math help no guesses how do u solve it plz

The first figure of the Sierpinski triangle has one shaded triangle. The second figure of the Sierpinski triangle has three shaded triangles. The third figure of the Sierpinski triangle has nine shaded triangles. Which summation represents the total number of shaded triangles in the first 15 figures?

Answer:

  D.  (x - 2)(x - 2)

Step-by-step explanation:

x² - 4x + 4 = (x -2)(x -2)

___

The expression matches the form ...

  (a +b)² + a² +2ab +b²

where a = x and b = -2

Answer:

7

Step-by-step explanation:

The formula would be c=(320/x)+3

C is the total chairs and x is the price per chair and we add 3 since she is getting 3 for free

Following PEMDAS, we should do 320/80 first which is 4

Then the equation becomes 4+3=7

Answer: 4

Step-by-step explanation:

Answer:

[tex]2^{\frac{5}{2}}[/tex]

Step-by-step explanation:

We have to solve the given expression [tex][(2)^{\frac{1}{2}}(2)^{\frac{3}{4}}]^{2}[/tex]

As we know [[tex]x^{a}.x^{b}=x^{a+b}[/tex]]

Now by solving the given expression by this identity

[tex][2^{\frac{1}{2}+\frac{3}{4}}]^{2}[/tex]

= [tex][2^{\frac{5}{4}}]^{2}[/tex]

= [tex]2^{\frac{(5)(2)}{4}}[/tex]

= [tex]2^{\frac{10}{4} }[/tex]

= [tex]2^{\frac{5}{2}}[/tex]

Therefore, the given expression can be represented by [tex]2^{\frac{5}{2}}[/tex].

Answer:

[tex]f^{-1}(x)=-\frac{1}{5} x-\frac{4}{5}[/tex]

Step-by-step explanation:

It is called an inverse or reciprocal function of [tex]f[/tex] to another function [tex]f^{-1}[/tex] that fulfills that:

If [tex]f(a)=b[/tex], then [tex]f^{-1} (b)=a[/tex]

The inverse of [tex]f(x)=-5x-4[/tex] is:

We change the x for the y

[tex]x=-5y-4[/tex]

Now, let's clear y

[tex]y=\frac{x+4}{-5}[/tex]

Ordering

[tex]y = -\frac{1}{5} x-\frac{4}{5}[/tex]

So, the inverse of the function [tex]f(x)=-5x-4[/tex] is:

[tex]f^{-1}(x)=-\frac{1}{5} x-\frac{4}{5}[/tex]

.

Answer:

D. :)

Step-by-step explanation:

The total cost of materials is $1658

How to find the total cost?

Total cost is defined as the addition of the cost of individual material.

Cost of material=Cost*Number of pieces

Cost of:

Adding them up: 20*16.69+2*20.78+2*15.58+6*21.38+118*6.60+500*0.22+10*8.44+1*150

=$1658

Therefore, The subtotal of costs of material is $1658.

To know more about cost and materials refer:https://brainly.com/question/6857588

#SPJ2

Writing an equation in function notation, with x as the independent variable is the same as solving the equation for y.

So, we start with

[tex]y-x-4=0[/tex]

and we move [tex]-x-4[/tex] to the right hand side, i.e. we add [tex]x+4[/tex] to both sides:

[tex]y-x-4+(x+4)=0+(x+4) \iff y=x+4[/tex]

Answer:

c

Step-by-step explanation:

4×F=4×6 because if one bouquet is 6 flowers, and you had 4 bouquets youd have 4 times as many flowers

Answer:

no

Step-by-step explanation:

The Quotient is 8 and you would simplify if that's an option

if its not then I will tell you what else it could be

Answer:

Step-by-step explanation:

"What is the sum of 4/5 and 1/10, and how do I show that in this illustration?"

The result of this addition is 8/10 + 1/10, or 9/10; this is "the quotient" desired.

In the graph, we could divide each rectangle vertically, so that each half of each rectangle represents 1/10.  Adding 8 and 1 of these newly-drawn rectangles results in 9 such rectangles, which corresponds to 9/10 as the sum of the two fractions.

