Luiza is jumping on a trampoline. Ht models her distance above the ground (in m) t seconds after she starts

jumping. Here, t is entered in radians.

H(t) =-0.6 cos (2pi/2.5)t + 1.5

What is the second time when Luiza reaches a height of 1.2 m?

Round your final answer to the nearest hundredth of a second.

Answers

Answer 1

Answer:

t=2.08 seconds.

Step-by-step explanation:

Well, in this example, H(t)=-0.6cos(2pi/2.5)t+1.5 should be equal to 1.2. If calculated, -0.6cos(0.8pi)t=1.2-1.5 which is equal to -0.6cos(0.8pi)t=-0.3, then cos(0.8pi)t=0.5. The value of cosine in terms of radians when it is equal to 0.5 is pi/3. So, cos(0.8pi)t=cos(pi/3). If simplified, (0.8pi)*t=5pi/3. pi's are cancelled out and t is calculated as 2.08333... If rounded to the nearest hundredth it is 2.08.


Related Questions

a certain triangle has two 45 degree angles what type of triangle is it

Answers

Answer:

most likely isosceles

Step-by-step explanation:

due to the fact that two angles are congruent and the other angle is probably not it would make it all isosceles triangle

A triangle with two 45-degree angles is a special type of triangle known as an isosceles triangle.

In a triangle, if two angles are congruent, then the opposite sides of those angles are also congruent. In an isosceles triangle, two sides are equal in length, and the angles opposite those sides are congruent. Since two angles of the triangle are 45 degrees each, their opposite sides are also equal in length, making it an isosceles triangle.

Plz help me this isn’t that hard but I’m struggling so plz I don’t want another detention

Answers

Answer:

The length of the total 8 pieces in 0.8 meters = 6.4 meters

How many pieces there are in the remaining 0.4 meter = 6.5

Step-by-step explanation:

0.8 x 8 = 6.4

9 meters - 6.4 meters = the remaining 2.6 meters

2.6 x 0.4 = 6 1/2 pieces of ribbon in 0.4 meters.

Prove that ABCD is a square if a A(1,3) B(2,0) C(5,1) and D(4,4)

Answers

[tex]AB=BC=CD=AD = \sqrt{10}[/tex]

As all the sides have same length, ABCD is a square

Step-by-step explanation:

To prove ABCD a square we have to find the lengths of each side

So,

the distance formula will be used to find the lengths

The distance formula is:

[tex]d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Now,

[tex]AB = \sqrt{(2-1)^2+(0-3)^2}\\= \sqrt{(1)^2+(-3)^2}\\=\sqrt{1+9}\\=\sqrt{10}[/tex]

[tex]BC = \sqrt{(5-2)^2+(1-0)^2}\\= \sqrt{(3)^2+(1)^2}\\=\sqrt{9+1}\\=\sqrt{10}[/tex]

[tex]CD = \sqrt{(4-5)^2+(4-1)^2}\\= \sqrt{(-1)^2+(3)^2}\\=\sqrt{1+9}\\=\sqrt{10}[/tex]

[tex]AD = \sqrt{(4-1)^2+(4-3)^2}\\= \sqrt{(3)^2+(1)^2}\\=\sqrt{9+1}\\=\sqrt{10}[/tex]

we can see that

[tex]AB=BC=CD=AD = \sqrt{10}[/tex]

As all the sides have same length, ABCD is a square

Keywords: Distance formula, square

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Solve the following system of equations.

3x + 2y - 5 = 0
x = y + 10

Make sure there are NO SPACES in your answer. Include a comma in your answer.

ANSWER: {(
)}

Answers

Answer:

The solution is the point (5,-5)

Step-by-step explanation:

we have

[tex]3x + 2y - 5 = 0[/tex] -----> equation A

[tex]x = y + 10[/tex] -----> equation B

Solve the system by substitution

substitute equation B in equation A

[tex]3(y+10) + 2y - 5 = 0[/tex]

solve for y

[tex]3y+30 + 2y - 5 = 0[/tex]

[tex]5y=-25[/tex]

[tex]y=-5[/tex]

Find the value of x

[tex]x=5+ 10[/tex]

[tex]x=5[/tex]

therefore

The solution is the point (5,-5)

The diameter of a circle is 4 cm. Which equation can be used to find its circumference?

