NaCl(aq) AgNO3(aq) → AgCl(s) NaNO3(aq) : NaCl(aq) AgNO3(aq) \rightarrow AgCl(s) NaNO3(aq) : blank H2SO4(aq) 2 LiOH(aq) → 2 H2O(l) Li2SO4(aq) : H2SO4(aq) 2 LiOH(aq) \rightarrow 2 H2O(l) Li2SO4(aq) : blank HCl(aq) (NH4)2S(aq) → H2S(g) 2 NH4Cl(aq) : HCl(aq) (NH4)2S(aq) \rightarrow H2S(g) 2 NH4Cl(aq) : blank Mg(s) Cu(NO3)2(aq) → Mg(NO3)2(aq) Cu(s) :

Answer:

Covalent bond

Explanation:

Ionic bond- When 1 atom totally transfers 1 or more electron to another atom in order to reach stability.

Covalent bond- Is when 2 atoms share there electrons instead of transferring them so they both would be at a stable configuration.

Answer:

Natural Gas

Explanation:

Naturally occurring hydrocarbon gas are popularly referred to as natural gas or fossil gas. It components include majorly methane gas, other higher alkanes, little percentage of CO₂, N₂, H₂S (hydrogen sulfide) etc. They are produced as a result of exposure of  plant and animal matter to intense heat and pressure under the surface of the Earth over millions of years.When fossil gas/natural gas are burned, they release no sulphur content and there is usually a higher net energy yield than other fossil fuels.

Natural gas is a non-renewable hydrocarbon used as a source of energy such as electric generation, fuels for vehicles etc due to their higher net energy yield.

Answer:

The answer to your question is letter A

Explanation:

Process

1.- Calculate the molar mass of KNO₃

KNO₃    molecular mass = 39.1 + 14.01 + (3 x 16)

                                        = 39.1 + 14.01 + 48

                                        = 101.11 g

2.- Use a rule of three to find the percent of nitrogen

                            101.11 g of KNO₃  ---------------   100%

                             14.01 g of N        ---------------     x

                             x = (14.01 x 100) / 101.11

                             x = 13.86%

Final answer:

In this problem, 1 mole of CO₂ is produced for every mole of carbon atoms and 1 mole of H₂O is produced for every 2 moles of hydrogen atoms. By using these ratios, the masses of carbon and hydrogen in the original sample can be calculated from the masses of CO₂ and H₂O, and their molar masses.

Explanation:

Upon combustion, 1 mol of CO₂ is produced for each mole of carbon atoms in the original sample. Similarly, 1 mol of H₂O is produced for every 2 mol of hydrogen atoms present in the sample. The masses of carbon and hydrogen in the original sample can be calculated from these ratios, the masses of CO₂ and H₂O, and their molar masses. Because the units of molar mass are grams per mole, we must first convert the masses from milligrams to grams:

Answer:

1. Amplitude 2. Wavelength 3.Pressure

Explanation:

I just did the quiz

A loud sound has a large amplitude. Wavelength is the distance between two peaks or crests. Sound waves are a type of radiation  wave.

Sound is defined in physics as a vibration that travels as just an acoustic wave through with a data transmission like a gas, liquid, or solid. Sound is the receipt of such waves as well as their perception even by brain in human physiology as well as psychology.

A loud sound has a large amplitude. Wavelength is the distance between two peaks or crests. Sound waves are a type of radiation  wave.

Therefore, a loud sound has a large amplitude. Wavelength is the distance between two peaks or crests. Sound waves are a type of radiation  wave.

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Answer:

3

Explanation:

Firstly, we need to define the phenomenon know as isomerism. It is a phenomena in which 2 or more organic compounds have the same molecular formula but different structural arrangements.

In this special case of pentane, we are looking at other compounds whose molecular formulas are also C5H12 but have a different structure from that of pentane. It must be noted that two isomers might belong to the same homologous series or belong to a different homologous series entirely.

The first isomer is 2-methylbutane also known trivially as isopentane. It has the same molecular formula as said earlier with a methyl group substituted for a hydrogen atom on the second carbon of the principal chain of the molecule.

