Joe and Mary each pay the same price for a T-shirt. Before they buy it, Mary has $\$ 2$ more than Joe. To buy the T-shirt, Joe spends $ \$1 $ less than $\frac{2}{5}$ of his money, and Mary spends $\frac{1}{3}$ of her money. What was the total amount of money Joe and Mary originally had altogether?

Answers

Answer 1
Let Joe initially have J dollars, and Mary have M dollars. Let the price of the T-shirt be T dollars.

i) "Before they buy it, Mary has 2$ more than Joe":

means M=J+2

ii)

"To buy the T-shirt, Joe spends 1 $ less than \frac{2}{5} of his money"

so  [tex]T= \frac{2}{5}J-1 [/tex]

iii) 

"Mary spends \frac{1}{3} of her money"

means [tex]T= \frac{1}{3}M [/tex]

equalize equations ii) and iii):

[tex]\frac{2}{5}J-1= \frac{1}{3}M[/tex]        (they are both equal to T)

substitute M=J+2 from equation i:

[tex]\frac{2}{5}J-1= \frac{1}{3}(J+2)[/tex]

[tex]\frac{2J-5}{5}= \frac{J+2}{3}[/tex]

[tex]3(2J-5)=5(J+2)[/tex]

6J-15=5J+10
J=25

so M=25+2=27 (dollars)

Together Mary and Joe had 27+25=52 (dollars)


Answer: 52 $
Answer 2

Answer:

52

Step-by-step explanation:

Suppose Joe had $J$ dollars to start with. Then Mary had $J + 2$ dollars. Since they both spent the same amount on their shirts, $\frac{2}{5} J - 1 = \frac{1}{3} (J + 2)$. Distributing, we get $\frac{2}{5} J - 1 = \frac{1}{3}J + \frac{2}{3}$. Isolating $J$ on the left side, $\frac{1}{15}J = \frac{5}{3}$. Therefore, $J = 25$. Thus, their original total amount of money was $J + (J + 2) = \boxed{52}$ dollars.


Related Questions

SOMEONE PLEASE HELP ME WITH MATH! WILL GIVE BRAINLIEST TO FIRST PERSON WHO ANSWERS!!

Solve each system by substitution.
1. -5x-8y=9
y= -3.

2. y= -3x
-6x-2y=3

3. 6x+5y=10
y=-8x+2

4.6x+2y= -6
y= -3x -3

Thank you!

Answers

1. -5x-8(-3)=9
-5x+24=9
-5x=-15
x=3
(3,-3)

2. -6x-2(-3x)=3
-6x+6x=3
0=3
No solution

3. 6x+5(-8x+2)=10
6x-40x+10=10
-34x+10=10
-34x=0
x=0
y=-8(0)+2
y=2
(0,2)

4. 6x+2(-3x-3)=-6
6x-6x-6=-6
-6=-6
Infinitely many solutions

5 radians is the same as _____.

Answers

There are 2π radians per 360° so

5rad(360°/2π rad)=900/π degrees

That is approximately:

286.48° (to nearest hundredth of a degree) or

286°28'44" (to nearest second)


Answer:

286°28'44

Step-by-step explanation:

Walter bought a square plot of land. the perimeter is 544 feet. how wide is the property?

Answers

perimeter of a square = is side times 4

so divide 544 by 4

544/4 = 136

the property is 136 feet wide

Miss broom invested $10,000 into an account with an interest rate of 6% compounded annually which equation models the time it will take for his money to double?

A- logbase2 1.06= T

B- log2 =T

C-log1.06 =T

D= logbase1.06 2=t

Answers

The answer is
D= logbase1.06 2=t

If you compute it, you will will get 11.89 years which rounded to 12 years

Juanita’s boss told her that once she has worked with the company for 10 years, her salary will be increased to 3 times what she makes now plus $2,000. If s represents her original salary, which expression represents what her salary will be after 10 years at the company?

Answers

The expression represents what her salary will be after 10 years at the company is
A=3s+2000

Answer:3s+2,000

Step-by-step explanation:

Find the exact solution to the equation. Show your work for credit. (1 point) four to the power of quantity twelve minus four x equals two hundred and fifty six.

