , what is the radius of the curve?
Final answer:
The radius of curvature for a car rounding a curve with a constant speed of 10 m/s and a centripetal acceleration of 5 m/s2 is calculated to be 20 meters.
Explanation:
The problem requires us to find the radius of curvature when a car is rounding a curve with a centripetal acceleration. Centripetal acceleration (a) is given by the formula a = v² / r, where v is the constant speed of the car and r is the radius of curvature. Knowing that the car has a constant speed (10 m/s) and a centripetal acceleration (5 m/s²), we can rearrange this formula to solve for the radius r as follows:
r = v² / a
Substituting the given values:
r = (10 m/s)² / (5 m/s²)
r = 100 m²/s² / 5 m/s²
r = 20 m
Therefore, the radius of curvature of the curve is 20 meters.
The sun was created at the center of the accretionary disk when the temperature became high enough for _________ to occur. fusion fission combustion radiation
Astronauts on our moon must function with an acceleration due to gravity of 0.170 g. If an astronaut can throw a certain wrench 12.0 m vertically upward on earth, how high could he throw it on our moon if he gives it same starting speed in both places?
Final answer:
An astronaut could theoretically throw a wrench approximately 73.5 meters high on the Moon, which is about 6 times higher than on Earth, due to the lower gravitational acceleration.
Explanation:
The question is about how high an astronaut could throw a wrench on the Moon compared to the Earth given the same starting speed. The gravitational acceleration on the Moon is 0.170 g, or approximately 1.6 m/s², which is about 1/6 of that on Earth (9.8 m/s²). Therefore, if an astronaut can throw a wrench 12.0 meters high on Earth, we can calculate how high it would go on the Moon using the ratios of the accelerations due to gravity.
First, we recognize that the maximum height reached by an object thrown vertically is inversely proportional to the local gravitational acceleration. Mathematically:
Height on Earth / Height on Moon = Acceleration due to gravity on Moon / Acceleration due to gravity on Earth
Substituting the given values:
12.0 m / Height on Moon = 1.6 m/s² / 9.8 m/s²
Solving for the height on the Moon gives:
Height on Moon = 12.0 m * (9.8 m/s² / 1.6 m/s²) = 12.0 m * 6.125 = 73.5 m
Therefore, the astronaut could throw the wrench approximately 73.5 meters high on the Moon, assuming no air resistance and the same initial throwing speed.