Line segment AB with endpoints A(4, 16) and B(20,4) lies in the coordinate plane. The segment will be dilated with a scale factor of 3/4 and a center at the origin to create A'B'. What will be the length of A'B'?

Answers

Answer 1

Answer:

The length of A'B' is 15 units

Step-by-step explanation:

As line segment AB has end points

A(4, 16)B(20, 4)

The distance formula to calculate the distance between two points is given by:

[tex]{\displaystyle d={\sqrt {(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}}}[/tex]

[tex]{\displaystyle d={\sqrt {(20-4)^{2}+(4-16)^{2}}}}[/tex]

[tex]d=\sqrt{16^2+(-12)^2}[/tex]

[tex]d=\sqrt{256+144}[/tex]

[tex]d=\sqrt{400}[/tex]

[tex]d=20[/tex]

[tex]d=20[/tex] is also the length of the line segment AB.

As segment will be dilated with a scale factor of 3/4 and a center at the origin to create A'B'.

So,

The length of A'B' can be obtained by multiplying the length of AB by 3/4

Therefore,

The length of A'B' = 3/4 × 20 = 15

So, the length of A'B' is 15 units.

Keywords: dilation, distance formula, length, line segment

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Related Questions

There are 12 grams of sugar in 1/3 of a piece of candy. How much sugar is in 3/4
of a piece of candy?
grams

Answers

Hi! This problem be set up with a ratio or fraction. 12/.333 = x/.75
Cross multiply
9=.333x
divide by .333 on each side
giving you x=27
There are 27 grams of sugar in a 3/4 piece of candy

A collector has 120 movie posters and 100 band posters. She wants to sell 24 movie posters but still have her poster collection maintain the same ratio of 120:100. If she sells 24 movie posters, how many band posters should she sell? Explain.

Answers

Answer:

20

Step-by-step explanation:

120x=100*24

x= 100*24/120

................... i got roasted by someone I don’t know wow

Answers

Turn both into improper fractions.

6 1/3 = 19/3

4 1/9 = 37/9

Find common denominators

19/3 = 57/9

37/9

Subtract.

57/9 - 37/9 = 20/9

Turn back into a mixed number.

20/9 = 2 2/9

Best of Luck!

Answer:

2 2/9

Step-by-step explanation:

Cuz yeah

A factory runs nonstop for three 14 - hour shifts. The first shift starts at 9.00 AM. At what times does their third shift end?

Answers

Answer:

Step-by-step explanation:

3 fourteen hr shifts.....that (14 * 3) = 42 hrs....thats 1 day and 18 hrs

first shift starts at 9 AM......

one day later will make it 9 AM the next day....now we have the 18 hrs.....so from 9 AM to 9 PM is 12 hrs.....so we are at 9 PM and have 6 hrs left.....making the last shift end at 3 AM <==

3:00 pm is the  time where  does their third shift end.

What is Equation?

Two or more expressions with an Equal sign is called as Equation.

Given that A factory runs nonstop for three 14 - hour shifts.

The first shift starts at 9.00 AM.

We need to find the times does their third shift end.

First shift:

9:00Am to 11:00Pm (14 hours)

second shift:

11:00pm to 1:00 am (14 hours)

Third shift

1:00 am to 3:00 pm (14 hours)

Hence, 3:00 pm is the  times where  does their third shift end.

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Solve for y in terms of x: 3y-2x=7

Answers

Answer will be: y=7/3+2x/3

Answer:

y =  2/3x + 7 / 3

Step-by-step explanation:

Step 1: Add 2x to both sides.

−2x+3y+2x=7+2x

3y=2x+7

Step 2: Divide both sides by 3.

3y  / 3 = 2x+7 / 3

y=  2 / 3x  + 7 / 3

what is the slope of the line x=2

Answers

Answer:

infinite

Step-by-step explanation:

The slope is the amount the line moves in y direction when you go move unit in the x direction. For a vertical line that is infinite...


mr.james runs a petting zoo. he records the number of visitors each week,v, t weeks, after opening the petting zoo. according to the table what is the average rate of change over the interval [2,5]
a.57 visitors per month
b. 28 visitors per month
c. 36 visitors per month
d 19 visitors per month ​

Answers

Answer:

[tex]\large \boxed{\text{19 visitors/mo}}[/tex]

Step-by-step explanation:

The average rate of change is the change in the number of visitors divided by the change in the number of months.