OC = T2

OC= Tx4

4

Answers

Answer: OC = πx4

Step-by-step explanation:

This question is incomplete, the correct question is

The diameter of a circle is 4 cm. Which equation can be used to find its circumference?

OC = πx2

OC= πx4

4

Answer,

Since the diameter is given as 4cm

Also,

The circumference of a circle OC = π x diameter

Therefore, OC = πx4

Please solve number 80

Answers

Answer:

option D. 20 cm

Step-by-step explanation:

step 1

Find the volume of the water

The volume of the water is equal to

[tex]V=LWH[/tex]

we have

[tex]L=60\ cm\\W=40\ cm\\H=50\ cm[/tex]

substitute

[tex]V=(60)(40)(50)[/tex]

[tex]V=120,000\ cm^3[/tex] ---> volume of water

step 2

Find the deep of the water, if the tank is returned to its horizontal position

we have

[tex]V=120,000\ cm^3[/tex]

[tex]L=100\ cm\\W=60\ cm\\H=?\ cm[/tex]

where

H is the deep of the water

substitute in the formula of volume

[tex]120,000=(100)(60)(H)[/tex]

solve for H

[tex]120,000=6,000)(H)[/tex]

[tex]H=20\ cm[/tex]

Two equivalent fractions of 4/7

Answers

Answer:

8/14 and 12/21

Step-by-step explanation:

Just multiply numerator and denominator by the same number, e.g., 2 and 3 to get above.

Answer:

8/14 and 12/21

Step-by-step explanation:

when a positive number is multiplied by itself, the result is equal to 3 more than twice the original amount. What is the value of that number?

Answers

Hope it helps u..........

Find the product
(-3)(8)

Answers

Answer:

-24

Step-by-step explanation:

This is a simple multiplication problem. 8 times 3 is 24, and since one of the numbers is negative, the product (answer in multiplication) will be negative.

In multiplication and division of integers (positive and negative numbers), if the numbers have the same signs, the answer is ALWAYS positive, and if the numbers have different signs, the answer is ALWAYS negative.

Answer: -24

Step-by-step explanation: To multiply (-3)(8), it is important to understand that a negative times a positive is a negative so (-3)(8) is -24.

Evaluate f(1) using substitution:
f(x) =2x^3 -3x^2-18x+8​

Answers

。☆✼★ ━━━━━━━━━━━━━━  ☾  

Substitute 1 in everywhere you see 'x'

2(1)^3 - 3(1)^2 - 18(1) + 8

Solve:

f(1) = -11

Have A Nice Day ❤    

Stay Brainly! ヅ    

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。☆✼★ ━━━━━━━━━━━━━━  ☾

Final answer:

To evaluate the function f [tex](x) = 2x^3 - 3x^2 - 18x + 8[/tex] at x=1, substitute 1 for every instance of x in the function and simplify to get f(1) = -11.

Explanation:

The question appears to be a math problem where the student is asked to evaluate a function at a specific input. Specifically, the function given is  [tex]f(x) = 2x^3 - 3x^2 - 18x + 8[/tex] and the student has been asked to evaluate this function when x is equal to 1. To find f(1), we replace every instance of x in the function with 1.

So, f(1) = [tex]2(1)^3 - 3(1)^2 - 18(1) + 8[/tex]= 2(1) - 3(1) - 18 + 8 = 2 - 3 - 18 + 8 = -11.

Thus, f(1) evaluates to -11.

A movie theater sells out 7 times per month. How many times will it sell out in the next 2 years?

Answers

1 year = 12 months.

2 years = 12 x 2 = 24 months.

Multiply the number of times it sells out per month by the number of months:

7 x 24 months = 168 times.

7 x 12 = 84. 84 x 2 = 168. 168 is the answer.

what number is 10 times as great as 7962​

Answers

To find a number that is 10 times greater than 7962, we can multiply.

7,962 * 10 = 79,620

79,620 is 10 times greater than 7,962.

Best of Luck!

Answer:

79,620

Step-by-step explanation:

7,962 (10) = 79,620

( SHOW WORK NEED IT BY TONIGHT! ) Write a system of equations to describe the situation below, solve using substitution, and fill in the blanks.

