How to solve for a side of a right triangle when you only know one side?
“all integers are rational numbers” true or false? why?
Angle a has the property that twenty eight times times its complement is equal to thirteen times its supplement. find the measure of angle
a.
how would you graph the solution set of the system of inequalities {3y≤2x+6} { 2x+y>0}
Customers of a phone company can choose between two service plans for long distance calls. The first plan has a $27 monthly fee and charges an additional $0.12 for each minute of calls. The second plan has no monthly fee but charges $0.16 for each minute of calls. For how many minutes of calls will the costs of the two plans be equal?
Write an expression that is equivalent to 2/3 (4x + 9).
8/3x + 6
8/3x + 9
2/3x + 6
2/3x + 9
2/3 of 9 = 6
2/3 *4 = 8/3
so the answer would be 8/3x +6
Can someone help me with this? 18(−8c+16)−13(6+3c) =
If a share of stock costs $32.63, what would it cost to buy 1,000 shares of the stock?
Consider the function
{8x-x^2 for x is less than or equal to 8
x^2+3 for x>8}
what is f(8)?
Help please !!!!!!!!!!!!!!
Pythagorean Theorem. I need help please!!!!!
The legs of a right triangle measure 30cm and 40cm.what is the length of the hypotenuse
What? I don’t know what I’m doing???
Can you find a shortcut in doing two translations in geometry
if i have 64,32,16,8 what two numbers comes next
I need help with #17
Which expression is equivalent to -3.5(4x – 3)?
A. -3.9x – 3.2
B. -3.9x + 3.2
C. -14x + 10.5
D. -14x – 10.5
Answer:
The answer is c
Step-by-step explanation:
A company plans to enclose three parallel rectangular areas for sorting returned goods. the three areas are within one large rectangular area and 10641064 yd of fencing is available. what is the largest total area that can be enclosed?
First get the perimeter
Perimeter: 2l + 2w = 1064 yd
The region inside the fence is the area
Area: A = lw
We need to solve the perimeter formula for either length or width.
2l + 2w = 1064 yd
2w = 1064 yd – 2l
W = 1064– 2l / 2
W = 532 – l
Now substitute than to the area formula
A = lw
A = l (532 – l)
A = 532 – l^2
Since the equation A represents a quadratic expression, rewritte the expression with the exponents in descending order
A(l) = -l^2 + 532l
Then look for the value of the x coordinate
l = -b/2a
l = -532/2(-1)
l = -532/-2
l = 266 yards
Plugging in the value into our calculation for area:
A(l) = -l^2 + 532
A(266) = -(266)^2 + 532 (266)
A(266) = 70756+ 141512
= 70756 square yards.
Thus the largest area that could encompass would be a square where each side has a length of 266 yards and a width of:
W = 532 – l
= 532 – 266
= 266
It should be noted that the largest total area that can be enclosed will be 70756 yards².
How to calculate the area.Firstly, we have to calculate the perimeter. This will be:
2l + 2w = 1064 yd
Area: A = length × width
2l + 2w = 1064 yd
2w = 1064 yd – 2l
W = 1064– 2l / 2
W = 532 – l
Since Area = lw
A = l(532 – l)
A = 532 – l²
A(l) = -l² + 532l
l = -b/2a
l = -532/2(-1)
l = -532/-2
l = 266 yards
The length is 266 yards.
Area = -l² + 532
A( = -(266)² + 532 (266)
Area = 70756+ 141512
Area = 70756 yards²
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nick bought a pet lizard and enjoys the responsibility of taking care of it . every week , the lizard will eat 60 grasshoppers. nick pays $1 for 20 grasshoppers . how many dollars will a year’s worth of food cost for the lizard
60*52 = 3120 per year
3120/20 = 156
it will cost $156 a year
Find the length of the diagonal of this rectangle.
Answer:
The length of the diagonal of the given Rectangle is, 11.80 m (Approx.)
Step-by-step explanation:
In Rectangle:
* It is a four sided shape where every angle is a right angle.
* The alternative sides are equal.
*Two axes of symmetry bisect each other.
* Diagonals are equal in length.
The figure of rectangle has given the length [tex]l[/tex] = 10m
In right angle triangle ADC.
DC = 10 m ( as alternative sides are equal )
Note that we are given here the adjacent and we have to find the length of hypotenuse, then we use trigonometric ratio that contains both sides adjacent and hypotenuse.
Use: [tex]Cosine = \frac{Adjacent}{hypotenuse}[/tex]
then,
[tex]\cos 32^{\circ} = \frac{10}{AC}[/tex] or
[tex]Ac = \frac{10}{\cos 32^{\circ}} =\frac{10}{0.8480481}[/tex]
On simplify we get;
AC = 11.791784 m
therefore, the length of the diagonal of this rectangle (AC) is, 11.80 m (Approx)
I really need help with these problems please come it will mean a lot if u help.
write a word phrase for each algebraic expression
1. 25 - 6
2. 2/3y + 4
factor each expression
3. 45c + 10d
4. 27 - 9x + 15y
Simplify the expression.