Answer:

u=(14/3  ,-13,23/3)

Step-by-step explanation:

Given

u=3v-2/3 w+2z

And

v=(4,-3,5)

w=(2,6,-1)

z=(3,0,4)

Putting the values of v,w and z

u=3(4,-3,5)-2/3 (2,6,-1)+2(3,0,4)

u=(12,-9,15)-(4/3,12/3,-2/3)+(6,0,8)

=(12,-9,15)-(4/3,4,-2/3)+(6,0,8)

We will perform the addition first..

=(12,-9,15)-(4/3+6 ,4+0,-2/3+8)

= (12,-9,15)-(22/3,4,22/3)

Subtraction will give us:

=(12-22/3  ,-9-4 ,15-22/3)

=(14/3  ,-13,23/3)

Final Answer:

The ordered triple for vector u is then [tex]\( u = (17\frac{2}{3}, -13, 23\frac{2}{3}) \)[/tex]

Explanation:

To find the ordered triple that represents the vector u in the equation [tex]\( u = 3v - \frac{2}{3}w + 2z \)[/tex], we need to perform the vector operations on v = (4, -3, 5), w = (2, 6, -1) , and z = (3, 0, 4).
Step 1: Multiply vector v by 3.
[tex]\[ 3v = 3 * (4, -3, 5) = (3*4, 3*(-3), 3*5) = (12, -9, 15) \][/tex]
Step 2: Multiply vector w by [tex]\( -\frac{2}{3} \)[/tex].
[tex]\[ -\frac{2}{3}w = -\frac{2}{3} * (2, 6, -1) = (-\frac{2}{3}*2, -\frac{2}{3}*6, -\frac{2}{3}*(-1)) = (-\frac{4}{3}, -\frac{12}{3}, \frac{2}{3}) \\\\\[ -\frac{2}{3}w = (-\frac{4}{3}, -4, \frac{2}{3}) \\\\\[ -\frac{2}{3}w = (-1\frac{1}{3}, -4, \frac{2}{3}) \][/tex]
Step 3: Multiply vector \( z \) by 2.
[tex]\[ 2z = 2 * (3, 0, 4) = (2*3, 2*0, 2*4) = (6, 0, 8) \][/tex]
Step 4: Add the resulting vectors from steps 1, 2, and 3.
We add the corresponding components from each vector:
[tex]\[ (12, -9, 15) + (-1\frac{1}{3}, -4, \frac{2}{3}) + (6, 0, 8) \][/tex]
To add these, perform the addition component-wise:
- For the first component:
[tex]\[ 12 + (-1\frac{1}{3}) + 6 = 12 - 1\frac{1}{3} + 6 = 11\frac{2}{3} + 6 = 17\frac{2}{3} \][/tex]
- For the second component:
[tex]\[ -9 + (-4) + 0 = -9 - 4 = -13 \][/tex]
- For the third component:
[tex]\[ 15 + \frac{2}{3} + 8 = 15 + \frac{2}{3} + 8 = 23\frac{2}{3} \][/tex]
The ordered triple for vector u is then [tex]\( u = (17\frac{2}{3}, -13, 23\frac{2}{3}) \)[/tex].
However, to express this as a proper ordered triple, we usually write the components as fractions or decimals. So, let's convert the fractions into decimals:
[tex]\[ 17\frac{2}{3} = 17 + \frac{2}{3} = 17 + 0.666\ldots \approx 17.67 \\\\\[ 23\frac{2}{3} = 23 + \frac{2}{3} = 23 + 0.666\ldots \approx 23.67 \][/tex]
So the ordered triple for vector u in decimal form is approximately u = (17.67, -13, 23.67).

Please note that the approximation is to two decimal places. If exact values are desired, it is best to leave the answer in fraction form as [tex]\( u = (17\frac{2}{3}, -13, 23\frac{2}{3}) \)[/tex].

Answer:

C

Step-by-step explanation:

Using sum/difference to product identity

• sin x - sin y = 2 cos([tex]\frac{x+y}{2}[/tex]) sin ([tex]\frac{x-y}{2}[/tex])

with x = 4Θ and y = 2Θ

Then

sin(4Θ) - sin(2Θ)

= 2 cos([tex]\frac{4o+2o}{2}[/tex]) sin([tex]\frac{4o-2o}{2}[/tex])

= 2cos(3Θ)sinΘ → C

Answer:

Step-by-step explanation:

Here a score is considered to be "unusual" if higher than 2 std. dev. from the mean OR lower than 2 std. dev. from the mean.