Two students in Mr. Kelley's class, Tori and Cora, have been assigned a workbook to complete at their own pace. They get together at Tori's house after school to complete as many pages as they can. Tori has already completed 16 pages and will continue working at a rate of 5 pages per hour. Cora has completed 13 pages and can work at a rate of 8 pages per hour. Eventually, the two students will be working on the same page. How long will that take? How many pages will each of them have completed?


After _ hours, Tori and Cora will have each completed _ pages in their workbooks.

Answers

Answer:

1 hour with 21 pages completed for each.

Step-by-step explanation:

First you need to list out what you know.

Tori:

Finished: 16 pgs

Rate: 5 pgs per hr

Cora:

Finished: 13 pgs

Rate: 8 pgs per hr

Now we compose Equations. In an equation we put the rate with the "X" because it is a constant rate of change. The finished amount of pages is our starting point or our y intercept we write it in this format:

y=mx+b

m being the rate of change

b being the initial amount or the starting point

For Tori the equation would be 5x+16 because 5 is our rate of change since she completes 5 pages per hour and 16 is our initial amount since she already completed them.

For Cora the equation would be 8x+13 because 8 is our rate of change since she completes 8 pages per hour and 13 is our initial amount since she already completed them.

we set these equation equal to each other:

5x+16=8x+13

eliminate the 5x on one side to leave the 16 by its self which in this case we subtract 5x to each side and get :

16=3x+13

the we subtract the 13 to leave 3x by its self and subtract 13 on both sides and get :

3=3x

lastly we divide 3 on both sides to isolate x and this would be our hours until they are both working on the same page:

1=x

this gives us 1 which means in 1 hour of working, both Cora and Tori will be working on the same page.

Substitute the 1 for each equation to get the total amount of pages completed in 1 hour:

5(1)+16

5+16

21 pages for Tori

8(1)+13

8+13

21  pages for Cora

Done

In one hour both Tori and Cora will have done 21 pages

.The sum of the digits of a two-digit number is one-fifth the value of the
number. The tens digits is one less than the ones digit. What is the two-digit
number? (Hint: Assign a different variable to the value of each digit.)

Answers

Here's how I'm assigning a different variable to the value of each digit:

10x + y, where x is the first digit, and y is the second digit (you can test if this equation works)

The sum of the digits is 1/5 the value of the number. Using the information, we can form the equation:

x + y = (1/5)(10x + y)

Simplify

x + y = 2x + (1/5)y

The tens digit is one less than the ones digit. Using this information, we can form the equation:

x = y - 1

Adding both sides by 1 gives

x + 1 = y

Substituting this into the y's the first equation gives:

x + x + 1 = 2x + (1/5)(x + 1)

Distribute and simplify

2x + 1 = 2x + (1/5)x + 1/5

Subtract both sides by 2x

1 = (1/5)x + 1/5

Subtract 1/5 from both sides

4/5 = (1/5)x

Multiply both sides by 5

4 = x

x = 4

Use this to solve for y

x + 1 = y

4 + 1 = y

y = 5

Thus, x = 4 and y = 5. The 2 digit number is XY, which is 45.

Let me know if you need any clarifications; this was a very interesting math problem to solve!

Write the quadratic equation whose roots are 3 and 4, and whose leading coefficient is 2.
(Use the letter x to represent the variable.)

Answers

Step-by-step explanation:

equation-

(x-3) (x-4) =

[tex] {x }^{2} - 3x - 4x + 12 = {x}^{2} - 7x + 12[/tex]

Final answer:

Given the roots 3 and 4 of a quadratic equation, and the leading coefficient 2, the quadratic equation can be derived as 2x^2 - 14x + 24.

Explanation:

To find a quadratic equation given its roots and leading coefficient, you use the factored form of a quadratic equation, x = (x - root1)(x - root2).  

Given that the roots are 3 and 4, the equation takes the form of x = (x - 3)(x - 4). When you multiply this out, you get x^2 - 7x + 12.

The problem also states that the leading coefficient is 2, so we multiply our obtained equation by 2 to get: 2x^2 - 14x + 24.

So, the requested quadratic equation is 2x^2 - 14x + 24.

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Select the correct answer from each drop-down menu.

A 4
7
15


B 15
4
7


C 15
7
4

Answers

Answer:   The correct answer is:   [C]:  "  [tex]15^{(7/4)}[/tex] " .