Answers

4^(12-4x)=256  realize that 256 is 4^4  so we really have:

4^(12-4x)=4^4  taking the natural log of both sides

(12-4x)ln4=4ln4  dividing both sides by ln4

12-4x=4  subtract 12 from both sides

-4x=-8  divide both sides by -4

x=2


The exact solution to the equation [tex]4^{(12 - 4x)[/tex] = 256 is x = 2. By recognizing that 256 is 4 raised to the fourth power, we equate the exponents and solve for x.

To solve this problem, we need to recognize that 256 is a power of 4. 4⁴ = 256. With this insight, the equation can be rewritten as:

[tex]4^{(12 - 4x)[/tex] = 4⁴

Since the bases are the same, we can equate the exponents:

12 - 4x = 4

Now, we'll isolate the variable x:

Subtract 12 from both sides: -4x = 4 - 12

-4x = -8

Divide both sides by -4: x = 2

Thus, the exact solution to the given equation is x = 2.

I want to make sure of my answer is right?

Answers

20 2/7 = 142/7 -20/35

find common denominator ( in this case it is 35)

35/7 =5 , multiply 142*5=710, 7*5 =35

142/7 = 710/35

710/35 - 20/35  = 710-20 = 690

690/35 now simplify that fraction

690/35 = 19.714

19*35 = 665

690-665=25

19 25/35

25/35 can reduce to 5/7

answer = 19 5/7


Which of the following is a factor of 6x2 + 2x − 21?

4x − 3
2x + 7
6x − 3
None of the above

Answers

ANSWER

None of the above

EXPLANATION

The quadratic expression given to us is

[tex]6 {x}^{2} + 2x - 21[/tex]

If the discriminant of this quadratic expression is a perfect square, then it has rational factors,

If we compare the above expression to the general quadratic expression,

[tex]a {x}^{2} + bx + c[/tex]
We have,
[tex]a=6,b=2,c=-21[/tex]


The discriminant is given by,

[tex] D = {b}^{2} - 4ac[/tex]

Thus

[tex] D = {2}^{2} - 4(6)( - 21)[/tex]


[tex] D = 4 + 504 = 508[/tex]

Since 508 is not a perfect square, the expression


[tex]6 {x}^{2} + 2x - 21[/tex]
has no rational factors.


Therefore D is the correct answer.

if 6a-8b=0 and c=12b, the ratio of a to c is equivalent to the ratio of one to what number?

Answers

6a=8b
3a=4b
c=3*(4b)=3*3a=9a
c=9a
First find the ratio of a:b since you know 6a=8b, then reduce to get 3a=4b. Since c=12b, let's multiply everything by 3 so 9a=12b. This means 9a=c. This is the same as 9a=1c so now you can easily get your answer:)

The measure of ∠B is (3x – 4 )° and the measure of ∠D is (2x – 6)°. What are the measures of angles B and D?

Answers

B = 110 D = 70 your welcome yall

The measures of angles B and D are 110° and 70° respectively.

What is cyclic quadrilateral?

The rule of cyclic quadrilateral states that, the sum of the opposite is supplementary i.e 180°

Therefore, applying this rule, Angle B and D are supplementary

Then, B+D=180°

Given that, B=3x-4 and D= 2x-6

Thus, (3x-4)+(2x-6)=180°

3x-4+2x-6=180°

3x+2x-4-6=180°

5x-10=180°

5x=180°+10

5x=190°

Then, x =190/5

x=38°

Then solving for B and D;

B=3x-4

B=3(38)-4

B=114-4

B=110°

Also, D=2x-6

D=2(38)-6

D=76-6

D=70°

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if f (x) =-14x-2, then f^-1 (x) =

Answers

Hi!

Switch up the variables:

y = -14x - 2.

x = -14y - 2.

Add 2 to both sides.

x + 2 = -14y - 2 + 2.

x + 2 = -14y.

Divide by -14 on both sides.

(x + 2) / -14 = -14y / -14.

(x + 2) / -14 = y.

Change the y to f^-1(x).

f^-1(x) = (x + 2) / -14.

Hopefully, this helps! =)

Use the functions h(x) = 2x + 5 and t(x) = 7x − 6 to complete the function operations listed below.