1. Change in number of  visitors  

Change in visitors = 182 -125 = 57 visitors

2. Change in number of weeks

Change in time = 5 - 2 = 3 months

3. Average rate of change

[tex]\begin{array}{rcl}\text{Average rate of change} &= &\dfrac{\text{change in visitors}}{\text{change in months}}\\\\&= &\dfrac{\text{57 visitors}}{\text{3 mo}}\\\\& = & \textbf{19 visitors/mo}\\\end{array}\\\text{The average rate of change is $\large \boxed{\textbf{19 visitors/mo}}$}[/tex]

Omar has 2 3/4 cups of dough to make dumplings. If he uses 3/16 cups of dough for each dumpling, how many whole dumplings can Omar make?

Plsss help me

Answers

Answer: Omar can make 14 whole dumplings.

Step-by-step explanation: Make 2 3/4 an improper fraction. To do this, multiply 2 by the denominator, 4. From this, you get 8. Then add 8 to the numerator, which is 3, and you get 11. Keep the denominator and you'll have 11/4.

To divide fractions, you make 3/16 its reciprocal by basically flipping the fraction so that the numerator becomes the denominator and vise versa, making it 16/3. Then multiply 11/4 and 16/3. 11 x 16 is 176; 4 x 3 is 12. The result is 176/12. Simplify by dividing the numerator and denominator by 4. Your resulting answer should be 44/3. Simplify even further by simple division. Your final answer should be 14 2/3. Discard the 2/3 because Omar needs to make whole dumplings. So the answer is 14.

Final answer:

Omar can make 14 whole dumplings with 2 3/4 cups of dough when each dumpling requires 3/16 cups of dough.

Explanation:

The student's question asks how many whole dumplings Omar can make with 2 3/4 cups of dough if each dumpling uses 3/16 cups of dough.

Convert 2 3/4 cups to an improper fraction: 11/4 cups.

Divide the total cups of dough (11/4) by the amount needed for one dumpling (3/16) to find the number of dumplings Omar can make.

Perform the division: (11/4) \/ (3/16) = 11/4 \\* 16/3 = 44/3.

Omar can make 44/3 dumplings, which is 14 whole dumplings with some dough left over.

Omar can make 14 whole dumplings with 2 3/4 cups of dough when each dumpling uses 3/16 cups of dough.

the sum of 3x and 14 equals the difference of 20 and 2x

Answers

Answer. 17<18

The sum of 3x + 14 equals 17x.

The difference between 20 - 2x equals 18x.

Therefore the equation is not equal to each other.

Which is the MOST REASONABLE approach for the company to take to lessen the number of latecomers to work?
A) Relocate the company to an area with less traffic.
B) Deduct the lost time for any reason from vacation time.
C) Delay the start time of work days when there is bad weather.
D) Implement better procedures at the security gate.

Answers

Answer:

D. implement better procedures at the security gate.

Step-by-step explanation:

did the usa test prep

I dont kno if how much is Multiple add or subtract please help.

Answers

Answer:

You have to subtract 1.01 from 4.12 because it says how much it rained on Tuesday.

Step-by-step explanation:

The equation says that it rained 4.12 inches on Monday and 1.01 less on Tuesday.

So to write in number form = 4.12 - 1.01 = 3.11

So your answer is 3.11 inches.

It rained 3.11 inches on Tuesday.

Hope this helps!

Find the solution(s) for x in the equation below. x^2 + 10x + 21= 0

Answers

The solutions for ‘x’ in the given equation are – 3  and  - 7

Step-by-step explanation:

Given equation:

                   [tex]x^{2} + 10 x + 21 = 0[/tex]

To find the ‘x’ value, try to factor, because in this case it works, it's fast. By using factor method, we get

                    (x + 3) (x + 7) = 0  (adding both value we get 10 and multiply as 21 as in equation and check with signs also while factoring)

                     x = - 3, -7

Verify above values by multiply both terms,

                     (x + 3) (x + 7) = 0

                [tex]x^{2} + 7 x + 3 x + 21 = 0[/tex]

                [tex]x^{2} + 10 x + 21 = 0[/tex] (so values obtained from factor method are correct)

Or, can use quadratic formula, for [tex]a x^{2} + b x + c=0[/tex], the solutions are given by:

                      [tex]x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}[/tex]

