matt can buy an 8-ounce jar of salsa for $2.79 or a 15-ounce jar os salsa for $5.54. which jar has the best unit rate?

If the volume of a chunk of gold with a mass of 4,830 kg is 0.25 cubic meters. The gold will have a density of 19,320 kg/m.

It is defined as the mass-to-volume ratio. The density indicates the object's density and is represented by the symbol. The density is measured in kilograms per cubic meter. While volume is a three-dimensional space enclosed by an object or thing.

It is given that, a block of gold with a mass of 4,830 kilograms has a volume of 0.25 cubic meters.

We have to find the density of the gold.

Density = mass/volume

Density = 4,830 / 0.25

Density = 19,320 kg/m

Thus, if the volume of a chunk of gold with a mass of 4,830 kg is 0.25 cubic meters. The gold will have a density of 19,320 kg/m.

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Answer:

The slope is 4/11 y-intercept is -52/11

y = 4/11x + -52/11

Step-by-step explanation:

multiply distance by change in speed:

300.5 feet x -0.2 mph

300.5 * -0.2 = -60.1 change in speed

The length of each side of the pentagon is 19.2 meters.

To find the length of each side of the pentagon, we need to divide the perimeter of the pentagon by 5, since a pentagon has 5 sides. If the perimeter is 96 meters, each side would have a length of 96/5 = 19.2 meters.

Answer:

Amount of Increase:

106-100= 6

Percent Increase:

6 divided by 100 , 0,06, and 6

Step-by-step explanation:

I couldnt put a division sign so i jsut but the word and yea hope that helps

The percent increases for the given quantities are 6%, 60%, and 12% respectively. To find these, subtract the original quantity from the new quantity to find the amount of increase, then divide this by the original quantity and multiply by 100.

In order to find the percent increase, you can follow this formula:

Now, let's solve the questions :

a. Original Quantity: 100, New Quantity: 106

Amount of increase = 106 - 100 = 6

Percent increase = (6/100)*100 = 6%

b. Original Quantity: 10, New Quantity: 16

Amount of increase = 16 - 10 = 6

Percent increase = (6/10)*100 = 60%

c. Original Quantity: 50, New Quantity: 56

Amount of increase = 56 - 50 = 6

Percent increase = (6/50)*100 = 12%

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48 grams of water is added to the syrup solution.

It represents the x value of something out of 100 is called percentage.

Given

32 gram of a 25% sugar syrup.

To find

How much pure water should she add to have a 10% syrup?

Let x gram of water is added.

25% + 0% = 10%

(32)g   (x)g  (x+32)g

Now we create the equation.

[tex]\begin{aligned} (0.25*32) + (0*x) &= [(x+32)*0.1]\\8 + 0 &= 0.1x + 3.2\\8 - 3.2 &= 0.1x\\4.8 &= 0.1x\\x &= \dfrac{4.8}{0.1} \\x &= 48\\\end{aligned}[/tex]

Thus, 48 grams of water is added to the syrup solution.

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There are 3 cups of 1/4 cups in 3/4 cups.

explanation;

3/4 is equal to 3 times 1/4. 3 times

⇒ 1/4 implies 3×1/4 = 3/4.

A ratio is an ordered pair of numbers a and b, written a / b in which b does no longer identical zero. A proportion is an equation wherein ratios are set equal to each other. The share components is used to depict if two ratios or fractions are same. we can find the lacking fee by dividing the given values. the proportion formula can be given as a: b::c : d = a/b = c/d wherein a and d are the acute terms and b and c are the mean phrases.

The quantitative relation among two quantities showing the number of times one cost consists of or is contained inside the other. The indicated quotient of two mathematical expressions. b : the connection in quantity, quantity, or size among  or more matters.

A ratio can be defined as the connection or assessment among two numbers of the same unit to check how larger is one variety than the alternative one. as an instance, if the quantity of marks scored in a take a look at is 2 out of 5, then the ratio of marks received to the total range of marks is written as 2:5.

The ratio is the relationship or evaluation among two quantities of the identical unit to check how bigger is one variety than the alternative one. it is written as a/b or a: b in which b isn't always identical to zero. A share is an equality of  ratios. Proportions are used to write down equal ratios which helps to resolve the unknown quantities. The numbers in a ratio can be quantities of any type, along with counts of people or objects, or along with measurements of lengths, weights, time, and so on. In maximum contexts, both numbers are confined to be fine.

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Answer:

m<D is [tex]13^{0}[/tex]

Step-by-step explanation:

Vertically opposite angles are said to be equal angles, thus;

                   m<C = m<D

So that,

              -3x + 58 = x -2

             -3x - x = -2 -58

               - 4x = - 60

                 x = [tex]\frac{- 60}{- 4}[/tex]

                 x = 15

Thus,

  m< D = x - 2

           = 15 - 2

           = [tex]13^{0}[/tex]

Therefore, m<D is [tex]13^{0}[/tex]

1 gallon = 3.785 liters

 3.5 * 3.785 = 13.2475 total liters

1 liter = 1000 milliliters

13.2475 * 1000 = 13,247.5 milliliters

 Answer is B

Answer:

b

Step-by-step explanation:

hope this helped you!!

To solve this, you represent the the question as:

x + ( x + 1 ) + ( x + 2 ) = 84

The expression 12 + 3 + 5 + 6 is rewrite as 26. The original problem will be 26.

The analysis of mathematical representations is algebra, and the handling of those symbols is logic.

Pilar wanted to use estimation to solve a decimal addition problem.

She correctly used estimation to rewrite the problem as 12 + 3 + 5 + 6.

Then the original problem will be

⇒ 12 + 3 + 5 + 6

⇒ 26

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The number of hours Jason has worked so far is [tex]4\frac{1}{3}[/tex] hours.

Subtracting fractions include the subtraction of two or more fractions with the same or different denominators. Like fractions can be subtracted directly but for unlike fractions we need to make the denominators same first and then subtract them.

Given that, Jason spends [tex]2\frac{2}{3}[/tex] hours more at the camp, he will complete 7 hours of camp counseling.

Now, 7- [tex]2\frac{2}{3}[/tex]

= 7-8/3

= (21-8)/3

= 13/3

= [tex]4\frac{1}{3}[/tex]

Therefore, the number of hours Jason has worked so far is [tex]4\frac{1}{3}[/tex] hours.

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