____________________________________

Step-by-step explanation:

____________________________________

Note the property for square roots in exponential form:

_____________________________________

     →    [tex]\sqrt[a]{(b)^ c}[/tex]  ;  ↔  b[tex]b^{(c/a)}[/tex] ;

    { [tex]a\neq 0[/tex] ; [tex][a^{(b/c)}]\neq 0[/tex] ; [tex]c\neq 0[/tex]  .}.

_____________________________________

As such, given:

     →    [tex]\sqrt[4]{(15^7)}[/tex] ;  

  a = 15,  b = 7,  c = 4 .

     

     →    [tex]\sqrt[4]{(15^7)}[/tex] ;   ↔  [tex]15^{(7/4)}[/tex] ;

     →  which corresponds to:

_____________________________________

Answer choice:  [C]:  "  [tex]15^{(7/4)}[/tex] " .

_____________________________________

Hope this helps!

  Wishing you well in your academic endeavors!

_____________________________________

Write the equation of the line that passes through (-1, 8) and is parallel to the line that passes through (5, -1) and (2, -5).

Answers

Answer:

[tex]\large\boxed{y=-\dfrac{3}{4}x+\dfrac{29}{4}}[/tex]

Step-by-step explanation:

[tex]\text{Let}\\\\k:y=m_1x+b_1,\ l:y=m_2x+b_2\\\\k\ ||\ l\iff m_1=m_2\\\\k\ \perp\ l\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\\\=================================[/tex]

[tex]\text{The formula of a slope:}\\\\m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]

[tex]\text{Calculate the slops:}\\\\(5,\ -1),\ (2,\ -5)\\\\m_1=\dfrac{-5-(-1)}{2-5}=\dfrac{-5+1}{-3}=\dfrac{-4}{-3}=\dfrac{4}{3}\\\\\text{Therefore}\\\\m_2=-\dfrac{1}{\frac{4}{3}}=-1\left(\dfrac{3}{4}\right)=-\dfrac{3}{4}\\\\\text{Put the value of slope and coordinates of the given point (-1, 8) }\\\text{to the equation of a line:}\\\\8=-\dfrac{3}{4}(-1)+b\\\\8=\dfrac{3}{4}+b\qquad\text{subtract}\ \dfrac{3}{4}\ \text{from both sides}\\\\7\dfrac{1}{4}=b\to b=\dfrac{29}{4}\\\\\text{Finally:}\\\\y=-\dfrac{3}{4}x+\dfrac{29}{4}[/tex]

A cat is running away from a dog. After 5 seconds it is 16 feet away from the dog and after 11 seconds
it is 28 feet away from the dog. Let x represent the time in seconds that have passed and y represent the
distance in feet that the cat is away from the dog.

Answers

Answer:

18 feet

Step-by-step explanation:

Given:

A cat is running away from a dog.

After 5 seconds it is 16 feet away from the dog

After 11 seconds  it is 28 feet away from the dog.

Let x represent the time in seconds that have passed and y represent the

distance in feet, so there are two points are formed such as (5, 16) and (11,28).

We will find the distance between dog and cat. by using distance formula of the two points.

[tex]d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} }[/tex]

Now we substitute the given value in above equation.

[tex]d=\sqrt{(11-5)^{2}+(28-11)^{2} }[/tex]

[tex]d=\sqrt{(6)^{2}+(17)^{2} }[/tex]

[tex]d=\sqrt{36+289}[/tex]

[tex]d=\sqrt{325}[/tex]

[tex]d=18.08\ feet[/tex]

18.08 ≅ 18

So [tex]d=18\ feet[/tex]

Therefore the distance between dog and cat is 18 feet.

To find the linear equation for the distance between the cat and the dog, we calculate the slope with the given points and use it with one of the points to establish the equation y = 2x + 6. A graph can be drawn with the points (5, 16) and (11, 28) to visualize the cat's path.

The linear equation describing the distance the cat is from the dog in relation to time can be determined using the two given points: (5, 16) and (11, 28), where 'x' is the time in seconds and 'y' is the distance in feet.