The second one is n-pentane itself. This is the normal straight chain pentane in its linear form.

The third one is 2-ethylpropane or dimethylpropane trivially knows as neopentane.

Pentane (C₅H₁₂) has three structural isomers: pentane, isopentane, and neopentane. These isomers differ in their carbon chain arrangement and have distinct properties, including boiling points. This brings the total number of structural isomers to three.

Pentane (C₅H₁₂) is a straight-chain hydrocarbon with a molecular formula that allows for three structural isomers. These isomers are:

Therefore, besides the straight-chain version (pentane), there are two additional structural isomers for pentane, bringing the total number of isomers to three. Each of these isomers possesses unique properties, such as different boiling points: pentane (36.1°C), isopentane (27.7°C), and neopentane (9.5°C).

Answer:

Empyrical formula is CH₂

Explanation:

A compound of carbon and hydrogen which has a molar mass of 42 g/m, is the  propene, alkene of 3 carbons.

CH₂ == CH --- CH₃

As the molecular formula is C₃H₆, the empyrical formula (which is the simplest chemical formula with the minimum amount in whole numbers between its atoms ) is CH₂

Answer:

True

Explanation:

The wind speed to be considered a tornado is 40 to 72 mph

Answer:

40% of the hurricane that occur in the United states hit Florida . the difference between a tropical storm and a

hurricane is wind speed – tropical strom usually bring wind of 36 to 47 mph where as hurricane winds speed are at least 74 mph

Answer:

28.16 °C

Explanation:

Considering that:-

Heat gain by water = Heat lost by metal

Thus,  

[tex]m_{water}\times C_{water}\times (T_f-T_i)=-m_{metal}\times C_{metal}\times (T_f-T_i)[/tex]

Where, negative sign signifies heat loss

Or,  

[tex]m_{water}\times C_{water}\times (T_f-T_i)=m_{metal}\times C_{metal}\times (T_i-T_f)[/tex]

For water:

Mass = 165 g

Initial temperature = 28 °C

Specific heat of water = 4.184 J/g°C

For metal:

Mass = 4.00 g

Initial temperature = 75 °C

Specific heat of water = 0.600 J/g°C

So,  

[tex]165\times 4.184\times (T_f-28)=4.00\times 0.600\times (75-T_f)[/tex]

[tex]690360\left(T_f-28\right)=2400\left(75-T_f\right)[/tex]

[tex]692760T_f=19510080[/tex]

[tex]T_f = 28.16\ ^0C[/tex]

Hence, the final temperature is 28.16 °C

Answer:

1013.32 J/kg.K

Explanation:

The heat transferred by a changing in temperature without phase change can be calculated by:

Q = m*c*ΔT

Where m is the mass, c is the specific heat, and ΔT is the change in temperature (final - initial).

The values of c for water and copper can e found in thermodynamics tables:

cwater = 4.19x10³ J/kg.K

ccopper = 0.39x10³ J/kg.k

By the conservation of energy:

Qwater + Qcopper + Qmaterial = 0

0.200*4.19x10³*(26.1 - 19.0) + 0.150*0.39x10³*(26.1 - 19.0) + 0.085*c*(26.1 - 100) = 0

5949.8 + 415.35 - 6.2815c = 0

6.2815c = 6365.15

c = 1013.32 J/kg.K

The specific heat capacity of the unknown material is 1013.32 J/kg°C.

A calorimeter is used to measure the specific heat capacity of an unknown material. The calorimeter contains 0.200 kg of water and 0.150 kg of copper. A 0.085-kg sample of the unknown material is dropped into the calorimeter, and the temperature of the calorimeter increases from 19.0°C to 26.1°C. The specific heat capacities of water and copper are 4186 J/kg°C and 385 J/kg°C, respectively.

