Lin was waiting to check out at a store. She estimated her total bill to be $20. The actual total was $24.16. What is the difference between Lin’s estimate and the actual total?

The temperature at noon was 2.4 degrees Fahrenheit.

Arithmetic operations can also be specified by subtracting, dividing, and multiplying built-in functions.

To determine the temperature at noon, we need to first calculate the temperature decrease between midnight and 7:00 a.m. and then add the temperature increase from 7:00 a.m. to noon.

The temperature decreased at a rate of 1.1 degrees Fahrenheit per hour, and it took 7 hours from midnight to 7:00 a.m., so the temperature decreased by a total of 7 hours x 1.1 degrees per hour = 7.7 degrees.

The temperature at 7:00 a.m. would therefore be 5.2 degrees - 7.7 degrees = -2.5 degrees Fahrenheit.

At noon, the temperature increased by a total of 4.9 degrees, so the temperature at noon would be -2.5 degrees + 4.9 degrees = 2.4 degrees Fahrenheit.

Thus, the temperature at noon was 2.4 degrees Fahrenheit.

Learn more about Addition operations here:

brainly.com/question/25834626

#SPJ2

1 mile = 5280 feet

5280 * 3/5 = 3168 feet more to go

Answer:

-5p-3

Step-by-step explanation:

use the distributive property

The value of the integral is:  πcos(16)- πcos (81)

The polar coordinate system is a two-dimensional coordinate system in which each point on a plane is determined by a  from a reference point and an angle from a reference direction.

Given:

∫∫ r sin(x²+y²)dA and 16≤x²+y²≤81.

Now,

x =rcosϕ

y=rsinϕ

I=r

Find the integration limits:

ϕ∈[0,2π]

16≤x²+y²≤81

16≤r² cos² Ф + r²sin² Ф≤81

16≤r²≤81

4≤r≤9

So, r∈[4,9]

Now,

∫∫ r sin(x²+y²)dA=

= [tex]\int\limits^9_4 {dr} \int\limits^{2\pi}_0 {rsin \;(r^{2}) } \, d\phi[/tex]

=2π [tex]\int\limits^9_4 {rsin \;(r^{2}) } \, dr[/tex]

Let r² = u

2rdr=du

Also, limit will change from 16 to 25.  

5→25

4→16

​

So,

= π[tex]\int\limits^{81}_{16} {sin \;(u) } \, du[/tex]

=−π|cos (u)∣[tex]^{81}_{16}[/tex]

= πcos(16)- πcos (81)

Learn more about integral here:

https://brainly.com/question/17191581

#SPJ2

​

The  quotient of −4 1/2 ÷ (−2 2/3) would be equal to  1 1/16 as a mixed number, in simplified form.

Quotients are the number that is obtained by dividing one number by another number. We can use the fact that division can be taken as multiplication but with the denominator's multiplicative inverse.

Thus,

[tex]\dfrac{a}{\frac{b}{c}} = a \times \dfrac{1}{\frac{b}{c} } = a \times \dfrac{c}{b} = \dfrac{a \times c}{b}[/tex]

We have been given that [tex]-4 \dfrac{1}{2}[/tex]  ÷ (-[tex]2 \dfrac{2}{3}[/tex])

But first convert the mixed fraction into simple fraction

[tex]-4 \dfrac{1}{2}[/tex]  = -9/2

(-[tex]2 \dfrac{2}{3}[/tex]) = -8/3

Thus, we have to divide the terms;

[tex]-4 \dfrac{1}{2}[/tex]  ÷ (-[tex]2 \dfrac{2}{3}[/tex])

-9/2 ÷  -8/3

-9/2 x -3/8

27/ 16

In a mixed fraction; [tex]1\dfrac{1}{16}[/tex]

Hence, the quotient of −4 1/2 ÷ (−2 2/3) would be equal to  1 1/16 as a mixed number, in simplified form.

Learn more about the quotient;

https://brainly.com/question/26913992

#SPJ2

Answer: 265 calories

Step-by-step explanation:

The discretionary calorie allowance is the balance of a person can take after achieving the number of calories need to get essential nutrients.

Given : Every day Energy allowance for Ray =  2,000 calories

Energy level required to get essential nutrients =1,735 calories

Then Ray's discretionary calorie allowance =

Energy allowance - Calories required to get essential nutrients

=2000-1735=265 calories

Hence, Ray's discretionary calorie allowance will be 265 calories.

If the graph has 1/3 length…

At least 20 minutes late: this would mean 20 minutes late or more.

20 or more minutes goes from 20 to 30. So that is a difference of 30 – 20 = 10. The distance of your rectangle is 10.

Length * width = (1/30) * 10 = 1/3 or 0.3333. The probability the friend is at least 20 minutes late is 0.3333.

Answer:

Step-by-step explanation:

Given is a scatter plot and the regression line using least squares.

We are required to find out how many more goals a player will score for every additional hour of practice.

In other words, we are to find the slope of the regression line.

By taking two points on the line we can find slope of the line.

(1.5,2) and (6.5,6) are points on the line

Find slope using two point formula

Slope = [tex]\frac{y2-y1}{x2-x1} =\frac{6-2}{6.5-1.5} \\=\frac{4}{5}[/tex]

near slope is 3/4

Hence answer is option b.

On average, the goals a player scores for every additional hour of practice will be 3/4.

The slope is the ratio of the vertical changes to the horizontal changes between two points of the line.

We need to find out how many more goals a player will score for every additional hour of practice.

In other words, we have to find the slope of the regression line.

By taking two points on the line we can find the slope of the line.

Lets (1.5,2) and (6.5,6) are points on the line

So, the slope will be

Slope = y-y₁ / (x-x₁)

          = 6- 2 / 6.5 - 1.5

          = 4/5

Thus, the near slope is 3/4. Option B is correct.

Learn more about slope;

https://brainly.com/question/3605446

#SPJ3

Answer:

The rate of change of section A is 3 and rate of change of section B is 48.

Step-by-step explanation:

The given function is

[tex]h(x)=4^x[/tex]

Formula for average rate:

[tex]m=\frac{f(x_2)-f(x_1)}{x_2-x_1}[/tex]

Section A is from x = 0 to x = 1, the average rate of change of section A is

[tex]m_1=\frac{h(1)-h(0)}{1-0}=\frac{4-1}{1}=3[/tex]

Section B is from x = 2 to x = 3, the average rate of change of section B is

[tex]m_2=\frac{h(3)-h(2)}{3-2}=\frac{64-16}{1}=48[/tex]

Therefore rate of change of section A is 3 and rate of change of section B is 48.

[tex]m_1\times k=m_2[/tex]

[tex]3\times k=48[/tex]

[tex]k=12[/tex]

Therefore average rate of change of Section B is 12 times of Section A.

The given function is an exponential function and rate of change is not constant.