We first find the slope (m) of the line using the formula:

m = (y2 - y1) / (x2 - x1)

Plugging in the values we get:

m = (28 - 16) / (11 - 5) = 12 / 6 = 2

This means for each second that passes, the cat is 2 feet further away from the dog. Next, we use one of the points and the slope to write the equation in point-slope form. Using the point (5, 16) we have:

y - 16 = 2(x - 5)

Expanding and simplifying this equation gives us:

y = 2x + 6

This is the linear equation that describes the distance of the cat from the dog over time. To draw a graph, we plot the two points given and draw the line that passes through them, which will represent the cat's path. The slope of 2 indicates that for every 1 second, the distance increases by 2 feet.

What did Tarzan like to play?

Answers

Answer:

Step-by-step explanation:

evaluate 81/36 x^2 - y^2/25

Answers

Answer:

Step-by-step explanation:

Final answer:

To simplify the given expression involving fractions and variables, multiply, divide, and subtract accordingly to obtain the simplified form. Therefore, the simplified expression is   [tex](9/4)x^2 - (1/25)y^2.[/tex]

Explanation:

The given expression is:

[tex]81/36 * x^2 - y^2/25[/tex]

To simplify this expression:

Multiply 81/36 which equals 9/4.

Then, divide [tex]x^2[/tex] by 4, and subtract [tex]y^2[/tex] divided by 25.

Therefore, the simplified expression is  [tex](9/4)x^2 - (1/25)y^2.[/tex]



Tell whether the sequence is arithmetic. If it is, what is the common difference? -19,-11,-3,5,...

Answers

Every next number is incremented by 8 from the previous number hence the sequence is arithmetic and the common difference is 8.

Hope this helps.

Answer:

The given sequence is arithmetic and common difference is 8.

Step-by-step explanation:

Given that :

            - 19, - 11, - 3, 5......

Here, a = - 19 ;  a is the first term of the series.

Now, For common difference-

d = [tex]t_{2} - t_{1}[/tex] = [tex]t_{3} - t_{2}[/tex] = [tex]t_{4} - t_{3}[/tex]

Let [tex]t_{1} = - 19,  t_{2} = - 11[/tex]

 d = - 11 - (-19)

 =  -11 + 19

  = 8

Let [tex]t_{3} = - 3,  t_{2} = - 11[/tex]

d = - 3 -(-11)

  = - 3 + 11

   = 8

Let [tex]t_{4} = 5,  t_{3} = - 3[/tex]

d = 5 - (-3)

  = 8

In each condition common difference d is same therefore the given sequence is arithmetic and common difference d = 8.

A man gained rs. 3000 by selling a mobile set allowing 15 % discount on the marked price the loss would be rs. 8000. Find the marked price and cost price of a mobile set​

Answers

Answer:

Marked price is Rs. 53333.33 and the cost price is Rs. 42333.33.

Step-by-step explanation:

Let Rs. x and Rs. y are the cost price and marked price of the mobile set respectively.

Now, the man has a loss of Rs. 8000 after giving a 15% discount on the marked price.

Therefore, 15% of y is 8000 i.e. [tex]8000 = \frac{y\times 15}{100}[/tex]

⇒ y = Rs. 53333.33

Now, the man gained Rs. 3000 by selling the mobile set allowing 15% discount on the marked price.

Therefore, the mobile set has the cost price = x = Rs. [(53333.33 - 8000) - 3000] = Rs. 42333.33 (Answer)

To the nearest tenth, what is the distance between the point (10, -11) and (-1, -5)

Answers

Answer:

≈ 12.5 units

Step-by-step explanation:

Calculate the distance d using the distance formula

d = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = (10, - 11) and (x₂, y₂ ) = (- 1, - 5)

d = [tex]\sqrt{(-1-10)^2+(-5+11)^2}[/tex]

   = [tex]\sqrt{(-11)^2+6^2}[/tex]

   = [tex]\sqrt{121+36}[/tex]

   = [tex]\sqrt{157}[/tex] ≈ 12.5 ( to the nearest tenth )

   

The number of students enrolled at a college is 12,000 and grows 4% each year. Complete parts (a) through (e).
a) The initial amount a is
.

Answers

Answer:

48000

Step-by-step explanation:

12000 students

4%

1 =annually

12×4×1= 48000

Answer:12,000

Step-by-step explanation:can’t give you one cuz I’m doing this in mathxl :p

The scale map shows that 5 centimeters =2 kilometers.What number of centimeters on the map represents an actual distance of 5 kilometers?