Heat transfer equation: Q = m * c * ΔT

Values of c for water and copper:

c_water = 4.19e3 J/kg°C

c_copper = 0.39e3 J/kg°C

Conservation of energy: Q_water + Q_copper + Q_material = 0

Calculations:

0.200 * 4.19e3 * (26.1 - 19.0) + 0.150 * 0.39e3 * (26.1 - 19.0) + 0.085 * c_material * (26.1 - 100) = 0

5949.8 + 415.35 - 6.2815c = 0

6.2815c = 6365.15

c_material = 1013.32 J/kg°C

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The question probable may be;

The complete question is: A laboratory technician drops a 0.0850-kg sample of unknown solid material, at 100.0∘C, into a calorimeter. The calorimeter can, initially at 19.0∘C, is made of 0.150 kg of copper and contains 0.200 kg of water. The final temperature of the calorimeter can and contents is 26.1∘C. Compute the specific heat of the sample.

Answer:

The percent by mass of nitric acid in the mixture is 11.1 %

Explanation:

Step 1: Data given

Mass of HNO3 = 8.89 grams

Volume of KOH = 27.1 mL = 0. 0271 L

Molarity of KOH = 0.581 M

Step 2: The balanced equation

HNO 3  +  KOH  →  KNO 3  +  H 2 O

Step 3: Calculate the moles of KOH

Moles of KOH = molarity KOH * volume

Moles KOH = 0.581 M * 0.0271 L

Moles KOH = 0.0157 moles

Step 4: Calculate moles of HNO3

For 1 mol of KOH we need 1 mol of HNO3

For 0.0157 moles of KOH we need 0.0157 moles of HNO3

Step 5: Calculate mass of HNO3

Mass KOH = moles KOH * molar mass KOH

Mass KOH = 0.0157 moles * 63.01 g/mol

Mass KOH = 0.989 grams

Step 6: Calculate mass % HNO3 in sample

mass % = (0.989 grams / 8.89 grams)*100%

mass % = 11.1 %

The percent by mass of nitric acid in the mixture is 11.1 %

Answer:

The coefficient of oxygen in the balanced equation is equal to 3.

Explanation:

The combustion reaction of ethanol in the "gasohol" produces carbon dioxide and water as follows:        

CH₃CH₂OH + O₂ → CO₂ + H₂O       (1)      

To find the coefficient of oxygen in equation (1), we need to balance it. The balanced reaction is the next:

CH₃CH₂OH + 3O₂ → 2CO₂ + 3H₂O      

In the balanced equation, we have the same number of carbon, hydrogen, and oxygen atoms in the products than in the reactants. Therefore, the coefficient of oxygen in the balanced equation is equal to 3.  

I hope it helps you!          

Final answer:

The coefficient of oxygen in the balanced chemical equation for the combustion of ethanol is 3.

Explanation:

The combustion of ethanol, C₂H₅OH, when it is blended with gasoline to make 'gasohol' involves a reaction with oxygen to produce carbon dioxide and water.

The balanced chemical equation for this combustion is C₂H₅OH(l) + 3O₂(g) --> 2CO₂(g) + 3H₂O(g).

Therefore, the coefficient of oxygen in the balanced equation is 3, indicating that three molecules of diatomic oxygen are required for the complete combustion of one molecule of ethanol.

Answer:

The hydrolysis rate is significantly low because the energy of the transition state for hydrolysis is significantly high

Explanation:

In the given problem,  It was stated that the peptide bond is not stable thermodynamically. Peptide bonds are typically formed between molecules with carboxyl groups and molecules with amino groups. Therefore, it can be inferred that the hydrolysis rate is significantly low because the energy of the transition state for hydrolysis is significantly high.

Answer:

The larger person will have to get a larger parachute. The answer is D

Explanation:

If the smaller person does nothing, the larger person subsequently accelerate for more time and with larger terminal velocity. In this case the person needs to do something so as to reduce the terminal velocity and can also effectively raise the air resistance. For this reason the person should get a bigger parachute. The air resistance in the opened parachute overwhelms the downward force of the gravity. Whereas the net force as well as the acceleration of the person is upward. The bigger parachute has the ability to grab the greater force. If the parachute, dragging force works in the opposite to that of the force of the gravity, hence the drag force slows the parachute decrease as they fall.

Answer:

See explanation below

Explanation:

The drawing of the molecule and mechanism, you can see it in the attached pictures.