In the given equation, a = 1, b = 10, c = 21, apply these in above formula

                     [tex]x=\frac{-10 \pm \sqrt{10^{2}-(4 \times 1 \times 21)}}{2(1)}=\frac{-10 \pm \sqrt{100-84}}{2}[/tex]

                     [tex]x=\frac{-10 \pm \sqrt{16}}{2}=\frac{-10 \pm 4}{2}[/tex]

So,

When  [tex]x=\frac{-10+4}{2}=\frac{-6}{2}=-3[/tex]

When [tex]x=\frac{-10-4}{2}=\frac{-14}{2}=-7[/tex]

Hence, the values for ‘x’ are - 3 and - 7

Answer:I got it right on quiz

Step-by-step explanation:

8 over 15 minus 1 over 5

Answers

Answer:

1/3

Step-by-step explanation:

(8/15)   -   (1/5)

change 1/5 to 3/15 (which is equivalent to 1/5)

(8/15) - (3/15) = (5/15)

Simplify

(5/15) = (1/3)

Answer:

1/3

Step-by-step explanation:

8/15-1/5=8/15-3/15=5/15=1/3

ASAP!!!!!!10 POINTS I NEED HELP!!!!!!!! A beekeeper pours honey into jars. Each large jar holds 18 ounces of honey. Each small jar holds 12 ounces of honey. The beekeeper fills 32 large jars and 46 small jars.

Which answer is the most reasonable estimate of the total amount of honey in the jars?

Answers

Answer:

1,100

Step-by-step explanation:

The total number of ounces that were put in  jars was 1,128 Oz  so your answer would be 1,110 rounded to the nearest hundred.

The answer is;

20 x 30 + 10 x 50 = 1,100


2. Sue is buying a 13-pound mixture of gummy candy, jelly beans, and hard candy. The cost of gummy candy is $1.20 per pound, jelly beans cost $2.00 per pound, and hard candy costs $2.60 per pound. The mixture calls for three times as many gummy candy pieces as jelly beans. The total cost of the mixture is $21.80. How much of each ingredient did the store use?

Answers

Answer:

Store used 7.5 pounds of gummy candy, 2.5 pounds of jelly beans, and 3 pounds of hard candy.

Step-by-step explanation:

Let the amount of gummy candy be 'x'.

Let the amount of jelly beans be 'y'.

Let the amount of hard candy 'z'.

Now Given:

Sue is buying 13 pound of mixture.

So we can say that;

[tex]x+y+z =13[/tex]

But Given:

The mixture calls for three times as many gummy candy pieces as jelly beans.

[tex]x=3y[/tex]

Substituting the value of x in above equation we get;

[tex]3y+y+z=13\\\\4y +z =13 \ \ \ \ \ equation \ 1[/tex]

Also Given:

cost of gummy candy = $1.20

cost of jelly beans = $2.00

cost of hard candy = $2.60

Total Cost of mixture  = $21.80

Now Total Cost of mixture is equal to cost of gummy candy multiplied amount of gummy candy plus cost of jelly bean multiplied amount of jelly bean plus cost of hard candy multiplied amount of hard candy.

framing in equation form we get;

[tex]1.2x+2y+2.6z=21.80[/tex]

But  [tex]x=3y[/tex]

So [tex]1.2(3y)+2y+2.6z=21.80\\\\3.6y+2y+2.6z=21.80\\\\5.6y+2.6z=21.80[/tex]

Now Multiplying by both side by 10 we get;

[tex]10(5.6y+2.6z)=21.80\times 10\\\\10\times5.6y + 10\times2.6z =218\\\\56y+26z=218 \ \ \ \ \ equation \ 2[/tex]

Now Multiplying equation 1 by 14 we get;

[tex]14(4y +z) =13\times14\\\\14\times4y +14z =182\\\\56y+14z=182[/tex]

Now Subtracting equation 3 from equation 2 we get;

[tex](56y+26z) - (56y+14z) =218-182\\\\56y +26z-56y-14z=36\\\\12z=36\\\\z=\frac{36}{12} = 3 \ pounds[/tex]

Now Substituting value of z in equation 1 we get;

[tex]4y+z=13\\\\4y+3=13\\\\4y=13-3\\\\4y = 10\\\\y=\frac{10}{4} = 2.5 \ pounds[/tex]

Now also;

[tex]x= 3y\\\\x =3\times2.5 =7.5 \ pounds[/tex]

Hence Store used 7.5 pounds of gummy candy, 2.5 pounds of jelly beans, and 3 pounds of hard candy.

an airport shuttle company owns cars that have a maximum capacity of 3 passengers and vans that have a maximum capacity of 8 passengers . their 12 vehicles have a combination maximum capacity of 61 passengers. write and solve a system of equations to determine how many vans the company owns

Answers

Answer:

The Total number of car is 7 and The Total number of van is 5 .