Part A: Find (h + t)(x). Show your work. (3 points)

Part B: Find (h ⋅ t)(x). Show your work. (3 points)

Part C: Find h[t(x)]. Show your work. (4 points)

Answers

We have to use the functions:
h ( x ) = 2 x + 5 and t ( x ) = 7 x - 6
Part A:
( h + t ) ( x ) = ( 2 x + 5 )  + ( 7 x - 6 ) = 9 x - 1
Part B :
( h · t ) ( x ) = ( 2 x + 5 ) · ( 7 x - 6 ) = 14 x² - 12 x + 35 x - 30 =
= 14 x² + 23 x - 30
Part C :
h [ t ( x ) ] = h ( 7 x - 6 ) = 2 · ( 7 x - 6 ) + 5 = 14 x - 12 + 5 =
= 14 x - 7

One number is 2 more than 3 times another. their sum is 22. find the numbers. 8, 14

Answers

x + y = 22
x = 3y + 2

3y + 2 + y = 22
4y + 2 = 22
4y = 22 - 2
4y = 20
y = 20/4
y = 5

x = 3y + 2 = 3(5) + 2 = 15 + 2 = 17

ur numbers are 5 and 17
Let the number be x.

Hence the other number is 2 + 3*x.

Their sum is 22;

x + 2 + 3x = 22

4x + 2 = 22

4x = 20

 Therefore, x = 5

[ 2 + 3x = 2 + 3*5 = 2+15 = 17 ]

Hence the two numbers are, 5 and 17. 

how close are a meter and a yard? convert 1 meter into yards by using the fact
that there are 100 centimeters in a meter, 2.53 centimeters in a inch, 12 inches in a foot, and 3 feet in a yard.

Answers

1 meter= 100cm

2.53cm=1 inch

12 inches= 1 foot

3 feet= 1 yard

2.53*12*3=91.08

1 yard=91.08cm
1 meter=100cm

1 meter is 8.92cm longer than 1 yard

I hope this helps, if you need more elaboration, just ask

Wich of the operations ,+,-,x➗are inverse o each other

Answers

The correct answers are as follows: Adding (+) and subtracting (-) are inverse to each other. And then multiplication (x) is inverse to division (➗)

33.
In quadrilateral PQRS, the coordinates are P(0, 0), Q(a + c, 0), R(2a + c, b), and S(a, b). How can you use coordinate geometry to show that the diagonals are perpendicular?

Apply the Distance Formula to show that opposite sides to show they  are congruent.

Find the slopes of  their product is 1.

Apply the Distance Formula to show that opposite sides to show sides  are congruent.

Find the slopes and show that their product is -1.

Answers

By definition, perpendicular line are two lines that intersect at right angles. In other words, the angle made by two lines should be 90°. Therefore, the use of distance formula does not help because it only tells you if the sides are equal. It does not tell you about the intercepted angle.

A technique that can help you to know if two straight lines are perpendicular is is you find their slopes. Let's say the slope of line 1 is m1 and the slope of line 2 is m2. If m1*m2 yields a product of -1, then the lines are perpendicular. This is because if m1 is the negative reciprocal of m2, the lines are perpendicular. But if m1=m2, the lines are parallel, meaning they don't intersect at all.

Therefore, the answer is: Find the slopes and show that their product is -1.

Answer: The answer is (d) Find the slopes and show that their product is -1.

Step-by-step explanation:  Given in the question and shown in the attached figure that the vertices of the quadrilateral PQRS are P(0, 0), Q(a + c, 0), R(2a + c, b), and S(a, b). We are asked to use geometry to show that the diagonals PR and QS are perpendicular to each other.

We know that the two lines are perpendicular if the product of their slopes is --1.

So, first we will find the slopes of PR and QS, multiply them, and check the value.If the value is -1, then the diagonals are perpendicular to each other.

That is, if 'm' and 'p' are the slopes of the diagonals PR and QS, and if m × p = -1, then the two diagonals are perpendicular.

Thus, the correct answer is (d).

Let $f$ be a function such that $f(x+y) = x + f(y)$ for any two real numbers $x$ and $y$. if $f(0) = 2$, then what is $f(2012)?$

Answers

Given:

f(0) = 2

So first of all, we let x = 2012, y = 0: 


Then, F(2012) = 2012 + f(0)

Since f(0) = 2, then f(2012) = 2012 + 2 = 2014.

To add, the process that relates an input to an output is called a function.

 

 

There are always three main parts of a function, namely:

Input

The Relationship

The Output

 

The classic way of writing a function is "f(x) = ... ".