Answers

Answer:

Therefore 12.5 centimeters on the map represents an actual distance of 5 kilometers.

Step-by-step explanation:

Given:

The scale map shows that

5 centimeters =2 kilometers.

To Find:

What number of centimeters on the map represents an actual distance of 5 kilometers?

Solution:

Let 'x' cm be on the map to represent 5 kilometer.

Given:

5 centimeters = 2 kilometers.

Therefore,

x cm = 5 kilometer

Soon Equality of proportion we get

[tex]\dfrac{5}{x}= \dfrac{2}{5}\\ \\x=\dfrac{5\times 5}{2}=\dfrac{25}{2}=12.5\ cm\\\\\therefore x = 12.5\ cm[/tex]

Therefore 12.5 centimeters on the map represents an actual distance of 5 kilometers.

how can you use functions to solve real world problems ??

Answers

Answer:ioj;i;

h

Step-by-step explanation:

fkuyhjgyhkuyh

4x-1=2x+11
what is the value of x and what are the steps?

Answers

Answer:

x=6

Step-by-step explanation:

4x-1=2x+11

4x-2x-1=11

2x-1=11

2x=11+1

2x=12

x=12/2

x=6

X = 6

You need to isolate the variable or get x on one side of the = sign and a number on the other side.

1. Do the inverse operation and add one to each side of the equation. -1+1= 0 and 11+1=12

2. Subtract 2x from both sides. 2x-2x=0 and 4x-2x=2x.

So we are left with 2x=12 or 2 times some number “x” is equal to twelve.

3. Next we divide both sides by 2
2/2=1 and 12/2=6

So x=6

-3x+7y=5x+2y−3x+7y=5x+2yminus, 3, x, plus, 7, y, equals, 5, x, plus, 2, y

Complete the missing value in the solution to the equation.

(-5,(−5,left parenthesis, minus, 5, comma

))

Answers

Answer:

The complete missing value in the solution to the equation is (-5,-8).

Step-by-step explanation:

Consider the provided equation.

[tex]-3x+7y=5x+2y[/tex]

We need to find the missing value of the coordinate; (-5__)

To find the missing value substitute x = -5 in above equation.

[tex]-3(-5)+7y=5(-5)+2y[/tex]

[tex]15+7y=-25+2y[/tex]

[tex]7y-2y=-25-15[/tex]

[tex]5y=-40[/tex]

[tex]y=-8[/tex]

Hence, the missing value is -8.

Thus, the complete missing value in the solution to the equation is (-5,-8).

Answer:

Step-by-step explanation:

-5, -8

The following proof shows an equivalent system of equations created from another system of equations. Fill in the missing reason in the proof.


Statements Reasons
2x + 2y = 14
−x + y = 5 Given
2x + 2y = 14
y = x + 5 ?

Answers

Answer:

As addition property of equality clearly states that if we add the same number to both sides of an equation, the sides remain equal.

Step-by-step explanation:

[tex]2x + 2y = 14[/tex]

[tex]-x + y = 5[/tex]    Add x in both sides (Addition Property of Equality)

[tex]2x + 2y = 14[/tex]

[tex]y = x + 5[/tex]    Multiply both sides by 2

[tex]2x + 2y = 14[/tex]

[tex]2y = 2x + 10[/tex]    Subtract 2x in both sides

[tex]+\left \{ {{2x + 2y=14} \atop {-2x + 2y=10}} \right.[/tex]       ∵adding both equation

[tex]4y = 24[/tex] divide both sides by 4

[tex]y = 6[/tex]

Put the value of y = 6 to the equation [tex]-x + y = 5[/tex]

[tex]-x + 6 = 5[/tex]  Subtract 6 from both sides

[tex]-x = -1[/tex]    Change the sign

[tex]x = 1[/tex]     

Keywords: Addition property of equality, reason, proof

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Which equation has both -3 and 3 as possible values of y?


A
y^2=6

B
y^2=8

C
y^2=9

D
y^2=64

Answers

Answer:

C. [tex]y^2=9[/tex]

Step-by-step explanation:

1. [tex]y^2 = 9[/tex]

2. [tex]y = \frac{+}{}\sqrt{9}[/tex]

3. Equation solutions:

[tex]y_{1} = 3\\y_{2} = -3[/tex]

Other Questions
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