Step-by-step explanation:

Given as :

The maximum capacity of car = 3 passengers

The maximum capacity of van = 8 passengers

Total number of vehicles = c + v = 12 vehicles

The maximum capacity of vehicles combination = 61 passengers

Let The Total number of car = c

Let The Total number of van = v

Now, According to question

c + v = 12            .........A

3 c + 8 v = 61            ............B

Now, Solving eq A and B

I.e (3 c + 8 v) - 3 × (c + v) = 61 - (3 × 12)

Or, (3 c - 3 c) + (8 v - 3 v) = 61 - 36

Or, 0 + 5 v = 25

∴ v = [tex]\dfrac{25}{5}[/tex]

i.e v = 5

So,The Total number of van = v = 5

Now Put the value of v into eq A

∵ c + v = 12    

So, c + 5 = 12

∴ c = 12 - 5

i.e c = 7

So,The Total number of car = c = 7

Hence,The Total number of car is 7 and The Total number of van is 5 . Answer

Final answer:

The student's question is about determining the number of vans owned by a company using a system of linear equations. By setting up two equations and using the elimination method, we find that the company owns 5 vans and 7 cars.

Explanation:

The question involves solving a system of linear equations to determine how many vans a company owns. We know that the company has a total of 12 vehicles, which are either cars with a capacity of 3 passengers or vans with a capacity of 8 passengers. The total capacity of all 12 vehicles combined is 61 passengers. To solve this problem, we will create two equations based on this information:

Let c represent the number of cars and v represent the number of vans.The first equation is based on the number of vehicles: c + v = 12.The second equation represents the total capacity: 3c + 8v = 61.We can solve this system using substitution or elimination methods.

Using elimination to solve the equations:

Multiply the first equation by -3 to align the passenger capacity of the cars: -3c - 3v = -36.Add this result to the second equation: (-3c - 3v) + (3c + 8v) = -36 + 61.Simplify the equation: 5v = 25.Divide both sides by 5 to find v: v = 5.Substitute v back into the first equation: c + 5 = 12.Solve for c: c = 7.

Therefore, the company owns 7 cars and 5 vans.

anyone good in LAW OF SINES??​

Answers

Answer:

Step-by-step explanation:

Answer:

b = 6.7cm

Step-by-step explanation:

The law of sines is:

[tex]\frac{a}{sinA} =\frac{b}{sinB} =\frac{c}{sinC}[/tex] OR [tex]\frac{sinA}{a} =\frac{sinB}{b} =\frac{sinC}{c}[/tex]

Each section represents an angle (capital) and its opposite side (lowercase). When you use it, only use two sections at a time. You may have one missing piece of information when using it. Use the formula that puts the missing information in the numerator (top).

This problem:

We are given one set of information, 8cm and 55°. This can be "a" and "A" (not labelled).

We need angle B to find side b.

Since we are given two of the three angles in the triangle, and the sum of all interior angles of any triangle is 180°, we can find the missing angle.

∠B = 180° - (∠A + ∠C)

∠B = 180° - (55° + 82°)

∠B = 43°

Use the law of sines with sections "A" and "B", with the lowercase letters in the top.

[tex]\frac{a}{sinA} =\frac{b}{sinB}[/tex]  Substitute known measurements

[tex]\frac{8cm}{sin(55)} =\frac{b}{sin(43)}[/tex]  Rearrange to isolate "b"

[tex]b = \frac{8cm}{sin(55)}X{sin(43)}[/tex]  Solve, degree mode on calculator

[tex]b = 6.660...cm[/tex] Exact answer

[tex]b = 6.7cm[/tex] Rounded to nearest tenth

Therefore side b is 6.7cm.