Now, answering the theorical questions:

The 1-butene is like this:

CH2 = CH - CH2 - CH3

If this molecule reacts with bromine (Br2) the reaction and product formed is:

CH2 = CH - CH2 - CH3 + Br2 -----------> Br-CH2 - CH(Br) - CH2 - CH3

The product formed is called 1,2 - dibromo - butane, and the reaction with halides like bromine is called halogenation. In this case, alkenes halogenation, so, we become a alkene like the 1-butene with a halide like bromine to form an alkane with halides. This reaction is taking place in conditions of Sn1, although this is an addition (Two steps, see picture below for mechanism).

The bromine, has a high electronegativity (2.9) this is even bigger than the iodine (2.7), so, when the bromine acts as a nucleophile in a SN2 or SN1 reaction (like this one),  bromine atom becomes slightly more negative, and iodine atom becomes slightly more positive, so strictly speaking, the molecule is slightly polar. When the difference of the electronegativities is below of 0.4, we can say that the molecule is non-polar.

Because of the explanation above, the reaction is taking place with bromine, because it has a higher electronegativity, even more than the chlorine, so the molecule is more polar and can have a better reaction with the 1-butene than the chlorine. Has a better nucleophyle attack and also, is a great leaving group.

The picture below will show the mechanism:

Final answer:

To find the mole fraction of methanol in the solution, calculate the moles of methanol and water in the mixture. The mole fraction of methanol is 0.4.

Explanation:

To find the mole fraction of methanol in the solution, we need to calculate the moles of methanol and water in the mixture. The formula for mole fraction (X) is the moles of the component divided by the total moles in the solution.

First, we calculate the moles of methanol by dividing the mass of methanol by its molar mass:

Moles of methanol = 128 g / 32.04 g/mol = 4 mol

Next, we calculate the moles of water by dividing the mass of water by its molar mass:

Moles of water = 108 g / 18.02 g/mol = 6 mol

The total moles in the solution is the sum of the moles of methanol and water:

Total moles = 4 mol + 6 mol = 10 mol

Finally, we can calculate the mole fraction of methanol:

Mole fraction of methanol = Moles of methanol / Total moles = 4 mol / 10 mol = 0.4

The mole fraction of methanol in the solution is 0.4.

Answer:

When cation of metal and anion of non metal are combine they form salt.

Explanation:

When cation of metal and anion of non metal are combine they form salt. Consider the example of sodium chloride.

Sodium chloride is salt and also an ionic compound. The electronegativity of chlorine is 3.16 and for sodium is 0.93. There is large difference is present. That's why electron from sodium is transfer to the chlorine. Sodium becomes positive and chlorine becomes negative ion. Both atoms are bonded together electrostatic attraction occur between anion and cations and form salt sodium chloride.

Salt is formed during the neutralization reaction of acid and base.

For example:

When sodium hydroxide and hydrochloric acid react they form sodium chloride and water.

NaOH + HCl →  NaCl + H₂O

Answer:

salt is a rock

Explanation:

Answer:

type 2 diabetes

insulin

Explanation:

type 2 diabetes is a chronic condition that affects the way the body processes blood sugar. A patient with type 2 diabetes in the body either doesn't produce enough insulin, or it resists insulin.

As Chromium levels can be below normal in people with type 2  diabetes. Research studies shows that taking drugs that contains chromium such as chromium picolinate can help increase the effectiveness of insulin levels and help insulin work in people with type 2 diabetes.

Answer:

1. Dalton..........Father of Atomic theory

2. Bohr..........Postulated the quantum atom

3. nucleus..........location of the most of the mass of the atom

4. Chadwick..........discovered the neutron

5. Rutherford..........discovered the proton

6. electrons..........emitted from a cathode-ray tube

7. J.J. Thomson..........discovered the electron

Explanation:

The question is incomplete.Here is the cmplete question.

Match these items.