5. 3(t - 4) - 8 (2 - 3t )
6. 12x + 24
Answer:
Step-by-step explanation:
1)Twenty five minus sixty percent times a number.
Complete the pairs of 's.
(triangle)FCA ~= (triangle)
DAC
EBC
GCA
Answer:
DAC
Step-by-step explanation:
We can write, from the figure of the question.
In ΔFCA and ΔDAC.
∠FAC=∠DCA,
AC=CA, (common)
∠FCA=∠DAC.
Hence , we can say ΔFCA ≅ ΔDAC, because here in ΔFCA and ΔDAC, the two corresponding angles and including side are same (from ASA postulate ).
What is the angle of elevation from jim to the top of the waterfall
Answer: <7
Step-by-step explanation:
When two straight lines or rays intersect at a shared endpoint, an angle is generated. The angle of elevation from Jim to the top of the waterfall is ∠5. The correct option is B.
What is an angle?When two straight lines or rays intersect at a shared endpoint, an angle is generated. An angle's vertex is the common point of contact. Angle is derived from the Latin word angulus, which means "corner."
The angle of elevation is an imaginary angle that is assumed between the horizontal line and the line through which an object at a height is been seen.
In the given image the angle of elevation from Jim to the top of the waterfall is the angle formed by the line parallel to the horizontal plane and the line that connects Jim's eyesight to the top of the waterfall.
Hence, the angle of elevation from Jim to the top of the waterfall is ∠5.
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What is the area of a triangle with vertices at (−4, 1) , (−7, 5) , and (0, 1) ?
Enter your answer in the box.
we know that
A method for calculating the area of a triangle when you know the lengths of all three sides is the Heron's Formula.
The Heron's Formula states that
[tex]A=\sqrt{p(p-a)(p-b)(p-c)}[/tex]
where
a,b.c are the length sides of the triangle
p is half the perimeter of the triangle
Let
[tex]A(-4,1)\\B(-7,5)\\C(0,1)[/tex]
Step 1
Find the distance AB
we know that
the formula to calculate the distance between two points is equal to
[tex]d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}[/tex]
we have
[tex]A(-4,1)\\B(-7,5)[/tex]
substitute the values in the formula
[tex]d=\sqrt{(5-1)^{2}+(-7+4)^{2}}[/tex]
[tex]d=\sqrt{(4)^{2}+(-3)^{2}}[/tex]
[tex]d=\sqrt{25}[/tex]
[tex]dAB=5\ units[/tex]
Step 2
Find the distance BC
we know that
the formula to calculate the distance between two points is equal to
[tex]d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}[/tex]
we have
[tex]B(-7,5)\\C(0,1)[/tex]
substitute the values in the formula
[tex]d=\sqrt{(1-5)^{2}+(0+7)^{2}}[/tex]
[tex]d=\sqrt{(-4)^{2}+(7)^{2}}[/tex]
[tex]d=\sqrt{65}[/tex]
[tex]dBC=8.06\ units[/tex]
Step 3
Find the distance AC
we know that
the formula to calculate the distance between two points is equal to
[tex]d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}[/tex]
we have
[tex]A(-4,1)\\C(0,1)[/tex]
substitute the values in the formula
[tex]d=\sqrt{(1-1)^{2}+(0+4)^{2}}[/tex]
[tex]d=\sqrt{(0)^{2}+(4)^{2}}[/tex]
[tex]d=\sqrt{16}[/tex]
[tex]dAC=4\ units[/tex]
Step 4
Find half the perimeter
[tex]p=\frac{1}{2}(AB+BC+AC)[/tex]
substitute the values
[tex]p=\frac{1}{2}(5+8.06+4)[/tex]
[tex]p=8.53\ units[/tex]
Step 5
Find the area
Applying the Heron's Formula
[tex]A=\sqrt{8.53(8.53-5)(8.53-8.06)(8.53-4)}[/tex]
[tex]A=\sqrt{8.53(3.53)(0.47)(4.53)}[/tex]
[tex]A=\sqrt{64.11}[/tex]
[tex]A=8\ units^{2}[/tex]
therefore
the answer is
the area of the triangle is [tex]8\ units^{2}[/tex]
The area of a shape is the amount of space it occupies.
The area of the triangle is 8 unit square.
The vertices are given as:
[tex]\mathbf{A = (-4,1)}[/tex]
[tex]\mathbf{B = (-7,5)}[/tex]
[tex]\mathbf{C = (0,1)}[/tex]
The area of the triangle is:
[tex]\mathbf{A= \frac{1}{2} \times |A_x(B_y - C_y) + B_x(C_y - A_y) + C_x(A_y - B_y)|}[/tex]
So, we have:
[tex]\mathbf{A= \frac{1}{2} \times |-4(5 - 1) -7(1 - 1) + 0(1 - 5)|}[/tex]
[tex]\mathbf{A= \frac{1}{2} \times |-4(4) -7(0) + 0|}[/tex]
[tex]\mathbf{A= \frac{1}{2} \times |-4(4) -0 + 0|}[/tex]
[tex]\mathbf{A= \frac{1}{2} \times |-16|}[/tex]
Remove absolute brackets
[tex]\mathbf{A= \frac{1}{2} \times 16}[/tex]
[tex]\mathbf{A= 8}[/tex]
Hence, the area of the triangle is 8 unit square.