Thus, any score lower than (120 - 2[12]), or 96, or higher than (120 + 2[12] ), or 144, is considered to be "unusual."

Answer:

  see attachment

Step-by-step explanation:

The directions tell you what you need to know. It is a matter of adding up the values shown and finding the missing number to make the total be -20. Of course, it works best to start with a row, column, or diagonal that has 4 numbers already.Then, you're only finding the 5th number.

You can start with either diagonal, column 1 or 4, and row 4 or 5. Filling the missing numbers in those spots (red) will let you find the remaining missing numbers (green, then blue).

The square at row 2, column 2 can be filled on the first round using the down-right diagonal. I have shown it as filled on the second round after row 5 column 2 is filled.

Using a spreadsheet can make this easier, because you can write formulas for the sums in each row, column, and diagonal. Then you're just making those sums be -20.

___

For example, consider the up-right diagonal. The sum of the given values, -6, 0, -4, -2, is -12. Then the spot at row 1, column 5 must be filled with -8 to make the sum be -20.

Final answer:

The expression 3 · (5 + 4)2 – 42 evaluates to 227, after applying the order of operations to add, square, multiply, and subtract the given numbers.

Explanation:

To evaluate the given exponential expression 3 · (5 + 4)2 – 42, we follow the order of operations, commonly known as PEMDAS (Parentheses, Exponents, Multiplication and Division, Addition and Subtraction).

First, we add the numbers inside the parentheses: (5 + 4), which equals 9.

Next, we raise this sum to the power of 2: 92, which is equal to 81.

Then, we calculate 42, which is 16.

Now, we multiply 3 by the result of 92: 3 · 81, giving us 243.

Lastly, we subtract 42 from this result: 243 – 16, yielding the final answer of 227.

The final result of the expression 3 · (5 + 4)2 – 42 is 227.

Answer:

• arc PS = 40°

• arc UV = 24°

Step-by-step explanation:

There are relationships between the arcs intercepted by secant lines and the angle the secant lines make with each other. In these problems, you are expected to make use of these relationships, along with others you have learned about triangles.

The relationships are basically these:

• when the secants intersect inside the circle, the angle between them is half the sum of the intercepted arcs.

• when the secants intersect outside the circle, the angle between them is half the difference of the intercepted arcs.

__

First problem:

The angle between the secants QS and PR is shown to be 50°. Intercepted arc QR is shown to be 60°. You are asked to find the other intercepted arc, PS. Based on the above, we know ...

∠POS = (1/2)(arc PS + arc QR)

50° = (1/2)(arc PS + 60°)

Multiplying by 2, we get ...

100° = arc PS + 60°

Subtracting 60°, gives ...

40° = arc PS

__

Second problem:

We need to name a couple of points so we can describe more clearly what is going on. Call the point on arc PS where line QT intersects it point R. Call the point where line QT crosses line SU point X. (Point X is the vertex of the 99° angle.)

The relations described above tell us ...

angle W = (1/2)(arc PS - arc UV)

In this equation, we only know the value of arc PS = arc PR + arc RS = 20° + 94° = 114°.

But, we know two of the angles in triangle QWX. They are angle Q = 36° and angle X = 99°. Then angle W must be ...

angle W = 180° -36° -99° = 45°

Now, we can finish the above equation involving arc UV:

45° = (1/2)(arc PS - arc UV) . . . . . put the values we know in the secant relation

90° = 114° -arc UV

arc UV = 114° -90° = 24° . . . . . . . .solve for arc UV

Answer: i think he answered ur Q and i need points so sorry

please forgive me

Step-by-step explanation:

Answer:

The number of pennies doubles each time, so the count grows exponentially.

The number of pennies on Rows 5-8 will be much greater than on Rows 1-4.

Answer:

The number of pennies doubles each time, so the count grows exponentially.

The number of pennies on Rows 5-8 will be much greater than on Rows 1-4.

Step-by-step explanation:

Answer:

The answer is the graph in the image.

Give brainliest if you please.  :)

A logarithmic graph that can be used to approximate the value of y in the equation [tex]3^y = 8[/tex] is =: B. graph B.