1. Dalton...... emitted from a cathode-ray tube

2. Bohr.......... discovered the neutron

3. nucleus.......... discovered the electron

4. Chadwick........ postulated the quantum atom

5. Rutherford........... discovered the proton

6. electrons ............father of atomic theory

7. J. J. Thomson.............location of most of the mass of the atom

1) Dalton is the father of atomic theory

He proposed that matter comprises of indivisible particles called atoms. Atoms are the building block of a matter. All atoms of an element are identical. Atoms of different elements differ from each other in terms of size and mass.

2. Bohr postulated the quantum atom

He proposed that electrons revolve around the nucleus in orbits. Each orbit is labelled by an integer 'n’. This integer is the quantum number. Electrons can move between shells by emitting or absorbing energy.

3. Nucleus is the location of most of the mass of the atom

The entire mass (almost 99%) of atom is concentrated in the nucleus containing protons and neutrons. Electrons orbiting around have negligible mass compared the protons and neutrons.  

4. Chadwick discovered the neutron.

In an experiment, Chadwick bombarded beryllium atoms with alpha rays. He noticed that beryllium emitted neutral rays as a result. Unlike gamma rays, the rays did not create photo electric effect when they hit charged electroscope. He concluded that they are neutrons instead.  

5. Rutherford discovered the proton  

In his famous gold foil experiment, he bombarded positively charged alpha rays to gold foil as saw a large proportion of them being deflected. He concluded that the atoms must have positively charged particles that caused the deflection.

6. Electrons are emitted from a cathode-ray tube  

When electricity is passed through the cathode in the tube, electrons in the outermost orbit gain enough energy to break out from it

7. J. J. Thomson discovered the elections.  

In the cathode-ray tube, Thompson observed that the rays emitted from the cathode are deflected towards to the positively charged plate. He concluded that cathode rays composed of negatively charged particles, i.e. electrons.  

Answer:

Correct matches below.

Explanation:

Dalton - Father of Atomic Theory

Chadwick - Discovered the neutron

J.J Thomson - Discovered the electron

Bohr - Postulated the quantum atom

Rutherford - Discovered the proton

Nucleus - Location of most of the mass in the atom

Electrons - Emitted from a cathode-ray tube

Answer:

Intermolecular

Explanation:

When a gas is cooled, attractive forces between molecules increases as the temperature is reduced and the average kinetic energy of the molecules decreases, intermolecular attraction becomes more significant and the gas condenses to liquid.

The change from gaseous Cl2 to liquid Cl2 when cooled is due to intermolecular forces, which are the attractions between Cl2 molecules and are weaker than the intramolecular forces that bond atoms within a molecule.

The transition of gaseous Cl2 into a liquid when cooled involves forces known as intermolecular forces, which are attractions between molecules. These are different from intramolecular forces, which are the bonds that hold atoms together within a molecule. When Cl2 is cooled, the kinetic energy of its molecules decreases, allowing the intermolecular forces to bring them closer together, resulting in a liquid state. It's important to differentiate between these two types of forces, as intermolecular forces govern changes of state, such as from gas to liquid, whereas intramolecular forces are responsible for holding the atoms within a single molecule together and require significantly more energy to break.

Answer : The boiling point of the resulting solution is, [tex]100.6^oC[/tex]

Explanation :

Formula used for Elevation in boiling point :

[tex]\Delta T_b=i\times k_b\times m[/tex]

or,

[tex]T_b-T^o_b=i\times k_b\times \frac{w_2\times 1000}{M_2\times w_1}[/tex]

where,

[tex]T_b[/tex] = boiling point of solution = ?

[tex]T^o_b[/tex] = boiling point of water = [tex]100^oC[/tex]

[tex]k_b[/tex] = boiling point constant  = [tex]0.52^oC/m[/tex]

m = molality

i = Van't Hoff factor = 1 (for non-electrolyte)

[tex]w_2[/tex] = mass of solute (sucrose) = 5.0 g

[tex]w_1[/tex] = mass of solvent (water) = 10.0 g

[tex]M_2[/tex] = molar mass of solute (sucrose) = 342.3 g/mol

Now put all the given values in the above formula, we get:

[tex](T_b-100)^oC=1\times (0.52^oC/m)\times \frac{(5.0g)\times 1000}{342.3\times (10.0g)}[/tex]

[tex]T_b=100.6^oC[/tex]

Therefore, the boiling point of the resulting solution is, [tex]100.6^oC[/tex]

Answer:

The answer to your question is below

Explanation:

There are 4 types of chemical reactions:

- Synthesis is when two elements or compounds form only one compound.