Which value is equivalent to 7 multiplied by 3 multiplied by 2 whole over 7 multiplied by 5, the whole raised to the power of 2 multiplied by 7 to the power of 0 over 5 to the power of negative 3, whole to the power of 3 multiplied by 5 to the power of negative 9? (1 point)


6 over 25

36 over 25

12 over 5

252 over 5

Answers

Answer:

Option b) 36 over 25 is correct

That is given expression is equivalent to [tex]\frac{36}{25}[/tex]

Step-by-step explanation:

Given expression can be written as below:

[tex](\frac{7\times 3\times 2}{7\times 5})^2\times \frac{7^0}{5^{-3}}\times 5^{-9}[/tex]

To find the value of given expression:

[tex](\frac{7\times 3\times 2}{7\times 5})^2\times \frac{7^0}{5^{-3}}\times 5^{-9}=(\frac{6}{5})^2\times (\frac{1}{5^{-3}})^3\times \frac{1}{5^9}[/tex]

[tex]=(\frac{6}{5})^2\times (5^3)^3\times \frac{1}{5^9}[/tex]

[tex]=\frac{36}{25}\times 5^9\times \frac{1}{5^9}[/tex]

[tex]=\frac{36}{25}[/tex]

Therefore [tex](\frac{7\times 3\times 2}{7\times 5})^2\times \frac{7^0}{5^{-3}}\times 5^{-9}=\frac{36}{25}[/tex]

Option b) 36 over 25 is correct

That is given expression is equivalent to [tex]\frac{36}{25}[/tex]

Answer:

36/25 is the answer

I kinda need help with this i’ve already done all the other questions but this one and i really want these 600 points :( <3

Answers

I think that the answer is A, because in the range, none of the numbers should be the same, and the numbers are all different in choice A

Circle A and circle B are congruent. CD is a cord of both circles. if AB = 24 inches in the radius is 13 inches how long is CD A.10in B.26in C.12in D.9in

Answers

Option A

Length of CD is 10 inches

Solution:

The diagram is attached below

Given that, Circle A and circle B are congruent

CD is a cord of both circles

AB = 24 inches

Radius = 13 inches

To find: length of CD

Draw a straight line connecting A and C

AC represents the radius of circle. Also given that radius is 13 inches, So AC = 13 inches

Given in question that AB = 24 inches

Therefore from figure, AO = AB/2 = 24/2 = 12

AO = 12

Let "b" be the length of CO

Therefore, CD = CO + OD = b + b

AOC forms a triangle, so we can use pythogoras theorem

Pythagorean theorem, states that the square of the length of the hypotenuse is equal to the sum of squares of the lengths of other two sides of the right-angled triangle.

By above definition for triangle AOC

[tex]AC^2 = AO^2 + OC^2[/tex]

Substituting AC = 13 and AO = 12 and OC = b

[tex]13^2 = 12^2 + b^2\\\\b^2 = 169 - 144\\\\b^2 = 25\\\\b = 5[/tex]

Thus length of CD is:

CD = b + b = 5 + 5 = 10

Thus length of CD is 10 inches

9.014 which digit is in the hundredths place

Answers

Final answer:

The digit in the hundredths place of the number 9.014 is 1. Significant figures and rounding concepts determine that if the digit in the thousandths place is 5 or greater, the hundredths place digit is rounded up.

Explanation:

The digit in the hundredths place of the number 9.014 is 1. When dealing with decimal numbers, the first place to the right of the decimal point is the tenths place, the second place is the hundredths place, and so on. In the context of significant figures and rounding, if we need to round a number to the hundredths position, and the digit in the thousandths place (the third position to the right of the decimal) is 5 or greater, we round the hundredths digit up.

For example, if the calculator answer is 921.996 and we need to round to the hundredths place, we look at the thousandths place digit. Since it is greater than 5, we round up, changing the answer to 922.00.

Which of the following values would complete the ordered pair if the point is on the graph of ƒ(x) = -2x - 1? (-2, ___)

A. 3

B. 4

C. 5

Answers

Option A: 3 is the right answer

Step-by-step explanation:

Given

[tex]f(x) = -2x-1[/tex]

In an ordered pair, the x-coordinate is the input to the function and y-coordinate is the output of the function on specified input.