In Mathematics and Geometry, an exponential function can be modeled by using this mathematical equation:

[tex]y = a(b)^x[/tex]

Where:

Based on the information provided above, we can logically deduce the following equation;

[tex]3^y = 8[/tex]

By applying base 3 logarithm to boths sides of the equation, we have;

[tex]log_{3}(3^y)=log_{3}(8)\\\\ylog_{3}3=log_{3}8\\\\y=log_{3}8\\\\y\approx 1.89\\\\\\\\y=log_{3}x[/tex]

In conclusion, we can reasonably infer and logically deduce that only graph B is a logarithmic graph that can be used to approximate the value of y in the equation [tex]3^y = 8[/tex], which is approximately equal to 1.89.

Missing information:

Which logarithmic graph can be used to approximate the value of y in the equation [tex]3^y = 8[/tex]?

Answer:

13 cases

Step-by-step explanation:

we know that

You have 1 case of soap bars

There are 150 bars in a case

You use 300 bars of soap per day ----> 2 cases per day

using proportion

Find how many cases do you need to order to have enough for 7 days

Let

x ----->the number of cases

2/1=x/7

x=2*7=14 cases

but remember that you have 1 case

so

you needed 14-1=13 cases

Answer:

Greatest common factor = 1

Step-by-step explanation:

given algebraic expressions are 7w and [tex]4m^3[/tex].

Now we need to find about what is the greatest common factor that is GCF of given algebraic expressions 7w and [tex]4m^3[/tex].

7 is a prime number so that can't be factored more.

There is no common factor of 7 and 4 except 1.

there is no common factor of w and [tex]m^3[/tex].

Hence required greatest common factor of given algebraic expressions 7w and [tex]4m^3[/tex] is 1.

Answer:

A line.

Step-by-step explanation:

This is a line passing through the origin and rising to the right. The angle betwee the line and the x axis = pi/3 radians.

Answer:

C. Line.

Step-by-step explanation:

We are asked to find the name of shape that is graphed by the function [tex]\theta =\frac{\pi}{3}[/tex].

We can see that the measure of theta is constant [tex]\frac{\pi}{3}[/tex]. This means that slope of function is also constant.

We know that slope of a straight line is always constant for all values in its domain.

Therefore, the shape of our given function is a line and option C is the correct choice.

Answer:

30

Step-by-step explanation:

We need to find the greatest common factor of 120 and 144.

First, write the prime factorization of both:

120 = 2³×3×5

144 = 2⁴×3²

Both have 2³ and 3 in common, so the GCF is:

GCF = 2³×3

GCF = 24

So the side length is 24 cm.  The number of squares along the width is:

120 / 24 = 5

And the number of squares along the length:

144 / 24 = 6

So the number of squares need to fill the entire area is 5×6 = 30.  This is the least number of squares with whole-number side lengths that he can use.

Answer:

Step-by-step explanation:

the x coordinate is to the right so your choices are J A K G and C. You know this because 1 is positive and that moves to the right.

The -3 moves 3 units below the x axis. That limits your answer to KCG

We have to assume that each square is worth one, so the answer must be C.

Answer:

A. 3:7

Step-by-step explanation:

The volume of the smaller cube is 216 m³.

The volume of the larger cube is 2744 m³

Let the  similarity ratio be [tex]l:L[/tex]

The volume of these two cubes are in the ratio:

[tex]l^3:L^3=216:2744[/tex]

This implies that:

[tex](\frac{l}{L})^3 =\frac{216}{2744}[/tex]

We take the cube root of both sides to obtain:

[tex]\frac{l}{L} =\sqrt[3]{\frac{216}{2744}}[/tex]

[tex]\frac{l}{L} =\frac{6}{14}[/tex]

This simplifies to:

[tex]\frac{l}{L} =\frac{3}{7}[/tex]

Therefore the ratio is 3:7

Answer: 48.75$

Step-by-step explanation:

just took it

Answer:48.75

Step-by-step explanation:

ANSWER

EXPLANATION

We want to simplify:

[tex](2\sqrt{5}+3)(\sqrt{5}-1)[/tex]

Recall the distributive property;

(a+b)(c+d)=a(c+d)+b(c+d)

We apply this property to get,

[tex]2\sqrt{5}(\sqrt{5}-1) + 3(\sqrt{5}-1)[/tex]

We expand to get,

[tex]2 \times 5-2 \sqrt{5} + 3\sqrt{5}-3[/tex]

This simplifies to,

[tex]10 + \sqrt{5}-3[/tex]

The simplest form of the given expression is:

[tex]7 + \sqrt{5}[/tex]

Answer:

an = 10 (-8)^(n-1)

Step-by-step explanation:

In a geometric series, each term is multiplied by a common ratio to get the next term.  Such that:

an = a₁ (r)^(n-1)

Here, the first term, a₁, is 10.  The common ratio, r, is -8, because each term is multiplied by -8 to get the next term.  So:

an = 10 (-8)^(n-1)

Your answer is correct, well done!