- Decomposition is when 1 compound is broken into 2 or more products.

- Single replacement is when one element is replaced by another element.

- Double replacement is when the cations of two compounds are interchanged.

1.- Decomposition                      2 Al₂O₃    ⇒    4 Al   +  3O₂

2.- Single replacement          Mg  +  2HNO₃   ⇒   Mg(NO₃)₂   +  H₂

3.- Combustion                      2C₆H₆  +  15O₂   ⇒   12CO₂   +   6H₂O

4.- Synthesis                          2Ag   +   S   ⇒   Ag₂S

5.- Double replacement      3Ca(OH)₂   + 2H₃PO₄   ⇒   Ca₃(PO₄)₂  + 6 H₂O

Answer : The number of electrons transferred are, 10

Explanation :

Rules for the balanced chemical equation in acidic solution are :

First we have to write into the two half-reactions.

Now balance the main atoms in the reaction.

Now balance the hydrogen and oxygen atoms on both the sides of the reaction.

If the oxygen atoms are not balanced on both the sides then adding water molecules at that side where the less number of oxygen are present.

If the hydrogen atoms are not balanced on both the sides then adding hydrogen ion [tex](H^+)[/tex] at that side where the less number of hydrogen are present.

Now balance the charge.

The given balanced redox reaction is,

[tex]2MnO_4^-(aq)+10Br^-{aq)+16H^+(aq)\rightarrow 2Mn^{2+}(aq)+5Br_2(aq)+8H_2O(l)[/tex]

Step 1: Separate the skeleton equation into two half-reactions.

Oxidation : [tex]Br^-\rightarrow Br_2[/tex]

Reduction : [tex]MnO_4^-\rightarrow Mn^{2+}[/tex]

Step 2: Balance all atoms other than H and O.

Oxidation : [tex]2Br^-\rightarrow Br_2[/tex]

Reduction : [tex]MnO_4^-\rightarrow Mn^{2+}[/tex]

Step 3: Balance O.

Oxidation : [tex]2Br^-\rightarrow Br_2[/tex]

Reduction : [tex]MnO_4^-\rightarrow Mn^{2+}+4H_2O[/tex]

Step 4: Balance H.

Oxidation : [tex]2Br^-\rightarrow Br_2[/tex]

Reduction : [tex]MnO_4^-+8H^+\rightarrow Mn^{2+}+4H_2O[/tex]

Step 5: Balance the charge.

Oxidation : [tex]2Br^-\rightarrow Br_2+2e^-[/tex]

Reduction : [tex]MnO_4^-+8H^++5e^-\rightarrow Mn^{2+}+4H_2O[/tex]

Step 6: Equalize electrons transferred.

Oxidation : [tex]2Br^-\rightarrow Br_2+2e^-[/tex]    × 5

Reduction : [tex]MnO_4^-+8H^++5e^-\rightarrow Mn^{2+}+4H_2O[/tex]   × 2

and,

Oxidation : [tex]10Br^-\rightarrow 5Br_2+10e^-[/tex]

Reduction : [tex]2MnO_4^-+16H^++10e^-\rightarrow 2Mn^{2+}+8H_2O[/tex]

Step 7: Add the two half-reactions.

[tex]2MnO_4^-(aq)+16H^+(aq)+10Br^-(aq)\rightarrow 2Mn^{2+}(aq)+8H_2O(l)+5Br_2(aq)[/tex]

In this reaction, there are 10 number of electrons transferred.

Hence, the number of electrons transferred are, 10

The total number of electrons transferred in the reaction is 10.

