The cost to rent a car is $30 per day. Write an expression for the cost of renting a car d days. Make a table to find how much it will cost to rent a car for 3, 5, 7, and 10 days.
[tex]c=30d[/tex]
The table can be made as follows:Number of days Cost
3 90
5 150
7 210
10 300
Step-by-step explanation:It is given that:
The cost to rent a car is $30 per day.
Now, the expression which is used to represent the cost for renting a car d days is:
[tex]c=30d[/tex]
where c is the cost of renting a car.
when d=3 we have:
c=90
( Since, 30×3=90 )
when d=5
c=150
( Since, 30×5=150 )
when d=7
c=210
( Since, 30×7=210 )
when d=10
c=300
( Since, 30×10=300 )
4.3t-2.1t-2.3=7.6
Solve equation
The equation can be solved by combining like terms, isolating the variable t, then dividing by the coefficient of the variable. The solution to the equation is t = 4.5.
Explanation:The given equation in this problem is 4.3t - 2.1t - 2.3 = 7.6. To solve the equation, first we need to combine like terms, meaning we would subtract 2.1t from 4.3t.
This leaves us with 2.2t - 2.3 = 7.6. After that, we must isolate t by adding 2.3 to both sides of the equation. This results in 2.2t = 9.9. Finally, we divide both sides by 2.2 to solve for t, which gives us t = 4.5.
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Mrs. Synder must choose two of her homeroom students to be class representatives. The class consists of 13 girls and 9 boys. Approximately what percent chance is there that the first student chosen is a boy and the second student chosen is a girl? (Round to the nearest percent)
A. 10%
B. 25%
C. 22%
D. 15%
Answer: B. 25%
Step-by-step explanation:
Given : Number of boys in the class = 13
Number of girls in the class = 9
Total students = 13+9=22
Now, the number of ways to choose first boy then a girl =[tex]13\times9=117[/tex] (1)
Number of ways to choose nay two students :-
[tex]{22}P_{2}=\dfrac{22!}{(22-2)!}\\\\=\dfrac{22\times21\times20!}{20!}=462[/tex] (2)
Now, the probability that the first student chosen is a boy and the second student chosen is a girl :-
[tex]\dfrac{117}{462}=0.253246753247\approx0.25[/tex] [Divide (1) by (2)]
In percent , [tex]0.25\times100=25\%[/tex]
Hence, approximately 25% chance that the first student chosen is a boy and the second student chosen is a girl.
I'm a bit confused on how to get x, the example doesn't make sense either.
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