The recursive rule of the geometric sequence is [tex]a_{n+1}= -8a_n[/tex] where a1 = 10

The geometric sequence is given as:

10, −80,  640, −5120, ...

Start by calculating the common ratio (r)

[tex]r = \frac{a_{n-1}}{a_n}[/tex]

Substitute 2 for n

[tex]r = \frac{a_{2}}{a_1}[/tex]

Substitute known values

[tex]r = \frac{-80}{10}[/tex]

Evaluate the quotient

[tex]r = -8[/tex]

Substitute -8 for r in [tex]r = \frac{a_{n+1}}{a_n}[/tex]

[tex]-8 = \frac{a_{n+1}}{a_n}[/tex]

Cross multiply

[tex]a_{n+1}= -8a_n[/tex]

Hence, the recursive rule of the geometric sequence is [tex]a_{n+1}= -8a_n[/tex] where a1 = 10

Read more about geometric sequence at:

brainly.com/question/24643676

Step-by-step explanation:

A geometric series is:

an = a₁ (r)^(n-1)

Here:

an = 2/5 (5)^(n-1)

So a₁ = 2/5, and r = 5.  So an = 5an-1.

Your answer is correct, well done!

Answer:

The direction of the given vector is 45° N of W

Step-by-step explanation:

* Lets revise the four directions with the four quadrants

- The four directions are:

# North which represented by the positive part of y-axis

# South which represented by the negative part of y-axis

# East which represented by the positive part of x-axis

# West which represented by the negative part of y-axis

∴ The first quadrant is between the East and the North

∴ The second quadrant is between the West and the North

∴ The third quadrant is between the West and the South

∴ The fourth quadrant is between the East and the South

* The direction of any vector is tan Ф, where Ф is the angle between

 the vector and the x-axis, then:

- The direction of North of East is 45° ⇒ first quadrant

- The direction of North of West is 45° ⇒ second quadrant

- The direction of South of West is 45° ⇒ third quadrant

- The direction of South of East is 45° ⇒ fourth quadrant

* Now lets solve the problem

∵ The direction of the vector is between the North and the West

  (its vertex in the second quadrant)

∴ Its direction is 45° North of West

* The direction of the given vector is 45° N of W

assuming 7/10 eom means 7 - 10 days after, your answer would be A. April 18th, 2012.

Answer:

Option A. April 18,2012.

Step-by-step explanation:

This invoice of stationary  is dated 8 April 2012, and terms written on it 7/10 EOM.

It means 7% discount of the payment within 10 days or full payment at the End of the Month (EOM)

Therefore, the last day Sharon can take advantage is 10 days after the date of invoice.

Date of invoice = April 8, 2012

after 10 days = April 18, 2012

Option A. is the correct answer.

Split up the interval [0, 2] into 4 subintervals, so that

[tex][0,2]=\left[0,\dfrac12\right]\cup\left[\dfrac12,1\right]\cup\left[1,\dfrac32\right]\cup\left[\dfrac32,2\right][/tex]

Each subinterval has width [tex]\dfrac{2-0}4=\dfrac12[/tex]. The area of the trapezoid constructed on each subinterval is [tex]\dfrac{f(x_i)+f(x_{i+1})}4[/tex], i.e. the average of the values of [tex]x^2[/tex] at both endpoints of the subinterval times 1/2 over each subinterval [tex][x_i,x_{i+1}][/tex].

So,

[tex]\displaystyle\int_0^2x^2\,\mathrm dx\approx\dfrac{0^2+\left(\frac12\right)^2}4+\dfrac{\left(\frac12\right)^2+1^2}4+\dfrac{1^2+\left(\frac32\right)^2}4+\dfrac{\left(\frac32\right)^2+2^2}4[/tex]

[tex]=\displaystyle\sum_{i=1}^4\frac{\left(\frac{i-1}2\right)^2+\left(\frac i2\right)^2}4=\frac{11}4[/tex]