The number of electrons transferred can be given by half reactions:

Oxidation reaction: [tex]\rm Br^-\rightarrow\;Br_2[/tex]

Reduction reaction : [tex]\rm MnO_4^-\;\rightarrow\;Mn^2^+[/tex]

The transfer of electrons can be balanced with the addition of a water molecule to the reaction. If the hydrogen atoms are not balanced on both sides then add hydrogen ion at that side where the less number of hydrogen is present. The electron transfer will be:

Oxidation reaction : [tex]\rm 2\;Br^-\;\rightarrow\;Br_2\;+\;2\;e^-[/tex]

Reduction reaction : [tex]\rm MnO_4^-\;+\;H^+\;+\;5\;e^-\;\rightarrow\;Mn^2^+\;+\;2\;H_2O[/tex].

By balancing the equation and electron transfer:

[tex]\rm 2\;MnO_4^-\;+\;16\;H^+\;10\;Br^-\;\rightarrow\;2\;Mn^2^+\;8\;H_2O\;+\;5\;Br_2[/tex]

The total number of electrons transferred in the reaction is 10.

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Answer: D

Explanation:

The molecular theory of gases states that there are no intermolecular forces between gases. Gas molecules are separated from each other such that individual molecules are far apart from each other. When volume is increased, gas molecules spread out from each other and the distance between them increases thus approximating the situation in ideal gases.

Final answer:

The behavior of a sample of a real gas more closely approximates that of an ideal gas as its volume is increased because the average distance between molecules becomes greater.

Explanation:

The behavior of a sample of a real gas more closely approximates that of an ideal gas as its volume is increased at constant temperature because the average distance between molecules becomes greater. In an ideal gas, the molecules are assumed to have zero volume, while in real gases, the molecules have small but measurable volumes. As the volume of the gas increases, the intermolecular distances become larger, reducing the frequency of molecule-wall collisions. This behavior is described by Avogadro's law, which states that increasing the number of gas molecules requires a proportional increase in the container volume to yield a constant number of collisions per unit wall area per unit time.

Most nonmetals are gases at room temperature. This statement accurately describe nonmetals

Nonmetals are periodic table elements that lack the characteristic properties of metals. They can be found in the upper right-hand corner of the periodic table, to the right of the zigzag line that divides metals and nonmetals. Nonmetals are easily formed and moldable. False; nonmetals are brittle and typically break when moulded or shaped. At normal temperature, the majority of nonmetals are gases. That is correct.

Oxygen, nitrogen, and carbon dioxide are a few examples. Under pressure, nonmetals easily fracture. True, however nonmetals are often brittle in their solid state and hence cannot resist pressure without deforming. At room temperature, the majority of nonmetals are liquids. This is not correct. The majority of nonmetals do not exist in liquid form. They exist in both gaseous and solid states.

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Answer:

Alloy

Explanation:

Alloy: An alloy is a substance prepared by adding one or more element to a base or parent metal to obtain desirable products. The added element are usually metals or carbon. An alloy can be considered as a uniform mixture.

Examples of Alloy:

⇒ Brass is an alloy that contains 60 - 80% of copper and 20- 40% of zinc.

⇒Bronze is an alloy that contains 90% of copper and 10% of tin.

⇒ Steel is an alloy that contains  99.8% of iron and 0.2% of carbon.

Uses of Alloys:

⇒ They are used for making coins and medals

⇒ They are used in the construction of aircraft, ships and cars.

⇒They are used for making electromagnet.

Answer:

ΔE = -2661 KJ/mole

ΔH = -2658 KJ/mole

Explanation:

ΔH = q - PΔV

ΔE = q + w

First, to find ΔE:

The reaction PRODUCES 2658 kJ of h (q), and does 3 kJ of work (w).

2658 kJ(q) + 3 kJ(w) = 2661 kJ, BUT the reaction PRODUCES heat, which means ΔE is negative.

ΔE = -2661 KJ/mole

Second, to find ΔH:

ΔH = q - PΔV

ΔH = 2658 kJ(q) - PΔV

Now, the question states that butane burns at a constant pressure; that just translates to the pressure of the reaction is equal to 0.

ΔH = 2658 KJ(q) - (0)ΔV

ΔH = 2658 KJ - 0

ΔH = 2658 kJ, BUT, like before, the reaction PRODUCES heat, which also mean ΔH is negative.