In the given ordered pair,

x-coordinate is -2 so we will put it into the function to get the y-coordinate

So,

[tex]f(-2) = -2(-2)-1\\= 4-1\\=3[/tex]

3 will complete the ordered pair of the point on the graph

Hence,

Option A: 3 is the right answer

Keywords: functions, variables

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Answer:

A

Step-by-step explanation:

(x coodinate, y coodinate) = (x, f(x))

(-2, ___) is saying us x=-2, and question is asking y =?

f(x) = -2x -1

f(-2) = -2.-2 -1

f(-2)= 4 -1

f(-2) = 3

so, y= f(-2) = 2

(x, f(x)) = (-2, f(-2)) = (-2,3)

Hope this helps ^-^

Mike is making a scale model of his favorite car. The actual car is 8 feet long and four feet wide. Mike wants his model to be 12 inches in length. Which of the following proportions could be used to find the width, w, of his model?

A:8/4=12/w B:8/4=w/12 C: 8/12=w/4 D:12/8=4/w

Answers

Answer:

A. 8/4=12/w

Step-by-step explanation:

8/4=12/x

8feet long           12 inches

----------------   =    ----------------

4feet wide            X because we dont know exact width

Answer:

A. 8/4=12/w

Step-by-step explanation:

12. The results of an election
for mayor are shown
at the right. Which candidate
received the
most votes and which received
the least votes?
DATA
Candidate
Leonard Hansen
Margaret O'Connor
Jillian Garcia
Number of Votes
12,409
12,926
12,904

Answers

Answer:

Margaret O'Connor has the highest votes.. 12,926.

Leonard Hansen has the least votes.. 12,409

Final answer:

Margaret O'Connor received the most votes with 12,926, while Leonard Hansen received the least with 12,409. Margaret would win in a plurality election, but a runoff would be needed in a majority election as no candidate won over 50% of the votes.

Explanation:

In the results of an election for mayor, which candidate received the most votes and which received the least?

Margaret O'Connor received the most votes with a total of 12,926. Leonard Hansen received the least number of votes, totaling 12,409. If this were a plurality election, Margaret O'Connor would be declared the winner since she has more votes than any other candidate. In a majority election, a runoff would likely be necessary because no single candidate received more than 50% of the votes.




The quadrilateral shown is a rhombus. What is m∠4?

Answers

Answer:

m∠4= 360-(m∠A+m∠1+m∠3+m∠C+m∠2)

Step-by-step explanation:

In the diagram. check attach image

m∠A + m∠B + m∠C + m∠D = 360º.

Every quadrilateral can be decomposed (cut apart) into two triangles, each of whose angles' measures sum to 180º.

m∠A + m∠1 + m∠ 3 = 180º

m∠C + m∠2 + m∠4 = 180º

m∠A+m∠1+m∠3+m∠C+m∠2+m∠4 = 360º

therefore :

m∠4= 360-(m∠A+m∠1+m∠3+m∠C+m∠2)

Which angle is an acute angle?
(Full question above)

Answers

Answer:

∠CPB is an acute angle.

Step-by-step explanation:

Firstly, lets go over what an acute angle is. An acute angle is any angle that is less than 90°.

In the problem, we are told that ∠APE is a right angle. This means that it is 90°.

As ∠APE and ∠BPD are vertical angles, they must have the same measure. This means that ∠BPD is also 90°

As ∠BPD has the line PC in the middle of it, this angle could be split into ∠CPB and ∠CPD. These two angles must add up to be the same as ∠BPD, which is 90°. As these two angles must add to be 90° they must be less than 90°. This means that both ∠CPB and ∠CPD are acute angles.

As ∠CPD is not one of the options for the question, ∠CPB is the only correct answer.

Acute angles measure less than 90°. Among the options, only C) Angle CPB fulfills this condition. It's the only angle clearly smaller than a right angle in the image.

An acute angle is an angle that measures less than 90 degrees. In the image you sent, only one of the angles measures less than 90 degrees.

-angle APE is a right angle, which measures exactly 90 degrees.

-angle CPE and angle APC are both obtuse angles, which measure more than 90 degrees but less than 180 degrees.

-angle CPB is the only angle that measures less than 90 degrees, so it is the only acute angle.

Therefore, the answer is C) Angle CPB.

Benson played 12 games of trivia. He had
a perfect score on every game and received
35 bonus points per game. He earned a
total of 1,260 points. How many points did
he earn per game not including the
bonus points?

Answers

Benson earned 70 points per game not including the bonus points.