 

What goes into the function is put inside parentheses () after the name of the function: So, f(x) shows us the function is called "f", and "x" goes in.

 

 

What a function does with the input can be usually seen as:

 

f(x) = x2 reveals to us that function "f" takes "x" and squares it.

Factor this expression. With work please!

Answers

[tex]\bf \textit{difference of squares} \\ \quad \\ (a-b)(a+b) = a^2-b^2\qquad \qquad a^2-b^2 = (a-b)(a+b)\\ \quad \\ \quad \\ % difference of cubes \textit{difference of cubes} \\ \quad \\ a^3+b^3 = (a+b)(a^2-ab+b^2)\qquad (a+b)(a^2-ab+b^2)= a^3+b^3 \\ \quad \\ a^3-b^3 = (a-b)(a^2+ab+b^2)\qquad (a-b)(a^2+ab+b^2)= a^3-b^3\\\\ -------------------------------[/tex]

[tex]\bf x^6-9x^4-81x^2+729\qquad \begin{cases} x^6=x^{2\cdot 3}\\ \qquad (x^2)^3\\ 729=9\cdot 9\cdot 9\\ \qquad 9^3\\ 81=9\cdot 9\\ \qquad 9^2 \end{cases}\\\\ -------------------------------\\\\[/tex]

[tex]\bf (x^6+729)-(9x^4+81x^2)\implies [(x^2)^3+9^3]-(9x^2x^2+9^2x^2) \\\\\\\ [\underline{(x^2+9)}(x^4-9x^2+9^2)]\ -\ [9x^2\underline{(x^2+9)}]\impliedby \begin{array}{llll} notice\ the\\ \textit{\underline{common factor}} \end{array} \\\\\\ (x^2+9)\ [(x^4\underline{-9x^2}+9^2)\underline{-9x^2}]\impliedby \textit{now we add \underline{these two}} \\\\\\[/tex]

[tex]\bf (x^2+9)\ [x^4-18x^2+9^2]\impliedby \begin{cases} \sqrt{x^4}=x^2\\ \sqrt{9^2}=9\\ 18x^2=2(x^2)(9)\\ thus\ a\\ \textit{perfect square trinomial} \end{cases} \\\\\\ (x^2+9)\ [(x^2)^2-18x^2+9^2] \\\\\\ (x^2+9)(x^2-9)^2\implies (x^2+9)(x^2-3^2)^2 \\\\\\ (x^2+9)\ [(x-3)(x+3)]^2\implies \boxed{(x^2+9)(x-3)^2(x+3)^2} \\\\\\ \textit{and I guess you could be redundant and use} \\\\\\ (x^2+9)(x-3)(x-3)(x+3)(x+3)[/tex]

Suppose there are 10,000 civilizations in the milky way galaxy. if the civilizations were randomly distributed throughout the disk of the galaxy, about how far (on average) would it be to the nearest civilization? (hint: start by finding the area of the milky way's disk, assuming that it is circular and 100,000 light-years in diameter. then find the average area per civilization, and use the distance across this area to estimate the distance between civilizations.)

Answers

The shape of the galaxy is a circular, with diameter 100, 000 lights year, 
so the radius is 50, 000 lights year, thus

 Area of the galaxy is [tex]A(galaxy)= \pi r^{2}= \pi (50,000)^{2}=25*10^{8} \pi [/tex] (lights year square)

The area per civilisation is [tex] \frac{25*10^{8} \pi }{10,000}=25*10^{4} \pi[/tex]

from this result we can assume as a circle of Radius=[tex]25*10^{2}=2500[/tex] lights year.

and assume that each civilisation lives in a planet at the center of these smaller circles.

Check the figure attached.

Planet A, and B are closest in distance. They are each at the center of a circle with radius 2500, and they are tangent. So the distance of A to B is 2500+2500=5000 (light years).


Answer: 5000 light years

Evaluate P(6,2).
A.) 12
B.) 30
C.) 360

Answers

Permutation
[tex]6P2=\frac{6!}{(6-2)!}=\frac{4!\cdot 5 \cdot 6}{4!}=5 \cdot 6=30[/tex]

The value of the [tex]\rm ^6p_2[/tex] is 30.

We have to determine

The value of  P(6,2).

According to the question

The value of the [tex]\rm ^6p_2[/tex] is determined by using permutation.