ΔH = -2658 KJ/mole

I hope this helped! Have a nice week.

Explanation:

Metals in their solid form contain free electrons( mobile in nature), these free electrons are responsible for electricity conduction in solids metals.

Whereas in ionic compounds ions are stationary and they do not conduct electricity, however, their when dissolved in water, their ions dissociate and they start conducting electricity.

There are 1.25 moles of oxygen atoms in 20 g of O2, calculated by converting the mass to moles using the molar mass.

To determine the number of moles of oxygen atoms in 20 g of [tex]\(O_2\)[/tex], we first need to find the molar mass of [tex]\(O_2\)[/tex]. Oxygen [tex](\(O\))[/tex] has an atomic mass of approximately 16 g/mol. Since [tex]\(O_2\)[/tex] molecules contain two oxygen atoms, the molar mass of [tex]\(O_2\) is \(2 \times 16 \, \text{g/mol} = 32 \, \text{g/mol}\).[/tex]

Next, we use the formula:

[tex]\[ \text{Number of moles} = \frac{\text{Mass}}{\text{Molar mass}} \][/tex]

Substituting the given mass of [tex]\(20 \, \text{g}\)[/tex] and the molar mass of [tex]\(O_2\) (\(32 \, \text{g/mol}\)):[/tex]

[tex]\[ \text{Number of moles} = \frac{20 \, \text{g}}{32 \, \text{g/mol}} \][/tex]

[tex]\[ \text{Number of moles} = 0.625 \, \text{mol} \][/tex]

Since each molecule of [tex]\(O_2\)[/tex] contains 2 oxygen atoms, the number of moles of oxygen atoms is twice the number of moles of [tex]\(O_2\)[/tex]:

[tex]\[ \text{Number of moles of oxygen atoms} = 2 \times 0.625 \, \text{mol} = 1.25 \, \text{mol} \][/tex]

Therefore, there are [tex]\(1.25 \, \text{mol}\)[/tex] of oxygen atoms in [tex]\(20 \, \text{g}\)[/tex] of [tex]\(O_2\)[/tex].

The question probable maybe:

How many moles of oxygen atoms are there in 20 g of O2?

Answer:

K = 3.37

Explanation:

2 NH₃(g) → N₂(g)  + 3H₂(g)

Initially we have 4 mol of ammonia, and in equilibrium we have 2 moles, so we have to think, that 2 moles have been reacted (4-2).

              2 NH₃(g)    →    N₂(g)  + 3H₂(g)

Initally       4moles             -            -

React        2moles           2m   +   3m

Eq             2 moles          2m        3m

We had produced 2 moles of nitrogen and 3 mol of H₂ (ratio is 2:3)

The expression for K is:  ( [H₂]³ . [N₂] ) / [NH₃]²

We have to divide the concentration /2L, cause we need MOLARITY to calculate K (mol/L)

K = ( (2m/2L) . (3m/2L)³ ) / (2m/2L)²

K = 27/8 / 1 → 3.37

Answer:

The value of K for this reaction is 1.69

Explanation:

Step 1: Data given

Moles of NH3 = 4.0 moles

Volume of the container = 2.0 L

At the equilibrium 2.0 moles NH3 remains

Step 2: The balanced equation

2 NH3(g) → N2(g) + 3H2(g)

Step 3: Initial number of moles

NH3: 4.0 moles

N2: 0 moles

H2: 0 moles

Step 4: Number of moles at the equilibrium

NH3: 2.0 moles

This means there reacts 2.0 moles of NH3

For 2 moles of NH3 we have 1 mol of N2 and 3 moles of H2

There will be produced 1 mol of N2 and 3 moles of H2

Step 5: Calculate molarity

Molarity = moles / volume

Molarity of NH3 = 2.0 moles / 2.0 L = 1 M

Molarity of N2 = 1.0 mol / 2.0 L = 0.5 M

Molarity of H2 = 3.0 mol / 2.0 L = 1.5 M

Kc = ([H2]³[N2]) / [NH3]²

Kc = (1.5³ * 0.5) / (1²)

Kc = 1.69

The value of K for this reaction is 1.69