Step-by-step explanation:

Given,

Games of trivia played = 12

Bonus points received per game = 35 points

Bonus points for 12 games = 35*12 = 420 points

Total points earned = 1260 points

Points earned in games = Total points - bonus points

Points earned in games = 1260 - 420 = 840 points

As he scored 840 points in 12 games, therefore,

12 games = 840 points

1 game = [tex]\frac{840}{12} = 70\ points[/tex]

Benson earned 70 points per game not including the bonus points.

Keywords: subtraction, division

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To be labeled as a jumbo egg, the egg is supposed to weight 2.5 oz. However, when Desmond buys a carton of jumbo eggs, the weight of one is 2.4 oz. What is the percent error?

(Explain in a detailed way on how you got your answer)

Answers

The percent error is 4.17 %

Solution:

To be labeled as a jumbo egg, the egg is supposed to weight 2.5 oz

When Desmond buys a carton of jumbo eggs, the weight of one is 2.4 oz

To find: percent error

Percent error is the difference between a measured and known value, divided by the known value, multiplied by 100%

[tex]\% \text { error }=\frac{\text {approximate value}-\text {exact value}}{\text {exact value}} \times 100[/tex]

Here approximate value = 2.5 oz and exact value = 2.4 oz

[tex]\% \text { error }=\frac{2.5-2.4}{2.4} \times 100\\\\\% \text { error }= \frac{0.1}{2.4} \times 100 = 4.17[/tex]

Therefore percent error is 4.17 %

Let gx) = 2x and h(x)= x2 + 4
Evaluate (hog)(-3)
40
26
16
32

Answers

Answer:

40

Step-by-step explanation:

Evaluate g(- 3) then use the value obtained to evaluate h(x)

g(- 3) = 2(- 3) = - 6, then

h(- 6) = (- 6)² + 4 = 36 + 4 = 40

If the range of f (x) = StartRoot m x EndRoot and the range of g (x) = m StartRoot x EndRoot are the same, which statement is true about the value of m? m can only equal 1. m can be any positive real number. m can be any negative real number. m can be any real number.

Answers

Answer:

b. m can be any positive real number.

Step-by-step explanation:

The value of m can be any positive real number. The correct answer is option b) m can be any positive real number.

Step 1

To determine the value of m that makes the ranges of [tex]\( f(x) = m^x \)[/tex] and [tex]\( g(x) = x^m \)[/tex] the same, we need to analyze the ranges of both functions.

Analyzing [tex]\( f(x) = m^x \)[/tex] :

- If [tex]\( m > 0 \)[/tex], [tex]\( m^x \)[/tex] is an exponential function.

 - For [tex]\( m > 1 \)[/tex], [tex]\( f(x) = m^x \)[/tex] increases and its range is [tex]\( (0, \infty) \)[/tex].

 - For [tex]\( 0 < m < 1 \)[/tex], [tex]\( f(x) = m^x \)[/tex] decreases and its range is also [tex]\( (0, \infty) \)[/tex].

Step 2

Analyzing [tex]\( g(x) = x^m \)[/tex] :

- The range of [tex]\( x^m \)[/tex] depends on whether m is positive or negative:

 - For positive m :

   - When [tex]\( m = 1 \)[/tex], [tex]\( g(x) = x \)[/tex], the range is all real numbers, [tex]\( \mathbb{R} \)[/tex].

   - When [tex]\( m > 1 \)[/tex] or [tex]\( 0 < m < 1 \)[/tex], the function is defined for [tex]\( x > 0 \)[/tex] and its range is [tex]\( (0, \infty) \)[/tex] .

 - For negative m :

   - The function [tex]\( x^m \)[/tex] is undefined for [tex]\( x = 0 \)[/tex] and for negative x, and thus its range is [tex]\( (0, \infty) \)[/tex].

Both [tex]\( f(x) = m^x \)[/tex] and [tex]\( g(x) = x^m \)[/tex] have the range [tex]\( (0, \infty) \)[/tex] for any positive [tex]\( m \)[/tex], but for any negative m, [tex]\( g(x) \)[/tex] is undefined at zero and for negative x.

The value of m can be any positive real number (option b).

Complete question : If the range of f(x) = ^mx and the range of g(x) = m ^ x are the same, which statement is true about the value of m?

a) m can only equal 1.

b) m can be any positive real number.

c) m can be any negative real number.

d) m can be any real number.

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