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1. Create a circle. Show and explain the difference between the following:
a. secant line and tangent line
b. inscribed angle and central angle
2. Describe the steps necessary to construct an inscribed circle in a triangle and contrast this with the steps you take to construct a circumscribed circle.
3. Demonstrate on the whiteboard how to find the center and radius of a circle using an equation. Be sure to provide a unique example of your own that shows how to find both of these.
4. A classmate is having difficulty finding the measures of
5. The world’s largest round pizza, which also happened to be gluten-free, was set in December 2012 by five Italian chefs. The diameter of this pizza was 131 feet. If this pizza was cut into 50 slices, what would be the area of each slice and the length of the crust for the slice? Explain what concepts of a circle these calculations related to.
Final answer:
The differences between secant and tangent lines, and between inscribed and central angles, involve the number of intersection points with the circle and the position of the vertex, respectively. Constructing an inscribed circle involves finding the incenter, while a circumscribed circle requires finding the circumcenter. To find the center and radius of a circle using its equation, we use the standard form (x - h)² + (y - k)² = r².
Explanation:
Differences Between Secant Lines, Tangent Lines, Inscribed Angles, and Central Angles
A secant line is a line that intersects a circle at two points, while a tangent line touches the circle at exactly one point. An inscribed angle is an angle formed by two chords in a circle that meet at one point in the circle, whereas a central angle is an angle whose apex (vertex) is the center of the circle.
Constructing Inscribed and Circumscribed Circles in a Triangle
To construct an inscribed circle (incircle) of a triangle, draw the angle bisectors of the triangle's angles to find the incenter, and then use this point to draw the circle that touches all three sides of the triangle. For a circumscribed circle (circumcircle), draw the perpendicular bisectors of the triangle's sides and the point where they intersect will be the circumcenter; use this as the center to draw the circle that passes through all three vertices of the triangle.
Finding the Center and Radius of a Circle Using an Equation
Given a circle's equation in the standard form (x - h)² + (y - k)² = r², the center is at point (h, k), and the radius is the square root of r². For example, if we have the equation (x - 3)² + (y + 2)² = 16, the center is (3, -2) and the radius is 4 units.
Area and Length of the Crust of a Circular Pizza Slice
For the world's largest round pizza with a diameter of 131 feet, the radius would be 65.5 feet. The area of each slice is a fraction of the whole pizza's area, which can be found using the formula A = πR², and the length of the crust for the slice corresponds to the arc length of that slice.
Area of whole pizza = 3.14 * 65.5² ≈ 13478.2 ft²
Area of each slice = total area /50 = 13478.2/50 ≈ 269.5 ft²
Length of crust = 2πR * (slice area/total area)
= 2 * 3.14 * (1/50)
≈ 0.125 ft
what did the candle say to the match
What is the ratio 35 to 15 expressed as a fraction in simplest form?
The functions graphed show the snowfall, in inches, in two cities after x hours.
Select each correct answer.
Middletown had a faster rate of snowfall.
Smithville had a faster rate of snowfall.
Snow fell in Smithville at a rate of 4 inches per hour.
Middletown already had snow on the ground at the beginning of the storm.
we know that
the formula to calculate the slope between two points is equal to
[tex]m=\frac{y2-y1}{x2-x1}[/tex]
in this problem
the rate of snowfall is equal to the slope of the linear equation
so
Let
x-------> the time in hours
y---------> the snowfall in inches
Step 1
Find the slope of the line of the Smithville city
Let
[tex]A(0,0)\\B(5,20)[/tex]
substitute the values in the formula above
[tex]m=\frac{20-0}{5-0}[/tex]
[tex]m=4\frac{inches}{hour}[/tex]
Step 2
Find the slope of the line of the Middletown city
Let
[tex]A(0,0)\\B(5,15)[/tex]
substitute the values in the formula above
[tex]m=\frac{15-0}{5-0}[/tex]
[tex]m=3\frac{inches}{hour}[/tex]
Step 3
Verify the statements
case A) Middletown had a faster rate of snowfall
The statement is False
Because Smithville had a faster rate of snowfall with [tex]4\frac{inches}{hour}[/tex]
case B) Smithville had a faster rate of snowfall
The statement is True
case C) Snow fell in Smithville at a rate of 4 inches per hour
The statement is True
case D) Middletown already had snow on the ground at the beginning of the storm
The statement is False
Because at the beginning of the storm the value of the snow is equal to zero
therefore
the answer is
Smithville had a faster rate of snowfall
Snow fell in Smithville at a rate of 4 inches per hour
Simplify (s)(-3st)(-1/3).
A.) -3 1/3 t
B.) s^2t
C.) 3s^2t
(If this format is too weird I have added a screenshot)
Thanks in advance!