The probability of selecting an ordered set of 'r' objects from a group of 'n' number of objects.

The order of objects matters in the case of permutation.

The formula to find [tex]\rm ^np_r[/tex] is given by:

[tex]\rm ^np_r = \dfrac{n!}{(n-r)!}[/tex]

Substitute n = 6 and r = 2 in the formula;

[tex]\rm ^np_r = \dfrac{n!}{(n-r)!}\\ \\ \rm ^6p_2 = \dfrac{6!}{(6-2)!}\\ \\ \rm ^6p_2= \dfrac{6 \times 5\times 4 \times 3\times2 \times 1}{4!}\\ \\ ^6p_2= \dfrac{6 \times 5\times 4 \times 3\times2 \times 1}{4\times 3 \times2 \times 1}\\ \\ ^6p_2= 6 \times 5}\\ \\ ^6p_2= 30[/tex]

Hence, The value of the [tex]\rm ^6p_2[/tex] is 30.

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write an equation for a line perpendicular to the x-axis that passes through the point (5,1)

Answers

If it is perpendicular to the x-axis, it is a vertical line of the form:

x=k, since it must pass through (5,1) that vertical line is:

x=5
Final answer:

The equation of a line perpendicular to the x-axis passing through the point (5,1) is x = 5. This is because a vertical line crossing the x-axis at a specific point will have the same x-coordinate for all its points.

Explanation:

In mathematics, a line perpendicular to the x-axis is a vertical line that crosses the x-axis at a specific point. All points on this line will share the same x-coordinate. Therefore, a line that is perpendicular to the x-axis, and passes through the point (5,1) will have the equation x = 5. This equation represents a line that is vertical and intercepts the x-axis at the point where x equals 5. This is because in each point on the line, x remains constant, which is the characteristic of a vertical line in a Cartesian Coordinate System.

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800x200 I know the answer is 160000 but I want to see how quick you guys answer...

Answers

hello : 
8×2 = 16
 and : four zero : 0000
you have : 160000

Find the surface area of the cone to the nearest tenth.


A. 203 cm2
B. 1341.5 cm2
C. 747.7 cm2
D. 213.5 cm2

Answers

So i also need closure on this question actualy taking the geometry examen rn... and i figured i had to do (pi)* 7^2 = 152.938......
soooo like this is what you gone do....
(pi) * 7^2+ (pi) *7 *27
=747.6990.....
hope this helps 
THE STRUGGLE IS REAL

The surface area of the given cone is 747.32.

What is area of a cone?

"The total surface area of a cone is defined as the total area of the cone occupied in a three-dimensional area. It is equal to the sum of the curved surface and the base of the cone. "

Surface area of the cone is [tex]\pi*r(l+r )[/tex]

[tex](22/7)*7*(27+7)[/tex]

= 747.32

The surface area of the cone is 747.32

Hence, option C is correct.

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Angles θ and Φ are supplementary, and theta equals 3pi/7 find the measure of theta

Answers

hello : 
Φ + 3π/7 = π 
Φ =  π - 3π/7
Φ =4π/7 

From Plato: Φ =7π/7 or π.

What are the explicit equation and domain for an arithmetic sequence with a first term of 5 and a second term of 2?
an = 5 − 2(n − 1); all integers where n ≥ 1
an = 5 − 2(n − 1); all integers where n ≥ 0
an = 5 − 3(n − 1); all integers where n ≥ 1
an = 5 − 3(n − 1); all integers where n ≥ 0

Answers

The easiest way to answer this is to try all choices, plug in values for the 1st term and 2nd term then check if the answer matches with 5 and 2. (n = 1 and n = 2)

We know that n starts with 1 because that is our 1st term, we do not have 0th term, therefore that leaves us with 2 choices.

Choice 1: an = 5 − 2(n − 1); all integers where n ≥ 1

n = 1

a1 = 5 – 2 (1 – 1) = 5 – 2 (0)

a1 = 5

 

n = 2

a2 = 5 – 2 (2 – 1) = 5 – 2 (1)

a2 = 3   (FALSE!)

 

Choice 2: an = 5 − 3(n − 1); all integers where n ≥ 1

n = 1

a1 = 5 – 3 (1 – 1) = 5 – 3 (0)

a1 = 5

 

n = 2

a2 = 5 – 3 (2 – 1) = 5 – 3 (1)

a2 = 2   (TRUE)

 

Therefore the correct answer is:

an = 5 − 3(n − 1); all integers where n ≥ 1

Answer:

A is INCORRECT

Step-by-step explanation:

Just finished the FLVS test

A right triangle has legs that are 10.1in and 12.2 in long. What is the approximate length of the hypotenuse?

Answers

a^2 + b^2 = c^2...a and b are the legs and c is the hypotenuse
10.1^2 + 12.2^2 = c^2
102.01 + 148.84 = c^2
250.85 = c^2
sqrt 250.85 = c
15.838 = c <== ur hypotenuse

How can you eliminate the fraction from each side of the equation to make finding the
solution easier?
The equation is 1/2(x - 4) = 1/3x + 2

Answers

hello : 
 1/2(x - 4) = 1/3x + 2
multiply by : 6
3(x-4) = 2x +4
solution easier:
3x -12 = 2x +4
3x - 2x = 12+4
 x = 16

How can the average rate of change be found using a discrete graph?

Answers

Final answer:

The average rate of change can be found using a discrete graph by calculating the slope between two points on the graph. This provides insight into how the dependent variable changes as the independent variable varies.

Explanation:

The average rate of change can be found using a discrete graph by calculating the difference in the y-values of two points and dividing it by the difference in the x-values of those same points. This will give you the slope of the line connecting the two points, which represents the average rate of change between those two points. For example, if you have two points (x1, y1) and (x2, y2), the average rate of change can be calculated as:

(y2 - y1) / (x2 - x1)

By finding the average rate of change at different intervals on the graph, you can analyze how the dependent variable changes in relation to the independent variable.

Which system is the only inconsistent system?
Select one:
a.
y
y
=
=
x+4
2x+4
y=x+4y=2x+4

b.
y
y
=
=
x
−x
y=xy=−x

c.
y
y
=4
=
x−3
4x+3
y=4x−3y=4x+3

d.
y
2y
=2
=
x−3
4x−6
y=2x−32y=4x−6

Answers

Final answer:

Option (c) represents an inconsistent system of equations, as the constant terms are not proportional, while the coefficients of x are. This system (y=4x-3, y=4x+3) has no solutions.

Explanation:

In mathematics, specifically in algebra, an inconsistent system is a system of equations that has no solutions. To check which system is inconsistent from the options you've given, we need to compare the coefficients of each equation within a system. An inconsistent system will have proportional coefficients of x and y between the two equations, but the constant terms will not be proportional.

Looking at each option:

Option (a): y=x+4 and y=2x+4
Option (b): y=x and y=−x
Option (c): y=4x−3 and y=4x+3
Option (d): y=2x−3 and 2y=4x−6

From here, we can see that option (c): y=4x-3, y=4x+3 is inconsistent. In this system, the coefficients of x are proportional (4), but the constant terms (-3 and +3) are not proportional.

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The coordinates of the midpoint of GH¯¯¯¯¯¯¯¯are M(−2, 5) and the coordinates of one endpoint are H(−3, 7) .

The coordinates of the other endpoint are ( __ , __ )

Answers

m = (x1 + x2)/2 , (y1 + y2)/2

(-3 + x) / 2 = -2
-3 + x = -4
x = -4 + 3
x = -1

(7 + y) / 2 = 5
7 + y = 10
y = 10 - 7
y = 3

so the other endpoint is (-1,3)

The coordinate point of the other endpoint, G is (-1, 3)

The given parameters;

the midpoint = M(-2, 5)

one end point = H(-3,7)

To find:

the coordinate point of the other endpoint, G

Let the coordinate point of the other endpoint = G(x, y)

The coordinate point of the other endpoint, G will be calculated using midpoint formula.

[tex]M(-2, 5) =( \frac{x + (-3)}{2} , \frac{y + 7}{2} )\\\\-2 = \frac{x - 3}{2} \ \ \ and \ \ 5 = \frac{y+ 7}{2} \\\\x-3 = 2(-2)\\\\x - 3 = -4\\\\x = -4 + 3\\\\x = -1\\\\y+ 7 = 2(5)\\\\y + 7 = 10\\\\y = 10 -7\\\\y = 3\\\\G= (-1, 3)[/tex]

Thus, the coordinate point of the other endpoint, G is (-1, 3)

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